Tüm alıştırma soruları

2789 soru

Soru 1481Soru

A moving company uses the equation C=2.5d+75C = 2.5d + 75 to determine the total charge CC, in dollars, for renting a small truck and driving it dd miles. According to the relationship, what is the charge, in dollars, for each mile the truck is driven?

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Cevap: 2.5

Cevap

The charge for each mile the truck is driven is 2.5 dollars.
In the linear model C=2.5d+75C = 2.5d + 75, the total cost CC is a function of the number of miles driven dd. The rate of change of this function represents the cost per mile driven. In the equation, this rate of change is the coefficient of dd, which is 2.5. Therefore, the charge for each mile the truck is driven is 2.5 dollars.

Adım Adım Çözüm

1
Analyze the linear equation C=2.5d+75C = 2.5d + 75 to determine the relationship between variables.
The total charge CC depends on the number of miles dd driven, with a rate of change of 2.5 dollars per mile and a base fee of 75 dollars.
Understanding the components of a linear equation helps isolate the rate of change.
2
Identify the coefficient of the independent variable dd.
The coefficient of dd is 2.5.
In a linear equation of the form y=mx+by = mx + b, the coefficient of the independent variable represents the rate of change.
3
Interpret the meaning of this coefficient in the context of the problem.
The coefficient 2.5 represents the cost, in dollars, incurred per mile driven.
The question asks for the charge per mile, which corresponds to the rate of change.

Anahtar Kavram

Interpreting Linear Relationships in Context
Soru 1482Soru

A system of two equations is given:

y=x2+kx+4y = x^2 + kx + 4
y=4xky = 4x - k

In these equations, kk represents a positive constant. If the system has a single real solution, what is the value of kk?

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Cevap: 12

Cevap

12
Setting the two equations equal yields the quadratic equation x2+(k4)x+(k+4)=0x^2 + (k - 4)x + (k + 4) = 0. For the system to have exactly one real solution, the discriminant of this quadratic equation must be equal to 00. The discriminant is (k4)24(1)(k+4)=k212k(k - 4)^2 - 4(1)(k + 4) = k^2 - 12k. Solving k212k=0k^2 - 12k = 0 yields k=0k = 0 or k=12k = 12. Since kk must be positive, the value of kk is 1212.

Adım Adım Çözüm

1
Set the two equations equal to each other to form a single quadratic equation in terms of xx.
x2+(k4)x+(k+4)=0x^2 + (k - 4)x + (k + 4) = 0
Equating the expressions for yy allows us to find the xx-coordinates where the graphs of the two equations intersect.
2
Set the discriminant of the quadratic equation to zero.
(k4)24(1)(k+4)=0(k - 4)^2 - 4(1)(k + 4) = 0
A system of equations consisting of a line and a parabola has a single real solution if and only if the line is tangent to the parabola, which corresponds to a quadratic equation with a discriminant of zero.
3
Expand and simplify the equation for kk.
k212k=0k^2 - 12k = 0
Expanding (k4)2(k - 4)^2 yields k28k+16k^2 - 8k + 16, and distributing 4-4 yields 4k16-4k - 16. Combining like terms simplifies the relation.
4
Solve for kk and apply the constraint that k>0k > 0.
k=12k = 12
Factoring k(k12)=0k(k - 12) = 0 gives k=0k = 0 or k=12k = 12. Since kk is specified to be positive, k=12k = 12 is the correct value.

Anahtar Kavram

Solving nonlinear systems of equations by substitution and using the discriminant to find conditions for a single real solution.
Soru 1483Soru

A software programmer is writing test cases for a new application. The programmer must write at least 15 test cases in total, consisting of xx unit tests and yy integration tests. Each unit test takes 10 minutes to write, and each integration test takes 30 minutes to write. If the programmer has at most 300 minutes to write all the test cases, what is the maximum number of integration tests the programmer can write?

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Cevap: 7

Cevap

7

Adım Adım Çözüm

1
Set up the system of inequalities representing the given constraints.
x+y15x + y \ge 15 and 10x+30y30010x + 30y \le 300
The total number of tests must be at least 15, and the total time taken by writing xx unit tests (10 minutes each) and yy integration tests (30 minutes each) cannot exceed 300 minutes.
2
Simplify the time inequality and combine it with the total test count constraint to isolate yy.
x+3y30x + 3y \le 30. Substituting x15yx \ge 15 - y into this inequality yields (15y)+3y30    15+2y30(15 - y) + 3y \le 30 \implies 15 + 2y \le 30.
Simplification and substitution help find the upper bound for the number of integration tests.
3
Solve for yy and determine the maximum integer value.
2y15    y7.52y \le 15 \implies y \le 7.5. The largest integer satisfying this inequality is 7.
The number of integration tests must be a whole number, so we round down to the nearest integer.
4
Verify that a valid integer number of unit tests (xx) exists when y=7y = 7.
When y=7y = 7, we get x157    x8x \ge 15 - 7 \implies x \ge 8 and x+3(7)30    x9x + 3(7) \le 30 \implies x \le 9. The integers x=8x = 8 and x=9x = 9 both satisfy the conditions.
We must confirm that the maximum value of yy is achievable with an integer number of unit tests.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 1484Soru

