Tüm alıştırma soruları

13931 soru

Soru 6801Soru

Apex Flour Mills Plc and Zenith Bakery Products Ltd agree to merge their operations into a single company so that wheat flour milling and commercial bread baking are managed under one corporate structure. Which type of business combination does this merger illustrate?

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Cevap: Vertical combination

Cevap

Vertical combination
The correct option is vertical combination because the merger unites two businesses operating at sequential stages of the same product pipeline: flour milling provides the essential ingredient used in commercial bread baking.

Adım Adım Çözüm

1
Analyze the business activities of the merging entities
Apex Flour Mills Plc produces flour (an intermediate input), while Zenith Bakery Products Ltd bakes bread (a finished consumer product).
Identifying the production stage of each firm helps determine the axis of combination.
2
Determine the relationship between the stages of production
The two firms operate at successive, complementary stages of the supply chain in the food manufacturing sector.
Combining successive stages from raw material processing to final consumption defines vertical integration.
3
Match the scenario to the appropriate business combination classification
The transaction represents a vertical combination.
Vertical combinations unite firms engaged at sequential levels of production or distribution within the same overall industry.

Anahtar Kavram

Vertical Business Combination
Soru 6802Soru

A fixed mass of gas occupies a volume of 800 cm3800\text{ cm}^3 at a pressure of 1.5 atm1.5\text{ atm} under isothermal conditions. What is the final volume of the gas in cm3\text{cm}^3 if the pressure is reduced to 570 mmHg570\text{ mmHg}? (1 atm=760 mmHg1\text{ atm} = 760\text{ mmHg})

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Cevap: 1600 cm31600\text{ cm}^3

Cevap

The final volume of the gas is 1600 cm31600\text{ cm}^3.
Under isothermal conditions, Boyle's Law applies (P1V1=P2V2P_1V_1 = P_2V_2). Converting the initial pressure of 1.5 atm1.5\text{ atm} to mmHg\text{mmHg} gives 1140 mmHg1140\text{ mmHg}. Substituting the values into 1140×800=570×V21140 \times 800 = 570 \times V_2 yields V2=1600 cm3V_2 = 1600\text{ cm}^3.

Adım Adım Çözüm

1
Convert the initial pressure (P1P_1) to the same unit as the final pressure (P2P_2).
P1=1.5 atm×760 mmHg/atm=1140 mmHgP_1 = 1.5\text{ atm} \times 760\text{ mmHg/atm} = 1140\text{ mmHg}.
Units of pressure must be consistent before applying gas law equations.
2
Apply Boyle's Law formula for isothermal conditions.
P1V1=P2V2    1140 mmHg×800 cm3=570 mmHg×V2P_1V_1 = P_2V_2 \implies 1140\text{ mmHg} \times 800\text{ cm}^3 = 570\text{ mmHg} \times V_2.
Boyle's Law states that for a fixed mass of gas at constant temperature, pressure and volume are inversely proportional.
3
Rearrange the equation to solve for V2V_2.
V2=1140×800570=1600 cm3V_2 = \frac{1140 \times 800}{570} = 1600\text{ cm}^3.
Calculates the expanded volume resulting from the decrease in pressure.

Anahtar Kavram

Boyle's Law (P1V1=P2V2P_1V_1 = P_2V_2 at constant temperature)
Tahmini Süre:1m 30s
Soru 6803Soru

An electric iron rated at 1200W1200\,\text{W} is operated for 5hours5\,\text{hours} each day for a period of 30days30\,\text{days}. If electrical energy costs 20.00\text{₦}20.00 per kilowatt-hour (kWh\text{kWh}), what is the total cost of electricity consumed by the iron over this period in Naira (\text{₦})?

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Cevap: 3600

Cevap

The total cost of electricity consumed by the iron over the 30-day period is 3600 Naira.
To find the cost of electrical energy in commercial units, express power in kilowatts (1.2kW1.2\,\text{kW}) and time in total hours (150h150\,\text{h}). The energy consumed is 1.2×150=180kWh1.2 \times 150 = 180\,\text{kWh}. At a tariff of 20.00\text{₦}20.00 per kWh\text{kWh}, the total cost is 180×20=3600Naira180 \times 20 = 3600\,\text{Naira}.

