Linear Equations in Two Variables

60 soru

Soru 21Soru

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the point (2,7)(2, 7). If this graph is translated 33 units to the right and 44 units down, the resulting graph passes through the point (4,2)(4, 2). What is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

5
The correct answer is 55. Since the original graph passes through (2,7)(2, 7) and undergoes a translation of 33 units to the right and 44 units down, the point (2,7)(2, 7) is translated to (2+3,74)=(5,3)(2 + 3, 7 - 4) = (5, 3) on the new graph. The translated graph also passes through (4,2)(4, 2). Using the slope formula on the two points (5,3)(5, 3) and (4,2)(4, 2) of the translated line gives a slope of 11. Since a translation preserves the slope, the original line also has a slope of 11. Substituting m=1m = 1 and (2,7)(2, 7) into the original equation y=mx+by = mx + b yields 7=1(2)+b7 = 1(2) + b, which simplifies to b=5b = 5.

Adım Adım Çözüm

1
Determine a point on the translated graph by translating the given point (2,7)(2, 7) on the original graph.
The point (5,3)(5, 3) is on the translated graph.
Since the entire graph is translated 33 units to the right and 44 units down, every point on the original graph is translated by the same vector (+3,4)(+3, -4).
2
Calculate the slope of the translated graph using the points (5,3)(5, 3) and (4,2)(4, 2).
The slope m=1m = 1.
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the change in y divided by the change in x.
3
Find the slope of the original graph.
The slope of the original graph is also 11.
Translating a line horizontally and vertically shifts its position but does not alter its slope.
4
Substitute the slope m=1m = 1 and the point (2,7)(2, 7) into the slope-intercept form of the original line, y=mx+by = mx + b, to solve for bb.
b=5b = 5.
This determines the value of the y-intercept of the original line.

Anahtar Kavram

Linear Equations in Two Variables
Soru 22Soru

A linear relationship exists between the variables pp and qq. When the value of pp increases by 66, the value of qq decreases by 44. If q=15q = 15 when p=2p = 2, which of the following equations correctly expresses pp in terms of qq?

Cevabı ve açıklamayı göster

Cevap: p=32q+492p = -\frac{3}{2}q + \frac{49}{2}

Cevap

p=32q+492p = -\frac{3}{2}q + \frac{49}{2}
The correct equation is found by first calculating the rate of change of qq with respect to pp, which is 46=23\frac{-4}{6} = -\frac{2}{3}. Using the point-slope form with (p,q)=(2,15)(p, q) = (2, 15), we set up the equation q15=23(p2)q - 15 = -\frac{2}{3}(p - 2). To express pp in terms of qq, we isolate pp by multiplying both sides by 32-\frac{3}{2} to get 32q+452=p2-\frac{3}{2}q + \frac{45}{2} = p - 2, and then adding 22 to both sides, which yields p=32q+492p = -\frac{3}{2}q + \frac{49}{2}.

Adım Adım Çözüm

1
Calculate the rate of change of qq relative to pp using the given changes.
The rate of change is 46=23-\frac{4}{6} = -\frac{2}{3}.
Since qq decreases by 44 when pp increases by 66, the slope mm in terms of Δq/Δp\Delta q / \Delta p is 23-\frac{2}{3}.
2
Set up the point-slope form of the linear equation using the point (p,q)=(2,15)(p, q) = (2, 15).
q15=23(p2)q - 15 = -\frac{2}{3}(p - 2)
The point-slope form is qq1=m(pp1)q - q_1 = m(p - p_1), where (p1,q1)=(2,15)(p_1, q_1) = (2, 15) and m=23m = -\frac{2}{3}.
3
Solve the equation for pp by first clearing the coefficient of the pp-term.
32(q15)=p2    32q+452=p2-\frac{3}{2}(q - 15) = p - 2 \implies -\frac{3}{2}q + \frac{45}{2} = p - 2
Multiplying both sides by 32-\frac{3}{2} simplifies isolation of the variable pp.
4
Complete the isolation of pp by adding 22 to both sides.
p=32q+452+2    p=32q+492p = -\frac{3}{2}q + \frac{45}{2} + 2 \implies p = -\frac{3}{2}q + \frac{49}{2}
Adding 22 (which is 42\frac{4}{2}) to 452\frac{45}{2} isolates pp on one side of the equation.

Anahtar Kavram

Linear relationships and isolating variables in two-variable linear equations.
Soru 23Soru

In the xyxy-plane, the graph of the equation ax+by=24ax + by = 24, where aa and bb are constants, is a line. The line has an xx-intercept of (d,0)(d, 0) and a yy-intercept of (0,d6)(0, d - 6), where d>6d > 6 is a constant. If the line passes through the point (2,5)(2, 5), what is the value of a+ba + b?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6
Substituting the intercepts (d,0)(d, 0) and (0,d6)(0, d-6) into ax+by=24ax + by = 24 gives a=24/da = 24/d and b=24/(d6)b = 24/(d-6). Using the point (2,5)(2, 5), we get 2(24/d)+5(24/(d6))=242(24/d) + 5(24/(d-6)) = 24, which simplifies to 2/d+5/(d6)=12/d + 5/(d-6) = 1. Solving for dd yields d213d+12=0d^2 - 13d + 12 = 0, giving d=12d = 12 or d=1d = 1. Given d>6d > 6, we have d=12d = 12. Substituting d=12d = 12 back gives a=2a = 2 and b=4b = 4, so a+b=6a + b = 6.

