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Question 1821Question

The quadratic function ff is defined by f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where aa, bb, and cc are constants. In the xyxy-plane, the graph of ff is a parabola with vertex (3,5)(3, -5) that passes through the point (0,4)(0, 4). What is the value of a+b+ca + b + c?

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Answer: -1

Answer

-1
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex. Substituting the given vertex (3,5)(3, -5) gives f(x)=a(x3)25f(x) = a(x - 3)^2 - 5. Since the graph passes through the point (0,4)(0, 4), substituting x=0x = 0 and f(x)=4f(x) = 4 yields the equation 4=a(03)254 = a(0 - 3)^2 - 5, which simplifies to 9a=99a = 9, or a=1a = 1. The function is therefore defined by f(x)=(x3)25f(x) = (x - 3)^2 - 5. The expression a+b+ca + b + c represents the sum of the coefficients of the quadratic function in standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c. Evaluating the function at x=1x = 1 gives f(1)=a(1)2+b(1)+c=a+b+cf(1) = a(1)^2 + b(1) + c = a + b + c. Substituting x=1x = 1 into our vertex form equation yields f(1)=(13)25=(2)25=45=1f(1) = (1 - 3)^2 - 5 = (-2)^2 - 5 = 4 - 5 = -1. Therefore, the value of a+b+ca + b + c is 1-1.

Step-by-Step Solution

1
Write the quadratic function in vertex form using the given vertex (3,5)(3, -5).
f(x)=a(x3)25f(x) = a(x - 3)^2 - 5, where aa is a constant.
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex.
2
Substitute the coordinates of the given point (0,4)(0, 4) into the vertex form equation to solve for aa.
4=a(03)254 = a(0 - 3)^2 - 5, which simplifies to 4=9a54 = 9a - 5, and solving for aa gives a=1a = 1.
Since the graph passes through (0,4)(0, 4), substituting these coordinates into the function's equation must yield a true statement.
3
Find the value of a+b+ca + b + c by evaluating f(1)f(1).
f(1)=1(13)25=1(2)25=45=1f(1) = 1(1 - 3)^2 - 5 = 1(-2)^2 - 5 = 4 - 5 = -1.
For any quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c, evaluating the function at x=1x = 1 gives f(1)=a(1)2+b(1)+c=a+b+cf(1) = a(1)^2 + b(1) + c = a + b + c.

Key Concept

Quadratic Functions and Graphs
Question 1822Question

A municipal water reservoir contains 250 million gallons of water. During a dry spell, water is released from the reservoir at a constant rate of 3.5 million gallons per day. Additionally, water evaporates from the reservoir at a constant rate of 0.3 million gallons per day. If no water enters the reservoir, the total amount of water WW, in million gallons, remaining in the reservoir after dd days of the dry spell is modeled by the equation W=250rdW = 250 - r d, where rr is a constant. What is the value of rr?

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Answer: 3.8

Answer

The correct value of rr is 3.8.
The constant rr in the linear equation W=250rdW = 250 - r d represents the total rate, in million gallons per day, at which the water volume in the reservoir decreases. Since water is lost through both release (3.53.5 million gallons per day) and evaporation (0.30.3 million gallons per day), the total rate of decrease is the sum of these two rates, which is 3.5+0.3=3.83.5 + 0.3 = 3.8 million gallons per day. Therefore, the value of rr is 3.83.8.

Step-by-Step Solution

1
Identify the factors causing a decrease in the reservoir's water volume.
Water is lost through release at 3.53.5 million gallons per day and evaporation at 0.30.3 million gallons per day.
Both release and evaporation contribute to the total rate of water depletion.
2
Calculate the total daily rate of water loss.
3.5+0.3=3.83.5 + 0.3 = 3.8 million gallons per day.
Adding the individual rates of loss yields the overall rate of decrease.
3
Compare the total daily rate of water loss to the model equation W=250rdW = 250 - r d.
r=3.8r = 3.8.
In the linear model, 250250 represents the initial amount of water, and rr represents the constant rate at which water decreases per day. Thus, rr is the total daily rate of water loss.

Key Concept

Interpreting the slope (rate of change) in a linear equation in context.
Question 1823Question

A garden hose discharges water at a constant rate of 88 quarts per minute. What is this rate, in gallons per hour? (Given that 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts})

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Answer: 120

Answer

120
To convert the discharge rate from quarts per minute to gallons per hour, we first convert quarts to gallons. Since 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts}, we divide the rate of 88 quarts per minute by 44 to get 22 gallons per minute. Next, to convert minutes to hours, we multiply this rate by 6060 (since there are 6060 minutes in 1 hour1\text{ hour}). This gives 2×60=1202 \times 60 = 120 gallons per hour.

Step-by-Step Solution

1
Convert quarts per minute to gallons per minute
22 gallons per minute
Since 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts}, divide the flow rate of 88 quarts per minute by the conversion factor of 44 to find the rate in gallons per minute: 8 quarts/min4 quarts/gallon=2 gallons/min\frac{8\text{ quarts/min}}{4\text{ quarts/gallon}} = 2\text{ gallons/min}.
2
Convert gallons per minute to gallons per hour
120120 gallons per hour
Since there are 6060 minutes in an hour, multiply the rate of 22 gallons per minute by 6060 to find the total gallons discharged in one hour: 2 gallons/min×60 min/hour=120 gallons/hour2\text{ gallons/min} \times 60\text{ min/hour} = 120\text{ gallons/hour}.

Key Concept

Unit Conversions
Question 1824Question

Which form of the noun 'archaeologist' grammatically completes the passage?

