Nephrology

337 questions

Question 201Question →

A patient in the surgical intensive care unit develops oliguria on the second day following an elective partial colectomy. Over the past 8 hours, the urinary catheter has drained only 150 mL of highly concentrated urine. The patient has been receiving maintenance intravenous fluids at a conservative rate due to a known history of heart failure with preserved ejection fraction.

Vital signs show a temperature of 37.2°C (99.0°F), heart rate of 105/min, and blood pressure of 102/65 mmHg. Physical examination reveals dry oral mucosa and flat jugular veins.

Laboratory studies are obtained:

Laboratory ParameterValue
Serum sodium140 mEq/L
Serum blood urea nitrogen48 mg/dL
Serum creatinine2.0 mg/dL
Urine sodium28 mEq/L
Urine creatinine80 mg/dL

Based on the provided laboratory values, calculate the patient's fractional excretion of sodium (FENa). (Enter your answer as a percentage.)

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Answer: 0.5

Answer

0.5
The correct answer is derived mathematically using the Fractional Excretion of Sodium (FENa) formula. By multiplying the urine sodium by the serum creatinine (28 × 2.0 = 56) and dividing that product by the multiplication of the serum sodium and urine creatinine (140 × 80 = 11200), the resulting ratio is 0.005. Multiplying this decimal by 100 expresses the final FENa as 0.5%. Physiologically, a value below 1% indicates robust tubular sodium reabsorption, which strongly suggests a prerenal mechanism for the patient's oliguria, consistent with volume depletion.

Step-by-Step Solution

1
Identify the formula used to calculate the fractional excretion of sodium.
FENa=UNa×PCrPNa×UCr×100FENa = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100
This formula relates the clearance of sodium to the clearance of creatinine to determine if the renal tubules are appropriately reabsorbing sodium in the setting of decreased renal perfusion.
2
Extract the specific variables needed from the provided laboratory table.
Urine sodium (UNaU_{Na}) = 28 mEq/L; Plasma (Serum) creatinine (PCrP_{Cr}) = 2.0 mg/dL; Plasma (Serum) sodium (PNaP_{Na}) = 140 mEq/L; Urine creatinine (UCrU_{Cr}) = 80 mg/dL.
Accurate variable identification prevents common inversion errors during calculation.
3
Substitute the values into the formula and calculate the percentage.
FENa=28×2.0140×80×100=5611200×100=0.005×100=0.5FENa = \frac{28 \times 2.0}{140 \times 80} \times 100 = \frac{56}{11200} \times 100 = 0.005 \times 100 = 0.5%
Completing the calculation yields the final value, which is less than 1%, clinically supporting a prerenal etiology for the patient's acute kidney injury.

Key Concept

Calculation of the Fractional Excretion of Sodium (FENa) to evaluate and differentiate etiologies of acute kidney injury.
Question 202Question →

A 32-year-old woman is brought to the emergency department by her husband due to progressive lethargy and confusion. She has a history of Crohn disease and has been experiencing frequent, voluminous, watery diarrhea for the past four days. Two days ago, she was prescribed oral hydrocodone-acetaminophen for an acute musculoskeletal back injury. Her husband reports she has been taking the pain medication more frequently than prescribed. Temperature is 37.1°C (98.8°F), blood pressure is 92/60 mm Hg, pulse is 112/min, and respirations are 8/min. Physical examination shows dry mucous membranes, decreased skin turgor, and pinpoint pupils. The patient is somnolent but arousable. Laboratory studies are obtained:

TestValue
Sodium136 mEq/L
Potassium2.8 mEq/L
Chloride115 mEq/L
Bicarbonate13 mEq/L
Arterial blood gas on room air:
TestValue
pH7.22
pCO2pCO_234 mm Hg
pO2pO_268 mm Hg

Based on these findings, which of the following best describes this patient's acid-base disorder?

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Answer: Normal anion gap metabolic acidosis and respiratory acidosis

Answer

Normal anion gap metabolic acidosis and respiratory acidosis
The correct answer is normal anion gap metabolic acidosis and respiratory acidosis. The patient's severe diarrhea causes a loss of bicarbonate, resulting in a primary metabolic acidosis. The first step in evaluating metabolic acidosis is calculating the anion gap (AG): AG=Na+−(Cl−+HCO3−)AG = Na^+ - (Cl^- + HCO_3^-). In this patient, AG=136−(115+13)=8AG = 136 - (115 + 13) = 8 mEq/L, which is within the normal range (8-12 mEq/L), confirming a normal anion gap metabolic acidosis (NAGMA). The next required step is evaluating for appropriate respiratory compensation using Winter's formula: Expected pCO2=(1.5×HCO3−)+8±2Expected\ pCO_2 = (1.5 \times HCO_3^-) + 8 \pm 2. For this patient, the expected pCO2pCO_2 is (1.5×13)+8=27.5±2(1.5 \times 13) + 8 = 27.5 \pm 2 mm Hg (range: 25.5 to 29.5 mm Hg). Because the patient's measured pCO2pCO_2 (34 mm Hg) is higher than the expected range, she is retaining more CO2CO_2 than she should. This indicates a concurrent primary respiratory acidosis. Clinically, this is explained by her recent overuse of hydrocodone-acetaminophen, leading to opiate-induced central respiratory depression (evidenced by lethargy, pinpoint pupils, and a respiratory rate of 8/min).

Step-by-Step Solution

1
Calculate the Anion Gap (AG).
AG=Na+−(Cl−+HCO3−)=136−(115+13)=8AG = Na^+ - (Cl^- + HCO_3^-) = 136 - (115 + 13) = 8 mEq/L.
To determine the mechanism of the primary metabolic acidosis (diarrhea-induced bicarbonate loss vs. unmeasured anions).
2
Calculate the expected respiratory compensation using Winter's formula.
Expected pCO2=(1.5×13)+8=19.5+8=27.5±2Expected\ pCO_2 = (1.5 \times 13) + 8 = 19.5 + 8 = 27.5 \pm 2 mm Hg (Range: 25.5 to 29.5 mm Hg).
To determine if the patient has a simple metabolic acidosis or a mixed acid-base disorder.
3
Compare expected pCO2pCO_2 to the measured pCO2pCO_2.
Measured pCO2pCO_2 (34 mm Hg) is greater than the expected range (25.5 - 29.5 mm Hg).
A measured pCO2pCO_2 higher than expected indicates a superimposed primary respiratory acidosis, driven here by opiate toxicity.

Key Concept

Patients with a primary metabolic acidosis must be evaluated for adequate respiratory compensation using Winter's formula. If the measured pCO2pCO_2 is higher than the calculated expected pCO2pCO_2, a concurrent primary respiratory acidosis is present.
Question 203Question →

Emergency medical responders transport a 6262-year-old woman to the emergency department due to progressive lethargy and a four-day history of a productive cough. Her past medical history is significant for severe chronic obstructive pulmonary disease. Upon arrival, her temperature is 38.8∘C38.8^\circ\text{C} (101.8∘F101.8^\circ\text{F}), blood pressure is 88/54 mm Hg88/54\text{ mm Hg}, pulse is 122/min122/\text{min}, and respirations are 26/min26/\text{min}. Oxygen saturation is 85%85\% on room air. Physical examination reveals a somnolent patient with prominent accessory muscle use, diffuse expiratory wheezing, and bilateral rhonchi. Laboratory results are as follows:

ParameterValue
Serum sodium138 mEq/L138\text{ mEq/L}
Serum potassium4.2 mEq/L4.2\text{ mEq/L}
Serum chloride102 mEq/L102\text{ mEq/L}
Serum bicarbonate12 mEq/L12\text{ mEq/L}
Blood urea nitrogen42 mg/dL42\text{ mg/dL}
Serum creatinine1.8 mg/dL1.8\text{ mg/dL}
Serum lactate6.5 mmol/L6.5\text{ mmol/L}

Arterial blood gas analysis (on room air):

ParameterValue
pH7.127.12
PaO2\text{PaO}_255 mm Hg55\text{ mm Hg}
PaCO2\text{PaCO}_238 mm Hg38\text{ mm Hg}

Which of the following best characterizes this patient's acid-base status?

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Answer: High anion gap metabolic acidosis and concurrent respiratory acidosis

Answer

High anion gap metabolic acidosis and concurrent respiratory acidosis
The patient's laboratory results demonstrate a high anion gap metabolic acidosis with a concurrent primary respiratory acidosis. First, the severe acidemia (pH 7.127.12) with a low bicarbonate (12 mEq/L12\text{ mEq/L}) establishes a primary metabolic acidosis. Next, calculating the anion gap (138−[102+12]=24 mEq/L138 - [102 + 12] = 24\text{ mEq/L}) confirms a high anion gap metabolic acidosis (HAGMA), which is driven by lactic acidosis from tissue hypoperfusion. Finally, Winter's formula must be applied to determine if the respiratory compensation is appropriate: Expected PaCO2=(1.5×HCO3−)+8±2\text{Expected PaCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2. For this patient, the expected PaCO2\text{PaCO}_2 is (1.5×12)+8=26±2 mm Hg(1.5 \times 12) + 8 = 26 \pm 2\text{ mm Hg}. Because the measured PaCO2\text{PaCO}_2 of 38 mm Hg38\text{ mm Hg} is significantly higher than the expected range of 24−28 mm Hg24-28\text{ mm Hg}, there is an inadequate respiratory response. This indicates a superimposed primary respiratory acidosis, a life-threatening complication in COPD patients experiencing acute respiratory failure alongside shock.

