Tüm alıştırma soruları

5556 soru

Soru 1701Soru

A student earned scores of 8585, 9090, 8888, and 9292 on the first four quizzes of the semester. What score must the student earn on the fifth quiz to have an average (arithmetic mean) score of exactly 9090 for all five quizzes?

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Cevap: 95

Cevap

The student must earn a score of 95 on the fifth quiz.
To find the score needed on the fifth quiz to achieve an average of 9090, first find the total number of points required. An average of 9090 on 55 quizzes requires a total sum of 5×90=4505 \times 90 = 450 points. The sum of the first four quiz scores is 85+90+88+92=35585 + 90 + 88 + 92 = 355 points. Subtracting the current sum from the required total sum (450355450 - 355) yields 9595, which is the score the student must earn on the fifth quiz.

Adım Adım Çözüm

1
Calculate the sum of the student's scores on the first four quizzes.
85+90+88+92=35585 + 90 + 88 + 92 = 355
To find the total number of points the student has earned so far.
2
Calculate the total sum of points required to achieve an average of 9090 over five quizzes.
5×90=4505 \times 90 = 450
The arithmetic mean formula is Mean = Sum / Count, which can be rearranged to Sum = Mean * Count.
3
Subtract the sum of the first four quiz scores from the required total sum of five quiz scores.
450355=95450 - 355 = 95
The difference represents the score needed on the fifth quiz to achieve the target average.

Anahtar Kavram

Finding a missing value given a target arithmetic mean
Soru 1702Soru

An investment fund allocates its capital into three portfolios: Real Estate, Technology, and Green Energy. Initially, 14\frac{1}{4} of the total capital is allocated to Real Estate, and 25\frac{2}{5} of the total capital is allocated to Technology. The remaining capital is allocated to Green Energy. During the first year, the Real Estate portfolio decreases in value by 16%16\%, the Technology portfolio increases in value by 15%15\%, and the Green Energy portfolio increases in value by p%p\%. If the total value of the entire investment fund at the end of the first year has increased by 9%9\% of its initial value, what is the value of pp?

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Cevap: 20.020.0

Cevap

The value of pp is 20.020.0.
The correct answer is 20.020.0. By assuming a total capital of 100100 units, we find that the Real Estate portfolio starts at 2525 units, the Technology portfolio at 4040 units, and the Green Energy portfolio at 3535 units. The change in Real Estate is 4-4 units, and the change in Technology is +6+6 units. To reach a total fund increase of 99 units, the change in the Green Energy portfolio must satisfy 4+6+Change in Green Energy=9-4 + 6 + \text{Change in Green Energy} = 9, which means the Green Energy portfolio must increase by 77 units. Finding what percent 77 is of 3535 yields 735=0.20\frac{7}{35} = 0.20, or 20%20\%.

Adım Adım Çözüm

1
Determine the initial allocation of capital for each portfolio by assuming a total initial capital of 100100 units.
Real Estate receives 14×100=25\frac{1}{4} \times 100 = 25 units. Technology receives 25×100=40\frac{2}{5} \times 100 = 40 units. The remaining capital allocated to Green Energy is 100(25+40)=35100 - (25 + 40) = 35 units.
This establishes the weighted share of each portfolio relative to the total capital.
2
Calculate the changes in value for the Real Estate and Technology portfolios based on their given percentage changes.
Real Estate change: 16% of 25=0.16×25=4-16\% \text{ of } 25 = -0.16 \times 25 = -4 units. Technology change: +15% of 40=0.15×40=+6+15\% \text{ of } 40 = 0.15 \times 40 = +6 units.
This determines the absolute change in value contributed by these two portfolios.
3
Calculate the total change in value for the entire fund.
Total fund change: +9% of 100=+9+9\% \text{ of } 100 = +9 units.
The total change in the fund is the sum of the individual changes in the portfolios.
4
Set up an equation representing the sum of the changes in all three portfolios and solve for pp.
4+6+(p100×35)=9    2+0.35p=9    0.35p=7    p=20-4 + 6 + \left(\frac{p}{100} \times 35\right) = 9 \implies 2 + 0.35p = 9 \implies 0.35p = 7 \implies p = 20.
This solves for the unknown percentage rate of increase required for the Green Energy portfolio.

Anahtar Kavram

Weighted average of percentage changes using fractional and decimal representations.

Alternatif Yöntem

Instead of choosing an arbitrary starting capital of 100100, you can use decimals directly. Let CC be the total capital. The weighted changes are 0.25C(0.16)+0.40C(0.15)+0.35C(p100)=0.09C0.25C(-0.16) + 0.40C(0.15) + 0.35C\left(\frac{p}{100}\right) = 0.09C. Dividing both sides by CC yields 0.04+0.06+0.0035p=0.09-0.04 + 0.06 + 0.0035p = 0.09. Simplifying gives 0.02+0.0035p=0.09    0.0035p=0.07    p=200.02 + 0.0035p = 0.09 \implies 0.0035p = 0.07 \implies p = 20.
Tahmini Süre:3m 0s
Soru 1703Soru

At a marketing firm, the ratio of designers to writers is 3:43:4, and the ratio of writers to managers is 5:25:2. The firm hires 1010 new designers and 44 new managers, while the number of writers remains the same. If the new ratio of designers to managers is 2:12:1, how many writers are employed at the firm?

