Linear Equations in Two Variables

60 soru

Soru 41Soru

A community art studio offers clay sculpting classes. The studio charges a one-time registration fee plus a fee for each pound of clay used. A student who uses 1212 pounds of clay is charged a total of $106\$106. A student who uses 2525 pounds of clay is charged a total of $197\$197. If the relationship between the total charge, CC, in dollars, and the amount of clay used, pp, in pounds, is linear, which of the following equations models this relationship?

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Cevap: C=7p+22C = 7p + 22

Cevap

C=7p+22C = 7p + 22
The correct equation is C=7p+22C = 7p + 22. To find this, we first determine the rate of change, which is the cost per pound of clay. This is calculated as the change in total cost divided by the change in the amount of clay used: 1971062512=9113=7\frac{197 - 106}{25 - 12} = \frac{91}{13} = 7 dollars per pound. Next, we use the linear equation form C=mp+bC = mp + b, where mm is the slope (77) and bb is the y-intercept (the registration fee). Substituting C=106C = 106 and p=12p = 12 gives 106=7(12)+b106 = 7(12) + b, which simplifies to 106=84+b106 = 84 + b. Solving for bb yields b=22b = 22. Therefore, the linear relationship is represented by C=7p+22C = 7p + 22.

Adım Adım Çözüm

1
Calculate the slope (mm), which represents the price per pound of clay, using the coordinate points (12,106)(12, 106) and (25,197)(25, 197).
m=1971062512=9113=7m = \frac{197 - 106}{25 - 12} = \frac{91}{13} = 7
The slope of a linear equation represents the constant rate of change between the independent variable (pounds of clay) and the dependent variable (total cost).
2
Substitute the slope m=7m = 7 and one of the points, such as (12,106)(12, 106), into the slope-intercept form C=mp+bC = mp + b to solve for the y-intercept bb.
106=7(12)+b    106=84+b    b=22106 = 7(12) + b \implies 106 = 84 + b \implies b = 22
The y-intercept represents the flat registration fee, which is the cost when 00 pounds of clay are used.
3
Write the final equation by substituting the calculated slope and y-intercept back into the slope-intercept form.
C=7p+22C = 7p + 22
Combining the constant rate of change and the initial value yields the linear model.

Anahtar Kavram

Linear Equations in Two Variables
Soru 42Soru

In the xyxy-plane, the line with equation ax+4y=36ax + 4y = 36, where aa is a constant, has a yy-intercept of (0,p)(0, p) and an xx-intercept of (q,0)(q, 0), where pp and qq are positive integers. If p+q=15p + q = 15, what is the value of aa?

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Cevap: 6

Cevap

6
To find the value of aa, we first determine the yy-intercept of the line by setting x=0x = 0 in the equation ax+4y=36ax + 4y = 36. This gives 4y=364y = 36, so y=9y = 9. Thus, the yy-intercept is (0,9)(0, 9), which means p=9p = 9. Using the given relationship p+q=15p + q = 15, we substitute p=9p = 9 to find q=6q = 6. The xx-intercept is therefore (6,0)(6, 0). Substituting these coordinates back into the line's equation gives a(6)+4(0)=36a(6) + 4(0) = 36, which simplifies to 6a=366a = 36. Solving for aa yields a=6a = 6.

Adım Adım Çözüm

1
Set x=0x = 0 in the equation ax+4y=36ax + 4y = 36 to find the yy-intercept.
4y=36    y=94y = 36 \implies y = 9, so p=9p = 9.
The yy-intercept of a graph is the point where x=0x = 0.
2
Substitute p=9p = 9 into the equation p+q=15p + q = 15 to solve for qq.
9+q=15    q=69 + q = 15 \implies q = 6.
We are given that the sum of the yy-coordinate of the yy-intercept and the xx-coordinate of the xx-intercept is 1515.
3
Substitute the xx-intercept (6,0)(6, 0) into the equation ax+4y=36ax + 4y = 36 to solve for aa.
a(6)+4(0)=36    6a=36    a=6a(6) + 4(0) = 36 \implies 6a = 36 \implies a = 6.
Since the xx-intercept is (q,0)(q, 0) and q=6q = 6, the point (6,0)(6, 0) must satisfy the equation of the line.

Anahtar Kavram

Finding and using intercepts of a linear equation in two variables.
Soru 43Soru

An online retail store charges a flat shipping fee plus a separate fee per package for bulk deliveries. The total shipping cost, CC, in dollars, for an order containing xx standard packages and yy deluxe packages can be modeled by the equation C=15x+10y+25C = 15x + 10y + 25. If the total shipping cost for a certain order is 195195 dollars and the order contains 8 deluxe packages, how many standard packages are in the order?

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Cevap: 6

Cevap

6
The correct answer is 6. Substituting the total cost of 195195 for CC and the 8 deluxe packages for yy into the equation C=15x+10y+25C = 15x + 10y + 25 yields 195=15x+10(8)+25195 = 15x + 10(8) + 25. Simplifying the equation gives 195=15x+105195 = 15x + 105. Subtracting 105 from both sides results in 90=15x90 = 15x. Dividing both sides by 15 gives x=6x = 6.

