Contour Lines and Relief Representation

29 soru

Soru 1Soru

Match each contour line pattern on a topographical map with the corresponding relief feature it represents.

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Öğeler

Concentric closed contours with values increasing towards the center
V-shaped contours pointing towards higher elevation (uphill)
Contour lines drawn very close together

Eşleşmeler

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Cevap

Concentric closed contours with increasing values inward match Hill top or hill peak; V-shaped contours pointing uphill match Valley or stream channel; Closely spaced contour lines match Steep slope or cliff.
Each contour pattern uniquely corresponds to a fundamental topographic feature according to standard map reading conventions.

Adım Adım Çözüm

1
Identify the arrangement of concentric closed contours increasing inward.
Matched to Hill top or hill peak.
As height increases towards the middle of closed shapes, it shows a rising landform such as a hill summit.
2
Determine the landform associated with V-shaped contours pointing uphill.
Matched to Valley or stream channel.
V-shaped contour apexes pointing towards higher elevations signify drainage lines or valleys.
3
Examine the spacing of contour lines placed close together.
Matched to Steep slope or cliff.
Tight contour spacing indicates rapid elevation change over a small horizontal ground distance.

Anahtar Kavram

Relief representation and contour pattern identification
Soru 2Soru

On a topographical map with a scale of 1:50,0001:50,000, Point X is situated on a contour line marked 350 m350\text{ m} and Point Y is situated on a contour line marked 500 m500\text{ m}. If the measured distance between Point X and Point Y on the map is 6 cm6\text{ cm}, what is the gradient of the slope between Point X and Point Y?

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Cevap: 1 in 201\text{ in } 20

Cevap

The gradient of the slope between Point X and Point Y is 1 in 201\text{ in } 20 (or 1:201:20).
The slope gradient is calculated by dividing the Vertical Interval (difference in elevation: 500 m350 m=150 m500\text{ m} - 350\text{ m} = 150\text{ m}) by the Horizontal Equivalent (actual ground distance: 6 cm×50,000=300,000 cm=3,000 m6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}). Converting both parameters into meters gives 1503000=120\frac{150}{3000} = \frac{1}{20}, which represents a slope ratio of 1 in 201\text{ in } 20.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI)
VI=500 m350 m=150 m\text{VI} = 500\text{ m} - 350\text{ m} = 150\text{ m}
The Vertical Interval is the difference in height between the two contour points.
2
Calculate the Horizontal Equivalent (HE) in ground measurement
HE=6 cm×50,000=300,000 cm=3,000 m\text{HE} = 6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}
The Representative Fraction scale of 1:50,0001:50,000 means 1 cm1\text{ cm} on the map represents 50,000 cm50,000\text{ cm} (500 m500\text{ m}) on the ground.
3
Calculate the slope gradient formula Gradient=VIHE\text{Gradient} = \frac{\text{VI}}{\text{HE}}
Gradient=150 m3,000 m=120\text{Gradient} = \frac{150\text{ m}}{3,000\text{ m}} = \frac{1}{20}
Dividing the vertical height by the horizontal distance in identical units expresses the slope as a ratio.

Anahtar Kavram

Topographic Slope Gradient Calculation
Tahmini Süre:2m 0s
Soru 3Soru

On a topographical map, a series of V-shaped contour lines have their apexes (pointed ends) pointing towards higher elevation. Which of the following relief features is represented by this contour pattern?

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Cevap: A river valley

Cevap

A river valley
When contour lines cross a river or valley, they bend upstream into a V-shape. Because the river flows from higher to lower ground, the V-shape points toward higher elevation (upstream). Therefore, V-shaped contours pointing toward higher ground represent a river valley.

Adım Adım Çözüm

1
Examine the shape and orientation of the contour lines.
The contour lines form V-shapes pointing toward higher elevation.
Water flows downhill, so river valleys cut into higher land, causing contour lines to bend upstream (towards higher elevation) where they cross a stream.
2
Identify the corresponding topographic landform.
V-shaped contours pointing uphill represent a river valley or ravine.
The apex of the 'V' points up the valley toward the river source.

Anahtar Kavram

Interpretation of contour patterns for landform identification
Tahmini Süre:45s
Soru 4Soru

On a topographical map drawn to a scale of 1:100,0001:100,000, a hill summit is marked with a spot height of 520 m520\text{ m}. The terrain features uniform contour intervals of 20 m20\text{ m}. Point XX is located on the fifth contour line directly below the summit. Point YY is situated at a lower elevation such that the vertical difference in height between Point XX and Point YY is 240 m240\text{ m}. If the straight-line distance measured between Point XX and Point YY on the map is 6 cm6\text{ cm}, calculate the average gradient between Point XX and Point YY expressed in the ratio 1:n1 : n. What is the value of nn?

