Electricity and Magnetism

16 soru

Soru 1Soru →

Understanding magnetic behaviors and electromagnetic interactions is fundamental in physical science. Match each magnetic concept on the left with its correct scientific description on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Ferromagnetic substance
Magnetic domain
Magnetic field lines
Electromagnetic induction

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Ferromagnetic substance matches the material strongly attracted to magnets and easily magnetized; Magnetic domain matches the microscopic region where atomic magnetic fields are aligned; Magnetic field lines match the lines of force mapping direction and strength from north to south; and Electromagnetic induction matches the process of generating an electric current via a changing magnetic field.
Each physical concept is paired with its precise scientific description: ferromagnetic substances describe materials like iron and nickel that exhibit strong magnetic attraction; magnetic domains are the microscopic aligned clusters of atomic dipoles; magnetic field lines map the invisible field geometry from north to south; and electromagnetic induction refers to current generation induced by a changing magnetic environment.

Adım Adım Çözüm

1
Identify the definition of a ferromagnetic substance
Matches the description of a material such as iron or nickel that is strongly attracted to magnets and can be magnetized
Ferromagnetism is the basic mechanism by which certain materials form permanent magnets or are attracted to magnets.
2
Identify the definition of a magnetic domain
Matches the description of a microscopic region within a solid where atomic magnetic fields are aligned
Domains are localized zones of uniform magnetic orientation within ferromagnetic materials.
3
Identify the definition of magnetic field lines
Matches the description of continuous lines of force emerging from north and entering south to indicate direction and strength
Field lines visually communicate the direction of the magnetic force and its magnitude through line spacing.
4
Identify the definition of electromagnetic induction
Matches the description of the process of generating an electric current in a conductor via a changing magnetic field
Relative movement between a magnetic field and a conductor produces an induced current.

Anahtar Kavram

Core concepts of magnetism, magnetic domains, field mapping, and electromagnetic induction
Tahmini Süre:1m 0s
Soru 2Soru →

An electrical circuit in an automated test bench connects a 24 V24\text{ V} direct-current power supply to two 12 Ω12\,\Omega heating elements arranged in parallel. What is the total electric current delivered by the power supply to the entire circuit?

Cevabı ve açıklamayı göster

Cevap: 4 A4\text{ A}

Cevap

4 A4\text{ A}
In a parallel circuit with two identical 12 Ω12\,\Omega loads, the total equivalent resistance is halved to 6 Ω6\,\Omega. By Ohm's law (I=VRI = \frac{V}{R}), the total current drawn from the 24 V24\text{ V} source is 24 V6 Ω=4 A\frac{24\text{ V}}{6\,\Omega} = 4\text{ A}. Alternatively, each branch draws 24 V12 Ω=2 A\frac{24\text{ V}}{12\,\Omega} = 2\text{ A}, yielding a total current of 2 A+2 A=4 A2\text{ A} + 2\text{ A} = 4\text{ A}.

Adım Adım Çözüm

1
Calculate the equivalent resistance of the two identical resistors connected in parallel.
Req=12 Ω2=6 ΩR_{\text{eq}} = \frac{12\,\Omega}{2} = 6\,\Omega
When identical resistors are in parallel, the equivalent resistance equals the resistance of one branch divided by the total number of branches.
2
Apply Ohm's law (I=VReqI = \frac{V}{R_{\text{eq}}}) using the total source voltage and equivalent resistance.
Itotal=24 V6 Ω=4 AI_{\text{total}} = \frac{24\text{ V}}{6\,\Omega} = 4\text{ A}
Ohm's law defines the relationship between total circuit voltage, equivalent resistance, and total current.

Anahtar Kavram

Parallel circuit resistance and Ohm's law
Tahmini Süre:1m 0s
Soru 3Soru →

A ceramic space heater is connected to a standard 120 V120\text{ V} electrical outlet. If the heating element has an internal resistance of 15 Ω15\,\Omega, what is the electric current flowing through the circuit, in amperes (A\text{A})?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

8 A
According to Ohm's Law (V=IRV = IR), the electric current (II) flowing through a circuit is found by dividing the potential difference (VV) by the resistance (RR). Dividing 120 V120\text{ V} by 15 Ω15\,\Omega gives an electric current of 8 A8\text{ A}.

