Soru

Zorluk: KolayGas Laws and the Ideal Gas Equation

A sample of ideal gas in a syringe occupies a volume of 300 cm3300\text{ cm}^3 at a temperature of 27C27^\circ\text{C}. If the pressure of the gas remains constant, what is its volume in cm3\text{cm}^3 when the temperature is raised to 127C127^\circ\text{C}?

Cevap: 400 cm³

Cevap

400 cm³
According to Charles's Law, at constant pressure, the volume of a given mass of gas is directly proportional to its absolute temperature (VTV \propto T). Converting the given temperatures to kelvins yields T1=300 KT_1 = 300\text{ K} and T2=400 KT_2 = 400\text{ K}. Applying V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2} gives V2=300×400300=400 cm3V_2 = \frac{300 \times 400}{300} = 400\text{ cm}^3.

Adım Adım Çözüm

1
Convert the initial and final temperatures from degrees Celsius to kelvins.
T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=127+273=400 KT_2 = 127 + 273 = 400\text{ K}
Gas law calculations require absolute temperature measured on the kelvin scale.
2
Apply Charles's Law, which relates volume and absolute temperature at constant pressure.
V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}
The pressure of the gas is maintained constant.
3
Substitute the values into the equation and solve for the final volume V2V_2.
300 cm3300 K=V2400 K    V2=400 cm3\frac{300\text{ cm}^3}{300\text{ K}} = \frac{V_2}{400\text{ K}} \implies V_2 = 400\text{ cm}^3
Cross-multiplying gives V2=300×400300=400 cm3V_2 = \frac{300 \times 400}{300} = 400\text{ cm}^3.

Anahtar Kavram

Charles's Law
Bu soruyu puanla