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Zorluk: OrtaCombinations

A music festival coordinator needs to select 44 bands to perform from a pool of 88 available bands. If 22 specific bands insist on either both being selected or neither being selected, in how many different ways can the 44 bands be chosen?

  1. 3030Cevap
  2. B
    6060
  3. C
    7070
  4. D
    390390

Cevap

The total number of ways to choose the bands under the given condition is 3030.
To satisfy the condition that the two specific bands are either both chosen or neither chosen, we evaluate two distinct cases. Case 1 (both chosen) requires choosing 22 additional bands from the remaining 66, yielding 6C2=15{}^6C_2 = 15 ways. Case 2 (neither chosen) requires choosing all 44 bands from the remaining 66, yielding 6C4=15{}^6C_4 = 15 ways. Adding both cases gives 15+15=3015 + 15 = 30 ways.

Adım Adım Çözüm

1
Analyze Case 1: Both specific bands are selected.
If both specific bands are included, we only need to select 22 more bands from the remaining 66 bands. The number of ways is 6C2=6×52×1=15{}^6C_2 = \frac{6 \times 5}{2 \times 1} = 15.
Since order does not matter in forming a group of performers, we use combinations.
2
Analyze Case 2: Neither of the specific bands is selected.
If neither of the 22 specific bands is chosen, all 44 bands must be selected from the remaining 66 bands. The number of ways is 6C4=6C2=15{}^6C_4 = {}^6C_2 = 15.
Excluding the 22 specific bands leaves 66 candidate bands to choose 44 from.
3
Sum the mutually exclusive cases.
\text{Total ways} = 15 + 15 = 30.
The two scenarios are disjoint, so the addition principle applies.

Anahtar Kavram

Combinations with conditional restrictions
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