Tüm alıştırma soruları

612 soru

Soru 141Soru

If the expression 3x38x2+kx63x2\frac{3x^3 - 8x^2 + kx - 6}{3x - 2} is equivalent to x22x+3x^2 - 2x + 3 for all x23x \neq \frac{2}{3}, where kk is a constant, what is the value of kk?

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Cevap: 13

Cevap

13
By multiplying both sides of the equation by 3x23x - 2, the rational expression simplifies to a polynomial identity: 3x38x2+kx6=(x22x+3)(3x2)3x^3 - 8x^2 + kx - 6 = (x^2 - 2x + 3)(3x - 2). Expanding the right side yields 3x38x2+13x63x^3 - 8x^2 + 13x - 6. Since the two polynomials are equivalent, their corresponding coefficients must be equal, meaning the coefficient of the linear term, kk, must be equal to 1313.

Adım Adım Çözüm

1
Multiply both sides of the equivalence by the denominator (3x2)(3x - 2)
3x38x2+kx6=(x22x+3)(3x2)3x^3 - 8x^2 + kx - 6 = (x^2 - 2x + 3)(3x - 2)
To clear the fraction and align the polynomial expressions for coefficient comparison.
2
Expand the right side of the equation using the distributive property
3x38x2+13x63x^3 - 8x^2 + 13x - 6
To obtain the expanded form of the polynomial so that we can identify the coefficients of each term.
3
Equate the corresponding coefficients of the linear xx terms on both sides of the equation
k=13k = 13
Since the two expressions are equivalent for all values of xx, their coefficients for each corresponding power of xx must be equal.

Anahtar Kavram

Equivalent Algebraic Expressions
Soru 142Soru

A nutritionist is designing a diet plan using two food types, Food A and Food B. The table below shows the amount of protein and carbohydrates, in grams, per gram of each food type:

Food TypeProtein (g)Carbohydrates (g)
Food A0.120.120.080.08
Food B0.180.180.050.05

The nutritionist wants to combine the two foods to obtain a mixture that has a total mass of 250250 grams and contains exactly 3636 grams of protein. How many grams of carbohydrates will be in this mixture?

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Cevap: 17

Cevap

The total amount of carbohydrates in the mixture is 17 grams.
To find the total amount of carbohydrates in the mixture, we first define xx as the mass in grams of Food A and yy as the mass in grams of Food B. Since the total mass of the mixture is 250250 grams, we write the equation x+y=250x + y = 250. Since the total protein in the mixture must be 3636 grams, and Food A and Food B contain 0.120.12 grams and 0.180.18 grams of protein per gram respectively, we write the equation 0.12x+0.18y=360.12x + 0.18y = 36. Multiplying the first equation by 1212 yields 12x+12y=300012x + 12y = 3000, and multiplying the second equation by 100100 yields 12x+18y=360012x + 18y = 3600. Subtracting the first new equation from the second gives 6y=6006y = 600, which simplifies to y=100y = 100. Substituting this back into the first equation gives x+100=250x + 100 = 250, so x=150x = 150. Using these values, the total amount of carbohydrates is 0.08(150)+0.05(100)=12+5=170.08(150) + 0.05(100) = 12 + 5 = 17 grams.

Adım Adım Çözüm

1
Define variables for the mass of each food type.
Let xx be the mass, in grams, of Food A, and let yy be the mass, in grams, of Food B.
To represent the unknown quantities in the system of equations.
2
Set up the system of linear equations.
x+y=250x + y = 250 (total mass equation) and 0.12x+0.18y=360.12x + 0.18y = 36 (total protein equation).
The mixture has a total mass of 250250 grams and must contain exactly 3636 grams of protein.
3
Solve the system of equations for xx and yy.
Multiply the first equation by 1212 to get 12x+12y=300012x + 12y = 3000. Multiply the second equation by 100100 to get 12x+18y=360012x + 18y = 3600. Subtract the first modified equation from the second to get 6y=6006y = 600, which gives y=100y = 100. Substitute y=100y = 100 back into x+y=250x + y = 250 to get x=150x = 150.
To find the specific masses of Food A and Food B required for the mixture.
4
Calculate the total mass of carbohydrates in the mixture.
Total carbohydrates =0.08x+0.05y=0.08(150)+0.05(100)=12+5=17= 0.08x + 0.05y = 0.08(150) + 0.05(100) = 12 + 5 = 17 grams.
The question asks for the total grams of carbohydrates in the final mixture.

Anahtar Kavram

Systems of Linear Equations
Soru 143Soru

An empty water tank is being filled by two hoses. Hose A fills the tank at a constant rate of 12 gallons per minute. Hose B fills the tank at a constant rate of 15 gallons per minute. Hose A is turned on first, and 5 minutes later, Hose B is also turned on. If both hoses run until the tank contains a total of 330 gallons of water, for how many minutes was Hose A running?

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Cevap: 15

Cevap

15
Let mm be the number of minutes Hose A was running. Since Hose B was turned on 5 minutes after Hose A, Hose B was running for m5m - 5 minutes. The volume of water contributed by Hose A is 12m12m gallons, and the volume of water contributed by Hose B is 15(m5)15(m - 5) gallons. The sum of these volumes is 330 gallons, which gives the equation 12m+15(m5)=33012m + 15(m - 5) = 330. Distributing 15 gives 12m+15m75=33012m + 15m - 75 = 330. Combining like terms yields 27m75=33027m - 75 = 330. Adding 75 to both sides gives 27m=40527m = 405. Dividing both sides by 27 yields m=15m = 15. Thus, Hose A was running for 15 minutes.