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Cevap: 25

Cevap

The value of nn is 25, corresponding to an average gradient of 1:251 : 25 (or 1 in 25).
To find the denominator nn of the gradient ratio 1:n1:n, the vertical interval (VI = 240 m240\text{ m}) is compared to the horizontal equivalent (HE = 6,000 m6,000\text{ m}). Dividing 6,000 m6,000\text{ m} by 240 m240\text{ m} yields 2525, meaning the slope rises 1 meter vertically for every 25 meters horizontally.

Adım Adım Çözüm

1
Determine the elevation of Point X from the contour interval and spot height.
Elevation of Point X = 520 m(5×20 m)=420 m520\text{ m} - (5 \times 20\text{ m}) = 420\text{ m}.
Point X lies on the fifth contour line below the 520 m520\text{ m} summit with a 20 m20\text{ m} interval.
2
Identify the Vertical Interval (VI) between Point X and Point Y.
VI=240 m\text{VI} = 240\text{ m}.
The vertical elevation difference is directly specified in the problem statement.
3
Convert map distance to actual ground horizontal distance (Horizontal Equivalent, HE) using the map scale.
HE=6 cm×100,000=600,000 cm=6,000 m\text{HE} = 6\text{ cm} \times 100,000 = 600,000\text{ cm} = 6,000\text{ m}.
Unit conversions must align VI and HE in meters before computing the ratio.
4
Express the gradient as a ratio 1:n1 : n by dividing HE by VI.
n=HEVI=6,000 m240 m=25n = \frac{\text{HE}}{\text{VI}} = \frac{6,000\text{ m}}{240\text{ m}} = 25.
Gradient ratio is defined as Vertical IntervalHorizontal Equivalent=1n\frac{\text{Vertical Interval}}{\text{Horizontal Equivalent}} = \frac{1}{n}.

Anahtar Kavram

Gradient Calculation and Unit Alignment from Topographical Maps
Tahmini Süre:2m 30s
Soru 5Soru

On a topographical map drawn to a scale of 1:25,0001:25,000, a road ascends continuously from Point P at a contour elevation of 180 m180\text{ m} to Point Q at a contour elevation of 430 m430\text{ m}. If the average gradient along this section of the road is 1 in 201\text{ in } 20, what is the distance between Point P and Point Q on the map in centimeters?

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Cevap: 20.0 cm20.0\text{ cm}

Cevap

The distance between Point P and Point Q on the map is 20.0 cm20.0\text{ cm}.
The height difference (Vertical Interval) between the two points is 430 m180 m=250 m430\text{ m} - 180\text{ m} = 250\text{ m}. With a gradient ratio of 1 in 201\text{ in } 20, the horizontal ground distance (Horizontal Equivalent) is 250 m×20=5,000 m250\text{ m} \times 20 = 5,000\text{ m}, which equals 500,000 cm500,000\text{ cm}. Applying the map scale of 1:25,0001:25,000 gives a map measurement of 500,000 cm/25,000=20.0 cm500,000\text{ cm} / 25,000 = 20.0\text{ cm}.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI) between Point P and Point Q
VI=430 m180 m=250 m\text{VI} = 430\text{ m} - 180\text{ m} = 250\text{ m}
Vertical Interval represents the height difference between the two contour elevations.
2
Calculate the Horizontal Equivalent (HE) on the ground using the given gradient
HE=VI×20=250 m×20=5,000 m\text{HE} = \text{VI} \times 20 = 250\text{ m} \times 20 = 5,000\text{ m}
Gradient is defined as VIHE\frac{\text{VI}}{\text{HE}}. Therefore, HE=VI/Gradient=250 m×20\text{HE} = \text{VI} / \text{Gradient} = 250\text{ m} \times 20.
3
Convert the ground distance (HE) to centimeters
HE in cm=5,000 m×100 cm/m=500,000 cm\text{HE in cm} = 5,000\text{ m} \times 100\text{ cm/m} = 500,000\text{ cm}
Map distance calculations require identical linear units for numerator and denominator.
4
Determine the map distance using the Representative Fraction scale (1:25,0001:25,000)
Map Distance=500,000 cm25,000=20.0 cm\text{Map Distance} = \frac{500,000\text{ cm}}{25,000} = 20.0\text{ cm}
Dividing the actual ground distance by the scale factor gives the equivalent measurement on the map.

Anahtar Kavram

Topographic Gradient and Map Scale Conversion
Tahmini Süre:2m 0s
Soru 6Soru

Match each topographical contour line pattern with the correct relief feature or slope characteristic it depicts on a map.