Adım Adım Çözüm

1
Find expressions for aa and bb in terms of dd by substituting the given intercepts.
a=24da = \frac{24}{d} and b=24d6b = \frac{24}{d-6}
The xx-intercept (d,0)(d, 0) and yy-intercept (0,d6)(0, d-6) lie on the line ax+by=24ax + by = 24.
2
Substitute the point (2,5)(2, 5) into the line's equation.
2a+5b=242a + 5b = 24
The point (2,5)(2, 5) lies on the line.
3
Substitute the expressions for aa and bb into 2a+5b=242a + 5b = 24 and simplify.
2d+5d6=1\frac{2}{d} + \frac{5}{d-6} = 1
To create a single equation in terms of the variable dd.
4
Solve the rational equation for dd.
d=12d = 12
Multiplying by the common denominator d(d6)d(d-6) leads to the quadratic equation d213d+12=0d^2 - 13d + 12 = 0, which factors as (d12)(d1)=0(d-12)(d-1) = 0. Since the problem states d>6d > 6, the only valid solution is d=12d = 12.
5
Calculate aa and bb using d=12d = 12, and find their sum.
a=2a = 2, b=4b = 4, and a+b=6a + b = 6
Substituting d=12d = 12 into the expressions for aa and bb yields the constant coefficients, and summing them provides the final requested value.

Anahtar Kavram

Using intercepts and a given point on a line in the coordinate plane to solve for the parameters of its linear equation.
Soru 24Soru

In the xyxy-plane, a line with a positive slope mm passes through the points (2,5)(2, 5) and (m,13)(m, 13). Which of the following is the yy-intercept of this line?

Cevabı ve açıklamayı göster

Cevap: (0,3)(0, -3)

Cevap

(0,3)(0, -3)
The correct answer is the point (0,3)(0, -3). The slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) is expressed as m=135m2=8m2m = \frac{13 - 5}{m - 2} = \frac{8}{m - 2}. Multiplying by m2m - 2 yields the quadratic equation m22m8=0m^2 - 2m - 8 = 0. Factoring this equation gives (m4)(m+2)=0(m - 4)(m + 2) = 0. Since the slope mm is given as positive, we select m=4m = 4. Using the point-slope form with m=4m = 4 and the point (2,5)(2, 5) yields the equation y5=4(x2)y - 5 = 4(x - 2), which simplifies to y=4x3y = 4x - 3. The yy-intercept of this line is found by setting x=0x = 0, giving y=3y = -3, or the coordinate point (0,3)(0, -3).

Adım Adım Çözüm

1
Use the slope formula to express the slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) in terms of mm.
m=135m2    m=8m2m = \frac{13 - 5}{m - 2} \implies m = \frac{8}{m - 2}
The slope of a line is defined as the ratio of the change in yy to the change in xx between any two points on the line.
2
Solve the equation m=8m2m = \frac{8}{m - 2} for mm by converting it into a quadratic equation.
m(m2)=8    m22m8=0    (m4)(m+2)=0m(m - 2) = 8 \implies m^2 - 2m - 8 = 0 \implies (m - 4)(m + 2) = 0, which gives m=4m = 4 or m=2m = -2. Since the slope is positive, m=4m = 4.
Multiplying both sides by the denominator clears the fraction and allows us to solve for the unknown parameter mm using factoring.
3
Determine the equation of the line using the point-slope form with m=4m = 4 and the point (2,5)(2, 5).
y5=4(x2)    y=4x8+5    y=4x3y - 5 = 4(x - 2) \implies y = 4x - 8 + 5 \implies y = 4x - 3
The point-slope form provides a direct way to write the linear equation using a known point and the calculated slope.
4
Find the yy-intercept by evaluating the line equation at x=0x = 0.
y=4(0)3    y=3y = 4(0) - 3 \implies y = -3, which corresponds to the point (0,3)(0, -3).
The yy-intercept of any line is the point where the line crosses the yy-axis, which occurs at x=0x = 0.

Anahtar Kavram

Linear Equations in Two Variables

Alternatif Yöntem

Alternatively, once the slope m=4m = 4 is found, we can write the equation of the line in slope-intercept form y=4x+by = 4x + b. Substituting the coordinates of the point (2,5)(2, 5) into the equation gives 5=4(2)+b    5=8+b5 = 4(2) + b \implies 5 = 8 + b. Solving for bb gives b=3b = -3. Since bb is the yy-intercept, the point is (0,3)(0, -3).
Tahmini Süre:2m 30s
Soru 25Soru

For a constant kk, the graph of the linear equation kx4y=15kx - 4y = 15 in the xyxy-plane contains the point (3,3)(3, 3). What is the slope of the line?