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Cevap: 40

Cevap

There are 40 writers employed at the firm.
To find the number of writers, we combine the ratios of designers to writers (3:43:4) and writers to managers (5:25:2) by finding a common multiple for the number of writers (20). This gives a combined ratio of 15:20:815:20:8 for designers, writers, and managers. Representing these quantities as 15x15x, 20x20x, and 8x8x, we can write the equation for the new ratio of designers to managers: 15x+108x+4=2\frac{15x + 10}{8x + 4} = 2. Solving this equation gives 15x+10=16x+815x + 10 = 16x + 8, which simplifies to x=2x = 2. The number of writers is 20(2)=4020(2) = 40.

Adım Adım Çözüm

1
Align the two given ratios to find a common ratio.
The ratio of designers to writers is 3:4=15:203:4 = 15:20. The ratio of writers to managers is 5:2=20:85:2 = 20:8. The combined ratio of designers to writers to managers is 15:20:815:20:8.
To analyze the changes across the different categories, we need a single ratio that shares the common term (writers).
2
Express the quantities of employees in terms of a variable xx.
Let the number of designers be 15x15x, writers be 20x20x, and managers be 8x8x.
This allows us to represent the actual number of employees algebraically.
3
Set up an equation based on the new ratio of designers to managers after the new hires.
15x+108x+4=21\frac{15x + 10}{8x + 4} = \frac{2}{1}
The firm hired 10 designers and 4 managers, and the ratio of these new quantities is 2:12:1.
4
Solve the equation for xx.
15x+10=2(8x+4)    15x+10=16x+8    x=215x + 10 = 2(8x + 4) \implies 15x + 10 = 16x + 8 \implies x = 2.
Solving for xx gives us the multiplier to find the actual employee counts.
5
Calculate the total number of writers.
W=20(2)=40W = 20(2) = 40.
The number of writers is represented by 20x20x.

Anahtar Kavram

Combining multiple ratios and setting up algebraic equations from changing rates/proportions.

Alternatif Yöntem

Express the number of designers and managers in terms of the number of writers, WW. The number of designers is 34W\frac{3}{4}W, and the number of managers is 25W\frac{2}{5}W. After hiring, the equation is 34W+1025W+4=2\frac{\frac{3}{4}W + 10}{\frac{2}{5}W + 4} = 2. Solving for WW yields 34W+10=45W+8    2=120W    W=40\frac{3}{4}W + 10 = \frac{4}{5}W + 8 \implies 2 = \frac{1}{20}W \implies W = 40.
Tahmini Süre:2m 0s
Soru 1704Soru

Four distinct quantities are defined by different exponential, radical, or scientific notation expressions. What is the correct order of these quantities from the smallest value to the largest value?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct order of the expressions from least to greatest is 5205^{20}, followed by 3303^{30}, then 8.0×10148.0 \times 10^{14}, and finally 2100\sqrt{2^{100}}.
Simplifying 2100\sqrt{2^{100}} yields 2502^{50}. Expressing 5205^{20} as 251025^{10} and 3303^{30} as 271027^{10} shows that 520<3305^{20} < 3^{30}. By estimating upper and lower bounds relative to powers of 1010, we find that 330<30105.9×10143^{30} < 30^{10} \approx 5.9 \times 10^{14}, which is less than 8.0×10148.0 \times 10^{14}. Meanwhile, 250=10245>(103)5=10152^{50} = 1024^5 > (10^3)^5 = 10^{15}, which is greater than 8.0×10148.0 \times 10^{14}. This establishes the sequence 520<330<8.0×1014<21005^{20} < 3^{30} < 8.0 \times 10^{14} < \sqrt{2^{100}}.

Adım Adım Çözüm

1
Simplify the radical expression 2100\sqrt{2^{100}} using fractional exponent rules.
2100=(2100)1/2=250\sqrt{2^{100}} = (2^{100})^{1/2} = 2^{50}
Converting the square root to a power of 1/21/2 simplifies the expression into a single base and exponent.
2
Compare the exponential expressions 5205^{20} and 3303^{30} by expressing them with a common power of 1010.
520=(52)10=25105^{20} = (5^2)^{10} = 25^{10} and 330=(33)10=27103^{30} = (3^3)^{10} = 27^{10}. Since 25<2725 < 27, then 2510<271025^{10} < 27^{10}, so 520<3305^{20} < 3^{30}.
Rewriting the powers to share an exponent of 1010 allows direct comparison of the base values.
3
Establish an upper limit for 3303^{30} to compare it with the scientific notation quantity 8.0×10148.0 \times 10^{14}.
330=2710<3010=310×10103^{30} = 27^{10} < 30^{10} = 3^{10} \times 10^{10}. Since 35=2433^5 = 243, we have 310=2432=59,0493^{10} = 243^2 = 59,049. Therefore, 310×1010=5.9049×10143^{10} \times 10^{10} = 5.9049 \times 10^{14}. Since 5.9049×1014<8.0×10145.9049 \times 10^{14} < 8.0 \times 10^{14}, we have 330<8.0×10143^{30} < 8.0 \times 10^{14}.
Using a slightly larger round number base of 3030 allows an upper bound calculation that demonstrates 3303^{30} is strictly less than 8.0×10148.0 \times 10^{14}.
4
Establish a lower limit for the simplified radical expression 2502^{50} to compare it with 8.0×10148.0 \times 10^{14}.
250=(210)5=102452^{50} = (2^{10})^5 = 1024^5. Since 1024>1000=1031024 > 1000 = 10^3, then 10245>(103)5=10151024^5 > (10^3)^5 = 10^{15}. Because 1015=10×1014>8.0×101410^{15} = 10 \times 10^{14} > 8.0 \times 10^{14}, it follows that 250>8.0×10142^{50} > 8.0 \times 10^{14}.
Using the approximation 2101032^{10} \approx 10^3 shows that 2502^{50} is greater than 101510^{15}, which exceeds the scientific notation value.
5
Combine the individual inequalities to construct the complete chain of comparisons.
520<330<8.0×1014<21005^{20} < 3^{30} < 8.0 \times 10^{14} < \sqrt{2^{100}}
Linking the inequalities using transitive properties determines the correct least-to-greatest order.