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Öğeler

Contours widely spaced at higher elevations and closely spaced at lower elevations near the base
Contours closely spaced at higher elevations and widely spaced at lower elevations near the base
V-shaped contours with their apexes (pointed ends) pointing toward lower elevation values
Asymmetrical contour arrangement with very tight spacing on one face and wide spacing on the opposite face

Eşleşmeler

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Cevap

The correct pairings are: Widely spaced at top / closely spaced at base matches Convex slope; Closely spaced at top / widely spaced at base matches Concave slope; V-shaped contours pointing downhill match Spur; Asymmetrical contour spacing on opposite sides matches Escarpment.
Each contour pattern corresponds to a fundamental geometric principle of map work: contour density reflects gradient steepness (wide = gentle, close = steep), and V-shaped orientation indicates direction of slope projection.

Adım Adım Çözüm

1
Analyze contour spacing relative to slope profiles.
Wide spacing indicates a gentle gradient, whereas close spacing indicates a steep gradient.
Topographical slope profiles (convex vs. concave) are determined by how gradient changes from high elevation to low elevation.
2
Differentiate between convex and concave slopes.
Convex slope = gentle top (wide spacing) to steep base (close spacing). Concave slope = steep top (close spacing) to gentle base (wide spacing).
Curvature of terrain determines where gradient transitions occur along elevation contours.
3
Analyze V-shaped contour orientation for relief features.
V-shapes pointing toward lower elevation represent spurs projecting downhill; V-shapes pointing toward higher elevation represent river valleys.
Contour lines bend around highland projections (spurs) differently than valley depressions.
4
Evaluate asymmetrical ridge patterns.
A steep slope on one side paired with a gentle slope on the other represents an escarpment (scarp and dip slopes).
Escarpments arise from tilted rock strata, resulting in contrasting contour densities across the ridge crest.

Anahtar Kavram

Interpretation of Relief and Slope Profiles from Topographical Contour Configurations
Soru 7Soru

On a topographical map drawn to a scale of 1:20,0001:20,000, a foot trail ascends continuously from Point A at a contour elevation of 150 m150\text{ m} to Point B at a contour elevation of 300 m300\text{ m}. If the straight-line map distance between Point A and Point B measures 15.0 cm15.0\text{ cm}, what is the average gradient of the slope from Point A to Point B?

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Cevap: 1:201 : 20

Cevap

The average gradient of the slope from Point A to Point B is 1:201 : 20.
To determine topographic gradient, calculate the Vertical Interval (VI\text{VI}) as 300 m150 m=150 m300\text{ m} - 150\text{ m} = 150\text{ m}. Convert the map distance (15.0 cm15.0\text{ cm}) to ground distance using the map scale (1:20,0001:20,000): 15.0 cm×20,000=300,000 cm=3,000 m15.0\text{ cm} \times 20,000 = 300,000\text{ cm} = 3,000\text{ m}. The ratio VIHE=150 m3,000 m=120\frac{\text{VI}}{\text{HE}} = \frac{150\text{ m}}{3,000\text{ m}} = \frac{1}{20}, giving an average gradient of 1:201 : 20.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI)
VI=300 m150 m=150 m\text{VI} = 300\text{ m} - 150\text{ m} = 150\text{ m}
The vertical interval represents the total vertical height gained between the starting contour line and the destination contour line.
2
Convert map distance to ground distance to determine the Horizontal Equivalent (HE)
HE=15.0 cm×20,000=300,000 cm=3,000 m\text{HE} = 15.0\text{ cm} \times 20,000 = 300,000\text{ cm} = 3,000\text{ m}
Using the map scale ratio of 1:20,0001:20,000, every 1 cm1\text{ cm} on the map corresponds to 20,000 cm20,000\text{ cm} (200 m200\text{ m}) on the actual terrain.
3
Compute the slope gradient ratio
Gradient=VIHE=150 m3,000 m=120=1:20\text{Gradient} = \frac{\text{VI}}{\text{HE}} = \frac{150\text{ m}}{3,000\text{ m}} = \frac{1}{20} = 1 : 20
Gradient expresses the ratio of vertical rise to horizontal distance when both measurements are expressed in identical units.

Anahtar Kavram

Topographic Slope Gradient Calculation
Soru 8Soru

On a topographical map drawn to a scale of 1:50,0001:50,000, a road ascends continuously from a contour elevation of 200 m200\text{ m} to 450 m450\text{ m}. If the distance along the road measured on the map is 5.0 cm5.0\text{ cm}, what is the average gradient of the road?