Fill in the blanks below

During a 2021 excavation in Egypt's Valley of the Kings, a team of archaeologists uncovered a series of previously undocumented tomb shafts. Because the humidity inside the chambers could damage the fragile wall paintings, the primary objective was to stabilize the microclimate before proceeding with any excavation.
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Answer

archaeologists'
The correct answer is 'archaeologists''. The context establishes that there are multiple archaeologists ('a team of archaeologists') and that the objective belongs to them ('primary objective'). To form the possessive of a plural noun ending in 's', an apostrophe is added to the end of the word, resulting in 'archaeologists''.

Step-by-Step Solution

1
Determine the number (singular or plural) of the noun based on context clues.
The noun refers back to 'a team of archaeologists,' which indicates multiple individuals. Therefore, the plural form is required.
The phrase 'a team of archaeologists' establishes a plural subject.
2
Determine the case (possessive or non-possessive) of the noun based on its grammatical role.
The noun modifies the noun phrase 'primary objective,' indicating ownership or association. Therefore, the possessive case is required.
A noun that shows ownership over another noun must be in the possessive form.
3
Apply standard spelling and punctuation rules for plural possessive nouns.
For a regular plural noun ending in 's' (archaeologists), the possessive is formed by adding an apostrophe after the final 's', yielding 'archaeologists''.
Plural possessive nouns ending in 's' receive only an apostrophe at the end, without an additional 's'.

Key Concept

Plural and possessive nouns require correct placement of the apostrophe depending on the number of the noun and its relationship to other words in the sentence.
Question 1825Question

A retailer purchased a shipment of coats for a wholesale price of xx dollars each. The retailer marked up the wholesale price by 40%40\% to determine the retail price. During a winter sale, the retailer offered a discount of 20%20\% off the retail price of the coats. If the sale price of a coat was 8484 dollars, what was the wholesale price, xx, of the coat?

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Answer: 7575

Answer

7575
The correct answer is 7575. The retail price is determined by increasing the wholesale price, xx, by 40%40\%, which can be represented as 1.40x1.40x. The sale price is determined by decreasing the retail price by 20%20\%, which is 0.80(1.40x)=1.12x0.80(1.40x) = 1.12x. Since the sale price of the coat was 8484 dollars, we set up the equation 1.12x=841.12x = 84. Solving for xx yields x=841.12=75x = \frac{84}{1.12} = 75.

Step-by-Step Solution

1
Represent the retail price in terms of the wholesale price xx.
Retail price = 1.40x1.40x
A markup of 40%40\% on xx is equivalent to multiplying xx by 1+0.40=1.401 + 0.40 = 1.40.
2
Represent the sale price in terms of the retail price.
Sale price = 0.80(1.40x)=1.12x0.80(1.40x) = 1.12x
A discount of 20%20\% off the retail price is equivalent to multiplying the retail price by 10.20=0.801 - 0.20 = 0.80.
3
Set up the equation with the given sale price and solve for xx.
1.12x=84    x=841.12=751.12x = 84 \implies x = \frac{84}{1.12} = 75
The sale price of the coat is given as 8484 dollars, so we set the algebraic representation equal to 8484 and solve for xx.

Key Concept

Applying consecutive percentage increases and decreases to find initial values.
Question 1826Question

In the xyxy-plane, the graph of a cubic polynomial function pp with real coefficients has exactly two xx-intercepts, at (1,0)(1, 0) and (4,0)(4, 0). If the graph of pp passes through the points (0,8)(0, -8) and (2,2)(2, 2), what is the value of p(6)p(6)?

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Answer: 10

Answer

10
A cubic polynomial with real coefficients and exactly two xx-intercepts at (1,0)(1, 0) and (4,0)(4, 0) must have one root of multiplicity 1 and one root of multiplicity 2. This yields two possible forms: p(x)=a(x1)2(x4)p(x) = a(x - 1)^2(x - 4) or p(x)=a(x1)(x4)2p(x) = a(x - 1)(x - 4)^2. Substituting the yy-intercept (0,8)(0, -8) into the first form gives a=2a = 2, but the resulting polynomial p(x)=2(x1)2(x4)p(x) = 2(x - 1)^2(x - 4) does not pass through (2,2)(2, 2) since p(2)=4p(2) = -4. Substituting (0,8)(0, -8) into the second form gives a=12a = \frac{1}{2}, and the resulting polynomial p(x)=12(x1)(x4)2p(x) = \frac{1}{2}(x - 1)(x - 4)^2 correctly passes through (2,2)(2, 2) since p(2)=2p(2) = 2. Finally, evaluating this function at x=6x = 6 yields p(6)=12(61)(64)2=10p(6) = \frac{1}{2}(6 - 1)(6 - 4)^2 = 10.

Step-by-Step Solution

1
Determine the possible forms of the cubic polynomial based on its xx-intercepts.
Two possible cases: Case 1: p(x)=a(x1)2(x4)p(x) = a(x - 1)^2(x - 4) or Case 2: p(x)=a(x1)(x4)2p(x) = a(x - 1)(x - 4)^2, where aa is a non-zero constant.
Since the polynomial has degree 3 and exactly two distinct xx-intercepts, one intercept must be a root of multiplicity 2 (tangent to the xx-axis) and the other must be a root of multiplicity 1 (crossing the xx-axis).
2
Solve for the constant aa in Case 1 using the yy-intercept (0,8)(0, -8).
a=2a = 2, yielding the candidate function p(x)=2(x1)2(x4)p(x) = 2(x - 1)^2(x - 4).
Substituting x=0x = 0 and p(0)=8p(0) = -8 into the equation for Case 1 allows us to solve for aa.
3
Test the point (2,2)(2, 2) in the Case 1 candidate function.
p(2)=42p(2) = -4 \neq 2, which means Case 1 is incorrect.
The correct function must satisfy all given points, including (2,2)(2, 2).
4
Solve for the constant aa in Case 2 using the yy-intercept (0,8)(0, -8).
a=12a = \frac{1}{2}, yielding the candidate function p(x)=12(x1)(x4)2p(x) = \frac{1}{2}(x - 1)(x - 4)^2.
Substituting x=0x = 0 and p(0)=8p(0) = -8 into the equation for Case 2 allows us to solve for aa.
5
Test the point (2,2)(2, 2) in the Case 2 candidate function.
p(2)=2p(2) = 2, which matches the given point.
Confirming that the Case 2 function is consistent with the point (2,2)(2, 2).
6
Evaluate the correct function at x=6x = 6.
p(6)=10p(6) = 10.
Substituting x=6x = 6 into the verified function p(x)=12(x1)(x4)2p(x) = \frac{1}{2}(x - 1)(x - 4)^2 to find the final answer.

