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Question 1841Question

In the xyxy-plane, the graph of the quadratic function f(x)=x24x5f(x) = x^2 - 4x - 5 intersects the xx-axis at the points (p,0)(p, 0) and (q,0)(q, 0) and has vertex (h,k)(h, k). What is the area of the triangle with vertices at (p,0)(p, 0), (q,0)(q, 0), and (h,k)(h, k)?

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Answer: 27

Answer

The area of the triangle is 27.
To find the area of the triangle, we first determine the coordinates of its vertices. The base of the triangle lies on the xx-axis, with endpoints at the xx-intercepts of the function f(x)=x24x5f(x) = x^2 - 4x - 5. Solving x24x5=0x^2 - 4x - 5 = 0 by factoring gives (x5)(x+1)=0(x - 5)(x + 1) = 0, so the intercepts are at x=1x = -1 and x=5x = 5. The distance between these two points is 5(1)=65 - (-1) = 6, which is the base of the triangle. The third vertex is the vertex of the parabola. The xx-coordinate of the vertex is h=b2a=42(1)=2h = -\frac{b}{2a} = -\frac{-4}{2(1)} = 2. Substituting x=2x = 2 into the function gives the yy-coordinate: k=f(2)=224(2)5=9k = f(2) = 2^2 - 4(2) - 5 = -9. The height of the triangle is the vertical distance from the xx-axis to the vertex, which is 9=9|-9| = 9. The area of the triangle is 12×base×height=12×6×9=27\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 6 \times 9 = 27.

Step-by-Step Solution

1
Find the xx-intercepts of the parabola.
The intercepts are (1,0)(-1, 0) and (5,0)(5, 0).
Setting f(x)=0f(x) = 0 gives x24x5=0x^2 - 4x - 5 = 0. Factoring the quadratic equation yields (x5)(x+1)=0(x - 5)(x + 1) = 0, which gives x=5x = 5 and x=1x = -1.
2
Calculate the base of the triangle.
The base length is 66.
The base of the triangle is the segment along the xx-axis between the two intercepts. The distance between (1,0)(-1, 0) and (5,0)(5, 0) is 5(1)=65 - (-1) = 6.
3
Find the vertex (h,k)(h, k) of the parabola.
The vertex is at (2,9)(2, -9).
The xx-coordinate of the vertex is the midpoint of the intercepts: h=1+52=2h = \frac{-1 + 5}{2} = 2. The yy-coordinate is k=f(2)=224(2)5=485=9k = f(2) = 2^2 - 4(2) - 5 = 4 - 8 - 5 = -9.
4
Calculate the area of the triangle.
The area is 2727.
The height of the triangle is the distance from the xx-axis to the vertex, which is k=9=9|k| = |-9| = 9. Using the formula for the area of a triangle, Area=12×base×height=12×6×9=27\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 6 \times 9 = 27.

Key Concept

Finding the xx-intercepts and vertex of a quadratic function to solve geometric problems in the coordinate plane.
Question 1842Question

The function ff is defined by f(x)=(x3)(x3kx2+5x15)f(x) = (x - 3)(x^3 - kx^2 + 5x - 15), where kk is a constant. In the xyxy-plane, the graph of y=f(x)y = f(x) is tangent to the xx-axis at the point (3,0)(3, 0). What is the value of kk?

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Answer: 3

Answer

3
For the graph of a polynomial function to be tangent to the xx-axis at (3,0)(3, 0), the root x=3x = 3 must have an even multiplicity (at least 2). The function is defined as f(x)=(x3)(x3kx2+5x15)f(x) = (x - 3)(x^3 - kx^2 + 5x - 15). Since there is already one factor of (x3)(x - 3) explicitly defined, the remaining cubic factor g(x)=x3kx2+5x15g(x) = x^3 - kx^2 + 5x - 15 must also have a factor of (x3)(x - 3) to make the total multiplicity of the root x=3x = 3 at least 2. According to the Factor Theorem, if (x3)(x - 3) is a factor of g(x)g(x), then g(3)=0g(3) = 0. Substituting x=3x = 3 into g(x)g(x) gives 33k(3)2+5(3)15=03^3 - k(3)^2 + 5(3) - 15 = 0, which simplifies to 279k=027 - 9k = 0. Solving this equation for kk yields k=3k = 3.

Step-by-Step Solution

1
Identify the relationship between graph tangency and factor multiplicity.
For the graph of a polynomial function to be tangent to the xx-axis at a point (c,0)(c, 0), the factor (xc)(x - c) must have an even multiplicity of at least 2 in the polynomial's factored form.
An odd multiplicity root causes the graph to cross the xx-axis, while an even multiplicity root causes the graph to touch the xx-axis and turn around (tangency).
2
Apply the multiplicity requirement to the given function.
Since f(x)=(x3)(x3kx2+5x15)f(x) = (x - 3)(x^3 - kx^2 + 5x - 15) already contains one factor of (x3)(x - 3), the cubic expression g(x)=x3kx2+5x15g(x) = x^3 - kx^2 + 5x - 15 must also contain (x3)(x - 3) as a factor to ensure the total multiplicity of the root x=3x = 3 is at least 2.
This guarantees that (x3)2(x - 3)^2 is a factor of f(x)f(x).
3
Apply the Factor Theorem to the cubic expression.
Since (x3)(x - 3) is a factor of g(x)g(x), then g(3)=0g(3) = 0.
The Factor Theorem states that a polynomial P(x)P(x) has a factor (xc)(x - c) if and only if P(c)=0P(c) = 0.
4
Solve for the constant kk by substituting x=3x = 3 into g(x)g(x).
33k(3)2+5(3)15=0    279k+1515=0    279k=0    9k=27    k=33^3 - k(3)^2 + 5(3) - 15 = 0 \implies 27 - 9k + 15 - 15 = 0 \implies 27 - 9k = 0 \implies 9k = 27 \implies k = 3.
Arithmetic simplification yields the value of the constant.