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Cevap: 1 in 101\text{ in }10

Cevap

The average gradient of the road is 1 in 101\text{ in }10.
To find the gradient, first compute the Vertical Interval (V.I.) as the difference between the two contour elevations: 450 m200 m=250 m450\text{ m} - 200\text{ m} = 250\text{ m}. Next, determine the Horizontal Equivalent (H.E.) on the ground by converting the map distance using the scale: 5.0 cm×50,000=250,000 cm=2,500 m5.0\text{ cm} \times 50,000 = 250,000\text{ cm} = 2,500\text{ m}. Dividing the V.I. by the H.E. gives 2502,500=110\frac{250}{2,500} = \frac{1}{10}, which expresses an average gradient of 1 in 101\text{ in }10.

Adım Adım Çözüm

1
Calculate the Vertical Interval (V.I.)
V.I.=450 m200 m=250 m\text{V.I.} = 450\text{ m} - 200\text{ m} = 250\text{ m}
The Vertical Interval is the difference in height between the upper and lower contour elevations.
2
Calculate the Horizontal Equivalent (H.E.) in ground distance
H.E.=5.0 cm×50,000=250,000 cm=2,500 m\text{H.E.} = 5.0\text{ cm} \times 50,000 = 250,000\text{ cm} = 2,500\text{ m}
The map scale of 1:50,0001:50,000 means 1 cm1\text{ cm} on the map represents 50,000 cm50,000\text{ cm} (500 m500\text{ m}) on the ground.
3
Calculate the Gradient ratio
Gradient=V.I.H.E.=250 m2,500 m=110=1 in 10\text{Gradient} = \frac{\text{V.I.}}{\text{H.E.}} = \frac{250\text{ m}}{2,500\text{ m}} = \frac{1}{10} = 1\text{ in }10
Topographic gradient is defined as the ratio of Vertical Interval to Horizontal Equivalent expressed in the same unit.

Anahtar Kavram

Calculating Topographic Gradient from Contour Lines and Map Scale
Tahmini Süre:1m 30s
Soru 9Soru

On a topographical survey map drawn to a scale of 1:40,0001:40,000, Point X lies at an elevation of 250 m250\text{ m} on a hillside, and Point Y lies further uphill along a straight spur at an elevation of 650 m650\text{ m}. If the distance between Point X and Point Y measured on the map is 5 cm5\text{ cm}, the gradient of the slope between the two points can be expressed in the ratio form 1:x1 : x. What is the numerical value of xx?

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Cevap: 5

Cevap

The numerical value of xx is 5.
The difference in elevation (Vertical Interval) between the two points is 400 m400\text{ m}. Converting the 5 cm5\text{ cm} map measurement to ground distance using the 1:40,0001:40,000 scale gives 2,000 m2,000\text{ m} (Horizontal Equivalent). Dividing the Vertical Interval by the Horizontal Equivalent yields 4002000=15\frac{400}{2000} = \frac{1}{5}, meaning the gradient expressed as 1:x1 : x has x=5x = 5.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI)
400 m
The vertical interval represents the elevation difference between Point Y and Point X: 650 m250 m=400 m650\text{ m} - 250\text{ m} = 400\text{ m}.
2
Calculate the Horizontal Equivalent (HE)
2,000 m
At a map scale of 1:40,0001:40,000, 1 cm1\text{ cm} on the map corresponds to 40,000 cm=400 m40,000\text{ cm} = 400\text{ m} on the ground. A map measurement of 5 cm5\text{ cm} equals 5×400 m=2,000 m5 \times 400\text{ m} = 2,000\text{ m}.
3
Determine the Gradient Ratio
1 : 5 (x = 5)
Gradient is determined by dividing Vertical Interval by Horizontal Equivalent: 400 m2,000 m=15\frac{400\text{ m}}{2,000\text{ m}} = \frac{1}{5}. Writing this ratio as 1:x1 : x yields x=5x = 5.

Anahtar Kavram

Slope and Gradient Calculation from Topographical Contour Maps
Soru 10Soru

On a topographical map, a series of V-shaped contour lines point towards lower elevation values as they extend across the landscape. Which of the following relief features is represented by this contour pattern?

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Cevap: Spur

Cevap

Spur
V-shaped contour lines whose apexes point towards lower elevation represent a spur, which is a tongue of elevated land projecting downwards from a main hill or ridge. Conversely, when V-shapes point upstream towards higher elevation, they indicate a river valley.

Adım Adım Çözüm

1
Analyze the contour line geometry described in the prompt
The contour lines form V-shapes pointing towards decreasing (lower) elevation.
Understanding the orientation of V-shaped contours relative to elevation is key to identifying linear relief features.
2
Distinguish between a spur and a valley using contour apex orientation
Apexes pointing upstream (higher elevation) represent valleys, whereas apexes pointing downstream/down-slope (lower elevation) represent spurs.
A spur is a salient tongue of high ground sloping downwards between two valleys.