Adım Adım Çözüm

1
Substitute the given values into the linear equation.
Substituting C=195C = 195 and y=8y = 8 into the equation C=15x+10y+25C = 15x + 10y + 25 yields 195=15x+10(8)+25195 = 15x + 10(8) + 25.
This sets up the equation with only one variable, xx, which we need to solve for.
2
Simplify the constants on the right side of the equation.
195=15x+80+25195 = 15x + 80 + 25, which simplifies to 195=15x+105195 = 15x + 105.
Combining like terms simplifies the algebraic expression.
3
Isolate the variable term 15x15x.
Subtracting 105 from both sides of the equation gives 15x=19510515x = 195 - 105, which simplifies to 15x=9015x = 90.
To solve for xx, we must isolate the term containing the variable on one side.
4
Solve for the variable xx.
x=9015=6x = \frac{90}{15} = 6.
Dividing by the coefficient of xx isolates the variable completely.

Anahtar Kavram

Solving linear equations in two variables by substituting known values and isolating the variable.
Soru 44Soru

In the xyxy-plane, a line passes through the point (5,1)(5, -1) and has a slope of 25\frac{2}{5}. If the line also passes through the point (15,p)(15, p), what is the value of pp?

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Cevap: 3

Cevap

The value of pp is 33.
To find the value of pp, the equation of the line can be established using the point-slope form: yy1=m(xx1)y - y_1 = m(x - x_1). Substituting the given slope m=25m = \frac{2}{5} and the point (5,1)(5, -1) gives y(1)=25(x5)y - (-1) = \frac{2}{5}(x - 5). Simplifying this yields y+1=25x2y + 1 = \frac{2}{5}x - 2, which reduces to y=25x3y = \frac{2}{5}x - 3. Substituting the point (15,p)(15, p) into this equation gives p=25(15)3=63=3p = \frac{2}{5}(15) - 3 = 6 - 3 = 3.

Adım Adım Çözüm

1
Determine the equation of the line using point-slope form.
y=25x3y = \frac{2}{5}x - 3
The equation of a line with slope mm passing through a point (x1,y1)(x_1, y_1) is yy1=m(xx1)y - y_1 = m(x - x_1). Substituting m=25m = \frac{2}{5} and the point (5,1)(5, -1) gives y(1)=25(x5)y - (-1) = \frac{2}{5}(x - 5). Simplifying this equation results in y+1=25x2y + 1 = \frac{2}{5}x - 2, which becomes y=25x3y = \frac{2}{5}x - 3.
2
Substitute the point (15,p)(15, p) into the linear equation.
p=3p = 3
Since the line passes through the point (15,p)(15, p), the coordinates must satisfy the equation of the line. Substituting x=15x = 15 and y=py = p into y=25x3y = \frac{2}{5}x - 3 gives p=25(15)3p = \frac{2}{5}(15) - 3, which simplifies to p=63=3p = 6 - 3 = 3.

Anahtar Kavram

Using the slope and a point on a line to find another coordinate along the same line.
Soru 45Soru

A linear relationship between xx and yy is represented by the values in the table below.

xxyy
2-2aa
1155
441717
77bb

What is the value of bab - a?

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Cevap: 36

Cevap

36
The constant rate of change (slope) of the relationship is 4, which is found by dividing the difference in yy-values by the difference in xx-values for the given points: 17541=4\frac{17 - 5}{4 - 1} = 4. The value of bab - a represents the change in yy over the interval from x=2x = -2 to x=7x = 7. The length of this interval is 7(2)=97 - (-2) = 9. Multiplying the rate of change by this interval length gives the total change in yy: 4×9=364 \times 9 = 36. Alternatively, solving for the equation yields y=4x+1y = 4x + 1, where substituting x=2x = -2 gives a=7a = -7 and substituting x=7x = 7 gives b=29b = 29, and their difference is 29(7)=3629 - (-7) = 36.

Adım Adım Çözüm

1
Find the constant rate of change (slope) of the linear relationship using the points (1,5)(1, 5) and (4,17)(4, 17).
The slope mm is 17541=123=4\frac{17 - 5}{4 - 1} = \frac{12}{3} = 4.
Since the relationship is linear, the rate of change is constant between any two points.
2
Determine the value of aa when x=2x = -2.
Using the point (1,5)(1, 5) and moving to x=2x = -2, the change in xx is 3-3. The corresponding change in yy is 4×(3)=124 \times (-3) = -12. Thus, a=512=7a = 5 - 12 = -7.
This establishes the value of the first variable in the expression.
3
Determine the value of bb when x=7x = 7.
Using the point (4,17)(4, 17) and moving to x=7x = 7, the change in xx is +3+3. The corresponding change in yy is 4×3=124 \times 3 = 12. Thus, b=17+12=29b = 17 + 12 = 29.
This establishes the value of the second variable in the expression.
4
Calculate the value of bab - a.
ba=29(7)=29+7=36b - a = 29 - (-7) = 29 + 7 = 36.
Subtracting a negative number is equivalent to adding its positive counterpart.

Anahtar Kavram

Linear rate of change and evaluation of linear relationships from tables of values

Alternatif Yöntem

Instead of calculating the individual values of aa and bb, recognize that bab - a is the total change in yy over the interval from x=2x = -2 to x=7x = 7. The change in xx is 7(2)=97 - (-2) = 9. Since the constant rate of change (slope) is 44, the change in yy is simply 4×9=364 \times 9 = 36.
Tahmini Süre:1m 30s
Soru 46Soru

A commercial printing press uses a continuous roll of paper to print newspapers at a constant rate. After 1010 minutes of operation, the remaining length of the paper roll is 12,50012,500 feet. After 2525 minutes of operation, the remaining length of the paper roll is 8,0008,000 feet. If the relationship between the printing time, in minutes, and the remaining length of the paper roll, in feet, is linear, how many minutes after the printing press starts operating will the remaining length of the paper roll be 2,0002,000 feet?