If (x,y)(x, y) is a solution to the system of equations below and x>0x > 0, what is the value of x+yx + y?

x2+y2=50xy=6\begin{aligned} x^2 + y^2 &= 50 \\ x - y &= 6 \end{aligned}
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Cevap: 8

Cevap

8
Solving the linear equation for xx gives x=y+6x = y + 6. Substituting this into the circle equation yields (y+6)2+y2=50(y + 6)^2 + y^2 = 50, which simplifies to 2y2+12y14=02y^2 + 12y - 14 = 0. Dividing by 22 gives y2+6y7=0y^2 + 6y - 7 = 0, which factors as (y+7)(y1)=0(y + 7)(y - 1) = 0. This yields y=1y = 1 (with x=7x = 7) or y=7y = -7 (with x=1x = -1). The constraint x>0x > 0 requires selecting the solution (7,1)(7, 1). The sum of xx and yy for this solution is 7+1=87 + 1 = 8.

Adım Adım Çözüm

1
Express xx in terms of yy using the linear equation.
x=y+6x = y + 6
This allows for substitution into the second equation to reduce the system to a single variable.
2
Substitute the expression for xx into the equation of the circle and expand.
2y2+12y14=02y^2 + 12y - 14 = 0
Substituting x=y+6x = y + 6 into x2+y2=50x^2 + y^2 = 50 yields (y+6)2+y2=50(y + 6)^2 + y^2 = 50. Expanding gives y2+12y+36+y2=50y^2 + 12y + 36 + y^2 = 50.
3
Simplify and solve the quadratic equation by factoring.
y=1y = 1 or y=7y = -7
Dividing the equation by 2 gives y2+6y7=0y^2 + 6y - 7 = 0, which factors as (y+7)(y1)=0(y + 7)(y - 1) = 0.
4
Calculate the corresponding values of xx for each yy.
For y=1y = 1, x=7x = 7; for y=7y = -7, x=1x = -1
Using the relation x=y+6x = y + 6 yields the coordinates of the two intersection points.
5
Apply the constraint x>0x > 0 and calculate x+yx + y.
x+y=8x + y = 8
Since x>0x > 0, the only valid solution is (7,1)(7, 1). The sum of the coordinates is 7+1=87 + 1 = 8.

Anahtar Kavram

Solving a nonlinear system of equations representing a circle and a line using substitution and factoring.
Soru 1485Soru

In the xyxy-plane, the graph of the linear equation 3x+5y=c3x + 5y = c, where cc is a constant, passes through the point (4,3)(4, 3). What is the xx-coordinate of the point on this graph where the yy-coordinate is 3-3?

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Cevap: 14

Cevap

The correct answer is 14.
To find the correct answer, first substitute the given point (4,3)(4, 3) into the equation 3x+5y=c3x + 5y = c to determine the value of the constant cc: 3(4)+5(3)=12+15=273(4) + 5(3) = 12 + 15 = 27. Thus, the equation is 3x+5y=273x + 5y = 27. Next, substitute 3-3 for yy in this equation to find the corresponding xx-coordinate: 3x+5(3)=27    3x15=273x + 5(-3) = 27 \implies 3x - 15 = 27. Adding 1515 to both sides gives 3x=423x = 42, and dividing by 33 yields x=14x = 14.

Adım Adım Çözüm

1
Substitute the point (4,3)(4, 3) into the equation 3x+5y=c3x + 5y = c to solve for cc.
c=27c = 27
Since the point lies on the graph of the equation, its coordinates must satisfy the equation.
2
Substitute y=3y = -3 and c=27c = 27 into the equation 3x+5y=c3x + 5y = c.
3x15=273x - 15 = 27
We want to find the xx-coordinate of the point on the line when the yy-coordinate is 3-3.
3
Solve the equation 3x15=273x - 15 = 27 for xx.
x=14x = 14
Isolating xx gives the xx-coordinate of the point.

Anahtar Kavram

Using a known point on a line to find a constant coefficient or constant term, and using the resulting equation to find other coordinates.

Alternatif Yöntem

Alternatively, you can write the equation in slope-intercept form. Solving 3x+5y=c3x + 5y = c for yy gives y=35x+c5y = -\frac{3}{5}x + \frac{c}{5}. The slope of the line is 35-\frac{3}{5}. Since the slope is constant, the change in yy divided by the change in xx between (4,3)(4, 3) and (x,3)(x, -3) is equal to the slope: 33x4=35    6x4=35\frac{-3 - 3}{x - 4} = -\frac{3}{5} \implies \frac{-6}{x - 4} = -\frac{3}{5}. Cross-multiplying gives 30=3(x4)    10=x4    x=14-30 = -3(x - 4) \implies 10 = x - 4 \implies x = 14.
Tahmini Süre:1m 30s
Soru 1486Soru

For all x>3x > 3, which of the following expressions is equivalent to x29x22x3x+1x\frac{x^2 - 9}{x^2 - 2x - 3} \cdot \frac{x + 1}{x}?

