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Zorluk: KolayRules of Differentiation (Product, Quotient, and Chain Rules)

If y=(3x1)4y = (3x - 1)^4, what is the numerical value of dydx\frac{dy}{dx} evaluated at x=1x = 1?

Cevap: 96

Cevap

96
Applying the chain rule ddx[un]=nun1dudx\frac{d}{dx}[u^n] = n u^{n-1} \cdot \frac{du}{dx} to y=(3x1)4y = (3x - 1)^4 gives dydx=4(3x1)33=12(3x1)3\frac{dy}{dx} = 4(3x - 1)^3 \cdot 3 = 12(3x - 1)^3. Evaluating this expression at x=1x = 1 yields 12(3(1)1)3=12(2)3=9612(3(1) - 1)^3 = 12(2)^3 = 96.

Adım Adım Çözüm

1
Differentiate y=(3x1)4y = (3x - 1)^4 with respect to xx using the chain rule.
dydx=12(3x1)3\frac{dy}{dx} = 12(3x - 1)^3
Differentiate the outer power function to get 4(3x1)34(3x - 1)^3 and multiply by the derivative of the inner linear function 3x13x - 1, which is 3.
2
Substitute x=1x = 1 into the derivative function.
96
Evaluating 12(3(1)1)312(3(1) - 1)^3 gives 12(2)3=12×8=9612(2)^3 = 12 \times 8 = 96.

Anahtar Kavram

Chain Rule of Differentiation
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