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Cevap: 45

Cevap

The remaining length of the paper roll will be 2,0002,000 feet after 4545 minutes of operation.
We are given that the remaining length of the paper roll is a linear function of time, tt. Let L(t)L(t) be the remaining length of the paper roll, in feet, after tt minutes of operation. We can represent the given information as two coordinate points: (10,12500)(10, 12500) and (25,8000)(25, 8000). First, find the slope, which represents the constant rate at which the paper is consumed: m=8000125002510=450015=300m = \frac{8000 - 12500}{25 - 10} = \frac{-4500}{15} = -300 feet per minute. Next, write the linear equation using the point-slope form: L(t)12500=300(t10)L(t) - 12500 = -300(t - 10), which simplifies to L(t)=15500300tL(t) = 15500 - 300t. To find the time when the remaining length is 2,0002,000 feet, set L(t)=2000L(t) = 2000 and solve for tt: 2000=15500300t2000 = 15500 - 300t, which simplifies to 300t=13500300t = 13500, giving t=45t = 45.

Adım Adım Çözüm

1
Calculate the rate of paper consumption (the slope of the linear equation) using the two given points, (10,12500)(10, 12500) and (25,8000)(25, 8000).
The rate of paper consumption is 300-300 feet per minute.
To establish the linear relationship, we first need the constant rate of change (slope) from the two known coordinate points.
2
Use the point-slope equation of a line, yy1=m(xx1)y - y_1 = m(x - x_1), with the point (10,12500)(10, 12500) and slope m=300m = -300, to find the equation relating the remaining length, LL, to the time, tt.
L(t)=15500300tL(t) = 15500 - 300t
We need the full linear model to calculate the remaining length at any specific time.
3
Substitute L(t)=2000L(t) = 2000 into the linear equation and solve for tt.
t=45t = 45
This gives the specific operating time in minutes when the remaining paper roll length is 2,0002,000 feet.

Anahtar Kavram

Writing and solving linear equations in two variables from two coordinate points.
Soru 47Soru

A chemist cools a liquid compound in a laboratory refrigerator. The temperature of the liquid decreases at a constant rate. After 44 minutes of cooling, the temperature of the liquid is 22C22^\circ\text{C}. After 1010 minutes of cooling, the temperature of the liquid is 13C13^\circ\text{C}. Which of the following equations represents the relationship between the temperature, TT, in degrees Celsius, of the liquid and the number of minutes, mm, it has been cooling?

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Cevap: 3m+2T=563m + 2T = 56

Cevap

The equation 3m+2T=563m + 2T = 56 correctly represents the relationship between the temperature TT and the cooling time mm.
The relationship between the temperature TT and the cooling time mm is linear, which can be represented by the equation T=1.5m+28T = -1.5m + 28. Rearranging this equation by adding 1.5m1.5m to both sides yields 1.5m+T=281.5m + T = 28. Multiplying the entire equation by 22 to clear the decimal gives 3m+2T=563m + 2T = 56, which is the correct linear relationship.

Adım Adım Çözüm

1
Calculate the rate of temperature change (slope, kk) per minute of cooling.
k=1322104=96=1.5Ck = \frac{13 - 22}{10 - 4} = \frac{-9}{6} = -1.5^\circ\text{C} per minute.
A linear relationship has a constant rate of change, which is found by dividing the change in temperature by the change in time.
2
Use the point-slope form to write the equation of the line.
T22=1.5(m4)T - 22 = -1.5(m - 4), which simplifies to T=1.5m+28T = -1.5m + 28.
This models the relationship between TT and mm by using one of the given data points and the calculated slope.
3
Rearrange the equation into standard form with integer coefficients.
1.5m+T=28    3m+2T=561.5m + T = 28 \implies 3m + 2T = 56.
The options are written in standard form, so adding 1.5m1.5m to both sides and multiplying the entire equation by 22 matches the target format.

Anahtar Kavram

Linear Equations in Two Variables
Soru 48Soru

An artist creates custom ceramic tiles in two shapes: square tiles and hexagonal tiles. Each square tile has an area of 1212 square inches, and each hexagonal tile has an area of 2828 square inches. The artist is designing a mosaic with a total area of 460460 square inches using only these two types of tiles. If the artist uses 1515 square tiles, how many hexagonal tiles are used in the mosaic?

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Cevap: 10

Cevap

The correct answer is 10. By setting up a linear equation representing the total area of the mosaic, 12s+28h=46012s + 28h = 460, and substituting the given value of 15 for the number of square tiles, we solve for the number of hexagonal tiles to get 10.
To find the number of hexagonal tiles used in the mosaic, we set up a linear equation in two variables representing the total area. Let ss represent the number of square tiles, and let hh represent the number of hexagonal tiles. The total area is the sum of the areas of the square tiles and the hexagonal tiles, which is 12s+28h=46012s + 28h = 460. Given that the artist uses 1515 square tiles, we substitute s=15s = 15 into the equation to get 12(15)+28h=46012(15) + 28h = 460. Simplifying the equation yields 180+28h=460180 + 28h = 460. Subtracting 180180 from both sides gives 28h=28028h = 280. Dividing both sides by 2828 yields h=10h = 10. Therefore, the artist uses 10 hexagonal tiles.

