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Zorluk: OrtaLinear Equations in Two Variables

In the xyxy-plane, a line is represented by the equation ay−bx=24ay - bx = 24, where aa and bb are constants. If the line has a yy-intercept of (0,−3)(0, -3) and passes through the point (4,5)(4, 5), what is the slope of the line?

Cevap: 2

Cevap

The slope of the line is 2.
Substituting the y-intercept (0,−3)(0, -3) into the equation ay−bx=24ay - bx = 24 yields −3a=24-3a = 24, which gives a=−8a = -8. Substituting the point (4,5)(4, 5) and a=−8a = -8 into the equation yields −8(5)−4b=24-8(5) - 4b = 24, which simplifies to −40−4b=24-40 - 4b = 24, giving b=−16b = -16. Re-assembling the equation gives −8y+16x=24-8y + 16x = 24. Solving for yy in terms of xx yields y=2x−3y = 2x - 3, where the coefficient of xx is the slope, 2.

Adım Adım Çözüm

1
Substitute the y-intercept (0,−3)(0, -3) into the given equation ay−bx=24ay - bx = 24 to find the value of aa.
a=−8a = -8
Since the y-intercept lies on the line, its coordinates satisfy the line's equation.
2
Substitute the point (4,5)(4, 5) and the value of a=−8a = -8 into the equation to find the value of bb.
b=−16b = -16
Since the point (4,5)(4, 5) lies on the line, its coordinates must satisfy the equation.
3
Write the resulting equation −8y+16x=24-8y + 16x = 24 in slope-intercept form (y=mx+cy = mx + c) to identify the slope.
y=2x−3y = 2x - 3, which gives a slope of 22.
The slope of a line in the form y=mx+cy = mx + c is represented by the coefficient mm of xx.

Anahtar Kavram

Finding the slope of a line from a given equation by determining its constant coefficients using known points.
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