Key Concept

Identifying the algebraic form of a polynomial from its xx-intercepts and multiplicities, and determining unknown coefficients using coordinate points.
Question 1827Question

A chemist mixes a 10%10\% acid solution and a 30%30\% acid solution to create 200200 milliliters of a mixture that is 18%18\% acid. How many milliliters of the 30%30\% acid solution are in the mixture?

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Answer: 80

Answer

80
The correct answer is 8080 milliliters. By translating the problem into a system of linear equations, we let xx be the volume of the 10%10\% acid solution and yy be the volume of the 30%30\% acid solution. Since the total volume is 200200 milliliters, x+y=200x + y = 200. The amount of acid in the solutions must sum to the amount of acid in the final mixture, so 0.10x+0.30y=0.18(200)0.10x + 0.30y = 0.18(200), which simplifies to 0.10x+0.30y=360.10x + 0.30y = 36. Multiplying this equation by 1010 gives x+3y=360x + 3y = 360. Subtracting the first equation from this yields (x+3y)(x+y)=360200(x + 3y) - (x + y) = 360 - 200, or 2y=1602y = 160. Solving for yy gives 8080 milliliters of the 30%30\% solution.

Step-by-Step Solution

1
Define variables and set up the system of equations.
Let xx be the number of milliliters of the 10%10\% acid solution and yy be the number of milliliters of the 30%30\% acid solution. The total volume equation is x+y=200x + y = 200. The total acid content equation is 0.10x+0.30y=0.18(200)0.10x + 0.30y = 0.18(200).
This sets up the system of linear equations representing the physical constraints of the mixture.
2
Simplify the acid content equation and prepare for elimination.
0.10x+0.30y=360.10x + 0.30y = 36. Multiplying the entire equation by 1010 yields x+3y=360x + 3y = 360.
Eliminating decimals simplifies the coefficients and makes it easier to solve the system using integer arithmetic.
3
Eliminate xx by subtracting the total volume equation from the simplified acid content equation.
(x+3y)(x+y)=360200    2y=160    y=80(x + 3y) - (x + y) = 360 - 200 \implies 2y = 160 \implies y = 80.
This isolates the variable yy, which directly represents the volume of the 30%30\% acid solution requested in the problem.

Key Concept

Solving systems of linear equations in context
Question 1828Question

If the graph of y=f(x)y = f(x) contains the point (3,7)(3, 7), and the function gg is defined by g(x)=f(x+4)2g(x) = f(x + 4) - 2, what is the value of g(1)g(-1)?

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Answer: 5

Answer

5
Since the graph of y=f(x)y = f(x) contains the point (3,7)(3, 7), we have f(3)=7f(3) = 7. The function gg is defined as g(x)=f(x+4)2g(x) = f(x + 4) - 2. To find the value of g(1)g(-1), we substitute x=1x = -1 into the definition of gg: g(1)=f(1+4)2=f(3)2g(-1) = f(-1 + 4) - 2 = f(3) - 2. Substituting f(3)=7f(3) = 7 gives g(1)=72=5g(-1) = 7 - 2 = 5.

Step-by-Step Solution

1
Translate the point (3,7)(3, 7) on the graph of f(x)f(x) into function notation.
f(3)=7f(3) = 7
By definition, if a point (a,b)(a, b) is on the graph of y=f(x)y = f(x), then f(a)=bf(a) = b.
2
Substitute x=1x = -1 into the expression for g(x)g(x) to evaluate g(1)g(-1).
g(1)=f(1+4)2g(-1) = f(-1 + 4) - 2
To find g(1)g(-1), replace every occurrence of xx with 1-1 in the function definition of g(x)g(x).
3
Simplify the input of the function ff and compute the final value.
g(1)=f(3)2=72=5g(-1) = f(3) - 2 = 7 - 2 = 5
Simplify 1+4-1 + 4 to 33, then substitute the known value f(3)=7f(3) = 7 and subtract 22.

Key Concept

Evaluating a transformed function using function notation and given coordinate points.
Question 1829Question

A retailer purchases an item at a wholesale price. The retailer marks up the wholesale price by p%p\% to establish the retail price. During a clearance sale, the retailer discounts the retail price by (p10)%(p - 10)\%. If the clearance sale price of the item is 8%8\% greater than the original wholesale price, and p>10p > 10, what is the value of pp?

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Answer: 20

Answer

The value of pp is 2020.
The correct answer is 2020. By representing the markup and discount as decimal multipliers, we can write the equation for the final price as a function of the wholesale price: W(1+p100)(1p10100)=1.08WW \left(1 + \frac{p}{100}\right)\left(1 - \frac{p - 10}{100}\right) = 1.08W. Dividing by WW and letting y=p100y = \frac{p}{100}, we get (1+y)(1.1y)=1.08(1 + y)(1.1 - y) = 1.08. Expanding this gives 1.1+0.1yy2=1.081.1 + 0.1y - y^2 = 1.08, which rearranges to the quadratic equation y20.1y0.02=0y^2 - 0.1y - 0.02 = 0. Factoring this equation yields (y0.2)(y+0.1)=0(y - 0.2)(y + 0.1) = 0. Since p>10p > 10, yy must be positive, which means y=0.2y = 0.2. Therefore, p=20p = 20.

