Tüm alıştırma soruları

5215 soru

Soru 5201Soru →

Which of the following is equivalent to the expression (3m−2n4)2(2m5n0)(3m^{-2}n^4)^2(2m^5n^0)?

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Cevap: 18mn818mn^8

Cevap

The simplified expression is 18mn818mn^8.
The correct answer is derived by first squaring each part of the initial term, making it 9m−4n89m^{-4}n^8. The second term simplifies to 2m52m^5 because n0=1n^0 = 1. Multiplying these together requires multiplying the coefficients (9×2=189 \times 2 = 18) and adding the exponents for mm (−4+5=1-4 + 5 = 1), resulting in 18mn818mn^8.

Adım Adım Çözüm

1
Simplify the first factor by applying the power of 2 to the coefficient and the variable exponents.
(3)2(m−2)2(n4)2=9m−4n8(3)^2(m^{-2})^2(n^4)^2 = 9m^{-4}n^8
When a product is raised to a power, the exponent must be applied to every factor inside the parentheses, multiplying the variable exponents.
2
Simplify the second factor using the zero exponent rule.
2m5(1)=2m52m^5(1) = 2m^5
Any non-zero term raised to the power of 0 equals 1, so n0=1n^0 = 1.
3
Multiply the two simplified factors together.
(9m−4n8)(2m5)=(9⋅2)(m−4⋅m5)(n8)(9m^{-4}n^8)(2m^5) = (9 \cdot 2)(m^{-4} \cdot m^5)(n^8)
To multiply terms, multiply the numerical coefficients and add the exponents of like bases.
4
Perform the final arithmetic for the coefficients and exponents.
18m−4+5n8=18m1n8=18mn818m^{-4+5}n^8 = 18m^1n^8 = 18mn^8
Evaluating 9⋅2=189 \cdot 2 = 18 and combining the exponents of mm gives the final simplified expression.

Anahtar Kavram

Operations with Variable Exponents
Soru 5202Soru →
Find the numerical value of the rational expression 3a2−4bc+2\frac{3a^2 - 4b}{c + 2} using the parameter values a=−2a = -2, b=−5b = -5, and c=−6c = -6.
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Cevap: -8

Cevap

The final numerical value is -8.
The correct value is found by carefully substituting the negative integer values into the rational expression, strictly applying the order of operations (exponents, then multiplication, then addition/subtraction), and accurately tracking the signs at each step to get 32 in the numerator and -4 in the denominator, which yields -8.

Adım Adım Çözüm

1
Substitute the given values into the expression.
3(−2)2−4(−5)−6+2\frac{3(-2)^2 - 4(-5)}{-6 + 2}
Replace variables aa, bb, and cc with their assigned numerical equivalents to begin evaluation.
2
Evaluate the exponent in the numerator.
3(4)−4(−5)−6+2\frac{3(4) - 4(-5)}{-6 + 2}
According to the order of operations, exponents must be evaluated before multiplication. The square of a negative number is positive: (−2)2=4(-2)^2 = 4.
3
Perform the multiplications in the numerator.
12−(−20)−6+2\frac{12 - (-20)}{-6 + 2}
Calculate the products: 3×4=123 \times 4 = 12 and 4×(−5)=−204 \times (-5) = -20.
4
Simplify the subtraction in the numerator.
12+20−6+2=32−6+2\frac{12 + 20}{-6 + 2} = \frac{32}{-6 + 2}
Subtracting a negative number is equivalent to adding a positive number: 12−(−20)=12+20=3212 - (-20) = 12 + 20 = 32.
5
Evaluate the addition in the denominator.
32−4\frac{32}{-4}
Combine the constant terms in the denominator: −6+2=−4-6 + 2 = -4.
6
Divide the numerator by the denominator.
-8
A positive number divided by a negative number results in a negative quotient: 32÷(−4)=−832 \div (-4) = -8.

Anahtar Kavram

Evaluating Algebraic Expressions
Soru 5203Soru →

Consider the following mathematical relationship:

34(m−8)+2=12m−1 \frac{3}{4}(m - 8) + 2 = \frac{1}{2}m - 1

Which of the following represents the correct solution for mm?

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Cevap: 12

Cevap

The correct solution is 12.
The correct solution is found by systematically applying the distributive property to eliminate parentheses, combining the constant terms, grouping the variable terms on one side, and fully isolating the variable. Following these steps accurately yields a value of 12.

