Tüm alıştırma soruları

512 soru

Soru 321Soru →

A manual meat grinder is operated by turning a crank handle. The crank arm has a length of 8.0 inches8.0 \text{ inches} (acting as the radius of the wheel). The internal grinding shaft, which acts as the axle, has a diameter of 1.6 inches1.6 \text{ inches}. If a user applies a steady perpendicular force of 15 pounds15 \text{ pounds} to the crank handle, what is the resulting theoretical output force (in pounds) exerted at the outer surface of the grinding shaft? Assume 100%100\% efficiency.

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Cevap: 150

Cevap

150
The machine multiplies the input force based on the ratio of the crank arm radius to the grinding shaft radius. Converting the 1.6 inch1.6 \text{ inch} axle diameter to a 0.8 inch0.8 \text{ inch} radius gives an Ideal Mechanical Advantage (IMA) of 1010 (8.0÷0.88.0 \div 0.8). Multiplying the 15 pound15 \text{ pound} input force by this IMA results in a 150 pound150 \text{ pound} theoretical output force.

Adım Adım Çözüm

1
Determine the radius of the axle.
Axle radius = 0.8 inches0.8 \text{ inches}
The Ideal Mechanical Advantage formula requires comparing equivalent radial measurements. Since the wheel dimension is given as a radius, converting the axle's diameter to a radius ensures units are consistent.
2
Calculate the Ideal Mechanical Advantage (IMA).
IMA=10IMA = 10
Dividing the wheel radius (8.0 inches8.0 \text{ inches}) by the axle radius (0.8 inches0.8 \text{ inches}) determines the mechanical advantage multiplier of the machine.
3
Calculate the theoretical output force.
Output Force = 150 pounds150 \text{ pounds}
Multiplying the input force (15 pounds15 \text{ pounds}) by the mechanical advantage (1010) yields the final output force exerted at the axle surface.

Anahtar Kavram

The Ideal Mechanical Advantage (IMA) of a wheel and axle is the ratio of the wheel's radius to the axle's radius. The resulting output force is equal to the input force multiplied by this mechanical advantage.
Soru 322Soru →

A rapid transit commuter train leaves a station, accelerating uniformly along a straight track. It reaches a cruising velocity of 27.0 m/s27.0 \text{ m/s} from a complete stop. If the acceleration phase lasts exactly 0.75 minutes0.75 \text{ minutes}, what is the train's average acceleration in m/s2\text{m/s}^2?

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Cevap: 0.6

Cevap

The train's average acceleration is 0.6 m/s20.6 \text{ m/s}^2.
Acceleration is defined as the change in velocity divided by the time it takes for that change to occur. By converting the time unit to seconds and substituting the initial velocity, final velocity, and time into the standard acceleration formula, the correct magnitude of 0.6 m/s20.6 \text{ m/s}^2 is determined.

Adım Adım Çözüm

1
Identify the known kinematic variables.
Initial velocity vi=0 m/sv_i = 0 \text{ m/s}, final velocity vf=27.0 m/sv_f = 27.0 \text{ m/s}, and time t=0.75 minutest = 0.75 \text{ minutes}.
Extracting the given values is necessary before selecting the appropriate formula.
2
Convert the time from minutes to standard SI units (seconds).
t=0.75×60=45 secondst = 0.75 \times 60 = 45 \text{ seconds}.
Acceleration in m/s2\text{m/s}^2 requires the time unit to match the time component of the velocity unit (seconds).
3
Calculate the average acceleration using the formula a=vf−vita = \frac{v_f - v_i}{t}.
a=27.0−045=0.6 m/s2a = \frac{27.0 - 0}{45} = 0.6 \text{ m/s}^2.
This formula directly relates the change in an object's velocity to the time interval over which the change occurred.

Anahtar Kavram

Kinematics: Uniform Acceleration and Unit Conversion
Soru 323Soru →

An industrial sheet metal shear operates as a second-class lever. The pivot point (fulcrum) is located at the far end of the cutting arm. A mechanic applies a downward effort force of 150 N150 \text{ N} at the handle, which is located 80 cm80 \text{ cm} from the fulcrum. The metal sheet is positioned 16 cm16 \text{ cm} from the fulcrum. Assuming the lever is rigid and frictionless, what is the downward cutting force, in newtons, applied to the metal sheet?