Key Concept

The relationship between polynomial factors, root multiplicities, and the behavior of the graph at xx-intercepts.
Question 1843Question

A polynomial function qq with real coefficients satisfies the equation q(x)+q(6x)=8q(x) + q(6-x) = 8 for all real numbers xx. In the xyxy-plane, the graph of y=q(x)y = q(x) has an xx-intercept at (5,0)(5, 0). What is the remainder when q(x)q(x) is divided by x1x-1?

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Answer: 88

Answer

The correct answer is 88, which is the remainder when the polynomial is divided by x1x-1.
To find the remainder when the polynomial q(x)q(x) is divided by x1x-1, we use the Remainder Theorem, which states that this remainder is equal to q(1)q(1). Since the graph of y=q(x)y = q(x) has an xx-intercept at (5,0)(5, 0), we know that q(5)=0q(5) = 0. Substituting x=5x = 5 into the given equation q(x)+q(6x)=8q(x) + q(6-x) = 8 yields q(5)+q(65)=8q(5) + q(6-5) = 8, which simplifies to q(5)+q(1)=8q(5) + q(1) = 8. Substituting q(5)=0q(5) = 0 into this equation gives 0+q(1)=80 + q(1) = 8, so q(1)=8q(1) = 8. Geometrically, the equation q(x)+q(6x)2=4\frac{q(x) + q(6-x)}{2} = 4 shows that the graph of qq is symmetric under a point reflection about (3,4)(3, 4). Reflecting the point (5,0)(5, 0) about (3,4)(3, 4) gives the point (1,8)(1, 8), verifying that q(1)=8q(1) = 8.

Step-by-Step Solution

1
Translate the given graphical intercept into function notation.
q(5)=0q(5) = 0
An xx-intercept at (5,0)(5, 0) means that when the input xx is 55, the output of the function is 00.
2
Apply the Remainder Theorem to the divisor x1x-1.
The remainder is equal to q(1)q(1).
The Remainder Theorem states that when a polynomial q(x)q(x) is divided by xax-a, the remainder is q(a)q(a).
3
Substitute x=5x = 5 into the given functional equation q(x)+q(6x)=8q(x) + q(6-x) = 8.
q(5)+q(65)=8    q(5)+q(1)=8q(5) + q(6-5) = 8 \implies q(5) + q(1) = 8
Substituting x=5x = 5 allows us to relate the known value q(5)q(5) directly to the target value q(1)q(1).
4
Solve for q(1)q(1) using the value of q(5)q(5).
0+q(1)=8    q(1)=80 + q(1) = 8 \implies q(1) = 8
Substituting q(5)=0q(5) = 0 into the equation yields the value of q(1)q(1), which is the remainder.

Key Concept

Remainder Theorem and Polynomial Graphs

Alternative Method

Use the point symmetry of the graph. The equation q(x)+q(6x)=8q(x) + q(6-x) = 8 can be rewritten as q(x)+q(6x)2=4\frac{q(x) + q(6-x)}{2} = 4. This indicates that the graph of y=q(x)y = q(x) has point symmetry about the point (3,4)(3, 4). Since the graph has an xx-intercept at (5,0)(5, 0), point symmetry dictates that the reflected point across (3,4)(3, 4) must also lie on the graph. The midpoint of (5,0)(5, 0) and the symmetric point (x0,y0)(x_0, y_0) is (3,4)(3, 4). Solving 5+x02=3\frac{5+x_0}{2} = 3 gives x0=1x_0 = 1, and 0+y02=4\frac{0+y_0}{2} = 4 gives y0=8y_0 = 8. Thus, (1,8)(1, 8) lies on the graph, meaning q(1)=8q(1) = 8. By the Remainder Theorem, the remainder when q(x)q(x) is divided by x1x-1 is q(1)=8q(1) = 8.
Estimated Time:1m 30s
Question 1844Question
An equation is shown below.
xx12x+2=6x2+x2\frac{x}{x - 1} - \frac{2}{x + 2} = \frac{6}{x^2 + x - 2}
What is the value of the real solution to the equation?
Show answer & explanation

Answer: 2

Answer

The correct answer is 2.
The correct answer is 2. Multiplying both sides by the least common denominator (x1)(x+2)(x - 1)(x + 2) results in the quadratic equation x(x+2)2(x1)=6x(x + 2) - 2(x - 1) = 6. Simplifying this equation yields x2+2=6x^2 + 2 = 6, which has solutions x=2x = 2 and x=2x = -2. However, substituting x=2x = -2 into the original equation results in division by zero, making it an extraneous solution. Therefore, 22 is the only valid real solution.