Step-by-Step Solution

1
Express the retail price in terms of the wholesale price WW and the markup percentage p%p\%.
Retail Price = W(1+p100)W \left(1 + \frac{p}{100}\right)
A markup of p%p\% increases the base price WW by a factor of (1+p100)\left(1 + \frac{p}{100}\right).
2
Express the clearance sale price after applying a discount of (p10)%(p - 10)\% to the retail price.
Clearance Price = W(1+p100)(1p10100)W \left(1 + \frac{p}{100}\right)\left(1 - \frac{p - 10}{100}\right)
A discount of (p10)%(p - 10)\% decreases the retail price by a factor of (1p10100)\left(1 - \frac{p - 10}{100}\right).
3
Set the clearance price equal to 1.08W1.08W, which represents an 8%8\% increase over the wholesale price, and simplify the equation by dividing both sides by WW.
(1+p100)(1p10100)=1.08\left(1 + \frac{p}{100}\right)\left(1 - \frac{p - 10}{100}\right) = 1.08
The final clearance price is 8%8\% greater than the wholesale price WW, so we equate it to 1.08W1.08W and divide both sides by WW to eliminate the variable.
4
Substitute y=p100y = \frac{p}{100} into the simplified equation and expand the terms.
(1+y)(1.1y)=1.081.1+0.1yy2=1.08(1 + y)(1.1 - y) = 1.08 \Rightarrow 1.1 + 0.1y - y^2 = 1.08
Writing the equation in terms of yy simplifies the algebraic expansion. The term 1p101001 - \frac{p - 10}{100} becomes 1(y0.1)=1.1y1 - (y - 0.1) = 1.1 - y.
5
Rearrange the quadratic equation into standard form, factor it, and solve for yy.
y20.1y0.02=0(y0.2)(y+0.1)=0y=0.2y^2 - 0.1y - 0.02 = 0 \Rightarrow (y - 0.2)(y + 0.1) = 0 \Rightarrow y = 0.2 (since p>10p > 10, y>0.1y > 0.1)
Factoring the quadratic yields y=0.2y = 0.2 and y=0.1y = -0.1. Since p>10p > 10, yy must be positive, which leaves y=0.2y = 0.2 as the only valid solution.
6
Convert the value of yy back to pp.
p=20p = 20
Since y=p100=0.2y = \frac{p}{100} = 0.2, multiplying both sides by 100100 gives p=20p = 20.

Key Concept

Compounding percent changes algebraically using variable markups and discounts.
Question 1830Question

In the quadratic equation x28x+k=0x^2 - 8x + k = 0, kk is a constant. If the difference between the two real solutions to the equation is 22, what is the value of kk?

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Answer: 15

Answer

15
The correct answer is 15. The sum of the solutions to the quadratic equation x28x+k=0x^2 - 8x + k = 0 is given by 81=8-\frac{-8}{1} = 8. We are given that the difference between the two solutions is 22. Let the two solutions be x1x_1 and x2x_2. We can set up the system of equations: x1+x2=8x_1 + x_2 = 8 and x1x2=2x_1 - x_2 = 2. Adding the equations gives 2x1=102x_1 = 10, so x1=5x_1 = 5. Thus, x2=3x_2 = 3. The product of the solutions is equal to the constant term kk. Therefore, k=x1×x2=5×3=15k = x_1 \times x_2 = 5 \times 3 = 15. Alternatively, using the difference of roots formula, b24aca=2(8)24(1)(k)1=2644k=2\frac{\sqrt{b^2 - 4ac}}{a} = 2 \Rightarrow \frac{\sqrt{(-8)^2 - 4(1)(k)}}{1} = 2 \Rightarrow \sqrt{64 - 4k} = 2. Squaring both sides gives 644k=44k=60k=1564 - 4k = 4 \Rightarrow 4k = 60 \Rightarrow k = 15.

Step-by-Step Solution

1
Find the sum of the two solutions of the quadratic equation.
The sum of the solutions is 88.
For a quadratic equation in the form x2+bx+c=0x^2 + bx + c = 0, the sum of the solutions is equal to b-b. Here, (8)=8-(-8) = 8.
2
Set up a system of linear equations using the sum and the given difference of the solutions to find the individual solutions.
The solutions are 55 and 33.
Let the solutions be x1x_1 and x2x_2. We have the system: x1+x2=8x_1 + x_2 = 8 and x1x2=2x_1 - x_2 = 2. Adding these two equations gives 2x1=102x_1 = 10, so x1=5x_1 = 5. Substituting 55 back into the first equation gives 5+x2=85 + x_2 = 8, so x2=3x_2 = 3.
3
Use the product of the solutions to determine the value of kk.
The value of kk is 1515.
For a quadratic equation in the form x2+bx+c=0x^2 + bx + c = 0, the product of the solutions is equal to cc, which is kk. Therefore, k=x1×x2=5×3=15k = x_1 \times x_2 = 5 \times 3 = 15.

Key Concept

Relationship between the roots and coefficients of a quadratic equation (Vieta's Formulas).
Question 1831Question

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the points (2,15)(2, 15) and (6,7)(6, 7). What is the value of bb?

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Answer: 19

Answer

The value of bb is 1919.
The slope of the line is found using the two given points: m=71562=2m = \frac{7 - 15}{6 - 2} = -2. Substituting the slope m=2m = -2 and the point (2,15)(2, 15) into the equation y=mx+by = mx + b gives 15=2(2)+b15 = -2(2) + b, which simplifies to 15=4+b15 = -4 + b. Adding 44 to both sides yields b=19b = 19.