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Cevap: x+3x\frac{x+3}{x}

Cevap

x+3x\frac{x+3}{x}
Factoring the numerator of the first fraction as (x3)(x+3)(x-3)(x+3) and its denominator as (x3)(x+1)(x-3)(x+1) allows the common factor (x3)(x-3) to cancel out, leaving x+3x+1\frac{x+3}{x+1}. Multiplying this result by the second fraction, x+1x\frac{x+1}{x}, permits the cancellation of the common factor (x+1)(x+1), which simplifies the entire expression to the equivalent form x+3x\frac{x+3}{x}.

Adım Adım Çözüm

1
Factor the numerator and the denominator of the first rational expression: x29x22x3\frac{x^2 - 9}{x^2 - 2x - 3}.
The numerator factors as (x3)(x+3)(x - 3)(x + 3) using the difference of squares identity. The denominator factors as (x3)(x+1)(x - 3)(x + 1) by finding two numbers that multiply to 3-3 and add to 2-2.
Factoring polynomials is necessary to identify and cancel common factors.
2
Simplify the first fraction by canceling the common factor (x3)(x-3) from both the numerator and denominator.
The first fraction simplifies to x+3x+1\frac{x+3}{x+1}.
Since x>3x > 3, the term x3x-3 is non-zero, making division by it valid.
3
Multiply the simplified first fraction by the second fraction: x+3x+1x+1x\frac{x+3}{x+1} \cdot \frac{x+1}{x}.
The common factor (x+1)(x+1) in the numerator and denominator cancels out, resulting in x+3x\frac{x+3}{x}.
Canceling the common factor (x+1)(x+1) yields the simplest equivalent expression.

Anahtar Kavram

Simplifying rational expressions by factoring polynomials and canceling common factors.
Soru 1487Soru

For all x>3x > 3, the expression x32x29x+18x25x+6x3+3x24x12x2+5x+6\frac{x^3 - 2x^2 - 9x + 18}{x^2 - 5x + 6} - \frac{x^3 + 3x^2 - 4x - 12}{x^2 + 5x + 6} is equivalent to the constant kk. What is the value of kk?

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Cevap: 5

Cevap

The value of the constant kk is 5.
Factoring the numerators by grouping yields x32x29x+18=(x3)(x+3)(x2)x^3 - 2x^2 - 9x + 18 = (x-3)(x+3)(x-2) and x3+3x24x12=(x2)(x+2)(x+3)x^3 + 3x^2 - 4x - 12 = (x-2)(x+2)(x+3). Dividing out their respective denominators (x2)(x3)(x-2)(x-3) and (x+2)(x+3)(x+2)(x+3) leaves the simplified linear expressions x+3x+3 and x2x-2. Subtracting these yields (x+3)(x2)=5(x+3) - (x-2) = 5.

Adım Adım Çözüm

1
Factor the numerator and denominator of the first rational expression and cancel common factors.
x+3x + 3
To simplify the first fraction by reducing it to its lowest terms.
2
Factor the numerator and denominator of the second rational expression and cancel common factors.
x2x - 2
To simplify the second fraction by reducing it to its lowest terms.
3
Subtract the second simplified expression from the first simplified expression.
5
To find the constant value equivalent to the given difference of rational expressions, ensuring to distribute the negative sign to all parts of the subtracted binomial.

Anahtar Kavram

Simplifying rational expressions by factoring cubic polynomials by grouping and quadratic trinomials
Soru 1488Soru

If the expression 6x2+7x202x3\frac{6x^2 + 7x - 20}{2x - 3} is equivalent to ax+b+c2x3ax + b + \frac{c}{2x-3} for all x1.5x \neq 1.5, where aa, bb, and cc are constants, what is the value of a+b+ca + b + c?

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Cevap: 15

Cevap

The value of a+b+ca + b + c is 15.
By dividing the numerator 6x2+7x206x^2 + 7x - 20 by the denominator 2x32x - 3, we find that the quotient is 3x+83x + 8 and the remainder is 44. Thus, the expression can be rewritten as 3x+8+42x33x + 8 + \frac{4}{2x-3}. Comparing this to the given expression ax+b+c2x3ax + b + \frac{c}{2x-3}, we obtain a=3a = 3, b=8b = 8, and c=4c = 4. Their sum is 3+8+4=153 + 8 + 4 = 15.