Adım Adım Çözüm

1
Convert the power rating of the appliance from watts to kilowatts
P=1200W1000=1.2kWP = \frac{1200\,\text{W}}{1000} = 1.2\,\text{kW}
Commercial energy consumption is calculated in kilowatt-hours (kWh), requiring power in kilowatts.
2
Calculate the total operating time in hours
t=5hours/day×30days=150hourst = 5\,\text{hours/day} \times 30\,\text{days} = 150\,\text{hours}
The usage duration across the month must be expressed in total hours.
3
Determine electrical energy consumed in kWh
E=P×t=1.2kW×150h=180kWhE = P \times t = 1.2\,\text{kW} \times 150\,\text{h} = 180\,\text{kWh}
Energy is the product of power in kilowatts and time in hours.
4
Calculate total cost of energy consumed
Total Cost=180kWh×20.00/kWh=3600\text{Total Cost} = 180\,\text{kWh} \times \text{₦}20.00/\text{kWh} = \text{₦}3600
Total cost is found by multiplying energy in kWh by the unit tariff rate.

Anahtar Kavram

Commercial electrical energy unit (kWh) and billing calculation
Soru 6804Soru

Concentrated tetraoxosulfate(VI) acid (H2SO4H_2SO_4) is added to hydrated copper(II) tetraoxosulfate(VI) crystals (CuSO45H2OCuSO_4 \cdot 5H_2O), turning their blue color to white. In a separate vessel, dilute tetraoxosulfate(VI) acid reacts with zinc granules to evolve hydrogen gas (H2H_2). Which chemical properties of tetraoxosulfate(VI) acid are demonstrated in the first and second reactions, respectively?

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Cevap: Dehydrating property and acidic property

Cevap

Dehydrating property and acidic property
The removal of water of crystallization from blue CuSO45H2OCuSO_4 \cdot 5H_2O to leave white anhydrous CuSO4CuSO_4 demonstrates the dehydrating property of concentrated H2SO4H_2SO_4. The reaction of dilute H2SO4H_2SO_4 with zinc to yield hydrogen gas demonstrates a fundamental chemical property of acids.

Adım Adım Çözüm

1
Analyze the first reaction involving concentrated H2SO4H_2SO_4 and hydrated copper(II) tetraoxosulfate(VI)
Concentrated H2SO4H_2SO_4 acts as a dehydrating agent by removing the five molecules of water of crystallization from blue CuSO45H2OCuSO_4 \cdot 5H_2O to form white anhydrous CuSO4CuSO_4.
Dehydration is the chemical removal of chemically combined water molecules from a compound.
2
Analyze the second reaction involving dilute H2SO4H_2SO_4 and zinc granules
Dilute H2SO4H_2SO_4 reacts with zinc (ZnZn) according to Zn(s)+H2SO4(aq)ZnSO4(aq)+H2(g)Zn_{(s)} + H_2SO_{4(aq)} \rightarrow ZnSO_{4(aq)} + H_{2(g)}, liberating hydrogen gas.
A characteristic property of acids is reacting with metals above hydrogen in the reactivity series to form a salt and hydrogen gas.
3
Combine the identified properties in sequential order
The first reaction exhibits a dehydrating property, and the second reaction exhibits an acidic property.
The question asks for the properties demonstrated in the first and second experiments respectively.

Anahtar Kavram

Distinct behavior of concentrated vs dilute tetraoxosulfate(VI) acid
Soru 6805Soru

Match each commercial organization listed on the left with its principal aim or scope of operation on the right.

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Öğeler

Trade Association
Chamber of Commerce
Employers' Association

Eşleşmeler

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Cevap

Trade Association matches with establishing standardized trade practices within the same industry; Chamber of Commerce matches with promoting economic interests across sectors in a specific region; Employers' Association matches with representing business owners in collective bargaining with labor unions.
Trade Associations unify companies in the exact same business line to establish ethics and industry standards. Chambers of Commerce unite merchants across diverse fields within a defined geographic territory to advance overall regional commerce. Employers' Associations specifically handle employer-employee relations and collective bargaining with labor unions.

Adım Adım Çözüm

1
Analyze the operational scope of a Trade Association.
Trade Associations bind firms in the exact same trade or industry together.
Their goal is to promote standardized practices, technical research, and uniform codes of conduct for their specific sector.
2
Analyze the operational scope of a Chamber of Commerce.
Chambers of Commerce bring together diverse commercial entities from a particular city or territory.
Their focus is geographically bounded rather than sector-bound, aiming to boost overall regional business growth and trade relations.
3
Differentiate Employers' Associations from general trade bodies.
Employers' Associations focus on industrial relations and labor management.
They provide a unified voice for employers during wage negotiations and dispute resolutions with labor unions.

Anahtar Kavram

Distinct structural boundaries, aims, and functions of Trade Associations, Chambers of Commerce, and Employers' Associations.
Soru 6806Soru

A major manufacturing firm in Lagos seeks to expand its operations by obtaining a substantial loan from a commercial bank. To approve the loan facility, the bank demands assurance that the firm's assets are protected against unexpected catastrophic events such as fire or industrial accidents. How does insurance primarily assist the firm in fulfilling this credit requirement?