Step-by-Step Solution

1
Multiply the entire equation by the least common denominator, (x1)(x+2)=x2+x2(x - 1)(x + 2) = x^2 + x - 2, to clear the denominators.
x(x+2)2(x1)=6x(x + 2) - 2(x - 1) = 6
This simplifies the rational equation into a polynomial equation.
2
Expand the terms and simplify the equation.
x2+2x2x+2=6x^2 + 2x - 2x + 2 = 6, which simplifies to x2+2=6x^2 + 2 = 6.
Distributing the terms allows us to group like terms and solve for the variable.
3
Solve the quadratic equation for xx.
x2=4x^2 = 4, which gives x=2x = 2 or x=2x = -2.
Subtracting 2 from both sides isolates the squared variable.
4
Check for extraneous solutions by substituting the potential solutions back into the original denominators.
For x=2x = -2, the denominator x+2x + 2 becomes 0, which is undefined. For x=2x = 2, all denominators are non-zero.
Solutions that make any denominator in the original equation equal to zero are extraneous and must be excluded.

Key Concept

Solving rational equations by finding a common denominator and checking for extraneous solutions.
Question 1845Question

A digital photography archive consists of RAW files and JPEG files. Initially, the RAW files account for 80%80\% of the total storage space used by the archive. To reduce the storage space, the photographer compresses 40%40\% of the RAW files into JPEGs, which reduces the storage space of those specific files by 62.5%62.5\%. If the remaining uncompressed RAW files now account for x%x\% of the updated total storage space of the archive, what is the value of xx?

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Answer: 60

Answer

The remaining uncompressed RAW files occupy 48% of the initial total storage space, and the updated total storage space is 80% of the initial storage space. The percentage of the updated total storage space occupied by the uncompressed RAW files is therefore 60%.
The remaining uncompressed RAW files occupy 48%48\% of the initial total storage space, and the updated total storage space is 80%80\% of the initial storage space. The percentage of the updated total storage space occupied by the uncompressed RAW files is therefore 60%.

Step-by-Step Solution

1
Define variables for initial storage space.
Initial RAW space is 0.80T0.80T; initial JPEG space is 0.20T0.20T.
Establishes the baseline values relative to the initial total storage space TT.
2
Calculate the space occupied by the portion of RAW files to be compressed and the remaining uncompressed RAW files.
Compressed RAW space is 0.32T0.32T; remaining uncompressed RAW space is 0.48T0.48T.
Splits the RAW files into the group that changes size and the group that remains unchanged.
3
Determine the new space occupied by the compressed files after the 62.5%62.5\% reduction.
Reduction is 0.20T0.20T; new space of compressed files is 0.12T0.12T.
Calculates the impact of the compression percent change on the target subpopulation.
4
Calculate the updated total storage space of the archive.
Updated total storage space is 0.80T0.80T.
Summing all updated file spaces (0.48T0.48T uncompressed RAW + 0.20T0.20T original JPEG + 0.12T0.12T newly compressed files) provides the new base for the final percentage calculation.
5
Compute the final percentage of the updated total storage space occupied by the uncompressed RAW files.
x=60x = 60.
Dividing the remaining uncompressed RAW space (0.48T0.48T) by the new total space (0.80T0.80T) gives the updated percentage.

Key Concept

Multi-step percent change and relative base calculations.
Question 1846Question

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the points (2,5)(-2, 5) and (4,7)(4, 7). What is the value of m+bm + b?

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Answer: 66

Answer

The value of m+bm + b is 66.
The correct answer is 66. By finding the slope mm using the change in yy divided by the change in xx, we get m=13m = \frac{1}{3}. Using the slope-intercept form with the point (4,7)(4, 7) allows us to solve for b=173b = \frac{17}{3}. Adding the two values together yields m+b=13+173=6m + b = \frac{1}{3} + \frac{17}{3} = 6.

Step-by-Step Solution

1
Calculate the slope mm of the line using the two points (2,5)(-2, 5) and (4,7)(4, 7).
m=754(2)=26=13m = \frac{7 - 5}{4 - (-2)} = \frac{2}{6} = \frac{1}{3}
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Substitute the slope m=13m = \frac{1}{3} and the coordinates of one point, such as (4,7)(4, 7), into the slope-intercept equation y=mx+by = mx + b to solve for bb.
7=13(4)+b7=43+bb=1737 = \frac{1}{3}(4) + b \Rightarrow 7 = \frac{4}{3} + b \Rightarrow b = \frac{17}{3}
Substituting a known point and the slope into the slope-intercept form allows us to isolate and solve for the constant yy-intercept.
3
Add the calculated values of mm and bb to find m+bm + b.
m+b=13+173=183=6m + b = \frac{1}{3} + \frac{17}{3} = \frac{18}{3} = 6
The question asks for the sum of the slope mm and the yy-intercept bb.

Key Concept

Linear Equations in Two Variables
Question 1847Question

In the system of equations below, xx and yy are variables.

2xy=52x - y = 5
3x2y=173x - 2y = -17

What is the value of xx?