Adım Adım Çözüm

1
Set up the polynomial division of the numerator 6x2+7x206x^2 + 7x - 20 by the denominator 2x32x - 3.
Dividing 6x2+7x206x^2 + 7x - 20 by 2x32x - 3.
To express the rational expression in terms of a polynomial quotient and a remainder.
2
Divide the first term of the numerator by the first term of the denominator to determine the first quotient term.
The first term is 3x3x. Subtracting 3x(2x3)3x(2x - 3) from the numerator leaves 16x2016x - 20.
6x22x=3x\frac{6x^2}{2x} = 3x, and subtracting 6x29x6x^2 - 9x from the polynomial leaves the next term to be divided.
3
Divide the leading term of the remaining expression by the leading term of the denominator to determine the constant term of the quotient.
The constant term is 88. Subtracting 8(2x3)8(2x - 3) from 16x2016x - 20 leaves a remainder of 44.
16x2x=8\frac{16x}{2x} = 8, and subtracting 16x2416x - 24 from 16x2016x - 20 gives the final constant remainder.
4
Compare the quotient and remainder to the given form to identify aa, bb, and cc.
a=3a = 3, b=8b = 8, and c=4c = 4.
The quotient is 3x+83x + 8 and the remainder is 44, which matches the form ax+b+c2x3ax + b + \frac{c}{2x-3}.
5
Calculate the sum of aa, bb, and cc.
3+8+4=153 + 8 + 4 = 15.
The question asks for the value of a+b+ca + b + c.

Anahtar Kavram

Polynomial division and rewrite of rational expressions
Soru 1489Soru

In the field of paleoethnobotany, phytoliths—microscopic silica structures formed within plant tissues—are invaluable because they can survive for thousands of years after the surrounding organic material decays. By analyzing these durable microfossils, researchers can reconstruct ancient agricultural ______ identifying the exact plant species from phytolith shapes alone remains a significant challenge due to structural variations.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: practices; however,

Cevap

practices; however,
The sentence contains two independent clauses. The first independent clause is 'By analyzing these durable microfossils, researchers can reconstruct ancient agricultural practices,' and the second is 'identifying the exact plant species from phytolith shapes alone remains a significant challenge due to structural variations.' To connect two independent clauses, a semicolon must be used. Furthermore, because the second clause presents a contrast to the first, the conjunctive adverb 'however' is appropriate and must be followed by a comma.

Adım Adım Çözüm

1
Identify the clause boundaries in the sentence.
The sentence contains two independent clauses: 'By analyzing these durable microfossils, researchers can reconstruct ancient agricultural practices' and 'identifying the exact plant species from phytolith shapes alone remains a significant challenge due to structural variations.'
Determining where one independent clause ends and the next begins is necessary to select the correct punctuation and linking words.
2
Analyze the relationship between the two independent clauses.
The second clause presents a limitation or contrast to the first clause.
Understanding the logical connection helps choose the right transition word or conjunction.
3
Evaluate the choices to find the one that grammatically and logically connects the clauses.
The option with a semicolon followed by 'however' and a comma correctly joins the two independent clauses while expressing a contrast.
A semicolon is a standard way to link independent clauses, and 'however' is the correct conjunctive adverb for contrast.

Anahtar Kavram

Clause Boundaries and Linking
Soru 1490Soru

A commercial cargo aircraft's total weight WW, in kilograms, is modeled as a linear function of the volume of fuel FF, in liters, in its fuel tanks. The equation modeling this relationship is:

W=0.8F+74,000W = 0.8F + 74,000

To comply with runway safety regulations at a destination airport, the aircraft's total weight must not exceed 85,00085,000 kilograms upon landing. The aircraft takes off with 18,00018,000 liters of fuel and consumes fuel at a constant rate of 1,7001,700 liters per hour of flight. What is the minimum number of hours the aircraft must fly before it can safely land?

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Cevap: 2.5

Cevap

The minimum number of hours the aircraft must fly is 2.5.
To satisfy runway safety regulations, the aircraft's weight must be at most 85,00085,000 kg. According to the weight model W=0.8F+74,000W = 0.8F + 74,000, we set 0.8F+74,00085,0000.8F + 74,000 \leq 85,000, which simplifies to 0.8F11,0000.8F \leq 11,000. Dividing by the density coefficient 0.80.8 yields F13,750F \leq 13,750 liters as the maximum amount of fuel the aircraft can contain at landing. Since the aircraft takes off with 18,00018,000 liters of fuel and consumes 1,7001,700 liters per hour, the fuel remaining after tt hours is 18,0001,700t18,000 - 1,700t. To ensure the remaining fuel is less than or equal to 13,75013,750 liters, we solve 18,0001,700t13,75018,000 - 1,700t \leq 13,750, which simplifies to 4,2501,700t4,250 \leq 1,700t, or t2.5t \geq 2.5 hours. Therefore, the minimum duration of the flight is 2.5 hours.