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Cevap: 750

Cevap

750
A second-class lever always places the resistance between the effort and the fulcrum, providing a mechanical advantage greater than 1. The torque applied by the effort (150 N×80 cm150 \text{ N} \times 80 \text{ cm}) must equal the opposing torque exerted on the resistance (Fr×16 cmF_r \times 16 \text{ cm}). Solving this equilibrium equation yields a cutting force of 750 N750 \text{ N}.

Adım Adım Çözüm

1
Identify the lever parameters and equation
Fe=150 NF_e = 150 \text{ N}, de=80 cmd_e = 80 \text{ cm}, dr=16 cmd_r = 16 \text{ cm}
Establishing the values needed for the principle of moments (torque balance).
2
Apply the law of the lever
150×80=Fr×16150 \times 80 = F_r \times 16
In equilibrium, the input torque equals the output torque.
3
Calculate the unknown resistance force
Fr=1200016=750 NF_r = \frac{12000}{16} = 750 \text{ N}
Isolating FrF_r gives the mechanical force applied to the metal.

Anahtar Kavram

Mechanical Advantage and Torque Balance in Second-Class Levers
Tahmini Süre:1m 0s
Soru 324Soru →

The circumference of a circular stained glass window is 18π18\pi inches. What is the area of the window in square inches?

(Enter only the numerical value that multiplies π\pi. For example, if the area is 10π10\pi, enter 10.)

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Cevap: 81

Cevap

81
The correct answer is 81. First, the radius is found by dividing the circumference (18π18\pi) by 2π2\pi, which gives a radius of 9 inches. Then, the area is calculated by squaring this radius and multiplying by π\pi (92=819^2 = 81), resulting in a total area of 81π81\pi. Since the prompt asks for just the numerical value multiplying π\pi, the final response is 81.

Adım Adım Çözüm

1
Find the radius of the circular window using the circumference formula C=2πrC = 2\pi r.
18π=2πr⇒r=918\pi = 2\pi r \Rightarrow r = 9 inches.
The area formula requires the radius, so we must work backward from the given circumference to find it.
2
Calculate the area of the window using the area formula A=πr2A = \pi r^2.
A=π(9)2=81πA = \pi(9)^2 = 81\pi square inches.
Squaring the radius and multiplying by π\pi yields the total area of the circle.
3
Identify the requested numerical value.
81
The question specifically asks for the numerical coefficient that multiplies π\pi.

Anahtar Kavram

Calculating the area of a circle by first determining the radius from the circumference.
Soru 325Soru →

Two angles are supplementary. The measure of the larger angle is 24∘24^\circ more than three times the measure of the smaller angle. What is the measure, in degrees, of the larger angle?

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Cevap: 141

Cevap

141
Supplementary angles have a total sum of 180∘180^\circ. By letting the smaller angle equal xx, the larger angle becomes 3x+243x + 24. Adding these gives x+(3x+24)=180x + (3x + 24) = 180. Simplifying this results in 4x=1564x = 156, so x=39x = 39. Since the question asks for the larger angle, we must substitute x=39x = 39 into our expression for the larger angle: 3(39)+24=117+24=1413(39) + 24 = 117 + 24 = 141. Therefore, the larger angle measures 141∘141^\circ.

Adım Adım Çözüm

1
Assign algebraic expressions to the unknown angles.
Smaller angle = xx, Larger angle = 3x+243x + 24
This translates the given text relationships into mathematical variables that can be used to set up an equation.
2
Set up an equation based on the geometric property of supplementary angles.
x+(3x+24)=180x + (3x + 24) = 180
Supplementary angles, by definition, always add up to exactly 180 degrees.
3
Simplify and solve the linear equation for xx.
4x=1564x = 156, meaning x=39x = 39
Isolating xx provides the measure of the smaller angle.
4
Calculate the measure of the larger angle.
3(39)+24=1413(39) + 24 = 141
The question specifically asks for the measure of the larger angle, so we must plug xx back into the original expression.

