Translating and Solving Algebraic Word Problems

44 soru

Soru 21Soru

A landscaping company charges a flat equipment fee plus a fixed hourly rate for lawn maintenance. For a job that took 44 hours, the company charged a total of $190\$190. For a different job that took 77 hours, the company charged a total of $295\$295. The company also offers a package that includes a 15%15\% discount on the hourly rate, but the flat equipment fee remains the same. Under this discounted package, what is the total charge, in dollars, for a job that takes 88 hours?

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Cevap: 288

Cevap

The total charge for an 88-hour job under the discounted package is 288288 dollars.
By translating the problem into the equations F+4H=190F + 4H = 190 and F+7H=295F + 7H = 295, we find that the hourly rate HH is 3535 dollars and the flat fee FF is 5050 dollars. Applying a 15%15\% discount to the hourly rate yields a new rate of 29.7529.75 dollars per hour. The total cost for 88 hours is then 50+8(29.75)=28850 + 8(29.75) = 288 dollars.

Adım Adım Çözüm

1
Define variables for the flat fee and hourly rate, and translate the given information into a system of linear equations.
F+4H=190F + 4H = 190 and F+7H=295F + 7H = 295, where FF is the flat fee and HH is the hourly rate.
To represent the cost structure algebraically.
2
Solve the system of equations by elimination or substitution.
H=35H = 35 and F=50F = 50.
To determine the individual cost components (flat fee and hourly rate).
3
Apply the 15%15\% discount to the hourly rate.
Hdiscounted=35×(10.15)=29.75H_{\text{discounted}} = 35 \times (1 - 0.15) = 29.75.
To find the new hourly rate under the discounted package.
4
Calculate the total cost for 88 hours of work with the flat fee and the discounted hourly rate.
Total Cost=50+8(29.75)=288\text{Total Cost} = 50 + 8(29.75) = 288.
To answer the question asking for the total charge of an 88-hour job under the discounted package.

Anahtar Kavram

Translating verbal statements into a system of linear equations and solving them to evaluate a modified expression.
Soru 22Soru

A digital marketing firm allocates a total monthly advertising budget of BB dollars between search engine ads and social media ads. The amount allocated to social media ads is $800\$800 less than twice the amount allocated to search engine ads. The firm then increases its total monthly budget by 20%20\% and allocates this entire increase to search engine ads. As a result, the new amount allocated to search engine ads is equal to the amount originally allocated to social media ads. What was the firm's original total monthly advertising budget, BB?

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Cevap: $4,000\$4,000

Cevap

The original total monthly advertising budget was $4,000\$4,000.
By defining the original search engine advertising budget as SS, the original social media advertising budget as M=2S800M = 2S - 800, and the original total budget as B=3S800B = 3S - 800, we can set up the equation S+0.20B=MS + 0.20B = M using the condition that the new search engine budget equals the original social media budget. Solving this equation yields S=1600S = 1600. Substituting S=1600S = 1600 into the expression for the total budget gives B=3(1600)800=4000B = 3(1600) - 800 = 4000 dollars.

Adım Adım Çözüm

1
Define the variables representing each budget allocation.
Let SS represent the original amount allocated to search engine ads, and let MM represent the original amount allocated to social media ads. The original total budget is B=S+MB = S + M.
Establishing clear variables is necessary to translate the verbal relationships into equations.
2
Translate the relationship between the two advertising categories into an equation.
M=2S800M = 2S - 800
The problem states that the social media ads budget is $800\$800 less than twice the search engine ads budget.
3
Express the original total budget BB in terms of a single variable, SS.
B=S+(2S800)=3S800B = S + (2S - 800) = 3S - 800
Substituting the expression for MM into the total budget equation simplifies the system to a single variable.
4
Set up the equation for the new budget allocation after the 20%20\% increase.
S+0.20B=MS + 0.20B = M
An increase of 20%20\% of the total budget is 0.20B0.20B, which is added entirely to the search engine ads budget, making it equal to the original social media ads budget.
5
Substitute the expressions for BB and MM in terms of SS into the new budget equation.
S+0.20(3S800)=2S800S + 0.20(3S - 800) = 2S - 800
Substituting the relationships found in steps 2 and 3 allows us to solve for SS directly.
6
Solve the equation for SS.
S+0.60S160=2S8001.60S160=2S800640=0.40SS=1,600S + 0.60S - 160 = 2S - 800 \Rightarrow 1.60S - 160 = 2S - 800 \Rightarrow 640 = 0.40S \Rightarrow S = 1,600
Distributing, combining like terms, and isolating the variable yields the original search engine ads allocation.
7
Calculate the original total budget, BB.
B=3(1,600)800=4,800800=4,000B = 3(1,600) - 800 = 4,800 - 800 = 4,000
The question asks for the original total budget BB, so we must evaluate the expression for BB using the value of SS.

