Tüm alıştırma soruları

2131 soru

Soru 1901Soru

In 1915, chemist Alice Ball developed an injectable form of oil derived from seeds of the *Hydnocarpus* tree, providing the first effective treatment for Hansen's disease (leprosy). Prior to Ball’s innovation, patients were treated with raw chaulmoogra oil, which was too viscous for intravenous administration and produced unbearable digestive distress when ingested orally. Ball solved this problem by isolating the active ethyl esters of the chaulmoogra fatty acids, rendering the compound water-soluble and capable of absorption into the bloodstream without causing severe localized tissue necrosis. Although her supervisor, Arthur L. Dean, published the method following Ball's death in 1916 without granting her co-authorship, local physician Harry T. Hollmann publicly documented Ball's priority in 1922, designating the technique the "Ball Method."

According to the passage, prior to the development of the "Ball Method," treatment of Hansen's disease with chaulmoogra oil presented which of the following complications?

Select all choices that apply.

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Cevap: Oral administration of the untreated oil resulted in severe digestive distress.; The raw oil possessed a level of viscosity that precluded intravenous injection.

Cevap

The correct selections describe oral ingestion producing severe digestive distress and high viscosity preventing intravenous injection.
The correct selections directly reflect explicitly stated facts in the passage: raw chaulmoogra oil caused severe digestive distress when ingested orally, and its high viscosity prevented intravenous administration.

Adım Adım Çözüm

1
Locate the portion of the text that describes chaulmoogra oil treatment prior to Alice Ball's innovation.
The second sentence explicitly addresses raw chaulmoogra oil characteristics and complications before Ball's work.
Direct retrieval requires isolating facts explicitly stated in the context.
2
Evaluate the choice concerning oral administration.
The text confirms that raw oil produced unbearable digestive distress when ingested orally.
Verifies direct paraphrase of explicit passage detail.
3
Evaluate the choice concerning intravenous administration and viscosity.
The text confirms that raw oil was too viscous for intravenous administration.
Verifies direct paraphrase of explicit passage detail.
4
Evaluate the choice concerning stomach lining necrosis.
The passage associates tissue necrosis with bloodstream absorption, not stomach lining contact.
Identifies misread details and incorrect context association.

Anahtar Kavram

Explicit Detail Retrieval
Soru 1902Soru

If xx satisfies the linear equation 3(x1)2x+54=2x33\frac{3(x - 1)}{2} - \frac{x + 5}{4} = \frac{2x - 3}{3}, what is the value of 4x+74x + 7?

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Cevap: 19

Cevap

19
Multiplying the entire equation by the least common denominator 12 yields 18(x1)3(x+5)=4(2x3)18(x - 1) - 3(x + 5) = 4(2x - 3). Expanding the terms gives 18x183x15=8x1218x - 18 - 3x - 15 = 8x - 12, which simplifies to 15x33=8x1215x - 33 = 8x - 12. Subtracting 8x8x and adding 3333 gives 7x=217x = 21, so x=3x = 3. Substituting x=3x = 3 into 4x+74x + 7 produces 4(3)+7=194(3) + 7 = 19.

Adım Adım Çözüm

1
Find the least common denominator (LCD) for all fractions in the equation.
The LCD of 2, 4, and 3 is 12.
Clearing denominators simplifies the linear equation to integer coefficients.
2
Multiply both sides of the equation by 12.
12 \cdot \left(\frac{3(x - 1)}{2}\right) - 12 \cdot \left(\frac{x + 5}{4}\right) = 12 \cdot \left(\frac{2x - 3}{3}\right) \implies 6 \cdot 3(x - 1) - 3(x + 5) = 4(2x - 3)
Multiplying each term by 12 eliminates all fractions.
3
Expand the terms on both sides of the equation.
18(x - 1) - 3(x + 5) = 8x - 12 \implies 18x - 18 - 3x - 15 = 8x - 12
Distribute the coefficients across each set of parentheses.
4
Combine like terms and solve for xx.
15x - 33 = 8x - 12 \implies 7x = 21 \implies x = 3
Isolate the variable term xx on one side of the equation.
5
Evaluate the requested expression 4x+74x + 7 using x=3x = 3.
4(3) + 7 = 12 + 7 = 19
Substitute the value of xx into 4x+74x + 7 to find the final requested value.

Anahtar Kavram

Solving multi-step linear equations in one variable with fractional coefficients by clearing denominators.
Tahmini Süre:1m 30s
Soru 1903Soru

When the expression 3x212x2\frac{3x^2 - 12}{x - 2} is completely simplified, it can be written in the form ax+bax + b for all x2x \neq 2, where aa and bb are constants. What is the value of a+ba + b?

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Cevap: 9

Cevap

The value of a+ba + b is 9.
Factoring the numerator gives 3x212=3(x24)=3(x2)(x+2)3x^2 - 12 = 3(x^2 - 4) = 3(x - 2)(x + 2). Canceling the common factor (x2)(x - 2) in the denominator yields 3(x+2)3(x + 2), which expands to 3x+63x + 6. Matching this expression to ax+bax + b reveals a=3a = 3 and b=6b = 6. Adding these constants gives a+b=9a + b = 9.