Adım Adım Çözüm

1
Apply the distributive property to the left side of the equation.
34m−6+2=12m−1 \frac{3}{4}m - 6 + 2 = \frac{1}{2}m - 1
This removes the parentheses by multiplying the fraction through the terms inside.
2
Combine the constant terms on the left side.
34m−4=12m−1 \frac{3}{4}m - 4 = \frac{1}{2}m - 1
Simplifying the expressions on both sides makes it easier to isolate the variable.
3
Subtract 12m \frac{1}{2}m from both sides to group the variable terms.
14m−4=−1 \frac{1}{4}m - 4 = -1
This places all terms containing the variable on one side of the equation. (Note: 34m−24m=14m \frac{3}{4}m - \frac{2}{4}m = \frac{1}{4}m )
4
Add 4 to both sides to isolate the variable term.
14m=3 \frac{1}{4}m = 3
This cancels out the constant on the left side, leaving only the variable term.
5
Multiply both sides by 4.
m=12 m = 12
This clears the fractional coefficient and solves for the final value of the variable.

Anahtar Kavram

Solving one-variable linear equations with fractions and distribution
Soru 5204Soru →

A fitness center offers two membership plans. Plan A requires a one-time enrollment fee of 4545 dollars and costs 3030 dollars per month. Plan B requires a one-time enrollment fee of 105105 dollars and costs 2020 dollars per month. For how many months of membership will the total cost of both plans be exactly the same?

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Cevap: 6

Cevap

The plans will cost the exact same amount at 6 months.
Setting the cost of Plan A (45+30m45 + 30m) equal to the cost of Plan B (105+20m105 + 20m) creates the equation 45+30m=105+20m45 + 30m = 105 + 20m. By isolating the variable, we find that 10m=6010m = 60, which simplifies to m=6m = 6. Therefore, it takes exactly 66 months for both memberships to cost the same.

Adım Adım Çözüm

1
Define the variable and formulate a one-variable linear equation.
45+30m=105+20m45 + 30m = 105 + 20m
To determine when the total costs are equal, the cost expression for Plan A (4545 fee plus 3030 per month) must be set equal to the cost expression for Plan B (105105 fee plus 2020 per month).
2
Subtract 20m20m from both sides of the equation.
45+10m=10545 + 10m = 105
This groups all terms containing the variable mm on one side of the equation.
3
Subtract 4545 from both sides of the equation.
10m=6010m = 60
This isolates the variable term by moving all constant values to the opposite side of the equation.
4
Divide both sides by 1010.
m=6m = 6
Dividing by the coefficient of the variable provides the final numerical solution for the unknown.

Anahtar Kavram

Translating a real-world scenario into a one-variable linear equation and isolating the variable to solve for an unknown value.
Tahmini Süre:1m 30s
Soru 5205Soru →

Which of the following values for mm makes the equation true?

35(10m−15)−4m=12(8m+14)−34 \frac{3}{5}(10m - 15) - 4m = \frac{1}{2}(8m + 14) - 34
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Cevap: 9

Cevap

The correct answer is 9.
The correct answer is found by properly executing the distributive property on both sides to clear the parentheses. On the left side, 3/5 is distributed to yield 6m - 9. On the right side, 1/2 is distributed to yield 4m + 7. After combining the remaining like terms, the equation simplifies to 2m - 9 = 4m - 27. Adding 27 and subtracting 2m from both sides gives 18 = 2m, which simplifies to m = 9.

Adım Adım Çözüm

1
Distribute the fractions into the parentheses on both sides of the equation.
6m−9−4m=4m+7−346m - 9 - 4m = 4m + 7 - 34
The distributive property must be applied first to expand the expressions and eliminate the parentheses.
2
Combine like terms on each side of the equal sign.
2m−9=4m−272m - 9 = 4m - 27
Simplifying each side individually makes it easier to isolate the variable in subsequent steps.
3
Subtract 2m from both sides.
−9=2m−27-9 = 2m - 27
This gathers all variable terms on one side of the equation.
4
Add 27 to both sides and divide the result by 2.
18=2m18 = 2m, which means m=9m = 9
This isolates the variable completely and provides the final solution.

Anahtar Kavram

Solving One-Variable Linear Equations
Tahmini Süre:1m 30s
Soru 5206Soru →

A technician calculates a load factor using the expression x2−2yx+2\frac{x^2 - 2y}{x + 2}. If the inputs are x=−4x = -4 and y=3y = 3, what is the resulting load factor?

