Ohm's Law Calculations and Concepts

29 soru

Soru 21Soru →

An automotive technician tests a fuel level sensor module connected to a 12 V12\text{ V} direct current (DC) supply. An in-line digital multimeter measures a steady current flow of 15 mA15\text{ mA} through the module. What is the electrical resistance of the sensor module?

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Cevap: 800 Ω800\text{ }\Omega

Cevap

The electrical resistance of the sensor module is 800 Ω800\text{ }\Omega.
According to Ohm's law, resistance equals voltage divided by current (R=VIR = \frac{V}{I}). Converting 15 mA15\text{ mA} to amperes gives 0.015 A0.015\text{ A}. Dividing 12 V12\text{ V} by 0.015 A0.015\text{ A} yields 800 Ω800\text{ }\Omega.

Adım Adım Çözüm

1
Convert the measured current from milliamperes (mA) to the base SI unit amperes (A).
I=15 mA=15×10−3 A=0.015 AI = 15\text{ mA} = 15 \times 10^{-3}\text{ A} = 0.015\text{ A}
Standard electrical formulas require quantities in base units (volts, amperes, ohms).
2
State Ohm's law rearranged to solve for resistance (RR).
R=VIR = \frac{V}{I}
Resistance equals electromotive force (voltage) divided by current flow.
3
Substitute the given values into the formula and calculate the resistance.
R=12 V0.015 A=1200015 Ω=800 ΩR = \frac{12\text{ V}}{0.015\text{ A}} = \frac{12000}{15}\text{ }\Omega = 800\text{ }\Omega
Dividing 12 V12\text{ V} by 0.015 A0.015\text{ A} yields the total circuit resistance in ohms.

Anahtar Kavram

Ohm's Law (V=I×RV = I \times R) defines the relationship between voltage, current, and resistance in a DC circuit.
Tahmini Süre:45s
Soru 22Soru →

A marine communications transceiver utilizes a direct current (DC) bias network. A voltmeter connected across a fixed 2.5 kΩ2.5\text{ k}\Omega resistor measures a steady voltage drop of 15 V15\text{ V}. What is the current flowing through this resistor?

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Cevap: 6 mA6\text{ mA}

Cevap

The current flowing through the resistor is 6 mA6\text{ mA}.
According to Ohm's law, current equals voltage divided by resistance (I=V/RI = V / R). Dividing 15 V15\text{ V} by 2.5 kΩ2.5\text{ k}\Omega (2500 Ω2500\text{ }\Omega) yields 0.006 A0.006\text{ A}, which converts directly to 6 mA6\text{ mA}.

Adım Adım Çözüm

1
Convert the given resistance from kilo-ohms to fundamental SI units (ohms).
R=2.5 kΩ=2.5×103 Ω=2500 ΩR = 2.5\text{ k}\Omega = 2.5 \times 10^3\text{ }\Omega = 2500\text{ }\Omega
Standard calculations in Ohm's law require values in fundamental units (volts, amperes, ohms).
2
Apply Ohm's law formula to solve for current (I=V/RI = V / R).
I=15 V2500 Ω=0.006 AI = \frac{15\text{ V}}{2500\text{ }\Omega} = 0.006\text{ A}
Current is directly proportional to voltage and inversely proportional to resistance.
3
Convert the resulting current from amperes to milliamperes.
0.006 A=0.006×1000 mA=6 mA0.006\text{ A} = 0.006 \times 1000\text{ mA} = 6\text{ mA}
Matching the standard unit formatting in electronic measurement options.

Anahtar Kavram

Ohm's Law expresses the fundamental relationship between voltage, current, and resistance in a DC circuit (I=V/RI = V / R).
Tahmini Süre:1m 0s
Soru 23Soru →

An industrial temperature sensor module with a calibrated internal resistance of 4.5 kΩ4.5\text{ k}\Omega draws a steady direct current of 8 mA8\text{ mA} during normal operation. What is the voltage drop across the sensor module in volts (V\text{V})?

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Cevap: 36

Cevap

The voltage drop across the sensor module is 36 V36\text{ V}.
According to Ohm's Law, voltage (VV) equals current (II) multiplied by resistance (RR). Given I=8 mA=0.008 AI = 8\text{ mA} = 0.008\text{ A} and R=4.5 kΩ=4500 ΩR = 4.5\text{ k}\Omega = 4500\text{ }\Omega, the calculation is V=0.008 A×4500 Ω=36 VV = 0.008\text{ A} \times 4500\text{ }\Omega = 36\text{ V}.