Anahtar Kavram

Comparing complex numerical expressions containing powers, radicals, and scientific notation by finding common exponents and using base-10 estimation.

Alternatif Yöntem

Alternatively, convert all expressions into scientific notation approximations. Note that 520=2510=(2.5×10)10=2.510×10105^{20} = 25^{10} = (2.5 \times 10)^{10} = 2.5^{10} \times 10^{10}. Since 2.51095362.5^{10} \approx 9536, we get 5209.5×10135^{20} \approx 9.5 \times 10^{13}. Applying a similar approximation to 330=2710=2.710×10102.06×10143^{30} = 27^{10} = 2.7^{10} \times 10^{10} \approx 2.06 \times 10^{14}. Since 250=1.0245×10151.13×10152^{50} = 1.024^5 \times 10^{15} \approx 1.13 \times 10^{15}, we can compare the coefficients and exponents: 9.5×1013<2.06×1014<8.0×1014<1.13×10159.5 \times 10^{13} < 2.06 \times 10^{14} < 8.0 \times 10^{14} < 1.13 \times 10^{15}.
Tahmini Süre:3m 0s
Soru 1705Soru

Acoustics experts studying the ancient theater of Epidaurus have long marveled at its extraordinary sound design. Even from the back row of the massive stone structure, spectators can clearly hear a whisper from the stage. While early theories attributed this phenomenon to local wind patterns, recent research indicates that the limestone seats play a critical role, filtering out low-frequency background noise while cranking up the high-frequency voices of the performers.

Which choice best maintains the established tone of the passage?

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Cevap: amplifying the high-frequency voices of the performers

Cevap

amplifying the high-frequency voices of the performers
The choice that states 'amplifying the high-frequency voices of the performers' is correct because it uses the clear, objective, and academic verb 'amplifying' and the correct preposition 'of'. This language fits perfectly with the scientific, professional tone established by the surrounding sentences.

Adım Adım Çözüm

1
Analyze the surrounding text to determine the established tone of the passage.
The passage uses formal, scientific, and academic vocabulary (such as 'acoustics experts,' 'marveled,' 'phenomenon,' and 'filtering out'), establishing a professional and objective tone.
Identifying the author's tone is necessary to ensure the underlined portion maintains style and tone consistency.
2
Evaluate the choices to find the one that fits this academic tone and uses correct grammar.
The phrasing 'amplifying the high-frequency voices of the performers' is clear, precise, and grammatically correct, matching the rest of the text.
This choice maintains tone consistency without being overly informal, overly pretentious, or grammatically incorrect.

Anahtar Kavram

Tone Consistency
Soru 1706Soru

Unlike the visible colors of most flowers, which are produced by chemical pigments, the brilliant blue of a peacock's feather is created by structural coloration. The surface of the feather contains tiny, regular channels that reflect specific wavelengths of light. [1] Nevertheless, this microscopic architecture creates an iridescent shimmer that changes depending on the angle from which it is viewed.

Which of the following choices is the most logical transition to use at the underlined portion marked [1]?

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Cevap: As a result,

Cevap

As a result,
The transition 'As a result,' is correct because it establishes the logical cause-and-effect relationship between the microscopic channels on the peacock's feather and the resulting iridescent shimmer.

Adım Adım Çözüm

1
Analyze the relationship between the two sentences separated by the transition.
The first sentence describes the physical structure of the feather (tiny, regular channels that reflect light), and the second sentence describes the visual outcome of this structure (an iridescent shimmer).
Understanding the logical connection between the two ideas is necessary to select the correct transitional phrase.
2
Evaluate the relationship type.
The relationship is cause-and-effect, as the physical channels directly cause the shimmer.
Identifying the relationship type allows you to eliminate transitions that denote contrast, comparison, or illustration.
3
Select the transition that expresses this cause-and-effect relationship.
'As a result,' correctly shows that the shimmer is the direct outcome of the microscopic architecture.
Matching the transition to the cause-and-effect relationship completes the logical flow of the passage.

Anahtar Kavram

Sentence-Level Transitions
Tahmini Süre:1m 0s
Soru 1707Soru

A school district requires a chaperone-to-student ratio of 3:53:5 for all field trips. If there are exactly 1515 chaperones registered for an upcoming field trip, what is the maximum number of students who can attend?