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Cevap: By providing financial security against risk, thereby enhancing business creditworthiness and enabling assets to serve as collateral

Cevap

Insurance primarily assists businesses by providing financial security against loss, which protects asset value, instills confidence in lenders, and allows insurance coverage to enhance creditworthiness for business loans.
Insurance plays a vital role in commerce by spreading financial risk across a pool of policyholders. By protecting business assets against loss, insurance instills confidence in lenders, elevates the firm's credit rating, and enables insured assets or insurance policies to be pledged as security for loans.

Adım Adım Çözüm

1
Analyze the firm's requirement in the scenario.
The manufacturing firm needs a commercial bank loan, but the bank demands risk mitigation to ensure the firm remains solvent if assets are destroyed.
Lending institutions require assurance that funded or pledged assets will retain value even if unexpected perils occur.
2
Examine the role of insurance as an auxiliary to trade.
Insurance transfers and pools risks, providing financial indemnification and security to businesses.
By reducing financial uncertainty, insurance encourages capital investment and facilitates credit acquisition.
3
Identify the correct function matching the scenario.
Providing security against risks directly satisfies the lender's requirement by guaranteeing financial compensation in the event of loss.
Risk protection enhances business creditworthiness and satisfies collateral requirements.

Anahtar Kavram

Role of Insurance in Credit Enhancement and Business Security
Soru 6807Soru

A wholesaler dispatched goods valued at ₦150,000 to a retailer but accidentally billed the retailer ₦135,000 on the commercial invoice. Which commercial document will the wholesaler issue to rectify this undercharge?

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Cevap: A Debit Note

Cevap

A Debit Note
A Debit Note is sent by a seller to notify the buyer that their account balance has been increased to rectify an undercharge on a previously issued invoice.

Adım Adım Çözüm

1
Identify the financial transaction discrepancy.
The retailer was billed ₦135,000 instead of ₦150,000, creating an undercharge of ₦15,000.
The seller needs to collect the remaining unpaid balance from the customer.
2
Determine the commercial document used to increase a customer's account debt in home trade.
A Debit Note is selected.
A Debit Note informs the buyer that their account has been debited for an additional amount to correct an undercharge.

Anahtar Kavram

Debit Note function in Home Trade
Soru 6808Soru

Two electric lamps rated at 60W,220V60\,\text{W}, 220\,\text{V} and 100W,220V100\,\text{W}, 220\,\text{V} respectively are connected in series across a 220V220\,\text{V} supply line. What is the total electric power dissipated by the combination?

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Cevap: 37.5W37.5\,\text{W}

Cevap

The total electric power dissipated by the two lamps in series is 37.5W37.5\,\text{W}.
For two appliances designed for the same rated voltage VV connected in series across that voltage VV, the equivalent power is given by the formula Ptotal=P1P2P1+P2P_{\text{total}} = \frac{P_1 P_2}{P_1 + P_2}. Substituting P1=60WP_1 = 60\,\text{W} and P2=100WP_2 = 100\,\text{W} gives Ptotal=60×10060+100=37.5WP_{\text{total}} = \frac{60 \times 100}{60 + 100} = 37.5\,\text{W}.

Adım Adım Çözüm

1
Calculate the resistance of each lamp from its rating.
R1=V2P1=220260=806.67ΩR_1 = \frac{V^2}{P_1} = \frac{220^2}{60} = 806.67\,\Omega and R2=V2P2=2202100=484.00ΩR_2 = \frac{V^2}{P_2} = \frac{220^2}{100} = 484.00\,\Omega
Electrical devices are rated at a specific voltage, allowing their resistance to be determined via R=V2PR = \frac{V^2}{P}.
2
Find the total resistance of the series circuit.
Rtotal=R1+R2=806.67+484.00=1290.67ΩR_{\text{total}} = R_1 + R_2 = 806.67 + 484.00 = 1290.67\,\Omega
Resistors in series add directly.
3
Calculate total power drawn from the 220V220\,\text{V} supply.
Ptotal=V2Rtotal=22021290.67=37.5WP_{\text{total}} = \frac{V^2}{R_{\text{total}}} = \frac{220^2}{1290.67} = 37.5\,\text{W}
Total power is total voltage squared divided by equivalent resistance.

Anahtar Kavram

Power combination in series circuits
Tahmini Süre:1m 30s
Soru 6809Soru

Match each specialized banking service or payment instrument with the commercial trading need it satisfies for a business enterprise.