Step-by-Step Solution

1
Calculate the slope of the line passing through (2,15)(2, 15) and (6,7)(6, 7).
m=71562=84=2m = \frac{7 - 15}{6 - 2} = \frac{-8}{4} = -2
The slope mm of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Substitute the slope m=2m = -2 and the coordinates of one point, such as (2,15)(2, 15), into the equation y=mx+by = mx + b to find bb.
15=2(2)+b    15=4+b15 = -2(2) + b \implies 15 = -4 + b
Since the point lies on the line, its coordinates must satisfy the equation of the line.
3
Solve the equation for bb.
b=19b = 19
Add 44 to both sides of the equation to isolate the variable bb.

Key Concept

Determining the equation of a line given two points.
Question 1832Question

A polynomial function pp of degree 3 has xx-intercepts at (2,0)(-2, 0) with multiplicity 2, and (3,0)(3, 0) with multiplicity 1. In the xyxy-plane, the graph of y=p(x)y = p(x) intersects the yy-axis at (0,24)(0, 24). What is the remainder when p(x)p(x) is divided by x1x - 1?

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Answer: 3636

Answer

The remainder when the polynomial function is divided by x1x - 1 is 36.
The correct answer is 36. A polynomial with a root at x=2x = -2 of multiplicity 2 and a root at x=3x = 3 of multiplicity 1 has the form p(x)=a(x+2)2(x3)p(x) = a(x + 2)^2(x - 3). Since the yy-intercept is (0,24)(0, 24), we solve p(0)=a(2)2(3)=24p(0) = a(2)^2(-3) = 24 to find a=2a = -2. Thus, the polynomial is p(x)=2(x+2)2(x3)p(x) = -2(x + 2)^2(x - 3). According to the Remainder Theorem, dividing p(x)p(x) by x1x - 1 leaves a remainder of p(1)p(1). Substituting x=1x = 1 yields p(1)=2(3)2(2)=36p(1) = -2(3)^2(-2) = 36.

Step-by-Step Solution

1
Write the general form of the cubic polynomial using its roots and multiplicities.
p(x)=a(x+2)2(x3)p(x) = a(x + 2)^2(x - 3)
Since there is an xx-intercept at x=2x = -2 with multiplicity 2, (x+2)2(x + 2)^2 is a factor. Since there is an xx-intercept at x=3x = 3 with multiplicity 1, (x3)(x - 3) is a factor. Here, aa is a constant coefficient.
2
Determine the value of the constant coefficient aa using the yy-intercept.
a=2a = -2, so p(x)=2(x+2)2(x3)p(x) = -2(x + 2)^2(x - 3)
The graph intersects the yy-axis at (0,24)(0, 24), meaning p(0)=24p(0) = 24. Substituting x=0x = 0 gives p(0)=a(0+2)2(03)=12ap(0) = a(0 + 2)^2(0 - 3) = -12a. Setting 12a=24-12a = 24 yields a=2a = -2.
3
Apply the Remainder Theorem to find the required remainder.
The remainder is equal to p(1)p(1).
By the Remainder Theorem, the remainder when a polynomial p(x)p(x) is divided by xcx - c is p(c)p(c). Here, the divisor is x1x - 1, so we evaluate the polynomial at x=1x = 1.
4
Calculate the value of p(1)p(1).
p(1)=36p(1) = 36
Substituting x=1x = 1 into p(x)=2(x+2)2(x3)p(x) = -2(x + 2)^2(x - 3) gives p(1)=2(1+2)2(13)=2(9)(2)=36p(1) = -2(1 + 2)^2(1 - 3) = -2(9)(-2) = 36.

Key Concept

Identifying a polynomial from its roots and multiplicities, solving for its leading coefficient using a given point, and applying the Remainder Theorem.
Question 1833Question

The function ff is defined for all real numbers, and the graph of y=f(x)y = f(x) in the xyxy-plane has a single minimum at the point (5,2)(5, -2). The function gg is defined by g(x)=3f(2x4)+7g(x) = -3f(2x - 4) + 7. What is the yy-coordinate of the maximum point on the graph of y=g(x)y = g(x)?

Show answer & explanation

Answer: 13

Answer

The correct answer is 13.
The graph of y=f(x)y = f(x) has a minimum at (5,2)(5, -2), which means f(5)=2f(5) = -2 and f(x)2f(x) \ge -2 for all xx. The function g(x)=3f(2x4)+7g(x) = -3f(2x-4) + 7 includes a vertical stretch by a factor of 33, a vertical reflection across the xx-axis, and a vertical shift upward by 77 units. Because of the vertical reflection, the minimum value of the original function becomes the maximum value of the transformed function. Applying the vertical transformations to the yy-coordinate of the minimum point yields 3(2)+7=6+7=13-3(-2) + 7 = 6 + 7 = 13.

Step-by-Step Solution

1
Identify the minimum point and minimum value of the original function f(x)f(x).
f(5)=2f(5) = -2, and f(x)2f(x) \ge -2 for all real numbers xx.
The problem states that the graph of y=f(x)y = f(x) has a single minimum at the point (5,2)(5, -2).
2
Determine the transformed xx-coordinate corresponding to the original input of 55.
2x4=5    2x=9    x=4.52x - 4 = 5 \implies 2x = 9 \implies x = 4.5.
Setting the argument of the function f(2x4)f(2x-4) equal to the original minimum input of 55 allows us to find the corresponding input xx for the function gg.
3
Apply the vertical transformations to find the output value of g(x)g(x) at x=4.5x = 4.5.
g(4.5)=3f(5)+7=3(2)+7=6+7=13g(4.5) = -3f(5) + 7 = -3(-2) + 7 = 6 + 7 = 13.
Substituting f(5)=2f(5) = -2 into the definition of g(x)g(x) gives the vertical transformation of the point.
4
Confirm that the point is indeed the maximum of the transformed function g(x)g(x).
Since f(2x4)2f(2x-4) \ge -2, multiplying by 3-3 yields 3f(2x4)6-3f(2x-4) \le 6. Adding 77 yields g(x)13g(x) \le 13, confirming that 1313 is the maximum value.
Multiplying a function by a negative number reflects its graph vertically, changing a minimum point into a maximum point.

