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Question 381Question

In the xyxy-plane, the graph of the quadratic function f(x)=x2+6x+7f(x) = -x^2 + 6x + 7 has a vertex at (h,k)(h, k). If the graph of ff is translated 44 units to the right and 33 units up to produce the graph of the function gg, what is the maximum value of gg?

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Answer: 19

Answer

The maximum value of the function gg is 1919.
The vertex of the original quadratic function f(x)=x2+6x+7f(x) = -x^2 + 6x + 7 is (3,16)(3, 16). Since the coefficient of x2x^2 is negative, the graph opens downward, making 1616 the maximum value of the function. Translating the graph 33 units up shifts all yy-values up by 33, which increases the maximum value to 16+3=1916 + 3 = 19. The horizontal translation of 44 units to the right shifts the graph horizontally but does not affect the maximum output value.

Step-by-Step Solution

1
Find the vertex of the original quadratic function f(x)=x2+6x+7f(x) = -x^2 + 6x + 7.
The vertex of f(x)f(x) is (3,16)(3, 16).
Rewrite the function in vertex form, f(x)=(x3)2+16f(x) = -(x-3)^2 + 16, to identify the vertex (h,k)(h, k) as (3,16)(3, 16).
2
Determine the maximum value of the original function f(x)f(x).
The maximum value of f(x)f(x) is 1616.
Since the leading coefficient is negative, the parabola opens downward, and the maximum value occurs at the vertex's yy-coordinate.
3
Apply the vertical translation to find the maximum value of the new function g(x)g(x).
The maximum value of gg is 1919.
Translating the graph 33 units up increases all yy-values, including the maximum value, by 33, so 16+3=1916 + 3 = 19. The horizontal translation of 44 units to the right does not affect the maximum value.

Key Concept

Quadratic Functions and Graphs
Question 382Question

The equation 2x+12x=6\sqrt{2x + 12} - x = -6 has one real solution. What is this solution?

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Answer: 12

Answer

12
Substituting 12 into the original equation 2x+12x=6\sqrt{2x + 12} - x = -6 yields 2(12)+1212=3612=612=6\sqrt{2(12) + 12} - 12 = \sqrt{36} - 12 = 6 - 12 = -6. Since this creates a true statement, 12 is the unique real solution to the equation.

Step-by-Step Solution

1
Isolate the radical term by adding xx to both sides of the equation.
2x+12=x6\sqrt{2x + 12} = x - 6
Isolating the radical on one side allows us to eliminate it by squaring both sides in the next step.
2
Square both sides of the equation to clear the square root.
2x+12=(x6)22x + 12 = (x - 6)^2
Squaring a square root cancels the radical, allowing us to solve the equation algebraically.
3
Expand the squared binomial on the right-hand side.
2x+12=x212x+362x + 12 = x^2 - 12x + 36
Expanding (x6)2(x - 6)^2 to x212x+36x^2 - 12x + 36 helps set up a standard quadratic form.
4
Subtract 2x2x and 1212 from both sides to form a quadratic equation equal to zero.
x214x+24=0x^2 - 14x + 24 = 0
A quadratic equation must be in the form ax2+bx+c=0ax^2 + bx + c = 0 to solve by factoring or the quadratic formula.
5
Factor the quadratic equation.
(x12)(x2)=0(x - 12)(x - 2) = 0
Factoring finds two numbers that multiply to 24 and add to -14, which are -12 and -2.
6
Test the potential solutions x=12x = 12 and x=2x = 2 in the original equation to identify any extraneous solutions.
For x=2x = 2: 2(2)+122=162=42=26\sqrt{2(2) + 12} - 2 = \sqrt{16} - 2 = 4 - 2 = 2 \neq -6. For x=12x = 12: 2(12)+1212=3612=612=6\sqrt{2(12) + 12} - 12 = \sqrt{36} - 12 = 6 - 12 = -6. Thus, x=12x = 12 is the only valid solution.
Squaring both sides of an equation can introduce extraneous solutions that do not satisfy the original equation.

Key Concept

Solving radical equations by isolating the radical, squaring both sides, solving the resulting quadratic equation, and verifying all potential solutions to check for extraneous values.
Estimated Time:1m 30s
Question 383Question

A coffee roasting company uses a commercial roasting machine. The temperature of the roasting drum, TT, in degrees Fahrenheit (F^\circ\text{F}), is modeled as a linear function of the roasting time, tt, in minutes, where 0t100 \leq t \leq 10. After 22 minutes of roasting, the temperature of the drum is 280F280^\circ\text{F}. After 55 minutes of roasting, the temperature of the drum is 385F385^\circ\text{F}. What is the rate of temperature increase, in degrees Fahrenheit per minute, of the roasting drum?

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Answer: 35

Answer

The rate of temperature increase of the roasting drum is 3535 degrees Fahrenheit per minute.
The temperature, TT, is modeled as a linear function of time, tt. The constant rate of temperature increase corresponds to the slope of this linear function. Given two points, (2,280)(2, 280) and (5,385)(5, 385), the slope is calculated as the change in temperature divided by the change in time: 38528052=1053=35\frac{385 - 280}{5 - 2} = \frac{105}{3} = 35 degrees Fahrenheit per minute.