Adım Adım Çözüm

1
Formulate the weight limit inequality using the linear relationship.
0.8F+74,00085,0000.8F + 74,000 \leq 85,000
The aircraft's weight WW is given by 0.8F+74,0000.8F + 74,000, where 0.80.8 represents the density of the fuel in kg/L and 74,00074,000 represents the weight of the empty aircraft and its cargo. This total weight must not exceed 85,00085,000 kg.
2
Calculate the maximum fuel capacity allowed at landing by solving the inequality.
F13,750F \leq 13,750
Subtracting 74,00074,000 from both sides yields 0.8F11,0000.8F \leq 11,000. Dividing by 0.80.8 gives F13,750F \leq 13,750 liters as the fuel ceiling for landing.
3
Use the fuel consumption rate to find the minimum flight time.
t2.5t \geq 2.5
With an initial fuel volume of 18,00018,000 liters and a burn rate of 1,7001,700 liters/hour, the fuel remaining after tt hours is 18,0001,700t18,000 - 1,700t. Setting this expression to be at most 13,75013,750 liters yields 18,0001,700t13,75018,000 - 1,700t \leq 13,750. Subtracting 18,00018,000 gives 1,700t4,250-1,700t \leq -4,250, and dividing by 1,700-1,700 results in t2.5t \geq 2.5 hours.

Anahtar Kavram

Interpreting linear coefficients in context and setting up linear inequalities with rates to model real-world constraints.
Tahmini Süre:2m 30s
Soru 1491Soru

In the xyxy-plane, the graphs of the linear function 3x+y=63x + y = 6 and the quadratic function y=3x25x2y = 3x^2 - 5x - 2 intersect at two points. What is the sum of the yy-coordinates of these two intersection points?

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Cevap: 10

Cevap

10
The correct answer is 10. By rewriting the linear equation as y=63xy = 6 - 3x and substituting it into the quadratic equation, we get 63x=3x25x26 - 3x = 3x^2 - 5x - 2. Collecting all terms on one side yields the quadratic equation 3x22x8=03x^2 - 2x - 8 = 0. Factoring this equation gives (3x+4)(x2)=0(3x + 4)(x - 2) = 0, which results in x=2x = 2 and x=43x = -\frac{4}{3}. Substituting these xx-values back into the linear equation gives the yy-coordinates: y=63(2)=0y = 6 - 3(2) = 0 and y=63(43)=10y = 6 - 3(-\frac{4}{3}) = 10. The sum of these yy-coordinates is 0+10=100 + 10 = 10.

Adım Adım Çözüm

1
Express yy in terms of xx using the linear equation.
y=63xy = 6 - 3x
Isolating yy makes substitution into the quadratic equation straightforward.
2
Substitute the expression for yy into the quadratic equation and set the equation to zero.
63x=3x25x26 - 3x = 3x^2 - 5x - 2, which simplifies to 3x22x8=03x^2 - 2x - 8 = 0.
This forms a single quadratic equation in terms of xx to find the xx-coordinates of the intersection points.
3
Solve the quadratic equation by factoring.
(3x+4)(x2)=0(3x + 4)(x - 2) = 0, yielding x=2x = 2 and x=43x = -\frac{4}{3}.
Factoring determines the values of xx at the points of intersection.
4
Substitute the xx-values back into the linear equation y=63xy = 6 - 3x to find the corresponding yy-coordinates.
For x=2x = 2: y=63(2)=0y = 6 - 3(2) = 0. For x=43x = -\frac{4}{3}: y=63(43)=10y = 6 - 3(-\frac{4}{3}) = 10.
This identifies the coordinates of the two intersection points as (2,0)(2, 0) and (43,10)(-\frac{4}{3}, 10).
5
Calculate the sum of the yy-coordinates.
0+10=100 + 10 = 10
The question asks for the sum of the yy-coordinates of the two intersection points.

Anahtar Kavram

Solving a system of linear and quadratic equations using substitution.
Tahmini Süre:1m 30s
Soru 1492Soru

A scientist studying a sample of a radioactive isotope determines that its mass decays exponentially. The mass of the isotope, in grams, is modeled by the function M(t)=abtM(t) = a \cdot b^t, where tt is the time, in days, since the study began, and aa and bb are constants. The table below shows the mass of the isotope for selected values of tt.

tt (days)M(t)M(t) (grams)
0128
196
272

What is the value of bb?

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Cevap: 0.75

Cevap

0.75
To find the constant bb in the exponential decay function M(t)=abtM(t) = a \cdot b^t, we can use the given table values. For t=0t = 0, M(0)=ab0=a=128M(0) = a \cdot b^0 = a = 128. For t=1t = 1, M(1)=ab1=ab=96M(1) = a \cdot b^1 = a \cdot b = 96. Substituting a=128a = 128 into the second equation gives 128b=96128b = 96. Dividing both sides by 128128 yields b=96128=0.75b = \frac{96}{128} = 0.75 (or 34\frac{3}{4}). We can verify this with t=2t = 2: M(2)=128(0.75)2=1280.5625=72M(2) = 128 \cdot (0.75)^2 = 128 \cdot 0.5625 = 72, which matches the table.

