Propanoic acid is heated under reflux with ethanol in the presence of concentrated tetraoxosulfate(VI) acid to produce a sweet-smelling liquid ester. This ester is separated and subsequently boiled under reflux with aqueous potassium hydroxide until saponification is complete. Which pair of organic products is isolated from the saponification mixture?
- Potassium propanoate and ethanolCevap
- BPotassium ethanoate and propan-1-ol
- CPropanoic acid and ethanol
- DEthanoic acid and propan-1-ol
Cevap
The isolated products of the alkaline hydrolysis are potassium propanoate and ethanol.
In the initial esterification reaction, propanoic acid and ethanol react in the presence of concentrated tetraoxosulfate(VI) acid catalyst to form ethyl propanoate (). When ethyl propanoate is subsequently hydrolyzed under basic conditions with aqueous potassium hydroxide (saponification), the carbonyl-oxygen ester linkage is irreversibly cleaved. This forms the potassium salt of the carboxylic acid (potassium propanoate) and regenerates the alcohol (ethanol).
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Anahtar Kavram
Alkaline Hydrolysis (Saponification) of Esters
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