Anahtar Kavram

Solving algebraic equations involving supplementary angles
Soru 326Soru →

A heavy equipment transporter has a maximum fuel capacity of 250250 gallons and operates with a fuel efficiency of 44 miles per gallon. The vehicle is dispatched to deliver cargo to a remote site and immediately return to its base along the same route. Military regulations require the transporter to arrive back at base with a minimum of 5050 gallons of fuel in reserve. What is the maximum one-way distance, in miles, the transporter can travel to the remote site without refueling?

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Cevap: 400

Cevap

The maximum one-way distance the transporter can travel is 400 miles.
The correct answer is derived by first identifying the usable fuel (250 - 50 = 200 gallons). Next, the total round-trip distance is calculated by multiplying the usable fuel by the fuel efficiency (200 gallons * 4 miles/gallon = 800 miles). Finally, since the vehicle must travel to the site and return, the total range is divided by 2, resulting in a maximum one-way distance of 400 miles.

Adım Adım Çözüm

1
Determine the amount of usable fuel available for the mission.
200 gallons
The transporter has a 250-gallon tank but must retain a 50-gallon reserve upon return, meaning only 200 gallons can be consumed during the trip.
2
Calculate the total distance the vehicle can travel using the usable fuel.
800 miles
Multiplying the 200 gallons of usable fuel by the vehicle's fuel efficiency of 4 miles per gallon gives the total range.
3
Determine the maximum one-way distance.
400 miles
Because the mission is a round trip along the same route, the total range must cover the distance to the site and back. Therefore, the one-way distance is half of the total range.

Anahtar Kavram

Calculating one-way distance using fuel efficiency, total fuel capacity, required reserves, and accounting for round-trip constraints.
Soru 327Soru →

A technician uses a pair of long industrial tweezers to securely hold a sensitive electronic component. The tweezers pivot at the joined top end and have a total length of 40 cm40 \text{ cm} from the pivot to the gripping tips. The technician's fingers apply pressure at a point 8 cm8 \text{ cm} from the pivot. If the component requires a holding force of 50 N50 \text{ N} at the tips, what effort force (in Newtons) must the technician apply?

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Cevap: 250

Cevap

The technician must apply an effort force of 250 N.
In a third-class lever like tweezers, the effort is applied between the fulcrum and the load. Since the effort arm (8 cm8 \text{ cm}) is shorter than the load arm (40 cm40 \text{ cm}), the mechanical advantage is less than 1. This means a much larger effort force is required to generate a smaller load force at the tips. Using the torque balance equation Fe×de=Fl×dlF_e \times d_e = F_l \times d_l, we get Fe×8=50×40F_e \times 8 = 50 \times 40. Solving this gives 250 N250 \text{ N}.

Adım Adım Çözüm

1
Identify the lever configuration and its parameters.
The tweezers are a third-class lever (fulcrum at one end, effort in the middle). Effort arm de=8 cmd_e = 8 \text{ cm}, load arm dl=40 cmd_l = 40 \text{ cm}, load force Fl=50 NF_l = 50 \text{ N}.
Correctly identifying the lever class ensures the correct distances are used relative to the fulcrum.
2
Set up the torque equilibrium equation.
Fe×de=Fl×dlF_e \times d_e = F_l \times d_l
For the lever to remain stable and provide the required grip, the effort torque must balance the load torque.
3
Calculate the required effort force.
Fe×8=50×40⇒8Fe=2000⇒Fe=250 NF_e \times 8 = 50 \times 40 \Rightarrow 8 F_e = 2000 \Rightarrow F_e = 250 \text{ N}
To find the unknown variable by substituting the given values.

Anahtar Kavram

Torque Balance in Third-Class Levers
Soru 328Soru →

A flat metal washer is manufactured by stamping a circular hole with a diameter of 4 mm4 \text{ mm} out of the exact center of a solid circular disk with a diameter of 12 mm12 \text{ mm}. What is the area of the remaining flat face of the washer in square millimeters? (Enter only the numerical coefficient of π\pi in your answer. For example, if the area is 50π50\pi, enter 50).