Step-by-Step Solution

1
Determine the primary acid-base disorder by evaluating the arterial pH and serum bicarbonate.
The pH is 7.127.12 (acidemia) and the serum bicarbonate is 12 mEq/L12\text{ mEq/L} (markedly low), indicating a primary metabolic acidosis.
Establishing the primary direction of the pH derangement dictates which subsequent diagnostic formulas are required.
2
Calculate the serum anion gap to characterize the metabolic acidosis.
Anion Gap=Na+−(Cl−+HCO3−)=138−(102+12)=24 mEq/L\text{Anion Gap} = \text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-) = 138 - (102 + 12) = 24\text{ mEq/L}. This confirms a high anion gap metabolic acidosis (HAGMA).
Differentiation between high and normal anion gap acidosis is essential for uncovering the underlying etiology (in this case, lactic acidosis from sepsis).
3
Apply Winter's formula to assess the adequacy of the respiratory compensation.
Expected PaCO2=(1.5×HCO3−)+8±2=(1.5×12)+8=26±2 mm Hg\text{Expected PaCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2 = (1.5 \times 12) + 8 = 26 \pm 2\text{ mm Hg}.
Metabolic acidosis stimulates central chemoreceptors to increase alveolar ventilation. Winter's formula predicts the physiologically appropriate PaCO2\text{PaCO}_2 for a given bicarbonate level.
4
Compare the measured PaCO2 to the expected PaCO2 range.
The measured PaCO2\text{PaCO}_2 is 38 mm Hg38\text{ mm Hg}, which is significantly higher than the maximum expected value of 28 mm Hg28\text{ mm Hg}.
Because the patient is retaining more CO2\text{CO}_2 than physiologically expected for her level of metabolic acidosis, a concurrent primary respiratory acidosis is present (consistent with her severe COPD exacerbation).

Key Concept

In patients with a primary metabolic acidosis, Winter's formula (Expected PaCO2=[1.5×HCO3−]+8±2\text{Expected PaCO}_2 = [1.5 \times \text{HCO}_3^-] + 8 \pm 2) must be used to evaluate if the respiratory compensation is adequate. A measured PaCO2\text{PaCO}_2 higher than the expected range indicates a superimposed primary respiratory acidosis.
Question 204Question →

Match each clinical patient presentation with the most likely corresponding urinalysis sediment finding.

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Items

A 68-year-old man develops oliguria and a rapidly rising serum creatinine level two days after an emergency repair of a ruptured abdominal aortic aneurysm that was complicated by profound intraoperative hypotension.
A 45-year-old woman presents with newly developed periorbital edema, dark-colored urine, and hypertension two weeks after recovering from a severe streptococcal pharyngeal infection.
A 52-year-old man develops a low-grade fever, a pruritic maculopapular rash, and acute kidney injury one week after starting treatment with a cephalosporin antibiotic for a skin infection.
A 60-year-old man with a 20-year history of poorly controlled type 2 diabetes mellitus is evaluated for progressive lower extremity edema, significant proteinuria, and severe hypoalbuminemia.

Matches

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Answer

The ischemic presentation matches with muddy brown granular casts; the post-infectious nephritic presentation matches with red blood cell casts; the medication-induced allergic presentation matches with white blood cell casts; and the diabetic nephrotic presentation matches with oval fat bodies.
Each correct pairing links a classic clinical presentation to its definitive microscopic urinary finding based on the compartment of the kidney affected. Ischemia affects the tubules (muddy brown casts), inflammation of the glomeruli allows RBC leakage (RBC casts), drug allergies inflame the interstitium (WBC casts), and severe podocyte damage causes massive lipiduria (fatty casts).

Step-by-Step Solution

1
Analyze each clinical vignette to determine the underlying renal pathophysiology.
Identified the four mechanisms: ischemic acute tubular necrosis, nephritic syndrome (glomerulonephritis), acute interstitial nephritis, and nephrotic syndrome.
Accurate diagnosis of the underlying mechanism is required to predict the microscopic findings in the urine.
2
Correlate the identified pathophysiology with its pathognomonic urinalysis sediment finding.
Matched ATN to muddy brown casts, glomerulonephritis to RBC casts, AIN to WBC casts, and nephrotic syndrome to fatty casts.
Different compartments of the kidney (tubules, glomeruli, interstitium) slough specific cellular materials into the urine when injured.

Key Concept

Correlation of distinct acute kidney injury and glomerular disease mechanisms with their classic urinalysis sediment patterns.
Question 205Question →

An emergency medical response team transports a young adult male to the hospital after he was discovered lethargic in his dormitory. The patient, a 22-year-old college student with a known psychiatric history, reportedly ingested a large, unknown quantity of over-the-counter pain relievers earlier in the day. Upon arrival at the triage desk, he is tachypneic and diaphoretic. Vital signs include a temperature of 38.1°C (100.6°F), blood pressure of 112/68 mm Hg, heart rate of 115/min, and respiratory rate of 28/min.

Laboratory evaluation is obtained immediately:

Sodium: 140140 mEq/L
Potassium: 4.24.2 mEq/L
Chloride: 103103 mEq/L
Bicarbonate: 1313 mEq/L
Blood urea nitrogen: 1818 mg/dL
Creatinine: 1.01.0 mg/dL

Arterial blood gas parameters on room air:
pH: 7.437.43
PaCO2: 2020 mm Hg
PaO2: 9898 mm Hg

Based on the provided laboratory parameters, which of the following accurately characterizes the primary acid-base disturbance(s) in this patient?

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Answer: Mixed high anion gap metabolic acidosis and respiratory alkalosis

Answer

Mixed high anion gap metabolic acidosis and respiratory alkalosis
This patient's clinical presentation (lethargy, tachypnea, ingestion of over-the-counter medication) and laboratory findings are highly characteristic of salicylate (aspirin) toxicity. Salicylates cause a classic mixed acid-base disorder: they directly stimulate the medullary respiratory center to cause a primary respiratory alkalosis, and they disrupt cellular metabolism by uncoupling oxidative phosphorylation, leading to organic acid accumulation and a primary high anion gap metabolic acidosis.

This can be proven mathematically:
1. The pH of 7.437.43 indicates alkalemia, meaning the dominant primary disorder is a respiratory alkalosis (driven by the PaCO2 of 2020 mm Hg).
2. The expected acute metabolic compensation for a PaCO2 drop of 2020 mm Hg (from the baseline of 4040) is a 44 mEq/L drop in HCO3−HCO_3^- (22 mEq/L per 1010 mm Hg drop in PaCO2). The expected HCO3−HCO_3^- is therefore 2020 mEq/L.
3. The patient's actual HCO3−HCO_3^- is 1313 mEq/L, which is far lower than the compensatory 2020 mEq/L. This signifies an additional, independent primary metabolic acidosis.
4. The anion gap is calculated as Na+−(Cl−+HCO3−)=140−(103+13)=24Na^+ - (Cl^- + HCO_3^-) = 140 - (103 + 13) = 24 mEq/L. Since this is greater than the normal maximum of 1212 mEq/L, the metabolic component is specifically a high anion gap metabolic acidosis.

Alternatively, applying Winter's formula to the metabolic acidosis: Expected PaCO2=(1.5×13)+8=27.5±2Expected\ PaCO_2 = (1.5 \times 13) + 8 = 27.5 \pm 2 mm Hg. Because the measured PaCO2 (2020 mm Hg) is well below this range, a concurrent respiratory alkalosis is definitively present.

Step-by-Step Solution

1
Determine the primary acid-base disorder based on the pH.
The pH is 7.437.43, indicating alkalemia. The low PaCO2 (2020 mm Hg) aligns with this, establishing a primary respiratory alkalosis.
Identifying the primary disturbance directs the appropriate compensation formula to use.
2
Calculate the expected metabolic compensation for the primary respiratory alkalosis.
For acute respiratory alkalosis, HCO3−HCO_3^- decreases by 22 mEq/L per 1010 mm Hg drop in PaCO2. A drop from 4040 to 2020 mm Hg (a difference of 2020) should decrease HCO3−HCO_3^- by 44. Expected HCO3−HCO_3^- is 24−4=2024 - 4 = 20 mEq/L.
This determines if the low bicarbonate is solely compensatory or represents a concurrent primary metabolic acidosis.
3
Compare the measured bicarbonate to the expected compensatory value.
The measured HCO3−HCO_3^- (1313 mEq/L) is significantly lower than the expected 2020 mEq/L, confirming an additional primary metabolic acidosis.
A significant deviation from expected compensation indicates a mixed acid-base disorder.
4
Calculate the anion gap to classify the metabolic acidosis.
Anion Gap = Na+−(Cl−+HCO3−)=140−(103+13)=24Na^+ - (Cl^- + HCO_3^-) = 140 - (103 + 13) = 24 mEq/L. Since 24>1224 > 12, it is a high anion gap metabolic acidosis.
Metabolic acidosis must always be classified as normal or high anion gap to narrow the differential diagnosis.