Anahtar Kavram

Translating verbal descriptions of algebraic relationships into systems of linear equations and solving them.
Soru 23Soru

An agricultural cooperative packages a premium seed mixture containing rye grass, fescue, and bluegrass. The weight of the fescue in the mixture is 1010 pounds less than twice the weight of the rye grass. The weight of the bluegrass is 1515 pounds more than half the weight of the fescue. If the total weight of the mixture is 120120 pounds, how many pounds of bluegrass are in the mixture?

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Cevap: 40

Cevap

The weight of the bluegrass in the mixture is 40 pounds.
By translating the given relationships into equations (f=2r10f = 2r - 10, b=12f+15b = \frac{1}{2}f + 15, and r+f+b=120r + f + b = 120), we can express all variables in terms of rr, yielding r+(2r10)+(r+10)=120r + (2r - 10) + (r + 10) = 120. Solving this gives r=30r = 30. Substituting this back gives the weight of bluegrass as 30+10=4030 + 10 = 40 pounds.

Adım Adım Çözüm

1
Define variables for each type of grass in the mixture.
Let rr represent the weight of rye grass, ff represent the weight of fescue, and bb represent the weight of bluegrass.
Establishing variables is necessary to translate the verbal descriptions into algebraic terms.
2
Translate the given relationships into equations.
f=2r10f = 2r - 10 and b=12f+15b = \frac{1}{2}f + 15
The problem states the fescue is 10 pounds less than twice the rye grass, and the bluegrass is 15 pounds more than half the fescue.
3
Substitute the expression for f into the equation for b to express b solely in terms of r.
b=12(2r10)+15=r5+15=r+10b = \frac{1}{2}(2r - 10) + 15 = r - 5 + 15 = r + 10
Reducing the number of variables simplifies the system of equations.
4
Set up the total weight equation and solve for r.
r+(2r10)+(r+10)=120    4r=120    r=30r + (2r - 10) + (r + 10) = 120 \implies 4r = 120 \implies r = 30
The sum of the three grass weights is given as 120 pounds.
5
Calculate the weight of the bluegrass using the value of r.
b=30+10=40b = 30 + 10 = 40
The question asks specifically for the weight of the bluegrass.

Anahtar Kavram

Translating verbal relationships into linear equations and solving a system of equations
Soru 24Soru

A manufacturing plant operates two machines, Machine X and Machine Y, to produce identical components. Machine Y produces 12 fewer components per hour than Machine X. On a certain day, Machine X operated for 5 hours and Machine Y operated for 7 hours. If the two machines produced a combined total of 636 components, how many components did Machine X produce on that day?

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Cevap: 300

Cevap

300
To find the number of components Machine X produced, let xx represent Machine X's hourly production rate. This makes Machine Y's hourly rate x12x - 12. Since Machine X operated for 5 hours and Machine Y operated for 7 hours to produce a total of 636 components, we can write the equation: 5x+7(x12)=6365x + 7(x - 12) = 636. Distributing the 7 yields 5x+7x84=6365x + 7x - 84 = 636, which simplifies to 12x84=63612x - 84 = 636. Adding 84 to both sides gives 12x=72012x = 720, and dividing by 12 yields x=60x = 60 components per hour for Machine X. To find the total produced by Machine X, we multiply its hourly rate by the 5 hours it operated: 5×60=3005 \times 60 = 300. This matches the correct option.

Adım Adım Çözüm

1
Define variables for the hourly rates of both machines.
Let xx be the number of components Machine X produces per hour. Since Machine Y produces 12 fewer components per hour, Machine Y's hourly rate is x12x - 12.
Establishing algebraic expressions for each machine's rate allows us to set up a linear equation.
2
Set up an equation representing the total combined production.
The total production is the sum of the components produced by Machine X in 5 hours and Machine Y in 7 hours: 5x+7(x12)=6365x + 7(x - 12) = 636.
The sum of the products of each machine's rate and its operating time equals the total combined production of 636 components.
3
Solve the equation for the hourly rate of Machine X, xx.
Distribute the 7: 5x+7x84=6365x + 7x - 84 = 636. Combine like terms: 12x84=63612x - 84 = 636. Add 84 to both sides: 12x=72012x = 720. Divide by 12: x=60x = 60.
Solving for xx gives the hourly rate of Machine X.
4
Calculate the total components produced by Machine X.
Multiply the hourly rate of Machine X by its hours of operation: 5 hours×60 components/hour=3005 \text{ hours} \times 60 \text{ components/hour} = 300.
The question asks for the total components produced by Machine X, not its hourly rate.

Anahtar Kavram

Setting up and solving single-variable linear equations from verbal descriptions

Alternatif Yöntem

Instead of defining the variable as Machine X's rate, we could define yy as Machine Y's hourly rate. Then Machine X's rate is y+12y + 12. The total equation becomes 5(y+12)+7y=636    5y+60+7y=636    12y=576    y=485(y + 12) + 7y = 636 \implies 5y + 60 + 7y = 636 \implies 12y = 576 \implies y = 48. Since Machine X's hourly rate is y+12=60y + 12 = 60, it produced 5×60=3005 \times 60 = 300 components.
Tahmini Süre:1m 30s
Soru 25Soru

For the opening night of a school play, a total of 320320 tickets were sold, raising a total of $2140\$2{}140 in ticket sales. Student tickets were sold for $5\$5 each, and adult tickets were sold for $8\$8 each. How many adult tickets were sold?