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Cevap: 32

Cevap

32
The area of the remaining metal washer face is found by calculating the area of the large outer circle (36π36\pi) and subtracting the area of the smaller inner circle hole (4π4\pi), which leaves a remaining area of 32π32\pi. Since the question asks for the coefficient of π\pi, the correct numerical entry is 32.

Adım Adım Çözüm

1
Calculate the radius of the outer disk.
R=12÷2=6 mmR = 12 \div 2 = 6 \text{ mm}
The area formula for a circle requires the radius, which is half of the diameter.
2
Calculate the area of the outer disk.
Areaouter=π×62=36π mm2\text{Area}_{\text{outer}} = \pi \times 6^2 = 36\pi \text{ mm}^2
This represents the total surface area before the center hole is removed.
3
Calculate the radius of the inner hole.
r=4÷2=2 mmr = 4 \div 2 = 2 \text{ mm}
The radius of the removed section is needed to determine how much area to subtract.
4
Calculate the area of the inner hole.
Areainner=π×22=4π mm2\text{Area}_{\text{inner}} = \pi \times 2^2 = 4\pi \text{ mm}^2
This is the area of the metal that is stamped out.
5
Subtract the inner area from the outer area.
36π−4π=32π mm236\pi - 4\pi = 32\pi \text{ mm}^2
The remaining face area of the washer is the difference between the full disk and the removed hole.
6
Identify the coefficient of π\pi.
32
The stem specifically asks for the numerical coefficient only.

Anahtar Kavram

Calculating the area of an annulus (the region between two concentric circles) by subtracting the area of the inner circle from the area of the outer circle.
Soru 329Soru →

In carpentry and construction, nail lengths are designated using the penny system, indicated by the lowercase letter d\text{d}. According to standard pennyweight sizing rules for common nails up to 10d10\text{d}, what is the total length in inches of a 6d6\text{d} (6-penny) nail?

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Cevap: 2

Cevap

A 6d6\text{d} nail is exactly 2.0 inches2.0\text{ inches} long.
For standard common, box, and finishing nails from 2d2\text{d} through 10d10\text{d}, the length in inches increases by 14 inch\frac{1}{4}\text{ inch} for each penny step: Length=d4+0.5 inches\text{Length} = \frac{d}{4} + 0.5\text{ inches}. Substituting d=6d = 6 yields 64+0.5=1.5+0.5=2.0 inches\frac{6}{4} + 0.5 = 1.5 + 0.5 = 2.0\text{ inches}.

Adım Adım Çözüm

1
Identify the penny size number (dd) given in the problem.
d=6d = 6
The question specifies a 6d6\text{d} (6-penny) nail.
2
Apply the standard formula for converting penny size (dd) to length in inches for nails up to 10d10\text{d}: Length=d4+12\text{Length} = \frac{d}{4} + \frac{1}{2}.
Length=64+12=1.5+0.5=2.0 inches\text{Length} = \frac{6}{4} + \frac{1}{2} = 1.5 + 0.5 = 2.0\text{ inches}
Each penny increase represents a 14-inch\frac{1}{4}\text{-inch} increase in length starting from a 2d2\text{d} base of 1 inch1\text{ inch}.

Anahtar Kavram

Penny (dd) size conversion to physical nail length in inches
Tahmini Süre:45s
Soru 330Soru →

A custom corner desk is shaped like a right triangle so it fits perfectly against two perpendicular walls. The sections of the desk that touch the walls measure 24 inches24\text{ inches} and 10 inches10\text{ inches} in length. What is the length of the front edge of the desk in inches?

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Cevap: 26

Cevap

26
Because the walls meet at a perpendicular right angle, the corner desk forms a right triangle. The edges touching the walls act as the legs (a=24a = 24, b=10b = 10), and the front edge is the hypotenuse (cc). Using the Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2), we square both legs to get 576576 and 100100. Adding these together gives 676676. The square root of 676676 is 2626, which is the exact length of the front edge in inches.