Key Concept

Salicylate toxicity classically causes a mixed acid-base disorder: a primary respiratory alkalosis due to direct medullary respiratory center stimulation, and a primary high anion gap metabolic acidosis due to uncoupling of oxidative phosphorylation.
Estimated Time:1m 30s
Question 206Question →

A 48-year-old man with a history of severe alcohol use disorder is brought to the emergency department by paramedics after being found obtunded in a park. His temperature is 36.2∘C36.2^\circ\text{C} (97.2∘F97.2^\circ\text{F}), blood pressure is 110/70 mmHg110/70\text{ mmHg}, pulse is 105/min105/\text{min}, and respiratory rate is 18/min18/\text{min}. The patient is unarousable and responds only to painful stimuli.

Initial laboratory studies reveal the following:

Laboratory ParameterValue
Sodium138 mEq/L138\text{ mEq/L}
Potassium4.2 mEq/L4.2\text{ mEq/L}
Chloride104 mEq/L104\text{ mEq/L}
Bicarbonate22 mEq/L22\text{ mEq/L}
Blood urea nitrogen (BUN)28 mg/dL28\text{ mg/dL}
Creatinine1.1 mg/dL1.1\text{ mg/dL}
Glucose126 mg/dL126\text{ mg/dL}
Ethanol92 mg/dL92\text{ mg/dL}
Measured serum osmolality340 mOsm/kg H2O340\text{ mOsm/kg H}_2\text{O}

Based on the provided laboratory results, what is this patient's serum osmolar gap in mOsm/kg H2O\text{mOsm/kg H}_2\text{O}?

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Answer: 27

Answer

27
The serum osmolar gap is defined as the difference between the measured serum osmolality and the calculated serum osmolality. The standard formula for calculated serum osmolality in the United States (using mg/dL\text{mg/dL} for glucose and BUN) is 2×[Na+]+[Glucose]18+[BUN]2.82 \times [\text{Na}^+] + \frac{[\text{Glucose}]}{18} + \frac{[\text{BUN}]}{2.8}. However, when ethanol is present and measured, its contribution must also be subtracted to isolate the gap caused by other unidentified toxic alcohols (e.g., methanol, ethylene glycol). The conversion factor for ethanol is 4.64.6. Therefore, the complete calculation for this patient is 2×138+12618+282.8+924.6=276+7+10+20=313 mOsm/kg H2O2 \times 138 + \frac{126}{18} + \frac{28}{2.8} + \frac{92}{4.6} = 276 + 7 + 10 + 20 = 313 \text{ mOsm/kg H}_2\text{O}. Subtracting this from the measured osmolality of 340 mOsm/kg H2O340 \text{ mOsm/kg H}_2\text{O} gives a gap of 27 mOsm/kg H2O27 \text{ mOsm/kg H}_2\text{O}.

Step-by-Step Solution

1
Identify the need to calculate the serum osmolar gap.
The patient has altered mental status and a measured serum osmolality of 340 mOsm/kg H2O340 \text{ mOsm/kg H}_2\text{O}, indicating a potential toxic alcohol ingestion.
Calculating the osmolar gap is essential to unmask the presence of unmeasured osmotically active substances (like methanol, ethylene glycol, or isopropyl alcohol) not accounted for by standard chemistry panels.
2
Calculate the expected (calculated) serum osmolality.
Using the expanded formula: 2×138+12618+282.8+924.6=276+7+10+20=313 mOsm/kg H2O2 \times 138 + \frac{126}{18} + \frac{28}{2.8} + \frac{92}{4.6} = 276 + 7 + 10 + 20 = 313 \text{ mOsm/kg H}_2\text{O}.
Because ethanol is present in the patient's blood, its osmotic contribution must be included in the calculation. Failure to include it will result in an artificially elevated osmolar gap.
3
Determine the osmolar gap.
340 (Measured)−313 (Calculated)=27 mOsm/kg H2O340 \text{ (Measured)} - 313 \text{ (Calculated)} = 27 \text{ mOsm/kg H}_2\text{O}.
The osmolar gap is the difference between the measured and calculated osmolality. A normal gap is typically less than 10-15 mOsm/kg H2O10\text{-}15 \text{ mOsm/kg H}_2\text{O}. A gap of 2727 is elevated, suggesting ingestion of an additional toxic alcohol.

Key Concept

Calculation of the serum osmolar gap, including the proper osmotic contribution of ethanol.
Question 207Question →

Match each clinical vignette describing a renal or electrolyte complication of pharmacotherapy with the most likely responsible mechanism or drug effect.

Click a left item, then click its matching right item

Items

An inpatient being treated for a severe Pseudomonas aeruginosa bloodstream infection develops a progressive decline in renal function on the eighth day of antimicrobial therapy. The patient remains non-oliguric, but microscopic urinalysis shows an abundance of pigmented, granular casts.
A young adult receiving high-dose intravenous therapy for suspected herpes simplex encephalitis experiences a sudden decrease in urine output 48 hours after admission. Renal function rapidly deteriorates, and urine microscopy shows distinct needle-shaped, birefringent structures.
An individual managed for bipolar disorder reports excessive thirst and frequent urination of large volumes of pale fluid. Clinical evaluation reveals hypernatremia, and a water deprivation test shows persistently low urine osmolality that does not correct with the administration of exogenous desmopressin.
An immunocompromised patient on prophylactic therapy for Pneumocystis jirovecii is found to have elevated serum potassium and creatinine levels during a routine check. However, a specialized renal clearance study confirms that the true glomerular filtration rate has remained completely normal.

Matches

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Answer

The correct pairings match the anti-pseudomonal therapy complication to aminoglycoside-induced ATN, the encephalitis treatment complication to intratubular acyclovir precipitation, the bipolar treatment complication to lithium-induced nephrogenic diabetes insipidus, and the pneumonia prophylaxis complication to trimethoprim-induced channel blockade.
Each medication causes a unique and predictable pattern of renal impairment. Aminoglycosides directly damage proximal tubular cells causing ATN. Acyclovir is relatively insoluble in urine and precipitates in the tubules. Lithium impairs aquaporin insertion in the collecting duct. Trimethoprim acts on specific transporters without damaging the glomerulus itself.

Step-by-Step Solution

1
Analyze the first vignette featuring a delayed, gradual rise in creatinine and pigmented granular casts during anti-pseudomonal therapy.
Identified as acute tubular necrosis.
Aminoglycosides are classically associated with delayed-onset, non-oliguric ATN characterized by muddy brown casts.
2
Evaluate the second vignette detailing rapid oliguric acute kidney injury and needle-shaped crystals during treatment for viral encephalitis.
Identified as acyclovir crystal nephropathy.
Intravenous acyclovir is notorious for precipitating in the renal tubules, forming birefringent crystals and causing obstructive nephropathy.
3
Assess the third vignette describing polyuria, hypernatremia, and desmopressin-resistant dilute urine in a patient with a psychiatric history.
Identified as lithium-induced nephrogenic diabetes insipidus.
Lithium is a primary cause of acquired nephrogenic diabetes insipidus, which presents with ADH resistance at the collecting duct.
4
Examine the fourth vignette showing isolated hyperkalemia and elevated creatinine without true GFR decline during opportunistic pneumonia prophylaxis.
Identified as trimethoprim effect.
Trimethoprim blocks ENaC in the distal nephron (causing hyperkalemia) and inhibits creatinine secretion (elevating serum creatinine artificially).

Key Concept

Recognizing the distinct clinical presentations, timing, and urinary findings of medication-induced nephrotoxicity and electrolyte derangements.
Estimated Time:1m 30s
Question 208Question →

A 27-year-old woman is brought to the emergency department by her roommate due to severe weakness and four days of intractable vomiting. The patient has type 1 diabetes mellitus but has not administered her insulin for the past two days because she has been unable to tolerate oral intake. On physical examination, she appears lethargic. Her temperature is 37.1°C (98.8°F), blood pressure is 92/58 mm Hg, pulse is 122/min, and respirations are 16/min. Her mucous membranes are notably dry and skin turgor is decreased. Laboratory studies show the following:

Laboratory TestResult
Sodium142 mEq/L142 \text{ mEq/L}
Potassium3.8 mEq/L3.8 \text{ mEq/L}
Chloride94 mEq/L94 \text{ mEq/L}
Bicarbonate20 mEq/L20 \text{ mEq/L}
Blood urea nitrogen35 mg/dL35 \text{ mg/dL}
Creatinine1.4 mg/dL1.4 \text{ mg/dL}
Glucose512 mg/dL512 \text{ mg/dL}

An arterial blood gas on room air reveals:

TestResult
pH7.347.34
PaCO2PaCO_238 mm Hg38 \text{ mm Hg}
PaO2PaO_294 mm Hg94 \text{ mm Hg}

Which of the following best describes this patient's acid-base status?