Anahtar Kavram

Contour pattern recognition for spurs and valleys
Soru 11Soru

On a topographical map, a hillside shows contour lines that are densely packed near the hilltop at higher elevations and gradually become widely spaced towards the foot of the hill at lower elevations. Which type of relief slope does this contour pattern represent?

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Cevap: Concave slope

Cevap

Concave slope
The correct answer is a concave slope because contour lines that are closely spaced near the crest and widely spaced towards the base represent a steep upper slope transitioning into a gentle lower slope, which forms an inward-curving profile.

Adım Adım Çözüm

1
Analyze the contour line spacing at higher elevations.
Densely packed contours indicate a steep gradient near the top of the hill.
When contour lines are close together, elevation changes rapidly over a short horizontal distance.
2
Analyze the contour line spacing at lower elevations.
Widely spaced contours indicate a gentle gradient near the base of the hill.
When contour lines are far apart, elevation changes gradually over a longer horizontal distance.
3
Combine the gradient observations to identify the slope profile.
A slope that curves inward—steep near the summit and gentle near the base—is defined as a concave slope.
This physical shape corresponds to a concave profile.

Anahtar Kavram

Contour Spacing and Slope Profiles
Soru 12Soru

Match each relief feature or slope type with the contour line pattern that uniquely describes its representation on a topographical map.

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Öğeler

Concave Slope
Convex Slope
Col (Saddle)
Escarpment (Cliff)

Eşleşmeler

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Cevap

Concave Slope pairs with closely spaced contours at higher elevations and widely spaced contours at lower elevations; Convex Slope pairs with widely spaced contours at higher elevations and closely spaced contours at lower elevations; Col (Saddle) pairs with a low pass between two peaks bounded by contour lines curving away on opposing sides; Escarpment (Cliff) pairs with contour lines merging along a steep vertical face.
The paired features match their exact cartographic representations: concave slopes are steeper at high elevations; convex slopes are steeper at low elevations; cols are pass features between summits; and escarpments display merged contours due to vertical cliffs.

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1
Analyze the gradient changes of concave and convex slope profiles.
A concave slope grows steeper with altitude (contours close together near the top), while a convex slope flattens out near the top (contours widely spaced near the top).
Contour spacing directly corresponds to terrain gradient; closer contours indicate steeper slopes.
2
Identify the structural contour representation of a col or saddle.
A col appears as a low point between two adjacent high areas where contours loop away from the center gap.
The neck between two peaks creates a characteristic hourglass-shaped contour arrangement.
3
Examine how extreme vertical drops are shown on topographic maps.
A cliff or escarpment has very small or zero horizontal distance between elevation changes, making contour lines run together or merge.
Vertical relief over negligible horizontal equivalent results in overlapping contour lines.

Anahtar Kavram

Contour Line Patterns and Relief Feature Identification
Soru 13Soru

On a topographic map drawn to a scale of 1:50,0001 : 50,000, a road ascends continuously from Point A at a contour elevation of 160 m160\text{ m} to Point B at a contour elevation of 360 m360\text{ m}. If the straight-line distance between Point A and Point B measured on the map is 10 cm10\text{ cm}, calculate the gradient of the road between these two points. Express your answer as the value of NN in the ratio 1:N1 : N.

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Cevap: 25

Cevap

The value of N in the gradient ratio 1 : N is 25.
The vertical interval (difference in elevation) between the two points is 360 m160 m=200 m360\text{ m} - 160\text{ m} = 200\text{ m}. The horizontal ground distance (Horizontal Equivalent) is calculated from the map distance of 10 cm10\text{ cm} at a scale of 1:50,0001 : 50,000, giving 10 cm×50,000=500,000 cm=5,000 m10\text{ cm} \times 50,000 = 500,000\text{ cm} = 5,000\text{ m}. Dividing the vertical interval by the horizontal equivalent gives 200 m5,000 m=125\frac{200\text{ m}}{5,000\text{ m}} = \frac{1}{25}, which corresponds to a gradient ratio of 1:251 : 25, so N=25N = 25.

Adım Adım Çözüm

1
Calculate Vertical Interval (VI)
200 m
Subtract the lower contour height from the higher contour height (360 m - 160 m).
2
Calculate Horizontal Equivalent (HE) in meters
5,000 m
Multiply map measurement by scale factor (10 cm * 50,000 = 500,000 cm = 5,000 m).
3
Compute the gradient ratio (VI / HE)
1 / 25
Divide 200 m by 5,000 m and simplify the fraction to 1 / 25.

Anahtar Kavram

Slope and Gradient Calculation from Topographical Map Contours
Soru 14Soru

Match each contour line pattern listed on the left with the corresponding relief landform it represents on the right.