Adım Adım Çözüm

1
Identify the known sides of the right triangle
Legs are a=24a = 24 and b=10b = 10.
The walls are perpendicular, forming a 90∘90^{\circ} angle. Therefore, the edges touching the walls are the legs of a right triangle.
2
Set up the Pythagorean Theorem
242+102=c224^2 + 10^2 = c^2
The Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2) is the standard formula used to find the missing hypotenuse (cc) when both legs are known.
3
Square the lengths of the legs
576+100=c2576 + 100 = c^2
Evaluating the exponents is the required next step in the order of operations.
4
Add the squared values
676=c2676 = c^2
Combining the squares of the legs gives the square of the hypotenuse.
5
Find the square root of the sum
c=26c = 26
Taking the square root of 676676 isolates cc, revealing the true length of the desk's front edge.

Anahtar Kavram

Using the Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2) to calculate the length of a hypotenuse.

Alternatif Yöntem

You can solve this rapidly without large calculations by recognizing special Pythagorean triples. This triangle is a scaled-up version of the fundamental 5−12−135-12-13 right triangle. Multiplying each side of a 5−12−135-12-13 triangle by 22 gives side lengths of 1010, 2424, and 2626. Since the legs are 1010 and 2424, the hypotenuse must be 2626.
Tahmini Süre:45s
Soru 331Soru →

The circular foundation of a radar dome has a circumference of 36π feet36\pi \text{ feet}. What is the area of this circular foundation, in square feet?

(Enter only the numerical coefficient of π\pi in your answer. For example, if the area is 100π100\pi, enter 100.)

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Cevap: 324

Cevap

324
The circumference of a circle is calculated using C=2πrC = 2\pi r. Setting the given circumference 36π=2πr36\pi = 2\pi r gives a radius of 18 feet18 \text{ feet}. The area is found using A=πr2A = \pi r^2, which becomes A=π(18)2=324π square feetA = \pi(18)^2 = 324\pi \text{ square feet}. Since the question asks for the numerical coefficient of π\pi, the correct value to enter is 324.

Adım Adım Çözüm

1
Find the radius of the circular foundation from its given circumference.
r=18r = 18
The circumference formula is C=2πrC = 2\pi r. Setting 2πr=36π2\pi r = 36\pi allows us to solve for the radius.
2
Calculate the area of the foundation using the radius.
A=324πA = 324\pi
The area formula is A=πr2A = \pi r^2. Substituting r=18r = 18 gives A=π(18)2=324πA = \pi(18)^2 = 324\pi.
3
Extract the numerical coefficient of π\pi for the final answer.
324
The question explicitly asks to enter only the numerical coefficient of π\pi.

Anahtar Kavram

Calculating the area of a circle by first deriving the radius from its circumference
Soru 332Soru →

The total surface area of a cube is 150150 square centimeters. What is the volume of the cube, in cubic centimeters?

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Cevap: 125

Cevap

125
The correct answer is derived by first identifying the side length of the cube. Given the total surface area is 150150 square centimeters, we divide by 66 to find the area of a single face (2525 square centimeters). The square root of 2525 gives a side length of 55 centimeters. Finally, cubing this side length (5×5×55 \times 5 \times 5) results in a total volume of 125125 cubic centimeters.

Adım Adım Çözüm

1
Use the total surface area to find the area of a single face of the cube.
150÷6=25150 \div 6 = 25 square centimeters.
A cube has exactly 66 identical square faces. Dividing the total surface area by 66 isolates the area of just one face (s2s^2).
2
Determine the length of one edge of the cube.
s=25=5s = \sqrt{25} = 5 centimeters.
Because the area of a square face is the side length squared (s2s^2), taking the square root gives the side length.
3
Calculate the total volume of the cube.
V=53=125V = 5^3 = 125 cubic centimeters.
The formula for the volume of a cube is the side length cubed (V=s3V = s^3).

Anahtar Kavram

Converting between the surface area and volume of a 3D figure by finding the missing dimension.
Tahmini Süre:45s
Soru 333Soru →

In general carpentry and light framing, a standard rule of thumb requires a fastener to penetrate into the receiving structural member by at least twice the thickness of the board being fastened. If a worker is securing a 0.75-inch0.75\text{-inch}-thick wooden board directly to framing lumber, what is the minimum total nail length, in inches, required to satisfy this standard?