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Answer: High anion gap metabolic acidosis and metabolic alkalosis

Answer

The patient has a mixed acid-base disorder consisting of a high anion gap metabolic acidosis (due to diabetic ketoacidosis) and a concurrent metabolic alkalosis (due to severe vomiting).
This patient presents with a high anion gap metabolic acidosis (HAGMA) driven by diabetic ketoacidosis, evidenced by an anion gap of 28 (normal ~12). Despite the severe HAGMA, her bicarbonate is only mildly depressed at 20 mEq/L. To fully evaluate a HAGMA, the delta gap must be calculated to look for mixed metabolic disorders. The delta gap here is 16 (28 - 12). If HAGMA were the sole disorder, the bicarbonate should drop by an amount equal to the delta gap, resulting in an expected bicarbonate of 8 mEq/L (24 - 16 = 8). Because the patient's actual measured bicarbonate (20 mEq/L) is much higher than 8 mEq/L, there must be a second disorder independently raising the bicarbonate. In this clinical scenario, prolonged vomiting leads to substantial hydrogen ion and chloride loss, generating a concurrent metabolic alkalosis. Finally, Winter's formula calculation (1.5×20+8=381.5 \times 20 + 8 = 38) perfectly matches the patient's measured PaCO2, confirming appropriate respiratory compensation and ruling out any superimposed respiratory disorder.

Step-by-Step Solution

1
Calculate the primary anion gap to determine the core metabolic disorder.
AG=142−(94+20)=28AG = 142 - (94 + 20) = 28.
An anion gap greater than 12 indicates the presence of a high anion gap metabolic acidosis (HAGMA), which in this patient is due to diabetic ketoacidosis.
2
Calculate the expected respiratory compensation using Winter's formula.
Expected PaCO2=(1.5×20)+8=38±2 mm HgPaCO_2 = (1.5 \times 20) + 8 = 38 \pm 2 \text{ mm Hg}. The measured PaCO2PaCO_2 is exactly 38 mm Hg38 \text{ mm Hg}.
Because the measured PaCO2PaCO_2 falls precisely within the expected range, there is no concurrent respiratory acidosis or alkalosis.
3
Calculate the delta gap (delta-delta) to identify hidden secondary metabolic disorders.
ΔAG=28−12=16\Delta AG = 28 - 12 = 16. The expected normal HCO3−HCO_3^- if only HAGMA were present is 24−16=8 mEq/L24 - 16 = 8 \text{ mEq/L}. The measured HCO3−HCO_3^- is 20 mEq/L20 \text{ mEq/L}.
Because the measured bicarbonate (20 mEq/L20 \text{ mEq/L}) is significantly higher than the expected compensated bicarbonate (8 mEq/L8 \text{ mEq/L}), a second disorder that independently raises bicarbonate must be present—specifically, a metabolic alkalosis.

Key Concept

In a patient with a high anion gap metabolic acidosis, calculating the delta gap is essential to identify hidden concurrent metabolic disorders. If the measured bicarbonate is significantly higher than the expected bicarbonate (calculated as 24 minus the delta gap), a concurrent metabolic alkalosis is present.
Question 209Question →

Match each clinical presentation of hypokalemic metabolic alkalosis with its corresponding underlying pathophysiologic mechanism.

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Items

Adolescent evaluated for polyuria and polydipsia. Assessment reveals a blood pressure of 90/60 mm Hg, hypokalemia, metabolic alkalosis, and markedly elevated urine calcium levels.
Young adult referred for incidental profound hypokalemia. Blood pressure is 112/72 mm Hg. Further evaluation reveals metabolic alkalosis, hypomagnesemia, and decreased urinary calcium excretion.
Young patient presenting with severe, early-onset hypertension (170/110 mm Hg) and a family history of premature strokes. Labs demonstrate hypokalemia, metabolic alkalosis, and profoundly suppressed levels of both plasma renin activity and aldosterone.
Individual evaluated for resistant hypertension and a cervical bruit. Blood work demonstrates hypokalemia, metabolic alkalosis, high plasma renin activity, and high serum aldosterone levels.
Adult presenting with muscle cramps and treatment-resistant hypertension. Laboratory studies reveal hypokalemia, metabolic alkalosis, suppressed plasma renin activity, and elevated serum aldosterone concentration.

Matches

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Answer

The presentations map to their underlying mechanisms based on blood pressure and neurohormonal profiles: Bartter syndrome involves the Na⁺-K⁺-2Cl⁻ cotransporter; Gitelman syndrome involves the NaCl cotransporter; Liddle syndrome involves ENaC; Renovascular hypertension involves reduced afferent perfusion; and Conn syndrome involves autonomous adrenal hypersecretion.
Each clinical presentation aligns with the physiologic consequences of its specific cellular defect. Tubular wasting syndromes (Bartter/Gitelman) cause hypokalemia with normal or low blood pressure, and are differentiated by urine calcium levels. Hypertensive syndromes (Liddle, primary, and secondary hyperaldosteronism) are successfully differentiated by analyzing the renin-aldosterone profile.

Step-by-Step Solution

1
Assess the patient's blood pressure status.
Patients with Bartter and Gitelman syndromes are typically normotensive or hypotensive, while those with Liddle syndrome, primary hyperaldosteronism, and secondary hyperaldosteronism present with hypertension.
Blood pressure distinguishes volume-depleted states caused by tubular salt-wasting from volume-expanded states caused by excessive sodium retention.
2
Evaluate the plasma renin activity and aldosterone levels in the hypertensive patients.
High renin and high aldosterone indicate secondary hyperaldosteronism. Low renin and high aldosterone indicate primary hyperaldosteronism. Low renin and low aldosterone indicate an aldosterone-independent mechanism of sodium retention, such as Liddle syndrome.
The renin-angiotensin-aldosterone axis feedback loop localizes the primary defect causing the hypertension.
3
Evaluate urine calcium excretion and serum magnesium in the normotensive/hypotensive patients.
Hypercalciuria points to a thick ascending limb defect (Bartter syndrome), whereas hypocalciuria and hypomagnesemia point to a distal convoluted tubule defect (Gitelman syndrome).
Calcium and magnesium handling differ fundamentally based on the specific renal tubular segment affected.

Key Concept

Differential diagnosis of hypokalemic metabolic alkalosis based on blood pressure, the renin-aldosterone axis, and urine electrolytes.
Estimated Time:2m 0s
Question 210Question →

Which specific glomerular disease diagnosis best corresponds to each of the following patient clinical scenarios?

Click a left item, then click its matching right item

Items

A 2424-year-old man develops gross hematuria 4848 hours after the onset of viral pharyngitis. Serum C3 and C4 are normal.
A 1010-year-old boy has periorbital edema and dark urine 33 weeks after an episode of impetigo. Serum C3 is low.
A 4545-year-old man presents with hemoptysis and oliguria. Urinalysis shows RBC casts. Anti-GBM testing is positive.
A 5555-year-old man with chronic hepatitis B presents with lower extremity edema and a 2424-hour urine protein of 5.55.5 g.
A 66-year-old boy presents with sudden-onset anasarca. Urinalysis shows 4+4+ proteinuria and 00 RBCs per high-power field.

Matches

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Answer

The synpharyngitic hematuria pairs with IgA nephropathy; the post-impetigo nephritic syndrome pairs with Poststreptococcal glomerulonephritis; the pulmonary-renal syndrome pairs with Goodpasture syndrome; the hepatitis B-associated nephrotic syndrome pairs with Membranous nephropathy; and the childhood pure nephrotic syndrome pairs with Minimal change disease.
Accurate diagnosis of glomerular diseases requires synthesizing patient age, timing of symptom onset relative to triggers, presence of nephritic versus nephrotic syndrome, and specific serologic markers such as complement levels or autoantibodies.

Step-by-Step Solution

1
Analyze the patient age and timeline of symptom onset relative to triggering infections.
Identifies synpharyngitic presentation for IgA nephropathy versus a delayed post-infectious timeline.
Timing is a key discriminator for nephritic syndromes.
2
Evaluate laboratory data, specifically proteinuria levels and serum complement.
Categorizes the presentations into nephritic (hematuria, RBC casts) versus nephrotic (protein >3.5>3.5 g/day) and identifies C3 consumption.
Complement levels differentiate immune-complex mediated glomerulonephritides.
3
Correlate specific systemic symptoms and comorbidities with renal manifestations.
Hemoptysis points to pulmonary-renal syndromes; hepatitis B points to specific secondary nephropathies.
Systemic clues are essential for diagnosing secondary causes of glomerular disease.