Step-by-Step Solution

1
Identify the coordinates representing the relationship between time and temperature.
The two points are (2,280)(2, 280) and (5,385)(5, 385), where the first coordinate is the time, tt, in minutes, and the second coordinate is the temperature, TT, in degrees Fahrenheit.
To find the rate of change of a linear relationship, we first need to determine two points (t1,T1)(t_1, T_1) and (t2,T2)(t_2, T_2) from the given context.
2
Calculate the rate of temperature increase as the slope of the line passing through these two points.
The slope mm is given by m=38528052=1053=35m = \frac{385 - 280}{5 - 2} = \frac{105}{3} = 35.
The rate of temperature increase per minute is the constant slope of the linear relationship.

Key Concept

Slope of a linear relationship in context
Question 384Question

The function ff is defined by f(x)=x33x210x+kf(x) = x^3 - 3x^2 - 10x + k, where kk is a constant. In the xyxy-plane, the graph of y=f(x)y = f(x) has xx-intercepts at (c,0)(c, 0) and (2c,0)(2c, 0), where cc is a positive constant. What is the value of kk?

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Answer: 24

Answer

24
By applying the factor theorem to the two xx-intercepts (c,0)(c,0) and (2c,0)(2c,0), we establish the system c33c210c+k=0c^3 - 3c^2 - 10c + k = 0 and 8c312c220c+k=08c^3 - 12c^2 - 20c + k = 0. Subtracting these equations yields 7c39c210c=07c^3 - 9c^2 - 10c = 0. Since c>0c > 0, dividing by cc gives 7c29c10=07c^2 - 9c - 10 = 0, which factors as (7c+5)(c2)=0(7c+5)(c-2)=0, yielding the positive solution c=2c=2. Substituting c=2c=2 back into the first equation gives 81220+k=08 - 12 - 20 + k = 0, which solves to k=24k = 24.

Step-by-Step Solution

1
Set up equations for the roots cc and 2c2c using the factor theorem.
f(c)=c33c210c+k=0f(c) = c^3 - 3c^2 - 10c + k = 0 and f(2c)=8c312c220c+k=0f(2c) = 8c^3 - 12c^2 - 20c + k = 0
An xx-intercept at (r,0)(r, 0) means that rr is a root of the polynomial, so f(r)=0f(r) = 0.
2
Subtract the first equation from the second to eliminate the constant kk.
7c39c210c=07c^3 - 9c^2 - 10c = 0
Eliminating kk allows us to solve for the root cc directly.
3
Solve the polynomial equation for the positive constant cc.
c=2c = 2
Dividing the equation by cc (since c>0c > 0) yields 7c29c10=07c^2 - 9c - 10 = 0, which factors as (7c+5)(c2)=0(7c+5)(c-2) = 0. Since cc must be positive, c=2c = 2.
4
Substitute c=2c = 2 back into the equation for f(c)=0f(c) = 0 to solve for kk.
k=24k = 24
Substituting the known root value allows us to find the value of the constant coefficient kk.

Key Concept

The relationship between a polynomial's algebraic factors, its roots, and its xx-intercepts in the coordinate plane.
Estimated Time:2m 0s
Question 385Question

A deep space satellite transmits data to a ground station at a constant rate of 1.61.6 megabits per second. The transmitted data consists of actual scientific data and protocol overhead. The protocol overhead accounts for 25%25\% of the total transmitted bits, meaning the actual scientific data constitutes only 75%75\% of the total transmitted bits. The ground station needs to receive 55 scientific data files, each with a size of 1.081.08 gigabytes. How many hours will it take to transmit all 55 files? (Given that 1textbyte=8textbits1\\text{ byte} = 8\\text{ bits}, 1textmegabit=106textbits1\\text{ megabit} = 10^6\\text{ bits}, and 1textgigabyte=109textbytes1\\text{ gigabyte} = 10^9\\text{ bytes}.)

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Answer: 10

Answer

It will take 10 hours to transmit all 5 files.
The correct answer is 10. To find this, first calculate the total size of the scientific files: 5 files * 1.08 gigabytes per file = 5.4 gigabytes. Convert this to bytes: 5.4 * 10^9 bytes. Convert bytes to bits: 5.4 * 10^9 * 8 = 43.2 * 10^9 bits. Since protocol overhead is 25%, the scientific data is 75% of the total transmitted bits, so the total bits transmitted is 43.2 * 10^9 / 0.75 = 57.6 * 10^9 bits. The transmission rate is 1.6 megabits per second, or 1.6 * 10^6 bits per second. The transmission time in seconds is 57.6 * 10^9 / (1.6 * 10^6) = 36,000 seconds. Converting seconds to hours: 36,000 / 3,600 = 10 hours.

Step-by-Step Solution

1
Calculate the total size of the scientific files in gigabytes.
5.45.4 gigabytes
To find the total amount of scientific data that must be received.
2
Convert the total scientific data size from gigabytes to bytes and then to bits.
43.2times10943.2 \\times 10^9 bits
The transmission rate is given in megabits per second, so the data size must be converted to bits for unit consistency. Since 1textGB=109textbytes1\\text{ GB} = 10^9\\text{ bytes} and 1textbyte=8textbits1\\text{ byte} = 8\\text{ bits}, we have 5.4times109times8=43.2times1095.4 \\times 10^9 \\times 8 = 43.2 \\times 10^9 bits.
3
Calculate the total number of bits transmitted, including protocol overhead.
57.6times10957.6 \\times 10^9 bits
Since protocol overhead is 25%25\%, the scientific data is only 75%75\% of the total bits transmitted. Thus, we divide the scientific bits by 0.750.75 to find the total bits transmitted: frac43.2times1090.75=57.6times109\\frac{43.2 \\times 10^9}{0.75} = 57.6 \\times 10^9 bits.
4
Calculate the transmission time in seconds.
36,00036,000 seconds
Divide the total bits by the transmission rate in bits per second (1.6textMbps=1.6times1061.6\\text{ Mbps} = 1.6 \\times 10^6 bits per second): frac57.6times1091.6times106=36,000\\frac{57.6 \\times 10^9}{1.6 \\times 10^6} = 36,000 seconds.
5
Convert the transmission time from seconds to hours.
1010 hours
Since there are 3,6003,600 seconds in one hour, divide the total seconds by 3,6003,600: frac36,0003,600=10\\frac{36,000}{3,600} = 10.