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Cevap: 2.25

Cevap

The minimum required nail length is 2.25 inches2.25\text{ inches} (214 inches2\frac{1}{4}\text{ inches}, equivalent to a 7d7\text{d} nail).
To satisfy the standard carpentry rule of thumb that a nail must penetrate into the supporting timber at least twice the thickness of the piece being fastened, the penetration must be 2×0.75 in.=1.50 inches2 \times 0.75\text{ in.} = 1.50\text{ inches}. Adding the 0.75-inch0.75\text{-inch} thickness of the surface board gives a minimum total fastener length of 0.75 in.+1.50 in.=2.25 inches0.75\text{ in.} + 1.50\text{ in.} = 2.25\text{ inches}.

Adım Adım Çözüm

1
Calculate the required penetration depth into the base framing lumber.
Penetration depth = 2×0.75 in.=1.50 inches2 \times 0.75\text{ in.} = 1.50\text{ inches}.
Standard carpentry practice dictates that the fastener must embed into the receiving member at least twice the thickness of the fastened material to ensure adequate withdrawal and shear resistance.
2
Calculate the total minimum nail length by combining the board thickness and the penetration depth.
Total minimum length = 0.75 in.+1.50 in.=2.25 inches0.75\text{ in.} + 1.50\text{ in.} = 2.25\text{ inches}.
The total nail length must pass completely through the attached board before penetrating into the receiving member.

Anahtar Kavram

Fastener length determination using the two-thirds total length / two-times thickness penetration rule of thumb in carpentry.
Tahmini Süre:1m 0s
Soru 334Soru →

A painter leans a 25-foot25\text{-foot} ladder against a vertical wall. The base of the ladder is placed exactly 7 feet7\text{ feet} away from the base of the wall on level ground. How high up the wall, in feet, does the top of the ladder reach?

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Cevap: 24

Cevap

The top of the ladder reaches 24 feet up the wall.
The correct answer is derived by modeling the scenario as a right triangle. The ladder acts as the hypotenuse (c=25c = 25) and the distance along the ground acts as one leg (a=7a = 7). Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), we solve for the missing height (bb). Substituting the values gives 72+b2=2527^2 + b^2 = 25^2, which simplifies to 49+b2=62549 + b^2 = 625. Subtracting 49 yields b2=576b^2 = 576. The square root of 576 is 24, meaning the ladder reaches 24 feet up the wall.

Adım Adım Çözüm

1
Set up the right triangle relationship.
a2+b2=c2a^2 + b^2 = c^2, where c=25c = 25 and a=7a = 7
The wall is perpendicular to the ground, forming a right triangle with the ladder acting as the hypotenuse.
2
Substitute known values into the Pythagorean theorem.
72+b2=2527^2 + b^2 = 25^2
We know the hypotenuse (2525) and one leg (77), and we need to find the other leg (bb).
3
Square the known numbers.
49+b2=62549 + b^2 = 625
Evaluating the exponents is required before isolating the variable term.
4
Isolate the variable term.
b2=625−49=576b^2 = 625 - 49 = 576
Subtracting 4949 from both sides leaves b2b^2 by itself.
5
Solve for the height.
b=576=24b = \sqrt{576} = 24
Taking the square root of both sides gives the length of the missing side.

Anahtar Kavram

Using the Pythagorean theorem to find a missing leg of a right triangle in a real-world scenario.
Soru 335Soru →

A builder is fastening a 0.5-inch0.5\text{-inch}-thick plywood panel and a 0.75-inch0.75\text{-inch}-thick wooden furring strip to wall framing studs using standard 16d16\text{d} common nails (3.5 inches3.5\text{ inches} long). If each nail is driven straight and flush with the outer face of the furring strip, how many inches of the nail will penetrate into the framing stud?