Adım Adım Çözüm

1
Define variables and set up the linear equation representing the total area of the mosaic.
12s+28h=46012s + 28h = 460, where ss is the number of square tiles and hh is the number of hexagonal tiles.
This models the relationship between the quantities of each tile type used and the total surface area of the mosaic.
2
Substitute the given number of square tiles into the equation.
12(15)+28h=46012(15) + 28h = 460, which simplifies to 180+28h=460180 + 28h = 460.
We are given that the artist uses exactly 15 square tiles in the design.
3
Isolate the variable term by subtracting the constant from both sides.
28h=28028h = 280.
This isolates the term containing the unknown variable on one side of the equation.
4
Solve for the remaining variable by dividing both sides by its coefficient.
h=10h = 10.
Dividing both sides by the coefficient yields the final count of hexagonal tiles.

Anahtar Kavram

Linear Equations in Two Variables
Tahmini Süre:1m 30s
Soru 49Soru

A municipal water utility charges customers a flat monthly fee plus a constant rate per thousand gallons of water used. In June, a household used 88 thousand gallons of water and was charged a total of $46.00\$46.00. In July, the same household used 1212 thousand gallons of water and was charged a total of $62.00\$62.00. If xx represents the number of thousand gallons of water used in a month, and yy represents the total monthly charge, in dollars, which of the following equations represents the relationship between xx and yy?

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Cevap: y=4x+14y = 4x + 14

Cevap

y=4x+14y = 4x + 14
The correct equation is y=4x+14y = 4x + 14. The constant rate of change (slope) is found by dividing the difference in monthly charges by the difference in water usage: 6246128=4\frac{62 - 46}{12 - 8} = 4. Using the point-slope form or slope-intercept form with the point (8,46)(8, 46) yields 46=4(8)+b46 = 4(8) + b, which simplifies to b=14b = 14 for the y-intercept (the flat monthly fee). Substituting these parameters back into the slope-intercept form yields the correct relationship.

Adım Adım Çözüm

1
Calculate the constant rate of change (slope, mm) using the two given data points, (8,46)(8, 46) and (12,62)(12, 62).
m=6246128=164=4m = \frac{62 - 46}{12 - 8} = \frac{16}{4} = 4.
The constant rate of change represents the slope of the linear equation.
2
Use the slope-intercept form, y=mx+by = mx + b, and substitute one of the data points, such as (8,46)(8, 46), to solve for the y-intercept (bb).
46=4(8)+b    46=32+b    b=1446 = 4(8) + b \implies 46 = 32 + b \implies b = 14.
Substituting a known point allows us to isolate and find the value of the flat monthly fee, which is the y-intercept.
3
Write the final equation by substituting the calculated slope (m=4m = 4) and y-intercept (b=14b = 14) back into the slope-intercept form.
y=4x+14y = 4x + 14.
This combines the rate per thousand gallons and the flat fee into the final linear relationship.

Anahtar Kavram

Linear Equations in Two Variables
Tahmini Süre:1m 30s
Soru 50Soru

In the xyxy-plane, the graph of the linear equation kx3y=18kx - 3y = 18, where kk is a constant, has a yy-intercept of (0,b)(0, b) and an xx-intercept of (a,0)(a, 0), where aa and bb are constants. If ab=15a - b = 15, what is the value of kk?

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Cevap: 2

Cevap

2
To find the value of kk, we first determine the intercepts of the linear equation kx3y=18kx - 3y = 18. The yy-intercept (0,b)(0, b) occurs where x=0x = 0. Substituting x=0x = 0 gives 3b=18-3b = 18, which solves to b=6b = -6. Next, we use the given relation ab=15a - b = 15. Substituting b=6b = -6 yields a(6)=15a - (-6) = 15, or a+6=15a + 6 = 15, which gives a=9a = 9. The xx-intercept is therefore (9,0)(9, 0). Since this point lies on the line, we substitute x=9x = 9 and y=0y = 0 into the original equation: k(9)3(0)=18k(9) - 3(0) = 18. This simplifies to 9k=189k = 18, which gives k=2k = 2.

Adım Adım Çözüm

1
Find the yy-coordinate of the yy-intercept (bb) by setting x=0x = 0 in the equation kx3y=18kx - 3y = 18.
b=6b = -6
The yy-intercept occurs where the graph crosses the yy-axis, which corresponds to x=0x = 0.
2
Use the equation ab=15a - b = 15 and the value of b=6b = -6 to solve for aa.
a=9a = 9
Substituting b=6b = -6 into ab=15a - b = 15 gives a(6)=15a - (-6) = 15, which simplifies to a+6=15a + 6 = 15.
3
Find the value of kk by substituting the xx-intercept (9,0)(9, 0) into the equation kx3y=18kx - 3y = 18.
k=2k = 2
Since (a,0)=(9,0)(a, 0) = (9, 0) is the xx-intercept, it must satisfy the equation of the line.

Anahtar Kavram

Determining intercepts of a linear equation in two variables and using them to find unknown constants.
Soru 51Soru

The table below shows the remaining balance, BB, in dollars, on a transit card after a user has taken rr rides on a city bus.