Adım Adım Çözüm

1
Determine the initial value aa using the data point for t=0t = 0.
a=128a = 128
Substituting t=0t = 0 into M(t)=abtM(t) = a \cdot b^t gives M(0)=ab0=aM(0) = a \cdot b^0 = a. Since the table shows M(0)=128M(0) = 128, aa must equal 128128.
2
Use the data point for t=1t = 1 to write an equation for bb.
128b=96128b = 96
Substituting t=1t = 1 and a=128a = 128 into the function gives M(1)=128b1=128bM(1) = 128 \cdot b^1 = 128b. The table shows M(1)=96M(1) = 96.
3
Solve the equation to find bb.
b=0.75b = 0.75
Dividing both sides of 128b=96128b = 96 by 128128 yields b=96128b = \frac{96}{128}, which simplifies to 0.750.75 (or 34\frac{3}{4}).

Anahtar Kavram

Finding the decay factor (base) of an exponential function from a table of values.
Soru 1493Soru

If 92x+1=27x39^{2x + 1} = 27^{x - 3}, what is the value of xx?

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Cevap: 11-11

Cevap

11-11
To solve 92x+1=27x39^{2x + 1} = 27^{x - 3}, express 9 and 27 with a common base of 3: (32)2x+1=(33)x3(3^2)^{2x + 1} = (3^3)^{x - 3}. Apply the power of a power rule to get 32(2x+1)=33(x3)3^{2(2x + 1)} = 3^{3(x - 3)}, which simplifies to 34x+2=33x93^{4x + 2} = 3^{3x - 9}. Equating the exponents gives 4x+2=3x94x + 2 = 3x - 9. Solving for xx by subtracting 3x3x and 22 from both sides yields x=11x = -11. Therefore, the value of xx is 11-11.

Adım Adım Çözüm

1
Rewrite both sides of the equation with a common base.
(32)2x+1=(33)x3(3^2)^{2x+1} = (3^3)^{x-3}
Since 9 and 27 are both powers of 3 (9=329 = 3^2 and 27=3327 = 3^3), expressing them with the same base allows the application of exponent rules.
2
Apply the power of a power rule (am)n=amn(a^m)^n = a^{mn} to simplify the exponents.
32(2x+1)=33(x3)3^{2(2x+1)} = 3^{3(x-3)}, which simplifies to 34x+2=33x93^{4x+2} = 3^{3x-9}
Multiplying the inner exponent by the outer exponent simplifies the expression on both sides.
3
Set the exponents equal to each other.
4x+2=3x94x + 2 = 3x - 9
Since the bases are equal and positive, the exponential expressions are equal if and only if their exponents are equal.
4
Solve the linear equation for xx.
x=11x = -11
Subtracting 3x3x and 22 from both sides isolates the variable xx.

Anahtar Kavram

Solving exponential equations by converting to a common base and equating exponents.
Soru 1494Soru

A logistics company uses two types of boxes, small and large, to ship items. A shipment of 88 small boxes and 55 large boxes has a total weight of 180180 pounds. A second shipment of 66 small boxes and 1010 large boxes has a total weight of 260260 pounds. What is the weight, in pounds, of one large box?

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Cevap: 20

Cevap

The weight of one large box is 20 pounds.
The correct weight of one large box is 20 pounds. By formulating the system of linear equations representing the total weight of each shipment (8s+5L=1808s + 5L = 180 and 6s+10L=2606s + 10L = 260), we can eliminate LL by multiplying the first equation by 2, resulting in 16s+10L=36016s + 10L = 360. Subtracting the second equation from this gives 10s=10010s = 100, which solves to s=10s = 10. Substituting s=10s = 10 back into 8s+5L=1808s + 5L = 180 yields 80+5L=18080 + 5L = 180, which simplifies to 5L=1005L = 100, meaning L=20L = 20.

Adım Adım Çözüm

1
Set up a system of two linear equations based on the shipments.
Let ss be the weight of a small box and LL be the weight of a large box. The system of equations is:
8s+5L=1806s+10L=260\begin{aligned} 8s + 5L &= 180 \\ 6s + 10L &= 260 \end{aligned}
Translating the verbal statements into mathematical symbols represents the problem systemically.
2
Multiply the first equation by 2 to align the coefficients of LL.
16s+10L=36016s + 10L = 360
This sets up the variable LL to have the same coefficient in both equations, allowing for elimination.
3
Subtract the second equation from the modified first equation to solve for ss.
(16s+10L)(6s+10L)=360260(16s + 10L) - (6s + 10L) = 360 - 260
10s=10010s = 100
s=10s = 10
Subtracting eliminates the variable LL, leaving a single-variable linear equation to solve.
4
Substitute s=10s = 10 back into the first equation to solve for LL.
8(10)+5L=1808(10) + 5L = 180
80+5L=18080 + 5L = 180
5L=1005L = 100
L=20L = 20
Substituting the value of the solved variable determines the value of the remaining variable.

Anahtar Kavram

Solving systems of linear equations in two variables using elimination or substitution.
Soru 1495Soru

While the class of marine organisms known as cephalopods possesses advanced problem-solving skills, ______ evolutionary history remains poorly understood due to a lack of fossilized remains.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: its

Cevap

its
The singular possessive pronoun 'its' correctly refers back to the singular collective noun antecedent 'class' and modifies 'evolutionary history'.