Adım Adım Çözüm

1
Identify the given electrical values from the problem statement.
Voltage V=120 VV = 120\text{ V} and resistance R=15 ΩR = 15\,\Omega.
Determining known quantities is required to choose the appropriate formula.
2
State Ohm's Law and isolate current (II).
I=VRI = \frac{V}{R}
Ohm's Law governs the relationship between potential difference, current, and resistance in an electrical circuit.
3
Divide voltage by resistance to calculate the current in amperes.
I=120 V15 Ω=8 AI = \frac{120\text{ V}}{15\,\Omega} = 8\text{ A}
Carrying out the arithmetic yields the resulting current in amperes.

Anahtar Kavram

Ohm's Law (V=IRV = IR) defines the relationship among voltage, current, and resistance, where current is directly proportional to voltage and inversely proportional to resistance.
Tahmini Süre:1m 0s
Soru 4Soru →

An emergency backup lighting system connects three identical 15 Ω15\,\Omega indicator lamps in series across a 45 V45\text{ V} direct-current power source. What is the electric current flowing through each lamp?

Cevabı ve açıklamayı göster

Cevap: 1.0 A1.0\text{ A}

Cevap

1.0 A1.0\text{ A}
In a series circuit, the total electrical resistance is the sum of all individual resistances in the path: Rtotal=15 Ω+15 Ω+15 Ω=45 ΩR_{\text{total}} = 15\,\Omega + 15\,\Omega + 15\,\Omega = 45\,\Omega. Applying Ohm's law (I=VRI = \frac{V}{R}), the current drawn from the 45 V45\text{ V} source is I=45 V45 Ω=1.0 AI = \frac{45\text{ V}}{45\,\Omega} = 1.0\text{ A}. In any series circuit, the electric current is identical at every point, meaning exactly 1.0 A1.0\text{ A} flows through each lamp.

Adım Adım Çözüm

1
Calculate the total equivalent resistance of the series circuit.
Rtotal=15 Ω+15 Ω+15 Ω=45 ΩR_{\text{total}} = 15\,\Omega + 15\,\Omega + 15\,\Omega = 45\,\Omega
In a series circuit, the total electrical resistance equals the direct sum of all individual resistances.
2
Apply Ohm's law to determine the total circuit current.
I=VRtotal=45 V45 Ω=1.0 AI = \frac{V}{R_{\text{total}}} = \frac{45\text{ V}}{45\,\Omega} = 1.0\text{ A}
Current is calculated by dividing total source voltage by the total resistance of the circuit.
3
Determine the current flowing through each individual lamp.
Ilamp=1.0 AI_{\text{lamp}} = 1.0\text{ A}
Because there is only one continuous path for electrical charge in a series circuit, the current is uniform through all components.

Anahtar Kavram

Ohm's law and total resistance in series circuits
Tahmini Süre:1m 0s
Soru 5Soru →

Electrical circuits and power distribution systems utilize specialized components to regulate, convert, and protect electrical energy. Which functional description correctly matches each electrical component?

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Fuse
Transformer
Capacitor
Diode

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The correct pairings match Fuse with interrupting excessive current by melting a sacrificial strip, Transformer with altering alternating-current voltage levels through electromagnetic induction, Capacitor with storing separated electric charge across an insulating dielectric layer, and Diode with restricting current flow primarily to a single direction.
Each component is correctly paired with its defining physical mechanism: a fuse provides overcurrent protection by melting its internal element; a transformer modulates AC voltage via mutual electromagnetic induction; a capacitor accumulates electrostatic charge across separated plates; and a diode rectifies or guides current in a single direction.