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Cevap: -5

Cevap

The resulting load factor is -5.
Substituting x=−4x = -4 and y=3y = 3 into the numerator gives (−4)2−2(3)=16−6=10(-4)^2 - 2(3) = 16 - 6 = 10. Substituting x=−4x = -4 into the denominator gives −4+2=−2-4 + 2 = -2. Finally, dividing the numerator by the denominator yields 10/−2=−510 / -2 = -5.

Adım Adım Çözüm

1
Substitute the values x=−4x = -4 and y=3y = 3 into the numerator of the expression.
(−4)2−2(3)(-4)^2 - 2(3)
Variable substitution requires replacing the letters with their corresponding numerical values, using parentheses for negative numbers.
2
Evaluate the numerator following the standard order of operations.
16−6=1016 - 6 = 10
Squaring the negative integer −4-4 results in positive 1616. Multiplication (2×3=62 \times 3 = 6) must be performed before subtraction.
3
Substitute the value of xx into the denominator and evaluate.
−4+2=−2-4 + 2 = -2
Adding a positive integer to a negative integer reduces its absolute value while maintaining the negative sign.
4
Divide the evaluated numerator by the evaluated denominator.
10/−2=−510 / -2 = -5
A positive number divided by a negative number results in a negative quotient.

Anahtar Kavram

Evaluating rational algebraic expressions with negative integers
Soru 5207Soru →

Which of the following expressions is equivalent to the product of (5x−2)(5x - 2) and (x2−3x−4)(x^2 - 3x - 4)?

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Cevap: 5x3−17x2−14x+85x^3 - 17x^2 - 14x + 8

Cevap

The correct answer is 5x3−17x2−14x+85x^3 - 17x^2 - 14x + 8.
The correct expression is found by systematically distributing each term in the first polynomial to each term in the second. First, multiplying 5x5x by (x2−3x−4)(x^2 - 3x - 4) yields 5x3−15x2−20x5x^3 - 15x^2 - 20x. Next, multiplying −2-2 by (x2−3x−4)(x^2 - 3x - 4) yields −2x2+6x+8-2x^2 + 6x + 8. Finally, combining the like terms (−15x2-15x^2 and −2x2-2x^2 becomes −17x2-17x^2; −20x-20x and 6x6x becomes −14x-14x) results in the simplified polynomial 5x3−17x2−14x+85x^3 - 17x^2 - 14x + 8.

Adım Adım Çözüm

1
Distribute the first term of the binomial, 5x5x, to each term in the trinomial.
5x(x2−3x−4)=5x3−15x2−20x5x(x^2 - 3x - 4) = 5x^3 - 15x^2 - 20x
To expand the polynomials, every term in the first polynomial must be multiplied by every term in the second.
2
Distribute the second term of the binomial, −2-2, to each term in the trinomial.
−2(x2−3x−4)=−2x2+6x+8-2(x^2 - 3x - 4) = -2x^2 + 6x + 8
The second term, along with its negative sign, must also be multiplied by every term in the trinomial.
3
Add the results from Step 1 and Step 2 and combine like terms.
(5x3−15x2−20x)+(−2x2+6x+8)=5x3−17x2−14x+8(5x^3 - 15x^2 - 20x) + (-2x^2 + 6x + 8) = 5x^3 - 17x^2 - 14x + 8
Combining terms with the same variable to the same power fully simplifies the resulting polynomial.

Anahtar Kavram

Multiplying Polynomials using Distribution
Soru 5208Soru →

Solve the following equation for the variable nn:

2n−43=n+52\frac{2n - 4}{3} = \frac{n + 5}{2}

What is the correct value of nn?

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Cevap: 23

Cevap

The correct value for the variable is 23.
The correct value is 23, which is found by properly cross-multiplying the fractions, distributing the values to all terms in the numerators, and maintaining equality while isolating the variable.

Adım Adım Çözüm

1
Cross-multiply to eliminate the fractions.
2(2n−4)=3(n+5)2(2n - 4) = 3(n + 5)
Multiplying each side's numerator by the other side's denominator clears the fractions from the equation.
2
Distribute the constants on both sides of the equation.
4n−8=3n+154n - 8 = 3n + 15
Applying the distributive property removes the parentheses so like terms can be combined.
3
Subtract 3n3n from both sides.
n−8=15n - 8 = 15
This moves all variable terms to the left side of the equation to begin isolating nn.
4
Add 8 to both sides.
n=23n = 23
This isolates the variable nn to find the final solution.

