Question

Difficulty: HardOxidation Numbers and IUPAC Nomenclature of Redox Species

Match each chemical species listed on the left with its correct systematic IUPAC name on the right.

  • MnO42MnO_4^{2-}Tetraoxomanganate(VI) ion
  • ClO4ClO_4^-Tetraoxochlorate(VII) ion
  • N2ON_2ODinitrogen(I) oxide
  • Fe2O3Fe_2O_3Iron(III) oxide

Answer

The correct pairings are: MnO42MnO_4^{2-} matches Tetraoxomanganate(VI) ion; ClO4ClO_4^- matches Tetraoxochlorate(VII) ion; N2ON_2O matches Dinitrogen(I) oxide; and Fe2O3Fe_2O_3 matches Iron(III) oxide.
Each chemical formula correctly corresponds to its IUPAC name based on the calculated oxidation number of the electropositive element and standard IUPAC nomenclature rules for oxoanions and oxides.

Step-by-Step Solution

1
Determine the oxidation number of manganese in MnO42MnO_4^{2-}
Manganese has an oxidation state of +6+6.
Applying the algebraic rule for polyatomic ions: x+4(2)=2    x=+6x + 4(-2) = -2 \implies x = +6. The four oxygen atoms prefix as 'tetraoxo-', giving tetraoxomanganate(VI) ion.
2
Determine the oxidation number of chlorine in ClO4ClO_4^-
Chlorine has an oxidation state of +7+7.
Applying the algebraic rule: x+4(2)=1    x=+7x + 4(-2) = -1 \implies x = +7. The species is named tetraoxochlorate(VII) ion.
3
Determine the oxidation number of nitrogen in N2ON_2O
Nitrogen has an oxidation state of +1+1.
Applying the neutrality rule: 2x+(2)=0    2x=+2    x=+12x + (-2) = 0 \implies 2x = +2 \implies x = +1. The IUPAC name is dinitrogen(I) oxide.
4
Determine the oxidation number of iron in Fe2O3Fe_2O_3
Iron has an oxidation state of +3+3.
Applying the neutrality rule: 2x+3(2)=0    2x=+6    x=+32x + 3(-2) = 0 \implies 2x = +6 \implies x = +3. The IUPAC name is iron(III) oxide.

Key Concept

Calculation of oxidation numbers for central atoms in oxoanions and binary oxides to deduce standard IUPAC names.
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