Adım Adım Çözüm

1
Identify the protective mechanism of a fuse.
A fuse contains a thin wire designed to melt under overcurrent conditions, matching the description of interrupting excessive current by melting a sacrificial strip.
Fuses protect wiring and equipment from dangerous current overloads and short circuits.
2
Identify the electromagnetic function of a transformer.
A transformer transfers energy between AC circuits through mutual magnetic flux, matching the description of altering AC voltage levels through electromagnetic induction.
Transformers rely on changing magnetic fields produced by alternating current to induce voltage across windings.
3
Identify the electrostatic storage mechanism of a capacitor.
A capacitor holds electrostatic charge on opposing plates separated by a dielectric, matching the description of accumulating and storing separated electric charge.
Capacitors maintain potential difference by holding static charge rather than dissipating or converting it.
4
Identify the unidirectional conducting property of a diode.
A diode conducts forward-bias current while blocking reverse-bias current, matching the description of restricting current flow to a single direction.
Diodes are fundamental semiconductor components used in rectification and polarity protection.

Anahtar Kavram

Functional characteristics and operating principles of fundamental electrical circuit components
Tahmini Süre:1m 0s
Soru 6Soru →

A remote weather-monitoring station is powered by a 36 V36\text{ V} direct-current solar battery bank. Two identical communication transmitters are connected in parallel across the power terminals. If the monitoring station draws a total current of 4 A4\text{ A} when both transmitters are operating simultaneously, what is the electrical resistance of each individual transmitter?

Cevabı ve açıklamayı göster

Cevap: 18 Ω18\,\Omega

Cevap

The electrical resistance of each individual transmitter is 18 Ω18\,\Omega.
In a parallel circuit, each identical branch draws an equal share of the total current. With a total current of 4 A4\text{ A} split evenly across two identical paths, each transmitter draws 2 A2\text{ A}. Applying Ohm's law (R=VIR = \frac{V}{I}) across one branch with the full 36 V36\text{ V} potential difference yields R=36 V2 A=18 ΩR = \frac{36\text{ V}}{2\text{ A}} = 18\,\Omega.

Adım Adım Çözüm

1
Calculate the total equivalent resistance of the parallel circuit using Ohm's Law.
Req=VItotal=36 V4 A=9 ΩR_{\text{eq}} = \frac{V}{I_{\text{total}}} = \frac{36\text{ V}}{4\text{ A}} = 9\,\Omega
The total resistance of the entire circuit relates the total supply voltage to the total current drawn from the battery bank.
2
Determine the resistance of each individual transmitter from the parallel combination formula.
1Req=1R+1R=2R  ⟹  R=2×Req=2×9 Ω=18 Ω\frac{1}{R_{\text{eq}}} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R} \implies R = 2 \times R_{\text{eq}} = 2 \times 9\,\Omega = 18\,\Omega
When two identical resistors are connected in parallel, their equivalent resistance is equal to half the resistance of a single component.

Anahtar Kavram

Ohm's law and equivalent resistance in parallel circuits

Alternatif Yöntem

Determine the current per branch directly: because the two transmitters are identical and in parallel across the 36 V36\text{ V} source, each receives the full supply voltage and carries half the total current (Ibranch=4 A2=2 AI_{\text{branch}} = \frac{4\text{ A}}{2} = 2\text{ A}). Then apply Ohm's law directly to a single branch: R=VIbranch=36 V2 A=18 ΩR = \frac{V}{I_{\text{branch}}} = \frac{36\text{ V}}{2\text{ A}} = 18\,\Omega.
Tahmini Süre:1m 0s
Soru 7Soru →

A workshop exhaust fan is connected to a 120 V120\text{ V} power supply and consumes 480 W480\text{ W} of electric power during normal operation. What is the effective electrical resistance of the fan motor, in ohms (Ω\Omega)?

Cevabı ve açıklamayı göster

Cevap: 30

Cevap

The effective electrical resistance of the fan motor is 30 Ω30\,\Omega.
To find the resistance from voltage and power, determine the current using I=PV=480 W120 V=4 AI = \frac{P}{V} = \frac{480\text{ W}}{120\text{ V}} = 4\text{ A}, then use Ohm's law R=VI=120 V4 A=30 ΩR = \frac{V}{I} = \frac{120\text{ V}}{4\text{ A}} = 30\,\Omega. Alternatively, using R=V2PR = \frac{V^2}{P} yields 1202480=14400480=30 Ω\frac{120^2}{480} = \frac{14400}{480} = 30\,\Omega.