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Öğeler

Credit Transfer
Discounting Bill of Exchange
Bank Draft
Night Safe Facility

Eşleşmeler

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Cevap

Credit Transfer matches with settlement of multiple creditor payments via a single instruction. Discounting Bill of Exchange matches with immediate cash payment for a term trade debt before maturity. Bank Draft matches with a guaranteed cheque drawn on the bank's own funds. Night Safe Facility matches with depositing daily cash receipts outside operating hours.
Each commercial banking instrument specifically addresses a distinct financial operational challenge in trade: credit transfers aggregate multiple payments, discounting bills unlocks tied-up receivables before maturity, bank drafts offer guaranteed settlement for high-risk sales, and night safes safeguard after-hours cash proceeds.

Adım Adım Çözüm

1
Identify the payment consolidation service
Credit transfer transfers funds from one customer account to multiple payee accounts in a single batch transaction.
Traders use credit transfers to streamline supplier payments and payroll.
2
Identify the short-term working capital facility for trade bills
Discounting a bill of exchange converts a future receivable into immediate cash less interest.
This improves merchant cash flow without waiting for the credit term to elapse.
3
Identify the guaranteed bank payment instrument
A bank draft is drawn directly on the bank, guaranteeing payment security.
Creditors accept bank drafts when personal or business cheques carry a risk of dishonor.
4
Identify the after-hours cash protection service
Night safe facilities provide secure access to drop cash after regular branch closing times.
This protects traders from overnight theft risks.

Anahtar Kavram

Banking Functions and Services to Trade
Soru 6810Soru

Match each chemical reaction involving acids or bases listed on the left with its correct characteristic observation or product on the right.

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Öğeler

Reaction of dilute HClHCl with Na2CO3Na_2CO_3
Heating NH4ClNH_4Cl with aqueous NaOHNaOH
Reaction of dilute H2SO4H_2SO_4 with zinc metal
Reaction of aqueous NaOHNaOH with dilute HNO3HNO_3

Eşleşmeler

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Cevap

Reaction of dilute HClHCl with Na2CO3Na_2CO_3 pairs with effervescence of carbon(IV) oxide gas; heating NH4ClNH_4Cl with aqueous NaOHNaOH pairs with evolution of pungent ammonia gas; reaction of dilute H2SO4H_2SO_4 with zinc metal pairs with liberation of hydrogen gas; and reaction of aqueous NaOHNaOH with dilute HNO3HNO_3 pairs with neutralization forming a salt and water without gas evolution.
Each acid and base chemical property produces a distinct, diagnostic observation: acid + carbonate yields carbon(IV) oxide (CO2CO_2), base + ammonium salt yields ammonia (NH3NH_3), acid + reactive metal yields hydrogen (H2H_2), and acid + base (hydroxide) results in neutralisation forming salt and water.

Adım Adım Çözüm

1
Analyze acid-trioxocarbonate(IV) reaction property.
2HCl(aq)+Na2CO3(aq)2NaCl(aq)+H2O(l)+CO2(g)2HCl_{(aq)} + Na_2CO_{3(aq)} \rightarrow 2NaCl_{(aq)} + H_2O_{(l)} + CO_{2(g)}. The evolved CO2CO_2 gas causes effervescence and turns lime water milky.
Acids liberate carbon(IV) oxide gas from trioxocarbonates(IV).
2
Analyze base-ammonium salt reaction property.
NH4Cl(s)+NaOH(aq)NaCl(aq)+H2O(l)+NH3(g)NH_4Cl_{(s)} + NaOH_{(aq)} \rightarrow NaCl_{(aq)} + H_2O_{(l)} + NH_{3(g)}. Ammonia gas is pungent and alkaline, turning moist red litmus paper blue.
Soluble bases displace ammonia from ammonium salts when heated.
3
Analyze acid-metal displacement reaction property.
Zn(s)+H2SO4(aq)ZnSO4(aq)+H2(g)Zn_{(s)} + H_2SO_{4(aq)} \rightarrow ZnSO_{4(aq)} + H_{2(g)}. Hydrogen gas burns with a pop sound.
Dilute acids react with metals above hydrogen in the electrochemical series to yield hydrogen gas.
4
Analyze acid-base neutralization property.
NaOH(aq)+HNO3(aq)NaNO3(aq)+H2O(l)NaOH_{(aq)} + HNO_{3(aq)} \rightarrow NaNO_{3(aq)} + H_2O_{(l)}. This is a neutralisation reaction yielding salt and water.
Soluble metal hydroxides react with acids to form salt and water only.