Cevabı ve açıklamayı göster

Cevap: 2.25

Cevap

2.25
Substituting the coordinates of the point (3,3)(3, 3) into the given equation yields k(3)4(3)=15k(3) - 4(3) = 15, which simplifies to 3k12=153k - 12 = 15. Adding 1212 to both sides gives 3k=273k = 27, and dividing by 33 gives k=9k = 9. Substituting k=9k = 9 back into the original equation gives 9x4y=159x - 4y = 15. To find the slope of the line, the equation can be written in slope-intercept form, y=mx+by = mx + b, by isolating yy. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing all terms by 4-4 yields y=94x154y = \frac{9}{4}x - \frac{15}{4}, or y=2.25x3.75y = 2.25x - 3.75. Therefore, the slope of the line is 94\frac{9}{4}, or 2.252.25.

Adım Adım Çözüm

1
Substitute the point (3,3)(3, 3) into the equation kx4y=15kx - 4y = 15
3k12=153k - 12 = 15
Since the graph of the equation contains the point (3,3)(3, 3), substituting x=3x = 3 and y=3y = 3 must satisfy the equation.
2
Solve for the constant kk
k=9k = 9
Adding 1212 to both sides of the equation gives 3k=273k = 27. Dividing both sides by 33 yields k=9k = 9.
3
Substitute k=9k = 9 into the equation and rewrite it in slope-intercept form (y=mx+by = mx + b)
y=94x154y = \frac{9}{4}x - \frac{15}{4}
Substituting k=9k = 9 gives 9x4y=159x - 4y = 15. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing both sides by 4-4 isolates yy.
4
Identify the slope from the slope-intercept form
Slope = 2.252.25 (or 94\frac{9}{4})
In the slope-intercept form y=mx+by = mx + b, the coefficient mm represents the slope of the line.

Anahtar Kavram

Determining the slope of a line from a linear equation by first finding an unknown constant using a given point on the line.
Soru 26Soru

A delivery truck carries a total of xx bags of organic fertilizer and yy bags of compost. Each bag of fertilizer weighs 4545 pounds, and each bag of compost weighs 3030 pounds. When the truck is loaded to exactly 80%80\% of its maximum payload capacity, the relationship between xx and yy can be represented by the equation 3x+2y=2403x + 2y = 240. What is the truck's maximum payload capacity, in pounds?

Cevabı ve açıklamayı göster

Cevap: 4,5004,500

Cevap

The maximum payload capacity of the truck is 4,5004,500 pounds.
The total weight of the bags loaded on the truck is represented by the expression 45x+30y45x + 30y pounds. Factoring out 1515 from this expression gives 15(3x+2y)15(3x + 2y). We are given that when the truck is loaded to exactly 80%80\% of its capacity, the relationship between xx and yy is 3x+2y=2403x + 2y = 240. Substituting 240240 for 3x+2y3x + 2y in the weight expression shows that the weight of the load at 80%80\% capacity is 15×240=3,60015 \times 240 = 3,600 pounds. To find the maximum capacity, we set up the equation 0.80×C=3,6000.80 \times C = 3,600, where CC is the maximum payload capacity. Solving for CC yields C=3,6000.80=4,500C = \frac{3,600}{0.80} = 4,500 pounds.

Adım Adım Çözüm

1
Write the expression for the total weight of the bags in terms of xx and yy.
Total weight W=45x+30yW = 45x + 30y pounds.
Each of the xx bags of fertilizer weighs 4545 pounds and each of the yy bags of compost weighs 3030 pounds.
2
Relate the total weight expression to the given equation for 80%80\% capacity.
45x+30y=15(3x+2y)45x + 30y = 15(3x + 2y)
Factoring out the greatest common divisor of 4545 and 3030, which is 1515, allows us to write the weight expression in terms of the left-hand side of the given equation 3x+2y=2403x + 2y = 240.
3
Calculate the actual weight of the load when the truck is at 80%80\% capacity.
W=15×240=3,600W = 15 \times 240 = 3,600 pounds.
Since the relationship at 80%80\% capacity is 3x+2y=2403x + 2y = 240, we can substitute 240240 for 3x+2y3x + 2y in the factored weight expression.
4
Calculate the maximum payload capacity of the truck.
Maximum capacity C=3,6000.80=4,500C = \frac{3,600}{0.80} = 4,500 pounds.
The weight of 3,6003,600 pounds represents 80%80\% of the maximum payload capacity, so dividing the actual weight by 0.800.80 gives the total capacity.