Adım Adım Çözüm

1
Factor the numerator of the rational expression.
3x212=3(x24)=3(x2)(x+2)3x^2 - 12 = 3(x^2 - 4) = 3(x - 2)(x + 2)
Factoring out the common numerical factor 3 and using the difference of squares identity (u2v2=(uv)(u+v))(u^2 - v^2 = (u-v)(u+v)) completely factors the numerator.
2
Simplify the expression by canceling common factors.
3(x2)(x+2)x2=3(x+2)=3x+6\frac{3(x - 2)(x + 2)}{x - 2} = 3(x + 2) = 3x + 6
Because x2x \neq 2, the factor (x2)(x - 2) is non-zero and can be canceled from both numerator and denominator.
3
Identify the values of aa and bb and compute a+ba + b.
a=3a = 3, b=6b = 6, so a+b=3+6=9a + b = 3 + 6 = 9
Comparing 3x+63x + 6 to ax+bax + b gives a=3a = 3 and b=6b = 6.

Anahtar Kavram

Factoring algebraic expressions using common monomial factors and the difference of squares to simplify rational expressions.
Soru 1904Soru

Which words best complete the passage so that the text maintains logical coherence and proper inter-blank structural dependency?

Aşağıdaki boşlukları doldurun

The committee's report was far from (i); while its preliminary findings appeared to condemn the firm's executive oversight, its concluding chapter provided a nuanced defense that effectively (ii) the initial severity of the charges.
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Cevap

Blank 1: monolithic (or unequivocal); Blank 2: mitigated (or tempered).
The passage establishes a clear structural contrast introduced by 'while'. The second half explains that the report contains both preliminary condemnation and a nuanced defense. A defense functions to lessen or soften initial accusations, calling for a word such as 'mitigated' or 'tempered' for the second blank. Tracking this dependency back to the first blank reveals that a report containing such opposing elements is not uniform or single-minded; thus, the phrase 'far from' requires a word like 'monolithic' or 'unequivocal' for the first blank.

Adım Adım Çözüm

1
Analyze the structural pivot 'while' and internal contrast signals.
The clause indicates a shift between preliminary harsh condemnation and a later nuanced defense.
Identifying the relationship between the two parts of the report is required to solve both blanks.
2
Determine the appropriate meaning for Blank 2 based on the effect of a 'nuanced defense'.
A defense reduces the harshness of charges, pointing to terms meaning to lessen or soften, such as 'mitigated' or 'tempered'.
The concluding defense acts as a counterweight to the initial severity.
3
Establish the dependency for Blank 1 based on the resolved meaning of Blank 2.
Because the document contains both critical findings and mitigating defense, it is multifaceted rather than single-minded, making it 'far from monolithic'.
The presence of contrasting perspectives within one document contradicts the idea of a uniform or monolithic stance.

Anahtar Kavram

Multi-blank inter-blank dependency and contrast resolution
Soru 1905Soru

If xx and yy are real numbers such that 1<x<0<y<1-1 < x < 0 < y < 1, which of the following statements MUST be true? Select all such statements.

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Cevap: x3<x5x^3 < x^5; (y1/2)x>1\left(y^{1/2}\right)^x > 1

Cevap

The statements x3<x5x^3 < x^5 and (y1/2)x>1\left(y^{1/2}\right)^x > 1 MUST be true.
For 1<x<0<y<1-1 < x < 0 < y < 1, odd powers of xx satisfy 1<x<x3<x5<0-1 < x < x^3 < x^5 < 0, making the inequality comparing x3x^3 and x5x^5 true. Furthermore, y1/2y^{1/2} lies in (0,1)(0, 1), and raising a base in (0,1)(0, 1) to a negative exponent xx produces a result strictly greater than 1.

Adım Adım Çözüm

1
Analyze the odd power inequality x3<x5x^3 < x^5 for 1<x<0-1 < x < 0.
Since x(1,0)x \in (-1, 0), x2(0,1)x^2 \in (0, 1). Multiplying 1<x<0-1 < x < 0 by x2x^2 gives x<x3<x5<0x < x^3 < x^5 < 0. Thus, x3<x5x^3 < x^5 holds.
Odd powers preserve negative signs, and higher powers of fractions between 0 and 1 have smaller absolute values.
2
Evaluate the principal square root x2\sqrt{x^2}.
By definition, x2=x\sqrt{x^2} = |x|. Since x<0x < 0, x=xx|x| = -x \neq x.
The principal square root of a real number is always non-negative.
3
Analyze the expression (y1/2)x\left(y^{1/2}\right)^x.
Since 0<y<10 < y < 1, 0<y1/2<10 < y^{1/2} < 1. Let k=y1/2k = y^{1/2}. Then kx=(1k)xk^x = \left(\frac{1}{k}\right)^{-x}. Since k<1k < 1, 1k>1\frac{1}{k} > 1, and since x<0x < 0, x>0-x > 0. A base greater than 1 raised to a positive power is greater than 1.
Negative exponents indicate the reciprocal of the base.
4
Evaluate (x+y)2=x2+y2(x + y)^2 = x^2 + y^2.
(x+y)2=x2+2xy+y2(x + y)^2 = x^2 + 2xy + y^2. Because x<0x < 0 and y>0y > 0, 2xy<02xy < 0, so (x+y)2<x2+y2(x + y)^2 < x^2 + y^2.
Exponents do not distribute over addition, and cross-terms must be accounted for.
5
Evaluate x4>x2x^4 > x^2.
For 1<x<0-1 < x < 0, 0<x2<10 < x^2 < 1. Squaring a number in (0,1)(0, 1) yields a smaller number, so x4<x2x^4 < x^2.
Higher even powers of quantities with magnitude less than 1 decrease in magnitude.