Key Concept

Clinical presentation and diagnosis of primary and secondary glomerular diseases
Question 211Question →

A 60-year-old man with a history of peptic ulcer disease is brought to the emergency department due to 5 days of severe, intractable nausea and nonbilious vomiting. He reports being unable to tolerate any oral intake and feels profoundly weak. On physical examination, the patient appears lethargic. His mucous membranes are markedly dry, and capillary refill is prolonged. Temperature is 37.1 C (98.8 F), blood pressure is 88/55 mm Hg, pulse is 118/min, and respirations are 16/min. Laboratory studies are as follows:

Laboratory testResultReference range
Serum sodium140 mEq/L136-145 mEq/L
Serum potassium3.1 mEq/L3.5-5.0 mEq/L
Serum chloride86 mEq/L98-106 mEq/L
Serum bicarbonate24 mEq/L22-28 mEq/L
Blood urea nitrogen75 mg/dL8-20 mg/dL
Serum creatinine3.8 mg/dL0.7-1.3 mg/dL
Arterial blood gas (room air)ResultReference range
pH7.407.35-7.45
PaCO240 mm Hg35-45 mm Hg
PaO290 mm Hg75-105 mm Hg

Which of the following is the most accurate interpretation of this patient's acid-base status?

Show answer & explanation

Answer: High anion gap metabolic acidosis and metabolic alkalosis

Answer

High anion gap metabolic acidosis and metabolic alkalosis
The correct answer accurately identifies a mixed acid-base disorder by utilizing the anion gap and delta-delta calculations. Even when the pH and bicarbonate are normal, an anion gap must be calculated. The anion gap is significantly elevated at 30 mEq/L30 \text{ mEq/L} (normal is approximately 12 mEq/L12 \text{ mEq/L}), indicating a high anion gap metabolic acidosis (HAGMA) due to poor perfusion and acute kidney injury. The delta gap (ΔAG=30−12=18\Delta AG = 30 - 12 = 18) indicates that the bicarbonate should have fallen by 18 mEq/L18 \text{ mEq/L} to an expected level of 6 mEq/L6 \text{ mEq/L}. Because the measured bicarbonate is 24 mEq/L24 \text{ mEq/L}, there is a concurrent severe metabolic alkalosis perfectly balancing the acidosis. This is consistent with his severe vomiting, which causes hypochloremic metabolic alkalosis via the loss of gastric H+H^+ and Cl−Cl^-.

Step-by-Step Solution

1
Evaluate the primary acid-base values from the arterial blood gas.
The pH is 7.40, PaCO2PaCO_2 is 40 mm Hg, and HCO3−HCO_3^- is 24 mEq/L. These values are all within strictly normal limits.
Establishing the baseline acid-base status is the required first step in interpretation, but normal values do not preclude mixed disorders.
2
Calculate the serum anion gap using the formula: AG=Na+−(Cl−+HCO3−)AG = Na^+ - (Cl^- + HCO_3^-).
Anion gap = 140−(86+24)=140−110=30 mEq/L140 - (86 + 24) = 140 - 110 = 30 \text{ mEq/L}.
The anion gap must always be calculated, even if pH and HCO3−HCO_3^- are normal, to avoid missing a hidden high anion gap metabolic acidosis (HAGMA).
3
Calculate the expected bicarbonate level using the delta gap (ΔAG\Delta AG) to check for a mixed disorder.
Expected HCO3−=24−(Measured AG−Normal AG)=24−(30−12)=6 mEq/LHCO_3^- = 24 - (\text{Measured AG} - \text{Normal AG}) = 24 - (30 - 12) = 6 \text{ mEq/L}. Since measured HCO3−HCO_3^- (24 mEq/L) is much higher than the expected HCO3−HCO_3^- (6 mEq/L), there is a concurrent metabolic alkalosis.
A delta gap analysis reveals additional metabolic disturbances that are masked by opposing effects on the serum bicarbonate level.
4
Correlate the calculated mixed acid-base disorder with the patient's clinical presentation.
The HAGMA is driven by lactic acidosis (hypoperfusion) and uremia (acute kidney injury), while the metabolic alkalosis is driven by severe vomiting (loss of H+H^+ and Cl−Cl^-).
Clinical correlation confirms the pathophysiologic etiology of the identified disorders.

Key Concept

In patients with severe vomiting and hypoperfusion, opposing acid-base disturbances (metabolic alkalosis and HAGMA) can result in a deceptively normal pH and bicarbonate. Calculating the anion gap and delta gap is essential to unmask the mixed disorder.

Alternative Method

The delta ratio (ΔAGΔHCO3−\frac{\Delta AG}{\Delta HCO_3^-}) can also be used to evaluate mixed disorders. Delta ratio = 30−1224−24=180\frac{30 - 12}{24 - 24} = \frac{18}{0}. As the denominator approaches zero, the ratio approaches infinity. Any delta ratio >2.0> 2.0 strongly indicates a concurrent metabolic alkalosis.
Estimated Time:1m 30s
Question 212Question →

Emergency medical services bring a 47-year-old mechanic to the hospital after he was found deeply lethargic in his workshop. His coworkers report that he had been working alone on a vehicle's cooling system and seemed disoriented before collapsing. On presentation, his temperature is 36.8∘C36.8^\circ C (98.2∘F98.2^\circ F), blood pressure is 105/65105/65 mmHg, pulse is 112112/min, and respiratory rate is 2424/min. Physical examination reveals an unarousable patient with deep, rapid breathing. Arterial blood gas analysis on room air shows a pH of 7.21, PaCO2PaCO_2 of 24 mmHg, and PaO2PaO_2 of 95 mmHg.

Laboratory evaluation reveals the following:
ParameterValue
Sodium142142 mEq/L
Potassium4.84.8 mEq/L
Chloride104104 mEq/L
Bicarbonate1010 mEq/L
Blood urea nitrogen1414 mg/dL
Creatinine1.61.6 mg/dL
Glucose9090 mg/dL
Measured serum osmolality334334 mOsm/kg H2OH_2O

Based on the provided laboratory results, what is the patient's calculated serum osmolar gap in mOsm/kg H2OH_2O?

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Answer: 40

Answer

40
The correct answer is 40. The serum osmolar gap is defined as the difference between the directly measured serum osmolality and the calculated serum osmolality. The formula for calculated serum osmolality in conventional units (mg/dL) is: Calculated Osmolality=2×[Na+]+[Glucose]18+[BUN]2.8Calculated\ Osmolality = 2 \times [Na^+] + \frac{[Glucose]}{18} + \frac{[BUN]}{2.8}. Using the patient's values, this is computed as 2(142)+9018+142.8=284+5+5=2942(142) + \frac{90}{18} + \frac{14}{2.8} = 284 + 5 + 5 = 294 mOsm/kg H2OH_2O. The measured osmolality is 334 mOsm/kg H2OH_2O. Subtracting the calculated value from the measured value yields an osmolar gap of 334−294=40334 - 294 = 40 mOsm/kg H2OH_2O. A normal osmolar gap is typically less than 10 to 15 mOsm/kg H2OH_2O. In a patient with central nervous system depression, high anion gap metabolic acidosis, and exposure to automotive fluids, a markedly elevated osmolar gap strongly suggests intoxication with an unmeasured osmotically active alcohol, such as ethylene glycol (antifreeze).

Step-by-Step Solution

1
Calculate the expected serum osmolality using the standard formula for conventional units.
294294 mOsm/kg H2OH_2O
This establishes the baseline osmolality contributed by the primary endogenous osmoles (sodium, glucose, and urea).
2
Subtract the calculated osmolality from the measured serum osmolality.
334−294=40334 - 294 = 40 mOsm/kg H2OH_2O
An elevated difference (gap >10 mOsm/kg) indicates the presence of unmeasured exogenous osmotically active substances, such as ethylene glycol.

Key Concept

Calculation and interpretation of the serum osmolar gap in toxic alcohol ingestion.
Question 213Question →

A 68-year-old man is evaluated in the hospital for decreased urine output. He was admitted 3 days ago for severe community-acquired pneumonia and has been receiving intravenous antibiotics. His blood pressure is 98/60 mm Hg and heart rate is 102/min. Physical examination shows dry mucous membranes and flat jugular veins. Laboratory studies are obtained to evaluate his acute kidney injury:

Laboratory TestResult
Serum sodium135 mEq/L
Serum creatinine1.5 mg/dL
Blood urea nitrogen38 mg/dL
Urine sodium27 mEq/L
Urine creatinine60 mg/dL

What is the patient's fractional excretion of sodium (FeNa) expressed as a percentage?