Anahtar Kavram

Translating a real-world scenario into a linear equation and interpreting its coefficients and constants to solve for unknown quantities.
Soru 27Soru

In the xyxy-plane, the graph of the linear equation ax+by=cax + by = c, where aa, bb, and cc are constants, has a slope of 23\frac{2}{3} and passes through the point (6,5)(6, 5). If a+b=5a + b = 5, what is the value of cc?

Cevabı ve açıklamayı göster

Cevap: 15

Cevap

15
Rearranging the linear equation ax+by=cax + by = c into slope-intercept form y=abx+cby = -\frac{a}{b}x + \frac{c}{b} shows the slope is ab-\frac{a}{b}. Setting ab=23-\frac{a}{b} = \frac{2}{3} gives 2b=3a2b = -3a, or b=1.5ab = -1.5a. Substituting this into a+b=5a + b = 5 yields a1.5a=5a - 1.5a = 5, which simplifies to 0.5a=5-0.5a = 5, so a=10a = -10. This means b=1.5(10)=15b = -1.5(-10) = 15. Substituting the values of a=10a = -10 and b=15b = 15 along with the point (6,5)(6, 5) into the equation ax+by=cax + by = c yields (10)(6)+(15)(5)=15(-10)(6) + (15)(5) = 15, so the value of cc is 1515.

Adım Adım Çözüm

1
Rewrite the standard form equation ax+by=cax + by = c in slope-intercept form.
y=abx+cby = -\frac{a}{b}x + \frac{c}{b}
This allows the identification of the slope of the line in terms of the coefficients aa and bb.
2
Set the slope expression equal to the given slope of 23\frac{2}{3} and solve for bb in terms of aa.
b=1.5ab = -1.5a
The slope of the line is ab-\frac{a}{b}, so ab=23    2b=3a    b=1.5a-\frac{a}{b} = \frac{2}{3} \implies 2b = -3a \implies b = -1.5a.
3
Substitute b=1.5ab = -1.5a into the given equation a+b=5a + b = 5 and solve for aa, then find bb.
a=10a = -10 and b=15b = 15
Substituting gives a1.5a=5    0.5a=5    a=10a - 1.5a = 5 \implies -0.5a = 5 \implies a = -10. Substituting a=10a = -10 back into the relationship gives b=1.5(10)=15b = -1.5(-10) = 15.
4
Substitute a=10a = -10, b=15b = 15, and the point (6,5)(6, 5) into the equation ax+by=cax + by = c and solve for cc.
c=15c = 15
(10)(6)+(15)(5)=c    60+75=15    c=15(-10)(6) + (15)(5) = c \implies -60 + 75 = 15 \implies c = 15.

Anahtar Kavram

Linear Equations in Two Variables
Soru 28Soru

The table below shows several values of xx and their corresponding values of yy for a linear relationship, where pp and kk are constants.

xxyy
pp44
p+2p + 21010
2p+32p + 3kk

If k=25k = 25, what is the value of pp?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

4
The correct answer is 4. A linear relationship has a constant rate of change (slope). Calculating the slope mm from the first two points (p,4)(p, 4) and (p+2,10)(p + 2, 10) gives m=104(p+2)p=3m = \frac{10 - 4}{(p + 2) - p} = 3. The equation of the line is y4=3(xp)y - 4 = 3(x - p), which simplifies to y=3x3p+4y = 3x - 3p + 4. Substituting the third point (2p+3,25)(2p + 3, 25) into this equation gives 25=3(2p+3)3p+425 = 3(2p + 3) - 3p + 4, which simplifies to 25=3p+1325 = 3p + 13. Solving for pp yields p=4p = 4.

Adım Adım Çözüm

1
Determine the slope of the linear relationship using the first two points from the table, (p,4)(p, 4) and (p+2,10)(p + 2, 10).
The slope is m=3m = 3.
A linear relationship has a constant rate of change (slope), which is the change in yy divided by the change in xx: m=104(p+2)p=62=3m = \frac{10 - 4}{(p + 2) - p} = \frac{6}{2} = 3.
2
Write the equation of the line using the point-slope form with the point (p,4)(p, 4) and slope m=3m = 3.
y=3x3p+4y = 3x - 3p + 4
Expressing the linear relationship as an equation allows us to find the relationship between the parameters pp and kk: y4=3(xp)y=3x3p+4y - 4 = 3(x - p) \Rightarrow y = 3x - 3p + 4.
3
Substitute the third point (2p+3,k)(2p + 3, k) into the linear equation and simplify the expression to solve for kk in terms of pp.
k=3p+13k = 3p + 13
Since the point (2p+3,k)(2p + 3, k) lies on the line, its coordinates must satisfy the line's equation: k=3(2p+3)3p+4k=6p+93p+4k=3p+13k = 3(2p + 3) - 3p + 4 \Rightarrow k = 6p + 9 - 3p + 4 \Rightarrow k = 3p + 13.
4
Substitute the given value k=25k = 25 into the equation k=3p+13k = 3p + 13 and solve for pp.
p=4p = 4
This isolates the variable pp to find its numerical value under the specified conditions: 25=3p+1312=3pp=425 = 3p + 13 \Rightarrow 12 = 3p \Rightarrow p = 4.