Adım Adım Çözüm

1
Define variables for the running time of each hose.
Let Hose A run for mm minutes. Then Hose B runs for m5m - 5 minutes.
Hose B started 5 minutes after Hose A, so it ran for 5 fewer minutes.
2
Set up a linear equation for the total gallons of water.
12m+15(m5)=33012m + 15(m - 5) = 330
The sum of the water from both hoses must equal 330 gallons.
3
Simplify and solve the linear equation.
27m=40527m = 405, which gives m=15m = 15.
Distribute, combine like terms, and isolate the variable mm.

Anahtar Kavram

Setting up and solving a multi-step linear equation in one variable from a real-world context.
Soru 144Soru

A public library is purchasing new books for its collection. The library plans to buy paperback books for 6eachandhardcoverbooksfor6 each and hardcover books for 20 each. The library has a budget of at most $1,200 for this purchase, wants to buy at most 120 total books, and must purchase at least 45 hardcover books. What is the maximum number of paperback books the library can purchase?

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Cevap: 50

Cevap

The maximum number of paperback books the library can purchase is 50.
The correct maximum number of paperback books is 50. By expressing the budget constraint as p200103hp \le 200 - \frac{10}{3}h, we see that the number of paperback books is maximized when the number of hardcover books, hh, is minimized. Since the library must buy at least 45 hardcover books, we substitute h=45h = 45 into the inequality to get p50p \le 50. This combination also satisfies the total book constraint because 50+45=9550 + 45 = 95, which is less than or equal to 120.

Adım Adım Çözüm

1
Set up the system of inequalities representing the library's constraints.
Let pp be the number of paperbacks and hh be the number of hardcovers. The constraints are 6p+20h12006p + 20h \le 1200, p+h120p + h \le 120, and h45h \ge 45.
This translates the word problem into mathematical inequalities.
2
Isolate the variable pp in the budget inequality to express it in terms of hh.
p200103hp \le 200 - \frac{10}{3}h
This shows how the number of paperbacks depends on the number of hardcovers purchased.
3
Maximize pp by using the minimum possible value of hh.
p200103(45)=50p \le 200 - \frac{10}{3}(45) = 50
To maximize pp, we must minimize hh because buying more hardcovers decreases the remaining budget for paperbacks. The minimum value for hh is 45.
4
Verify if the solution satisfies the remaining total books constraint.
50+45=9512050 + 45 = 95 \le 120, which is true.
This ensures the solution is feasible and does not violate any other constraints.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 145Soru

For a constant kk, the graph of the linear equation kx4y=15kx - 4y = 15 in the xyxy-plane contains the point (3,3)(3, 3). What is the slope of the line?

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Cevap: 2.25

Cevap

2.25
Substituting the coordinates of the point (3,3)(3, 3) into the given equation yields k(3)4(3)=15k(3) - 4(3) = 15, which simplifies to 3k12=153k - 12 = 15. Adding 1212 to both sides gives 3k=273k = 27, and dividing by 33 gives k=9k = 9. Substituting k=9k = 9 back into the original equation gives 9x4y=159x - 4y = 15. To find the slope of the line, the equation can be written in slope-intercept form, y=mx+by = mx + b, by isolating yy. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing all terms by 4-4 yields y=94x154y = \frac{9}{4}x - \frac{15}{4}, or y=2.25x3.75y = 2.25x - 3.75. Therefore, the slope of the line is 94\frac{9}{4}, or 2.252.25.

Adım Adım Çözüm

1
Substitute the point (3,3)(3, 3) into the equation kx4y=15kx - 4y = 15
3k12=153k - 12 = 15
Since the graph of the equation contains the point (3,3)(3, 3), substituting x=3x = 3 and y=3y = 3 must satisfy the equation.
2
Solve for the constant kk
k=9k = 9
Adding 1212 to both sides of the equation gives 3k=273k = 27. Dividing both sides by 33 yields k=9k = 9.
3
Substitute k=9k = 9 into the equation and rewrite it in slope-intercept form (y=mx+by = mx + b)
y=94x154y = \frac{9}{4}x - \frac{15}{4}
Substituting k=9k = 9 gives 9x4y=159x - 4y = 15. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing both sides by 4-4 isolates yy.
4
Identify the slope from the slope-intercept form
Slope = 2.252.25 (or 94\frac{9}{4})
In the slope-intercept form y=mx+by = mx + b, the coefficient mm represents the slope of the line.

Anahtar Kavram

Determining the slope of a line from a linear equation by first finding an unknown constant using a given point on the line.
Soru 146Soru

A beverage company produces a fruit juice blend using apple juice and cranberry juice. Let xx represent the volume, in liters, of apple juice, and let yy represent the volume, in liters, of cranberry juice used in one batch of the blend. The production constraints for each batch are modeled by the system of inequalities below:

x+y100x + y \geq 100
y13xy \geq \frac{1}{3}x
y12x+75y \leq -\frac{1}{2}x + 75

What is the maximum possible volume, in liters, of cranberry juice that can be used in a single batch?