Adım Adım Çözüm

1
Convert the given metric prefixes to standard base units (amperes and ohms).
I=8 mA=8×10−3 A=0.008 AI = 8\text{ mA} = 8 \times 10^{-3}\text{ A} = 0.008\text{ A} and R=4.5 kΩ=4.5×103 Ω=4500 ΩR = 4.5\text{ k}\Omega = 4.5 \times 10^{3}\text{ }\Omega = 4500\text{ }\Omega
Ohm's law requires fundamental SI units (volts, amperes, and ohms) for accurate mathematical evaluation.
2
Select the appropriate form of Ohm's Law to calculate voltage (VV).
V=I×RV = I \times R
Voltage across a resistive load equals the product of the current flowing through it and its resistance.
3
Substitute the converted values into the formula and solve.
V=0.008 A×4500 Ω=36 VV = 0.008\text{ A} \times 4500\text{ }\Omega = 36\text{ V}
Multiplying 8×10−3 A8 \times 10^{-3}\text{ A} by 4.5×103 Ω4.5 \times 10^{3}\text{ }\Omega simplifies directly to 8×4.5=36 V8 \times 4.5 = 36\text{ V} because the metric prefixes milli (10−310^{-3}) and kilo (10310^{3}) cancel each other.

Anahtar Kavram

Ohm's Law: Voltage Calculation (V=I×RV = I \times R)

Alternatif Yöntem

Recognize that the prefix multiplier milli- (10−310^{-3}) and kilo- (10310^{3}) cancel out when multiplied together: (8 mA)×(4.5 kΩ)=8×4.5 V=36 V(8\text{ mA}) \times (4.5\text{ k}\Omega) = 8 \times 4.5\text{ V} = 36\text{ V}.
Tahmini Süre:1m 0s
Soru 24Soru →

An avionics technician tests a direct current (DC) relay control circuit connected to a 36 V36\text{ V} power supply. An in-line ammeter indicates that the relay coil draws a steady current of 75 mA75\text{ mA}. What is the total electrical resistance of the relay coil?

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Cevap: 480 Ω480\text{ }\Omega

Cevap

The total electrical resistance of the relay coil is 480 Ω480\text{ }\Omega.
According to Ohm's Law, resistance is determined by dividing voltage by current (R=VIR = \frac{V}{I}). First, converting the current from milliamperes to amperes gives 75 mA=0.075 A75\text{ mA} = 0.075\text{ A}. Dividing the 36 V36\text{ V} supply by 0.075 A0.075\text{ A} yields a resistance of 480 Ω480\text{ }\Omega.

Adım Adım Çözüm

1
Convert the measured current from milliamperes to base amperes.
I=75 mA=75×10−3 A=0.075 AI = 75\text{ mA} = 75 \times 10^{-3}\text{ A} = 0.075\text{ A}
Standard electrical calculations using Ohm's law require values to be expressed in base SI units (volts, amperes, and ohms).
2
Apply Ohm's law rearranged to solve for resistance (R=VIR = \frac{V}{I}).
R=36 V0.075 A=480 ΩR = \frac{36\text{ V}}{0.075\text{ A}} = 480\text{ }\Omega
Resistance equals electromotive force (voltage) divided by current flow.

Anahtar Kavram

Calculating resistance in a DC circuit using Ohm's Law with metric prefix conversion.
Tahmini Süre:1m 0s
Soru 25Soru →

A technician is servicing an off-grid solar telemetry station and measures the operating parameters of four distinct direct current (DC) load circuits. Match each circuit description on the left with its corresponding calculated electrical quantity on the right using Ohm's law.

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Öğeler

A 24 V24\text{ V} cooling fan circuit with a measured internal resistance of 120 Ω120\text{ }\Omega
A 48 V48\text{ V} remote sensor beacon drawing a steady current of 16 mA16\text{ mA}
An environmental heating strip drawing 2.5 A2.5\text{ A} when supplied with 15 V15\text{ V}
A backup LED indicator branch drawing 50 mA50\text{ mA} through a 180 Ω180\text{ }\Omega resistor

Eşleşmeler

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Cevap

The 24 V24\text{ V} fan at 120 Ω120\text{ }\Omega matches 0.20 A0.20\text{ A}; the 48 V48\text{ V} beacon at 16 mA16\text{ mA} matches 3.0 kΩ3.0\text{ k}\Omega; the 15 V15\text{ V} heater drawing 2.5 A2.5\text{ A} matches 6.0 Ω6.0\text{ }\Omega; and the 50 mA50\text{ mA} indicator across 180 Ω180\text{ }\Omega matches 9.0 V9.0\text{ V}.
Each match correctly applies the appropriate algebraic variation of Ohm's law (V=I×RV = I \times R, I=VRI = \frac{V}{R}, or R=VIR = \frac{V}{I}) while properly converting metric units (1 mA=0.001 A1\text{ mA} = 0.001\text{ A} and 1 kΩ=1000 Ω1\text{ k}\Omega = 1000\text{ }\Omega).