Anahtar Kavram

Finding the equation of a line from a table of values and using substitution to solve for unknown parameters in a linear relationship.

Alternatif Yöntem

An alternative method is to use the property that the slope between any two points on a line is constant. We can equate the slope between (p,4)(p, 4) and (p+2,10)(p + 2, 10) to the slope between (p,4)(p, 4) and (2p+3,25)(2p + 3, 25). This gives the equation 104(p+2)p=254(2p+3)p\frac{10 - 4}{(p + 2) - p} = \frac{25 - 4}{(2p + 3) - p}, which simplifies to 3=21p+33 = \frac{21}{p + 3}. Solving this equation yields 3(p+3)=213(p + 3) = 21, so p+3=7p + 3 = 7, which gives p=4p = 4.
Tahmini Süre:2m 0s
Soru 29Soru

A line has the equation y=mx+ky = mx + k in the xyxy-plane, where mm and kk are constants. If the line passes through the points (2,p)(2, p) and (p,4)(p, -4), and has a yy-intercept of (0,3p)(0, 3p) for some constant p>0p > 0, what is the slope, mm, of the line?

Cevabı ve açıklamayı göster

Cevap: 4-4

Cevap

4-4
The correct answer is 4-4. Substituting the yy-intercept (0,3p)(0, 3p) into the slope-intercept form equation y=mx+ky = mx + k gives k=3pk = 3p. Substituting the point (2,p)(2, p) into y=mx+3py = mx + 3p gives p=2m+3pp = 2m + 3p, which simplifies to m=pm = -p. Then, substituting the point (p,4)(p, -4) into y=mx+3py = mx + 3p gives 4=mp+3p-4 = mp + 3p. Replacing mm with p-p results in 4=p2+3p-4 = -p^2 + 3p, which can be rearranged to the quadratic equation p23p4=0p^2 - 3p - 4 = 0. Factoring this equation yields (p4)(p+1)=0(p - 4)(p + 1) = 0. Since p>0p > 0, the only valid solution is p=4p = 4. Substituting p=4p = 4 back into the expression for mm gives the slope m=4m = -4.

Adım Adım Çözüm

1
Determine the y-intercept constant kk in terms of pp.
k=3pk = 3p
The equation of the line is y=mx+ky = mx + k. Since the yy-intercept is given as (0,3p)(0, 3p), substituting x=0x = 0 and y=3py = 3p gives k=3pk = 3p.
2
Find the relationship between the slope mm and the parameter pp.
m=pm = -p
Since the line passes through (2,p)(2, p), we substitute these coordinates into the equation y=mx+3py = mx + 3p to get p=2m+3pp = 2m + 3p. Solving for mm yields 2m=2p2m = -2p, or m=pm = -p.
3
Substitute the point (p,4)(p, -4) into the linear equation and solve the resulting quadratic equation for pp.
p=4p = 4
Substituting the coordinates of (p,4)(p, -4) into y=mx+3py = mx + 3p gives 4=mp+3p-4 = mp + 3p. Substituting m=pm = -p gives 4=p2+3p-4 = -p^2 + 3p, which simplifies to the quadratic equation p23p4=0p^2 - 3p - 4 = 0. Factoring this equation gives (p4)(p+1)=0(p - 4)(p + 1) = 0. Since p>0p > 0, we must have p=4p = 4.
4
Calculate the slope mm.
m=4m = -4
Since m=pm = -p and we found p=4p = 4, the slope is m=4m = -4.

Anahtar Kavram

Determining the slope of a line from given points and a parameter in a linear equation.

Alternatif Yöntem

Instead of finding the equation of the line first, the slope mm can be expressed directly using the slope formula between the points (2,p)(2, p) and (p,4)(p, -4): m=4pp2m = \frac{-4 - p}{p - 2}. Since the slope of the line connecting (0,3p)(0, 3p) and (2,p)(2, p) is also m=p3p20=pm = \frac{p - 3p}{2 - 0} = -p, we can set these two expressions for mm equal to each other: p=4pp2-p = \frac{-4 - p}{p - 2}. Multiplying both sides by p2p - 2 yields p(p2)=4p    p2+2p=4p-p(p - 2) = -4 - p \implies -p^2 + 2p = -4 - p. Rearranging the terms gives the quadratic equation p23p4=0p^2 - 3p - 4 = 0. Factoring gives (p4)(p+1)=0(p - 4)(p + 1) = 0. Since p>0p > 0, we find p=4p = 4, and the slope is m=p=4m = -p = -4.
Tahmini Süre:2m 0s
Soru 30Soru