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Answer: 27

Answer

The value of xx is 27.
Isolating yy from the first equation gives y=2x5y = 2x - 5. Substituting this expression into the second equation yields 3x2(2x5)=173x - 2(2x - 5) = -17. Distributing the 2-2 gives 3x4x+10=173x - 4x + 10 = -17, which simplifies to x+10=17-x + 10 = -17. Subtracting 1010 from both sides results in x=27-x = -27, meaning x=27x = 27. Alternatively, multiplying the first equation by 22 gives 4x2y=104x - 2y = 10, and subtracting the second equation from it eliminates yy directly to give x=10(17)=27x = 10 - (-17) = 27.

Step-by-Step Solution

1
Isolate the variable yy in the first equation, 2xy=52x - y = 5.
y=2x5y = 2x - 5
This allows for substitution of the expression for yy into the second equation.
2
Substitute the expression for yy into the second equation, 3x2y=173x - 2y = -17.
3x2(2x5)=173x - 2(2x - 5) = -17
To create a single-variable equation in terms of xx.
3
Distribute the coefficient 2-2 to the terms inside the parentheses and simplify the equation.
3x4x+10=173x - 4x + 10 = -17, which simplifies to x+10=17-x + 10 = -17
Applying the distributive property correctly, noting that 2×5=10-2 \times -5 = 10.
4
Subtract 1010 from both sides of the equation to isolate the term with xx.
x=27-x = -27
To isolate the variable term on one side of the equation.
5
Multiply both sides of the equation by 1-1 to solve for xx.
x=27x = 27
To find the positive value of the variable xx.

Key Concept

Solving systems of linear equations using the substitution method.
Estimated Time:1m 30s
Question 1848Question

In 1847, astronomer Maria Mitchell swept her telescope across the night sky and spotted a blurry streak that would become known as 'Miss Mitchell's Comet.' While many of Mitchell's contemporaries focused on documenting known celestial bodies, the _______ dedication to scanning the skies led to the historic discovery of a new comet and earned her international acclaim.

Which choice completes the text with the most logical and grammatically correct term?

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Answer: astronomer's

Answer

astronomer's
The correct answer is 'astronomer's'. The text refers to the dedication of one specific astronomer, Maria Mitchell. To show that the 'dedication' belongs to her, we must use the singular possessive form, which is created by adding an apostrophe and an 's' to the singular noun.

Step-by-Step Solution

1
Identify the relationship between the blank and the noun that follows it.
The blank precedes 'dedication', indicating that we need a possessive noun to show who the dedication belongs to.
Understanding the grammatical relationship helps determine if a possessive form is required.
2
Determine the number of the noun in context.
The sentence refers to Maria Mitchell, who is a single individual, so we need the singular form.
This establishes whether the noun should be singular or plural.
3
Combine the singular number and possessive case to choose the correct spelling.
The singular possessive form of 'astronomer' is 'astronomer's'.
This produces the grammatically correct word for the blank.

Key Concept

Singular possessive nouns require an apostrophe followed by an 's' to show ownership.
Question 1849Question

For the quadratic function ff, the table below shows three points that lie on its graph in the xyxy-plane, where kk is a constant.

xxf(x)f(x)
2200
6600
1115-15

If the vertex of the graph of y=f(x)y = f(x) is (4,k)(4, k), what is the value of kk?

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Answer: 12

Answer

The value of kk is 1212.
The table indicates that the function has xx-intercepts at x=2x = 2 and x=6x = 6 because f(2)=0f(2) = 0 and f(6)=0f(6) = 0. Consequently, the quadratic function can be written in factored form as f(x)=a(x2)(x6)f(x) = a(x - 2)(x - 6) for some constant aa. Using the point (1,15)(1, -15) to find aa, we substitute x=1x = 1 and f(1)=15f(1) = -15, which yields 15=a(12)(16)-15 = a(1 - 2)(1 - 6), or 15=5a-15 = 5a, so a=3a = -3. Since the vertex of the graph is (4,k)(4, k), the value of kk is the function value at the vertex's xx-coordinate, which is f(4)f(4). Evaluating the function gives k=3(42)(46)=3(2)(2)=12k = -3(4 - 2)(4 - 6) = -3(2)(-2) = 12.

Step-by-Step Solution

1
Write the quadratic function in factored form using the given xx-intercepts.
f(x)=a(x2)(x6)f(x) = a(x - 2)(x - 6)
The table shows that f(2)=0f(2) = 0 and f(6)=0f(6) = 0, meaning the graph has xx-intercepts at x=2x = 2 and x=6x = 6.
2
Substitute the point (1,15)(1, -15) into the factored equation to find the value of the constant aa.
a=3a = -3
Substituting x=1x = 1 and f(x)=15f(x) = -15 gives 15=a(12)(16)    15=5a    a=3-15 = a(1 - 2)(1 - 6) \implies -15 = 5a \implies a = -3.
3
Calculate the value of kk by finding the function value at the vertex x=4x = 4.
k=12k = 12
Since the vertex is (4,k)(4, k), the value of kk is f(4)f(4). Substituting x=4x = 4 into f(x)=3(x2)(x6)f(x) = -3(x - 2)(x - 6) yields k=3(42)(46)=3(2)(2)=12k = -3(4 - 2)(4 - 6) = -3(2)(-2) = 12.