Adım Adım Çözüm

1
Calculate the electric current flowing through the fan motor using the electrical power formula P=V×IP = V \times I.
I=PV=480 W120 V=4 AI = \frac{P}{V} = \frac{480\text{ W}}{120\text{ V}} = 4\text{ A}
Electric power equals the product of voltage and current, so dividing total wattage by applied voltage determines circuit current.
2
Calculate the resistance using Ohm's law rearranged as R=VIR = \frac{V}{I}.
R=120 V4 A=30 ΩR = \frac{120\text{ V}}{4\text{ A}} = 30\,\Omega
Resistance represents the opposition to current flow and is found by dividing the applied voltage by the circuit current.

Anahtar Kavram

Relationship between electrical power (P=IVP = IV) and Ohm's law (V=IRV = IR)
Tahmini Süre:1m 0s
Soru 8Soru →

In an industrial facility, three identical light fixtures are connected in parallel across a constant 120 V120\text{ V} electrical line. If one of the light fixtures burns out and creates an open circuit in its branch, what will happen to the remaining light fixtures and the total current drawn from the line?

Cevabı ve açıklamayı göster

Cevap: The remaining fixtures stay lit at the same brightness, and the total current drawn from the line decreases.

Cevap

The remaining fixtures stay lit at the same brightness, and the total current drawn from the line decreases.
In a parallel circuit, each device is connected across the full source voltage independently. When one fixture burns out, the voltage across the remaining fixtures remains at 120 V120\text{ V}, so their current and brightness stay the same. However, because the total current is the sum of the branch currents (Itotal=I1+I2+I3I_{\text{total}} = I_1 + I_2 + I_3), losing one branch reduces the total current supplied by the line from three branch currents down to two.

Adım Adım Çözüm

1
Analyze voltage across individual branches in a parallel circuit
Each remaining fixture continues to experience the full 120 V120\text{ V} line voltage.
In a parallel circuit, every branch is connected directly across the power source, so removing or opening one branch does not alter the voltage applied to the others.
2
Determine current and power dissipation for each remaining fixture
Individual current I=VRI = \frac{V}{R} and power P=V2RP = \frac{V^2}{R} remain constant, keeping brightness unchanged.
Since both the resistance of each remaining fixture and the supply voltage remain unchanged, the power output of each active lamp does not change.
3
Calculate the effect on total circuit current
Total current drops from Itotal=3IbranchI_{\text{total}} = 3I_{\text{branch}} to Itotal=2IbranchI_{\text{total}} = 2I_{\text{branch}}.
Total current in a parallel circuit is the sum of the individual branch currents (Itotal=I1+I2+I3I_{\text{total}} = I_1 + I_2 + I_3). When one branch opens, its current drops to zero, reducing the total current drawn from the supply.

Anahtar Kavram

Parallel Circuit Branch Independence and Current Summation
Tahmini Süre:1m 0s
Soru 9Soru →

In the analysis of direct-current electrical circuits, fundamental physical quantities define how electrical energy is stored, transported, and dissipated. Match each electrical quantity on the left with its correct physical definition on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Electric Current
Voltage (Electric Potential Difference)
Electrical Resistance
Electrical Power

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Electric Current matches 'The rate at which electric charge flows through a cross-sectional area of a conductor over time'; Voltage (Electric Potential Difference) matches 'The amount of electric potential energy delivered or work done per unit of electric charge'; Electrical Resistance matches 'The measure of a material's opposition to the passage of electric charge'; Electrical Power matches 'The rate at which electrical energy is transferred, converted, or dissipated per unit of time'.
Each term corresponds directly to its foundational physical definition in electromagnetism: Electric Current is the rate of charge flow (I=ΔQΔtI = \frac{\Delta Q}{\Delta t}), Voltage is the work/energy per unit charge (V=WQV = \frac{W}{Q}), Resistance is the opposition to charge movement (R=VIR = \frac{V}{I}), and Electrical Power is the time rate of total energy transfer (P=VIP = VI).

