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Zorluk: KolayBinary Operations

A binary operation ⊕\oplus is defined on the set of real numbers R\mathbb{R} by a⊕b=2a+3b−5a \oplus b = 2a + 3b - 5. What is the value of (4⊕1)⊕2(4 \oplus 1) \oplus 2?

Cevap: 13

Cevap

The value of (4⊕1)⊕2(4 \oplus 1) \oplus 2 is 13.
First, evaluate the inner expression 4⊕14 \oplus 1 using a=4a = 4 and b=1b = 1, which gives 2(4)+3(1)−5=8+3−5=62(4) + 3(1) - 5 = 8 + 3 - 5 = 6. Then, substitute this result into the outer expression to evaluate 6⊕26 \oplus 2 using a=6a = 6 and b=2b = 2, yielding 2(6)+3(2)−5=12+6−5=132(6) + 3(2) - 5 = 12 + 6 - 5 = 13.

Adım Adım Çözüm

1
Evaluate the inner operation 4⊕14 \oplus 1
6
Substitute a=4a = 4 and b=1b = 1 into the operational rule a⊕b=2a+3b−5a \oplus b = 2a + 3b - 5.
2
Evaluate the outer operation using the result from Step 1: 6⊕26 \oplus 2
13
Substitute a=6a = 6 and b=2b = 2 into the operational rule a⊕b=2a+3b−5a \oplus b = 2a + 3b - 5.

Anahtar Kavram

Evaluation of Binary Operations
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