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Cevap: 50

Cevap

50
To find the maximum possible value of yy, we examine the bounds of the feasible region. Rewriting the inequalities in terms of xx gives x100yx \geq 100 - y and x1502yx \leq 150 - 2y. Since xx must satisfy both inequalities simultaneously, the lower bound must be less than or equal to the upper bound, meaning 100y1502y100 - y \leq 150 - 2y. Solving this inequality for yy gives y50y \leq 50. The point (50,50)(50, 50) also satisfies the remaining constraint y13xy \geq \frac{1}{3}x, confirming that 50 is the maximum possible value.

Adım Adım Çözüm

1
Isolate xx in the first inequality: x+y100x + y \geq 100 becomes x100yx \geq 100 - y.
x100yx \geq 100 - y
This establishes a lower bound for the volume of apple juice in terms of the volume of cranberry juice.
2
Isolate xx in the third inequality: y12x+75y \leq -\frac{1}{2}x + 75 can be rewritten by subtracting 75 from both sides to get y7512xy - 75 \leq -\frac{1}{2}x, then multiplying by 2-2 and reversing the inequality sign to get x1502yx \leq 150 - 2y.
x1502yx \leq 150 - 2y
This establishes an upper bound for the volume of apple juice in terms of the volume of cranberry juice.
3
Combine the lower and upper bounds of xx: 100yx1502y100 - y \leq x \leq 150 - 2y. For a valid solution to exist, the lower bound must be less than or equal to the upper bound.
100y1502y100 - y \leq 150 - 2y
This allows us to solve directly for the constraint on the cranberry juice volume yy.
4
Solve the inequality 100y1502y100 - y \leq 150 - 2y by adding 2y2y to both sides and subtracting 100 from both sides.
y50y \leq 50
This determines that the maximum possible value for yy is 50.
5
Substitute y=50y = 50 back into the compound inequality to find xx: 10050x1502(50)    50x50100 - 50 \leq x \leq 150 - 2(50) \implies 50 \leq x \leq 50, which means x=50x = 50. Check if the point (50,50)(50, 50) satisfies the remaining inequality y13xy \geq \frac{1}{3}x: 5013(50)16.6750 \geq \frac{1}{3}(50) \approx 16.67, which is true.
The point (50,50)(50, 50) is a valid solution to the system.
This confirms that 50 is a achievable value within the system of inequalities.

Anahtar Kavram

Finding the boundary limits and optimization points within a system of linear inequalities in two variables.
Soru 147Soru

A hot air balloon is at an altitude of hh meters. The balloon begins to descend at a constant rate. After 33 minutes, the altitude of the balloon is 540540 meters. After 88 minutes, the altitude of the balloon is 390390 meters. If the altitude of the balloon is modeled by a linear function of time, what was the initial altitude of the balloon, in meters?

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Cevap: 630

Cevap

The initial altitude of the balloon was 630 meters.
To find the initial altitude, we model the balloon's descent as a linear equation of the form h(t)=mt+bh(t) = mt + b, where h(t)h(t) is the altitude at time tt, mm is the constant rate of change, and bb is the initial altitude. Using the given points (3,540)(3, 540) and (8,390)(8, 390), we find the slope m=39054083=30m = \frac{390 - 540}{8 - 3} = -30 meters per minute. Substituting m=30m = -30 and the point (3,540)(3, 540) into h(t)=mt+bh(t) = mt + b gives 540=30(3)+b540 = -30(3) + b. Solving for bb yields b=540+90=630b = 540 + 90 = 630 meters.

Adım Adım Çözüm

1
Identify two data points from the problem context
The coordinate points are (3,540)(3, 540) and (8,390)(8, 390)
To define the linear relationship, we need at least two coordinate points representing (time, altitude)
2
Calculate the slope (mm) of the linear function
m=39054083=1505=30m = \frac{390 - 540}{8 - 3} = \frac{-150}{5} = -30
The rate of change represents the speed at which the balloon descends each minute
3
Solve for the vertical intercept (bb) using the slope-intercept form y=mx+by = mx + b
540=30(3)+b    b=630540 = -30(3) + b \implies b = 630
The initial altitude corresponds to the altitude at time t=0t = 0, which is the vertical intercept of the linear function

Anahtar Kavram

Linear Functions and Graphs
Soru 148Soru

If the expression 6x3+7x214x+192x+5\frac{6x^3 + 7x^2 - 14x + 19}{2x + 5} is equivalent to ax2+bx+c+k2x+5ax^2 + bx + c + \frac{k}{2x + 5} for all x2.5x \neq -2.5, where aa, bb, cc, and kk are constants, what is the value of ab+c+ka - b + c + k?

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Cevap: 14

Cevap

14
Dividing the numerator 6x3+7x214x+196x^3 + 7x^2 - 14x + 19 by the denominator 2x+52x + 5 using polynomial division yields a quotient of 3x24x+33x^2 - 4x + 3 and a remainder of 44. The equivalent expression is 3x24x+3+42x+53x^2 - 4x + 3 + \frac{4}{2x + 5}. Comparing this with the form ax2+bx+c+k2x+5ax^2 + bx + c + \frac{k}{2x + 5} gives the values a=3a = 3, b=4b = -4, c=3c = 3, and k=4k = 4. Substituting these values into ab+c+ka - b + c + k gives 3(4)+3+4=143 - (-4) + 3 + 4 = 14.

