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Zorluk: OrtaLaws of Chemical Combination (Conservation of Mass, Definite & Multiple Proportions)

A sample of a pure iron oxide synthesized in a laboratory contains 5.60 g5.60\text{ g} of iron and 2.40 g2.40\text{ g} of oxygen. According to the Law of Definite Proportions, what is the mass of iron, in grams, present in a 20.0 g20.0\text{ g} sample of the same iron oxide collected from a natural deposit?

Cevap: 14 g

Cevap

The mass of iron present in the 20.0 g sample of iron oxide is 14.0 g.
According to the Law of Definite Proportions, a pure chemical compound always contains the same elements combined together in the exact same proportion by mass, regardless of its source or method of preparation. In the laboratory sample, 8.00 g8.00\text{ g} of iron oxide contains 5.60 g5.60\text{ g} of iron, giving an iron mass composition of 70%70\%. Therefore, a 20.0 g20.0\text{ g} natural sample of the same compound must also contain 70%70\% iron by mass, which equals 14.0 g14.0\text{ g}.

Adım Adım Çözüm

1
Calculate total mass of the laboratory sample
5.60 g+2.40 g=8.00 g5.60\text{ g} + 2.40\text{ g} = 8.00\text{ g}
The total mass of the compound is the sum of the constituent element masses (Law of Conservation of Mass).
2
Find the mass percentage/fraction of iron
5.60 g8.00 g=0.70\frac{5.60\text{ g}}{8.00\text{ g}} = 0.70 (or 70%70\%)
By the Law of Definite Proportions, the mass ratio of elements in a pure compound is constant.
3
Calculate mass of iron in the 20.0 g natural sample
0.70×20.0 g=14.0 g0.70 \times 20.0\text{ g} = 14.0\text{ g}
Applying the constant mass composition percentage to the new sample mass.

Anahtar Kavram

Law of Definite Proportions (Constant Composition)
Tahmini Süre:1m 30s
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