Anahtar Kavram

Chemical properties of acids and bases including gas evolution tests and neutralization
Soru 6811Soru

For a fixed mass of gas maintained at a constant temperature, a plot of pressure (PP) against volume (VV) produces a straight line passing through the origin.

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Cevap: False

Cevap

The statement is False. At constant temperature, gas pressure is inversely proportional to volume (P1VP \propto \frac{1}{V}), resulting in a hyperbolic curve when plotting PP versus VV, rather than a straight line.
Boyle's law dictates that the pressure of a fixed mass of gas is inversely proportional to its volume at constant temperature (P1VP \propto \frac{1}{V}). As a result, graphing pressure (PP) directly against volume (VV) produces a non-linear, downward-sloping curve known as a rectangular hyperbola. To produce a straight line passing through the origin, pressure (PP) must be plotted against the reciprocal of volume (1V\frac{1}{V}).

Adım Adım Çözüm

1
State the mathematical formulation of Boyle's law for a fixed mass of gas at constant temperature.
P1VP \propto \frac{1}{V} or PV=kP \cdot V = k, where kk is a constant.
Boyle's law describes an inverse relationship between pressure and volume.
2
Analyze the nature of a graph where one variable is plotted directly against another inversely proportional variable (PP vs VV).
The resulting curve is a rectangular hyperbola that approaches the axes asymptotically.
Inversely proportional quantities do not produce a linear plot when graphed directly against each other.
3
Determine the graphical condition required to obtain a straight line passing through the origin.
Plotting pressure (PP) against reciprocal volume (1V\frac{1}{V}) yields a straight line with slope equal to constant kk.
Linearity is achieved by plotting one variable against the reciprocal of the other when P1VP \propto \frac{1}{V}.

Anahtar Kavram

Graphical representation of Boyle's Law (PP-VV relationship)
Soru 6812Soru

In commercial practice, while both Trade Associations and Chambers of Commerce aim to promote business activities, which of the following features uniquely characterizes a Chamber of Commerce?

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Cevap: Membership comprises firms across different lines of business within a specific geographical area.

Cevap

Membership comprises firms across different lines of business within a specific geographical area.
The correct answer accurately states that a Chamber of Commerce is a multi-industry business association structured around a defined geographical boundary (such as a city, state, or country) to foster local economic development, organize trade fairs, and advocate for business interests.

Adım Adım Çözüm

1
Identify the organizational scope of a Chamber of Commerce.
A Chamber of Commerce unites business enterprises across varied sectors based on geographical location.
Unlike sector-specific bodies, Chambers of Commerce represent general commercial interests within a locality or region.
2
Differentiate a Chamber of Commerce from related commercial organizations.
Trade Associations are sector-specific, Trade Unions represent workers, and statutory export councils are government agencies.
Analyzing organizational goals and membership boundaries isolates the distinctive feature of a Chamber of Commerce.

Anahtar Kavram

Structural and functional distinctions between Chambers of Commerce and Trade Associations
Tahmini Süre:1m 0s
Soru 6813Soru

A sample of oxygen gas occupies a volume of 450 cm3450\text{ cm}^3 at a temperature of 27C27^\circ\text{C}. If the pressure remains constant, what will be the volume of the gas when its temperature is increased to 207C207^\circ\text{C}?

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Cevap: 720 cm3720\text{ cm}^3

Cevap

The volume of the gas at 207C207^\circ\text{C} is 720 cm3720\text{ cm}^3.
According to Charles's Law, the volume of a gas is directly proportional to its absolute temperature when pressure remains constant (V1/T1=V2/T2V_1/T_1 = V_2/T_2). Converting the temperatures to Kelvin (T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=207+273=480 KT_2 = 207 + 273 = 480\text{ K}) and calculating gives V2=450×(480/300)=720 cm3V_2 = 450 \times (480 / 300) = 720\text{ cm}^3.

Adım Adım Çözüm

1
Convert temperatures from Celsius to the absolute (Kelvin) scale.
T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=207+273=480 KT_2 = 207 + 273 = 480\text{ K}.
Gas laws require temperatures to be expressed on the absolute temperature scale (Kelvin).
2
Apply Charles's Law equation.
V1T1=V2T2    V2=V1×T2T1\frac{V_1}{T_1} = \frac{V_2}{T_2} \implies V_2 = V_1 \times \frac{T_2}{T_1}.
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature.
3
Substitute the known values and calculate V2V_2.
V2=450×480300=450×1.6=720 cm3V_2 = 450 \times \frac{480}{300} = 450 \times 1.6 = 720\text{ cm}^3.
Completing the arithmetic yields the final volume.