Anahtar Kavram

Properties of exponents, fractional powers, and principal square roots for bounded negative and positive real numbers
Tahmini Süre:2m 30s
Soru 1906Soru

At a clothing retailer, the wholesale cost of a leather coat was 50%50\% greater than the wholesale cost of a denim jacket. The following year, the wholesale cost of the leather coat increased by 20%20\%, while the wholesale cost of the denim jacket decreased by 10%10\%. What was the overall percentage increase in the combined wholesale cost of one leather coat and one denim jacket?

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Cevap: 8%8\%

Cevap

An overall increase of 8%8\% in the combined wholesale cost.
Assuming an initial denim jacket cost of 100100, the leather coat costs 150150, giving an initial combined cost of 250250. After a 20%20\% increase, the coat costs 180180, and after a 10%10\% decrease, the jacket costs 9090. The new combined total is 270270. The total increase is 2020, which represents 20250=8%\frac{20}{250} = 8\% of the original combined cost.

Adım Adım Çözüm

1
Define variables for the initial costs of the items.
Let the initial cost of the denim jacket be d=100d = 100. Then the initial cost of the leather coat is 1.50d=1501.50d = 150.
Choosing a convenient base value makes calculating relative percentage changes straightforward.
2
Calculate the initial total cost and the new individual costs after price changes.
Initial total cost = 100+150=250100 + 150 = 250. New cost of leather coat = 150×(1+0.20)=180150 \times (1 + 0.20) = 180. New cost of denim jacket = 100×(10.10)=90100 \times (1 - 0.10) = 90.
Percentage increases and decreases must be applied to their respective starting costs.
3
Compute the new combined total cost and calculate the net percentage change.
New combined total cost = 180+90=270180 + 90 = 270. Dollar change = 270250=20270 - 250 = 20. Net percentage increase = 20250×100%=8%\frac{20}{250} \times 100\% = 8\%.
Percent change is calculated by dividing the absolute change by the original combined base value.

Anahtar Kavram

Combined Percent Change and Weighted Base Values
Soru 1907Soru

Read the passage below:

For decades, nineteenth-century astrophysicists regarded solar spectrographic lines as purely (i)________ anomalies, treating each spectral line as an isolated curiosity rather than an index of atomic architecture. However, once laboratory experimenters demonstrated that atomic emissions follow predictable mathematical series, this assumption was entirely (ii)________. Far from being meaningless noise, spectral lines were recognized as (iii)________ indicators of atomic energy transitions, effectively laying the groundwork for quantum mechanics.

Which set of terms, when inserted into the blanks in order, best maintains the cross-sentence contextual coherence of the passage?

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Cevap: (i) incidental, (ii) dismantled, (iii) indispensable

Cevap

(i) incidental, (ii) dismantled, (iii) indispensable
The combination of '(i) incidental, (ii) dismantled, (iii) indispensable' maintains strict thematic and structural logic across the passage. 'Incidental' aligns with 'isolated curiosity', 'dismantled' correctly registers the shift signaled by 'However' after laboratory discoveries, and 'indispensable' logically connects with 'laying the groundwork for quantum mechanics'.

Adım Adım Çözüm

1
Analyze Blank (i) using clues within Sentence 1.
The phrase 'isolated curiosity rather than an index of atomic architecture' indicates that the spectral lines were viewed as minor, non-essential occurrences. 'Incidental' (minor/accidental) fits this meaning.
The contrast 'rather than an index' demands a word signifying something non-fundamental.
2
Analyze Blank (ii) using the transition signal 'However' in Sentence 2.
Since laboratory experiments proved spectral lines follow predictable mathematical series, the initial assumption that they were minor anomalies was disproved. 'Dismantled' accurately reflects this reversal.
The contrast marker 'However' signals a turn away from the nineteenth-century belief.
3
Analyze Blank (iii) using cross-sentence clues in Sentence 3.
The phrase 'Far from being meaningless noise' and the outcome 'laying the groundwork for quantum mechanics' require a positive word meaning essential or crucial. 'Indispensable' fits precisely.
The trajectory of the passage moves from dismissal to recognizing crucial scientific value.

Anahtar Kavram

Cross-Sentence Contextual Coherence in Multi-Blank Text Completion
Soru 1908Soru

In Month 1, a data center's two facilities, Facility A and Facility B, consumed a combined total of 120,000 kWh120,000\text{ kWh} of electricity. In Month 2, Facility A decreased its electricity consumption by 15%15\%, while Facility B increased its electricity consumption by 20%20\%. If the combined electricity consumption of the two facilities increased by 6%6\% overall in Month 2, how many kilowatt-hours (kWh\text{kWh}) of electricity did Facility A consume in Month 1?

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Cevap: 48000

Cevap

Facility A consumed 48,000 kWh of electricity in Month 1.
Let AA represent the electricity consumed by Facility A in Month 1. The remaining electricity consumed by Facility B in Month 1 is 120,000A120,000 - A. In Month 2, the decrease in Facility A's consumption is 15%15\% of AA, or 0.15A0.15A, and the increase in Facility B's consumption is 20%20\% of (120,000A)(120,000 - A), or 0.20(120,000A)0.20(120,000 - A). The net increase overall is 6%6\% of 120,000120,000, which is 7,200 kWh7,200\text{ kWh}. Setting up the change equation 0.15A+0.20(120,000A)=7,200-0.15A + 0.20(120,000 - A) = 7,200 leads to 0.35A+24,000=7,200-0.35A + 24,000 = 7,200, which simplifies to 0.35A=16,8000.35A = 16,800. Solving for AA yields A=48,000 kWhA = 48,000\text{ kWh}.