Adım Adım Çözüm

1
Determine the physical definition of Electric Current.
Electric current is the flow of electric charge per unit time (I=ΔQΔtI = \frac{\Delta Q}{\Delta t}), which matches 'The rate at which electric charge flows through a cross-sectional area of a conductor over time'.
Current measures how many coulombs of charge pass through a point each second.
2
Determine the physical definition of Voltage (Electric Potential Difference).
Voltage is the potential energy difference per unit charge (V=WQV = \frac{W}{Q}), which matches 'The amount of electric potential energy delivered or work done per unit of electric charge'.
Voltage represents the electrical 'push' or work done to move a unit charge between two points.
3
Determine the physical definition of Electrical Resistance.
Resistance describes the opposition encountered by flowing charge (R=VIR = \frac{V}{I}), which matches 'The measure of a material's opposition to the passage of electric charge'.
Resistance impedes electric current and creates a potential drop across a circuit component.
4
Determine the physical definition of Electrical Power.
Electrical power is the rate of energy transformation or consumption (P=ΔEΔt=VIP = \frac{\Delta E}{\Delta t} = VI), which matches 'The rate at which electrical energy is transferred, converted, or dissipated per unit of time'.
Power quantifies how rapidly electrical potential energy is converted into thermal energy, light, or mechanical work.

Anahtar Kavram

Fundamental electrical circuit quantities, their standard physical definitions, and underlying unit relationships
Tahmini Süre:1m 0s
Soru 10Soru →

Match each electromagnetic device or physical phenomenon on the left with its corresponding fundamental mechanism and energy interaction on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Electromagnetic induction in an electric generator
Magnetic torque production in a direct-current motor
Joule heating across an electrical resistor
Electrostatic energy storage in a capacitor

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Electromagnetic induction matches the generation of an electromotive force via varying magnetic flux; magnetic torque in a motor matches the Lorentz force acting on current-carrying conductors; Joule heating matches the conversion of electrical energy into thermal dissipation through lattice collisions; and capacitor storage matches the retention of potential energy in an electric field across an insulating dielectric.
Each electromagnetic concept correctly corresponds to its underlying physical law: electromagnetic induction generates voltage from changing magnetic flux, motor action generates mechanical torque from magnetic forces on current, resistive heating results from microscopic electron collisions yielding thermal dissipation, and capacitors store potential energy in the electric field between separated charges.

Adım Adım Çözüm

1
Analyze the operational principle of generators versus motors.
Generators convert mechanical work to electricity via changing magnetic flux (induction), whereas motors convert electrical current in a magnetic field to mechanical torque (Lorentz force).
Differentiating between motor action (electrical-to-mechanical) and generator action (mechanical-to-electrical) prevents confusing input and output energy forms.
2
Analyze energy dissipation in resistive components.
Resistive conduction dissipates energy thermally as moving charge carriers collide with conductor ions.
Ohmic resistance transforms electric potential energy irreversibly into internal thermal energy.
3
Analyze static field storage in reactive capacitive components.
Capacitors hold charge statically across a dielectric boundary, storing energy within an electric field rather than dissipating it or relying on continuous charge flow.
Capacitive storage is electrostatic and reversible, contrasting with resistive thermal dissipation and magnetic induction.

Anahtar Kavram

Fundamental principles of electromagnetism, circuit components, and electromechanical energy conversions
Tahmini Süre:1m 30s
Soru 11Soru →

A direct-current circuit is powered by a 12 V12\text{ V} battery connected in series with a 3 Ω3\,\Omega resistor, followed by two 6 Ω6\,\Omega resistors connected in parallel with each other. If one of the 6 Ω6\,\Omega parallel resistors burns out and creates an open circuit, what is the total electrical power consumed by the remaining active circuit?