Anahtar Kavram

Charles's Law states that at constant pressure, the volume of a given mass of gas is directly proportional to its absolute temperature (VTV \propto T).
Soru 6814Soru

A rigid metallic cylinder contains a fixed mass of gas at an initial pressure of 1.2 atm1.2\text{ atm} and a temperature of 27C27^\circ\text{C}. If the gas is heated until its temperature reaches 177C177^\circ\text{C} while the volume remains constant, what is the final pressure of the gas in atmospheres?

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Cevap: 1.8

Cevap

The final pressure of the gas is 1.8 atm1.8\text{ atm}.
Converting the temperatures to Kelvin (T1=300 KT_1 = 300\text{ K} and T2=450 KT_2 = 450\text{ K}) and applying Gay-Lussac's Pressure Law P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2} gives P2=1.2×450300=1.8 atmP_2 = 1.2 \times \frac{450}{300} = 1.8\text{ atm}.

Adım Adım Çözüm

1
Convert given temperatures to the Kelvin scale
T1=300 KT_1 = 300\text{ K} and T2=450 KT_2 = 450\text{ K}
Gas laws require absolute temperature values measured in Kelvin (TK=tC+273T_K = t_C + 273).
2
Set up Gay-Lussac's Pressure Law proportion P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}
P2=P1×T2T1=1.2×450300P_2 = P_1 \times \frac{T_2}{T_1} = 1.2 \times \frac{450}{300}
At constant volume, the pressure of a fixed mass of gas is directly proportional to its absolute temperature.
3
Perform the multiplication to determine the final pressure
P2=1.8 atmP_2 = 1.8\text{ atm}
Multiplying 1.21.2 by the ratio 1.51.5 yields 1.8 atm1.8\text{ atm}.

Anahtar Kavram

Pressure Law (Gay-Lussac's Law) states that for a given mass of gas at constant volume, the pressure is directly proportional to its absolute temperature in Kelvin (PTP \propto T).
Soru 6815Soru

Match each electrical operational scenario on the left with its corresponding effect on electrical energy or power on the right.

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Öğeler

Doubling the electric current passing through a resistor of constant resistance for a fixed duration
Halving the operating potential difference applied across a resistor of constant resistance
Connecting two identical resistors in parallel across a constant voltage source
Operating a 500W500\,\text{W} appliance continuously for a duration of 2hours2\,\text{hours}

Eşleşmeler

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Cevap

Doubling current quadruples heat energy (HI2H \propto I^2); halving voltage reduces power to one-quarter (PV2P \propto V^2); connecting two identical resistors in parallel doubles total power (P1/ReqP \propto 1/R_{\text{eq}}); and operating a 500 W appliance for 2 hours consumes 1.0 kWh.
Each left-side scenario correctly aligns with fundamental laws of electrical energy and power: doubling current quadruples heat energy via HI2H \propto I^2; halving voltage reduces power to one-quarter via PV2P \propto V^2; parallel resistor connection halves total resistance and doubles power; and operating a 0.5 kW appliance for 2 hours consumes 1.0 kWh.

Adım Adım Çözüm

1
Apply Joule's Law of Heating (H=I2RtH = I^2 R t) to determine the effect of changing current.
Doubling current from II to 2I2I results in H=(2I)2Rt=4I2Rt=4HH' = (2I)^2 R t = 4 I^2 R t = 4H, so heat quadruples.
Heat generation depends on the square of current when resistance and time are constant.
2
Apply the voltage-power relationship (P=V2RP = \frac{V^2}{R}) for changing voltage.
Halving potential difference to V/2V/2 yields P=(V/2)2R=V24R=P4P' = \frac{(V/2)^2}{R} = \frac{V^2}{4R} = \frac{P}{4}, so power drops to one-quarter.
Power is directly proportional to the square of potential difference across a constant resistance.
3
Calculate parallel resistance and total circuit power.
Equivalent resistance of two parallel resistors is R/2R/2. Total power is Ptotal=V2R/2=2V2RP_{\text{total}} = \frac{V^2}{R/2} = 2 \frac{V^2}{R}, which is double the single resistor power.
Parallel combination reduces net resistance by half, thereby doubling total current and power drawn from a constant voltage source.
4
Calculate energy consumption in commercial units (kWh).
E=0.5kW×2h=1.0kWhE = 0.5\,\text{kW} \times 2\,\text{h} = 1.0\,\text{kWh}.
Commercial energy is computed by expressing power in kW and time in hours.

