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Zorluk: KolayProperties of Integers and Divisibility

When the positive integer nn is divided by 77, the remainder is 44. What is the remainder when n+18n + 18 is divided by 77?

Cevap: 1

Cevap

The remainder when n+18n + 18 is divided by 77 is 11.
Because nn leaves a remainder of 44 when divided by 77, nn can be represented as 7k+47k + 4. Adding 1818 gives n+18=7k+22n + 18 = 7k + 22. Since 7k7k is a multiple of 77, the remainder of (7k+22)÷7(7k + 22) \div 7 depends entirely on 22÷722 \div 7. Dividing 2222 by 77 gives a quotient of 33 with a remainder of 11.

Adım Adım Çözüm

1
Represent the positive integer nn algebraically based on the given remainder.
n=7k+4n = 7k + 4 for some non-negative integer kk.
By the division algorithm, any integer nn divided by 77 with remainder 44 can be written as 7k+47k + 4.
2
Add 1818 to nn.
n+18=(7k+4)+18=7k+22n + 18 = (7k + 4) + 18 = 7k + 22.
Substitute 7k+47k + 4 for nn in the expression n+18n + 18.
3
Determine the remainder when 7k+227k + 22 is divided by 77.
Since 7k7k is divisible by 77, the remainder is 22(mod7)=122 \pmod 7 = 1.
Dividing 2222 by 77 yields a quotient of 33 and a remainder of 11 (22=7×3+122 = 7 \times 3 + 1).

Anahtar Kavram

Remainder Properties under Addition
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