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Zorluk: OrtaBinary Operations

A binary operation \otimes on the set of real numbers R\mathbb{R} is defined by ab=a2+b2aba \otimes b = a^2 + b^2 - ab. If x3=19x \otimes 3 = 19 and x>0x > 0, find the value of xx.

Cevap: 5

Cevap

The value of xx is 55.
Applying the operation rule gives x2+323x=19x^2 + 3^2 - 3x = 19, which simplifies to x23x10=0x^2 - 3x - 10 = 0. Factoring this equation yields (x5)(x+2)=0(x - 5)(x + 2) = 0. Since xx is constrained to be positive (x>0x > 0), the unique valid answer is 55.

Adım Adım Çözüm

1
Apply the definition of the binary operation to x3x \otimes 3
x2+323(x)=x23x+9x^2 + 3^2 - 3(x) = x^2 - 3x + 9
Substitute a=xa = x and b=3b = 3 into ab=a2+b2aba \otimes b = a^2 + b^2 - ab.
2
Equate the result to 19 and rearrange into standard quadratic form
x23x10=0x^2 - 3x - 10 = 0
Subtract 19 from both sides to set the quadratic equation to zero.
3
Factor the quadratic equation and solve for xx
(x5)(x+2)=0    x=5 or x=2(x - 5)(x + 2) = 0 \implies x = 5 \text{ or } x = -2
Find two numbers that multiply to 10-10 and add up to 3-3.
4
Apply the restriction x>0x > 0
x=5x = 5
Reject the negative solution x=2x = -2 because xx must be strictly positive.

Anahtar Kavram

Evaluation of Binary Operations and Solving Quadratic Equations
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