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Cevap: 180

Cevap

180
The correct answer is 180180. By setting up a single-variable linear equation where aa represents the number of adult tickets, the problem translates to 8a+5(320a)=21408a + 5(320 - a) = 2140. Simplifying this yields 3a+1600=21403a + 1600 = 2140, which simplifies to 3a=5403a = 540 and results in a=180a = 180.

Adım Adım Çözüm

1
Define variables for the unknown quantities based on the given total.
Let aa represent the number of adult tickets sold. The number of student tickets sold is represented as 320a320 - a.
Since the total number of tickets is 320320, subtracting the number of adult tickets from the total yields the number of student tickets.
2
Construct a linear equation using the ticket prices and the total revenue.
8a+5(320a)=21408a + 5(320 - a) = 2140
Multiplying the quantity of each ticket type by its respective price (88 dollars for adult and 55 dollars for student) yields the total ticket sales revenue of 2,1402,140 dollars.
3
Solve the equation for the variable aa.
8a+16005a=2140    3a+1600=2140    3a=540    a=1808a + 1600 - 5a = 2140 \implies 3a + 1600 = 2140 \implies 3a = 540 \implies a = 180
Apply the distributive property, group like terms, isolate the variable term, and divide to solve for the number of adult tickets.

Anahtar Kavram

Translating word problems into a single-variable linear equation and solving for the unknown quantity.
Soru 26Soru

A local library has two types of books: fiction and non-fiction. The number of fiction books is 120120 more than twice the number of non-fiction books. If the library has a total of 18601\text{}860 books, how many more fiction books than non-fiction books does the library have?

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Cevap: 700700

Cevap

The library has 700700 more fiction books than non-fiction books.
The correct answer is 700700 because defining the non-fiction books as nn gives 2n+1202n + 120 fiction books. Summing these to equal 18601860 yields 3n+120=18603n + 120 = 1860, which solves to n=580n = 580. The number of fiction books is therefore 2(580)+120=12802(580) + 120 = 1280. The difference between the two quantities is 1280580=7001280 - 580 = 700.

Adım Adım Çözüm

1
Define variables for the two categories of books.
Let nn be the number of non-fiction books. Then the number of fiction books, ff, can be written as f=2n+120f = 2n + 120.
This translates the statement 'the number of fiction books is 120120 more than twice the number of non-fiction books' into an algebraic expression.
2
Set up an equation representing the total number of books.
n+f=1860    n+(2n+120)=1860    3n+120=1860n + f = 1860 \implies n + (2n + 120) = 1860 \implies 3n + 120 = 1860.
The sum of the fiction and non-fiction books must equal the total library inventory of 18601860 books.
3
Solve the equation for the number of non-fiction books, nn.
3n=1740    n=5803n = 1740 \implies n = 580.
Subtracting 120120 from both sides and then dividing by 33 isolates the variable nn.
4
Calculate the number of fiction books and find the difference.
Fiction books: f=2(580)+120=1280f = 2(580) + 120 = 1280. Difference: fn=1280580=700f - n = 1280 - 580 = 700.
The question asks for the difference between the number of fiction and non-fiction books.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
Soru 27Soru

A smart home heating system has two operating modes: Eco mode and Comfort mode. In a certain week, the system was active in one of these two modes for a total of 168168 hours. The number of hours the system was in Eco mode was 2424 hours less than three times the number of hours it was in Comfort mode. For how many hours was the heating system in Comfort mode during that week?

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Cevap: 48

Cevap

The heating system was in Comfort mode for 48 hours.
The correct answer is obtained by representing the hours in Comfort mode as cc and Eco mode as 3c243c - 24. Since their sum is 168168, we write the equation c+3c24=168c + 3c - 24 = 168. Solving this linear equation gives 4c=1924c = 192, which yields c=48c = 48.

Adım Adım Çözüm

1
Define variables for the Comfort and Eco modes.
Let cc represent the hours in Comfort mode and ee represent the hours in Eco mode.
To represent the unknown quantities algebraically.
2
Translate the given information into a system of equations.
c+e=168c + e = 168 and e=3c24e = 3c - 24
The sum of the hours in both modes is 168168, and the relationship between Eco and Comfort hours is described.
3
Substitute the expression for ee into the total hours equation.
c+(3c24)=168c + (3c - 24) = 168
To create a single linear equation with one variable.
4
Solve for the variable cc.
4c24=1684c=192c=484c - 24 = 168 \Rightarrow 4c = 192 \Rightarrow c = 48
Simplifying the equation gives the value of cc, which is the hours spent in Comfort mode.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Soru 28Soru

A commercial printing press charges a business a setup fee of 100100 plus 0.150.15 per brochure printed. To encourage green practices, the press offers a recycling discount equal to 3030 less than 0.050.05 per brochure printed. If the business has a budget of at most 380380 for their brochure order, what is the maximum number of brochures they can print?