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Öğeler

Concentric closed contour lines with elevation values decreasing towards the center
V-shaped contour lines with the apex of the V pointing towards higher ground
Closely spaced contours at higher elevation changing to widely spaced contours at lower elevation
Two adjacent sets of closed high-elevation contours separated by a narrow lower dip

Eşleşmeler

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Cevap

The correct matches are: Concentric closed contours decreasing inward match with Depression or Basin; V-shaped contours pointing uphill match with River Valley or Stream Bed; Contours closely spaced above and widely spaced below match with Concave Slope; Two high closed contour sets separated by a narrow dip match with Saddle or Col.
Each contour pattern corresponds directly to a distinct landform: inward-decreasing closed contours represent a depression; uphill-pointing V-contours mark a river valley; steep-then-gentle contour density indicates a concave slope; and a low ridge between two peaks forms a saddle or col.

Adım Adım Çözüm

1
Analyze contour spacing and elevation trends for closed ring patterns.
Decreasing values toward the center signify a depression rather than a hill summit.
Topographic elevation decreases toward the middle in depressions.
2
Examine V-shaped contour orientation relative to elevation values.
The apex pointing toward higher terrain indicates water flow direction down the valley line.
Valleys cut into terrain such that contour V-shapes point up-valley toward higher ground.
3
Evaluate contour density variations from higher to lower elevations.
Steep slope near the top transition to gentle slope at the bottom defines a concave profile.
Contour spacing directly correlates with slope steepness (close = steep, wide = gentle).
4
Identify relief between two high hilltops.
The low region connecting two summits represents a saddle or col.
A saddle is formed by the low area between two surrounding high points.

Anahtar Kavram

Relief Representation and Contour Patterns
Soru 15Soru

On a topographic map, index contours are drawn at elevations of 400 m400\text{ m} and 700 m700\text{ m}. There are 55 equal contour intervals (spaces) between these two index contours. A radio transmission mast is located on a contour line situated 33 contour intervals higher than the 700 m700\text{ m} index contour. What is the elevation, in meters, of the contour line where the radio mast is located?

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Cevap: 880

Cevap

The elevation of the contour line where the radio mast stands is 880 m880\text{ m}.
The elevation difference between the 400 m400\text{ m} and 700 m700\text{ m} index lines is 300 m300\text{ m}. With 55 equal spaces separating them, the contour interval is 60 m60\text{ m}. Adding 33 contour intervals (180 m180\text{ m}) to the 700 m700\text{ m} index line yields an elevation of 880 m880\text{ m}.

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1
Calculate the elevation difference between the given index contours.
Vertical difference = 700 m400 m=300 m700\text{ m} - 400\text{ m} = 300\text{ m}.
Index contours serve as reference lines to determine the vertical rise across intervening contour spaces.
2
Determine the contour interval (the vertical distance between consecutive contour lines).
Contour Interval = 300 m5=60 m\frac{300\text{ m}}{5} = 60\text{ m}.
Dividing the total height difference between index lines by the number of spaces gives the value of a single contour interval.
3
Calculate the target elevation at 3 contour intervals above the 700 m700\text{ m} index line.
Target elevation = 700 m+(3×60 m)=880 m700\text{ m} + (3 \times 60\text{ m}) = 880\text{ m}.
Adding three vertical intervals (180 m180\text{ m}) to the 700 m700\text{ m} reference line gives the exact height of the target contour line.

Anahtar Kavram

Contour Interval Determination and Relief Elevation Calculation
Soru 16Soru

On a topographical map, a surveyor assesses two observation posts: Post X at an elevation of 750 m750\text{ m} and Post Y at an elevation of 900 m900\text{ m}, separated by a straight-line distance of 4.0 km4.0\text{ km}. An intervening ridge crest with a summit elevation of 820 m820\text{ m} is located exactly 1.5 km1.5\text{ km} along the line of sight from Post X. Assuming a direct line of sight between the two posts, which of the following statements correctly evaluates their intervisibility?

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Cevap: The posts are not intervisible because the elevation of the line of sight at the ridge location is 806.25 m806.25\text{ m}, which is below the ridge summit elevation of 820 m820\text{ m}.

Cevap

The posts are not intervisible because the line of sight elevation at the position of the intervening ridge is 806.25 m806.25\text{ m}, which is lower than the ridge crest of 820 m820\text{ m}.
Intervisibility between two points on a contour map requires that no intervening landform rises above the imaginary straight ray connecting them. Calculating the line of sight height at 1.5 km1.5\text{ km} gives 750 m+(1.54.0×150 m)=806.25 m750\text{ m} + \left(\frac{1.5}{4.0} \times 150\text{ m}\right) = 806.25\text{ m}. Because the intervening ridge reaches 820 m820\text{ m}, it obstructs the view, making the posts non-intervisible.