Anahtar Kavram

Solving One-Variable Linear Equations
Tahmini Süre:1m 30s
Soru 5209Soru →

If −4(2n−3)=2n−3(3n+1)-4(2n - 3) = 2n - 3(3n + 1), what is the value of nn?

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Cevap: 15

Cevap

15
The equation correctly simplifies to -8n + 12 = -7n - 3 after proper distribution and combining of like terms. Isolating the variable by adding 8n and 3 to both sides yields n = 15.

Adım Adım Çözüm

1
Distribute the factors on both sides of the equation.
−8n+12=2n−9n−3-8n + 12 = 2n - 9n - 3
Multiplying the outside numbers across the terms inside the parentheses removes the grouping symbols.
2
Combine like terms on the right side.
−8n+12=−7n−3-8n + 12 = -7n - 3
Adding 2n2n and −9n-9n simplifies the right side to a single variable term.
3
Isolate the variable nn.
12+3=−7n+8n12 + 3 = -7n + 8n, which simplifies to 15=n15 = n
Moving all variable terms to one side and constant terms to the other side solves the equation.

Anahtar Kavram

Solving one-variable linear equations requiring distribution and combining like terms.
Soru 5210Soru →

Find the value of xx that satisfies the equation:

x−34+2x+13=5x6 \frac{x - 3}{4} + \frac{2x + 1}{3} = \frac{5x}{6}

Enter the exact value of xx.

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Cevap: 5

Cevap

5
By finding the least common denominator (12) and multiplying every term by it, the fractions are cleanly eliminated. After applying the distributive property and combining like terms (11x−5=10x11x - 5 = 10x), isolating the variable xx yields exactly 5.

Adım Adım Çözüm

1
Multiply all terms by the least common denominator (12).
12(x−34)+12(2x+13)=12(5x6)12 \left(\frac{x - 3}{4}\right) + 12 \left(\frac{2x + 1}{3}\right) = 12 \left(\frac{5x}{6}\right)
Multiplying by the LCD eliminates all fractions from the equation, simplifying further steps.
2
Simplify the resulting fractions.
3(x−3)+4(2x+1)=2(5x)3(x - 3) + 4(2x + 1) = 2(5x)
Dividing 12 by each respective denominator leaves an integer multiplier for the numerators.
3
Distribute the multipliers across the terms in the parentheses.
3x−9+8x+4=10x3x - 9 + 8x + 4 = 10x
The distributive property is required to remove the parentheses.
4
Combine like terms on the left side of the equation.
11x−5=10x11x - 5 = 10x
Grouping xx terms (3x+8x3x + 8x) and constant terms (−9+4-9 + 4) simplifies the expression.
5
Isolate the variable xx.
x=5x = 5
Subtracting 10x10x from both sides gives x−5=0x - 5 = 0. Adding 55 to both sides results in x=5x = 5.

Anahtar Kavram

Solving linear equations involving rational expressions by multiplying by a least common denominator.
Tahmini Süre:1m 30s
Soru 5211Soru →

A rectangular garden has a length of (3x−2)(3x - 2) meters and a width of (2x+5)(2x + 5) meters. Inside the garden, a smaller rectangular paved patio is built with a length of (x+4)(x + 4) meters and a width of 2x2x meters. Which of the following expressions represents the total area of the garden that is NOT paved, in square meters?

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Cevap: 4x2+3x−104x^2 + 3x - 10

Cevap

The expression representing the unpaved area is 4x2+3x−104x^2 + 3x - 10.
The correct answer is found by calculating the area of the entire garden and subtracting the area of the patio. First, multiply the dimensions of the garden using the distributive property (FOIL): (3x−2)(2x+5)=6x2+15x−4x−10=6x2+11x−10(3x - 2)(2x + 5) = 6x^2 + 15x - 4x - 10 = 6x^2 + 11x - 10. Next, find the area of the patio by distributing 2x2x: (x+4)(2x)=2x2+8x(x + 4)(2x) = 2x^2 + 8x. Finally, subtract the patio's area from the total area: (6x2+11x−10)−(2x2+8x)(6x^2 + 11x - 10) - (2x^2 + 8x). Make sure to distribute the negative sign to both terms in the second polynomial: 6x2+11x−10−2x2−8x=4x2+3x−106x^2 + 11x - 10 - 2x^2 - 8x = 4x^2 + 3x - 10.