Adım Adım Çözüm

1
Identify the antecedent of the pronoun needed to modify 'evolutionary history'.
The antecedent is the singular noun phrase 'the class', not the plural noun 'cephalopods'.
The singular verb 'possesses' in the dependent clause confirms that 'the class' is the grammatical subject and antecedent.
2
Determine the correct grammatical number and case for the pronoun.
A singular possessive pronoun is required.
The pronoun must be singular to agree with 'class' and possessive to modify 'evolutionary history'.
3
Select the option that is singular, possessive, and spelled correctly without an apostrophe.
'its' is chosen over 'their', 'it's', and 'they're'.
'its' is the singular possessive pronoun, whereas 'it's' is a contraction of 'it is'.

Anahtar Kavram

Pronoun-Antecedent Agreement and Case
Soru 1496Soru

In the xyxy-plane, the graphs of the linear equation y=3x+ky = 3x + k, where kk is a constant, and the quadratic equation y=x22x+7y = x^2 - 2x + 7 intersect at two points. If the distance between the two points of intersection is 130\sqrt{130}, what is the value of kk?

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Cevap: 4

Cevap

4
The correct value of kk is 44. Equating the two equations yields the quadratic equation x25x+(7k)=0x^2 - 5x + (7 - k) = 0. Since the slope of the line is 33, the difference in the y-coordinates of the intersection points is 33 times the difference in the x-coordinates. Applying the distance formula shows that the distance is equal to 10(x2x1)2\sqrt{10(x_2 - x_1)^2}. Setting this equal to the given distance of 130\sqrt{130} yields (x2x1)2=13(x_2 - x_1)^2 = 13. Substituting Vieta's relations (x1+x2=5x_1 + x_2 = 5 and x1x2=7kx_1 x_2 = 7 - k) into the identity (x2x1)2=(x1+x2)24x1x2(x_2 - x_1)^2 = (x_1 + x_2)^2 - 4x_1 x_2 results in 13=254(7k)13 = 25 - 4(7 - k), which simplifies to k=4k = 4.

Adım Adım Çözüm

1
Equate the linear and quadratic equations to set up the intersection condition.
x22x+7=3x+k    x25x+(7k)=0x^2 - 2x + 7 = 3x + k \dots \implies x^2 - 5x + (7 - k) = 0
The x-coordinates of the intersection points are the roots of this quadratic equation.
2
Express the distance between the two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in terms of the difference of their x-coordinates.
d=(x2x1)2+(y2y1)2=(x2x1)2+(3(x2x1))2=10(x2x1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(x_2 - x_1)^2 + (3(x_2 - x_1))^2} = \sqrt{10(x_2 - x_1)^2}
Since both points lie on the line y=3x+ky = 3x + k, the difference in their y-coordinates is y2y1=3(x2x1)y_2 - y_1 = 3(x_2 - x_1).
3
Use the given distance to find the value of (x2x1)2(x_2 - x_1)^2.
10(x2x1)2=130    (x2x1)2=1310(x_2 - x_1)^2 = 130 \implies (x_2 - x_1)^2 = 13
The distance between the intersection points is given as 130\sqrt{130}.
4
Apply Vieta's formulas and the algebraic identity for the squared difference of the roots to solve for kk.
x1+x2=5x_1 + x_2 = 5 and x1x2=7kx_1 x_2 = 7 - k. Substituting these into (x2x1)2=(x1+x2)24x1x2(x_2 - x_1)^2 = (x_1 + x_2)^2 - 4x_1 x_2 gives 13=524(7k)    13=2528+4k    4k=16    k=413 = 5^2 - 4(7 - k) \implies 13 = 25 - 28 + 4k \implies 4k = 16 \implies k = 4.
Vieta's formulas relate the coefficients of the quadratic equation to the sum and product of its roots.

Anahtar Kavram

Solving systems of linear and quadratic equations and finding constants based on geometric constraints.
Soru 1497Soru

If x29x+18=0x^2 - 9x + 18 = 0 and x>4x > 4, what is the value of xx?

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Cevap: 6

Cevap

The value of xx is 6.
Factoring the equation x29x+18=0x^2 - 9x + 18 = 0 gives (x3)(x6)=0(x - 3)(x - 6) = 0, which yields the solutions x=3x = 3 and x=6x = 6. Applying the constraint x>4x > 4, the only valid solution is 6.

Adım Adım Çözüm

1
Factor the quadratic equation x29x+18=0x^2 - 9x + 18 = 0.
(x3)(x6)=0(x - 3)(x - 6) = 0
Finding two numbers that multiply to 18 and add to -9 allows us to write the quadratic expression in its factored form.
2
Solve for the roots of the equation.
x=3x = 3 or x=6x = 6
By the zero product property, setting each factor to zero yields the possible solutions for the equation.
3
Apply the given constraint x>4x > 4.
x=6x = 6
Since the question specifies that xx must be greater than 4, the root x=3x = 3 is discarded, leaving x=6x = 6 as the only valid solution.