Number of rides (rr)Remaining balance (BB, in dollars)
3322.5022.50
8810.0010.00
12120.000.00

Which of the following equations represents the relationship between BB and rr?

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Cevap: B=30.002.50rB = 30.00 - 2.50r

Cevap

B=30.002.50rB = 30.00 - 2.50r
The correct equation has a rate of change of 2.50-2.50 dollars per ride and a starting balance of 30.0030.00 dollars. The rate of change (slope) can be calculated by finding the change in balance divided by the change in the number of rides between two points, such as (3,22.50)(3, 22.50) and (8,10.00)(8, 10.00), which gives 10.0022.5083=2.50\frac{10.00 - 22.50}{8 - 3} = -2.50. Using the slope-intercept form B=mr+B0B = mr + B_0 and the point (12,0.00)(12, 0.00), we get 0.00=2.50(12)+B00.00 = -2.50(12) + B_0, which simplifies to B0=30.00B_0 = 30.00. Therefore, the equation is B=30.002.50rB = 30.00 - 2.50r.

Adım Adım Çözüm

1
Calculate the slope (rate of change) using two points from the table, such as (3,22.50)(3, 22.50) and (8,10.00)(8, 10.00).
The slope is m=10.0022.5083=12.505=2.50m = \frac{10.00 - 22.50}{8 - 3} = \frac{-12.50}{5} = -2.50.
The slope represents the constant change in the remaining balance per ride.
2
Use the slope-intercept form B=mr+B0B = mr + B_0 and one point to find the initial balance B0B_0.
Substituting m=2.50m = -2.50 and the point (12,0.00)(12, 0.00) gives 0.00=2.50(12)+B00.00 = -2.50(12) + B_0, which simplifies to 0.00=30.00+B00.00 = -30.00 + B_0, so B0=30.00B_0 = 30.00.
The initial balance B0B_0 is the y-intercept, which is the value of BB when r=0r = 0.
3
Write the final linear equation representing the relationship.
The final equation is B=30.002.50rB = 30.00 - 2.50r.
This equation models the remaining balance on the card as a function of the number of rides taken.

Anahtar Kavram

Finding a linear equation in two variables from a table of values.
Soru 52Soru

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the points (2,15)(2, 15) and (6,7)(6, 7). What is the value of bb?

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Cevap: 19

Cevap

The value of bb is 1919.
The slope of the line is found using the two given points: m=71562=2m = \frac{7 - 15}{6 - 2} = -2. Substituting the slope m=2m = -2 and the point (2,15)(2, 15) into the equation y=mx+by = mx + b gives 15=2(2)+b15 = -2(2) + b, which simplifies to 15=4+b15 = -4 + b. Adding 44 to both sides yields b=19b = 19.

Adım Adım Çözüm

1
Calculate the slope of the line passing through (2,15)(2, 15) and (6,7)(6, 7).
m=71562=84=2m = \frac{7 - 15}{6 - 2} = \frac{-8}{4} = -2
The slope mm of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Substitute the slope m=2m = -2 and the coordinates of one point, such as (2,15)(2, 15), into the equation y=mx+by = mx + b to find bb.
15=2(2)+b    15=4+b15 = -2(2) + b \implies 15 = -4 + b
Since the point lies on the line, its coordinates must satisfy the equation of the line.
3
Solve the equation for bb.
b=19b = 19
Add 44 to both sides of the equation to isolate the variable bb.

Anahtar Kavram

Determining the equation of a line given two points.
Soru 53Soru

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the points (2,5)(-2, 5) and (4,7)(4, 7). What is the value of m+bm + b?

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Cevap: 66

Cevap

The value of m+bm + b is 66.
The correct answer is 66. By finding the slope mm using the change in yy divided by the change in xx, we get m=13m = \frac{1}{3}. Using the slope-intercept form with the point (4,7)(4, 7) allows us to solve for b=173b = \frac{17}{3}. Adding the two values together yields m+b=13+173=6m + b = \frac{1}{3} + \frac{17}{3} = 6.

Adım Adım Çözüm

1
Calculate the slope mm of the line using the two points (2,5)(-2, 5) and (4,7)(4, 7).
m=754(2)=26=13m = \frac{7 - 5}{4 - (-2)} = \frac{2}{6} = \frac{1}{3}
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Substitute the slope m=13m = \frac{1}{3} and the coordinates of one point, such as (4,7)(4, 7), into the slope-intercept equation y=mx+by = mx + b to solve for bb.
7=13(4)+b7=43+bb=1737 = \frac{1}{3}(4) + b \Rightarrow 7 = \frac{4}{3} + b \Rightarrow b = \frac{17}{3}
Substituting a known point and the slope into the slope-intercept form allows us to isolate and solve for the constant yy-intercept.
3
Add the calculated values of mm and bb to find m+bm + b.
m+b=13+173=183=6m + b = \frac{1}{3} + \frac{17}{3} = \frac{18}{3} = 6
The question asks for the sum of the slope mm and the yy-intercept bb.

Anahtar Kavram

Linear Equations in Two Variables
Soru 54Soru

In the xyxy-plane, a line is represented by the equation aybx=24ay - bx = 24, where aa and bb are constants. If the line has a yy-intercept of (0,3)(0, -3) and passes through the point (4,5)(4, 5), what is the slope of the line?