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Cevap: 2525

Cevap

The maximum number of students who can attend is 2525.
The correct answer is 2525. To maintain the required ratio of 33 chaperones to 55 students, we set up the proportion 35=15x\frac{3}{5} = \frac{15}{x}, where xx is the number of students. Cross-multiplying gives 3x=753x = 75, and dividing by 33 gives x=25x = 25.

Adım Adım Çözüm

1
Set up the proportion using the given chaperone-to-student ratio.
ChaperonesStudents=35=15x\frac{\text{Chaperones}}{\text{Students}} = \frac{3}{5} = \frac{15}{x}, where xx represents the maximum number of students.
Establishing a direct proportion allows us to find the unknown quantity while maintaining the required ratio.
2
Solve for the unknown variable xx by cross-multiplying.
3×x=5×15    3x=753 \times x = 5 \times 15 \implies 3x = 75
Cross-multiplication is a standard algebraic method to solve proportions.
3
Divide both sides of the equation by 33 to isolate xx.
x=25x = 25
This yields the final value of students who can attend.

Anahtar Kavram

Solving direct proportions from part-to-part ratios
Tahmini Süre:45s
Soru 1708Soru

A metal alloy is composed of copper, zinc, and nickel. In the original alloy, the ratio of the weight of copper to zinc is 3:43:4, and the ratio of the weight of zinc to nickel is 4:54:5. A metallurgist melts this 240240-gram alloy and adds a mixture of pure copper and pure nickel. The weight of the copper added is twice the weight of the nickel added. In the resulting alloy, the weight of copper is equal to the weight of nickel. What is the ratio of the weight of zinc to the total weight of the new alloy?

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Cevap: 29\frac{2}{9}

Cevap

The correct ratio of the weight of zinc to the total weight of the new alloy is 29\frac{2}{9}.
The correct answer is 29\frac{2}{9}. To find this, we first establish the joint ratio of the metals as Copper : Zinc : Nickel = 3:4:53 : 4 : 5. For a 240240-gram alloy, this gives 6060 g of copper, 8080 g of zinc, and 100100 g of nickel. Adding xx grams of nickel and 2x2x grams of copper yields a new copper weight of 60+2x60 + 2x and a new nickel weight of 100+x100 + x. Since these weights are equal in the new alloy, 60+2x=100+x    x=4060 + 2x = 100 + x \implies x = 40. The new total weight is 240+3(40)=360240 + 3(40) = 360 grams. The weight of zinc remains 8080 grams, so the ratio of zinc to the total weight is 80/360=2980/360 = \frac{2}{9}.

Adım Adım Çözüm

1
Express the ratio of the three metals in the original alloy.
Copper : Zinc : Nickel = 3:4:53 : 4 : 5
Since Copper : Zinc = 3:43:4 and Zinc : Nickel = 4:54:5, the zinc terms are already aligned, allowing us to combine them into a single three-part ratio.
2
Calculate the initial weights of copper, zinc, and nickel in the 240240-gram alloy.
Copper = 6060 grams, Zinc = 8080 grams, Nickel = 100100 grams
The sum of the ratio parts is 3+4+5=123 + 4 + 5 = 12. Each part represents 240 grams/12=20240 \text{ grams} / 12 = 20 grams. Multiplying each part by 20 gives the initial weights.
3
Define variables for the added metals and set up the equation for the new weights.
New Copper = 60+2x60 + 2x, New Nickel = 100+x100 + x
Let xx represent the weight of nickel added in grams. Since the weight of the copper added is twice that of the nickel added, 2x2x grams of copper are added.
4
Solve for the value of xx using the condition that the final weights of copper and nickel are equal.
x=40x = 40
Setting the expressions equal gives 60+2x=100+x60 + 2x = 100 + x. Subtracting xx and 6060 from both sides yields x=40x = 40 grams.
5
Determine the new total weight of the alloy and calculate the final ratio of zinc to the total weight.
New Total Weight = 360360 grams, Final Ratio = 29\frac{2}{9}
The new total weight is the original weight plus the added metals: 240+3(40)=360240 + 3(40) = 360 grams. Since no zinc was added, the weight of zinc remains 8080 grams. The ratio is 80/360=2980 / 360 = \frac{2}{9}.

Anahtar Kavram

Combining ratios and setting up algebraic equations to model changing quantities in mixtures.
Soru 1709Soru

The pistol shrimp relies on a specialized claw to hunt. When snapped shut, the claw produces a high-pressure bubble of water that collapses with a loud snap, producing a flash of light that is visible to the eye and can be seen.

Which choice most effectively eliminates redundancy in the underlined portion of the sentence?

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Cevap: producing a flash of light

Cevap

producing a flash of light
The correct option is the most concise choice because it removes the redundant phrases 'visible to the eye' and 'can be seen,' which repeat the same idea of visibility. It leaves a grammatically correct and direct description of the flash of light.

Adım Adım Çözüm

1
Identify any redundant or repetitive phrasing in the underlined portion of the sentence.
The phrase 'visible to the eye' and the clause 'can be seen' both describe the ability of the flash to be observed, making them redundant when used together.
ACT English questions require eliminating wordiness and synonym redundancy to make sentences as clear and concise as possible.
2
Evaluate the options to find the one that is most concise while maintaining proper sentence structure.
The option 'producing a flash of light' eliminates the redundant descriptions entirely. The options containing 'it produces' and '. Which is visible' introduce grammatical errors (a comma splice and a sentence fragment, respectively).
The correct answer must be both grammatically correct and free of unnecessary repetition.

