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Zorluk: OrtaSystems of Linear Equations

A venue offers two types of event packages: Standard and Deluxe. The total cost of 3 Standard packages and 2 Deluxe packages is 410.Thetotalcostof2Standardpackagesand5Deluxepackagesis410. The total cost of 2 Standard packages and 5 Deluxe packages is 640. What is the cost, in dollars, of 1 Deluxe package?

Cevap: 100 dollars

Cevap

100
Setting up the linear system 3S+2D=4103S + 2D = 410 and 2S+5D=6402S + 5D = 640 allows us to multiply the equations by 2 and 3 respectively, obtaining 6S+4D=8206S + 4D = 820 and 6S+15D=19206S + 15D = 1920. Subtracting the two equations eliminates SS and gives 11D=110011D = 1100, leading to D=100D = 100.

Adım Adım Çözüm

1
Define variables and establish the system of linear equations.
Let SS represent the cost of a Standard package and DD represent the cost of a Deluxe package.
Equation 1: 3S+2D=4103S + 2D = 410
Equation 2: 2S+5D=6402S + 5D = 640
Translating the scenario into mathematical equations forms a 2x2 system of linear equations.
2
Use elimination to eliminate variable SS.
Multiply Equation 1 by 2: 6S+4D=8206S + 4D = 820
Multiply Equation 2 by 3: 6S+15D=19206S + 15D = 1920
Creating matching coefficients for SS allows elimination by subtraction.
3
Subtract the transformed equations and solve for DD.
(6S+15D)(6S+4D)=1920820    11D=1100    D=100(6S + 15D) - (6S + 4D) = 1920 - 820 \implies 11D = 1100 \implies D = 100
Subtracting cancels out SS, leaving a single linear equation in terms of DD.

Anahtar Kavram

Solving 2x2 Systems of Linear Equations via Elimination

Alternatif Yöntem

Use the substitution method: Solve for SS in terms of DD from the first equation (S=4102D3S = \frac{410 - 2D}{3}) and substitute this into the second equation (2(4102D3)+5D=6402\left(\frac{410 - 2D}{3}\right) + 5D = 640). Multiplying both sides by 3 yields 8204D+15D=1920820 - 4D + 15D = 1920, which simplifies to 11D=110011D = 1100, so D=100D = 100.
Tahmini Süre:1m 30s
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