Adım Adım Çözüm

1
Perform the first step of polynomial long division by dividing 6x36x^3 by 2x2x.
Quotient term: 3x23x^2; Remainder: 8x214x+19-8x^2 - 14x + 19
To eliminate the highest-degree term of the numerator.
2
Perform the second step of division by dividing 8x2-8x^2 by 2x2x.
Quotient term: 4x-4x; Remainder: 6x+196x + 19
To find the next term of the quotient.
3
Perform the third step of division by dividing 6x6x by 2x2x.
Quotient term: 33; Remainder: 44
To find the constant term of the quotient and the final remainder.
4
Compare the resulting expression 3x24x+3+42x+53x^2 - 4x + 3 + \frac{4}{2x + 5} with the given form to identify the constants aa, bb, cc, and kk.
a=3a = 3, b=4b = -4, c=3c = 3, k=4k = 4
To map the coefficients of equivalent algebraic expressions.
5
Evaluate the expression ab+c+ka - b + c + k using the identified values.
3(4)+3+4=143 - (-4) + 3 + 4 = 14
To obtain the final numeric value requested.

Anahtar Kavram

Equivalent Algebraic Expressions via Polynomial Long Division
Soru 149Soru

Oven A preheats at a constant rate of 1515 degrees Celsius per minute, starting from an initial temperature of 2525 degrees Celsius. Oven B starts preheating 55 minutes after Oven A begins, starting from an initial temperature of 2020 degrees Celsius and preheating at a constant rate of 2020 degrees Celsius per minute. If both ovens continue to preheat, how many minutes after Oven A begins preheating will both ovens reach the same temperature?

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Cevap: 21

Cevap

The ovens will reach the same temperature 2121 minutes after Oven A begins preheating.
To find the number of minutes after Oven A begins preheating when both ovens reach the same temperature, we can write an equation in terms of tt, the time in minutes since Oven A started. Oven A starts at 2525 degrees Celsius and increases by 1515 degrees per minute, so its temperature is 25+15t25 + 15t. Oven B starts 55 minutes later, meaning it preheats for t5t - 5 minutes. Starting from 2020 degrees Celsius and preheating at 2020 degrees per minute, Oven B's temperature is 20+20(t5)20 + 20(t - 5). Setting these two expressions equal gives the equation 25+15t=20+20(t5)25 + 15t = 20 + 20(t - 5). Distributing 2020 yields 25+15t=20t8025 + 15t = 20t - 80. Isolating tt gives 5t=1055t = 105, which results in t=21t = 21.

Adım Adım Çözüm

1
Set up expressions representing the temperature of each oven tt minutes after Oven A begins preheating.
Oven A: 25+15t25 + 15t; Oven B: 20+20(t5)20 + 20(t - 5)
Since Oven B starts 55 minutes after Oven A, it has been preheating for t5t - 5 minutes.
2
Set the temperature expressions equal to find the time at which they reach the same temperature.
25+15t=20+20(t5)25 + 15t = 20 + 20(t - 5)
We want to find the value of tt where the temperatures of the two ovens are equal.
3
Distribute and simplify the equation.
25+15t=20t8025 + 15t = 20t - 80
Distributing the 2020 across (t5)(t - 5) yields 20t10020t - 100. Combining the constant terms gives 20100=8020 - 100 = -80.
4
Solve for tt by isolating the variable term.
5t=1055t = 105, which gives t=21t = 21
Subtract 15t15t and add 8080 to both sides, then divide by 55.

Anahtar Kavram

Solving linear equations in one variable that model real-world situations with a time delay.
Soru 150Soru
For each real number kk except 22, the system of equations below has a unique solution (x,y)(x, y).
kx+(k+2)y=3k+1(k1)x+ky=2k1\begin{aligned} kx + (k + 2)y &= 3k + 1 \\ (k - 1)x + ky &= 2k - 1 \end{aligned}
If the solution (x,y)(x, y) to the system also satisfies the equation x+2y=6x + 2y = 6, what is the value of kk?
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Cevap: 4

Cevap

The value of kk is 4.
Subtracting the second equation from the first equation yields x+2y=k+2x + 2y = k + 2. Since the solution must also satisfy x+2y=6x + 2y = 6, we set k+2=6k + 2 = 6, which gives k=4k = 4.

Adım Adım Çözüm

1
Subtract the second equation from the first equation.
x+2y=k+2x + 2y = k + 2
To find a direct linear combination of xx and yy that can be compared directly to the target equation.
2
Equate the resulting expression to the target equation x+2y=6x + 2y = 6.
k+2=6k + 2 = 6
Since the solution (x,y)(x, y) must satisfy x+2y=6x + 2y = 6, the value of the linear combination x+2yx + 2y from the system must equal 66.
3
Solve for kk by subtracting 2 from both sides.
k=4k = 4
Isolating the variable kk yields the final solution.

Anahtar Kavram

Solving systems of linear equations with parameter coefficients by identifying algebraic structure and linear combinations.

Alternatif Yöntem

Solve the system for xx and yy in terms of kk using elimination. Multiplying the first equation by (k1)(k-1) and the second by kk, and then subtracting them yields y=k2k1k2y = \frac{k^2 - k - 1}{k - 2}. Substituting this back gives x=k2+2k2k2x = \frac{-k^2 + 2k - 2}{k - 2}. Substituting these expressions into the equation x+2y=6x + 2y = 6 results in k24k2=6\frac{k^2 - 4}{k - 2} = 6. For k2k \neq 2, factoring k24k^2 - 4 as (k2)(k+2)(k-2)(k+2) allows simplification to k+2=6k + 2 = 6, which yields k=4k = 4.
Tahmini Süre:2m 0s
Soru 151Soru

A solution to a system of inequalities in the xyxy-plane is represented by the point (2,y)(2, y). If the system is defined by:

y4x2y \geq 4x - 2
y2x+10y \leq -2x + 10

what is the value of yy?