Cevabı ve açıklamayı göster

Cevap: 2.25

Cevap

2.25 inches
The nail passes through both the 0.75-inch0.75\text{-inch} furring strip and the 0.5-inch0.5\text{-inch} plywood panel, which take up a combined thickness of 1.25 inches1.25\text{ inches}. Subtracting this 1.25 inches1.25\text{ inches} from the total 3.5-inch3.5\text{-inch} nail length leaves exactly 2.25 inches2.25\text{ inches} of penetration into the framing stud.

Adım Adım Çözüm

1
Calculate the total thickness of the layers through which the fastener passes before entering the stud.
0.75 in+0.50 in=1.25 in0.75\text{ in} + 0.50\text{ in} = 1.25\text{ in}
The nail must pass completely through both the outer furring strip and the intermediate plywood panel.
2
Determine the effective length of the fastener driven flush.
3.50 in3.50\text{ in}
A standard 16d16\text{d} (16-penny) common nail has an overall physical length of 3.5 inches3.5\text{ inches}.
3
Subtract the combined surface thickness from the total length of the nail.
3.50 in−1.25 in=2.25 in3.50\text{ in} - 1.25\text{ in} = 2.25\text{ in}
The remaining portion of the nail shank embeds directly into the receiving wooden stud.

Anahtar Kavram

Fastener penetration depth and standard pennyweight length calculation
Tahmini Süre:1m 0s
Soru 336Soru →

A community center is repainting the inside of an empty rectangular swimming pool. The pool is 2525 meters long, 1010 meters wide, and has a uniform depth of 22 meters. If the entire bottom and all four interior walls are to be painted, what is the total area, in square meters, that needs to be painted?

Cevabı ve açıklamayı göster

Cevap: 390

Cevap

390
The correct total area is found by adding the area of the bottom (250250 m 2^2) and the areas of the four vertical walls (100100 m 2^2 and 4040 m 2^2). Because it is a swimming pool, there is no top to paint, making the total area 390390 square meters.

Adım Adım Çözüm

1
Determine which surfaces of the rectangular pool need to be painted.
One bottom surface and four side walls (two long and two short). The top is open.
A pool is shaped like an open-top rectangular prism, so we only need to calculate the area of 5 faces instead of 6.
2
Calculate the area of the bottom surface.
Area = 25×10=25025 \times 10 = 250 square meters.
The bottom is a rectangle bounded by the length and width of the pool.
3
Calculate the combined area of the four side walls.
Long walls = 2×(25×2)=1002 \times (25 \times 2) = 100 square meters. Short walls = 2×(10×2)=402 \times (10 \times 2) = 40 square meters.
There are two identical walls along the length and two identical walls along the width. The area of each wall is its base dimension multiplied by the depth.
4
Sum the areas of all the painted surfaces.
250+100+40=390250 + 100 + 40 = 390 square meters.
The total area to be painted is the sum of the areas of the individual painted faces.

Anahtar Kavram

Surface area of an open rectangular prism
Soru 337Soru →

The entrance of a camping tent is shaped like an isosceles triangle. The base of the tent resting on the ground is 16 feet16\text{ feet} wide, and the two slanted sides are each 17 feet17\text{ feet} long. What is the maximum height of the tent, in feet, from the ground to the peak?

Cevabı ve açıklamayı göster

Cevap: 15

Cevap

15
By dividing the isosceles triangle in half, we form a right triangle with a hypotenuse of 17 and a base leg of 8. Applying the Pythagorean theorem (82+h2=1728^2 + h^2 = 17^2) gives 64+h2=28964 + h^2 = 289, resulting in h2=225h^2 = 225. The square root of 225 is 15, which is the maximum height of the tent.

Adım Adım Çözüm

1
Divide the base of the isosceles triangle in half to find the base of the inner right triangle.
16÷2=8 feet16 \div 2 = 8\text{ feet}
The height (altitude) of an isosceles triangle bisects the base, creating a right angle necessary for the Pythagorean theorem.
2
Set up the Pythagorean theorem equation (a2+b2=c2a^2 + b^2 = c^2).
h2+82=172h^2 + 8^2 = 17^2
The vertical height (hh) and half of the base (88) are the legs of the right triangle, while the slanted side (1717) is the hypotenuse.
3
Square the known values.
h2+64=289h^2 + 64 = 289
Simplifying the terms makes it possible to solve for the unknown.
4
Subtract 64 from both sides to isolate h2h^2.
h2=225h^2 = 225
Standard algebraic process for solving a one-variable equation.
5
Take the square root of both sides to find hh.
h=15h = 15
The inverse operation of squaring gives the final linear dimension of the height.