Key Concept

Applying horizontal and vertical transformations to function coordinates, and understanding how vertical reflections affect the extrema (minima and maxima) of a graph.
Question 1834Question

In the xyxy-plane, the graph of the quadratic function f(x)=x2+bx+cf(x) = -x^2 + bx + c, where bb and cc are constants, has its vertex at (h,k)(h, k). The function gg is defined by g(x)=f(x3)+4g(x) = f(x - 3) + 4. The graph of gg passes through the origin (0,0)(0,0), and its vertex lies on the line y=xy = x in the first quadrant. What is the value of f(0)f(0)?

Show answer & explanation

Answer: -7

Answer

-7
The correct answer is 7-7. Representing f(x)f(x) in vertex form as f(x)=(xh)2+kf(x) = -(x-h)^2 + k tells us that translating the function 3 units right and 4 units up shifts the vertex from (h,k)(h, k) to (h+3,k+4)(h+3, k+4). Since this vertex lies on the line y=xy=x, we have h+3=k+4h+3 = k+4, or k=h1k = h-1. Since the vertex of gg lies in the first quadrant, its coordinates must be positive, meaning h>3h > -3 and k>4k > -4. Using the fact that the graph of gg passes through the origin, we have g(0)=0    f(3)+4=0    f(3)=4g(0) = 0 \implies f(-3) + 4 = 0 \implies f(-3) = -4. Substituting x=3x = -3 into the vertex form of f(x)f(x) gives (3h)2+k=4    (h+3)2k=4-(-3-h)^2 + k = -4 \implies (h+3)^2 - k = 4. Substituting k=h1k = h-1 yields (h+3)2(h1)=4    h2+5h+6=0(h+3)^2 - (h-1) = 4 \implies h^2 + 5h + 6 = 0, which factors into (h+2)(h+3)=0(h+2)(h+3) = 0. The solution h=3h = -3 is discarded because it places the vertex of gg at (0,0)(0,0), which is not in the first quadrant. Therefore, h=2h = -2 and k=3k = -3. Calculating f(0)f(0) gives h2+k=(2)2+(3)=7-h^2 + k = -(-2)^2 + (-3) = -7.

Step-by-Step Solution

1
Determine the vertex form of f(x)f(x) and the vertex of g(x)g(x).
Since f(x)=x2+bx+cf(x) = -x^2 + bx + c has its vertex at (h,k)(h, k), its vertex form is f(x)=(xh)2+kf(x) = -(x - h)^2 + k. The function g(x)=f(x3)+4g(x) = f(x - 3) + 4 represents a horizontal shift of ff by 3 units to the right and a vertical shift by 4 units up. Thus, the vertex of gg is (h+3,k+4)(h + 3, k + 4).
Understanding translations allows us to write the coordinates of the new vertex in terms of the original vertex variables.
2
Use the line y=xy = x and quadrant constraints to find a relation between hh and kk.
Since the vertex of gg lies on the line y=xy = x, we set its coordinates equal: h+3=k+4h + 3 = k + 4, which simplifies to k=h1k = h - 1. Additionally, because the vertex is in the first quadrant, we must have h+3>0h + 3 > 0 and k+4>0k + 4 > 0.
The geometric placement of the vertex on the line y=xy = x constrains its coordinate values.
3
Apply the condition that the graph of gg passes through the origin.
g(0)=0    f(3)+4=0    f(3)=4g(0) = 0 \implies f(-3) + 4 = 0 \implies f(-3) = -4. Substituting x=3x = -3 into the vertex form of f(x)f(x) gives (3h)2+k=4-(-3 - h)^2 + k = -4, which simplifies to (h+3)2k=4(h + 3)^2 - k = 4.
The point (0,0)(0,0) lying on the graph of gg provides an equation to solve for the vertex parameters.
4
Substitute k=h1k = h - 1 into the quadratic equation and solve for hh.
(h+3)2(h1)=4    h2+6h+9h+1=4    h2+5h+6=0(h + 3)^2 - (h - 1) = 4 \implies h^2 + 6h + 9 - h + 1 = 4 \implies h^2 + 5h + 6 = 0. Factoring gives (h+2)(h+3)=0(h + 2)(h + 3) = 0, so h=2h = -2 or h=3h = -3.
Substituting the linear relation into the quadratic equation isolates the variable hh.
5
Filter the solutions using the first quadrant constraint and calculate f(0)f(0).
If h=3h = -3, then k=4k = -4, giving the vertex of gg at (0,0)(0, 0), which is not in the first quadrant. If h=2h = -2, then k=3k = -3, giving the vertex of gg at (1,1)(1, 1), which is in the first quadrant. Thus, h=2h = -2 and k=3k = -3. The value of f(0)f(0) is f(0)=(0h)2+k=h2+k=(2)2+(3)=43=7f(0) = -(0 - h)^2 + k = -h^2 + k = -(-2)^2 + (-3) = -4 - 3 = -7.
The quadrant condition uniquely determines the correct vertex coordinates, allowing us to find the y-intercept of the original function.

Key Concept

Quadratic Functions and Graphs
Question 1835Question

For which values of xx is the inequality 4(2x5)3x+9-4(2x - 5) \geq 3x + 9 true?

Show answer & explanation

Answer: x1x \leq 1

Answer

The inequality is true for all values of xx such that xx is less than or equal to 11.
The correct inequality representing the solution set is the one that shows the variable is less than or equal to one.