Anahtar Kavram

Eliminating Redundancy
Soru 1710Soru

If a=2×103a = 2 \times 10^3 and b=3×104b = 3 \times 10^{-4}, what is the value of the expression a3b21.8\sqrt{\frac{a^3 \cdot b^2}{1.8}}?

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Cevap: 20

Cevap

20
Evaluating the components of the expression sequentially: a3=8×109a^3 = 8 \times 10^9 and b2=9×108b^2 = 9 \times 10^{-8}. Multiplying them yields (8×9)×1098=72×101=720(8 \times 9) \times 10^{9-8} = 72 \times 10^1 = 720. Dividing by the decimal 1.81.8 results in 720/1.8=400720 / 1.8 = 400. The square root of 400400 yields 2020.

Adım Adım Çözüm

1
Calculate the value of a3a^3
8×1098 \times 10^9
Apply the power of a product rule, (xy)n=xnyn(xy)^n = x^n y^n, and the power of a power rule, (10p)q=10pq(10^p)^q = 10^{p \cdot q}.
2
Calculate the value of b2b^2
9×1089 \times 10^{-8}
Apply the power of a product rule and power of a power rule to (3×104)2(3 \times 10^{-4})^2.
3
Multiply a3a^3 and b2b^2
720720
Multiply the coefficients (8×9=728 \times 9 = 72) and add the exponents of the base 10 (109×108=10110^9 \times 10^{-8} = 10^1), resulting in 72×10=72072 \times 10 = 720.
4
Divide the product by 1.81.8
400400
Substitute the values to get 720/1.8720 / 1.8, which simplifies to 7200/18=4007200 / 18 = 400.
5
Take the square root of the quotient
2020
Find the non-negative square root of 400400, which is 2020.

Anahtar Kavram

Simplifying numerical expressions containing combinations of exponent rules, roots, and scientific notation.
Tahmini Süre:1m 30s
Soru 1711Soru

The following sentences are from a paragraph about nurse logs in temperate rainforests. In what order should these sentences be arranged to create the most logical and cohesive paragraph?

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Cevap

The correct sequence of sentences is: first, the sentence introducing the death of a massive tree as a new cycle of life; second, the sentence identifying these trees as nurse logs; third, the sentence explaining that seedlings sprout on the decaying wood; and fourth, the concluding sentence summarizing that debris becomes the foundation of the forest.
The correct sequence begins with the broad introductory statement about a tree's death initiating new life, transitions to naming these trees 'nurse logs' and describing their nutrients, details the seedlings sprouting as a direct result of these nutrients, and concludes with a summary sentence showing how debris becomes the foundation of the future forest.

Adım Adım Çözüm

1
Identify the introductory sentence.
The sentence introducing the death of a massive tree as the beginning of a new cycle of life establishes the paragraph's topic without referencing any outside context.
A logical paragraph must begin with a clear topic sentence that introduces the main subject.
2
Link the second sentence to the introduction using transition clues.
The sentence beginning with 'These fallen giants' directly refers back to the 'death of a massive tree' and names them 'nurse logs'.
Cohesion requires that demonstrative pronouns like 'these' refer back to an established antecedent in the preceding sentence.
3
Connect the supporting detail sentence.
The sentence starting with 'As a result' describes how seedlings sprout on the decaying wood, which explains the specific benefit of the nutrients and moisture mentioned in the previous sentence.
Cause-and-effect transitions must logically connect the cause (nutrients and moisture) with the effect (seedlings sprouting).
4
Place the concluding sentence.
The sentence starting with 'Consequently' summarizes the paragraph's transition from forest debris to the foundation of the future forest.
Concluding sentences often begin with summary transitions like 'consequently' to wrap up the main idea.

Anahtar Kavram

Opening and Concluding Sentences
Tahmini Süre:1m 30s
Soru 1712Soru

A scientist estimates that the population of a certain bacteria culture doubles every 4 hours. If the culture starts with 3.0×1053.0 \times 10^5 bacteria, the population after 24 hours can be written in scientific notation as a×107a \times 10^7. What is the value of aa?

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Cevap: 1.92

Cevap

The value of the coefficient aa is 1.921.92.
The correct answer is 1.921.92. In 24 hours, a population that doubles every 4 hours undergoes 6 doubling cycles. The growth factor is 26=642^6 = 64. Multiplying the initial population of 3.0×1053.0 \times 10^5 by 64 yields 192×105192 \times 10^5. Converting this value into standard scientific notation gives 1.92×1071.92 \times 10^7. Comparing this expression to the format a×107a \times 10^7 shows that the coefficient aa equals 1.921.92.

Adım Adım Çözüm

1
Determine the number of doubling periods.
6 doubling periods
Since the population doubles every 4 hours, over a span of 24 hours it will double 24÷4=624 \div 4 = 6 times.
2
Calculate the growth multiplier.
64
Doubling 6 times is represented by the exponential expression 262^6, which evaluates to 64.
3
Multiply the initial population by the growth factor.
192×105192 \times 10^5
Multiply the coefficient of the initial population by the growth multiplier: 3.0×64=1923.0 \times 64 = 192, yielding a total population of 192×105192 \times 10^5.
4
Convert the resulting value to the required scientific notation format.
1.92×1071.92 \times 10^7
To express 192×105192 \times 10^5 in the standard scientific notation format a×107a \times 10^7, divide 192 by 100 to get 1.92, and multiply the power of 10 by 10210^2 (raising the exponent from 5 to 7).