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Cevap: 2,500

Cevap

2,500
The correct answer is 2,500 brochures. The total cost is the setup fee of 100plustheprintingcostof100 plus the printing cost of 0.15 per brochure, minus the discount of 30lessthan30 less than 0.05 per brochure. Setting bb as the number of brochures, the discount is 0.05b300.05b - 30. The total cost equation is 100+0.15b(0.05b30)=130+0.10b100 + 0.15b - (0.05b - 30) = 130 + 0.10b. Setting this less than or equal to 380380 yields 130+0.10b3800.10b250b2,500130 + 0.10b \leq 380 \Rightarrow 0.10b \leq 250 \Rightarrow b \leq 2,500.

Adım Adım Çözüm

1
Define the variable and write the algebraic expressions for the cost components.
Let bb be the number of brochures printed. The total cost before the discount is 100+0.15b100 + 0.15b. The recycling discount is represented as 0.05b300.05b - 30.
Establishing clear variables and translating the textual relationships into mathematical expressions is the first step in solving word problems.
2
Set up the inequality representing the budget constraint.
100+0.15b(0.05b30)380100 + 0.15b - (0.05b - 30) \leq 380
The total cost (original cost minus the discount) must be at most the budget of 380380.
3
Simplify the left side of the inequality.
100+0.15b0.05b+30380130+0.10b380100 + 0.15b - 0.05b + 30 \leq 380 \Rightarrow 130 + 0.10b \leq 380
Distributing the subtraction sign across the discount expression and combining like terms simplifies the inequality.
4
Solve for the variable bb.
0.10b250b25000.10b \leq 250 \Rightarrow b \leq 2500
Isolating bb gives the maximum number of brochures that can be printed.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
Soru 29Soru

A boutique chocolatier packages two types of gift boxes: Standard and Deluxe. Each Standard box contains 44 dark chocolates, and each Deluxe box contains 88 dark chocolates. The chocolatier plans to prepare a batch of boxes such that the number of Standard boxes is exactly twice the number of Deluxe boxes. If the chocolatier has a total of 160160 dark chocolates available and uses all of them for this batch, what is the total number of boxes (both Standard and Deluxe combined) they can make?

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Cevap: 30

Cevap

The total number of boxes they can make is 30.
By defining the number of Deluxe boxes as xx, the number of Standard boxes is 2x2x. The equation for the total number of dark chocolates is 4(2x)+8x=1604(2x) + 8x = 160. Solving this gives 16x=16016x = 160, which simplifies to x=10x = 10. Thus, there are 1010 Deluxe boxes and 2020 Standard boxes, for a combined total of 3030 boxes.

Adım Adım Çözüm

1
Define variables for the number of boxes of each type.
Let xx be the number of Deluxe boxes and 2x2x be the number of Standard boxes.
We are given that the number of Standard boxes is exactly twice the number of Deluxe boxes.
2
Set up an equation representing the total number of dark chocolates used.
4(2x)+8x=1604(2x) + 8x = 160
Each Standard box requires 44 dark chocolates, each Deluxe box requires 88, and the total used is 160160.
3
Solve the equation for xx.
16x=160x=1016x = 160 \Rightarrow x = 10
Combining like terms gives 16x=16016x = 160, and dividing both sides by 1616 yields x=10x = 10.
4
Calculate the total number of boxes.
x+2x=30x + 2x = 30
The total number of boxes is the sum of Deluxe boxes (1010) and Standard boxes (2020).

Anahtar Kavram

Translating verbal descriptions of relationships and totals into linear equations to solve algebraic word problems.
Tahmini Süre:1m 30s
Soru 30Soru

An online streaming service offers a basic monthly plan that costs 1212 dollars plus 1.501.50 dollars for each premium movie rented. A premium monthly plan costs 2020 dollars and includes 33 free premium movie rentals, with each additional rental costing 1.001.00 dollar. If a subscriber rents xx premium movies in a month, where x>3x > 3, which of the following expressions represents the savings, in dollars, of the premium plan compared to the basic plan?

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Cevap: 0.50x50.50x - 5

Cevap

0.50x50.50x - 5
The cost of the basic plan for xx rentals is 12+1.50x12 + 1.50x dollars. Under the premium plan, the first 33 rentals are free, so the subscriber only pays for x3x - 3 rentals. The cost of the premium plan is 20+1.00(x3)20 + 1.00(x - 3) dollars, which simplifies to 17+x17 + x dollars. The savings of the premium plan compared to the basic plan is the difference between the basic cost and the premium cost: (12+1.50x)(17+x)=0.50x5(12 + 1.50x) - (17 + x) = 0.50x - 5 dollars.

Adım Adım Çözüm

1
Write the expression for the cost of the basic monthly plan.
12+1.50x12 + 1.50x
The basic plan has a flat fee of 1212 dollars and a rate of 1.501.50 dollars per movie for all xx movies rented.
2
Write the expression for the cost of the premium monthly plan.
20+1.00(x3)20 + 1.00(x - 3), which simplifies to 17+x17 + x.
The premium plan has a flat fee of 2020 dollars. Since 33 rentals are free, the subscriber only pays 1.001.00 dollar each for the remaining x3x - 3 rentals.
3
Subtract the premium plan cost from the basic plan cost to find the savings.
(12+1.50x)(17+x)=0.50x5(12 + 1.50x) - (17 + x) = 0.50x - 5
Savings represents the difference in cost: Basic Cost minus Premium Cost.