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Cevap: 6

Cevap

The value of yy must be exactly 6 because it is bounded both below and above by 6.
Substituting x=2x = 2 into the system of inequalities yields two constraints: y4(2)2y \geq 4(2) - 2, which simplifies to y6y \geq 6, and y2(2)+10y \leq -2(2) + 10, which simplifies to y6y \leq 6. The only value of yy that satisfies both statements is 6.

Adım Adım Çözüm

1
Substitute x=2x = 2 into the first inequality y4x2y \geq 4x - 2
y6y \geq 6
To determine the constraint on the yy-value from the first inequality at the coordinate x=2x = 2.
2
Substitute x=2x = 2 into the second inequality y2x+10y \leq -2x + 10
y6y \leq 6
To determine the constraint on the yy-value from the second inequality at the coordinate x=2x = 2.
3
Find the value of yy that satisfies both y6y \geq 6 and y6y \leq 6
y=6y = 6
For a value to be simultaneously greater than or equal to 6 and less than or equal to 6, it must be equal to 6.

Anahtar Kavram

Evaluating a system of linear inequalities at a specific coordinate to determine a unique boundary value
Tahmini Süre:45s
Soru 152Soru

If (x,y)(x, y) is a solution to the system of equations below and x>0x > 0, what is the value of xx?

y=x2y = x^2
y=x+6y = x + 6
Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The correct answer is 33.
Substituting y=x2y = x^2 into y=x+6y = x + 6 gives the quadratic equation x2x6=0x^2 - x - 6 = 0. Factoring this expression yields (x3)(x+2)=0(x - 3)(x + 2) = 0, which gives solutions of x=3x = 3 and x=2x = -2. Since the system requires x>0x > 0, the only valid solution is 33.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
x2=x+6x^2 = x + 6
To eliminate the variable yy and solve for xx directly.
2
Subtract xx and 66 from both sides to write the quadratic equation in standard form.
x2x6=0x^2 - x - 6 = 0
Setting the quadratic expression equal to zero allows it to be factored.
3
Factor the quadratic trinomial.
(x3)(x+2)=0(x - 3)(x + 2) = 0
Finding factors whose product is 6-6 and whose sum is 1-1 helps find the roots.
4
Solve for xx and apply the constraint x>0x > 0.
x=3x = 3
The equation has solutions x=3x = 3 and x=2x = -2. Because xx must be greater than 00, we discard the negative solution.

Anahtar Kavram

Solving a system of nonlinear equations by substitution and factoring the resulting quadratic equation.
Soru 153Soru

If the expression 5(2x3)4(x2)5(2x - 3) - 4(x - 2) is equivalent to ax+bax + b for all values of xx, where aa and bb are constants, what is the value of aa?

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Cevap: 6

Cevap

The value of the constant coefficient is 6.
Expanding the expression 5(2x3)4(x2)5(2x - 3) - 4(x - 2) yields 10x154x+810x - 15 - 4x + 8. Combining the like terms results in (10x4x)+(15+8)=6x7(10x - 4x) + (-15 + 8) = 6x - 7. Comparing this to the expression ax+bax + b, the constant coefficient aa is equal to 6.

Adım Adım Çözüm

1
Distribute the multipliers to the terms inside the parentheses.
10x154x+810x - 15 - 4x + 8
To remove the parentheses and prepare the expression for simplification, multiply each term inside (2x3)(2x - 3) by 55 and each term inside (x2)(x - 2) by 4-4.
2
Combine the linear terms and the constant terms.
6x76x - 7
Combine the variable terms (10x4x=6x10x - 4x = 6x) and the constants (15+8=7-15 + 8 = -7) to rewrite the expression in its simplest form.
3
Compare the simplified expression to the form ax+bax + b to identify the value of aa.
a=6a = 6
The coefficient of the variable xx in 6x76x - 7 corresponds directly to aa in ax+bax + b.

Anahtar Kavram

Equivalent Algebraic Expressions
Soru 154Soru

A student works two part-time jobs: tutoring, which pays 2020 dollars per hour, and working at a bookstore, which pays 1212 dollars per hour. The student can work at most 1515 hours per week and wants to earn at least 220220 dollars per week. If the student works a whole number of hours at each job, what is the minimum number of hours the student must tutor to meet these requirements?

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Cevap: 5

Cevap

5
The system of inequalities modeling the scenario consists of x+y15x + y \leq 15 (representing the limit on total hours) and 20x+12y22020x + 12y \geq 220 (representing the earning target), where xx is the hours of tutoring and yy is the hours at the bookstore. To find the minimum hours of tutoring, we assume the maximum bookstore hours y=15xy = 15 - x and substitute it into the earnings equation: 20x+12(15x)22020x + 12(15 - x) \geq 220. Simplifying yields 8x+1802208x + 180 \geq 220, which reduces to 8x408x \geq 40, or x5x \geq 5. The minimum integer value that satisfies this condition is 5.