Cevabı ve açıklamayı göster

Cevap: 16 W16\text{ W}

Cevap

16 W16\text{ W}
When one of the parallel 6 Ω6\,\Omega resistors opens, the parallel network is reduced to the single remaining 6 Ω6\,\Omega resistor. This resistor is in series with the 3 Ω3\,\Omega resistor, giving a total equivalent resistance of R=3 Ω+6 Ω=9 ΩR = 3\,\Omega + 6\,\Omega = 9\,\Omega. Applying the power formula P=V2RP = \frac{V^2}{R} with a 12 V12\text{ V} battery gives P=1449=16 WP = \frac{144}{9} = 16\text{ W}.

Adım Adım Çözüm

1
Determine the new circuit configuration after component failure
A single 3 Ω3\,\Omega resistor in series with the remaining 6 Ω6\,\Omega resistor
When one parallel branch burns out into an open circuit, no current flows through that branch, leaving the remaining parallel resistor in direct series with the first resistor.
2
Calculate the total equivalent resistance (RtotalR_{\text{total}})
Rtotal=3 Ω+6 Ω=9 ΩR_{\text{total}} = 3\,\Omega + 6\,\Omega = 9\,\Omega
Resistances in series add directly together.
3
Calculate total electrical power using the formula P=V2RP = \frac{V^2}{R}
P=(12 V)29 Ω=1449=16 WP = \frac{(12\text{ V})^2}{9\,\Omega} = \frac{144}{9} = 16\text{ W}
Electrical power is directly proportional to the square of the source voltage and inversely proportional to the total equivalent resistance.

Anahtar Kavram

Series-Parallel Circuit Analysis and Electrical Power Calculation
Tahmini Süre:1m 30s
Soru 12Soru →

In basic direct-current circuits, various fundamental electrical quantities describe the flow and use of electric energy. Match each electrical quantity on the left with its correct physical definition and standard unit on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Voltage
Current
Resistance
Electrical Power

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Voltage matches the electrical potential difference driving charge (volts); Current matches the rate of charge flow (amperes); Resistance matches the opposition to current flow (ohms); Electrical Power matches the rate of energy transfer (watts).
Each electrical quantity is correctly matched to its standard SI unit and underlying physical definition based on Ohm's law and electrical power principles.

Adım Adım Çözüm

1
Identify the definitions and units for potential difference and charge flow.
Voltage provides the electrical push measured in volts (V\text{V}), while Current represents the flow rate of charge measured in amperes (A\text{A}).
These are the two driving and kinematic parameters of an active circuit.
2
Identify the definitions and units for circuit opposition and energy rate.
Resistance opposes current flow and is measured in ohms (Ω\Omega), while Electrical Power is the energy conversion rate measured in watts (W\text{W}).
These relate the load characteristics and total work rate in the circuit.

Anahtar Kavram

Fundamental electrical properties, units of measurement, and definitions in direct-current circuits.
Tahmini Süre:45s
Soru 13Soru →

A string of decorative holiday lights is designed such that removing a single bulb causes all the other bulbs on the strand to go out immediately. Which type of electrical circuit does this light strand represent?

Cevabı ve açıklamayı göster

Cevap: A series circuit, because all components share a single continuous path for electric current

Cevap

A series circuit, because all components share a single continuous path for electric current
In a series circuit, all electrical loads are connected end-to-end along a single continuous path. Because electric current must travel through each component sequentially, removing or burning out any one bulb breaks the loop, creating an open circuit that immediately turns off all remaining bulbs.

Adım Adım Çözüm

1
Identify the pathway configuration of the electrical components in the circuit
The circuit contains only one continuous conducting path connecting every bulb in sequence.
Understanding the number of paths for current flow determines whether a circuit is wired in series or in parallel.
2
Analyze the effect of removing a component on the circuit loop
Removing one bulb creates a gap (open circuit), halting the flow of charge through the entire path.
Electric current requires an uninterrupted closed loop from the power source back to the source to flow.