Adım Adım Çözüm

1
Define variables for the initial Month 1 consumption of each facility.
Let AA = Month 1 consumption of Facility A. Month 1 consumption of Facility B = 120,000A120,000 - A.
Expressing one unknown in terms of the total reduces the system to a single variable equation.
2
Determine the net kilowatt-hour change for Month 2.
Net change = 0.06×120,000=7,200 kWh0.06 \times 120,000 = 7,200\text{ kWh}.
An overall increase of 6% applies to the total starting value of 120,000 kWh.
3
Express the individual percentage changes in terms of AA and equate to the net change.
0.15A+0.20(120,000A)=7,200-0.15A + 0.20(120,000 - A) = 7,200.
Facility A's 15% decrease contributes 0.15A-0.15A and Facility B's 20% increase contributes +0.20(120,000A)+0.20(120,000 - A).
4
Solve the linear equation for AA.
0.35A+24,000=7,2000.35A=16,800A=48,000-0.35A + 24,000 = 7,200 \Rightarrow 0.35A = 16,800 \Rightarrow A = 48,000.
Dividing 16,80016,800 by 0.350.35 yields the original consumption of Facility A.

Anahtar Kavram

Weighted Percent Change and Systems of Percent Equations
Soru 1909Soru

An automated micro-dispenser delivers liquid reagents in precise doses. Each dose has a volume of 3.6×1053.6 \times 10^{-5} liters. If a reservoir containing 0.01620.0162 liters of reagent is emptied completely by delivering these equal doses, how many doses were delivered?

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Cevap: 450

Cevap

450
Dividing the total volume of 1.62×1021.62 \times 10^{-2} liters by the single dose volume of 3.6×1053.6 \times 10^{-5} liters yields 1.623.6×102(5)=0.45×103=450\frac{1.62}{3.6} \times 10^{-2 - (-5)} = 0.45 \times 10^3 = 450 doses.

Adım Adım Çözüm

1
Express the total reservoir volume in scientific notation
0.0162=1.62×1020.0162 = 1.62 \times 10^{-2} liters
Converting decimals into standard scientific notation simplifies multiplication and division operations.
2
Set up the division for the number of doses
Number of doses=1.62×1023.6×105\text{Number of doses} = \frac{1.62 \times 10^{-2}}{3.6 \times 10^{-5}}
The total volume divided by the volume per single dose yields the total dose count.
3
Compute the division of coefficients and exponent terms independently
1.623.6=0.45\frac{1.62}{3.6} = 0.45 and 102105=102(5)=103\frac{10^{-2}}{10^{-5}} = 10^{-2 - (-5)} = 10^3
Applying the exponent quotient rule 10a/10b=10ab10^a / 10^b = 10^{a-b} yields 2(5)=3-2 - (-5) = 3.
4
Convert from scientific notation to a standard integer
0.45×103=4500.45 \times 10^3 = 450
Multiplying 0.450.45 by 1,0001,000 shifts the decimal point 3 places to the right.

Anahtar Kavram

Division of numbers in scientific notation and place value manipulation
Tahmini Süre:1m 30s
Soru 1910Soru

Line LL is defined by the equation 3x4y=123x - 4y = 12. Line MM is perpendicular to line LL and passes through the point (6,1)(6, -1). Which of the following statements about line MM must be true? Select all that apply.

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Cevap: Line MM has a yy-intercept of (0,7)(0, 7).; Line MM passes through the point (3,3)(3, 3).; Line MM is parallel to the line given by 4x+3y=104x + 3y = 10.

Cevap

The correct statements are that line MM has a yy-intercept of (0,7)(0, 7), passes through the point (3,3)(3, 3), and is parallel to the line given by 4x+3y=104x + 3y = 10.
Line LL has equation y=34x3y = \frac{3}{4}x - 3, so its slope is 34\frac{3}{4}. The perpendicular line MM has slope 43-\frac{4}{3}. Using point (6,1)(6, -1), the equation of line MM is y=43x+7y = -\frac{4}{3}x + 7. The statement claiming a yy-intercept of (0,7)(0, 7) is correct because y=7y = 7 when x=0x = 0. The statement claiming line MM passes through (3,3)(3, 3) is correct because 43(3)+7=3-\frac{4}{3}(3) + 7 = 3. The statement claiming line MM is parallel to 4x+3y=104x + 3y = 10 is correct because 4x+3y=104x + 3y = 10 has a slope of 43-\frac{4}{3}, which matches the slope of line MM.