Adım Adım Çözüm

1
Calculate the total area of the garden by multiplying its length and width.
(3x−2)(2x+5)=6x2+15x−4x−10=6x2+11x−10(3x - 2)(2x + 5) = 6x^2 + 15x - 4x - 10 = 6x^2 + 11x - 10
The area of a rectangle is found by multiplying its length by its width.
2
Calculate the area of the paved patio by multiplying its length and width.
(x+4)(2x)=2x2+8x(x + 4)(2x) = 2x^2 + 8x
We need the area of the inner rectangle in order to subtract it from the total area.
3
Subtract the patio's area from the total garden area to find the unpaved area.
(6x2+11x−10)−(2x2+8x)=6x2+11x−10−2x2−8x=4x2+3x−10(6x^2 + 11x - 10) - (2x^2 + 8x) = 6x^2 + 11x - 10 - 2x^2 - 8x = 4x^2 + 3x - 10
The unpaved region is the difference between the total area and the paved area. Note that the negative sign must be distributed to both terms in the second polynomial.

Anahtar Kavram

Multiplying Polynomials
Soru 5212Soru →

Determine the value of the missing coefficient by evaluating the problem below.

Aşağıdaki boşlukları doldurun

A rectangular solar panel has a length of (5k−4)(5k - 4) inches and a width of (3k+7)(3k + 7) inches. The area of the panel is represented by the fully expanded polynomial Ak2+Bk+CAk^2 + Bk + C square inches. The value of the coefficient BB is .
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Cevap

23
By multiplying the binomials (5k−4)(5k - 4) and (3k+7)(3k + 7), the expanded expression is 15k2+35k−12k−2815k^2 + 35k - 12k - 28. Combining the middle terms (35k−12k35k - 12k) yields 23k23k. Since the polynomial is in the standard form Ak2+Bk+CAk^2 + Bk + C, the value of BB is 23.

Adım Adım Çözüm

1
Set up the area calculation by multiplying the length and width binomials.
Area = (5k−4)(3k+7)(5k - 4)(3k + 7)
The area of a rectangle is found by multiplying its length by its width.
2
Distribute the terms using the FOIL method (First, Outer, Inner, Last).
15k2+35k−12k−2815k^2 + 35k - 12k - 28
Each term in the first binomial must be multiplied by each term in the second binomial.
3
Combine the like terms in the middle to find the value of BB.
15k2+23k−2815k^2 + 23k - 28
Adding 35k35k and −12k-12k simplifies the polynomial to the standard form Ak2+Bk+CAk^2 + Bk + C.
4
Identify the coefficient BB corresponding to the kk term.
B=23B = 23
The polynomial is 15k2+23k−2815k^2 + 23k - 28, so the coefficient of the kk term is 23.

Anahtar Kavram

Multiplying binomials and combining like terms to find a specific coefficient.
Soru 5213Soru →

Which of the following represents the fully simplified product of the polynomials (3a−2b)(3a - 2b) and (4a2+5ab−b2)(4a^2 + 5ab - b^2)?

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Cevap: 12a3+7a2b−13ab2+2b312a^3 + 7a^2b - 13ab^2 + 2b^3

Cevap

The fully simplified product is 12a3+7a2b−13ab2+2b312a^3 + 7a^2b - 13ab^2 + 2b^3.
The correct answer is obtained by distributing each term in the binomial to every term in the trinomial, and then combining the like terms. Multiplying 3a3a by each term yields 12a3+15a2b−3ab212a^3 + 15a^2b - 3ab^2. Multiplying −2b-2b by each term yields −8a2b−10ab2+2b3-8a^2b - 10ab^2 + 2b^3. Adding these together and combining the like terms (15a2b−8a2b=7a2b15a^2b - 8a^2b = 7a^2b and −3ab2−10ab2=−13ab2-3ab^2 - 10ab^2 = -13ab^2) results in the final expression.