Key Concept

Using intercepts and an additional point to determine the equation of a quadratic function, and evaluating it at the vertex.
Question 1850Question

The function ff is defined by f(x)=2x3f(x) = 2x - 3. If the function gg is defined by g(x)=f(x+4)g(x) = f(x + 4), what is the value of g(1)g(1)?

Show answer & explanation

Answer: 7

Answer

The correct answer is 7.
Since g(x)=f(x+4)g(x) = f(x + 4), evaluating g(1)g(1) requires finding f(1+4)f(1 + 4), which is f(5)f(5). Substituting 55 into the expression for f(x)f(x) gives f(5)=2(5)3=103=7f(5) = 2(5) - 3 = 10 - 3 = 7. Therefore, the correct answer is 7.

Step-by-Step Solution

1
Substitute x=1x = 1 into the definition of g(x)g(x) to express g(1)g(1) in terms of ff.
g(1)=f(1+4)=f(5)g(1) = f(1 + 4) = f(5)
To find the value of g(1)g(1), we must evaluate the input to the outer function first.
2
Substitute the input value 55 into the expression for f(x)f(x).
f(5)=2(5)3f(5) = 2(5) - 3
Evaluating f(5)f(5) requires replacing xx with 55 in the definition f(x)=2x3f(x) = 2x - 3.
3
Perform the operations to find the final value.
f(5)=103=7f(5) = 10 - 3 = 7
Simplifying the numerical expression gives the final value of g(1)g(1).

Key Concept

Evaluating a transformed function at a given point using function notation.
Estimated Time:45s
Question 1851Question

A specialized cooling system is used to lower the temperature of a chemical solution in a laboratory. The temperature of the solution, TT, in degrees Celsius, can be modeled by the linear equation T=85.41.25mT = 85.4 - 1.25m, where mm is the number of minutes since the cooling process began. According to the model, how many minutes does it take for the temperature of the solution to decrease by 1515 degrees Celsius?

Show answer & explanation

Answer: 12

Answer

12 minutes
The correct answer is 12. In the equation T=85.41.25mT = 85.4 - 1.25m, the coefficient of mm is 1.25-1.25, which indicates that the temperature decreases by 1.251.25 degrees Celsius for each minute that passes. To find how many minutes it takes for the temperature to decrease by 1515 degrees Celsius, divide the total decrease by the rate of decrease: 151.25=12\frac{15}{1.25} = 12.

Step-by-Step Solution

1
Identify the rate of change from the linear equation.
The rate of decrease is 1.251.25 degrees Celsius per minute.
The slope of the linear equation T=85.41.25mT = 85.4 - 1.25m is 1.25-1.25, representing the change in temperature per minute.
2
Divide the target temperature change by the rate of change to find the time.
12 minutes
To find the number of minutes for a 1515-degree decrease at a rate of 1.251.25 degrees per minute, calculate 151.25\frac{15}{1.25}.

Key Concept

Interpreting the slope of a linear relationship in context
Question 1852Question

A projectile is launched from the ground. Its height, in feet, tt seconds after launch is modeled by the function h(t)=16t2+v0th(t) = -16t^2 + v_0 t, where v0v_0 is the initial upward velocity in feet per second. If the projectile reaches its maximum height of 144144 feet, what is the value of v0v_0?

Show answer & explanation

Answer: 96

Answer

The correct answer is 96. The initial velocity of the projectile must be 96 feet per second to reach a maximum height of 144 feet.
The maximum height of a projectile modeled by a quadratic function is the yy-value of its vertex. For h(t)=16t2+v0th(t) = -16t^2 + v_0 t, the time tt at the vertex is given by t=b2a=v02(16)=v032t = -\frac{b}{2a} = -\frac{v_0}{2(-16)} = \frac{v_0}{32}. Substituting this value of tt back into the height equation yields the maximum height: h(v032)=16(v032)2+v0(v032)=16(v021024)+v0232=v0264+v0232=v0264h\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0}{32}\right)^2 + v_0\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0^2}{1024}\right) + \frac{v_0^2}{32} = -\frac{v_0^2}{64} + \frac{v_0^2}{32} = \frac{v_0^2}{64}. Given that the maximum height is 144144 feet, we set v0264=144\frac{v_0^2}{64} = 144, which simplifies to v02=144×64v_0^2 = 144 \times 64. Taking the square root of both sides gives v0=12×8=96v_0 = 12 \times 8 = 96.

Step-by-Step Solution

1
Find the time tt at which the maximum height occurs using the vertex formula.
t=v032t = \frac{v_0}{32}
For a quadratic function of the form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, the vertex occurs at x=b2ax = -\frac{b}{2a}. Here, a=16a = -16 and b=v0b = v_0, so the vertex is at t=v02(16)=v032t = -\frac{v_0}{2(-16)} = \frac{v_0}{32}.
2
Substitute the time t=v032t = \frac{v_0}{32} into the height function to express the maximum height in terms of v0v_0.
h(v032)=v0264h\left(\frac{v_0}{32}\right) = \frac{v_0^2}{64}
Evaluating h(v032)h\left(\frac{v_0}{32}\right) gives 16(v032)2+v0(v032)=16(v021024)+v0232=v0264+v0232=v0264-16\left(\frac{v_0}{32}\right)^2 + v_0\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0^2}{1024}\right) + \frac{v_0^2}{32} = -\frac{v_0^2}{64} + \frac{v_0^2}{32} = \frac{v_0^2}{64}.
3
Set the maximum height expression equal to the given maximum height of 144144 feet and solve for v0v_0.
v0=96v_0 = 96
Setting v0264=144\frac{v_0^2}{64} = 144 yields v02=144×64=9216v_0^2 = 144 \times 64 = 9216. Taking the positive square root (since v0v_0 represents a positive initial upward velocity) gives v0=144×64=12×8=96v_0 = \sqrt{144} \times \sqrt{64} = 12 \times 8 = 96.