Adım Adım Çözüm

1
Find the slope of line LL.
Convert 3x4y=123x - 4y = 12 to slope-intercept form: 4y=3x12    y=34x34y = 3x - 12 \implies y = \frac{3}{4}x - 3. The slope of line LL is mL=34m_L = \frac{3}{4}.
The slope of a linear equation in standard form can be determined by expressing it as y=mx+by = mx + b.
2
Determine the slope and equation of line MM.
Since line MM is perpendicular to line LL, its slope is the negative reciprocal: mM=43m_M = -\frac{4}{3}. Using point-slope form with (6,1)(6, -1): y(1)=43(x6)    y+1=43x+8    y=43x+7y - (-1) = -\frac{4}{3}(x - 6) \implies y + 1 = -\frac{4}{3}x + 8 \implies y = -\frac{4}{3}x + 7.
Perpendicular lines have slopes that are negative reciprocals of each other.
3
Evaluate statement regarding the yy-intercept.
Setting x=0x = 0 gives y=7y = 7, so the yy-intercept is (0,7)(0, 7). This statement is true.
The yy-intercept occurs where x=0x = 0.
4
Evaluate statement regarding point (3,3)(3, 3).
Plug in x=3x = 3: y=43(3)+7=3y = -\frac{4}{3}(3) + 7 = 3. The point (3,3)(3, 3) lies on line MM. This statement is true.
A point lies on a line if its coordinates satisfy the line equation.
5
Evaluate statement regarding Quadrant III passage.
For x<0x < 0, y=43x+7>7>0y = -\frac{4}{3}x + 7 > 7 > 0 (Quadrant II). For 0x5.250 \le x \le 5.25, y0y \ge 0 (Quadrant I). For x>5.25x > 5.25, y<0y < 0 (Quadrant IV). The line does not enter Quadrant III. This statement is false.
Lines with negative slopes and positive yy-intercepts pass through Quadrants I, II, and IV only.
6
Evaluate statement regarding the xx-intercept.
Setting y=0y = 0: 0=43x+7    x=214=5.250 = -\frac{4}{3}x + 7 \implies x = \frac{21}{4} = 5.25, giving xx-intercept (214,0)(\frac{21}{4}, 0). This statement is false.
The xx-intercept occurs where y=0y = 0.
7
Evaluate statement regarding parallelism to 4x+3y=104x + 3y = 10.
4x+3y=10    y=43x+1034x + 3y = 10 \implies y = -\frac{4}{3}x + \frac{10}{3}. The slope is 43-\frac{4}{3}, matching line MM's slope, with distinct yy-intercepts. This statement is true.
Lines with identical slopes and different yy-intercepts are parallel.

Anahtar Kavram

Perpendicular and parallel line slope relationships, point-slope equation derivation, and coordinate plane quadrant navigation.
Soru 1911Soru

If xx is a positive real number such that 2x25x3=02x^2 - 5x - 3 = 0, what is the value of x2+1x^2 + 1?

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Cevap: 10

Cevap

10
Factoring the quadratic equation 2x25x3=02x^2 - 5x - 3 = 0 yields (2x+1)(x3)=0(2x + 1)(x - 3) = 0, giving solutions x=12x = -\frac{1}{2} and x=3x = 3. Because xx is specified as a positive real number, we choose x=3x = 3. Substituting x=3x = 3 into x2+1x^2 + 1 yields 32+1=103^2 + 1 = 10.

Adım Adım Çözüm

1
Factor the quadratic equation 2x25x3=02x^2 - 5x - 3 = 0.
(2x+1)(x3)=0(2x + 1)(x - 3) = 0
Find two linear factors whose product gives 2x25x32x^2 - 5x - 3.
2
Solve for the roots of the equation.
x=12x = -\frac{1}{2} or x=3x = 3
Set each factor equal to zero: 2x+1=0    x=122x + 1 = 0 \implies x = -\frac{1}{2} and x3=0    x=3x - 3 = 0 \implies x = 3.
3
Apply the constraint x>0x > 0 to identify the valid root.
x=3x = 3
The root x=12x = -\frac{1}{2} is negative and thus violates the given condition that xx is positive.
4
Substitute x=3x = 3 into the target expression x2+1x^2 + 1.
32+1=9+1=103^2 + 1 = 9 + 1 = 10
Evaluate the expression using the valid positive value of xx.

Anahtar Kavram

Solving quadratic equations by factoring and applying domain constraints
Tahmini Süre:45s
Soru 1912Soru

Passage:
In 1891, German amateur scientist Agnes Pockels published a landmark paper detailing her development of a rectangular slide trough designed to measure the surface tension of water. Operating without access to a formal laboratory, Pockels devised a mechanism featuring a movable strip of tin that traversed the surface of a water-filled tray, allowing her to systematically manipulate surface impurities. By measuring the force required to detach a small ring from the liquid surface at varying concentrations of oil, she demonstrated that surface tension remains largely constant until oil molecules form a contiguous monomolecular layer, after which tension drops precipitously. Lord Rayleigh, to whom Pockels had originally sent her observations in a letter written in German, facilitated the paper's publication after recognizing that her device provided a far more precise quantitative measurement of monolayer coverage than previous methods, which relied on static liquid drops.

According to the passage, Pockels evaluated the behavior of surface tension across different oil concentrations by measuring which of the following?

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Cevap: The force required to detach a small ring from the liquid surface

Cevap

The correct option is the one stating that Pockels measured the force required to detach a small ring from the liquid surface.
The passage explicitly states that Pockels demonstrated the relationship between surface tension and monolayer coverage 'By measuring the force required to detach a small ring from the liquid surface at varying concentrations of oil.' This directly confirms the option identifying the force required to detach a small ring.

