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Zorluk: OrtaMendel's First Law and Monohybrid Inheritance

In fruit flies (*Drosophila melanogaster*), the allele for normal wings (VV) is completely dominant over the allele for vestigial wings (vv). Match each parental cross listed on the left with its corresponding expected offspring phenotypic or genotypic ratio on the right.

  • Cross between two heterozygous normal-winged flies (Vv×VvVv \times Vv)3 : 1 phenotypic ratio of normal wings to vestigial wings
  • Test cross of a heterozygous normal-winged fly (Vv×vvVv \times vv)1 : 1 phenotypic ratio of normal wings to vestigial wings
  • Cross between a homozygous normal-winged fly and a vestigial-winged fly (VV×vvVV \times vv)100% normal wings (all offspring are heterozygous VvVv)
  • Cross between a homozygous normal-winged fly and a heterozygous fly (VV×VvVV \times Vv)100% normal wings (1 : 1 genotypic ratio of VVVV to VvVv)

Cevap

Cross Vv×VvVv \times Vv matches 3:1 phenotypic ratio (normal:vestigial). Test cross Vv×vvVv \times vv matches 1:1 phenotypic ratio. Cross VV×vvVV \times vv matches 100% normal wings (all VvVv). Cross VV×VvVV \times Vv matches 100% normal wings (1:1 genotypic ratio VV:VvVV:Vv).
Each monohybrid cross yields specific offspring ratios according to Mendel's Law of Segregation. Crossing two heterozygotes (Vv×VvVv \times Vv) yields a 3:1 phenotypic ratio. A test cross (Vv×vvVv \times vv) yields a 1:1 phenotypic ratio. Crossing homozygous dominant with homozygous recessive (VV×vvVV \times vv) produces 100% heterozygous offspring (VvVv). Crossing homozygous dominant with a heterozygote (VV×VvVV \times Vv) yields 100% dominant phenotype with a 1:1 genotypic ratio of VVVV to VvVv.

Adım Adım Çözüm

1
Analyze the cross Vv×VvVv \times Vv
Produces genotypes 1 VV:2 Vv:1 vv1\ VV : 2\ Vv : 1\ vv. Since VV is dominant, 3 parts show normal wings and 1 part shows vestigial wings (3:1 phenotypic ratio).
Mendel's Law of Segregation states that two alleles of a gene separate during gamete formation.
2
Analyze the test cross Vv×vvVv \times vv
Gametes from VvVv are VV and vv; gametes from vvvv are vv. Offspring are 50% VvVv and 50% vvvv (1:1 phenotypic ratio).
A monohybrid test cross pairs a heterozygous individual with a homozygous recessive individual.
3
Analyze the cross VV×vvVV \times vv
All offspring inherit VV from the dominant parent and vv from the recessive parent, resulting in 100% VvVv (100% normal wings).
Homozygous dominant crossed with homozygous recessive produces uniformly heterozygous F1 offspring.
4
Analyze the cross VV×VvVV \times Vv
Offspring genotypes are 50% VVVV and 50% VvVv. Because all possess at least one dominant allele VV, 100% display normal wings.
The dominant allele masks the recessive allele in heterozygous individuals.

Anahtar Kavram

Mendel's First Law and Monohybrid Inheritance Ratios
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