Anahtar Kavram

Translating verbal descriptions of multi-step costs into linear algebraic expressions and simplifying them.
Tahmini Süre:1m 30s
Soru 31Soru

Two cyclists start at opposite ends of a 9090-mile trail at the same time and ride toward each other. One cyclist rides at a constant speed that is 33 miles per hour faster than the other cyclist. If the two cyclists meet after exactly 33 hours, what is the constant speed, in miles per hour, of the faster cyclist?

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Cevap: 16.5

Cevap

The speed of the faster cyclist is 16.516.5 miles per hour.
The correct answer of 16.516.5 is found by setting the speed of the slower cyclist to ss and the faster cyclist to s+3s + 3. Since both cyclists ride toward each other for 33 hours, their combined distance is 3s+3(s+3)=903s + 3(s + 3) = 90. Solving for ss yields 6s+9=906s + 9 = 90, which simplifies to 6s=816s = 81, or s=13.5s = 13.5. Adding 33 to 13.513.5 gives the speed of the faster cyclist, which is 16.516.5 miles per hour.

Adım Adım Çözüm

1
Define variables for the speeds of both cyclists in terms of a single variable.
Let ss be the speed of the slower cyclist. The speed of the faster cyclist is s+3s + 3.
Using a single variable simplifies the setup of a solvable linear equation.
2
Write a linear equation using the relationship Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}.
The equation is 3s+3(s+3)=903s + 3(s + 3) = 90.
The sum of the distances traveled by both cyclists when they meet must equal the total length of the trail, which is 9090 miles.
3
Solve the equation for ss.
6s+9=90    6s=81    s=13.56s + 9 = 90 \implies 6s = 81 \implies s = 13.5.
This yields the speed of the slower cyclist.
4
Calculate the speed of the faster cyclist.
13.5+3=16.513.5 + 3 = 16.5.
The question specifically asks for the speed of the faster cyclist, which is represented by s+3s + 3.

Anahtar Kavram

Translating distance-rate-time relationships from word problems into solvable linear equations.

Alternatif Yöntem

An alternative approach is to use the concept of relative speed. Since the two cyclists are moving directly toward each other, their relative speed of approach is the sum of their individual speeds. They cover a total of 9090 miles in 33 hours, which means their combined speed is 903=30\frac{90}{3} = 30 miles per hour. If the speed of the faster cyclist is ff and the slower is ss, then f+s=30f + s = 30 and fs=3f - s = 3. Adding these two equations gives 2f=332f = 33, which yields f=16.5f = 16.5 miles per hour.
Tahmini Süre:1m 15s
Soru 32Soru

A local courier service offers two delivery options inside the city limits: Standard and Express. A Standard delivery costs a flat fee of 15.00plus15.00 plus 0.75 per mile. An Express delivery costs a flat fee of 25.00plus25.00 plus 0.50 per mile. If the cost of a Standard delivery is exactly $5.00 less than the cost of an Express delivery, what is the total cost of the Express delivery?

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Cevap: $35.00

Cevap

The total cost of the Express delivery is $35.00.
The correct answer is 35.00.First,representthecostsasalgebraicfunctionsofthedistance35.00. First, represent the costs as algebraic functions of the distance m :: 15 + 0.75m forStandardand for Standard and 25 + 0.50m forExpress.SetuptheequationreflectingthattheStandardcostis for Express. Set up the equation reflecting that the Standard cost is 5.00 less than the Express cost: 15+0.75m=(25+0.50m)515 + 0.75m = (25 + 0.50m) - 5. Simplifying this equation gives 15+0.75m=20+0.50m15 + 0.75m = 20 + 0.50m. Subtracting 0.50m0.50m and 1515 from both sides results in 0.25m=50.25m = 5, which yields m=20m = 20. Finally, plug m=20m = 20 into the Express cost function: 25+0.50(20)=35.0025 + 0.50(20) = 35.00 dollars.

Adım Adım Çözüm

1
Define the variables and write the cost functions for both options.
Let mm represent the number of miles. The Standard delivery cost is S=15+0.75mS = 15 + 0.75m, and the Express delivery cost is E=25+0.50mE = 25 + 0.50m.
Translating the verbal descriptions into algebraic expressions establishes the basis for solving the problem.
2
Set up the equation using the given relationship that Standard is 5.00 dollars less than Express.
15+0.75m=(25+0.50m)515 + 0.75m = (25 + 0.50m) - 5
The phrase 'Standard cost is 5.00 dollars less than Express cost' translates to S=E5S = E - 5.
3
Solve the equation for mm.
15+0.75m=20+0.50m    0.25m=5    m=2015 + 0.75m = 20 + 0.50m \implies 0.25m = 5 \implies m = 20 miles.
Solving for mm determines the delivery distance that satisfies the cost relationship.
4
Calculate the total cost of the Express delivery by substituting the value of mm into the Express cost function.
E=25+0.50(20)=25+10=35E = 25 + 0.50(20) = 25 + 10 = 35 dollars.
The question specifically asks for the total cost of the Express delivery, not the distance or the Standard delivery cost.