Adım Adım Çözüm

1
Identify the target keyword and concept in the question stem.
The stem asks how Pockels evaluated/measured surface tension across varying concentrations of oil.
Direct retrieval requires locating the specific sentence in the passage discussing her measurement procedure.
2
Locate the explicit statement in the passage.
The text states: 'By measuring the force required to detach a small ring from the liquid surface at varying concentrations of oil, she demonstrated that surface tension remains largely constant...'
This directly describes her exact quantitative measurement metric.
3
Match the explicit fact to the correct option.
The option specifying 'The force required to detach a small ring from the liquid surface' directly paraphrases the passage fact without adding unwarranted extrapolations.
Explicit detail retrieval relies on direct text verification.

Anahtar Kavram

Explicit Detail Retrieval
Soru 1913Soru

The mass of a sample in a laboratory experiment is given by the expression M=0.000375×10nM = 0.000375 \times 10^n grams, where nn is an integer. When MM is written in standard scientific notation as a×10ka \times 10^k, where 1a<101 \le a < 10 and kk is an integer, the exponent kk is equal to 2-2. What is the value of nn?

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Cevap: 22

Cevap

The value of nn is 22.
Writing 0.0003750.000375 as 3.75×1043.75 \times 10^{-4} allows the mass MM to be rewritten as 3.75×104+n3.75 \times 10^{-4 + n}. Matching this with the standard scientific notation form a×10ka \times 10^k (where a=3.75a = 3.75 and k=2k = -2) gives the equation 4+n=2-4 + n = -2. Solving for nn yields n=2n = 2.

Adım Adım Çözüm

1
Convert the decimal decimal coefficient to scientific notation.
0.000375=3.75×1040.000375 = 3.75 \times 10^{-4}
Moving the decimal point 4 places to the right puts the leading number in the required range 1a<101 \le a < 10.
2
Substitute this conversion back into the expression for MM and combine powers of 10.
M=(3.75×104)×10n=3.75×10n4M = (3.75 \times 10^{-4}) \times 10^n = 3.75 \times 10^{n - 4}
By exponent rules, 10a×10b=10a+b10^a \times 10^b = 10^{a+b}.
3
Equate the exponent of 10 in the simplified expression to the given value of kk.
n4=2    n=2n - 4 = -2 \implies n = 2
The scientific notation requires a×10ka \times 10^k where k=2k = -2, so n4n - 4 must equal 2-2.

Anahtar Kavram

Converting numbers between standard decimal form and scientific notation using place value and exponent properties
Soru 1914Soru

In the xyxy-plane, line kk passes through the point (2,3)(2, -3) and has a slope of 43-\frac{4}{3}. Line mm is parallel to line kk and has an xx-intercept at (6,0)(6, 0). What is the yy-intercept of line mm?

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Cevap: 88

Cevap

The yy-intercept of line mm is 88.
Parallel lines have equal slopes, so line mm has slope m=43m = -\frac{4}{3}. An xx-intercept of (6,0)(6, 0) means line mm passes through (6,0)(6, 0). Substituting x=6x = 6, y=0y = 0, and m=43m = -\frac{4}{3} into y=mx+by = mx + b gives 0=43(6)+b0 = -\frac{4}{3}(6) + b, which simplifies to 0=8+b0 = -8 + b, so b=8b = 8. Thus, the yy-intercept is 88.

Adım Adım Çözüm

1
Determine the slope of line mm
The slope of line mm is 43-\frac{4}{3}.
Parallel lines in the coordinate plane have identical slopes. Since line kk has a slope of 43-\frac{4}{3}, line mm must also have a slope of 43-\frac{4}{3}.
2
Use the xx-intercept (6,0)(6, 0) to solve for the yy-intercept bb of line mm
0=43(6)+b    0=8+b    b=80 = -\frac{4}{3}(6) + b \implies 0 = -8 + b \implies b = 8.
Substitute x=6x = 6, y=0y = 0, and slope m=43m = -\frac{4}{3} into the slope-intercept form y=mx+by = mx + b.

Anahtar Kavram

Parallel line slopes and slope-intercept form
Tahmini Süre:1m 15s
Soru 1915Soru

Complete the passage below by filling in the blank with the word that best fits the context based on structural clues and transition signals.

Aşağıdaki boşlukları doldurun

In marine geochemistry, early models of hydrothermal vent sediment dynamics assumed that sulfur isotopic fractionation was uniform across benthic zones. However, recent micro-electrode analyses reveal that microbial sulfate reduction in abyssal sediments is surprisingly ; while peripheral zones exhibit predictable isotopic signatures, core vent chimneys harbor extreme enzymatic microenvironments that abruptly shift isotopic ratios.
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Cevap

heterogeneous (or synonymous terms such as non-uniform or variable)
The transition word 'However' signals a clear reversal of the early assumption that sulfur isotopic fractionation was 'uniform across benthic zones.' Furthermore, the semicolon elaboration explicitly contrasts 'peripheral zones' with 'core vent chimneys,' demonstrating that isotopic signatures vary by location. Therefore, a word meaning non-uniform or varied, such as 'heterogeneous,' correctly completes the blank.