Anahtar Kavram

Evaluating exponential growth and converting numbers to standard scientific notation format
Tahmini Süre:1m 30s
Soru 1713Soru

Which of the following is the completely factored form of x264x^2 - 64?

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Cevap: (x8)(x+8)(x - 8)(x + 8)

Cevap

(x8)(x+8)(x - 8)(x + 8)
The polynomial x264x^2 - 64 is a difference of two squares because x2x^2 is the square of xx and 6464 is the square of 88. Applying the difference of squares formula, a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b), with a=xa = x and b=8b = 8 gives the factored form (x8)(x+8)(x - 8)(x + 8).

Adım Adım Çözüm

1
Identify the structure of the polynomial.
The expression x264x^2 - 64 is a difference of two squares since x2x^2 is (x)2(x)^2 and 6464 is (8)2(8)^2.
Recognizing the difference of squares allows the use of the algebraic identity a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).
2
Apply the difference of squares identity with a=xa = x and b=8b = 8.
(x8)(x+8)(x - 8)(x + 8)
Substituting xx and 88 into the formula yields the factored form.

Anahtar Kavram

Factoring the difference of squares using the identity a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b)
Soru 1714Soru

Which of the following is equivalent to the expression 4x2(x2y)3x(x23xy)(x3+xy2)4x^2(x - 2y) - 3x(x^2 - 3xy) - (x^3 + xy^2) for all real values of xx and yy?

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Cevap: x2yxy2x^2y - xy^2

Cevap

The correct simplified expression is x2yxy2x^2y - xy^2.
Distributing the terms yields 4x38x2y3x3+9x2yx3xy24x^3 - 8x^2y - 3x^3 + 9x^2y - x^3 - xy^2. Grouping and combining like terms results in (431)x3+(8+9)x2yxy2=x2yxy2(4-3-1)x^3 + (-8+9)x^2y - xy^2 = x^2y - xy^2.

Adım Adım Çözüm

1
Distribute the term 4x24x^2 to the terms inside the first set of parentheses: 4x2(x2y)4x^2(x - 2y).
4x38x2y4x^3 - 8x^2y
Multiplying a monomial by a binomial requires distributing the multiplier to each term inside.
2
Distribute the term 3x-3x to the terms inside the second set of parentheses: 3x(x23xy)-3x(x^2 - 3xy).
3x3+9x2y-3x^3 + 9x^2y
Carefully apply the distributive property, remembering that multiplying a negative term by a negative term yields a positive term: 3x(3xy)=9x2y-3x \cdot (-3xy) = 9x^2y.
3
Distribute the negative sign (or 1-1) to the terms inside the third set of parentheses: (x3+xy2)-(x^3 + xy^2).
x3xy2-x^3 - xy^2
Distributing the negative sign changes the signs of all terms inside the parentheses.
4
Combine all parts and group the like terms: x3x^3, x2yx^2y, and xy2xy^2.
x2yxy2x^2y - xy^2
Add the coefficients of the terms with the same variable parts: (431)x3+(8+9)x2yxy2=0x3+x2yxy2=x2yxy2(4 - 3 - 1)x^3 + (-8 + 9)x^2y - xy^2 = 0x^3 + x^2y - xy^2 = x^2y - xy^2.

Anahtar Kavram

Simplifying algebraic expressions by distributing and combining like terms.
Tahmini Süre:1m 0s
Soru 1715Soru

For the imaginary unit ii, which of the following is equivalent to the complex expression 2+i1512i9\frac{2 + i^{15}}{1 - 2i^9}?

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Cevap: 45+35i\frac{4}{5} + \frac{3}{5}i

Cevap

45+35i\frac{4}{5} + \frac{3}{5}i
Simplifying the powers of ii yields i15=ii^{15} = -i and i9=ii^9 = i, giving the expression 2i12i\frac{2 - i}{1 - 2i}. Multiplying the numerator and denominator by the complex conjugate 1+2i1 + 2i results in the fraction (2i)(1+2i)(12i)(1+2i)\frac{(2 - i)(1 + 2i)}{(1 - 2i)(1 + 2i)}. Expanding both parts and substituting i2=1i^2 = -1 gives 4+3i5\frac{4 + 3i}{5}, which simplifies to 45+35i\frac{4}{5} + \frac{3}{5}i.