In the xyxy-plane, the graph of the linear equation ax+by=cax + by = c, where aa, bb, and cc are constants, has the property that the value of yy decreases by 33 for every increase of 55 in the value of xx. If the graph of this equation passes through the point (4,2)(4, -2) and a=6a = 6, what is the value of cc?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The correct answer is 44.
The correct answer is 44. The slope of the line described is m=ΔyΔx=35=0.6m = \frac{\Delta y}{\Delta x} = \frac{-3}{5} = -0.6. Rearranging ax+by=cax + by = c into slope-intercept form y=abx+cby = -\frac{a}{b}x + \frac{c}{b} shows that the slope is ab-\frac{a}{b}. Setting these equal gives ab=35    ab=35-\frac{a}{b} = -\frac{3}{5} \implies \frac{a}{b} = \frac{3}{5}. Since a=6a = 6, we find b=10b = 10. Substituting a=6a = 6, b=10b = 10, and the coordinates of the point (4,2)(4, -2) into the original equation yields 6(4)+10(2)=46(4) + 10(-2) = 4.

Adım Adım Çözüm

1
Determine the slope of the line from the described relationship between xx and yy.
The slope mm of the line is 35-\frac{3}{5}.
The slope represents the change in yy divided by the change in xx. Since yy decreases by 33 (Δy=3\Delta y = -3) for every increase of 55 in xx (Δx=5\Delta x = 5), the slope is m=ΔyΔx=35m = \frac{\Delta y}{\Delta x} = -\frac{3}{5}.
2
Express the slope of the line in terms of the coefficients from the standard form equation ax+by=cax + by = c.
The slope of the line is ab-\frac{a}{b}.
Rewriting the equation ax+by=cax + by = c in slope-intercept form gives by=ax+c    y=abx+cbby = -ax + c \implies y = -\frac{a}{b}x + \frac{c}{b}. The coefficient of xx is the slope, so m=abm = -\frac{a}{b}.
3
Equate the two expressions for the slope and solve for bb using the given value of a=6a = 6.
b=10b = 10
Setting ab=35-\frac{a}{b} = -\frac{3}{5} gives ab=35\frac{a}{b} = \frac{3}{5}. Substituting a=6a = 6 yields 6b=35\frac{6}{b} = \frac{3}{5}, which simplifies to 3b=303b = 30, so b=10b = 10.
4
Substitute the point (4,2)(4, -2) and the values of aa and bb into the equation ax+by=cax + by = c to solve for cc.
c=4c = 4
Substituting a=6a = 6, b=10b = 10, x=4x = 4, and y=2y = -2 into ax+by=cax + by = c gives 6(4)+10(2)=c    2420=c    c=46(4) + 10(-2) = c \implies 24 - 20 = c \implies c = 4.

Anahtar Kavram

Linear Equations in Two Variables
Soru 31Soru

A water utility company charges a flat monthly connection fee plus a constant rate per gallon of water consumed. In a certain month, a household that consumed 2,8002,800 gallons of water was billed a total of 62.0062.00 dollars, and a household that consumed 4,5004,500 gallons of water was billed a total of 87.5087.50 dollars. What is the flat monthly connection fee, in dollars, charged by the water utility company?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

The flat monthly connection fee charged by the water utility company is 20 dollars.
The flat monthly connection fee is 20 dollars. A linear relationship can be modeled by the equation y=mx+by = mx + b, where xx represents the water consumed in gallons, yy represents the total bill in dollars, mm represents the rate per gallon, and bb represents the flat monthly connection fee. Using the data for the two households, we get the points (2800,62)(2800, 62) and (4500,87.5)(4500, 87.5). The rate per gallon is the slope of the line passing through these points: m=87.56245002800=25.51700=0.015m = \frac{87.5 - 62}{4500 - 2800} = \frac{25.5}{1700} = 0.015 dollars per gallon. Substituting this slope and the point (2800,62)(2800, 62) into the equation gives 62=0.015(2800)+b62 = 0.015(2800) + b, which simplifies to 62=42+b62 = 42 + b. Solving for bb yields 2020 dollars.

Adım Adım Çözüm

1
Define the linear relationship using the variables xx for water consumed in gallons and yy for the total bill in dollars.
The relationship can be written as y=mx+by = mx + b, where mm represents the cost per gallon of water and bb represents the flat monthly connection fee.
This establishes the linear framework needed to solve for the unknown constants using the provided data points.
2
Calculate the constant rate of change (slope mm) using the coordinates of the two households: (2800,62)(2800, 62) and (4500,87.5)(4500, 87.5).
m=87.56245002800=25.51700=0.015m = \frac{87.5 - 62}{4500 - 2800} = \frac{25.5}{1700} = 0.015 dollars per gallon.
The slope of a linear function represents the constant rate of change between the two variables.
3
Substitute the calculated slope m=0.015m = 0.015 and the point (2800,62)(2800, 62) into the equation y=mx+by = mx + b to find the flat fee bb.
62=0.015(2800)+b    62=42+b    b=2062 = 0.015(2800) + b \implies 62 = 42 + b \implies b = 20.
The flat monthly connection fee corresponds to the vertical intercept (yy-intercept) of the linear equation.

