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Zorluk: KolayMatrices and Determinants

Find the product matrix ABAB given that A=(1203)A = \begin{pmatrix} 1 & 2 \\ 0 & 3 \end{pmatrix} and B=(4512)B = \begin{pmatrix} 4 & 5 \\ 1 & 2 \end{pmatrix}.

  1. (6936)\begin{pmatrix} 6 & 9 \\ 3 & 6 \end{pmatrix}Cevap
  2. B
    (41006)\begin{pmatrix} 4 & 10 \\ 0 & 6 \end{pmatrix}
  3. C
    (42318)\begin{pmatrix} 4 & 23 \\ 1 & 8 \end{pmatrix}
  4. D
    (5715)\begin{pmatrix} 5 & 7 \\ 1 & 5 \end{pmatrix}

Cevap

(6936)\begin{pmatrix} 6 & 9 \\ 3 & 6 \end{pmatrix}
The matrix product ABAB is found by performing row-by-column multiplication. Computing row 1 gives (1)(4)+(2)(1)=6(1)(4)+(2)(1) = 6 and (1)(5)+(2)(2)=9(1)(5)+(2)(2) = 9. Computing row 2 gives (0)(4)+(3)(1)=3(0)(4)+(3)(1) = 3 and (0)(5)+(3)(2)=6(0)(5)+(3)(2) = 6. Thus, the resulting matrix is (6936)\begin{pmatrix} 6 & 9 \\ 3 & 6 \end{pmatrix}.

Adım Adım Çözüm

1
Set up row-by-column matrix multiplication formula for 2×22 \times 2 matrices.
The entry at row ii, column jj of product ABAB is the dot product of row ii of AA and column jj of BB.
Matrix multiplication requires combining rows of the left matrix with columns of the right matrix.
2
Calculate row 1 entries of the product matrix.
First element: (1)(4)+(2)(1)=4+2=6(1)(4) + (2)(1) = 4 + 2 = 6. Second element: (1)(5)+(2)(2)=5+4=9(1)(5) + (2)(2) = 5 + 4 = 9.
Multiply elements of row 1 of AA by corresponding elements of columns 1 and 2 of BB and sum them.
3
Calculate row 2 entries of the product matrix.
Third element: (0)(4)+(3)(1)=0+3=3(0)(4) + (3)(1) = 0 + 3 = 3. Fourth element: (0)(5)+(3)(2)=0+6=6(0)(5) + (3)(2) = 0 + 6 = 6.
Multiply elements of row 2 of AA by corresponding elements of columns 1 and 2 of BB and sum them.
4
Assemble the product matrix.
AB=(6936)AB = \begin{pmatrix} 6 & 9 \\ 3 & 6 \end{pmatrix}.
Combine all computed row and column entries into a single 2×22 \times 2 matrix.

Anahtar Kavram

Matrix Multiplication (2×22 \times 2 Matrix Product)
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