Key Concept

Determining the vertex coordinates of a quadratic function to find maximum value in context.
Question 1853Question

If 272x2=(13)x827^{2x - 2} = \left(\frac{1}{3}\right)^{x - 8}, what is the value of xx?

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Answer: 2

Answer

The value of xx is 22.
To solve the equation 272x2=(13)x827^{2x - 2} = \left(\frac{1}{3}\right)^{x - 8}, express both sides with the base 33. Since 27=3327 = 3^3 and 13=31\frac{1}{3} = 3^{-1}, the equation becomes (33)2x2=(31)x8(3^3)^{2x - 2} = (3^{-1})^{x - 8}. Applying the exponent rule (am)n=amn(a^m)^n = a^{mn} yields 36x6=38x3^{6x - 6} = 3^{8 - x}. Since the bases are now the same, set the exponents equal to each other: 6x6=8x6x - 6 = 8 - x. Adding xx to both sides gives 7x6=87x - 6 = 8, and adding 66 to both sides gives 7x=147x = 14. Dividing by 77 results in x=2x = 2.

Step-by-Step Solution

1
Rewrite 2727 and 13\frac{1}{3} as powers of 33.
27=3327 = 3^3 and 13=31\frac{1}{3} = 3^{-1}
This allows both sides of the equation to be expressed with a common base of 33 so their exponents can be equated.
2
Substitute these bases back into the equation and apply exponent rules.
(33)2x2=(31)x8    33(2x2)=3(x8)    36x6=38x(3^3)^{2x - 2} = (3^{-1})^{x - 8} \implies 3^{3(2x - 2)} = 3^{-(x - 8)} \implies 3^{6x - 6} = 3^{8 - x}
Using the power rule (am)n=amn(a^m)^n = a^{mn}, multiply the outer exponent by the power of the base.
3
Equate the exponents and solve for xx.
6x6=8x    7x=14    x=26x - 6 = 8 - x \implies 7x = 14 \implies x = 2
Since the bases are equal, their exponents must be equal for the equation to hold true.

Key Concept

Solving exponential equations by finding a common base and applying exponent rules.
Question 1854Question

A bakery recipe requires 1212 ounces of butter to make one batch of bread. How many pounds of butter are needed to make 88 batches of bread? (Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces})

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Answer: 6

Answer

The bakery needs 66 pounds of butter.
The total amount of butter needed for 88 batches is calculated by multiplying the butter required for one batch by the number of batches: 8×12=968 \times 12 = 96 ounces. Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces}, we convert ounces to pounds by dividing the total ounces by 1616. Therefore, 96÷16=696 \div 16 = 6 pounds of butter are needed.

Step-by-Step Solution

1
Calculate the total ounces of butter needed.
9696 ounces
Since each batch requires 1212 ounces, 88 batches require 8×12=968 \times 12 = 96 ounces.
2
Convert the total ounces to pounds.
66 pounds
Divide the total number of ounces by the conversion factor (1616 ounces per pound): 9616=6\frac{96}{16} = 6.

Key Concept

To convert a quantity from a smaller unit to a larger unit, multiply the initial quantity by the number of groups to find the total in the smaller unit, and then divide by the conversion factor that relates the two units.
Question 1855Question

Deep-sea hydrothermal vents support complex communities in the complete absence of sunlight. Instead of relying on solar energy, the organisms in these extreme habitats depend on chemosynthetic bacteria that convert hydrogen sulfide into chemical energy ______ biological production forms the foundation of a food web that sustains unique species of tube worms, crabs, and shrimp.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Answer: ; this

Answer

The semicolon followed by the pronoun 'this' ('; this') is the correct choice because it appropriately links the two independent clauses.
The semicolon successfully links two independent clauses ('Instead of relying on solar energy, the organisms in these extreme habitats depend on chemosynthetic bacteria that convert hydrogen sulfide into chemical energy' and 'this biological production forms the foundation of a food web that sustains unique species of tube worms, crabs, and shrimp') without the need for a coordinating conjunction.

Step-by-Step Solution

1
Analyze the structure of the two clauses surrounding the blank.
The first clause ('Instead of relying on solar energy, the organisms in these extreme habitats depend on chemosynthetic bacteria that convert hydrogen sulfide into chemical energy') and the second clause ('this biological production forms the foundation of a food web that sustains unique species of tube worms, crabs, and shrimp') are both independent clauses.
Identifying the clause types is necessary to determine the correct punctuation and connectors required.
2
Determine the relationship between the two clauses.
The second clause continues and elaborates on the idea in the first clause, demonstrating a continuous and direct relationship rather than a contrast.
The logical relationship helps eliminate coordinators or subordinators that introduce inappropriate transitions.
3
Select the correct punctuation to join two independent clauses without a coordinating conjunction.
A semicolon is the appropriate punctuation mark to join two closely related independent clauses. A comma alone creates a comma splice, no punctuation creates a run-on, and using the coordinating conjunction 'but' introduces an incorrect sense of contrast.
Applying grammatical rules ensures the sentence conforms to Standard English conventions.