Adım Adım Çözüm

1
Identify the primary transition signal in the sentence.
The pivot word 'However' sets up a direct contrast with the initial assumption that sulfur isotopic fractionation was 'uniform across benthic zones'.
Contrast signals indicate that the missing word must express an idea opposite to 'uniform'.
2
Analyze the structural elaboration following the semicolon.
The clause introduced by 'while' contrasts 'peripheral zones' (which show predictable signatures) with 'core vent chimneys' (which harbor extreme microenvironments that abruptly shift ratios).
This structural breakdown confirms that conditions differ significantly from one location to another rather than remaining constant.
3
Deduce the contextual meaning and select an appropriate descriptor.
The blank requires an adjective signifying diverse, varied, or non-uniform spatial characteristics; 'heterogeneous' fits both the contrast signal and the semicolon elaboration.
A word expressing spatial variability satisfies all contextual and structural requirements of the passage.

Anahtar Kavram

Deciphering Meaning via Structural Clues and Contrast/Continuation Signals
Soru 1916Soru

In geomorphology, the evolution of bedrock rivers is often governed by knickpoints—abrupt slope alterations in a river profile usually caused by tectonic uplift or base-level lowering. While early models treated knickpoints as static boundaries marking distinct erosional regimes, recent hydrodynamic simulations demonstrate that knickpoints actively propagate upstream, consuming the relict landscape above them. As the slope steepens, the resulting increase in shear stress enhances bedrock incision, driving a continuous wave of retreat. Far from merely transmitting a passive signal of environmental perturbation, this migratory behavior reflects a dynamic readjustment of channel geometry. Consequently, geomorphologists must view knickpoint migration not as an ephemeral anomaly, but as the primary mechanism through which drainage basins continuously sculpt landscape topographies over geological timescales.

Based on the passage above, which of the following best captures the meaning of the word propagate as it is used by the author?

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Cevap: migrate or travel physically upstream

Cevap

The term 'propagate' as used in the passage means to migrate or travel physically upstream along the river profile.
The correct answer is the option stating 'migrate or travel physically upstream'. The passage explicitly pairs 'propagate' with the direction 'upstream' and refers back to this process as 'this migratory behavior' and 'knickpoint migration', establishing that the word refers to spatial movement along the riverbed.

Adım Adım Çözüm

1
Analyze the immediate sentence context containing the target word.
The text states that 'knickpoints actively propagate upstream, consuming the relict landscape above them.'
Word meaning in reading comprehension is dictated by surrounding modifiers and parallel descriptions.
2
Examine surrounding structural clues and restatements.
The subsequent sentences refer to 'a continuous wave of retreat', 'this migratory behavior', and 'knickpoint migration'.
The author explicitly rephrases the action of propagating as 'migratory behavior' and 'migration'.
3
Evaluate option choices against the contextual evidence.
The option stating 'migrate or travel physically upstream' matches the author's description of physical displacement along the river channel.
Only this definition aligns with the spatial movement described throughout the passage.

Anahtar Kavram

Passage-Based Word in Context Analysis
Tahmini Süre:1m 30s
Soru 1917Soru

A regional library recorded the daily number of public computer reservations over a 7-day period: 14,25,18,31,25,12,14, 25, 18, 31, 25, 12, and 2121. During the following week, 2 additional daily reservation values, xx and yy, were added to the dataset. If the median of the resulting 9-day dataset is equal to the mode of the original 7-day dataset, which of the following values could be the sum of xx and yy?

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Cevap: 54

Cevap

54
The mode of the original 7 values is 25. When 2 values (xx and yy) are added to form a 9-value dataset, the median is the 5th value when ordered. In the original sorted dataset (12,14,18,21,25,25,3112, 14, 18, 21, 25, 25, 31), there are only 3 values greater than or equal to 25. To make the 5th value of the combined 9-value list equal to 25, both added values must be at least 25 (x25x \ge 25 and y25y \ge 25). Consequently, their sum x+yx + y must be at least 5050. The only choice that satisfies x+y50x + y \ge 50 is 54.

Adım Adım Çözüm

1
Identify the mode of the original 7-day dataset.
The original values are 14,25,18,31,25,12,2114, 25, 18, 31, 25, 12, 21. The value 2525 appears twice, while all other numbers appear once. Therefore, the mode is 2525.
The question states that the target median of the 9-day dataset must equal the mode of the original dataset.
2
Sort the original 7-day dataset in ascending order.
The sorted original dataset is 12,14,18,21,25,25,3112, 14, 18, 21, 25, 25, 31.
Determining position-based metrics like median requires ordering the data.
3
Determine the condition required for the median of the 9-day dataset to be 25.
In a sorted 9-element dataset, the median is the 5th element. For the 5th element to be 2525, there must be at least 5 elements in the set that are greater than or equal to 2525. The original set contains 3 elements 25\ge 25 (25,25,3125, 25, 31). Thus, both new values xx and yy must be 25\ge 25.
If only one of xx or yy were 25\ge 25, there would only be 4 elements 25\ge 25, making the 5th element (median) less than 2525.
4
Calculate the lower bound for the sum x+yx + y and select the valid option.
Since x25x \geq 25 and y25y \geq 25, the sum must satisfy x+y25+25=50x + y \geq 25 + 25 = 50. Among the given options, only 5454 is greater than or equal to 5050.
Any sum less than 5050 violates the condition that both xx and yy are at least 2525.

Anahtar Kavram

Determining positional metrics (median) after dataset expansion
Soru 1918Soru

A specialty coffee shop prepares two custom coffee bean blends using Arabica and Robusta beans. The first 10-pound blend consists of 4 pounds of Arabica beans and 6 pounds of Robusta beans and costs $52\$52. The second 10-pound blend consists of 7 pounds of Arabica beans and 3 pounds of Robusta beans and costs $61\$61. What is the cost, in dollars, of 1 pound of Arabica coffee beans?

