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Zorluk: ZorModular Arithmetic

If xx is the least positive integer satisfying the modular congruence 4x+93(mod11)4x + 9 \equiv 3 \pmod{11}, what is the value of (x25x+2)(mod11)(x^2 - 5x + 2) \pmod{11} expressed in standard non-negative remainder form?

  1. A
    2
  2. B
    4
  3. C
    7
  4. 9Cevap

Cevap

The value of (x25x+2)(mod11)(x^2 - 5x + 2) \pmod{11} in standard non-negative remainder form is 9.
Solving 4x+93(mod11)4x + 9 \equiv 3 \pmod{11} yields 4x65(mod11)4x \equiv -6 \equiv 5 \pmod{11}. Multiplying by 3 (the inverse of 4 mod 11) gives x154(mod11)x \equiv 15 \equiv 4 \pmod{11}. Evaluating (x25x+2)(x^2 - 5x + 2) at x=4x = 4 gives 1620+2=216 - 20 + 2 = -2. Converting 2-2 into the standard non-negative remainder range [0,10][0, 10] gives 2+11=9-2 + 11 = 9.

Adım Adım Çözüm

1
Isolate the variable term in the linear modular congruence
4x396(mod11)4x \equiv 3 - 9 \equiv -6 \pmod{11}
Subtract 9 from both sides of the congruence.
2
Convert the negative right-hand side to a non-negative residue modulo 11
4x6+115(mod11)4x \equiv -6 + 11 \equiv 5 \pmod{11}
Add the modulus 11 to obtain the canonical non-negative equivalent.
3
Solve for xx by multiplying by the multiplicative inverse of 4 modulo 11
Since 4×3=121(mod11)4 \times 3 = 12 \equiv 1 \pmod{11}, multiply both sides by 3: x5×3=154(mod11)x \equiv 5 \times 3 = 15 \equiv 4 \pmod{11}. Thus, the least positive integer is x=4x = 4.
The modular inverse of 4 modulo 11 is 3.
4
Substitute x=4x = 4 into the expression (x25x+2)(x^2 - 5x + 2)
425(4)+2=1620+2=24^2 - 5(4) + 2 = 16 - 20 + 2 = -2
Evaluate the quadratic expression using the calculated value of xx.
5
Express 2-2 in canonical non-negative remainder form modulo 11
2+11=9(mod11)-2 + 11 = 9 \pmod{11}
Add the modulus 11 to convert the negative result to a non-negative remainder within [0,10][0, 10].

Anahtar Kavram

Solving linear modular congruences and converting negative remainders to canonical form
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