Key Concept

Multi-step dimensional analysis and compound rate conversions incorporating percentage overhead

Alternative Method

Instead of converting units step-by-step, dimensional analysis can be set up as a single product of conversion factors: 5 files * (1.08 GB / 1 file) * (10^9 bytes / 1 GB) * (8 bits / 1 byte) * (1 total bit / 0.75 scientific bits) * (1 second / 1.6 * 10^6 bits) * (1 hour / 3600 seconds) = 10 hours.
Estimated Time:3m 0s
Question 386Question

If 4x+38x1=163x\frac{4^{x+3}}{8^{x-1}} = 16^{3-x}, what is the value of xx?

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Answer: 1

Answer

1
The correct answer is 1. By writing all terms with a base of 2, the equation is expressed as (22)x+3(23)x1=(24)3x\frac{(2^2)^{x+3}}{(2^3)^{x-1}} = (2^4)^{3-x}. Applying the power rule to simplify the exponents yields 22x+623x3=2124x\frac{2^{2x+6}}{2^{3x-3}} = 2^{12-4x}. Using the quotient rule, we subtract the exponents on the left-hand side to get 2(2x+6)(3x3)=2x+92^{(2x+6)-(3x-3)} = 2^{-x+9}. Equating the exponents gives the linear equation x+9=124x-x+9 = 12-4x. Adding 4x4x and subtracting 99 from both sides results in 3x=33x = 3, which simplifies to x=1x=1.

Step-by-Step Solution

1
Express all exponential terms using a common base of 2
(22)x+3(23)x1=(24)3x\frac{(2^2)^{x+3}}{(2^3)^{x-1}} = (2^4)^{3-x}
Rewriting each base as a power of 2 allows the application of standard exponent rules.
2
Apply the power of a power rule (am)n=amn(a^m)^n = a^{mn} to distribute the exponents
22x+623x3=2124x\frac{2^{2x+6}}{2^{3x-3}} = 2^{12-4x}
Multiplying the inner exponent by each term of the outer exponent simplifies the expression.
3
Apply the quotient of powers rule aman=amn\frac{a^m}{a^n} = a^{m-n} to combine the fraction
2x+9=2124x2^{-x+9} = 2^{12-4x}
Subtracting the exponent in the denominator from the exponent in the numerator simplifies the left-hand side.
4
Equate the exponents since the bases are equal
x+9=124x-x + 9 = 12 - 4x
If two exponential expressions with the same positive base are equal, their exponents must be equal.
5
Solve the linear equation for xx
x=1x = 1
Isolating xx by algebraic manipulation yields the final answer.

Key Concept

Solving exponential equations by finding a common base and applying the laws of exponents.
Question 387Question

The graph of a linear equation in the xyxy-plane has an xx-intercept of (k,0)(k, 0) and a yy-intercept of (0,3k)(0, 3k), where kk is a positive constant. If the line passes through the point (2,12)(2, 12), what is the value of kk?

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Answer: 6

Answer

The value of kk is 66.
The correct answer is 66. The slope of the line can be found using the two intercepts (k,0)(k, 0) and (0,3k)(0, 3k): m=3k00k=3m = \frac{3k - 0}{0 - k} = -3. The equation of the line in slope-intercept form is y=3x+3ky = -3x + 3k. Since the line passes through the point (2,12)(2, 12), we substitute x=2x = 2 and y=12y = 12 into the equation to get 12=3(2)+3k12 = -3(2) + 3k. Simplifying the equation yields 12=6+3k12 = -6 + 3k, which gives 18=3k18 = 3k. Dividing both sides by 33 results in k=6k = 6.

Step-by-Step Solution

1
Find the slope of the line using the xx-intercept (k,0)(k, 0) and the yy-intercept (0,3k)(0, 3k).
The slope of the line is 3-3.
The slope formula is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the points (k,0)(k, 0) and (0,3k)(0, 3k) gives m=3k00k=3kk=3m = \frac{3k - 0}{0 - k} = \frac{3k}{-k} = -3.
2
Write the equation of the line in slope-intercept form.
The equation of the line is y=3x+3ky = -3x + 3k.
Using the slope-intercept form y=mx+by = mx + b, we substitute the slope m=3m = -3 and the yy-intercept value b=3kb = 3k from the point (0,3k)(0, 3k).
3
Substitute the given point (2,12)(2, 12) into the equation and solve for kk.
The value of kk is 66.
Substituting x=2x = 2 and y=12y = 12 into y=3x+3ky = -3x + 3k yields 12=3(2)+3k12 = -3(2) + 3k. This simplifies to 12=6+3k12 = -6 + 3k. Adding 66 to both sides gives 18=3k18 = 3k, and dividing by 33 gives k=6k = 6.