Adım Adım Çözüm

1
Calculate the current for the cooling fan circuit
I=VR=24 V120 Ω=0.20 AI = \frac{V}{R} = \frac{24\text{ V}}{120\text{ }\Omega} = 0.20\text{ A}
Ohm's law defines current as voltage divided by resistance.
2
Calculate the resistance for the remote sensor beacon
R=VI=48 V0.016 A=3000 Ω=3.0 kΩR = \frac{V}{I} = \frac{48\text{ V}}{0.016\text{ A}} = 3000\text{ }\Omega = 3.0\text{ k}\Omega
Convert milliamperes to amperes (16 mA=0.016 A16\text{ mA} = 0.016\text{ A}) and solve for resistance by dividing voltage by current.
3
Calculate the resistance for the environmental heating strip
R=VI=15 V2.5 A=6.0 ΩR = \frac{V}{I} = \frac{15\text{ V}}{2.5\text{ A}} = 6.0\text{ }\Omega
Ohm's law defines resistance as voltage divided by current.
4
Calculate the voltage for the backup LED indicator branch
V=I×R=0.050 A×180 Ω=9.0 VV = I \times R = 0.050\text{ A} \times 180\text{ }\Omega = 9.0\text{ V}
Convert milliamperes to amperes (50 mA=0.050 A50\text{ mA} = 0.050\text{ A}) and calculate voltage by multiplying current by resistance.

Anahtar Kavram

Ohm's Law states the fundamental relationship between voltage, current, and resistance in a direct current circuit: V=I×RV = I \times R, I=VRI = \frac{V}{R}, and R=VIR = \frac{V}{I}.
Tahmini Süre:1m 15s
Soru 26Soru →

An HVAC technician is testing a motorized zone damper actuator powered by a 24 V24\text{ V} direct current (DC) power supply. An ammeter connected in series measures a current draw of 400 mA400\text{ mA} through the actuator coil. What is the electrical resistance of the actuator coil?

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Cevap: 60 Ω60\text{ }\Omega

Cevap

The electrical resistance of the damper actuator coil is 60 Ω60\text{ }\Omega.
According to Ohm's Law, resistance is calculated by dividing the voltage across the component by the current flowing through it (R=VIR = \frac{V}{I}). Converting 400 mA400\text{ mA} to amperes yields 0.4 A0.4\text{ A}. Dividing 24 V24\text{ V} by 0.4 A0.4\text{ A} gives 60 Ω60\text{ }\Omega.

Adım Adım Çözüm

1
Convert the measured current from milliamperes (mA) to base amperes (A)
I=400 mA=4001000 A=0.4 AI = 400\text{ mA} = \frac{400}{1000}\text{ A} = 0.4\text{ A}
Standard electrical calculations using Ohm's Law require current to be expressed in amperes.
2
State and apply the Ohm's Law formula solved for resistance (RR)
R=VIR = \frac{V}{I}
Resistance equals electromotive force (voltage) divided by current.
3
Substitute the known values and calculate the resistance
R=24 V0.4 A=60 ΩR = \frac{24\text{ V}}{0.4\text{ A}} = 60\text{ }\Omega
Dividing 2424 by 0.40.4 gives the coil resistance in ohms.

Anahtar Kavram

Ohm's Law (R=VIR = \frac{V}{I}) and metric prefix conversion
Tahmini Süre:1m 0s
Soru 27Soru →

A technician is testing a direct current (DC) cooling fan motor installed in an equipment rack. When powered by a 48 V48\text{ V} DC supply, the motor draws a steady current of 250 mA250\text{ mA}. What is the electrical resistance of the cooling fan motor in ohms (Ω\Omega)?

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Cevap: 192

Cevap

The electrical resistance of the cooling fan motor is 192 Ω192\text{ }\Omega.
According to Ohm's law, resistance is found by dividing voltage by current (R=VIR = \frac{V}{I}). Converting 250 mA250\text{ mA} to 0.25 A0.25\text{ A} and dividing 48 V48\text{ V} by 0.25 A0.25\text{ A} gives exactly 192 Ω192\text{ }\Omega.

