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Zorluk: KolayLinear Equations in Two Variables

A linear relationship between xx and yy is defined by the values in the table below.

xxyy
27
413
619

Which of the following equations represents this relationship?

  1. A
    y=3x5y = 3x - 5
  2. B
    y=13x+193y = \frac{1}{3}x + \frac{19}{3}
  3. y=3x+1y = 3x + 1Cevap
  4. D
    y=6x5y = 6x - 5

Cevap

The equation representing the relationship is y=3x+1y = 3x + 1.
The correct equation is y=3x+1y = 3x + 1. The slope mm of the linear function can be determined from the table values (2,7)(2, 7) and (4,13)(4, 13) as 13742=62=3\frac{13 - 7}{4 - 2} = \frac{6}{2} = 3. Substituting the slope m=3m = 3 and the point (2,7)(2, 7) into the slope-intercept form y=mx+by = mx + b gives 7=3(2)+b7 = 3(2) + b, which simplifies to 7=6+b7 = 6 + b, so b=1b = 1. Therefore, the equation is y=3x+1y = 3x + 1.

Adım Adım Çözüm

1
Find the slope (mm) of the linear relationship using the points (2,7)(2, 7) and (4,13)(4, 13) from the table.
m=3m = 3
The slope is the ratio of the change in yy to the change in xx between any two points on the line: m=13742=62=3m = \frac{13 - 7}{4 - 2} = \frac{6}{2} = 3.
2
Use the slope m=3m = 3 and the point (2,7)(2, 7) to find the yy-intercept (bb) of the line.
b=1b = 1
Substituting the coordinates and slope into the slope-intercept equation y=mx+by = mx + b gives 7=3(2)+b7 = 3(2) + b, which simplifies to 7=6+b7 = 6 + b, leading to b=1b = 1.
3
Substitute the slope and yy-intercept into the slope-intercept form.
y=3x+1y = 3x + 1
Combining the slope of 33 and yy-intercept of 11 yields the equation y=3x+1y = 3x + 1.

Anahtar Kavram

Determining a linear equation from a table of values
Tahmini Süre:45s
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