Key Concept

Linear equations in two variables, finding equations from intercepts, and constant determination via point substitution.
Question 388Question

The table below shows the daily high temperatures, in degrees Celsius, recorded in a city over a 99-day period.

Daily High Temperature (°C)Number of Days
181833
191911
202022
212133

Based on the table, what was the median daily high temperature, in degrees Celsius, for the 99-day period?

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Answer: 20

Answer

The median daily high temperature for the 9-day period is 2020 °C.
To find the median daily high temperature, we first sum the frequencies to find the total number of days: 3+1+2+3=93 + 1 + 2 + 3 = 9. Because 99 is an odd number, the median is the middle value, which is the 55 th value when the data points are ordered from least to greatest. The first 33 values are 1818, the 44 th value is 1919, and the 55 th and 66 th values are 2020. Therefore, the 55 th value in the ordered list is 2020.

Step-by-Step Solution

1
Determine the total number of observations (days) in the data set.
99 days
To find the position of the median value, we must first calculate the total number of data points by adding the frequencies: 3+1+2+3=93 + 1 + 2 + 3 = 9.
2
Find the position of the median in the ordered data set.
55 th position
For an odd number of observations nn, the median is located at the n+12\frac{n+1}{2} position. With n=9n = 9, this corresponds to the 9+12=5\frac{9+1}{2} = 5 th value.
3
Identify the temperature at the 55 th position using the frequency table.
2020
Listing the temperatures in ascending order gives: 18,18,1818, 18, 18 (positions 1–3), 1919 (position 4), and 20,2020, 20 (positions 5–6). The value at the 55 th position is 2020.

Key Concept

Finding the median of a frequency distribution
Question 389Question

A library administrator tracked a sample of 120120 books checked out last week, categorizing them by genre (fiction or nonfiction) and format (print or audiobook). The results are summarized in the table below.

FormatFictionNonfiction
Print45453535
Audiobook15152525

Of the books in the sample that were checked out as audiobooks, what fraction were fiction?

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Answer: 0.375

Answer

The fraction of audiobooks that were fiction is 3/8 (which can also be gridded as the decimal .375).
To find the fraction of audiobooks that were fiction, find the total number of audiobooks in the sample by adding the values in the audiobook row: 15+25=4015 + 25 = 40. Next, find the number of fiction audiobooks, which is 1515. The fraction of audiobooks that were fiction is the ratio of these two values: 1540\frac{15}{40}, which simplifies to 38\frac{3}{8} (or 0.3750.375 in decimal form).

Step-by-Step Solution

1
Calculate the total number of audiobooks in the sample.
The total number of audiobooks is 15+25=4015 + 25 = 40.
The question asks for the fraction of books *that were checked out as audiobooks*, which means the denominator of our fraction must be the total number of audiobooks.
2
Identify the number of fiction audiobooks in the sample.
There are 1515 fiction audiobooks.
The question asks what fraction of the audiobooks were *fiction*, so the numerator must be the number of books that are both audiobooks and fiction.
3
Write and simplify the fraction representing the conditional probability.
1540=38\frac{15}{40} = \frac{3}{8}
Divide the target number of books (15) by the total number of audiobooks (40). Simplify by dividing the numerator and the denominator by their greatest common divisor, which is 5.

Key Concept

Conditional Probability from a Two-Way Table
Estimated Time:1m 15s
Question 390Question

In the quadratic equation 2x2bx+18=02x^2 - bx + 18 = 0, bb is a positive constant. If one of the solutions to the equation is 44 times the other solution, what is the value of bb?

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Answer: 15

Answer

15
By Vieta's formulas, the product of the roots of the quadratic equation 2x2bx+18=02x^2 - bx + 18 = 0 is 182=9\frac{18}{2} = 9. Letting the roots be r1r_1 and r2r_2 with r1=4r2r_1 = 4r_2, we have 4r22=94r_2^2 = 9, which yields r2=32r_2 = \frac{3}{2} (since b>0b > 0 implies the roots must be positive). Thus, r1=6r_1 = 6. The sum of the roots is 6+32=1526 + \frac{3}{2} = \frac{15}{2}, and by Vieta's formulas, this sum equals b2\frac{b}{2}. Solving for bb gives 1515.

Step-by-Step Solution

1
Set up the relationships for the product and sum of the roots using Vieta's formulas.
r1r2=9r_1 \cdot r_2 = 9 and r1+r2=b2r_1 + r_2 = \frac{b}{2}
Vieta's formulas relate the coefficients of a quadratic equation to the sum and product of its roots.
2
Substitute the given condition that one root is 44 times the other (r1=4r2r_1 = 4r_2) into the product equation.
4r22=94r_2^2 = 9
This reduces the product equation to a single variable equation in terms of r2r_2.
3
Solve for r2r_2 and determine its sign based on the constraint that bb is positive.
r2=32r_2 = \frac{3}{2}
Since b>0b > 0, the sum of the roots 5r2=b25r_2 = \frac{b}{2} must be positive, which requires r2>0r_2 > 0.
4
Calculate the second root r1r_1 and then use the sum of the roots to find bb.
b=15b = 15
The sum of the roots is 6+32=1526 + \frac{3}{2} = \frac{15}{2}, and since r1+r2=b2r_1 + r_2 = \frac{b}{2}, we have b2=152\frac{b}{2} = \frac{15}{2}.