Anahtar Kavram

Series vs. Parallel Circuits and Current Pathways
Tahmini Süre:45s
Soru 14Soru →

A portable work light operates on a simple direct-current circuit. When switched on, an electric current of 2 A2\text{ A} passes through the bulb, which has a resistance of 3 Ω3\,\Omega. According to Ohm's law (V=I×RV = I \times R), what is the voltage supplied by the battery?

Cevabı ve açıklamayı göster

Cevap: 6 V6\text{ V}

Cevap

The voltage supplied by the battery is 6 V6\text{ V}.
According to Ohm's law, voltage (VV) equals current (II) multiplied by resistance (RR). Multiplying 2 A2\text{ A} by 3 Ω3\,\Omega gives 6 V6\text{ V}.

Adım Adım Çözüm

1
Identify the given electrical quantities from the problem.
Current I=2 AI = 2\text{ A} and resistance R=3 ΩR = 3\,\Omega.
Ohm's law requires current and resistance to determine voltage.
2
Apply Ohm's law formula V=I×RV = I \times R.
V=2 A×3 Ω=6 VV = 2\text{ A} \times 3\,\Omega = 6\text{ V}.
Multiplying electric current by internal resistance calculates the total potential difference (voltage).

Anahtar Kavram

Ohm's law states that the electrical potential difference (voltage) across a conductor is directly proportional to the current flowing through it, given by V=I×RV = I \times R.
Tahmini Süre:40s
Soru 15Soru →

Electromagnetic principles are applied in many common electrical machines and tools. Match each device with its primary operational function.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Electric Generator
Electric Motor
Transformer
Electromagnet

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Electric Generator matches with converting mechanical energy to electrical energy; Electric Motor matches with converting electrical energy to mechanical rotation; Transformer matches with adjusting alternating current voltage levels; Electromagnet matches with producing a controllable magnetic field from electric current.
Each electromagnetic device corresponds directly to its defined operational function: generators convert mechanical work into electricity, motors convert electricity into mechanical rotation, transformers step AC voltage up or down, and electromagnets create temporary magnetic fields via electric current.

Adım Adım Çözüm

1
Identify the energy transformation in an electric generator.
Mechanical energy is converted into electrical energy via induction.
Generators are driven by mechanical power to produce current.
2
Identify the energy transformation in an electric motor.
Electrical energy is converted into mechanical motion.
Motors consume electricity to produce physical torque and rotation.
3
Identify the primary role of a transformer in power distribution.
Voltage levels of alternating current are increased or decreased.
Transformers rely on changing magnetic flux between primary and secondary coils to adjust voltage.
4
Identify the mechanism of an electromagnet.
Current flowing through a coil creates a magnetic field.
Moving electric charges naturally produce magnetic fields around the coil.

Anahtar Kavram

Electromagnetic Devices and Energy Transformations
Tahmini Süre:45s
Soru 16Soru →

A 12 V12\text{ V} direct-current car battery is connected to a circuit powering a single headlight with a resistance of 4 Ω4\,\Omega. What is the electric current, in amperes, flowing through the headlight?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The electric current flowing through the headlight is 3 amperes.
According to Ohm's law, electric current (II) equals voltage (VV) divided by resistance (RR). Dividing a voltage of 12 V12\text{ V} by a resistance of 4 Ω4\,\Omega yields an electric current of 3 A3\text{ A}.

Adım Adım Çözüm

1
Identify the relationship between voltage, current, and resistance using Ohm's law.
V=I×RV = I \times R, which rearranges to I=VRI = \frac{V}{R}.
Ohm's law governs the relationship between electric potential difference, current flow, and resistance in a DC circuit.
2
Substitute the given values into the formula and solve for current.
I=12 V4 Ω=3 AI = \frac{12\text{ V}}{4\,\Omega} = 3\text{ A}
Dividing the electromotive force (voltage) by the total circuit resistance yields the resulting electric current.

Anahtar Kavram

Ohm's Law (V=IRV = IR)
Electricity and Magnetism Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) | Examkin