Show answer & explanation

Answer: 0.5

Answer

0.5
The correct calculation yields a fractional excretion of sodium (FeNa) of exactly 0.5%. A FeNa of < 1% indicates a prerenal etiology for acute kidney injury. In this patient, signs of volume depletion (hypotension, tachycardia, dry mucous membranes) point toward prerenal azotemia secondary to dehydration, leading the kidneys to avidly reabsorb sodium and water in an attempt to restore intravascular volume.

Step-by-Step Solution

1
Identify the formula for Fractional Excretion of Sodium (FeNa).
FeNa=UNa×PCrPNa×UCr×100FeNa = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100
This formula relates the amount of sodium excreted to the amount of creatinine excreted, thereby correcting for urine concentration.
2
Extract the necessary values from the provided laboratory table.
UNa=27U_{Na} = 27 mEq/L, PCr=1.5P_{Cr} = 1.5 mg/dL, PNa=135P_{Na} = 135 mEq/L, and UCr=60U_{Cr} = 60 mg/dL.
These specific variables are required for the FeNa equation. The Blood Urea Nitrogen (BUN) value of 38 mg/dL is a distractor for this specific calculation.
3
Substitute the values into the FeNa equation.
FeNa=27×1.5135×60×100FeNa = \frac{27 \times 1.5}{135 \times 60} \times 100
Plugging the values into the correct positions in the numerator and denominator ensures mathematical accuracy.
4
Perform the arithmetic calculation.
40.58100×100=0.005×100=0.5\frac{40.5}{8100} \times 100 = 0.005 \times 100 = 0.5
This yields the final FeNa value as a percentage, which can then be interpreted clinically.

Key Concept

Calculation and interpretation of Fractional Excretion of Sodium (FeNa) in the evaluation of Acute Kidney Injury.
Question 214Question →

A 64-year-old woman is brought to the emergency department by her family due to profound weakness and confusion. She has had 5 days of severe, voluminous watery diarrhea. Her medical history includes type 2 diabetes mellitus and hypertension. On examination, blood pressure is 82/50 mm Hg, heart rate is 118/min, and respiratory rate is 24/min. She has dry mucous membranes, flat neck veins, and delayed capillary refill.

Laboratory studies show:
Serum Na+Na^+: 140 mEq/L
Serum K+K^+: 3.2 mEq/L
Serum Cl−Cl^-: 112 mEq/L
Serum HCO3−HCO_3^-: 8 mEq/L
Blood urea nitrogen: 54 mg/dL
Serum creatinine: 2.8 mg/dL (baseline 0.9 mg/dL)
Serum lactate: 5.2 mmol/L (Normal: 0.5-1.0 mmol/L)
Serum albumin: 4.0 g/dL

Assuming a reference anion gap of 12 mEq/L and a normal serum bicarbonate of 24 mEq/L, what is this patient's calculated delta ratio (also known as the Δ/Δ\Delta/\Delta ratio)?

Show answer & explanation

Answer: 0.5

Answer

0.5
The correct answer is 0.5. This patient presents with hypovolemic shock (hypotension, tachycardia, poor perfusion) secondary to severe watery diarrhea, leading to an elevated lactate level. Therefore, she has a mixed acid-base disorder: a high anion gap metabolic acidosis (HAGMA) from lactic acidosis, and a normal anion gap metabolic acidosis (NAGMA) from gastrointestinal bicarbonate losses. The delta ratio is used to uncover this mixed disorder. It is calculated by dividing the excess anion gap (ΔAG=20−12=8\Delta AG = 20 - 12 = 8) by the bicarbonate deficit (ΔHCO3−=24−8=16\Delta HCO_3^- = 24 - 8 = 16). The resulting ratio of 0.5 falls between 0.4 and 0.8, which is the classic diagnostic range for a mixed HAGMA and NAGMA.

Step-by-Step Solution

1
Calculate the serum anion gap.
2020 mEq/L
Determines the presence and magnitude of unmeasured anions contributing to the acidosis.
2
Calculate the ΔAG\Delta AG.
88 mEq/L
Quantifies the excess gap above the normal baseline (20−1220 - 12).
3
Calculate the ΔHCO3−\Delta HCO_3^-.
1616 mEq/L
Quantifies the total deficit of bicarbonate below the normal baseline (24−824 - 8).
4
Divide ΔAG\Delta AG by ΔHCO3−\Delta HCO_3^-.
0.50.5
Provides the delta ratio, which identifies complex mixed acid-base disorders.

Key Concept

In patients with a high anion gap metabolic acidosis (HAGMA), the delta ratio (ΔAG/ΔHCO3−\Delta AG / \Delta HCO_3^-) is calculated to identify concurrent concealed acid-base disorders. A ratio < 0.8 indicates a concurrent normal anion gap metabolic acidosis (NAGMA), which in this patient is due to severe diarrhea.
Question 215Question →

A 35-year-old woman presents to the clinic for evaluation of generalized muscle weakness and fatigue over the past several weeks. She also reports a recent history of passing two kidney stones. Her past medical history is significant for Sjögren syndrome, for which she uses artificial tears and saliva substitutes. Vital signs are within normal limits. Laboratory evaluation reveals the following:

TestValue
Sodium139 mEq/L
Potassium2.7 mEq/L
Chloride115 mEq/L
Bicarbonate14 mEq/L
Blood urea nitrogen14 mg/dL
Creatinine0.9 mg/dL

Urinalysis:
- pH: 6.5
- Specific gravity: 1.015
- Protein: Negative
- Blood: Negative
- Glucose: Negative

Which of the following is the most likely underlying mechanism for this patient's laboratory findings?

Show answer & explanation

Answer: Impaired hydrogen ion secretion in the distal tubule

Answer

Impaired hydrogen ion secretion in the distal tubule
The correct mechanism is impaired hydrogen ion secretion in the distal tubule, which is the pathophysiology of Type 1 (distal) renal tubular acidosis (RTA). The patient has a metabolic acidosis with a normal anion gap (139 - 115 - 14 = 10). In the presence of a hypokalemic normal anion gap metabolic acidosis, the urine pH must be assessed. The alpha-intercalated cells in the distal tubule normally secrete H+H^+ to acidify the urine. In Type 1 RTA, this mechanism fails, resulting in an inability to acidify the urine below a pH of 5.5 (patient's urine pH is 6.5). The alkaline urine promotes calcium phosphate precipitation, leading to recurrent kidney stones. Type 1 RTA is highly associated with autoimmune disorders, particularly Sjögren syndrome and rheumatoid arthritis.

Step-by-Step Solution

1
Calculate the serum anion gap.
AG=Na+−(Cl−+HCO3−)=139−(115+14)=10AG = Na^+ - (Cl^- + HCO_3^-) = 139 - (115 + 14) = 10 mEq/L.
Determining the anion gap is the essential first step in evaluating any metabolic acidosis to differentiate between HAGMA (>12 mEq/L) and NAGMA (8-12 mEq/L).
2
Evaluate the serum potassium in the context of a Normal Anion Gap Metabolic Acidosis (NAGMA).
The patient has severe hypokalemia (K+=2.7K^+ = 2.7 mEq/L).
Serum potassium levels help narrow the differential diagnosis of a NAGMA. Type 4 RTA is associated with hyperkalemia, whereas Type 1 RTA, Type 2 RTA, and gastrointestinal losses typically present with hypokalemia.
3
Assess the urine pH to differentiate the causes of hypokalemic NAGMA.
The urine pH is 6.56.5, which is inappropriately alkaline in the face of severe systemic academia.
In Type 2 RTA and severe diarrhea, the distal nephron is intact and maximally excretes H+H^+, lowering urine pH to <5.5< 5.5. A urine pH >5.5> 5.5 in a hypokalemic NAGMA is diagnostic of Type 1 (distal) RTA.

Key Concept

Type 1 (distal) renal tubular acidosis presents as a normal anion gap metabolic acidosis, hypokalemia, and an inappropriately alkaline urine pH (> 5.5), often complicated by calcium phosphate nephrolithiasis. It is strongly associated with autoimmune diseases like Sjögren syndrome.
Estimated Time:1m 30s
Question 216Question →

Match each clinical presentation of acute renal dysfunction with the most characteristic finding expected on microscopic urinalysis.

Click a left item, then click its matching right item

Items

Oliguric acute kidney injury following prolonged intraoperative hypotension during an abdominal aortic aneurysm repair.
Severe high anion gap metabolic acidosis and acute kidney injury following ingestion of a sweet-tasting, unknown liquid.
Rapidly worsening renal function, palpable purpura, and low serum complement levels in a patient with chronic hepatitis C.
Rising serum creatinine, low-grade fever, and a diffuse maculopapular rash developing two weeks after initiating intravenous nafcillin.

