Soru

Zorluk: KolayMeasures of Central Tendency for Grouped Data

The table below shows the distribution of quiz scores for a class of students:

Score IntervalFrequency (ff)
151 - 533
6106 - 1055
111511 - 1577
162016 - 2055

Calculate the mean score of the distribution.

Cevap: 11.5

Cevap

The mean score of the distribution is 11.5.
The mean for a grouped frequency table is calculated by taking the sum of the products of each midpoint (xx) and its frequency (ff), divided by the sum of all frequencies (ff). Here, fx=230\sum fx = 230 and f=20\sum f = 20, yielding xˉ=11.5\bar{x} = 11.5.

Adım Adım Çözüm

1
Determine the class midpoints (xx) for each interval.
Midpoints are 3, 8, 13, and 18.
Midpoints serve as the representative values for each class interval.
2
Calculate the product of each midpoint and frequency (fxfx).
Products are 9, 40, 91, and 90.
To find the total contribution of each class interval.
3
Find the sum of all frequencies (f\sum f) and products (fx\sum fx).
f=20\sum f = 20 and fx=230\sum fx = 230.
These totals are required for the grouped mean formula.
4
Divide the total product sum by total frequency.
xˉ=23020=11.5\bar{x} = \frac{230}{20} = 11.5.
Applying the formula for the mean of grouped data xˉ=fxf\bar{x} = \frac{\sum fx}{\sum f}.

Anahtar Kavram

Mean of Grouped Data using Class Midpoints
Bu soruyu puanla