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Cevap: 2

Cevap

The slope of the line is 2.
Substituting the y-intercept (0,3)(0, -3) into the equation aybx=24ay - bx = 24 yields 3a=24-3a = 24, which gives a=8a = -8. Substituting the point (4,5)(4, 5) and a=8a = -8 into the equation yields 8(5)4b=24-8(5) - 4b = 24, which simplifies to 404b=24-40 - 4b = 24, giving b=16b = -16. Re-assembling the equation gives 8y+16x=24-8y + 16x = 24. Solving for yy in terms of xx yields y=2x3y = 2x - 3, where the coefficient of xx is the slope, 2.

Adım Adım Çözüm

1
Substitute the y-intercept (0,3)(0, -3) into the given equation aybx=24ay - bx = 24 to find the value of aa.
a=8a = -8
Since the y-intercept lies on the line, its coordinates satisfy the line's equation.
2
Substitute the point (4,5)(4, 5) and the value of a=8a = -8 into the equation to find the value of bb.
b=16b = -16
Since the point (4,5)(4, 5) lies on the line, its coordinates must satisfy the equation.
3
Write the resulting equation 8y+16x=24-8y + 16x = 24 in slope-intercept form (y=mx+cy = mx + c) to identify the slope.
y=2x3y = 2x - 3, which gives a slope of 22.
The slope of a line in the form y=mx+cy = mx + c is represented by the coefficient mm of xx.

Anahtar Kavram

Finding the slope of a line from a given equation by determining its constant coefficients using known points.
Tahmini Süre:1m 30s
Soru 55Soru

An online retail company determines that the relationship between the selling price of a product, xx dollars, and the daily number of units sold, yy, can be modeled by a linear equation. When the selling price is 1212 dollars, the company sells 8080 units per day. For every 33 dollars increase in the selling price, the number of units sold daily decreases by 1515. Which of the following equations represents this relationship?

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Cevap: y=5x+140y = -5x + 140

Cevap

The equation y=5x+140y = -5x + 140
The relationship between price xx and units sold yy is linear. The slope mm represents the rate of change: m=ΔyΔx=153=5m = \frac{\Delta y}{\Delta x} = \frac{-15}{3} = -5. Using the point-slope form with the known point (12,80)(12, 80), we get y80=5(x12)y - 80 = -5(x - 12). Distributing the 5-5 gives y80=5x+60y - 80 = -5x + 60. Adding 8080 to both sides results in the equation y=5x+140y = -5x + 140.

Adım Adım Çözüm

1
Calculate the slope (mm) of the linear relation.
m=change in ychange in x=153=5m = \frac{\text{change in } y}{\text{change in } x} = \frac{-15}{3} = -5
The slope is the rate of change, which represents the decrease of 1515 units for every 33 dollars increase in price.
2
Set up the equation using point-slope form with the point (12,80)(12, 80) and the slope m=5m = -5.
y80=5(x12)y - 80 = -5(x - 12)
Point-slope form allows us to write the equation of a line given its slope and a point it passes through.
3
Simplify the equation into slope-intercept form.
y80=5x+60y=5x+140y - 80 = -5x + 60 \Rightarrow y = -5x + 140
Distributing the slope 5-5 to 12-12 yields +60+60, and adding 8080 to both sides isolates the variable yy.

Anahtar Kavram

Linear Equations in Two Variables

Alternatif Yöntem

Substitute the point (12,80)(12, 80) and slope m=5m = -5 into the slope-intercept equation y=mx+by = mx + b to find bb: 80=5(12)+b80=60+bb=14080 = -5(12) + b \Rightarrow 80 = -60 + b \Rightarrow b = 140. Thus, y=5x+140y = -5x + 140.
Tahmini Süre:1m 30s
Soru 56Soru

The graph of a linear equation in the xyxy-plane has an xx-intercept of (k,0)(k, 0) and a yy-intercept of (0,3k)(0, 3k), where kk is a positive constant. If the line passes through the point (2,12)(2, 12), what is the value of kk?

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Cevap: 6

Cevap

The value of kk is 66.
The correct answer is 66. The slope of the line can be found using the two intercepts (k,0)(k, 0) and (0,3k)(0, 3k): m=3k00k=3m = \frac{3k - 0}{0 - k} = -3. The equation of the line in slope-intercept form is y=3x+3ky = -3x + 3k. Since the line passes through the point (2,12)(2, 12), we substitute x=2x = 2 and y=12y = 12 into the equation to get 12=3(2)+3k12 = -3(2) + 3k. Simplifying the equation yields 12=6+3k12 = -6 + 3k, which gives 18=3k18 = 3k. Dividing both sides by 33 results in k=6k = 6.

Adım Adım Çözüm

1
Find the slope of the line using the xx-intercept (k,0)(k, 0) and the yy-intercept (0,3k)(0, 3k).
The slope of the line is 3-3.
The slope formula is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the points (k,0)(k, 0) and (0,3k)(0, 3k) gives m=3k00k=3kk=3m = \frac{3k - 0}{0 - k} = \frac{3k}{-k} = -3.
2
Write the equation of the line in slope-intercept form.
The equation of the line is y=3x+3ky = -3x + 3k.
Using the slope-intercept form y=mx+by = mx + b, we substitute the slope m=3m = -3 and the yy-intercept value b=3kb = 3k from the point (0,3k)(0, 3k).
3
Substitute the given point (2,12)(2, 12) into the equation and solve for kk.
The value of kk is 66.
Substituting x=2x = 2 and y=12y = 12 into y=3x+3ky = -3x + 3k yields 12=3(2)+3k12 = -3(2) + 3k. This simplifies to 12=6+3k12 = -6 + 3k. Adding 66 to both sides gives 18=3k18 = 3k, and dividing by 33 gives k=6k = 6.