Step-by-Step Solution

1
Distribute the factor of 4-4 to the terms inside the parentheses on the left side of the inequality.
8x+203x+9-8x + 20 \geq 3x + 9
Applying the distributive property gives 4×2x=8x-4 \times 2x = -8x and 4×5=20-4 \times -5 = 20.
2
Subtract 3x3x from both sides of the inequality to collect all terms with the variable xx on the left side.
11x+209-11x + 20 \geq 9
Grouping the variable terms helps isolate the variable.
3
Subtract 2020 from both sides of the inequality to isolate the variable term.
11x11-11x \geq -11
Subtracting twenty from both sides moves the constant terms to the right side of the inequality.
4
Divide both sides by 11-11 and reverse the direction of the inequality sign.
x1x \leq 1
Dividing or multiplying an inequality by a negative number requires flipping the inequality symbol.

Key Concept

Linear Inequalities in One Variable
Question 1836Question

Unlike almost all other vertebrates, fish of the family Channichthyidae, or Antarctic icefish, do not possess hemoglobin to transport oxygen in their blood. Instead, they survive in the freezing, oxygen-rich waters of the Southern Ocean by relying on oxygen dissolved directly in their blood plasma ______ biological anomaly is facilitated by their unusually large hearts and wide blood vessels, which pump blood at high rates.

Which choice completes the text so that it conforms to the conventions of Standard English?

Show answer & explanation

Answer: ; this

Answer

The correct answer is the option containing a semicolon followed by the pronoun 'this' ('; this').
The correct answer is the option that reads '; this'. The sentence contains two independent clauses: 'Instead, they survive in the freezing, oxygen-rich waters of the Southern Ocean by relying on oxygen dissolved directly in their blood plasma' and 'this biological anomaly is facilitated by their unusually large hearts and wide blood vessels, which pump blood at high rates.' A semicolon is a grammatically correct way to link two independent clauses without a coordinating conjunction.

Step-by-Step Solution

1
Analyze the structure of the two clauses separated by the blank.
The first clause ('Instead, they survive... blood plasma') is an independent clause because it has a subject and a verb and can stand alone. The second clause ('this biological anomaly... high rates') is also an independent clause with its own subject ('this biological anomaly') and verb ('is facilitated').
Identifying clause types is necessary to determine the appropriate punctuation and conjunctions needed to link them.
2
Determine the grammatically correct way to connect two independent clauses.
Two independent clauses must be joined by a period, a semicolon, or a coordinating conjunction (like 'and') preceded by a comma.
Joining two independent clauses with only a comma creates a comma splice, and joining them with no punctuation at all creates a run-on sentence.
3
Evaluate the choices to find the one that correctly connects the clauses without introducing grammatical or logical errors.
The choice containing '; this' uses a semicolon to separate the two independent clauses, which is grammatically correct. The choice with ', this' is a comma splice, the choice with 'this' is a run-on sentence, and the choice with ', although this' incorrectly uses a subordinating conjunction of contrast when the relationship between the clauses is explanatory.
The correct option must satisfy standard English grammar rules and preserve the logical connection between the ideas.

Key Concept

Clause Boundaries and Linking
Question 1837Question

If xx satisfies the equation below, what is the value of x3x - 3?

x2x+7=4x - \sqrt{2x + 7} = 4
Show answer & explanation

Answer: 6

Answer

6
The correct answer is the value 66. Isolating the radical in x2x+7=4x - \sqrt{2x + 7} = 4 gives x4=2x+7x - 4 = \sqrt{2x + 7}. Squaring both sides yields x28x+16=2x+7x^2 - 8x + 16 = 2x + 7, which simplifies to the quadratic equation x210x+9=0x^2 - 10x + 9 = 0. Factoring this equation gives (x9)(x1)=0(x - 9)(x - 1) = 0, yielding potential solutions of x=9x = 9 and x=1x = 1. Substituting these potential solutions back into the original equation reveals that x=9x = 9 is a valid solution because 925=49 - \sqrt{25} = 4, whereas x=1x = 1 is extraneous because 19=241 - \sqrt{9} = -2 \neq 4. The value of the expression x3x - 3 is 93=69 - 3 = 6.

Step-by-Step Solution

1
Isolate the radical term in the equation.
x4=2x+7x - 4 = \sqrt{2x + 7}
Before squaring both sides of a radical equation, it is best to isolate the radical term on one side.
2
Square both sides of the equation to eliminate the radical.
(x4)2=2x+7(x - 4)^2 = 2x + 7
Squaring a square root removes the radical, allowing us to solve the resulting algebraic equation.
3
Expand the squared binomial and move all terms to one side to set the quadratic equation to zero.
x210x+9=0x^2 - 10x + 9 = 0
(x4)2(x - 4)^2 expands to x28x+16x^2 - 8x + 16. Subtracting 2x2x and 77 from both sides gives the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
4
Factor the quadratic equation.
(x9)(x1)=0(x - 9)(x - 1) = 0
Finding two numbers that multiply to 99 and add to 10-10 gives 9-9 and 1-1. Thus, the potential solutions are x=9x = 9 and x=1x = 1.
5
Substitute both potential solutions back into the original equation to check for extraneous solutions.
x=9x = 9 is valid, while x=1x = 1 is extraneous.
Checking x=9x = 9: 92(9)+7=95=49 - \sqrt{2(9)+7} = 9 - 5 = 4 (true). Checking x=1x = 1: 12(1)+7=13=241 - \sqrt{2(1)+7} = 1 - 3 = -2 \neq 4 (false). Thus, x=9x = 9 is the only real solution.
6
Calculate the value of the requested expression x3x - 3.
93=69 - 3 = 6
Since the only valid solution is x=9x = 9, we substitute 99 into the expression x3x - 3 to find the final answer.

