Soru

Zorluk: OrtaLimiting and Excess Reactants in Chemical Reactions
Zinc metal reacts with hydrochloric acid according to the balanced chemical equation:
Zn(s)+2HCl(aq)ZnCl2(aq)+H2(g)\text{Zn}_{(s)} + 2\text{HCl}_{(aq)} \rightarrow \text{ZnCl}_{2(aq)} + \text{H}_{2(g)}
If 13.0 g13.0\text{ g} of zinc is added to a solution containing 7.3 g7.3\text{ g} of hydrochloric acid, what mass of zinc remains unreacted after the reaction goes to completion?
(Zn=65.0, H=1.0, Cl=35.5\text{Zn} = 65.0,\text{ H} = 1.0,\text{ Cl} = 35.5)
  1. 6.5 g6.5\text{ g}Cevap
  2. B
    5.7 g5.7\text{ g}
  3. C
    0.0 g0.0\text{ g}
  4. D
    3.25 g3.25\text{ g}

Cevap

The mass of zinc remaining unreacted is 6.5 g6.5\text{ g}.
Converting the given masses into moles shows that 0.20 mol of zinc and 0.20 mol of hydrochloric acid are present. Since 1 mole of zinc requires 2 moles of hydrochloric acid, 0.20 mol of hydrochloric acid reacts with only 0.10 mol of zinc. Hydrochloric acid is completely consumed, leaving 0.10 mol (6.5 g) of zinc unreacted.

Adım Adım Çözüm

1
Calculate the molar masses of the reactants
Molar mass of Zn=65.0 g/mol\text{Zn} = 65.0\text{ g/mol}; Molar mass of HCl=1.0+35.5=36.5 g/mol\text{HCl} = 1.0 + 35.5 = 36.5\text{ g/mol}.
Molar masses are required to convert the given masses to mole quantities.
2
Determine the initial mole quantities of each reactant
Moles of Zn=13.0 g65.0 g/mol=0.20 mol\text{Zn} = \frac{13.0\text{ g}}{65.0\text{ g/mol}} = 0.20\text{ mol}; Moles of HCl=7.3 g36.5 g/mol=0.20 mol\text{HCl} = \frac{7.3\text{ g}}{36.5\text{ g/mol}} = 0.20\text{ mol}.
Chemical reactions occur according to mole ratios, not mass ratios.
3
Identify the limiting reactant and calculate the moles of zinc consumed
From the equation, 1 mol of Zn1\text{ mol of Zn} reacts with 2 mol of HCl2\text{ mol of HCl}. Thus, 0.20 mol of HCl0.20\text{ mol of HCl} requires 0.202=0.10 mol of Zn\frac{0.20}{2} = 0.10\text{ mol of Zn}. HCl\text{HCl} is the limiting reactant.
The limiting reactant determines the extent of the reaction.
4
Calculate the unreacted moles and mass of zinc
Unreacted moles of Zn=0.20 mol0.10 mol=0.10 mol\text{Zn} = 0.20\text{ mol} - 0.10\text{ mol} = 0.10\text{ mol}. Unreacted mass of Zn=0.10 mol×65.0 g/mol=6.5 g\text{Zn} = 0.10\text{ mol} \times 65.0\text{ g/mol} = 6.5\text{ g}.
Subtracting consumed moles from initial moles gives the remaining amount.

Anahtar Kavram

Limiting and Excess Reactants
Bu soruyu puanla