Anahtar Kavram

Linear equations in two variables, finding equations from intercepts, and constant determination via point substitution.
Soru 57Soru

A municipal swimming pool is being filled with water at a constant rate. After 22 hours of filling, the pool contains 14,50014,500 gallons of water. After 55 hours of filling, the pool contains 20,20020,200 gallons of water. If the relationship between the time the pool has been filling, tt, in hours, and the volume of water in the pool, VV, in gallons, is linear, which of the following equations represents this relationship?

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Cevap: V=1,900t+10,700V = 1,900t + 10,700

Cevap

The equation representing the relationship is V=1,900t+10,700V = 1,900t + 10,700.
The correct equation is V=1,900t+10,700V = 1,900t + 10,700. The rate of change of the water volume is the change in volume divided by the change in time: 20,20014,50052=5,7003=1,900\frac{20,200 - 14,500}{5 - 2} = \frac{5,700}{3} = 1,900 gallons per hour. Using the point-slope form with the coordinate point (2,14,500)(2, 14,500) yields V14,500=1,900(t2)V - 14,500 = 1,900(t - 2). Simplifying this expression gives V14,500=1,900t3,800V - 14,500 = 1,900t - 3,800, which results in V=1,900t+10,700V = 1,900t + 10,700.

Adım Adım Çözüm

1
Identify two data points from the problem context.
The two coordinate pairs representing (t,V)(t, V) are (2,14,500)(2, 14,500) and (5,20,200)(5, 20,200).
These points will allow us to calculate the slope and the y-intercept of the linear equation.
2
Calculate the slope (mm) using the slope formula m=V2V1t2t1m = \frac{V_2 - V_1}{t_2 - t_1}.
m=20,20014,50052=5,7003=1,900m = \frac{20,200 - 14,500}{5 - 2} = \frac{5,700}{3} = 1,900.
The slope represents the constant rate, in gallons per hour, at which the pool is being filled.
3
Substitute the slope m=1,900m = 1,900 and the point (2,14,500)(2, 14,500) into the point-slope form equation VV1=m(tt1)V - V_1 = m(t - t_1) to solve for VV.
V14,500=1,900(t2)    V14,500=1,900t3,800    V=1,900t+10,700V - 14,500 = 1,900(t - 2) \implies V - 14,500 = 1,900t - 3,800 \implies V = 1,900t + 10,700.
This yields the equation representing the volume of water VV in the pool at any time tt.

Anahtar Kavram

Determining a linear equation in two variables given two points from a word problem context.

Alternatif Yöntem

Instead of solving the linear equation algebraically, you can test the coordinates of the two given points (2,14,500)(2, 14,500) and (5,20,200)(5, 20,200) in the answer choices. Substituting t=2t = 2 and t=5t = 5 into the correct equation V=1,900t+10,700V = 1,900t + 10,700 satisfies both conditions: 1,900(2)+10,700=14,5001,900(2) + 10,700 = 14,500 and 1,900(5)+10,700=20,2001,900(5) + 10,700 = 20,200. None of the other options satisfy both points.
Tahmini Süre:1m 30s
Soru 58Soru

A technician is monitoring the pressure of a gas inside a container during an experiment. The pressure PP, in kilopascals (kPa\text{kPa}), and the time elapsed tt, in minutes, are related by a linear equation. At t=4t = 4 minutes, the pressure is 112 kPa112\text{ kPa}. At t=12t = 12 minutes, the pressure is 136 kPa136\text{ kPa}. If the pressure continues to increase at this constant rate, what will the pressure be, in kPa\text{kPa}, at t=15t = 15 minutes?

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Cevap: 145

Cevap

145
The relationship between pressure PP and time tt is linear, which can be modeled by the equation P=mt+bP = mt + b, where mm is the rate of change (slope) and bb is the pressure at t=0t = 0. Using the points (4,112)(4, 112) and (12,136)(12, 136), the slope is calculated as m=136112124=248=3m = \frac{136 - 112}{12 - 4} = \frac{24}{8} = 3. Substituting the point (4,112)(4, 112) and m=3m = 3 into the equation P=mt+bP = mt + b yields 112=3(4)+b112 = 3(4) + b, which simplifies to 112=12+b112 = 12 + b, so b=100b = 100. The linear equation is P=3t+100P = 3t + 100. Substituting t=15t = 15 into this equation gives P=3(15)+100=45+100=145P = 3(15) + 100 = 45 + 100 = 145.

Adım Adım Çözüm

1
Calculate the rate of change (slope, mm) using the two given coordinate points (4,112)(4, 112) and (12,136)(12, 136).
m=136112124=248=3m = \frac{136 - 112}{12 - 4} = \frac{24}{8} = 3
To find the constant rate at which the pressure is increasing per minute.
2
Set up the linear equation using the point-slope form PP1=m(tt1)P - P_1 = m(t - t_1) with the point (4,112)(4, 112).
P112=3(t4)P=3t+100P - 112 = 3(t - 4) \Rightarrow P = 3t + 100
To establish the linear relationship between pressure and time.
3
Substitute t=15t = 15 into the linear equation to find the pressure at 1515 minutes.
P=3(15)+100=145P = 3(15) + 100 = 145
To determine the pressure at the requested time of 1515 minutes.