Adım Adım Çözüm

1
Simplify the powers of the imaginary unit ii in the expression.
i15=i12i3=1(i)=ii^{15} = i^{12} \cdot i^3 = 1 \cdot (-i) = -i and i9=i8i=1i=ii^9 = i^8 \cdot i = 1 \cdot i = i. The expression becomes 2i12i\frac{2 - i}{1 - 2i}.
Reducing powers of ii simplifies the expression and makes it easier to work with binomials.
2
Multiply the numerator and denominator by the complex conjugate of the denominator, 1+2i1 + 2i.
2i12i1+2i1+2i=(2i)(1+2i)(12i)(1+2i)\frac{2 - i}{1 - 2i} \cdot \frac{1 + 2i}{1 + 2i} = \frac{(2 - i)(1 + 2i)}{(1 - 2i)(1 + 2i)}
Multiplying by the conjugate rationalizes the denominator, converting it to a real number.
3
Expand and simplify the numerator and denominator using the property i2=1i^2 = -1.
Numerator: (2i)(1+2i)=2+4ii2i2=2+3i2(1)=4+3i(2 - i)(1 + 2i) = 2 + 4i - i - 2i^2 = 2 + 3i - 2(-1) = 4 + 3i. Denominator: (12i)(1+2i)=14i2=14(1)=5(1 - 2i)(1 + 2i) = 1 - 4i^2 = 1 - 4(-1) = 5.
Expanding the binomial products allows combining real and imaginary parts.
4
Write the resulting fraction in standard complex form a+bia + bi.
4+3i5=45+35i\frac{4 + 3i}{5} = \frac{4}{5} + \frac{3}{5}i
Standard form separates the real part and the imaginary part clearly.

Anahtar Kavram

Simplifying complex expressions by reducing powers of ii and rationalizing the denominator using the complex conjugate.
Soru 1716Soru

What is the positive difference between the two real solutions to the quadratic equation 2x(3x5)=3(x2)2x(3x - 5) = 3(x - 2)?

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Cevap: 56\frac{5}{6}

Cevap

The positive difference between the two solutions is 56\frac{5}{6}.
The correct positive difference is 56\frac{5}{6} because rearranging the equation 2x(3x5)=3(x2)2x(3x - 5) = 3(x - 2) yields 6x213x+6=06x^2 - 13x + 6 = 0. Factoring this equation gives (2x3)(3x2)=0(2x - 3)(3x - 2) = 0, which has the solutions x=32x = \frac{3}{2} and x=23x = \frac{2}{3}. Subtracting these values gives 3223=946=56\frac{3}{2} - \frac{2}{3} = \frac{9 - 4}{6} = \frac{5}{6}.

Adım Adım Çözüm

1
Expand both sides of the equation.
6x210x=3x66x^2 - 10x = 3x - 6
To begin solving, distribute the term 2x2x on the left side and the constant 33 on the right side.
2
Rearrange the terms to set the quadratic equation to zero.
6x213x+6=06x^2 - 13x + 6 = 0
Subtract 3x3x and add 66 to both sides of the equation to write it in standard form ax2+bx+c=0ax^2 + bx + c = 0.
3
Factor the quadratic equation over the integers.
(2x3)(3x2)=0(2x - 3)(3x - 2) = 0
Find two binomials whose product is 6x213x+66x^2 - 13x + 6. We search for two numbers that multiply to 3636 (from 6×66 \times 6) and sum to 13-13, which are 9-9 and 4-4, allowing factoring by grouping.
4
Solve for the roots of the equation.
x=32x = \frac{3}{2} or x=23x = \frac{2}{3}
Set each linear factor equal to zero using the Zero Product Property: 2x3=0    x=322x - 3 = 0 \implies x = \frac{3}{2} and 3x2=0    x=233x - 2 = 0 \implies x = \frac{2}{3}.
5
Calculate the positive difference between the two solutions.
3223=9646=56\frac{3}{2} - \frac{2}{3} = \frac{9}{6} - \frac{4}{6} = \frac{5}{6}
Subtract the smaller solution from the larger solution to find the positive difference.

Anahtar Kavram

Solving quadratic equations by rearranging and factoring over integers.
Soru 1717Soru

For all real numbers xx and yy, which of the following is equivalent to the expression (x2y)2(x25xy)(x - 2y)^2 - (x^2 - 5xy)?

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Cevap: 4y2+xy4y^2 + xy

Cevap

The expression is equivalent to 4y2+xy4y^2 + xy.
Expanding (x2y)2(x - 2y)^2 yields x24xy+4y2x^2 - 4xy + 4y^2. Distributing the negative sign to (x25xy)-(x^2 - 5xy) gives x2+5xy-x^2 + 5xy. Combining the results yields (x2x2)+(4xy+5xy)+4y2=xy+4y2(x^2 - x^2) + (-4xy + 5xy) + 4y^2 = xy + 4y^2, which is equivalent to 4y2+xy4y^2 + xy.

Adım Adım Çözüm

1
Expand the squared binomial (x2y)2(x - 2y)^2.
x24xy+4y2x^2 - 4xy + 4y^2
Apply the binomial squaring formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 to expand the expression.
2
Distribute the negative sign across the second parenthetical expression (x25xy)-(x^2 - 5xy).
x2+5xy-x^2 + 5xy
Distributing the negative sign changes the signs of both terms inside the parentheses.
3
Combine like terms from the expanded parts.
xy+4y2xy + 4y^2
Group and add coefficients of the like terms: (x2x2)+(4xy+5xy)+4y2=0+xy+4y2(x^2 - x^2) + (-4xy + 5xy) + 4y^2 = 0 + xy + 4y^2.

Anahtar Kavram

Simplifying Expressions and Combining Like Terms
Soru 1718Soru

Which of the following expressions represents the complete factorization of 2x4322x^4 - 32?

