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Zorluk: OrtaMatrices and Determinants

Given the matrices P=(2314)P = \begin{pmatrix} 2 & 3 \\ 1 & 4 \end{pmatrix} and Q=(5021)Q = \begin{pmatrix} 5 & 0 \\ -2 & 1 \end{pmatrix}, what is the product matrix PQPQ?

  1. A
    (10024)\begin{pmatrix} 10 & 0 \\ -2 & 4 \end{pmatrix}
  2. (4334)\begin{pmatrix} 4 & 3 \\ -3 & 4 \end{pmatrix}Cevap
  3. C
    (101532)\begin{pmatrix} 10 & 15 \\ -3 & -2 \end{pmatrix}
  4. D
    (163134)\begin{pmatrix} 16 & 3 \\ 13 & 4 \end{pmatrix}

Cevap

The product matrix PQPQ is (4334)\begin{pmatrix} 4 & 3 \\ -3 & 4 \end{pmatrix}.
To find PQPQ, multiply each row of matrix PP by each column of matrix QQ. The entry in row 1, column 1 is 2(5)+3(2)=42(5) + 3(-2) = 4. The entry in row 1, column 2 is 2(0)+3(1)=32(0) + 3(1) = 3. The entry in row 2, column 1 is 1(5)+4(2)=31(5) + 4(-2) = -3. The entry in row 2, column 2 is 1(0)+4(1)=41(0) + 4(1) = 4. Putting these together yields (4334)\begin{pmatrix} 4 & 3 \\ -3 & 4 \end{pmatrix}.

Adım Adım Çözüm

1
Compute the entries of the top row of PQPQ using the first row of PP and both columns of QQ.
First entry: (2)(5)+(3)(2)=106=4(2)(5) + (3)(-2) = 10 - 6 = 4. Second entry: (2)(0)+(3)(1)=0+3=3(2)(0) + (3)(1) = 0 + 3 = 3.
Matrix entry (1,1)(1,1) is the dot product of Row 1 of PP and Column 1 of QQ; entry (1,2)(1,2) is the dot product of Row 1 of PP and Column 2 of QQ.
2
Compute the entries of the bottom row of PQPQ using the second row of PP and both columns of QQ.
Third entry: (1)(5)+(4)(2)=58=3(1)(5) + (4)(-2) = 5 - 8 = -3. Fourth entry: (1)(0)+(4)(1)=0+4=4(1)(0) + (4)(1) = 0 + 4 = 4.
Matrix entry (2,1)(2,1) is the dot product of Row 2 of PP and Column 1 of QQ; entry (2,2)(2,2) is the dot product of Row 2 of PP and Column 2 of QQ.
3
Assemble the computed entries into a 2×22 \times 2 matrix.
PQ=(4334)PQ = \begin{pmatrix} 4 & 3 \\ -3 & 4 \end{pmatrix}.
Combining row results gives the final product matrix.

Anahtar Kavram

Matrix Multiplication (Row-by-Column Dot Product)
Tahmini Süre:1m 15s
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