Question

Difficulty: EasyOxidation Numbers and IUPAC Nomenclature of Redox Species

Match each oxoanion on the left with the correct oxidation number of its central element on the right.

  • PO43PO_4^{3-}+5
  • NO2NO_2^-+3
  • SO42SO_4^{2-}+6
  • CO32CO_3^{2-}+4

Answer

The correct matches pair PO43PO_4^{3-} with +5+5, NO2NO_2^- with +3+3, SO42SO_4^{2-} with +6+6, and CO32CO_3^{2-} with +4+4.
Each central atom's oxidation state is determined by setting the sum of the oxidation states equal to the net ionic charge, using 2-2 for each oxygen atom.

Step-by-Step Solution

1
Assign the standard oxidation number of 2-2 to oxygen in oxoanions.
Each oxygen atom contributes an oxidation state of 2-2.
Oxygen is more electronegative than phosphorus, nitrogen, sulfur, and carbon.
2
Set up an algebraic sum where the total oxidation numbers equal the ion's net charge.
For PO43PO_4^{3-}: P+4(2)=3P + 4(-2) = -3; for NO2NO_2^-: N+2(2)=1N + 2(-2) = -1; for SO42SO_4^{2-}: S+4(2)=2S + 4(-2) = -2; for CO32CO_3^{2-}: C+3(2)=2C + 3(-2) = -2.
The sum of oxidation states in a polyatomic species equals the charge on the species.
3
Solve each linear equation for the oxidation number of the central atom.
P=+5P = +5, N=+3N = +3, S=+6S = +6, and C=+4C = +4.
Algebraic isolation of the unknown variable determines the oxidation state.

Key Concept

Assigning Oxidation Numbers in Polyatomic Oxoanions
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