Key Concept

Relationship between roots and coefficients of a quadratic equation
Question 391Question

A digital music playlist contains only rock songs and pop songs. At the beginning of the month, 60%60\% of the songs in the playlist were rock songs. During the month, the number of rock songs in the playlist increased by 10%10\%, and the number of pop songs in the playlist increased by 35%35\%. If there were 120120 rock songs in the playlist at the beginning of the month, what percent of the songs in the playlist at the end of the month were pop songs?

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Answer: 45

Answer

The percent of the songs in the playlist at the end of the month that were pop songs is 45.
To find the final percentage of pop songs, we first determine the initial number of songs. Since 120120 rock songs represent 60%60\% of the playlist, the initial total is 120/0.60=200120 / 0.60 = 200 songs. This means there are 200120=80200 - 120 = 80 pop songs initially. During the month, the rock songs increase by 10%10\%, yielding 120×1.10=132120 \times 1.10 = 132 songs. The pop songs increase by 35%35\%, yielding 80×1.35=10880 \times 1.35 = 108 songs. The final total number of songs is 132+108=240132 + 108 = 240. The final percentage of pop songs is 108240×100=45%\frac{108}{240} \times 100 = 45\%. Thus, the correct value to grid in is 45.

Step-by-Step Solution

1
Determine the initial total number of songs and initial pop songs.
The initial total number of songs is 200, and the initial number of pop songs is 80.
Since 120 rock songs represent 60% of the playlist, the initial total is 120 / 0.60 = 200. The remaining songs are pop songs: 200 - 120 = 80.
2
Calculate the updated number of rock songs and pop songs after the percentage increases.
The final rock song count is 132, and the final pop song count is 108.
The number of rock songs increased by 10%, which is 120 * 1.10 = 132. The number of pop songs increased by 35%, which is 80 * 1.35 = 108.
3
Calculate the final total number of songs and the final percentage of pop songs.
The final total is 240 songs, and the final pop song percentage is 45%.
The final total is 132 + 108 = 240. The final pop song percentage is (108 / 240) * 100 = 45%.

Key Concept

Calculating absolute quantities from initial percentages, applying percentage increases to separate groups, and finding a new conditional percentage based on the final total.
Question 392Question

An industrial printing press uses ink at a constant rate of 0.050.05 milliliters per square centimeter of printed paper. The press prints a continuous roll of paper that is 4040 centimeters wide at a constant speed of 22 meters per second. At this rate, how many liters of ink does the press use during 11 hour of continuous printing?

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Answer: 1440

Answer

1440
The correct answer is 1440. First, convert the speed of the paper from meters per second to centimeters per second: 2 m/s×100 cm/m=200 cm/s2 \text{ m/s} \times 100 \text{ cm/m} = 200 \text{ cm/s}. Next, find the rate at which the paper surface area is printed: 40 cm×200 cm/s=8,000 cm2/s40 \text{ cm} \times 200 \text{ cm/s} = 8,000 \text{ cm}^2/\text{s}. Multiply this by the ink usage rate to find milliliters of ink per second: 8,000 cm2/s×0.05 mL/cm2=400 mL/s8,000 \text{ cm}^2/\text{s} \times 0.05 \text{ mL/cm}^2 = 400 \text{ mL/s}. Since there are 3,6003,600 seconds in 11 hour, the press uses 400 mL/s×3,600 s=1,440,000 mL400 \text{ mL/s} \times 3,600 \text{ s} = 1,440,000 \text{ mL} of ink per hour. Finally, convert milliliters to liters: 1,440,000 mL÷1,000 mL/L=1,4401,440,000 \text{ mL} \div 1,000 \text{ mL/L} = 1,440 liters.

Step-by-Step Solution

1
Convert the speed of the paper from meters per second to centimeters per second.
200 cm/s200 \text{ cm/s}
To align the speed unit with the paper width unit (40 cm40 \text{ cm}).
2
Calculate the surface area of paper printed per second.
8,000 cm2/s8,000 \text{ cm}^2/\text{s}
Multiply the width of the paper (40 cm40 \text{ cm}) by the converted speed (200 cm/s200 \text{ cm/s}).
3
Calculate the volume of ink used per second in milliliters.
400 mL/s400 \text{ mL/s}
Multiply the area printed per second (8,000 cm2/s8,000 \text{ cm}^2/\text{s}) by the ink consumption rate (0.05 mL/cm20.05 \text{ mL/cm}^2).
4
Convert the ink volume rate from per second to per hour.
1,440,000 mL/h1,440,000 \text{ mL/h}
Multiply the rate per second by 3,6003,600, since there are 3,6003,600 seconds in 11 hour.
5
Convert the final volume from milliliters to liters.
1440
Divide the total milliliters (1,440,0001,440,000) by 1,0001,000, since 11 liter is equal to 1,0001,000 milliliters.

Key Concept

Multi-step dimensional analysis and compound unit conversion (length, area, volume, and time).
Question 393Question

A town's population was 12,00012,000 in the year 20102010. Since 20102010, the population of the town has increased by a constant amount of 350350 people each year. Based on this information, what was the population of the town in the year 20182018?

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Answer: 14800

Answer

14,800
The population starts at 12,00012,000 in 20102010 and grows linearly by 350350 people per year. The number of years from 20102010 to 20182018 is 20182010=82018 - 2010 = 8 years. The total increase in population is 350×8=2,800350 \times 8 = 2,800 people. Adding this to the initial population of 12,00012,000 gives a total population of 12,000+2,800=14,80012,000 + 2,800 = 14,800 in the year 20182018.