Anahtar Kavram

Mathematical relationships governing electrical power (P=I2R=V2RP = I^2 R = \frac{V^2}{R}), Joule heating (H=I2RtH = I^2 R t), and commercial energy units (kWh).
Soru 6816Soru

A dip needle placed in the magnetic meridian at a location on the Earth's surface makes an angle of 3030^\circ with the horizontal. If the total intensity of the Earth's magnetic field at this location is 6.0×105 T6.0 \times 10^{-5}\text{ T}, what is the vertical component of the Earth's magnetic field?

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Cevap: 3.0×105 T3.0 \times 10^{-5}\text{ T}

Cevap

The vertical component of the Earth's magnetic field is 3.0×105 T3.0 \times 10^{-5}\text{ T}.
The vertical component of the Earth's magnetic field is given by Bv=BsinθB_v = B \sin \theta. Substituting B=6.0×105 TB = 6.0 \times 10^{-5}\text{ T} and θ=30\theta = 30^\circ yields Bv=6.0×105×0.5=3.0×105 TB_v = 6.0 \times 10^{-5} \times 0.5 = 3.0 \times 10^{-5}\text{ T}.

Adım Adım Çözüm

1
Identify the given physical quantities from the problem statement.
Total intensity B=6.0×105 TB = 6.0 \times 10^{-5}\text{ T} and inclination angle θ=30\theta = 30^\circ.
These parameters are required to compute the resolved component.
2
Recall the formula for resolving the vertical component of Earth's magnetic field.
Bv=BsinθB_v = B \sin \theta
The vertical component corresponds to the vertical side of the right triangle formed by total field BB and angle of dip θ\theta.
3
Substitute the given values into the formula and calculate.
Bv=(6.0×105 T)×sin(30)=(6.0×105)×0.5=3.0×105 TB_v = (6.0 \times 10^{-5}\text{ T}) \times \sin(30^\circ) = (6.0 \times 10^{-5}) \times 0.5 = 3.0 \times 10^{-5}\text{ T}.
Since sin(30)=0.5\sin(30^\circ) = 0.5, multiplying 6.0×1056.0 \times 10^{-5} by 0.50.5 yields 3.0×105 T3.0 \times 10^{-5}\text{ T}.

Anahtar Kavram

Resolution of Earth's total magnetic field into horizontal and vertical components
Soru 6817Soru

A textile merchant in Aba receives a 90-day bill of exchange from a buyer in Onitsha for goods delivered on credit. Wanting immediate funds to replenish inventory before the bill matures, the merchant presents the document to a commercial bank for immediate cash settlement at a slight deduction. Which banking service has the merchant utilized?

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Cevap: Discounting a bill of exchange

Cevap

Discounting a bill of exchange is the banking service that enables a seller to obtain immediate liquidity by selling an un-matured bill of exchange to a commercial bank at a discount.
Discounting a bill of exchange allows a trader to convert a debt owed to them into cash before the bill's maturity date. The bank pays the trader the face value minus a discount fee for early settlement.

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1
Analyze the merchant's financial scenario and requirement
The merchant holds a 90-day trade credit instrument (bill of exchange) but requires cash before the 90-day maturity period ends.
Identifying the specific financial need helps distinguish between credit facilities and negotiable instrument services.
2
Evaluate the commercial bank functions that provide early cash settlement for trade credit instruments
Commercial banks purchase un-matured bills of exchange from traders at a value lower than the face value, deducting a discount fee to cover interest.
Discounting bills of exchange acts as a short-term working capital solution for trade debts.

Anahtar Kavram

Discounting Bills of Exchange in Commercial Banking Services to Trade
Tahmini Süre:1m 0s
Soru 6818Soru

An aqueous solution of barium hydroxide, Ba(OH)2\text{Ba(OH)}_2, has a molar concentration of 0.0005 mol dm30.0005\text{ mol dm}^{-3}. Assuming complete dissociation of the base at 25C25^\circ\text{C}, what is the pH of this solution?

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Cevap: 11.011.0

Cevap

The pH of the solution is 11.011.0.
Barium hydroxide (Ba(OH)2\text{Ba(OH)}_2) produces two hydroxide ions (OH\text{OH}^-) per formula unit upon complete dissociation. Thus, a 0.0005 mol dm30.0005\text{ mol dm}^{-3} solution produces [OH]=2×0.0005=0.001 mol dm3=1.0×103 mol dm3[\text{OH}^-] = 2 \times 0.0005 = 0.001\text{ mol dm}^{-3} = 1.0 \times 10^{-3}\text{ mol dm}^{-3}. The pOH is log10(1.0×103)=3.0-\log_{10}(1.0 \times 10^{-3}) = 3.0. Subtracting pOH from 14.0 yields a pH of 11.011.0.

