Question

Difficulty: EasyTrigonometric Graphs and Simple Equations

What is the period, in degrees, of the trigonometric function y=7sin(5x)2y = 7\sin(5x) - 2?

Answer: 72 degrees

Answer

The period of the trigonometric function is 72 degrees.
For any function of the form y=Asin(Bx)+Dy = A\sin(Bx) + D, the period TT in degrees is calculated using T=360BT = \frac{360^\circ}{|B|}. For the given equation y=7sin(5x)2y = 7\sin(5x) - 2, the value of BB is 5. Substituting this into the formula gives T=3605=72T = \frac{360^\circ}{5} = 72^\circ.

Step-by-Step Solution

1
Identify the coefficient BB of the variable xx in the given function y=7sin(5x)2y = 7\sin(5x) - 2.
Here, A=7A = 7, B=5B = 5, and D=2D = -2.
The period of a sine function depends on the angular frequency parameter BB multiplying the input variable xx.
2
Apply the standard formula for finding the period TT of a sine function in degrees: T=360BT = \frac{360^\circ}{|B|}.
T=3605=72T = \frac{360^\circ}{5} = 72^\circ.
Dividing the standard full revolution of 360360^\circ by the multiplier 55 determines the angle needed for one full cycle.

Key Concept

Period of a Trigonometric Graph
Estimated Time:45s
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