Anahtar Kavram

Using the properties of isosceles triangles alongside the Pythagorean theorem to find an unknown altitude
Soru 338Soru →

The floor of a rectangular storage room has a diagonal measurement of 3939 feet and a width of 1515 feet. What is the total area of the floor in square feet?

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Cevap: 540

Cevap

540
The storage room floor forms a right triangle with the 39-foot diagonal as the hypotenuse and the 15-foot width as a leg. The missing length is calculated to be 36 feet using the Pythagorean theorem. Multiplying this 36-foot length by the 15-foot width yields a total area of 540 square feet.

Adım Adım Çözüm

1
Identify the right triangle formed by the floor dimensions
A right triangle is formed with the diagonal (39 feet) as the hypotenuse and the width (15 feet) as one leg.
The diagonal of any rectangle splits it into two identical right triangles.
2
Find the missing length of the floor
The length is 36 feet.
Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), 152+b2=39215^2 + b^2 = 39^2. This simplifies to 225+b2=1521225 + b^2 = 1521, so b2=1296b^2 = 1296 and b=36b = 36. Alternatively, recognize the 5-12-13 Pythagorean triple multiplied by 3.
3
Calculate the area of the rectangle
Area = 540 square feet.
The area of a rectangle is its length multiplied by its width (36×15=54036 \times 15 = 540).

Anahtar Kavram

Using the Pythagorean theorem to find unknown dimensions for area calculations.

Alternatif Yöntem

Instead of calculating 39239^2 and 15215^2 manually, recognize that the given sides are multiples of the common 5-12-13 Pythagorean triple (3×5=153 \times 5 = 15 and 3×13=393 \times 13 = 39). This immediately gives the missing length as 3×12=363 \times 12 = 36.
Tahmini Süre:1m 0s
Soru 339Soru →

A city is installing a new fence around a rectangular dog park. The park has a length of 8080 feet and a width of 6060 feet. How many feet of fencing are required to completely enclose the park?

Cevabı ve açıklamayı göster

Cevap: 280

Cevap

280
The fencing must cover the entire outer edge of the rectangular park. The perimeter is found by adding the length and width together, then multiplying the sum by 2 to account for all four sides. Thus, 2 × (80 + 60) = 280 feet.

Adım Adım Çözüm

1
Identify the given dimensions of the rectangular park.
Length = 80 feet, Width = 60 feet.
To determine the values needed for the perimeter formula.
2
Apply the formula for the perimeter of a rectangle.
Perimeter = 2 × (80 + 60)
The total fencing required is equal to the perimeter of the rectangle.
3
Perform the addition inside the parentheses.
80 + 60 = 140
Following the order of operations.
4
Multiply the sum by 2.
2 × 140 = 280
To account for all four sides of the rectangular boundary.

Anahtar Kavram

The perimeter of a rectangle is the total distance around the outside edge, calculated using the formula 2 × (Length + Width).
Soru 340Soru →

If 5m+12=2m+275m + 12 = 2m + 27, what is the value of mm?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

The correct value of the variable is 5.
By using inverse operations to collect the variable terms on one side and the constant terms on the other, the equation simplifies to 3m=153m = 15, which directly yields a result of 55.

Adım Adım Çözüm

1
Move all terms containing the variable to one side of the equation.
3m+12=273m + 12 = 27
Subtracting 2m2m from both sides eliminates the variable from the right side and groups it on the left.
2
Move all constant terms to the opposite side of the equation.
3m=153m = 15
Subtracting 1212 from both sides isolates the term containing the variable.
3
Solve for the variable.
m=5m = 5
Dividing both sides by the coefficient 33 provides the final value of mm.

Anahtar Kavram

Solving Linear Equations with Variables on Both Sides
Tahmini Süre:45s
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