Step-by-Step Solution

1
Calculate the number of years that passed between 20102010 and 20182018.
88 years
To determine the total population growth, we need the elapsed time in years.
2
Calculate the total population growth over this 88-year period.
2,8002,800 people
Since the growth is linear, the total growth is the constant annual rate of change multiplied by the number of years.
3
Add the total population growth to the initial population from 20102010.
14,80014,800
The population in 20182018 is the initial population plus the total growth over the 88-year period.

Key Concept

Linear growth represents a quantity that increases by a constant amount per unit of time.
Question 394Question

An online retailer offers free shipping on orders of 75ormore.Acustomerhasplacedashirtcosting75 or more. A customer has placed a shirt costing 22.50 and a pair of pants costing 34.80intheirshoppingcart.Theywanttobuysomepairsofsocksthatcost34.80 in their shopping cart. They want to buy some pairs of socks that cost 4.50 per pair to qualify for free shipping. What is the minimum number of pairs of socks the customer must add to their cart to qualify for free shipping?

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Answer: 4

Answer

The minimum number of pairs of socks the customer must add to the cart is 4.
The customer needs to spend at least 75toqualifyforfreeshipping.Thecurrentsubtotalofthecartis75 to qualify for free shipping. The current subtotal of the cart is 22.50 + 34.80=34.80 = 57.30. The remaining amount needed to reach 75is75 is 75.00 - 57.30=57.30 = 17.70. Let ss represent the number of pairs of socks purchased at 4.50perpair.Thiscanberepresentedbytheinequality4.50 per pair. This can be represented by the inequality 4.50s \geq 17.70 .Dividingbothsidesoftheinequalityby. Dividing both sides of the inequality by 4.50 gives gives s \geq 3.93$. Since the customer cannot purchase a fraction of a pair of socks, the minimum number of pairs of socks they must purchase is 4.

Step-by-Step Solution

1
Calculate the total cost of the items already in the shopping cart.
22.50+22.50 + 34.80 = $57.30
To determine how much has already been spent before adding socks.
2
Set up an inequality to represent the total cost of the order including ss pairs of socks meeting the free shipping threshold of $75.
57.30+4.50s7557.30 + 4.50s \geq 75
The total cost of the shirt, pants, and socks must be greater than or equal to $75.
3
Subtract $57.30 from both sides of the inequality to find the minimum amount that needs to be spent on socks.
4.50s17.704.50s \geq 17.70
To isolate the term representing the cost of the socks.
4
Divide both sides of the inequality by $4.50 to find the minimum number of pairs of socks.
s3.93s \geq 3.93
To isolate the variable representing the number of pairs of socks.
5
Determine the smallest integer value of ss that satisfies the inequality.
4
The number of pairs of socks must be a whole number, and 4 is the smallest integer greater than or equal to 3.93.

Key Concept

Solving linear inequalities in one variable to find the minimum integer solution in a real-world context.
Estimated Time:1m 30s
Question 395Question

A quadratic function ff has a vertex at (h,k)(h, k), where hh and kk are constants. In the xyxy-plane, the graph of y=f(x)y = f(x) contains the points (1,3)(-1, 3) and (7,3)(7, 3). The function gg is defined by g(x)=f(x+2)4g(x) = f(x + 2) - 4, and its graph has a vertex at (p,q)(p, q). If p+q=5p + q = 5, what is the value of kk?

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Answer: 8

Answer

The value of k is 8.
The axis of symmetry of the quadratic function f is located at the midpoint of the x-values of any two points on the graph that have the same y-value. Since the graph of f contains (-1, 3) and (7, 3), the x-coordinate of its vertex, h, is equal to the midpoint (-1 + 7) / 2 = 3. Thus, the vertex of f is (3, k). The definition of g(x) = f(x + 2) - 4 indicates a horizontal translation of 2 units to the left and a vertical translation of 4 units down. Applying these translations to the vertex (3, k) of f gives the vertex of g as (3 - 2, k - 4) = (1, k - 4). Since the vertex of g is defined as (p, q), we have p = 1 and q = k - 4. Substituting these values into the equation p + q = 5 yields 1 + (k - 4) = 5, which simplifies to k - 3 = 5, or k = 8.

Step-by-Step Solution

1
Find the x-coordinate of the vertex of the function f
h = 3
Because the points (-1, 3) and (7, 3) have the same y-coordinate, the axis of symmetry (and thus the x-coordinate of the vertex) must lie exactly halfway between x = -1 and x = 7.
2
Determine the vertex of the function g(x)
(p, q) = (1, k - 4)
The function g(x) = f(x + 2) - 4 represents a translation of the graph of f by 2 units to the left and 4 units down. Since the vertex of f is (3, k), the vertex of g is (3 - 2, k - 4).
3
Solve for k using the given sum p + q = 5
k = 8
Substitute p = 1 and q = k - 4 into the equation p + q = 5 to get 1 + k - 4 = 5, which simplifies to k = 8.

Key Concept

Quadratic functions and graphs, including symmetry and translations.
Question 396Question

A quadratic function ff is defined by f(x)=a(x4)(x10)f(x) = a(x - 4)(x - 10), where aa is a positive constant. In the xyxy-plane, the graph of ff has a vertex with a yy-coordinate of 18-18. What is the value of aa?

