Complete the following statement regarding manganese redox species by filling in the corre… — JAMB UTME

Complete the following statement regarding manganese redox species by filling in the correct numerical oxidation states.

Answer:In potassium manganate(VI),

K_2MnO_4

, the oxidation state of the central manganese atom is 【+6】, whereas in potassium tetraoxomanganate(VII),

KMnO_4

, the oxidation state of manganese is 【+7】.

The oxidation state of manganese in

K_2MnO_4

is +6, and in

KMnO_4

it is +7.

In potassium manganate(VI),

K_2MnO_4

, two potassium ions yield a

+2

total charge and four oxide ions yield

-8

, requiring manganese to be

+6

to balance to zero. In potassium tetraoxomanganate(VII),

KMnO_4

, one potassium ion (

+1

) and four oxide ions (

-8

) leave manganese at

+7

Calculate the oxidation state of manganese in

K_2MnO_4

Assign standard oxidation numbers:

K = +1

and

O = -2

. For the neutral molecule

K_2MnO_4

2(+1) + \text{Mn} + 4(-2) = 0 \implies +2 + \text{Mn} - 8 = 0 \implies \text{Mn} = +6

The sum of oxidation states in a neutral chemical compound must equal zero.

Calculate the oxidation state of manganese in

KMnO_4

Assign standard oxidation numbers:

K = +1

and

O = -2

. For the neutral molecule

KMnO_4

1(+1) + \text{Mn} + 4(-2) = 0 \implies +1 + \text{Mn} - 8 = 0 \implies \text{Mn} = +7

The sum of oxidation states in a neutral chemical compound must equal zero.

Determining oxidation states of central transition metal atoms in oxoanions and neutral salts.

Question