Key Concept

Linking Independent Clauses
Question 1856Question

A rideshare driver has a daily goal of earning at least 150.Sofartoday,thedriverhasearned150. So far today, the driver has earned 45. The driver earns 12perrideplusanaveragetipof12 per ride plus an average tip of 3 per ride. If the driver must pay a daily vehicle fee of $15, what is the minimum number of additional rides the driver must complete today to meet or exceed the daily earnings goal?

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Answer: 8

Answer

The minimum number of additional rides the driver must complete today is 8.
The driver earns 12plusa12 plus a 3 tip per ride, which is 15perride.Startingwith15 per ride. Starting with 45 and subtracting the 15feeleavesthedriverwith15 fee leaves the driver with 30 before completing any new rides. To reach at least 150,thedriverneedstoearnatleast150, the driver needs to earn at least 120 more. Dividing 120bythe120 by the 15 rate per ride gives a minimum of 8 rides.

Step-by-Step Solution

1
Define the variable xx for the number of additional rides and write an inequality representing the total net earnings.
45+12x+3x1515045 + 12x + 3x - 15 \geq 150
To represent the condition that the driver's total earnings, including initial earnings and new rides, minus the fee, must be at least $150.
2
Simplify the left side of the inequality by combining the constants and the xx terms.
30+15x15030 + 15x \geq 150
To group like terms and simplify the expression before solving.
3
Subtract 30 from both sides of the inequality to isolate the variable term.
15x12015x \geq 120
To isolate the term with the variable on one side of the inequality.
4
Divide both sides of the inequality by 15 to solve for xx.
x8x \geq 8
To find the minimum value of xx that satisfies the inequality.

Key Concept

Solving linear inequalities in one variable to find a minimum threshold value in a real-world scenario.
Question 1857Question

A medical study compared the effectiveness of two headache treatments, Treatment X and Treatment Y. The results of the study are shown in the table below.

TreatmentImprovedNo ImprovementTotal
Treatment X401050
Treatment Y351550
Total7525100

If a participant who received Treatment X is selected at random, what is the probability that the participant's headache improved?

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Answer: 45\frac{4}{5}

Answer

The correct answer is 45\frac{4}{5}.
The correct answer is the fraction expressing the number of participants who received Treatment X and improved (40) out of the total number of participants who received Treatment X (50), which simplifies to 45\frac{4}{5}.

Step-by-Step Solution

1
Identify the total number of participants in the conditional group.
The total number of participants who received Treatment X is 5050.
The question specifies that a participant is selected from those who received Treatment X, which restricts the sample space to this row.
2
Identify the number of participants in that conditional group who experienced improvement.
There are 4040 participants who received Treatment X and experienced improvement.
We need to find the number of favorable outcomes within the restricted sample space.
3
Calculate the conditional probability.
The probability is 4050=45\frac{40}{50} = \frac{4}{5}.
Probability is the ratio of the number of favorable outcomes to the total number of possible outcomes in the restricted group.

Key Concept

Calculating conditional probability from a two-way table by identifying the restricted sample space.
Estimated Time:45s
Question 1858Question

The quadratic function ff is defined by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where aa, hh, and kk are constants. In the xyxy-plane, the graph of y=f(x)y = f(x) has a vertex at (3,4)(3, -4) and passes through the point (5,8)(5, 8). If the function gg is defined by g(x)=2f(x1)+5g(x) = -2f(x - 1) + 5, what is the value of g(2)g(2)?

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Answer: -11

Answer

-11
To find the value of g(2)g(2), we first determine the equation of the quadratic function f(x)f(x). Since the vertex is (3,4)(3, -4), the vertex form is f(x)=a(x3)24f(x) = a(x - 3)^2 - 4. Substituting the point (5,8)(5, 8) yields 8=a(53)248 = a(5 - 3)^2 - 4, which simplifies to 12=4a12 = 4a, so a=3a = 3. Therefore, f(x)=3(x3)24f(x) = 3(x - 3)^2 - 4. We then substitute x=2x = 2 into the definition of g(x)g(x), obtaining g(2)=2f(21)+5=2f(1)+5g(2) = -2f(2 - 1) + 5 = -2f(1) + 5. Evaluating f(1)f(1) gives f(1)=3(13)24=8f(1) = 3(1 - 3)^2 - 4 = 8. Substituting this back into the expression for g(2)g(2) gives 2(8)+5=11-2(8) + 5 = -11. Thus, the option with value -11 is correct.