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Answer: 2

Answer

The value of aa is 2.
The vertex of a parabola lies on the axis of symmetry, which is located midway between its x-intercepts. Since the function is f(x)=a(x4)(x10)f(x) = a(x - 4)(x - 10), the x-intercepts are at x=4x = 4 and x=10x = 10. The midpoint of these values is 4+102=7\frac{4 + 10}{2} = 7. Thus, the x-coordinate of the vertex is 7. Since the y-coordinate of the vertex is given as 18-18, the vertex is at (7,18)(7, -18). Substituting these coordinates into the function equation yields 18=a(74)(710)-18 = a(7 - 4)(7 - 10), which simplifies to 18=a(3)(3)-18 = a(3)(-3), or 18=9a-18 = -9a. Solving for aa gives a=2a = 2.

Step-by-Step Solution

1
Find the x-coordinate of the vertex using the symmetry of the parabola.
The x-coordinate of the vertex is 7.
The x-coordinate of the vertex lies on the axis of symmetry, which is the midpoint of the x-intercepts x=4x = 4 and x=10x = 10.
2
Identify the coordinates of the vertex.
The vertex is at (7,18)(7, -18).
The y-coordinate of the vertex is given as 18-18, and its x-coordinate was calculated as 7.
3
Substitute the vertex coordinates into the function definition to solve for aa.
a=2a = 2
Substituting (7,18)(7, -18) into f(x)=a(x4)(x10)f(x) = a(x - 4)(x - 10) gives 18=a(74)(710)-18 = a(7 - 4)(7 - 10), which simplifies to 18=9a-18 = -9a.

Key Concept

Finding the vertex of a quadratic function from its factored form and solving for a leading coefficient.

Alternative Method

Alternatively, the function f(x)=a(x4)(x10)f(x) = a(x - 4)(x - 10) can be expanded to standard form: f(x)=a(x214x+40)f(x) = a(x^2 - 14x + 40). The x-coordinate of the vertex can be found using the formula x=b2ax = -\frac{b}{2a}, which gives x=14a2a=7x = -\frac{-14a}{2a} = 7. Then, substitute x=7x = 7 and f(7)=18f(7) = -18 to solve for aa.
Estimated Time:1m 30s
Question 397Question

A quadratic function ff has its vertex at (4,3)(4, -3) in the coordinate plane. The point (2,5)(2, 5) is on the graph of y=f(x)y = f(x). The function gg is defined by g(x)=f(x3)+8g(x) = -f(x - 3) + 8. What is the value of g(8)g(8)?

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Answer: 9

Answer

The correct answer is 9.
The correct answer is 9. To find this, we first establish the vertex form of the quadratic function f(x)=a(x4)23f(x) = a(x - 4)^2 - 3. Substituting the point (2,5)(2, 5) gives 5=a(24)235 = a(2 - 4)^2 - 3, which simplifies to 8=4a8 = 4a, so a=2a = 2. Thus, f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3. To find the value of g(8)g(8), we substitute 88 into the definition of g(x)g(x), yielding g(8)=f(83)+8=f(5)+8g(8) = -f(8 - 3) + 8 = -f(5) + 8. Evaluating f(5)f(5) gives 2(54)23=12(5 - 4)^2 - 3 = -1. Finally, substituting 1-1 back into the expression for g(8)g(8) gives (1)+8=9-(-1) + 8 = 9.

Step-by-Step Solution

1
Write the quadratic function f(x)f(x) in vertex form using its vertex (4,3)(4, -3).
f(x)=a(x4)23f(x) = a(x - 4)^2 - 3
The vertex form of a quadratic function with vertex (h,k)(h, k) is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k.
2
Substitute the coordinates of the point (2,5)(2, 5) into the vertex form to find the value of the constant aa.
a=2a = 2, so f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3
Since the point (2,5)(2, 5) lies on the graph of ff, substituting x=2x = 2 and f(2)=5f(2) = 5 allows us to solve for the vertical stretch factor aa.
3
Use the definition of g(x)g(x) to express g(8)g(8) in terms of ff.
g(8)=f(5)+8g(8) = -f(5) + 8
Substituting x=8x = 8 into the equation g(x)=f(x3)+8g(x) = -f(x - 3) + 8 yields g(8)=f(83)+8=f(5)+8g(8) = -f(8 - 3) + 8 = -f(5) + 8.
4
Evaluate f(5)f(5) using the equation for f(x)f(x) found in Step 2.
f(5)=1f(5) = -1
Substituting x=5x = 5 into f(x)=2(x4)23f(x) = 2(x - 4)^2 - 3 gives 2(54)23=2(1)3=12(5 - 4)^2 - 3 = 2(1) - 3 = -1.
5
Substitute the value of f(5)f(5) into the expression for g(8)g(8) to find the final result.
g(8)=9g(8) = 9
Substituting f(5)=1f(5) = -1 into g(8)=f(5)+8g(8) = -f(5) + 8 yields (1)+8=1+8=9-(-1) + 8 = 1 + 8 = 9.

Key Concept

Finding the equation of a quadratic function from its vertex and a point, and evaluating transformed functions using function notation.
Question 398Question

In the equation 25x5x3=1252\frac{25^x}{5^{x-3}} = 125^2, what is the value of xx?

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Answer: 3

Answer

The correct answer is 3.
By writing all terms with a base of 5, the equation 25x5x3=1252\frac{25^x}{5^{x-3}} = 125^2 becomes 52x5x3=56\frac{5^{2x}}{5^{x-3}} = 5^6. Applying the quotient rule of exponents, the left side simplifies to 52x(x3)=5x+35^{2x - (x-3)} = 5^{x+3}. Setting the exponents equal gives x+3=6x+3 = 6, which yields x=3x = 3.

