Question

Difficulty: MediumMendel's Second Law and Dihybrid Inheritance

In cattle (*Bos taurus*), the polled (hornless) condition (PP) is dominant to the horned condition (pp), and black coat color (BB) is dominant to red coat color (bb). If a heterozygous polled, heterozygous black bull (PpBbPpBb) is crossed with a horned, heterozygous black cow (ppBbppBb), what proportion of the offspring is expected to display the horned, black coat phenotype?

  1. 38\frac{3}{8}Answer
  2. B
    916\frac{9}{16}
  3. C
    14\frac{1}{4}
  4. D
    18\frac{1}{8}

Answer

The expected proportion of offspring displaying the horned, black coat phenotype is 38\frac{3}{8}.
According to Mendel's Law of Independent Assortment, the inheritance of horn condition and coat color are independent events. The cross between PpPp and pppp yields a 12\frac{1}{2} probability of horned offspring (pppp). The cross between BbBb and BbBb yields a 34\frac{3}{4} probability of black-coated offspring (BBBB or BbBb). Multiplying these independent probabilities (12×34\frac{1}{2} \times \frac{3}{4}) gives 38\frac{3}{8} as the expected fraction of horned, black-coated offspring.

Step-by-Step Solution

1
Analyze the cross for the horn condition trait independently.
The cross Pp×ppPp \times pp produces genotypes PpPp (polled) and pppp (horned) in a 1:11:1 ratio, giving a probability of P(pp)=12P(pp) = \frac{1}{2}.
Mendel's Law of Segregation dictates that alleles segregate independently into gametes.
2
Analyze the cross for the coat color trait independently.
The cross Bb×BbBb \times Bb produces phenotypes in a 3:13:1 ratio, giving a probability of P(black coat,B_)=34P(\text{black coat}, B\_) = \frac{3}{4}.
Crossing two heterozygotes results in 14BB\frac{1}{4} BB, 12Bb\frac{1}{2} Bb, and 14bb\frac{1}{4} bb genotypes.
3
Combine the independent probabilities using Mendel's Law of Independent Assortment.
P(horned and black coat)=P(pp)×P(B_)=12×34=38P(\text{horned and black coat}) = P(pp) \times P(B\_) = \frac{1}{2} \times \frac{3}{4} = \frac{3}{8}.
Because the two gene pairs assort independently, the combined probability is the product of their separate probabilities.

Key Concept

Mendel's Law of Independent Assortment and Probability Calculations in Dihybrid Crosses
Estimated Time:1m 30s
Rate this question