Matches

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Answer

Ischemic hypotension causes muddy brown granular casts; ethylene glycol toxicity produces calcium oxalate crystals; cryoglobulinemic glomerulonephritis leads to red blood cell casts; and nafcillin-induced interstitial nephritis generates white blood cell casts.
Urinary sediment serves as a 'liquid biopsy' that non-invasively distinguishes the anatomical compartment of renal injury. Ischemic damage exclusively targets tubular cells (ATN), yielding granular casts. Toxic ingestions like ethylene glycol have specific metabolites (oxalate) that crystallize. Glomerular inflammation (glomerulonephritis) uniquely allows red blood cells to cross the damaged basement membrane, forming RBC casts. Finally, allergic tubulointerstitial reactions (AIN) recruit inflammatory cells, forming WBC casts.

Step-by-Step Solution

1
Analyze the hypotensive surgical patient.
Identified ischemic acute tubular necrosis (ATN), which corresponds to muddy brown granular casts.
Hypoperfusion deprives the metabolically active renal medulla of oxygen, leading to tubular cell necrosis and sloughing.
2
Analyze the toxic ingestion with severe metabolic acidosis.
Identified ethylene glycol poisoning, which corresponds to envelope-shaped calcium oxalate crystals.
The toxic alcohol is metabolized by alcohol dehydrogenase into toxic metabolites, including oxalate, which crystallizes in the renal tubules.
3
Analyze the hepatitis C patient with purpura and low complement.
Identified mixed cryoglobulinemia causing glomerulonephritis, which corresponds to red blood cell casts.
Immune complex deposition in the glomeruli causes severe inflammation, allowing RBCs to leak and become trapped in Tamm-Horsfall protein within the tubules.
4
Analyze the patient with a rash and fever after starting nafcillin.
Identified drug-induced acute interstitial nephritis (AIN), which corresponds to white blood cell casts.
Beta-lactam antibiotics can act as haptens, triggering a delayed hypersensitivity reaction in the renal interstitium that recruits leukocytes.

Key Concept

Correlation of acute kidney injury etiologies with specific urinary sediment findings.
Question 217Question →

A 52-year-old man with a history of obesity hypoventilation syndrome and type 2 diabetes mellitus is brought to the emergency department by his wife due to profound weakness and confusion. For the past 4 days, he has had severe, watery diarrhea with up to 10 bowel movements daily, accompanied by abdominal cramping. He has not been able to tolerate oral intake. His temperature is 37.1∘C37.1^\circ\text{C} (98.8∘F98.8^\circ\text{F}), blood pressure is 90/60 mm Hg90/60\text{ mm Hg}, pulse is 112/min112\text{/min}, and respirations are 14/min14\text{/min}. Physical examination shows dry mucous membranes and decreased skin turgor. The patient appears somnolent but is arousable.

Laboratory studies show:
Serum sodium: 135 mEq/L135\text{ mEq/L}
Serum potassium: 3.2 mEq/L3.2\text{ mEq/L}
Serum chloride: 113 mEq/L113\text{ mEq/L}
Serum bicarbonate: 12 mEq/L12\text{ mEq/L}
Blood urea nitrogen: 42 mg/dL42\text{ mg/dL}
Serum creatinine: 1.6 mg/dL1.6\text{ mg/dL}
Serum albumin: 4.0 g/dL4.0\text{ g/dL}

Arterial blood gas analysis on room air:
pH: 7.087.08
PaCO2\text{PaCO}_2: 42 mm Hg42\text{ mm Hg}
PaO2\text{PaO}_2: 65 mm Hg65\text{ mm Hg}

Which of the following best describes this patient's acid-base status?

Show answer & explanation

Answer: Mixed normal anion gap metabolic acidosis and respiratory acidosis

Answer

Mixed normal anion gap metabolic acidosis and respiratory acidosis
This patient has a mixed normal anion gap metabolic acidosis and respiratory acidosis. The primary metabolic acidosis is diagnosed by the low pH (7.087.08) and low bicarbonate (12 mEq/L12\text{ mEq/L}), caused by profound bicarbonate loss from severe diarrhea. The anion gap is calculated as Sodium−(Chloride+Bicarbonate)\text{Sodium} - (\text{Chloride} + \text{Bicarbonate}), which is 135−(113+12)=10 mEq/L135 - (113 + 12) = 10\text{ mEq/L}. Since this is within the normal range of 8−12 mEq/L8-12\text{ mEq/L}, the primary disorder is a normal anion gap (hyperchloremic) metabolic acidosis. Next, Winter's formula must be applied to determine if respiratory compensation is adequate: Expected PaCO2=(1.5×HCO3−)+8±2\text{PaCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2. For this patient, the expected PaCO2\text{PaCO}_2 is (1.5×12)+8=26±2 mm Hg(1.5 \times 12) + 8 = 26 \pm 2\text{ mm Hg} (range 24−28 mm Hg24-28\text{ mm Hg}). The patient's actual PaCO2\text{PaCO}_2 is 42 mm Hg42\text{ mm Hg}. Because the actual PaCO2\text{PaCO}_2 is significantly higher than the expected range, he has a superimposed primary respiratory acidosis. This indicates a failure to mount the necessary hyperventilatory response, perfectly aligning with his history of obesity hypoventilation syndrome and current somnolent state.

Step-by-Step Solution

1
Identify the primary acid-base disturbance using pH and serum bicarbonate.
The pH is 7.087.08 (severe acidemia) and the serum bicarbonate is 12 mEq/L12\text{ mEq/L} (low), indicating a primary metabolic acidosis.
Determining the primary disorder is the critical first step in any acid-base evaluation.
2
Calculate the serum anion gap.
Anion Gap = Na+−(Cl−+HCO3−)\text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-) = 135−(113+12)=10 mEq/L135 - (113 + 12) = 10\text{ mEq/L}. This is within the normal range (8−12 mEq/L8-12\text{ mEq/L}).
Differentiating between normal and high anion gap metabolic acidosis narrows the differential diagnosis. This patient's profound diarrhea caused a normal anion gap metabolic acidosis due to gastrointestinal bicarbonate loss.
3
Calculate the expected respiratory compensation using Winter's formula.
Expected PaCO2=(1.5×HCO3−)+8±2=(1.5×12)+8±2=26±2 mm Hg\text{PaCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2 = (1.5 \times 12) + 8 \pm 2 = 26 \pm 2\text{ mm Hg}. The actual PaCO2\text{PaCO}_2 is 42 mm Hg42\text{ mm Hg}, which is significantly higher than the expected range.
If the actual PaCO2 is higher than the expected PaCO2, there is a concurrent primary respiratory acidosis. This patient's obesity hypoventilation syndrome and somnolence prevent him from adequately hyperventilating to compensate for the acidemia.

Key Concept

Evaluating complex acid-base disorders requires a stepwise approach: identify the primary disturbance, calculate the anion gap, and apply Winter's formula to determine if respiratory compensation is appropriate.
Question 218Question →

An 82-year-old man is brought to the emergency department due to sudden-onset, severe abdominal pain. He has a history of hypertension, type 2 diabetes mellitus, and atrial fibrillation for which he takes apixaban; however, he admits to missing several doses over the past week. During transport, paramedics administered intravenous morphine for pain control. On arrival, he appears drowsy but is arousable. Temperature is 37.1∘C37.1^\circ\text{C} (98.8∘F98.8^\circ\text{F}), blood pressure is 102/60 mmHg102/60\text{ mmHg}, pulse is 118/min118/\text{min} and irregular, and respiratory rate is 14/min14/\text{min}. The abdomen is slightly distended with absent bowel sounds, and there is minimal tenderness to palpation.

Laboratory results are as follows:

ParameterValue
Sodium140 mEq/L140\text{ mEq/L}
Potassium4.5 mEq/L4.5\text{ mEq/L}
Chloride104 mEq/L104\text{ mEq/L}
Bicarbonate12 mEq/L12\text{ mEq/L}
Blood urea nitrogen30 mg/dL30\text{ mg/dL}
Creatinine1.4 mg/dL1.4\text{ mg/dL}
Arterial blood gas (on room air):
ParameterValue
pH7.167.16
PaCO2\text{PaCO}_234 mmHg34\text{ mmHg}
PaO2\text{PaO}_272 mmHg72\text{ mmHg}

Which of the following best characterizes this patient's acid-base status?

Show answer & explanation

Answer: High anion gap metabolic acidosis and concurrent respiratory acidosis

Answer

High anion gap metabolic acidosis and concurrent respiratory acidosis
This patient's clinical presentation (atrial fibrillation off anticoagulation with abdominal pain out of proportion to exam) is classic for acute mesenteric ischemia, leading to lactic acidosis. The pH is 7.167.16 (acidemia) and bicarbonate is 12 mEq/L12\text{ mEq/L}, defining a primary metabolic acidosis. The anion gap is elevated at 2424 (140−[104+12]140 - [104 + 12]), categorizing it as a high anion gap metabolic acidosis (HAGMA). To assess respiratory compensation, Winter's formula is utilized: Expected PaCO2=(1.5×HCO3−)+8±2\text{Expected PaCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2. For this patient, the expected PaCO2=(1.5×12)+8=26±2 mmHg\text{PaCO}_2 = (1.5 \times 12) + 8 = 26 \pm 2\text{ mmHg}. Because the patient's actual PaCO2\text{PaCO}_2 is 34 mmHg34\text{ mmHg} (which is >28 mmHg>28\text{ mmHg}), he has an inadequate respiratory response. This relative hypoventilation, likely secondary to the recent administration of intravenous morphine, indicates a concurrent primary respiratory acidosis.