Anahtar Kavram

Finding and applying a linear equation in two variables from two points.
Soru 59Soru

The total daily cost CC, in dollars, for a custom apparel company to manufacture xx shirts is modeled by a linear equation. The table below shows the total daily cost for two different numbers of shirts manufactured:

Number of shirts, xxTotal daily cost, CC (dollars)
12260
20380

Based on the model, what is the total daily cost, in dollars, to manufacture 35 shirts?

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Cevap: 605

Cevap

605
To find the total daily cost to manufacture 35 shirts, we first determine the linear relationship C=mx+bC = mx + b between the number of shirts manufactured, xx, and the total cost, CC. The slope mm is the constant rate of change, calculated as m=3802602012=1208=15m = \frac{380 - 260}{20 - 12} = \frac{120}{8} = 15 dollars per shirt. Using the point-slope form with the point (12,260)(12, 260), we get C260=15(x12)C - 260 = 15(x - 12), which simplifies to C=15x+80C = 15x + 80. Substituting 3535 for xx in this equation yields C=15(35)+80=525+80=605C = 15(35) + 80 = 525 + 80 = 605. Therefore, the total daily cost to manufacture 35 shirts is 605 dollars.

Adım Adım Çözüm

1
Calculate the slope (rate of change) of the linear relationship using the two points from the table, (12,260)(12, 260) and (20,380)(20, 380).
Slope m=3802602012=1208=15m = \frac{380 - 260}{20 - 12} = \frac{120}{8} = 15 dollars per shirt.
Since the relationship is linear, the rate of change is constant.
2
Find the equation of the line using the point-slope form CC1=m(xx1)C - C_1 = m(x - x_1) with the point (12,260)(12, 260) and slope m=15m = 15.
C260=15(x12)    C=15x180+260    C=15x+80C - 260 = 15(x - 12) \implies C = 15x - 180 + 260 \implies C = 15x + 80.
This establishes the linear equation relating the number of shirts xx and the total daily cost CC.
3
Substitute x=35x = 35 into the linear equation to find the total daily cost to manufacture 35 shirts.
C=15(35)+80=525+80=605C = 15(35) + 80 = 525 + 80 = 605 dollars.
This evaluates the linear model at the desired quantity.

Anahtar Kavram

Determining a linear equation in two variables from a table of values and using it to predict a value.
Soru 60Soru

A hybrid car's fuel tank has a capacity of 1212 gallons. When driving on a highway, the amount of fuel in the tank decreases at a constant rate. After driving for 1.51.5 hours, 9.69.6 gallons of fuel remain in the tank. If the amount of fuel in the tank, FF, in gallons, after driving for tt hours is modeled by a linear equation, what is the value of FF when t=4t = 4?

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Cevap: 5.6

Cevap

The amount of fuel remaining in the tank after driving for 44 hours is 5.65.6 gallons.
The amount of fuel in the tank, FF, and the driving time, tt, share a linear relationship. The initial amount of fuel at t=0t = 0 is 1212 gallons, representing the vertical intercept. The fuel decreases at a constant rate, which is the slope of the line. Over a period of 1.51.5 hours, the amount of fuel decreases by 129.6=2.412 - 9.6 = 2.4 gallons. The rate of decrease is 2.41.5=1.6\frac{2.4}{1.5} = 1.6 gallons per hour, so the slope is 1.6-1.6. The linear model is F=1.6t+12F = -1.6t + 12. Substituting t=4t = 4 into this equation yields F=1.6(4)+12=6.4+12=5.6F = -1.6(4) + 12 = -6.4 + 12 = 5.6 gallons.

Adım Adım Çözüm

1
Calculate the constant rate of fuel consumption (the slope of the linear relationship).
The rate of consumption is 1.61.6 gallons per hour.
Since the fuel decreases at a constant rate, the change in fuel divided by the change in time gives the rate of consumption. In 1.51.5 hours, the fuel decreases from 1212 gallons to 9.69.6 gallons, which is a decrease of 129.6=2.412 - 9.6 = 2.4 gallons. Thus, the rate of consumption is 2.4 gallons1.5 hours=1.6\frac{2.4\text{ gallons}}{1.5\text{ hours}} = 1.6 gallons per hour.
2
Write the linear equation modeling the fuel remaining in the tank, FF, as a function of time, tt.
F=1.6t+12F = -1.6t + 12
The initial amount of fuel when t=0t = 0 is 1212 gallons, which represents the vertical intercept (b=12b = 12). The fuel decreases at a constant rate of 1.61.6 gallons per hour, which represents a slope of m=1.6m = -1.6.
3
Substitute t=4t = 4 into the linear equation to find the value of FF.
F=5.6F = 5.6
Evaluating the equation at t=4t = 4 yields F=1.6(4)+12=6.4+12=5.6F = -1.6(4) + 12 = -6.4 + 12 = 5.6.

Anahtar Kavram

Linear Equations in Two Variables
ÖncekiSayfa 3 / 3
Linear Equations in Two Variables Alıştırma Soruları — SAT — Sayfa 3 | Examkin