Adım Adım Çözüm

1
Define variables and set up the constraint for total hours worked.
x+y15x + y \leq 15
Let xx be the number of hours tutoring and yy be the number of hours working at the bookstore. The total hours cannot exceed 15.
2
Set up the constraint for the minimum weekly earnings.
20x+12y22020x + 12y \geq 220
Tutoring pays 2020 dollars per hour and the bookstore pays 1212 dollars per hour, and the total earnings must be at least 220220 dollars.
3
Substitute the maximum value of yy in terms of xx into the earnings inequality.
20x+12(15x)22020x + 12(15 - x) \geq 220
To minimize xx, we must maximize yy. From x+y15x + y \leq 15, the maximum value of yy is 15x15 - x.
4
Solve the inequality for xx.
x5x \geq 5
Distribute and simplify: 20x+18012x2208x+1802208x40x520x + 180 - 12x \geq 220 \Rightarrow 8x + 180 \geq 220 \Rightarrow 8x \geq 40 \Rightarrow x \geq 5.

Anahtar Kavram

Solving systems of linear inequalities to find optimal boundary values in context.
Tahmini Süre:1m 30s
Soru 155Soru

For all positive real numbers xx and yy, the expression (x3y2)2/3(x1y4)1/6(x2y)1/2\frac{(x^{3} y^{2})^{2/3} \cdot (x^{-1} y^{4})^{1/6}}{(x^2 y)^{1/2}} can be written in the equivalent form xaybx^a y^b, where aa and bb are constants. What is the value of 6a+2b6a + 2b?

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Cevap: 8

Cevap

The correct answer is 8.
Applying the rules of exponents systematically yields the simplified expression x5/6y3/2x^{5/6} y^{3/2}. By setting a=56a = \frac{5}{6} and b=32b = \frac{3}{2}, the linear combination 6a+2b6a + 2b evaluates to 6(56)+2(32)=5+3=86\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8.

Adım Adım Çözüm

1
Apply the power of a power rule to the first term in the numerator.
(x3y2)2/3=x323y223=x2y4/3(x^3 y^2)^{2/3} = x^{3 \cdot \frac{2}{3}} y^{2 \cdot \frac{2}{3}} = x^2 y^{4/3}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
2
Apply the power of a power rule to the second term in the numerator.
(x1y4)1/6=x116y416=x1/6y2/3(x^{-1} y^4)^{1/6} = x^{-1 \cdot \frac{1}{6}} y^{4 \cdot \frac{1}{6}} = x^{-1/6} y^{2/3}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
3
Multiply the two simplified terms in the numerator.
(x2y4/3)(x1/6y2/3)=x216y43+23=x11/6y2(x^2 y^{4/3})(x^{-1/6} y^{2/3}) = x^{2 - \frac{1}{6}} y^{\frac{4}{3} + \frac{2}{3}} = x^{11/6} y^2
When multiplying expressions with the same base, add their exponents.
4
Simplify the denominator.
(x2y)1/2=x212y112=xy1/2(x^2 y)^{1/2} = x^{2 \cdot \frac{1}{2}} y^{1 \cdot \frac{1}{2}} = x y^{1/2}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
5
Divide the numerator by the denominator.
x11/6y2xy1/2=x1161y212=x5/6y3/2\frac{x^{11/6} y^2}{x y^{1/2}} = x^{\frac{11}{6} - 1} y^{2 - \frac{1}{2}} = x^{5/6} y^{3/2}
When dividing expressions with the same base, subtract the exponent of the denominator from the exponent of the numerator.
6
Identify the values of aa and bb and calculate 6a+2b6a + 2b.
a=56a = \frac{5}{6}, b=32b = \frac{3}{2}, so 6a+2b=6(56)+2(32)=5+3=86a + 2b = 6\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8
Matching the simplified expression x5/6y3/2x^{5/6} y^{3/2} to xaybx^a y^b yields the values of the constants aa and bb, which are then used to calculate the required expression.

Anahtar Kavram

Simplifying rational expressions with fractional exponents using exponent rules.
Soru 156Soru

If the expression (x+5)2(x3)2(x + 5)^2 - (x - 3)^2 is equivalent to ax+bax + b for all values of xx, where aa and bb are constants, what is the value of aa?

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Cevap: 16

Cevap

16
Expanding (x+5)2(x + 5)^2 gives x2+10x+25x^2 + 10x + 25, and expanding (x3)2(x - 3)^2 gives x26x+9x^2 - 6x + 9. Subtracting the second expression from the first requires distributing the negative sign across all terms: x2+10x+25(x26x+9)=x2+10x+25x2+6x9x^2 + 10x + 25 - (x^2 - 6x + 9) = x^2 + 10x + 25 - x^2 + 6x - 9. Combining like terms yields 16x+1616x + 16. Comparing this to ax+bax + b shows that the coefficient of xx, aa, is 16.

Adım Adım Çözüm

1
Expand the first squared binomial term
(x+5)2=x2+10x+25(x + 5)^2 = x^2 + 10x + 25
To express the binomial square as a trinomial using the perfect square identity (u+v)2=u2+2uv+v2(u + v)^2 = u^2 + 2uv + v^2.
2
Expand the second squared binomial term
(x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9
To express the binomial square as a trinomial using the perfect square identity (uv)2=u22uv+v2(u - v)^2 = u^2 - 2uv + v^2.
3
Subtract the expanded expressions and distribute the negative sign
x2+10x+25x2+6x9x^2 + 10x + 25 - x^2 + 6x - 9
To combine the terms while correctly applying the distributive property to the subtracted expression.
4
Combine like terms to simplify the polynomial
16x+1616x + 16
To find the final simplified polynomial of the form ax+bax + b.
5
Compare the simplified expression to the standard form to find the value of aa
a=16a = 16
The constant aa represents the coefficient of the linear term xx, which is 16.