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Cevap: 2(x2)(x+2)(x2+4)2(x - 2)(x + 2)(x^2 + 4)

Cevap

2(x2)(x+2)(x2+4)2(x - 2)(x + 2)(x^2 + 4)
The correct answer is found by first factoring out the greatest common factor of 22, resulting in 2(x416)2(x^4 - 16). Next, recognize that x416x^4 - 16 is a difference of squares, (x2)242(x^2)^2 - 4^2, which factors into (x24)(x2+4)(x^2 - 4)(x^2 + 4). Finally, factor the remaining difference of squares, x24x^2 - 4, into (x2)(x+2)(x - 2)(x + 2). The sum of squares, x2+4x^2 + 4, cannot be factored further. Combining these parts gives the complete factorization.

Adım Adım Çözüm

1
Factor out the greatest common factor from the polynomial.
2(x416)2(x^4 - 16)
Both terms of 2x4322x^4 - 32 are divisible by 22, so we factor it out to simplify the remaining expression.
2
Factor the difference of squares inside the parentheses.
2(x24)(x2+4)2(x^2 - 4)(x^2 + 4)
The expression x416x^4 - 16 is a difference of squares because it can be written as (x2)242(x^2)^2 - 4^2.
3
Factor the remaining difference of squares.
2(x2)(x+2)(x2+4)2(x - 2)(x + 2)(x^2 + 4)
The binomial x24x^2 - 4 is also a difference of squares (x222x^2 - 2^2), which factors into (x2)(x+2)(x - 2)(x + 2). The sum of squares x2+4x^2 + 4 cannot be factored further using real numbers.

Anahtar Kavram

Factoring polynomials completely by extracting the greatest common factor and repeatedly applying the difference of squares formula.
Tahmini Süre:1m 0s
Soru 1719Soru

The square of 33 less than a number xx is equal to 1616. What is the greater of the two possible values for xx?

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Cevap: 7

Cevap

7
The word problem translates to the equation (x3)2=16(x-3)^2 = 16. Expanding the left side and subtracting 16 from both sides gives the standard quadratic equation x26x7=0x^2 - 6x - 7 = 0. This factors into (x7)(x+1)=0(x-7)(x+1) = 0, yielding two solutions: x=7x = 7 and x=1x = -1. The greater of these two values is 7.

Adım Adım Çözüm

1
Translate the verbal description into an algebraic equation.
(x3)2=16(x-3)^2 = 16
'3 less than a number xx' is written as x3x - 3, and its square is set equal to 16.
2
Expand the squared binomial and rearrange the terms into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
x26x7=0x^2 - 6x - 7 = 0
Expanding (x3)2(x-3)^2 yields x26x+9x^2 - 6x + 9. Subtracting 16 from both sides sets the equation to zero.
3
Factor the quadratic equation over the integers.
(x7)(x+1)=0(x - 7)(x + 1) = 0
We find two integers that multiply to 7-7 and add to 6-6, which are 7-7 and 11.
4
Solve for xx by setting each factor to zero, then select the greater value.
x=7x = 7 (since the solutions are 77 and 1-1)
Setting the factors to zero gives x7=0    x=7x - 7 = 0 \implies x = 7 and x+1=0    x=1x + 1 = 0 \implies x = -1. The larger of these two values is 77.

Anahtar Kavram

Solving Quadratic Equations by Factoring
Tahmini Süre:1m 0s
Soru 1720Soru

Which of the following is a factor of the polynomial 8x312x218x+278x^3 - 12x^2 - 18x + 27?

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Cevap: 2x+32x + 3

Cevap

The correct answer is 2x+32x + 3.
The correct answer is the factor 2x+32x + 3. By grouping the first two terms and the last two terms, we get 4x2(2x3)9(2x3)4x^2(2x - 3) - 9(2x - 3). Factoring out the common binomial yields (4x29)(2x3)(4x^2 - 9)(2x - 3). The term 4x294x^2 - 9 is a difference of squares, which factors into (2x3)(2x+3)(2x - 3)(2x + 3). Therefore, the fully factored expression is (2x3)2(2x+3)(2x - 3)^2(2x + 3), making the linear expression with a positive constant term the correct factor.

Adım Adım Çözüm

1
Group the four terms of the polynomial into two pairs.
(8x312x2)(18x27)(8x^3 - 12x^2) - (18x - 27)
Grouping terms allows us to find common binomial factors in a cubic polynomial.
2
Factor out the greatest common factor (GCF) from each group.
4x2(2x3)9(2x3)4x^2(2x - 3) - 9(2x - 3)
The GCF of 8x38x^3 and 12x212x^2 is 4x24x^2, and the GCF of 18x-18x and 2727 is 9-9 (factoring out the negative to match the binomials).
3
Factor out the common binomial factor (2x3)(2x - 3).
(4x29)(2x3)(4x^2 - 9)(2x - 3)
Both groups share the factor (2x3)(2x - 3), so it can be factored out.
4
Factor the quadratic difference of squares (4x29)(4x^2 - 9).
(2x3)(2x+3)(2x3)=(2x3)2(2x+3)(2x - 3)(2x + 3)(2x - 3) = (2x - 3)^2(2x + 3)
The term 4x294x^2 - 9 is a difference of squares of the form a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b), where a=2xa = 2x and b=3b = 3.

Anahtar Kavram

Factoring a cubic polynomial completely by grouping and then applying the difference of squares formula.
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