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Zorluk: ZorDrainage Patterns and River Basin Analysis

On a topographical map extract drawn at a scale of 1:50,0001:50,000, a river valley features V-shaped contour lines that point consistently toward the south-west. Point X lies directly on the 450 m450\text{ m} contour line, while Point Y lies 5 km5\text{ km} further down the channel path on the 200 m200\text{ m} contour line. Based on these topographic observations, toward which direction does the river flow, and what is its average channel gradient between Point X and Point Y?

  1. A
    Toward the south-west at a gradient of 1 in 201\text{ in }20
  2. Toward the north-east at a gradient of 1 in 201\text{ in }20Cevap
  3. C
    Toward the north-east at a gradient of 1 in 501\text{ in }50
  4. D
    Toward the south-west at a gradient of 1 in 501\text{ in }50

Cevap

The river flows toward the north-east at an average channel gradient of 1 in 201\text{ in }20.
In topographic map interpretation, contour lines form 'V' shapes when crossing river valleys, with the apex of the 'V' pointing upstream toward higher elevation. Because the V-shapes point south-west toward the 450 m450\text{ m} contour, the river must flow downstream toward the lower 200 m200\text{ m} contour in the north-east direction. Furthermore, the gradient calculation requires dividing the Vertical Interval (450 m200 m=250 m450\text{ m} - 200\text{ m} = 250\text{ m}) by the Horizontal Equivalent (5 km=5,000 m5\text{ km} = 5,000\text{ m}), giving 2505,000=120\frac{250}{5,000} = \frac{1}{20} (or 1 in 201\text{ in }20).

Adım Adım Çözüm

1
Determine flow direction from V-shaped contour lines
The river flows toward the north-east.
V-shaped contour lines crossing a river valley always point apex-upstream (toward higher ground/source). Since the V's point south-west (toward 450 m450\text{ m}), the river flows down the elevation slope toward the north-east (toward 200 m200\text{ m}).
2
Calculate Vertical Interval (VI)
VI=250 m\text{VI} = 250\text{ m}
Difference in elevation between Point X (450 m450\text{ m}) and Point Y (200 m200\text{ m}) is 450 m200 m=250 m450\text{ m} - 200\text{ m} = 250\text{ m}.
3
Convert Horizontal Equivalent (HE) to consistent units
HE=5,000 m\text{HE} = 5,000\text{ m}
The horizontal distance along the river course is 5 km=5×1,000 m=5,000 m5\text{ km} = 5 \times 1,000\text{ m} = 5,000\text{ m}.
4
Compute stream gradient ratio
Gradient=250 m5,000 m=120\text{Gradient} = \frac{250\text{ m}}{5,000\text{ m}} = \frac{1}{20} (1 in 201\text{ in }20)
Gradient is expressed as VI/HE\text{VI} / \text{HE}, simplifying 2505000\frac{250}{5000} to 120\frac{1}{20}.

Anahtar Kavram

Valley Contour Interpretation and Topographic Stream Gradient Analysis
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