Step-by-Step Solution

1
Express all terms with a common base of 5.
25x=(52)x=52x25^x = (5^2)^x = 5^{2x} and 1252=(53)2=56125^2 = (5^3)^2 = 5^6.
Expressing all exponential terms with the same base allows the exponents to be equated directly once simplified.
2
Substitute these expressions back into the original equation and simplify the left side using the quotient rule of exponents.
52x5x3=52x(x3)=5x+3\frac{5^{2x}}{5^{x-3}} = 5^{2x - (x-3)} = 5^{x+3}. The equation becomes 5x+3=565^{x+3} = 5^6.
The quotient rule states that dividing exponential terms with the same base requires subtracting the exponent of the denominator from the exponent of the numerator: bmbn=bmn\frac{b^m}{b^n} = b^{m-n}.
3
Equate the exponents and solve for xx.
x+3=6    x=3x + 3 = 6 \implies x = 3.
Since the bases on both sides of the equation are equal, their exponents must also be equal: if by=bzb^y = b^z where b>0b > 0 and b1b \neq 1, then y=zy = z.

Key Concept

Solving exponential equations by expressing terms with a common base and applying exponent rules.
Estimated Time:1m 30s
Question 399Question

A biologist measures the heights, in centimeters, of five seedlings in a laboratory. The heights are 1212, 1515, 88, 2121, and 1414. What is the range, in centimeters, of these heights?

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Answer: 13

Answer

13
To find the range of a dataset, subtract the minimum value from the maximum value. In the given dataset of seedling heights (1212, 1515, 88, 2121, and 1414), the maximum height is 2121 centimeters and the minimum height is 88 centimeters. Calculating the difference gives 218=1321 - 8 = 13 centimeters.

Step-by-Step Solution

1
Identify the maximum and minimum values in the dataset.
The maximum value is 2121 and the minimum value is 88.
The range is defined as the difference between the largest (maximum) and smallest (minimum) values in a data distribution.
2
Subtract the minimum value from the maximum value to calculate the range.
218=1321 - 8 = 13
Subtracting the minimum value of 88 from the maximum value of 2121 yields the range of the dataset.

Key Concept

The range of a dataset measures the spread of the data and is calculated by subtracting the minimum value from the maximum value.
Question 400Question

An express delivery truck travels from Warehouse A to Warehouse B at a constant speed, and then returns from Warehouse B to Warehouse A along the same route at a different constant speed. On the first trip, the ratio of the outbound travel time to the inbound travel time is 33 to 55. On a second trip along the same route, the truck's outbound speed is 50%50\% greater than its outbound speed on the first trip, and its inbound speed is 25%25\% less than its inbound speed on the first trip. If the total round-trip travel time for the second trip is 1313 hours, what is the total round-trip travel time, in hours, for the first trip?

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Answer: 12

Answer

The total round-trip travel time for the first trip is 12 hours.
The correct answer is 1212. By setting the outbound and inbound travel times of the first trip as t1t_1 and t2t_2 with t1=0.6t2t_1 = 0.6t_2, we apply the inverse relationships of speed and time to express the second trip's times as t1=23t1t_1' = \frac{2}{3}t_1 and t2=43t2t_2' = \frac{4}{3}t_2. Substituting these into the second trip's total time equation 23t1+43t2=13\frac{2}{3}t_1 + \frac{4}{3}t_2 = 13 yields t2=7.5t_2 = 7.5 and t1=4.5t_1 = 4.5, summing to 1212 hours.

Step-by-Step Solution

1
Set up the ratio of outbound to inbound travel times for the first trip.
t1=0.6t2t_1 = 0.6t_2 (or t1=35t2t_1 = \frac{3}{5}t_2)
The ratio of the outbound travel time (t1t_1) to the inbound travel time (t2t_2) is given as 33 to 55.
2
Express the new travel times for the second trip (t1t_1' and t2t_2') in terms of the original travel times.
t1=23t1t_1' = \frac{2}{3}t_1 and t2=43t2t_2' = \frac{4}{3}t_2
For a constant distance, travel time is inversely proportional to speed. A 50%50\% speed increase multiplies time by 11.5=23\frac{1}{1.5} = \frac{2}{3}, and a 25%25\% speed decrease multiplies time by 10.75=43\frac{1}{0.75} = \frac{4}{3}.
3
Create an equation for the total travel time of the second trip.
23t1+43t2=13\frac{2}{3}t_1 + \frac{4}{3}t_2 = 13
The sum of the outbound and inbound travel times on the second trip is given as 1313 hours.
4
Substitute the first trip's relationship into the equation and solve for t2t_2.
t2=7.5t_2 = 7.5
Substituting t1=35t2t_1 = \frac{3}{5}t_2 gives 23(35t2)+43t2=13    2615t2=13    t2=13×1526=7.5\frac{2}{3}\left(\frac{3}{5}t_2\right) + \frac{4}{3}t_2 = 13 \implies \frac{26}{15}t_2 = 13 \implies t_2 = 13 \times \frac{15}{26} = 7.5.
5
Determine t1t_1 and calculate the total travel time for the first trip.
t1+t2=12t_1 + t_2 = 12
Since t2=7.5t_2 = 7.5, then t1=0.6(7.5)=4.5t_1 = 0.6(7.5) = 4.5. The total round-trip time is 4.5+7.5=124.5 + 7.5 = 12.

Key Concept

Inverse proportionality of speed and time, and solving linear systems involving ratios.
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