Anahtar Kavram

Linear Equations in Two Variables
Soru 32Soru

In the xyxy-plane, a line has a yy-intercept of (0,d)(0, d) and passes through the point (4,d3)(4, d - 3), where dd is a constant. If the line also passes through the point (12,k)(12, k), which of the following expressions represents the value of kk?

Cevabı ve açıklamayı göster

Cevap: d9d - 9

Cevap

d9d - 9
The correct answer represents the value of kk as d9d - 9. The slope mm of the line passing through (0,d)(0, d) and (4,d3)(4, d - 3) is (d3)d40=34\frac{(d - 3) - d}{4 - 0} = -\frac{3}{4}. Using the yy-intercept (0,d)(0, d), the equation of the line is y=34x+dy = -\frac{3}{4}x + d. Substituting the point (12,k)(12, k) gives k=34(12)+d=d9k = -\frac{3}{4}(12) + d = d - 9.

Adım Adım Çözüm

1
Calculate the slope of the line using the points (0,d)(0, d) and (4,d3)(4, d - 3).
m=34m = -\frac{3}{4}
The slope formula is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the given coordinates yields m=(d3)d40=34m = \frac{(d - 3) - d}{4 - 0} = -\frac{3}{4}.
2
Write the equation of the line using the slope-intercept form.
y=34x+dy = -\frac{3}{4}x + d
Since the line's yy-intercept is (0,d)(0, d), the constant bb in the slope-intercept equation y=mx+by = mx + b is equal to dd.
3
Substitute the point (12,k)(12, k) into the equation of the line to solve for kk.
k=d9k = d - 9
Substituting x=12x = 12 and y=ky = k into y=34x+dy = -\frac{3}{4}x + d gives k=34(12)+d=9+dk = -\frac{3}{4}(12) + d = -9 + d, which simplifies to d9d - 9.

Anahtar Kavram

Determining the equation and coordinates of a line in the coordinate plane given its slope and intercepts.
Soru 33Soru

In the xyxy-plane, the graph of the linear equation 3x+5y=c3x + 5y = c, where cc is a constant, passes through the point (4,3)(4, 3). What is the xx-coordinate of the point on this graph where the yy-coordinate is 3-3?

Cevabı ve açıklamayı göster

Cevap: 14

Cevap

The correct answer is 14.
To find the correct answer, first substitute the given point (4,3)(4, 3) into the equation 3x+5y=c3x + 5y = c to determine the value of the constant cc: 3(4)+5(3)=12+15=273(4) + 5(3) = 12 + 15 = 27. Thus, the equation is 3x+5y=273x + 5y = 27. Next, substitute 3-3 for yy in this equation to find the corresponding xx-coordinate: 3x+5(3)=27    3x15=273x + 5(-3) = 27 \implies 3x - 15 = 27. Adding 1515 to both sides gives 3x=423x = 42, and dividing by 33 yields x=14x = 14.

Adım Adım Çözüm

1
Substitute the point (4,3)(4, 3) into the equation 3x+5y=c3x + 5y = c to solve for cc.
c=27c = 27
Since the point lies on the graph of the equation, its coordinates must satisfy the equation.
2
Substitute y=3y = -3 and c=27c = 27 into the equation 3x+5y=c3x + 5y = c.
3x15=273x - 15 = 27
We want to find the xx-coordinate of the point on the line when the yy-coordinate is 3-3.
3
Solve the equation 3x15=273x - 15 = 27 for xx.
x=14x = 14
Isolating xx gives the xx-coordinate of the point.

Anahtar Kavram

Using a known point on a line to find a constant coefficient or constant term, and using the resulting equation to find other coordinates.

Alternatif Yöntem

Alternatively, you can write the equation in slope-intercept form. Solving 3x+5y=c3x + 5y = c for yy gives y=35x+c5y = -\frac{3}{5}x + \frac{c}{5}. The slope of the line is 35-\frac{3}{5}. Since the slope is constant, the change in yy divided by the change in xx between (4,3)(4, 3) and (x,3)(x, -3) is equal to the slope: 33x4=35    6x4=35\frac{-3 - 3}{x - 4} = -\frac{3}{5} \implies \frac{-6}{x - 4} = -\frac{3}{5}. Cross-multiplying gives 30=3(x4)    10=x4    x=14-30 = -3(x - 4) \implies 10 = x - 4 \implies x = 14.
Tahmini Süre:1m 30s
Soru 34Soru

In the xyxy-plane, the graph of the linear equation y4=m(x6)y - 4 = m(x - 6), where mm is a constant, has a yy-intercept of (0,7)(0, 7). What is the xx-coordinate of the xx-intercept of the line?