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Cevap: 7

Cevap

The cost of 1 pound of Arabica coffee beans is 7 dollars.
By setting up the system 4A+6R=524A + 6R = 52 and 7A+3R=617A + 3R = 61, we can simplify the first equation to 2A+3R=262A + 3R = 26. Subtracting this simplified equation from the second equation eliminates RR, giving 5A=355A = 35, which simplifies directly to A=7A = 7.

Adım Adım Çözüm

1
Define variables and set up the system of linear equations.
Let AA be the price per pound of Arabica beans and RR be the price per pound of Robusta beans.
Equation 1: 4A+6R=524A + 6R = 52
Equation 2: 7A+3R=617A + 3R = 61
Translating the quantitative relationship given in the problem statement into algebraic equations.
2
Simplify Equation 1 and eliminate variable RR by subtraction.
Dividing Equation 1 by 2 gives 2A+3R=262A + 3R = 26. Subtracting this from Equation 2 yields (7A+3R)(2A+3R)=6126(7A + 3R) - (2A + 3R) = 61 - 26, which reduces to 5A=355A = 35.
Matching coefficients of RR allows for straightforward elimination of RR.
3
Solve for variable AA.
A=7A = 7
Dividing 35 by 5 yields the price per pound of Arabica beans.

Anahtar Kavram

Solving a system of 2x2 linear equations using substitution or elimination.
Soru 1919Soru

What is the smallest positive integer that is a multiple of 18, 24, and 30, and is also a perfect square?

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Cevap: 3600

Cevap

The smallest positive integer that is a multiple of 18, 24, and 30, and is also a perfect square is 3600.
The least common multiple of 18, 24, and 30 is 360, which factors into 2332512^3 \cdot 3^2 \cdot 5^1. For an integer to be a perfect square, all exponents in its prime factorization must be even. Multiplying 360 by 25=102 \cdot 5 = 10 completes the odd exponents to even values (2432522^4 \cdot 3^2 \cdot 5^2), giving 3600, which is the smallest perfect square divisible by 18, 24, and 30.

Adım Adım Çözüm

1
Find the prime factorization of 18, 24, and 30
18=213218 = 2^1 \cdot 3^2, 24=233124 = 2^3 \cdot 3^1, 30=21315130 = 2^1 \cdot 3^1 \cdot 5^1
Decomposing numbers into prime factors allows calculation of the LCM and analysis of perfect square conditions.
2
Calculate the LCM of 18, 24, and 30
LCM(18,24,30)=233251=360\text{LCM}(18, 24, 30) = 2^3 \cdot 3^2 \cdot 5^1 = 360
Any common multiple must be a multiple of the LCM of these three numbers.
3
Determine the smallest factor required to make the prime exponents even
Multiply 360 by 2151=102^1 \cdot 5^1 = 10
A perfect square requires all prime exponents to be even; 2 has power 3 and 5 has power 1 in 360, so one more factor of 2 and one more factor of 5 are required.
4
Compute the final result
360×10=3600360 \times 10 = 3600
3600=243252=6023600 = 2^4 \cdot 3^2 \cdot 5^2 = 60^2, which is a perfect square.

Anahtar Kavram

Prime Factorization, LCM, and Exponent Properties of Perfect Squares
Soru 1920Soru

In GRE Sentence Equivalence questions, candidate choices often contain semantic traps designed to test contextual precision. Match each category of option choice on the left with its defining structural characteristic on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

True Contextual Synonym Pair
False Synonym Pair Trap
Topically Related Distractor
Structural / Polarity Mismatch

Eşleşmeler

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Cevap

True Contextual Synonym Pair matches words fitting contextual logic to yield equivalent sentence meanings; False Synonym Pair Trap matches dictionary synonyms conflicting with sentence logic; Topically Related Distractor matches words aligned with subject matter but lacking a synonymous pair; Structural / Polarity Mismatch matches words opposing sentence transition signals.
Matching each category to its exact description relies on distinguishing between semantic pair fit and context fit. True contextual synonym pairs satisfy both sentence context and pair equivalence. False synonym pairs satisfy pair equivalence in isolation but fail sentence context. Topically related distractors rely on surface subject-matter association but lack a synonym partner. Structural mismatches directly violate the polarity or logical signals of the stem.

Adım Adım Çözüm

1
Analyze the primary requirement of GRE Sentence Equivalence questions.
Sentence Equivalence requires selecting two words that independently complete the sentence with equivalent meanings.
Understanding the core objective allows proper categorization of correct answer traits versus trap types.
2
Identify the trap mechanism of False Synonym Pairs.
False synonyms are legitimate synonyms in the dictionary but fail the contextual requirements of the stem.
Test-takers often mistakenly choose pairs simply because they are synonyms, ignoring sentence fit.
3
Evaluate the function of Topically Related Distractors and Structural Mismatches.
Topical distractors fit the broad topic but lack a pair; structural mismatches violate sentence polarity signals.
Recognizing these distractor profiles enables rapid elimination during exam-like conditions.

Anahtar Kavram

Eliminating False Synonyms and Topically Related Distractors in Sentence Equivalence
ÖncekiSayfa 96 / 107Sonraki
Tüm alıştırma soruları — GRE General Test | Examkin