Soru

Zorluk: OrtaCharles's Law and Absolute Temperature Scale

A sample of oxygen gas occupies a volume of 450 cm3450\text{ cm}^3 at a temperature of 27C27^\circ\text{C}. If the pressure remains constant, what will be the volume of the gas when its temperature is increased to 207C207^\circ\text{C}?

  1. 720 cm3720\text{ cm}^3Cevap
  2. B
    3450 cm33450\text{ cm}^3
  3. C
    281 cm3281\text{ cm}^3
  4. D
    630 cm3630\text{ cm}^3

Cevap

The volume of the gas at 207C207^\circ\text{C} is 720 cm3720\text{ cm}^3.
According to Charles's Law, the volume of a gas is directly proportional to its absolute temperature when pressure remains constant (V1/T1=V2/T2V_1/T_1 = V_2/T_2). Converting the temperatures to Kelvin (T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=207+273=480 KT_2 = 207 + 273 = 480\text{ K}) and calculating gives V2=450×(480/300)=720 cm3V_2 = 450 \times (480 / 300) = 720\text{ cm}^3.

Adım Adım Çözüm

1
Convert temperatures from Celsius to the absolute (Kelvin) scale.
T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=207+273=480 KT_2 = 207 + 273 = 480\text{ K}.
Gas laws require temperatures to be expressed on the absolute temperature scale (Kelvin).
2
Apply Charles's Law equation.
V1T1=V2T2    V2=V1×T2T1\frac{V_1}{T_1} = \frac{V_2}{T_2} \implies V_2 = V_1 \times \frac{T_2}{T_1}.
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature.
3
Substitute the known values and calculate V2V_2.
V2=450×480300=450×1.6=720 cm3V_2 = 450 \times \frac{480}{300} = 450 \times 1.6 = 720\text{ cm}^3.
Completing the arithmetic yields the final volume.

Anahtar Kavram

Charles's Law states that at constant pressure, the volume of a given mass of gas is directly proportional to its absolute temperature (VTV \propto T).
Bu soruyu puanla