Anahtar Kavram

Translating verbal descriptions of costs and differences into algebraic equations and solving them.

Alternatif Yöntem

You can test the choices. For example, if the Express cost is 35.00,thenthedistance35.00, then the distance m isfoundbysolving is found by solving 25 + 0.50m = 35 \implies 0.50m = 10 \implies m = 20 .At. At 20 miles,theStandardcostis miles, the Standard cost is 15 + 0.75(20) = 30 .Since. Since 30 isindeedexactly is indeed exactly 5 lessthan less than 35$, this choice is correct.
Tahmini Süre:1m 30s
Soru 33Soru

A botanist is monitoring the heights of two bamboo plants. Plant A is 2020 inches tall and grows at a constant rate of 1.51.5 inches per day. Plant B is 1212 inches tall and grows at a constant rate of 2.52.5 inches per day. After how many days will Plant B be exactly 66 inches taller than Plant A?

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Cevap: 14

Cevap

The correct answer is 14 days.
The correct answer is 1414 days because when we translate the relationship, we get the equation 12+2.5d=20+1.5d+612 + 2.5d = 20 + 1.5d + 6. Solving this equation yields d=14d = 14.

Adım Adım Çözüm

1
Define the variable dd as the number of days and write the expressions for the heights of both plants.
Plant A's height is 20+1.5d20 + 1.5d inches, and Plant B's height is 12+2.5d12 + 2.5d inches.
To represent the growth of each plant algebraically over time.
2
Set up an equation representing that Plant B's height is 66 inches more than Plant A's height.
12+2.5d=(20+1.5d)+612 + 2.5d = (20 + 1.5d) + 6
To translate the verbal relationship into a mathematical equation.
3
Simplify the equation and solve for dd.
d=14d = 14
To find the number of days that satisfies the given condition.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 15s
Soru 34Soru

A company's net profit is calculated by subtracting its monthly operating costs from its monthly revenue. In a certain month, the company's revenue is 260,000260,000 dollars minus twice its monthly operating costs. If the company wants its monthly net profit to be at least 110,000110,000 dollars, which of the following inequalities represents all possible values of its monthly operating costs, CC, in dollars?

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Cevap: C50,000C \le 50,000

Cevap

The inequality C50,000C \le 50,000
The correct inequality is obtained by setting up the net profit as the revenue (260,0002C260,000 - 2C) minus the operating costs (CC), which simplifies to 260,0003C260,000 - 3C. Setting this profit to be at least 110,000110,000 gives the inequality 260,0003C110,000260,000 - 3C \ge 110,000. Subtracting 260,000260,000 from both sides results in 3C150,000-3C \ge -150,000. Finally, dividing both sides by 3-3 and reversing the inequality sign because of the division by a negative number yields C50,000C \le 50,000.

Adım Adım Çözüm

1
Define the expression for net profit by subtracting the operating costs, CC, from the revenue, which is 260,0002C260,000 - 2C.
Net profit = (260,0002C)C=260,0003C(260,000 - 2C) - C = 260,000 - 3C
Net profit is defined as revenue minus operating costs.
2
Set up the inequality where the net profit is at least 110,000110,000.
260,0003C110,000260,000 - 3C \ge 110,000
The phrase 'at least' translates to the 'greater than or equal to' inequality sign (\ge).
3
Subtract 260,000260,000 from both sides of the inequality.
3C150,000-3C \ge -150,000
Isolate the term containing the variable CC.
4
Divide both sides by 3-3 and reverse the inequality sign.
C50,000C \le 50,000
Dividing an inequality by a negative number requires reversing the direction of the inequality sign.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
Soru 35Soru

A community theater group sells tickets for a play. Student tickets cost 1212 each, and adult tickets cost 1818 each. For a Friday night performance, the theater sold a total of 150150 tickets. The revenue from the adult tickets sold was 360360 more than the revenue from the student tickets sold. What is the absolute difference between the number of student tickets and the number of adult tickets sold for this performance?

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Cevap: 6

Cevap

6
The correct answer is 6. By setting the number of student tickets to ss, the number of adult tickets is 150s150 - s. Setting up the revenue relationship gives 18(150s)=12s+36018(150 - s) = 12s + 360. Solving this equation gives s=78s = 78 student tickets and 15078=72150 - 78 = 72 adult tickets. The absolute difference between the two values is 7872=678 - 72 = 6.