Anahtar Kavram

Simplifying algebraic expressions by expanding binomial products and combining like terms.
Soru 157Soru

A software company offers a Basic subscription for $15\$15 per month and a Premium subscription for $30\$30 per month. In April, the company had a total of 1,2001,200 active subscriptions. In May, the number of Basic subscriptions increased by 20%20\%, and the number of Premium subscriptions increased by 5%5\% compared to April. If the company's total monthly revenue increased by $2,700\$2,700 from April to May, how many Premium subscriptions did the company have in April?

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Cevap: 600

Cevap

600
To find the number of Premium subscriptions in April, we can set up a system of linear equations. Let BB represent the number of Basic subscriptions in April and PP represent the number of Premium subscriptions in April. Since the total number of subscriptions is 1,2001,200, we have B+P=1,200B + P = 1,200. The revenue increase from April to May is $2,700\$2,700. The increase in Basic subscriptions is 20%20\%, which contributes 15×0.20B=3B15 \times 0.20B = 3B dollars to the revenue increase. The increase in Premium subscriptions is 5%5\%, which contributes 30×0.05P=1.5P30 \times 0.05P = 1.5P dollars to the revenue increase. Thus, 3B+1.5P=2,7003B + 1.5P = 2,700. Substituting B=1,200PB = 1,200 - P into this equation yields 3(1,200P)+1.5P=2,7003(1,200 - P) + 1.5P = 2,700. Solving for PP gives 3,6001.5P=2,7003,600 - 1.5P = 2,700, which simplifies to 1.5P=9001.5P = 900, or P=600P = 600.

Adım Adım Çözüm

1
Define variables and write the first equation based on the total number of subscriptions in April.
B+P=1,200B + P = 1,200, where BB is the number of Basic subscriptions and PP is the number of Premium subscriptions.
To represent the relationship between the two types of subscriptions in April.
2
Write the second equation representing the change in monthly revenue from April to May.
3B+1.5P=2,7003B + 1.5P = 2,700
The change in revenue is the sum of the increase in revenue from each subscription type: 15(0.20B)+30(0.05P)=2,70015(0.20B) + 30(0.05P) = 2,700.
3
Solve the system of equations by substituting B=1,200PB = 1,200 - P into the revenue equation.
3(1,200P)+1.5P=2,700    3,6001.5P=2,7003(1,200 - P) + 1.5P = 2,700 \implies 3,600 - 1.5P = 2,700
Substitution eliminates the variable BB, allowing us to solve for PP directly.
4
Isolate the variable PP to find the number of Premium subscriptions in April.
1.5P=900    P=600-1.5P = -900 \implies P = 600
Dividing the revenue difference by the coefficient solves for the value of PP.

Anahtar Kavram

Solving systems of linear equations in real-life contexts involving percentage changes.
Soru 158Soru

A shipping company offers two types of delivery services: standard and express. The total shipping cost, in dollars, for a package sent via standard service is modeled by the function C(w)=1.25w+bsC(w) = 1.25w + b_s, where ww is the weight of the package, in pounds, and bsb_s is a constant representing the flat handling fee. The total shipping cost, in dollars, for a package sent via express service is modeled by the function E(k)=mek+beE(k) = m_e k + b_e, where kk is the weight of the package, in kilograms, and beb_e is a constant representing the flat handling fee.

The rate of change of the express shipping cost with respect to the package's weight, in dollars per kilogram, is 2.42.4 times the rate of change of the standard shipping cost with respect to the package's weight, in dollars per pound. The flat handling fee for the express service is 4.504.50 dollars more than the flat handling fee for the standard service. If it costs 58.5058.50 dollars to ship a package weighing 26.426.4 pounds using the express service, what is the cost, in dollars, to ship a package weighing 2020 pounds using the standard service? (Assume 1 kilogram=2.2 pounds1\text{ kilogram} = 2.2\text{ pounds}.)

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Cevap: 43

Cevap

The cost to ship a package weighing 20 pounds using the standard service is 43 dollars.
The correct answer is obtained by first calculating the rate of change of the express shipping cost (2.4×1.25=3.002.4 \times 1.25 = 3.00 dollars per kilogram). Next, the weight of the package is converted to kilograms (26.4/2.2=1226.4 / 2.2 = 12 kilograms) to match the express cost function's variable. Using the given cost of 58.5058.50 dollars for the express shipment, the express handling fee is determined to be 58.503(12)=22.5058.50 - 3(12) = 22.50 dollars. The standard handling fee is then found by subtracting 4.504.50 dollars from the express fee (22.504.50=18.0022.50 - 4.50 = 18.00 dollars). Finally, the cost of a 2020-pound standard package is computed as 1.25(20)+18.00=43.001.25(20) + 18.00 = 43.00 dollars.