Anahtar Kavram

Solving quadratic equations by factoring and applying constraints.
Soru 1498Soru

The quadratic function ff is defined by f(x)=(x5)(x11)f(x) = (x - 5)(x - 11). In the xyxy-plane, the graph of y=f(x)y = f(x) is a parabola with vertex (h,k)(h, k). What is the value of hh?

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Cevap: 8

Cevap

The value of hh is 88.
The given quadratic function is in factored form, f(x)=(x5)(x11)f(x) = (x - 5)(x - 11), which shows that the xx-intercepts of the graph are at x=5x = 5 and x=11x = 11. Because a parabola is symmetric, the xx-coordinate of its vertex, hh, is located exactly halfway between the two xx-intercepts. Calculating the average of the xx-intercepts gives h=5+112=8h = \frac{5 + 11}{2} = 8.

Adım Adım Çözüm

1
Find the xx-intercepts of the parabola.
The xx-intercepts are x=5x = 5 and x=11x = 11.
The xx-intercepts of a quadratic function in the form f(x)=(xr1)(xr2)f(x) = (x - r_1)(x - r_2) occur at x=r1x = r_1 and x=r2x = r_2 because setting f(x)=0f(x) = 0 yields these roots.
2
Calculate the xx-coordinate of the vertex, hh.
h=8h = 8
Since a parabola is symmetric, its vertex lies on the axis of symmetry, which is the vertical line halfway between the xx-intercepts. The average of 55 and 1111 is 5+112=8\frac{5 + 11}{2} = 8.

Anahtar Kavram

Finding the vertex of a parabola from its factored form
Soru 1499Soru

At a local coffee shop, the remaining weight of coffee beans CC, in pounds, after preparing nn cups of espresso is modeled by the equation C=800.04nC = 80 - 0.04n. What is the best interpretation of the number 0.040.04 in this context?

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Cevap: The weight of coffee beans, in pounds, used to prepare each cup of espresso

Cevap

The weight of coffee beans, in pounds, used to prepare each cup of espresso
The correct answer is the option stating that 0.040.04 is the weight of coffee beans, in pounds, used to prepare each cup of espresso. In the linear relationship C=800.04nC = 80 - 0.04n, the slope is 0.04-0.04, which represents the rate of change of the remaining weight of coffee beans with respect to the number of cups of espresso prepared. A rate of 0.04-0.04 pounds per cup means that for every cup prepared, the remaining coffee beans decrease by 0.040.04 pounds, indicating that 0.040.04 pounds of beans are consumed per cup.

Adım Adım Çözüm

1
Analyze the structure of the linear equation C=800.04nC = 80 - 0.04n.
The equation is in the slope-intercept form y=mx+by = mx + b, where the dependent variable is CC (remaining coffee beans in pounds), the independent variable is nn (number of cups of espresso), the constant (y-intercept) is 8080, and the slope (coefficient of nn) is 0.04-0.04.
Identifying the components of the linear equation helps in assigning their real-world contextual meanings.
2
Interpret the meaning of the slope in the context of the variables.
The slope of 0.04-0.04 represents the change in the remaining coffee beans (CC) for every 11-unit increase in the number of cups of espresso (nn). This means the remaining weight decreases by 0.040.04 pounds per cup.
The slope of a linear model shows the constant rate of change of the dependent variable per unit of the independent variable.
3
Relate the rate of decrease to the options.
A decrease of 0.040.04 pounds of remaining beans per cup of espresso means that 0.040.04 pounds of coffee beans are used to prepare each cup of espresso.
Translating the decrease rate into consumption rate matches the physical scenario described.

Anahtar Kavram

Interpreting Linear Relationships in Context
Tahmini Süre:45s
Soru 1500Soru

A wildlife biologist models the population of a certain bird species in a nature reserve using the function P(t)=120(1.05)tP(t) = 120(1.05)^t, where P(t)P(t) represents the number of birds tt years after the study began. What does the number 120120 represent in this model?

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Cevap: The initial number of birds in the reserve when the study began

Cevap

The initial number of birds in the reserve when the study began
In the exponential function model P(t)=abtP(t) = a \cdot b^t, the coefficient aa is the value of the function at t=0t = 0. Evaluating P(0)P(0) yields 120(1.05)0=120120(1.05)^0 = 120, which corresponds to the initial number of birds in the reserve when the study began.

Adım Adım Çözüm

1
Identify the standard form of the exponential growth function
P(t)=abtP(t) = a \cdot b^t, where aa represents the initial value and bb represents the growth factor.
This helps map the given constants to their mathematical meanings.
2
Substitute t=0t = 0 to find the starting population
P(0)=120(1.05)0=1201=120P(0) = 120(1.05)^0 = 120 \cdot 1 = 120.
Finding the value at t=0t = 0 defines the initial state of the model.
3
Interpret the initial value in the context of the problem
The number 120120 represents the number of birds present at the start of the study.
This links the mathematical result to the real-world scenario.

Anahtar Kavram

Interpreting components of an exponential function in context
ÖncekiSayfa 75 / 140Sonraki
Tüm alıştırma soruları — SAT | Examkin