Adım Adım Çözüm

1
Define variables for the unknown quantities.
Let ss be the number of student tickets sold. Since the total number of tickets sold was 150150, the number of adult tickets sold is 150s150 - s.
Establishing single-variable representations allows us to model the entire situation using one equation.
2
Write an equation representing the revenue relationship.
The revenue from student tickets is 12s12s and the revenue from adult tickets is 18(150s)18(150 - s). The equation is: 18(150s)=12s+36018(150 - s) = 12s + 360.
The problem states that the adult ticket revenue was 360360 more than the student ticket revenue.
3
Solve the linear equation for ss.
270018s=12s+360    2340=30s    s=782700 - 18s = 12s + 360 \implies 2340 = 30s \implies s = 78.
Solving the equation gives the exact number of student tickets sold.
4
Calculate the number of adult tickets sold.
Adult tickets sold = 15078=72150 - 78 = 72.
Subtracting the number of student tickets from the total ticket count yields the number of adult tickets.
5
Find the absolute difference between the two quantities.
7872=6|78 - 72| = 6.
The question asks for the absolute difference between the number of student tickets and the number of adult tickets sold.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
Soru 36Soru

Two volunteer teams, Team A and Team B, are packing food boxes for a local shelter. Team A packs at a constant rate of 1515 boxes per hour and begins packing at 8:00 a.m. Team B packs at a constant rate of 2020 boxes per hour and begins packing at 9:30 a.m. If both teams pack continuously at their respective rates, how many hours after Team A begins will both teams have packed the same total number of boxes?

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Cevap: 6

Cevap

Both teams will have packed the same total number of boxes 66 hours after Team A begins.
The correct answer is 66. Let xx be the number of hours Team A packs. Team B begins 1.5 hours later, so Team B packs for x1.5x - 1.5 hours. Setting their total boxes packed equal gives 15x=20(x1.5)15x = 20(x - 1.5). Distributing yields 15x=20x3015x = 20x - 30. Subtracting 20x20x from both sides gives 5x=30-5x = -30, which simplifies to x=6x = 6.

Adım Adım Çözüm

1
Define the variable for time and identify the time difference.
Let xx be the number of hours Team A packs. Since Team B starts 1 hour and 30 minutes (which is 1.51.5 hours) later, Team B's time is represented as x1.5x - 1.5 hours.
Establishing correct algebraic representations for time is necessary to set up the equation.
2
Set up an equation equating the total boxes packed by both teams.
The equation is 15x=20(x1.5)15x = 20(x - 1.5).
Since both teams pack a constant number of boxes per hour, multiplying their rate by their active time gives the total boxes packed.
3
Solve the linear equation for xx.
Distribute the 20: 15x=20x3015x = 20x - 30. Subtract 20x20x from both sides: 5x=30-5x = -30. Divide by 5-5: x=6x = 6.
Solving the equation gives the number of hours after Team A starts when their packed boxes are equal.

Anahtar Kavram

Translating real-world rates and time shifts into linear equations and solving them.
Soru 37Soru

A pet care service, Canine Care, charges a flat monthly registration fee of 25plus25 plus 15 per dog walk. A competing service, Paws & Claws, charges a flat monthly registration fee of 45plus45 plus 10 per dog walk. If a client's total monthly cost with Canine Care is $30 more than their total monthly cost with Paws & Claws for the same number of walks, how many dog walks did the client's dog receive during that month?

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Cevap: 10

Cevap

The client's dog received 10 dog walks during the month.
The correct answer is 10. By translating the verbal descriptions into algebraic expressions, we find that Canine Care's monthly cost is 15w+2515w + 25 and Paws & Claws' monthly cost is 10w+4510w + 45. Setting up the equation where Canine Care is 3030 more than Paws & Claws gives 15w+25=10w+45+3015w + 25 = 10w + 45 + 30. Simplifying the right side results in 15w+25=10w+7515w + 25 = 10w + 75. Subtracting 10w10w from both sides gives 5w+25=755w + 25 = 75. Subtracting 2525 from both sides gives 5w=505w = 50, and dividing by 55 yields w=10w = 10.

Adım Adım Çözüm

1
Define the variable and write the cost expression for Canine Care.
15w+2515w + 25, where ww is the number of walks.
To represent the total monthly cost of Canine Care algebraically based on the flat fee and per-walk rate.
2
Write the cost expression for Paws & Claws.
10w+4510w + 45, where ww is the number of walks.
To represent the total monthly cost of Paws & Claws algebraically based on the flat fee and per-walk rate.
3
Set up the equation relating the two costs.
15w+25=10w+45+3015w + 25 = 10w + 45 + 30
The problem states the cost of Canine Care is $30 more than the cost of Paws & Claws.
4
Simplify the equation and solve for ww.
5w=50w=105w = 50 \Rightarrow w = 10
Combine like terms and isolate the variable ww to find the number of dog walks.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Soru 38Soru

An online retail store charges a flat shipping fee of 10.0010.00 for any order, plus 5.005.00 per pound of the package's weight. A customer places an order and uses a coupon that gives them a 20%20\% discount on the total cost (the flat shipping fee plus the weight cost). If the customer's total bill after the discount is 36.0036.00, what would their total bill have been, in dollars, if they had not used the coupon?