Adım Adım Çözüm

1
Calculate the total vertical height difference between Post X and Post Y.
Vertical Difference =900 m750 m=150 m= 900\text{ m} - 750\text{ m} = 150\text{ m}.
Establishes the total elevation gain along the 4.0 km4.0\text{ km} line of sight.
2
Determine the proportional vertical rise along the line of sight at a distance of 1.5 km1.5\text{ km} from Post X.
Proportional Rise =1.5 km4.0 km×150 m=0.375×150 m=56.25 m= \frac{1.5\text{ km}}{4.0\text{ km}} \times 150\text{ m} = 0.375 \times 150\text{ m} = 56.25\text{ m}.
Determines how much elevation the line of sight gains over the distance to the intervening ridge.
3
Calculate the absolute elevation of the line of sight above sea level at the ridge position.
Line of Sight Elevation =750 m+56.25 m=806.25 m= 750\text{ m} + 56.25\text{ m} = 806.25\text{ m}.
Provides the baseline height of the visual ray path at the obstacle's location.
4
Compare the line of sight elevation with the actual ground elevation of the ridge summit.
Ground Elevation (820 m820\text{ m}) >> Line of Sight Elevation (806.25 m806.25\text{ m}). Intervisibility is obstructed.
If the terrain height is greater than the line of sight height, the view between the two points is blocked.

Anahtar Kavram

Intervisibility and Profile Line of Sight Analysis
Soru 17Soru

In topographical map interpretation, distinct contour patterns uniquely represent specific physical landforms and slope profiles. Match each contour line configuration on the left with the corresponding relief feature it describes on the right.

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Öğeler

Concentric closed contours with elevation values decreasing progressively towards the innermost contour line
Contours that are widely spaced near the summit and become progressively more densely packed towards lower elevations
Two distinct high-elevation contour loops enclosed within an outer ring contour, separated by a low-lying pass
Closely packed parallel contours that abruptly coincide and merge into a single continuous line

Eşleşmeler

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Cevap

The correct pairings are: Concentric closed contours decreasing inward match Crater or Depression; Widely spaced top contours becoming densely packed bottom contours match Convex Slope; Twin elevated contour loops separated by a pass match Saddle or Col; Closely packed contours merging into a single line match Vertical Cliff.
Each contour pattern corresponds directly to a unique 3D landform: decreasing inner values represent a crater/depression; wide spacing at upper elevations becoming dense at lower elevations represents a convex slope; twin enclosed summits represent a saddle/col; and coinciding merged lines represent a vertical cliff face.

Adım Adım Çözüm

1
Analyze contour value progression for closed loops.
Decreasing values toward the center signify a depression or crater.
Standard hills show increasing values inward; decreasing values indicate a descent into a enclosed hollow.
2
Examine contour spacing density across elevation levels.
Wide spacing at higher elevation transitioning to dense spacing at lower elevation indicates a convex slope.
Contour spacing is inversely proportional to gradient steepness; gentle upper slopes are widely spaced while steep lower slopes are closely spaced.
3
Identify multi-peak structural contour patterns.
Twin contour summits surrounded by an outer ring contour represent a saddle or col.
A saddle is the low point between two higher relief features.
4
Interpret overlapping or coalescing contour lines.
Merged contour lines represent a vertical cliff.
A vertical surface has zero horizontal equivalent distance between different elevation contours.

Anahtar Kavram

Relief Representation and Contour Line Pattern Interpretation
Tahmini Süre:2m 0s
Soru 18Soru

On a topographical map with a constant contour interval of 20 m20\text{ m}, Point X is located on the contour line labeled 240 m240\text{ m}. Point Y is located higher up the same hill, exactly three contour intervals above Point X. What is the elevation of Point Y in meters?

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Cevap: 300

Cevap

The elevation of Point Y is 300 m300\text{ m}.
The contour interval indicates that consecutive contour lines differ by 20 m20\text{ m} in elevation. Moving up three contour line intervals from Point X (240 m240\text{ m}) increases elevation by 3×20 m=60 m3 \times 20\text{ m} = 60\text{ m}. Thus, the elevation at Point Y is 240 m+60 m=300 m240\text{ m} + 60\text{ m} = 300\text{ m}.

Adım Adım Çözüm

1
Calculate total vertical rise between the two points
Vertical rise = 3×20 m=60 m3 \times 20\text{ m} = 60\text{ m}
Point Y is three contour intervals higher than Point X, and each interval represents 20 m20\text{ m} of vertical distance.
2
Calculate the elevation at Point Y
Elevation at Point Y = 240 m+60 m=300 m240\text{ m} + 60\text{ m} = 300\text{ m}
Adding the total vertical rise to the baseline elevation at Point X yields the final elevation at Point Y.

