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Zorluk: ZorElementary Surveying Instruments and Fieldwork

During a fieldwork measurement along a baseline, a geography student uses a steel tape with a nominal length of 30.00 m30.00\text{ m}. Due to high ambient temperature, the actual length of the tape has expanded to 30.15 m30.15\text{ m}. If the uncorrected recorded distance for the baseline is 450.00 m450.00\text{ m}, what is the true ground distance and the nature of the measurement error?

  1. The true ground distance is 452.25 m452.25\text{ m}, representing a cumulative negative error.Cevap
  2. B
    The true ground distance is 447.75 m447.75\text{ m}, representing a cumulative positive error.
  3. C
    The true ground distance is 452.25 m452.25\text{ m}, representing a compensatory positive error.
  4. D
    The true ground distance is 447.75 m447.75\text{ m}, representing a random field error.

Cevap

The true ground distance is 452.25 m452.25\text{ m}, representing a cumulative negative error.
The correct answer states that the true ground distance is 452.25 m452.25\text{ m} and represents a cumulative negative error. When a 30.00 m30.00\text{ m} tape expands to 30.15 m30.15\text{ m}, every time the tape is laid out, 30.15 m30.15\text{ m} of ground is covered, but only 30.00 m30.00\text{ m} is added to the tally. Multiplying 450.00 m450.00\text{ m} by the ratio 30.15/30.0030.15 / 30.00 gives a true ground distance of 452.25 m452.25\text{ m}. Because the recorded distance is shorter than the actual ground distance, the error is negative, and because it acts consistently in one direction throughout the survey, it is cumulative.

Adım Adım Çözüm

1
Determine the total number of tape applications made during the baseline measurement.
Number of applications N=450.00 m30.00 m=15N = \frac{450.00\text{ m}}{30.00\text{ m}} = 15.
The recorded distance is measured in standard 30.00 m30.00\text{ m} units.
2
Calculate the true ground distance using the actual expanded length of the tape.
True Distance =15×30.15 m=452.25 m= 15 \times 30.15\text{ m} = 452.25\text{ m} (or using Ltrue=Lrecorded×ll=450.00×30.1530.00=452.25 mL_{\text{true}} = L_{\text{recorded}} \times \frac{l'}{l} = 450.00 \times \frac{30.15}{30.00} = 452.25\text{ m}).
Each application of the expanded tape spans 30.15 m30.15\text{ m} of ground, while only 30.00 m30.00\text{ m} is recorded.
3
Classify the nature and sign of the survey error.
The recorded measurement is 2.25 m2.25\text{ m} less than the true distance (450.00 m<452.25 m450.00\text{ m} < 452.25\text{ m}). The error in the recorded distance is negative and accumulates proportionally with line length, making it a cumulative negative error.
When a measuring tape is too long, the recorded distance is always less than the true distance, causing a cumulative negative error.

Anahtar Kavram

Tape Length Error Corrections & Cumulative vs. Compensatory Errors
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