Adım Adım Çözüm

1
Distribute the first term of the binomial, 3a3a, to every term in the trinomial.
3a(4a2)+3a(5ab)+3a(−b2)=12a3+15a2b−3ab23a(4a^2) + 3a(5ab) + 3a(-b^2) = 12a^3 + 15a^2b - 3ab^2
This applies the distributive property to begin multiplying the polynomials.
2
Distribute the second term of the binomial, −2b-2b, to every term in the trinomial.
−2b(4a2)−2b(5ab)−2b(−b2)=−8a2b−10ab2+2b3-2b(4a^2) - 2b(5ab) - 2b(-b^2) = -8a^2b - 10ab^2 + 2b^3
This completes the distribution process for all terms.
3
Write out the full expanded expression by combining the results from the previous steps.
12a3+15a2b−3ab2−8a2b−10ab2+2b312a^3 + 15a^2b - 3ab^2 - 8a^2b - 10ab^2 + 2b^3
This provides the complete polynomial before simplification.
4
Group and combine the like terms.
12a3+(15a2b−8a2b)+(−3ab2−10ab2)+2b3=12a3+7a2b−13ab2+2b312a^3 + (15a^2b - 8a^2b) + (-3ab^2 - 10ab^2) + 2b^3 = 12a^3 + 7a^2b - 13ab^2 + 2b^3
Combining terms with identical variable parts simplifies the expression to its final standard form.

Anahtar Kavram

Multiplying a binomial by a polynomial requires distributing every term in the first polynomial to every term in the second polynomial, carefully tracking negative signs, and then combining any like terms.
Tahmini Süre:1m 30s
Soru 5214Soru →

An engineer uses the formula V=V0−r×t+CV = V_0 - r \times t + C to calculate the final volume of fluid in a tank in liters. If the initial volume V0=12.4V_0 = 12.4, the rate r=2.5r = 2.5, the time t=3.2t = 3.2, and a correction factor C=4.8C = 4.8, what is the final volume VV?

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Cevap: 9.2

Cevap

9.2
To find the final volume, substitute the values into the formula to get 12.4−2.5×3.2+4.812.4 - 2.5 \times 3.2 + 4.8. According to the order of operations, the multiplication must be evaluated first: 2.5×3.2=8.02.5 \times 3.2 = 8.0. Substituting this back gives 12.4−8.0+4.812.4 - 8.0 + 4.8. Performing the remaining operations from left to right, first subtract (12.4−8.0=4.412.4 - 8.0 = 4.4), and then add (4.4+4.8=9.24.4 + 4.8 = 9.2).

Adım Adım Çözüm

1
Substitute the given values into the formula.
V=12.4−2.5×3.2+4.8V = 12.4 - 2.5 \times 3.2 + 4.8
This sets up the arithmetic expression that needs to be evaluated.
2
Apply the order of operations (PEMDAS) by performing the multiplication first.
2.5×3.2=8.02.5 \times 3.2 = 8.0
Multiplication takes precedence over addition and subtraction.
3
Rewrite the expression with the product and perform the subtraction (working left to right).
12.4−8.0=4.412.4 - 8.0 = 4.4
Addition and subtraction are evaluated from left to right in the order they appear.
4
Perform the final addition step.
4.4+4.8=9.24.4 + 4.8 = 9.2
This yields the final evaluated volume.

Anahtar Kavram

Applying the order of operations (PEMDAS) to expressions containing decimals, ensuring proper place-value alignment during addition and subtraction.
Soru 5215Soru →

Calculate the value of ww in the given linear equation:

Aşağıdaki boşlukları doldurun

3(2w+5)−4w=5(w−1)+2 3(2w + 5) - 4w = 5(w - 1) + 2

Value of ww:
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Cevap

The correct value for the variable is 6.
The correct answer is 6. Applying the distributive property to both sides simplifies the equation to 6w+15−4w=5w−5+26w + 15 - 4w = 5w - 5 + 2. Grouping like terms on each side yields 2w+15=5w−32w + 15 = 5w - 3. Subtracting 2w2w from both sides and adding 33 to both sides results in 18=3w18 = 3w. Dividing both sides by 3 isolates the variable, giving w=6w = 6.

Adım Adım Çözüm

1
Distribute the constants across the terms inside the parentheses on both sides.
6w+15−4w=5w−5+26w + 15 - 4w = 5w - 5 + 2
To eliminate the parentheses and expose all terms for simplification.
2
Combine the like terms on each side of the equation independently.
2w+15=5w−32w + 15 = 5w - 3
To simplify both expressions before manipulating terms across the equals sign.
3
Move all variable terms to one side of the equation.
Subtract 2w2w from both sides to obtain 15=3w−315 = 3w - 3.
To group all the terms containing ww together and avoid negative coefficients.
4
Isolate the variable term and solve for ww.
Add 3 to both sides to get 18=3w18 = 3w, then divide by 3 to find w=6w = 6.
To determine the final numerical value of the variable.

Anahtar Kavram

Solving multi-step linear equations utilizing the distributive property and combining like terms.
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