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Zorluk: OrtaProperties of Integers and Divisibility

A positive integer nn yields a remainder of 77 when divided by 1212. What is the remainder when the expression 5n+35n + 3 is divided by 66?

  1. A
    00
  2. B
    11
  3. 22Cevap
  4. D
    33
  5. E
    55

Cevap

The remainder when 5n+35n + 3 is divided by 66 is 22.
Since nn leaves a remainder of 77 when divided by 1212, we can write n=12k+7n = 12k + 7 for some integer k0k \ge 0. Substituting this into 5n+35n + 3 yields 5(12k+7)+3=60k+385(12k + 7) + 3 = 60k + 38. Factoring out 66 gives 6(10k+6)+26(10k + 6) + 2. Because 6(10k+6)6(10k + 6) is divisible by 66, the remainder of the expression when divided by 66 is 22.

Adım Adım Çözüm

1
Express nn in terms of the division algorithm for divisor 1212.
n=12k+7n = 12k + 7 for some non-negative integer kk
An integer that leaves a remainder of 77 when divided by 1212 can be represented as 12k+712k + 7.
2
Substitute the expression for nn into 5n+35n + 3 and simplify.
5(12k+7)+3=60k+35+3=60k+385(12k + 7) + 3 = 60k + 35 + 3 = 60k + 38
Algebraic expansion allows us to analyze the entire expression modulo 66.
3
Determine the remainder of 60k+3860k + 38 when divided by 66.
60k+38=6(10k+6)+260k + 38 = 6(10k + 6) + 2
Since 60k+3660k + 36 is an exact multiple of 66, the leftover term 22 is the remainder.

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Properties of Integers and Remainder Arithmetic
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