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Zorluk: Çok zorSystems of Linear Equations
Consider the following system of linear equations in variables xx, yy, and zz, where aa is a real constant:
x+y+z=6x+2y+3z=10x+2y+(a21)z=a+8\begin{aligned} x + y + z &= 6 \\ x + 2y + 3z &= 10 \\ x + 2y + (a^2 - 1)z &= a + 8 \end{aligned}

Which of the following statements must be true? Select all that apply.

  1. If a=2a = 2, the system has infinitely many solutions.Cevap
  2. If a=2a = -2, the system has no solution.Cevap
  3. If a=2a = 2, every solution to the system satisfies 2x+y=82x + y = 8.Cevap
  4. D
    If a=3a = 3, the unique solution has y=3y = 3.
  5. E
    The system has a unique solution for all real values of aa except a=2a = 2.

Cevap

The correct statements are that a=2a = 2 yields infinitely many solutions, a=2a = -2 results in no solution, and for a=2a = 2 every solution satisfies 2x+y=82x + y = 8.
The reduced equation (a24)z=a2(a^2 - 4)z = a - 2 determines the behavior of the system. Setting a=2a = 2 gives 0=00 = 0, leading to infinitely many solutions where x=z+2x = z + 2 and y=42zy = 4 - 2z, which identically satisfies 2x+y=82x + y = 8. Setting a=2a = -2 gives 0=40 = -4, an inconsistency yielding no solutions.

Adım Adım Çözüm

1
Eliminate xx and yy using elimination between the second and third equations.
(x+2y+(a21)z)(x+2y+3z)=(a+8)10    (a24)z=a2(x + 2y + (a^2 - 1)z) - (x + 2y + 3z) = (a + 8) - 10 \implies (a^2 - 4)z = a - 2
Isolating the parameter dependence onto a single variable zz reveals existence and uniqueness conditions.
2
Analyze the equation (a2)(a+2)z=a2(a - 2)(a + 2)z = a - 2 for key parameter values.
If a=2a = 2, 0z=00 \cdot z = 0 (infinitely many solutions). If a=2a = -2, 0z=40 \cdot z = -4 (no solution). If a±2a \neq \pm 2, z=1a+2z = \frac{1}{a + 2} (unique solution).
Determining system consistency depends on whether the leading coefficient and right-hand side evaluate to zero.
3
Express xx and yy in terms of zz for the consistent case a=2a = 2.
Subtracting the first equation from the second gives y+2z=4    y=42zy + 2z = 4 \implies y = 4 - 2z. Substituting into the first gives x=z+2x = z + 2.
Parameterizing the solution set allows verification of linear combinations.
4
Evaluate the linear combination 2x+y2x + y when a=2a = 2.
2x+y=2(z+2)+(42z)=2z+4+42z=82x + y = 2(z + 2) + (4 - 2z) = 2z + 4 + 4 - 2z = 8.
Verifies that 2x+y=82x + y = 8 is an invariant across all parametric solutions.

Anahtar Kavram

Parametric Analysis of 3x3 Systems of Linear Equations
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