Anahtar Kavram

Calculating elevation on topographical maps using contour intervals
Tahmini Süre:45s
Soru 19Soru

On a topographical map drawn to a scale of 1:25,0001 : 25,000, a road ascends continuously from Point X at an elevation of 120 m120\text{ m} to Point Y at an elevation of 370 m370\text{ m}. If the average gradient of the slope along this road is 1 in 201 \text{ in } 20, what is the distance between Point X and Point Y on the map?

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Cevap: 20 cm20\text{ cm}

Cevap

The distance between Point X and Point Y on the map is 20 cm20\text{ cm}.
The elevation difference (Vertical Interval) between the two points is 370 m120 m=250 m370\text{ m} - 120\text{ m} = 250\text{ m}. Given a gradient of 1 in 201 \text{ in } 20, the horizontal distance on the ground is 250 m×20=5,000 m250\text{ m} \times 20 = 5,000\text{ m} (500,000 cm500,000\text{ cm}). Dividing this by the scale factor of 25,00025,000 yields a map distance of 20 cm20\text{ cm}.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI)
VI=370 m120 m=250 m\text{VI} = 370\text{ m} - 120\text{ m} = 250\text{ m}
Vertical interval is the difference in height between the two contour points.
2
Calculate the Horizontal Equivalent (HE) on the ground using the gradient formula
HE=VI×20=250 m×20=5,000 m\text{HE} = \text{VI} \times 20 = 250\text{ m} \times 20 = 5,000\text{ m}
Gradient is given as VI/HE=1/20\text{VI} / \text{HE} = 1 / 20, so HE=20×VI\text{HE} = 20 \times \text{VI}.
3
Convert the ground distance to centimeters and calculate the map distance using the scale 1:25,0001 : 25,000
Ground distance=5,000 m=500,000 cm\text{Ground distance} = 5,000\text{ m} = 500,000\text{ cm}; Map distance=500,000 cm25,000=20 cm\text{Map distance} = \frac{500,000\text{ cm}}{25,000} = 20\text{ cm}
To find distance on the map, convert the ground measurement to centimeters and divide by the scale denominator.

Anahtar Kavram

Topographical Gradient and Scale Conversion
Tahmini Süre:1m 30s
Soru 20Soru

On a topographical map with a scale of 1:25,0001 : 25,000 and a contour interval of 20 m20\text{ m}, a river flows down a valley. Contour line V1V_1, whose V-shape apex points upstream toward higher elevation, crosses the river channel at an elevation of 360 m360\text{ m}. Further downstream, the river crosses contour line V2V_2, which is separated from V1V_1 by 44 contour intervals. If the measured map distance along the stream between these two crossing points is 8 cm8\text{ cm}, what is the average gradient of the river channel between V1V_1 and V2V_2?

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Cevap: 1 in 25

Cevap

The average gradient of the river channel between points V1 and V2 is 1 in 25.
The vertical interval (VI) represents the height difference between the two points along the stream, which is equal to 4 intervals×20 m=80 m4 \text{ intervals} \times 20\text{ m} = 80\text{ m}. The horizontal equivalent (HE) is calculated by multiplying the map distance (8 cm8\text{ cm}) by the scale factor (25,00025,000), yielding 200,000 cm200,000\text{ cm} or 2,000 m2,000\text{ m}. Dividing VI by HE yields 802000=125\frac{80}{2000} = \frac{1}{25}, expressed as a ratio of 1 in 25.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI) between contour crossings
Vertical Interval (VI) = 4 intervals×20 m=80 m4 \text{ intervals} \times 20\text{ m} = 80\text{ m}
Since the stream flows downstream, elevation drops by 4 contour intervals from the initial elevation of 360m.
2
Convert the map distance to actual ground distance (Horizontal Equivalent, HE)
Ground distance (HE) = 8 cm×25,000=200,000 cm=2,000 m8\text{ cm} \times 25,000 = 200,000\text{ cm} = 2,000\text{ m}
Map scale 1 : 25,000 means 1 cm on the map equals 25,000 cm (or 250 m) on the ground.
3
Calculate the gradient using the ratio formula VI / HE
Gradient = 80 m2,000 m=125\frac{80\text{ m}}{2,000\text{ m}} = \frac{1}{25} or 1 in 251 \text{ in } 25
Both Vertical Interval and Horizontal Equivalent must be expressed in the same unit (meters) to compute the gradient ratio.

Anahtar Kavram

Topographic Gradient and Relief Interpretation
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Contour Lines and Relief Representation Alıştırma Soruları — JAMB UTME | Examkin