Adım Adım Çözüm

1
Convert the current from milliamperes to amperes
I=250 mA=0.25 AI = 250\text{ mA} = 0.25\text{ A}
Ohm's law calculations require current to be expressed in the base SI unit of amperes.
2
Calculate resistance using Ohm's law formula (R=VIR = \frac{V}{I})
R=48 V0.25 A=192 ΩR = \frac{48\text{ V}}{0.25\text{ A}} = 192\text{ }\Omega
Dividing the supply voltage by the total circuit current yields the resistance in ohms.

Anahtar Kavram

Calculating resistance using Ohm's law (R=VIR = \frac{V}{I}) combined with metric prefix conversion from milliamperes to amperes.
Tahmini Süre:1m 0s
Soru 28Soru →

An automated assembly fixture uses an industrial direct current (DC) solenoid valve to actuate a pneumatic clamp. The solenoid coil has an internal resistance of 600 Ω600\text{ }\Omega and requires a steady current of 35 mA35\text{ mA} to operate reliably. What DC voltage must the power supply deliver to the solenoid valve?

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Cevap: 21 V21\text{ V}

Cevap

21 V21\text{ V}
According to Ohm's Law, voltage is calculated by multiplying current by resistance (V=I×RV = I \times R). Converting the current from milliamperes to amperes gives 35 mA=0.035 A35\text{ mA} = 0.035\text{ A}. Multiplying 0.035 A×600 Ω0.035\text{ A} \times 600\text{ }\Omega results in 21 V21\text{ V}.

Adım Adım Çözüm

1
Convert the operating current from milliamperes (mA\text{mA}) to base amperes (A\text{A}).
35 mA=351,000 A=0.035 A35\text{ mA} = \frac{35}{1,000}\text{ A} = 0.035\text{ A}
Ohm's Law calculations require electrical quantities in standard SI base units.
2
Apply Ohm's Law (V=I×RV = I \times R) to find the required supply voltage.
V=0.035 A×600 Ω=21 VV = 0.035\text{ A} \times 600\text{ }\Omega = 21\text{ V}
Voltage equals the product of current and resistance.

Anahtar Kavram

Ohm's Law (V=I×RV = I \times R) with metric prefix conversion
Tahmini Süre:1m 0s
Soru 29Soru →

A technician is troubleshooting an industrial robotics controller that delivers direct current (DC) to a solid-state indicator module. The module has an internal resistance of 1.5 kΩ1.5\text{ k}\Omega. When the circuit is energized, a voltmeter measures a potential difference of 24 V24\text{ V} across the module. What is the current flowing through the indicator module?

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Cevap: 16 mA16\text{ mA}

Cevap

The current flowing through the indicator module is 16 mA16\text{ mA}.
According to Ohm's Law, current equals voltage divided by resistance (I=VRI = \frac{V}{R}). Converting the resistance of 1.5 kΩ1.5\text{ k}\Omega to base ohms gives 1500 Ω1{}500\text{ }\Omega. Dividing the voltage of 24 V24\text{ V} by 1500 Ω1{}500\text{ }\Omega yields 0.016 A0.016\text{ A}, which converts to 16 mA16\text{ mA}.

Adım Adım Çözüm

1
Convert the resistance from kilo-ohms to base ohms
R=1.5 kΩ=1.5×103 Ω=1500 ΩR = 1.5\text{ k}\Omega = 1.5 \times 10^3\text{ }\Omega = 1{}500\text{ }\Omega
Standard electrical calculations using Ohm's Law require values in fundamental SI units (volts, amperes, ohms).
2
Apply Ohm's Law to calculate the current in amperes
I=VR=24 V1500 Ω=0.016 AI = \frac{V}{R} = \frac{24\text{ V}}{1{}500\text{ }\Omega} = 0.016\text{ A}
Ohm's Law states that current equals electromotive force (voltage) divided by resistance.
3
Convert the resulting current from amperes to milliamperes
I=0.016 A×1000 mA/A=16 mAI = 0.016\text{ A} \times 1{}000\text{ mA/A} = 16\text{ mA}
Expressing fractional amperes in milliamperes aligns with standard instrumentation and option specifications.

Anahtar Kavram

Ohm's Law (I=VRI = \frac{V}{R}) and metric prefix conversion (kilo- and milli-).
Tahmini Süre:1m 0s
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