Step-by-Step Solution

1
Write the quadratic function f(x)f(x) in vertex form using the given vertex (3,4)(3, -4).
f(x)=a(x3)24f(x) = a(x - 3)^2 - 4
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex.
2
Substitute the point (5,8)(5, 8) into the vertex form to solve for the constant aa.
8=a(53)24    8=4a4    12=4a    a=38 = a(5 - 3)^2 - 4 \implies 8 = 4a - 4 \implies 12 = 4a \implies a = 3. Thus, f(x)=3(x3)24f(x) = 3(x - 3)^2 - 4.
Since the graph of ff passes through (5,8)(5, 8), these coordinates must satisfy the function's equation.
3
Substitute x=2x = 2 into the definition of g(x)g(x) to express g(2)g(2) in terms of ff.
g(2)=2f(21)+5=2f(1)+5g(2) = -2f(2 - 1) + 5 = -2f(1) + 5
We need to evaluate the inner function transformation f(x1)f(x - 1) at x=2x = 2.
4
Evaluate f(1)f(1) using the formula determined in Step 2.
f(1)=3(13)24=3(2)24=3(4)4=8f(1) = 3(1 - 3)^2 - 4 = 3(-2)^2 - 4 = 3(4) - 4 = 8
To find g(2)g(2), we must first compute the value of f(1)f(1).
5
Substitute f(1)=8f(1) = 8 back into the expression for g(2)g(2) and simplify.
g(2)=2(8)+5=16+5=11g(2) = -2(8) + 5 = -16 + 5 = -11
This completes the evaluation of the multi-step transformation.

Key Concept

Function Notation and Transformations
Estimated Time:2m 0s
Question 1859Question

A map has a scale where 22 centimeters represents 1515 kilometers. If the distance between two cities on the map is 88 centimeters, what is the actual distance between the two cities, in kilometers?

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Answer: 60

Answer

The actual distance between the two cities is 6060 kilometers.
The correct answer is 6060. The map scale is 22 centimeters to 1515 kilometers. The map distance between the cities is 88 centimeters, which is 44 times the scale distance of 22 centimeters (since 8÷2=48 \div 2 = 4). Therefore, the actual distance between the cities is 44 times the scale distance of 1515 kilometers, which is 15×4=6015 \times 4 = 60 kilometers.

Step-by-Step Solution

1
Set up a proportion using the map scale ratio of centimeters to kilometers.
215=8x\frac{2}{15} = \frac{8}{x}
This establishes that the ratio of map distance to actual distance remains constant.
2
Solve for the unknown actual distance, xx, by cross-multiplying.
2x=1202x = 120
Multiplying the numerator of each fraction by the denominator of the other solves the proportion.
3
Divide by the coefficient of xx to find the final actual distance.
x=60x = 60
Dividing 120120 by 22 isolates xx and gives the actual distance in kilometers.

Key Concept

Setting up and solving proportions using scale factors.
Question 1860Question

A manufacturer models the daily profit, P(x)P(x), in dollars, from producing and selling xx units of a product using the function P(x)=2x2+kx800P(x) = -2x^2 + kx - 800, where kk is a constant. If the maximum daily profit is 1,0001,000 dollars, what is the number of units that must be sold to achieve this maximum profit?

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Answer: 30

Answer

The manufacturer must sell 30 units to achieve the maximum daily profit.
The correct answer is 30. The maximum value of a downward-opening quadratic function occurs at its vertex (h,q)(h, q). Given that the maximum value is 1000, we write the function in vertex form: P(x)=2(xh)2+1000P(x) = -2(x - h)^2 + 1000. Expanding this gives P(x)=2x2+4hx2h2+1000P(x) = -2x^2 + 4hx - 2h^2 + 1000. Comparing this to the given function P(x)=2x2+kx800P(x) = -2x^2 + kx - 800, the constant term must satisfy 2h2+1000=800-2h^2 + 1000 = -800. Solving for hh yields 2h2=18002h^2 = 1800, so h2=900h^2 = 900. Taking the positive square root because the number of units must be positive gives h=30h = 30.

Step-by-Step Solution

1
Write the quadratic function in vertex form and identify the given parameters.
The vertex form of a quadratic function is P(x)=a(xh)2+qP(x) = a(x-h)^2 + q, where (h,q)(h, q) is the vertex. Here, a=2a = -2 and the maximum profit q=1000q = 1000, so the function is P(x)=2(xh)2+1000P(x) = -2(x-h)^2 + 1000.
Since the coefficient of the x2x^2 term is negative (a=2a = -2), the parabola opens downward, meaning the vertex represents the maximum value of the function.
2
Expand the vertex form equation to compare its coefficients with the standard form P(x)=2x2+kx800P(x) = -2x^2 + kx - 800.
P(x)=2(x22hx+h2)+1000=2x2+4hx(2h21000)P(x) = -2(x^2 - 2hx + h^2) + 1000 = -2x^2 + 4hx - (2h^2 - 1000)
Expanding the vertex form allows us to equate corresponding coefficients and constant terms between the two forms of the quadratic function.
3
Equate the constant terms from both expressions to solve for the vertex xx-coordinate hh.
2h2+1000=8002h2=1800h2=900h=30-2h^2 + 1000 = -800 \Rightarrow -2h^2 = -1800 \Rightarrow h^2 = 900 \Rightarrow h = 30 (since the number of units must be positive).
By setting the constant terms equal, we can isolate and solve for hh, which represents the number of units that maximizes the daily profit.

Key Concept

Quadratic functions in vertex form and their standard form equivalents.
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