Adım Adım Çözüm

1
Determine the concentration of hydroxide ions [OH][\text{OH}^-] from the mole ratio of Ba(OH)2\text{Ba(OH)}_2.
Since each mole of Ba(OH)2\text{Ba(OH)}_2 dissociates into two moles of OH\text{OH}^-, [OH]=2×0.0005 mol dm3=0.001 mol dm3=1.0×103 mol dm3[\text{OH}^-] = 2 \times 0.0005\text{ mol dm}^{-3} = 0.001\text{ mol dm}^{-3} = 1.0 \times 10^{-3}\text{ mol dm}^{-3}.
Barium hydroxide is a strong dibasic base that fully dissociates in aqueous solution.
2
Calculate the pOH of the solution.
pOH=log10[OH]=log10(1.0×103)=3.0\text{pOH} = -\log_{10}[\text{OH}^-] = -\log_{10}(1.0 \times 10^{-3}) = 3.0.
The pOH scale is defined as the negative logarithm of the hydroxide ion concentration.
3
Calculate the pH using the relationship pH+pOH=14.0\text{pH} + \text{pOH} = 14.0.
pH=14.03.0=11.0\text{pH} = 14.0 - 3.0 = 11.0.
At 25C25^\circ\text{C}, the sum of pH and pOH for any dilute aqueous solution equals 14.0.

Anahtar Kavram

pH and pOH calculations for strong basic solutions considering stoichiometry
Tahmini Süre:1m 0s
Soru 6819Soru

Money serves as a standard of deferred payment when it acts as the common unit used to express and compare the current market prices of different goods and services.

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Cevap: False

Cevap

False. Expressing and comparing current prices of goods and services describes the 'unit of account' function of money, whereas the 'standard of deferred payment' refers to settling future debts and credit transactions.
The statement is false because measuring and comparing the relative monetary values of goods and services is the 'unit of account' function. The 'standard of deferred payment' function specifically concerns facilitating credit sales and deferred financial contracts.

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1
Identify the specific function of money described in the statement (expressing and comparing current market prices).
The function that acts as a measure of value for pricing goods is the 'unit of account'.
Unit of account provides a common metric for pricing and financial record-keeping in current transactions.
2
Define the 'standard of deferred payment' function of money.
The standard of deferred payment allows financial obligations to be created today and settled at a specified future date.
This is a secondary function enabling deferred trade, loans, and credit sales.
3
Compare the function in the statement with the actual definition of standard of deferred payment.
The statement misattributes the primary function of unit of account to the secondary function of standard of deferred payment.
Because the statement confuses current price valuation with future debt settlement, it is logically false.

Anahtar Kavram

Distinction between Primary (Unit of Account) and Secondary (Standard of Deferred Payment) Functions of Money
Soru 6820Soru

An electric heating element rated at 1000W1000\,\text{W} and 220V220\,\text{V} is connected to a 110V110\,\text{V} power line. Assuming the electrical resistance of the heating element remains constant, what is the power dissipated by the heater when operating at this reduced voltage?

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Cevap: 250W250\,\text{W}

Cevap

250W250\,\text{W}
The electrical power rating of an appliance defines its fixed resistance via R=V2PR = \frac{V^2}{P}. With R=48.4ΩR = 48.4\,\Omega, connecting the appliance to a 110V110\,\text{V} supply yields P=110248.4=250WP = \frac{110^2}{48.4} = 250\,\text{W}. Alternatively, because PV2P \propto V^2 for a constant resistance, halving the voltage reduces the power by a factor of (1/2)2=1/4(1/2)^2 = 1/4, giving 1000W×14=250W1000\,\text{W} \times \frac{1}{4} = 250\,\text{W}.

Adım Adım Çözüm

1
Calculate the resistance RR of the heater from its rated values.
R=Vrated2Prated=22021000=484001000=48.4ΩR = \frac{V_{\text{rated}}^2}{P_{\text{rated}}} = \frac{220^2}{1000} = \frac{48400}{1000} = 48.4\,\Omega
The resistance of a heating element is determined by its physical design and rated specifications.
2
Calculate the power PnewP_{\text{new}} dissipated when connected to the 110V110\,\text{V} supply.
Pnew=Vnew2R=110248.4=1210048.4=250WP_{\text{new}} = \frac{V_{\text{new}}^2}{R} = \frac{110^2}{48.4} = \frac{12100}{48.4} = 250\,\text{W}
Electric power dissipated across a constant resistance varies with the square of the applied voltage.

Anahtar Kavram

Relationship between voltage, resistance, and electrical power dissipation
Tahmini Süre:1m 30s
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