Key Concept

Radical equations require isolating the radical, squaring both sides, solving the resulting equation, and checking for extraneous solutions that do not satisfy the original equation.
Estimated Time:1m 30s
Question 1838Question

A student is editing a passage about early botanical photography. Complete the passage by typing the correct form of the noun 'botanist' in the blank. Based on the grammatical context of the passage, what is the correct plural possessive form of the noun 'botanist' that should be written in the blank?

Fill in the blanks below

During the nineteenth century, standard academic practice required botanists to preserve plant specimens through delicate drying and pressing techniques. However, the introduction of cyanotype photography offered a more durable and efficient alternative. By capturing precise silhouettes of leaves and flowers on light-sensitive paper, the new process greatly simplified efforts to document diverse flora.
Show answer & explanation

Answer

botanists'
The sentence requires a plural possessive noun because the context refers to the collective efforts of multiple botanists introduced in the first sentence. The plural noun is 'botanists', and its possessive form is created by adding an apostrophe after the 's', resulting in 'botanists''.

Step-by-Step Solution

1
Determine whether the noun 'botanist' should be singular or plural based on the context.
The first sentence refers to 'botanists' in the plural, establishing that the passage discusses the collective work of multiple scientists.
This identifies the correct grammatical number for the noun.
2
Determine whether the noun requires a possessive form to modify the noun 'efforts'.
The blank precedes the noun 'efforts', indicating that the efforts belong to the botanists. Thus, a possessive form is required.
This identifies the correct grammatical case for the noun.
3
Form the plural possessive of 'botanist'.
The plural form 'botanists' ends in 's', so the possessive is formed by adding an apostrophe after the 's', yielding 'botanists''.
This applies the correct English punctuation rule for plural possessive nouns.

Key Concept

Plural and Possessive Nouns and Pronouns
Question 1839Question

A 3D printer extrudes plastic filament at a constant rate of 88 millimeters per second. What is this rate, in meters per hour?

Show answer & explanation

Answer: 28.828.8

Answer

The rate is 28.828.8 meters per hour.
To convert the rate from millimeters per second to meters per hour, we apply the unit conversion factors. We convert millimeters to meters by dividing by 10001000, and convert seconds to hours by multiplying by 36003600. This gives: 8 mm/s×1 m1000 mm×3600 s1 hour=8×3.6=28.8 meters per hour8\text{ mm/s} \times \frac{1\text{ m}}{1000\text{ mm}} \times \frac{3600\text{ s}}{1\text{ hour}} = 8 \times 3.6 = 28.8\text{ meters per hour}.

Step-by-Step Solution

1
Convert the length unit from millimeters to meters.
Since 1 meter=1000 millimeters1\text{ meter} = 1000\text{ millimeters}, a rate of 8 millimeters per second8\text{ millimeters per second} is equal to 81000=0.008 meters per second\frac{8}{1000} = 0.008\text{ meters per second}.
To convert from a smaller unit (millimeters) to a larger unit (meters), divide by the conversion factor of 10001000.
2
Convert the time unit from seconds to hours.
Since 1 hour=3600 seconds1\text{ hour} = 3600\text{ seconds}, a rate of 0.008 meters per second0.008\text{ meters per second} is equal to 0.008×3600=28.8 meters per hour0.008 \times 3600 = 28.8\text{ meters per hour}.
To find the distance printed in one hour, multiply the distance printed in one second by the number of seconds in one hour (36003600).

Key Concept

Unit Conversions

Alternative Method

We can combine the conversion steps into a single conversion factor: 3600 seconds/hour1000 millimeters/meter=3.6 (meters \cdotseconds) / (millimeters \cdothour)\frac{3600\text{ seconds/hour}}{1000\text{ millimeters/meter}} = 3.6\text{ (meters \cdot seconds) / (millimeters \cdot hour)}. Multiplying the rate of 8 mm/s8\text{ mm/s} by 3.63.6 gives the rate directly as 28.8 m/h28.8\text{ m/h}.
Estimated Time:1m 0s
Question 1840Question

An electric vehicle is connected to a charging station. The energy stored in the vehicle's battery pack, EE, in kilowatt-hours (kWh), can be modeled by the equation E=0.75m+24.0E = 0.75m + 24.0, where mm is the number of minutes the vehicle has been charging. Which of the following is the best interpretation of the number 0.750.75 in this context?

Show answer & explanation

Answer: The increase in the energy stored in the battery pack, in kilowatt-hours, for each additional minute the vehicle is charged

Answer

The increase in the energy stored in the battery pack, in kilowatt-hours, for each additional minute the vehicle is charged
The coefficient of mm in the linear equation E=0.75m+24.0E = 0.75m + 24.0 is the slope of the line. In context, the slope represents the rate of change of the dependent variable (stored energy, EE) per unit increase of the independent variable (time, mm). Thus, 0.750.75 represents an increase of 0.750.75 kilowatt-hours in stored energy for each additional minute of charging.

Step-by-Step Solution

1
Identify the form and components of the given equation.
The equation E=0.75m+24.0E = 0.75m + 24.0 is in the slope-intercept form y=mx+by = mx + b, where m=0.75m = 0.75 is the slope and b=24.0b = 24.0 is the y-intercept.
To relate the numerical values in the equation to their mathematical interpretations.
2
Interpret the meaning of the slope in context.
The slope, 0.750.75, represents the unit rate of change of the dependent variable (energy EE in kWh) per unit change of the independent variable (time mm in minutes).
To explain what the coefficient of mm means in real-world terms.
3
Combine the units and direction of change.
Since 0.750.75 is positive, the energy increases by 0.750.75 kWh for every additional 11 minute of charging time.
To formulate the final contextual interpretation of the slope.

Key Concept

Interpreting the slope of a linear equation in a real-world context
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