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Cevap: 45.0045.00

Cevap

The total bill without the coupon would have been 45.0045.00.
The correct answer represents the total cost before the coupon discount. Since a 20%20\% discount was applied to the entire bill, the final bill of 36.0036.00 represents 80%80\% of the original total bill. Setting up the equation 0.80T=36.000.80T = 36.00 and dividing 36.0036.00 by 0.800.80 yields the original total bill of 45.0045.00.

Adım Adım Çözüm

1
Define the variable for the original total bill and set up the equation using the discount percentage.
Let TT represent the total bill before the coupon discount. A 20%20\% discount means the customer pays 100%20%=80%100\% - 20\% = 80\% of the original total bill. This gives the linear equation 0.80T=36.000.80T = 36.00.
Establishing a direct relationship between the original price and the discounted price allows for a direct solution without needing to calculate the weight of the package first.
2
Solve the equation for TT by dividing the discounted cost by the remaining percentage factor.
T=36.000.80=45.00T = \frac{36.00}{0.80} = 45.00
Dividing both sides of the equation by 0.800.80 isolates the variable TT, representing the original total bill in dollars.

Anahtar Kavram

Translating percentage changes and linear cost models into algebraic equations.

Alternatif Yöntem

You can also solve this by finding the weight of the package first. Setting up the equation with the weight ww gives 0.80(10.00+5.00w)=36.000.80(10.00 + 5.00w) = 36.00. Dividing by 0.800.80 simplifies the expression to 10.00+5.00w=45.0010.00 + 5.00w = 45.00, which is the original bill. Solving further gives 5.00w=35.005.00w = 35.00 and w=7w = 7 pounds. Substituting 77 back into the original cost formula yields 10.00+5.00(7)=45.0010.00 + 5.00(7) = 45.00.
Tahmini Süre:1m 30s
Soru 39Soru

A landscaping company charges a one-time equipment mobilization fee of 4545 plus an hourly labor rate of 32.5032.50 per worker. A homeowner hires a crew of 33 workers to clear their yard. If the total bill for the job is 435435 dollars, for how many hours did the crew work?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

4
The total cost of 435435 dollars is the sum of the one-time 4545 dollar mobilization fee and the hourly labor cost of 32.5032.50 dollars per worker for 33 workers over hh hours. This translates to the equation 45+3(32.50)h=43545 + 3(32.50)h = 435, which simplifies to 45+97.50h=43545 + 97.50h = 435. Subtracting 4545 from both sides gives 97.50h=39097.50h = 390. Dividing by 97.5097.50 yields h=4h = 4 hours.

Adım Adım Çözüm

1
Set up the algebraic expression representing the total cost based on the number of hours worked, hh. The total cost consists of a fixed mobilization fee of 4545 dollars and a variable labor cost of 32.5032.50 dollars per worker per hour.
45+3(32.50)h45 + 3(32.50)h
To represent the relation between the hours worked and the total charge.
2
Equate the expression for the total cost to the actual total bill of 435435 dollars and simplify the labor rate coefficient.
45+97.50h=43545 + 97.50h = 435
To form a solvable linear equation in terms of the unknown number of hours, hh.
3
Subtract the fixed mobilization fee of 4545 from both sides of the equation.
97.50h=39097.50h = 390
To isolate the term containing the variable hh.
4
Divide both sides of the equation by 97.5097.50 to solve for hh.
h=4h = 4
To determine the number of hours the crew worked.

Anahtar Kavram

Formulating and solving linear equations from real-world contexts
Tahmini Süre:1m 30s
Soru 40Soru

A smartphone's battery is fully charged to 100%100\%. When the phone is in sleep mode, the battery drains at a constant rate of 1%1\% per hour. When the phone is in active use, the battery drains at a constant rate of 6%6\% per hour. Over a 2020-hour period, the phone is either in sleep mode or in active use, and the battery level decreases to 45%45\%. For how many hours was the phone in active use during this period?

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Cevap: 7

Cevap

The phone was in active use for 7 hours.
To find the active hours, first calculate the total percentage of the battery consumed: 100%45%=55%100\% - 45\% = 55\%. Let xx represent the number of hours in active use. The remaining time, 20x20 - x, represents the hours in sleep mode. Set up the equation representing the total battery drain: 6x+1(20x)=556x + 1(20 - x) = 55. Simplifying this equation gives 5x+20=555x + 20 = 55, which reduces to 5x=355x = 35, resulting in x=7x = 7 hours.

Adım Adım Çözüm

1
Calculate the total percentage of the battery that drained during the period.
100%45%=55%100\% - 45\% = 55\%
To determine the exact battery percentage consumed by both active use and sleep mode combined.
2
Set up a system of equations using xx for hours in active use and yy for hours in sleep mode.
x+y=20x + y = 20 and 6x+1y=556x + 1y = 55
To represent the constraints on the total duration (20 hours) and the total battery drain (55%).
3
Substitute y=20xy = 20 - x into the drain equation and solve for xx.
6x+(20x)=55    5x+20=55    5x=35    x=76x + (20 - x) = 55 \implies 5x + 20 = 55 \implies 5x = 35 \implies x = 7
To find the number of hours the phone was actively used.

Anahtar Kavram

Translating and solving a system of linear equations from a real-world word problem.
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