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Zorluk: OrtaNonlinear Systems of Equations

In the xyxy-plane, the graphs of the linear function 3x+y=63x + y = 6 and the quadratic function y=3x25x2y = 3x^2 - 5x - 2 intersect at two points. What is the sum of the yy-coordinates of these two intersection points?

  1. 10Cevap
  2. B
    23\frac{2}{3}
  3. C
    14
  4. D
    2

Cevap

10
The correct answer is 10. By rewriting the linear equation as y=63xy = 6 - 3x and substituting it into the quadratic equation, we get 63x=3x25x26 - 3x = 3x^2 - 5x - 2. Collecting all terms on one side yields the quadratic equation 3x22x8=03x^2 - 2x - 8 = 0. Factoring this equation gives (3x+4)(x2)=0(3x + 4)(x - 2) = 0, which results in x=2x = 2 and x=43x = -\frac{4}{3}. Substituting these xx-values back into the linear equation gives the yy-coordinates: y=63(2)=0y = 6 - 3(2) = 0 and y=63(43)=10y = 6 - 3(-\frac{4}{3}) = 10. The sum of these yy-coordinates is 0+10=100 + 10 = 10.

Adım Adım Çözüm

1
Express yy in terms of xx using the linear equation.
y=63xy = 6 - 3x
Isolating yy makes substitution into the quadratic equation straightforward.
2
Substitute the expression for yy into the quadratic equation and set the equation to zero.
63x=3x25x26 - 3x = 3x^2 - 5x - 2, which simplifies to 3x22x8=03x^2 - 2x - 8 = 0.
This forms a single quadratic equation in terms of xx to find the xx-coordinates of the intersection points.
3
Solve the quadratic equation by factoring.
(3x+4)(x2)=0(3x + 4)(x - 2) = 0, yielding x=2x = 2 and x=43x = -\frac{4}{3}.
Factoring determines the values of xx at the points of intersection.
4
Substitute the xx-values back into the linear equation y=63xy = 6 - 3x to find the corresponding yy-coordinates.
For x=2x = 2: y=63(2)=0y = 6 - 3(2) = 0. For x=43x = -\frac{4}{3}: y=63(43)=10y = 6 - 3(-\frac{4}{3}) = 10.
This identifies the coordinates of the two intersection points as (2,0)(2, 0) and (43,10)(-\frac{4}{3}, 10).
5
Calculate the sum of the yy-coordinates.
0+10=100 + 10 = 10
The question asks for the sum of the yy-coordinates of the two intersection points.

Anahtar Kavram

Solving a system of linear and quadratic equations using substitution.
Tahmini Süre:1m 30s
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