Step-by-Step Solution

1
Determine the primary acid-base disturbance.
The patient has an acidemia (pH 7.167.16). The HCO3−\text{HCO}_3^- is low (12 mEq/L12\text{ mEq/L}), confirming a primary metabolic acidosis.
pH < 7.40 indicates acidemia, and a matched decrease in bicarbonate establishes the primary metabolic nature of the disturbance.
2
Calculate the serum anion gap.
Anion Gap=Na+−(Cl−+HCO3−)=140−(104+12)=140−116=24\text{Anion Gap} = \text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-) = 140 - (104 + 12) = 140 - 116 = 24.
Differentiating between normal (8-12) and high anion gap metabolic acidosis is the required next step in evaluating any metabolic acidosis.
3
Calculate expected respiratory compensation using Winter's formula.
Expected PaCO2=1.5×[HCO3−]+8±2=1.5×12+8±2=18+8±2=26±2 mmHg\text{Expected PaCO}_2 = 1.5 \times [\text{HCO}_3^-] + 8 \pm 2 = 1.5 \times 12 + 8 \pm 2 = 18 + 8 \pm 2 = 26 \pm 2\text{ mmHg} (Range: 24-28 mmHg).
In primary metabolic acidosis, the lungs compensate by hyperventilating to blow off CO2\text{CO}_2. Winter's formula predicts the appropriate PaCO2\text{PaCO}_2 response.
4
Compare actual PaCO2\text{PaCO}_2 to expected PaCO2\text{PaCO}_2.
The actual PaCO2\text{PaCO}_2 (34 mmHg34\text{ mmHg}) is greater than the expected range (24−28 mmHg24-28\text{ mmHg}).
An actual PaCO2\text{PaCO}_2 higher than the expected compensated range indicates an inadequate respiratory drive, confirming a concurrent primary respiratory acidosis.

Key Concept

Calculation of Anion Gap and Winter's Formula to diagnose mixed acid-base disorders.
Question 219Question →

Match each clinical scenario describing a patient with newly detected hyponatremia to the most accurate expected pattern of laboratory findings, focusing on serum and urine osmolar characteristics.

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Items

A 68-year-old male with ischemic cardiomyopathy and orthopnea. Vitals show BP 105/65 mmHg. Exam demonstrates JVD to 12 cm H₂O and 3+ pitting lower extremity edema. Serum sodium is 128 mEq/L.
A 54-year-old female with a 40-pack-year smoking history presenting with chronic cough. BP is 125/80 mmHg, and she appears euvolemic. Imaging shows a central pulmonary mass. Serum sodium is 121 mEq/L.
A 26-year-old male with schizoaffective disorder who compulsively drinks from the ward's water fountain. Vitals are normal. Skin turgor is intact. Serum sodium is 118 mEq/L.
A 41-year-old female in the ED with Kussmaul respirations and fruity breath. BP is 90/60 mmHg, HR is 115 bpm. Capillary blood glucose is 820 mg/dL and serum sodium is 126 mEq/L.
A 35-year-old asymptomatic male evaluated for routine labs. Blood pressure is 118/72 mmHg. His blood draw appears milky with a triglyceride level of 4,200 mg/dL and serum sodium of 129 mEq/L.

Matches

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Answer

The heart failure patient represents hypervolemic hypotonic hyponatremia with sodium avidity. The lung mass patient exhibits SIADH with sodium wasting. The psychiatric patient has primary polydipsia with a maximally dilute urine. The DKA patient presents with hypertonic translocational hyponatremia. The patient with severe hypertriglyceridemia demonstrates isotonic pseudohyponatremia.
The algorithmic approach to hyponatremia mandates beginning with measured serum osmolality. Severe hypertriglyceridemia increases the non-aqueous phase of blood, causing an artifactual drop in sodium (isotonic pseudohyponatremia). Hyperglycemia acts as a potent osmole, pulling water into the extracellular space, causing a dilutional, hypertonic hyponatremia. True hypotonic hyponatremia requires interrogating ADH activity via urine osmolality. Primary polydipsia suppresses ADH, yielding a maximally dilute urine (<100 mOsm/kg H₂O). If ADH is active (urine osmolality >100 mOsm/kg H₂O), the urine sodium determines the drive: decreased effective arterial volume (e.g., heart failure) causes intense sodium avidity (urine Na <20 mEq/L), whereas SIADH (e.g., from small cell lung cancer) is characterized by relative volume expansion and obligate sodium wasting (urine Na >40 mEq/L).

Step-by-Step Solution

1
Evaluate the measured serum osmolality.
Categorizes the hyponatremia as isotonic (pseudohyponatremia from lipids/proteins), hypertonic (glucose, mannitol), or true hypotonic hyponatremia.
True hyponatremia must represent a state of hypotonicity. DKA creates hypertonicity, while hypertriglyceridemia creates isotonicity.
2
For patients with true hypotonicity, evaluate the urine osmolality.
Determines whether Antidiuretic Hormone (ADH) is appropriately suppressed.
If urine osmolality is <100 mOsm/kg H₂O, ADH is suppressed, pointing to primary polydipsia or advanced renal failure. If it is >100 mOsm/kg H₂O, ADH is active.
3
For patients with active ADH (urine osmolality >100 mOsm/kg H₂O), assess clinical volume status and urine sodium.
Differentiates appropriate ADH response from inappropriate ADH response.
A low effective arterial volume (heart failure, cirrhosis) triggers RAAS, reducing urine sodium to <20 mEq/L. Euvolemic states like SIADH suppress RAAS, causing urine sodium to exceed 40 mEq/L.

Key Concept

The diagnostic algorithm for hyponatremia relies on sequentially evaluating measured serum osmolality, urine osmolality, and urine sodium to determine the underlying pathophysiology.
Question 220Question →

Match each patient's clinical presentation and initial diagnostic findings with the most accurate underlying pathophysiologic mechanism or defining etiology.

Click a left item, then click its matching right item

Items

A 35-year-old man with hemoptysis, rapidly worsening renal function, and linear IgG deposits along the glomerular basement membrane on immunofluorescence.
A 22-year-old man with sensorineural hearing loss, microscopic hematuria, and a 'basket-weave' appearance of the glomerular basement membrane on electron microscopy.
A 45-year-old woman with chronic hepatitis C presenting with palpable purpura, arthralgias, and laboratory findings showing profoundly low C4 but normal C3 complement levels.
A 12-year-old boy with periorbital edema, gross hematuria, and subepithelial electron-dense 'humps' on renal biopsy two weeks after recovering from impetigo.
A 28-year-old patient of African descent with untreated HIV presenting with massive edema, heavy proteinuria, and glomerular tuft collapse on biopsy.

Matches

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Answer

The correct matches map Goodpasture syndrome to autoantibodies against the alpha-3 chain of type IV collagen; Alport syndrome to genetic mutations in type IV collagen assembly; Mixed cryoglobulinemia to cold-precipitable immune complexes with classical complement activation; Poststreptococcal glomerulonephritis to alternate complement pathway activation; and Collapsing FSGS to viral-associated podocyte injury linked to APOL1.
Each clinical vignette contains pathognomonic markers for a specific glomerular disease. Identifying the precise pattern of complement consumption, genetic history, or specific immunofluorescence findings allows for accurate matching to the underlying pathophysiology.

Step-by-Step Solution

1
Analyze the immunofluorescence, complement levels, and demographic clues in each vignette.
Identified five distinct glomerular syndromes: Anti-GBM disease, Alport syndrome, Cryoglobulinemia, PSGN, and Collapsing FSGS.
Accurate diagnosis of nephritic and nephrotic syndromes requires integrating clinical history with specific biopsy and serologic findings.
2
Differentiate between the two diseases involving type IV collagen.
Linked the patient with hemoptysis to autoimmune destruction (Goodpasture) and the patient with hearing loss to genetic structural defects (Alport).
Both conditions involve type IV collagen, but their mechanisms (autoimmune vs. congenital mutation) dictate vastly different clinical presentations.
3
Differentiate between the causes of hypocomplementemia.
Linked the Hepatitis C patient with low C4 to classical pathway activation (Cryoglobulinemia) and the post-impetigo patient to alternate pathway activation (PSGN).
Complement profiling (C3 vs. C4 levels) is a critical step in narrowing down the differential diagnosis for immune complex glomerulonephritis.

Key Concept

Pathophysiological mechanisms and histopathological correlates of primary and secondary glomerular diseases.
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