Adım Adım Çözüm

1
Determine the rate of change for the express service (mem_e).
me=3.00m_e = 3.00 dollars per kilogram
The rate of change of the standard shipping cost is 1.251.25 dollars per pound. Since the rate of change for the express shipping cost is 2.42.4 times this rate, me=2.4×1.25=3.00m_e = 2.4 \times 1.25 = 3.00 dollars per kilogram.
2
Convert the weight of the express package from pounds to kilograms.
k=12k = 12 kilograms
The weight of the package is given as 26.426.4 pounds. Using the conversion 1 kilogram=2.2 pounds1\text{ kilogram} = 2.2\text{ pounds}, the weight in kilograms is 26.42.2=12\frac{26.4}{2.2} = 12 kilograms.
3
Find the express flat handling fee (beb_e) using the given cost of the express shipment.
be=22.50b_e = 22.50 dollars
We are given that the cost of shipping a 1212-kilogram package using the express service is 58.5058.50 dollars. Substituting these values into the express cost function: 3(12)+be=58.5036+be=58.50be=22.503(12) + b_e = 58.50 \Rightarrow 36 + b_e = 58.50 \Rightarrow b_e = 22.50 dollars.
4
Find the standard flat handling fee (bsb_s).
bs=18.00b_s = 18.00 dollars
The express handling fee is 4.504.50 dollars more than the standard handling fee: be=bs+4.5022.50=bs+4.50bs=18.00b_e = b_s + 4.50 \Rightarrow 22.50 = b_s + 4.50 \Rightarrow b_s = 18.00 dollars.
5
Calculate the cost to ship a 2020-pound package using the standard service.
43.0043.00 dollars
Using the standard cost function C(w)=1.25w+bsC(w) = 1.25w + b_s with w=20w = 20 and bs=18.00b_s = 18.00: C(20)=1.25(20)+18.00=25.00+18.00=43.00C(20) = 1.25(20) + 18.00 = 25.00 + 18.00 = 43.00 dollars.

Anahtar Kavram

Interpreting slope, y-intercept, and rates of change of linear functions in a real-world context with unit conversions.
Soru 159Soru
Consider the system of equations below.
3(x+y)2(xy)=202(x+y)+3(xy)=22\begin{aligned} 3(x + y) - 2(x - y) &= 20 \\ 2(x + y) + 3(x - y) &= 22 \end{aligned}
If (x,y)(x, y) is the solution to the system of equations, what is the value of xx?
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Cevap: 5

Cevap

The value of xx is 55.
Expanding and simplifying the given system yields x+5y=20x + 5y = 20 and 5xy=225x - y = 22. Multiplying the second equation by 5 results in 25x5y=11025x - 5y = 110. Adding this to the first equation eliminates yy, leaving 26x=13026x = 130. Dividing both sides by 26 gives x=5x = 5.

Adım Adım Çözüm

1
Expand the algebraic expressions in both equations to rewrite the system in standard form.
x+5y=20x + 5y = 20 and 5xy=225x - y = 22
Expanding the first equation gives 3x+3y2x+2y=203x + 3y - 2x + 2y = 20, which simplifies to x+5y=20x + 5y = 20. Expanding the second equation gives 2x+2y+3x3y=222x + 2y + 3x - 3y = 22, which simplifies to 5xy=225x - y = 22.
2
Multiply the second equation by 5 to align the coefficients of the y-terms.
25x5y=11025x - 5y = 110
Multiplying 5xy=225x - y = 22 by 5 allows the subtraction of yy to cancel with the addition of 5y5y in the first equation.
3
Add the first equation to the modified second equation to eliminate the y-variable and solve for x.
26x=13026x = 130, which simplifies to x=5x = 5.
Adding (x+5y)+(25x5y)=20+110(x + 5y) + (25x - 5y) = 20 + 110 yields 26x=13026x = 130. Dividing by 26 gives the final value of xx.

Anahtar Kavram

Solving systems of linear equations using expansion and elimination.

Alternatif Yöntem

Define substitution variables u=x+yu = x + y and v=xyv = x - y. The system simplifies to 3u2v=203u - 2v = 20 and 2u+3v=222u + 3v = 22. Multiplying the first equation by 3 and the second by 2 gives 9u6v=609u - 6v = 60 and 4u+6v=444u + 6v = 44. Adding these equations yields 13u=104    u=813u = 104 \implies u = 8. Substituting u=8u = 8 back in gives 16+3v=22    3v=6    v=216 + 3v = 22 \implies 3v = 6 \implies v = 2. Now, solve the system x+y=8x + y = 8 and xy=2x - y = 2. Adding these two equations gives 2x=10    x=52x = 10 \implies x = 5.
Tahmini Süre:1m 30s
Soru 160Soru

A worker at a distribution center packages boxes at a constant rate. The total number of boxes, BB, the worker has packaged hh hours after starting their shift can be modeled by the equation B=12h+15B = 12h + 15. According to the model, how many boxes were already packaged at the start of the worker's shift?

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Cevap: 15

Cevap

At the start of the worker's shift, 1515 boxes were already packaged.
In the linear model B=12h+15B = 12h + 15, the term 1515 is the constant term (y-intercept), which represents the value of BB when h=0h = 0. In this context, h=0h = 0 represents the start of the worker's shift. Therefore, 1515 boxes were already packaged at the start of the shift.

Adım Adım Çözüm

1
Identify the value of hh that represents the start of the shift.
h=0h = 0
The variable hh represents the number of hours since the shift started, so the start of the shift corresponds to 00 hours.
2
Substitute h=0h = 0 into the given equation to find the value of BB.
B=15B = 15
Evaluating the equation at h=0h = 0 gives the initial number of packaged boxes, which is represented by the constant term of the linear equation.

Anahtar Kavram

Interpreting the y-intercept of a linear relationship in context
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