Cevabı ve açıklamayı göster

Cevap: 14

Cevap

The correct answer is 14. This is the x-coordinate of the point where the line crosses the x-axis, which is (14, 0).
To find the value of mm, substitute the y-intercept (0,7)(0, 7) into the equation: 74=m(06)7 - 4 = m(0 - 6), which simplifies to 3=6m3 = -6m, so m=12m = -\frac{1}{2}. The equation of the line is y4=12(x6)y - 4 = -\frac{1}{2}(x - 6). The x-intercept occurs when y=0y = 0. Substituting y=0y = 0 gives 4=12(x6)-4 = -\frac{1}{2}(x - 6), which simplifies to 8=x68 = x - 6, so x=14x = 14.

Adım Adım Çözüm

1
Substitute the y-intercept (0,7)(0, 7) into the given equation to solve for the constant mm.
74=m(06)    3=6m    m=127 - 4 = m(0 - 6) \implies 3 = -6m \implies m = -\frac{1}{2}
The y-intercept point (0,7)(0, 7) must satisfy the equation of the line, allowing us to find the slope mm.
2
Write the linear equation using the calculated value of mm.
y4=12(x6)y - 4 = -\frac{1}{2}(x - 6)
Knowing the slope allows us to write the complete linear equation in point-slope form.
3
Find the x-intercept of the line by setting y=0y = 0 and solving for xx.
04=12(x6)    4=12(x6)    8=x6    x=140 - 4 = -\frac{1}{2}(x - 6) \implies -4 = -\frac{1}{2}(x - 6) \implies 8 = x - 6 \implies x = 14
The x-intercept is the point on the line where the y-coordinate is equal to 0.

Anahtar Kavram

Finding the intercepts and slope of a linear equation in two variables.

Alternatif Yöntem

Alternatively, write the equation in slope-intercept form y=mx+by = mx + b. Since the y-intercept is (0,7)(0, 7), we have b=7b = 7, so the equation is y=mx+7y = mx + 7. Since the line passes through the point (6,4)(6, 4) (determined by the point-slope form y4=m(x6)y - 4 = m(x - 6)), substitute this point into the equation: 4=m(6)+7    3=6m    m=124 = m(6) + 7 \implies -3 = 6m \implies m = -\frac{1}{2}. Thus, the equation is y=12x+7y = -\frac{1}{2}x + 7. Setting y=0y = 0 for the x-intercept gives 0=12x+7    12x=7    x=140 = -\frac{1}{2}x + 7 \implies \frac{1}{2}x = 7 \implies x = 14.
Tahmini Süre:1m 30s
Soru 35Soru

A manufacturer plans to produce two models of smartphones: Model X and Model Y. The assembly of each Model X smartphone requires 2.52.5 hours, and the assembly of each Model Y smartphone requires 44 hours. A total of 800800 hours of assembly time is allocated for producing these two models. If the manufacturer produces 120120 Model X smartphones, what is the maximum number of Model Y smartphones that can be produced using the remaining allocated assembly time?

Cevabı ve açıklamayı göster

Cevap: 125

Cevap

The maximum number of Model Y smartphones that can be produced is 125.
The correct answer is the value that satisfies the linear relation under the given constraints. Setting up the equation 2.5x+4y=8002.5x + 4y = 800 and substituting 120120 for xx results in 300+4y=800300 + 4y = 800. Subtracting 300300 from both sides yields 4y=5004y = 500, and dividing by 44 gives 125125 Model Y smartphones.

Adım Adım Çözüm

1
Set up a linear equation representing the total assembly time.
2.5x+4y=8002.5x + 4y = 800, where xx is the number of Model X smartphones and yy is the number of Model Y smartphones.
The total assembly time is the sum of the time spent on Model X (2.52.5 hours per phone) and Model Y (44 hours per phone), which must equal the allocated 800800 hours.
2
Substitute the given number of Model X smartphones into the equation.
2.5(120)+4y=8002.5(120) + 4y = 800, which simplifies to 300+4y=800300 + 4y = 800.
The problem states that the manufacturer produces 120120 Model X smartphones.
3
Isolate the variable representing Model Y smartphones to find its value.
4y=5004y = 500, which simplifies to y=125y = 125.
Subtracting 300300 from both sides of the equation and then dividing by 44 isolates the variable yy.

Anahtar Kavram

Linear Equations in Two Variables
Tahmini Süre:1m 30s
Soru 36Soru

During a chemistry experiment, the temperature of a liquid increases at a constant rate. The temperature of the liquid is 24C24^\circ\text{C} at 55 minutes after the experiment starts, and 48C48^\circ\text{C} at 1515 minutes after the experiment starts. The temperature TT, in degrees Celsius, of the liquid tt minutes after the experiment starts can be modeled by the equation T=mt+bT = mt + b, where mm and bb are constants. What is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 12

Cevap

12
The correct answer is 12. By translating the given information into two points on the line, (5,24)(5, 24) and (15,48)(15, 48), we can find the slope m=4824155=2.4m = \frac{48 - 24}{15 - 5} = 2.4. Substituting this slope and the point (5,24)(5, 24) into T=mt+bT = mt + b yields 24=2.4(5)+b24 = 2.4(5) + b, which simplifies to 24=12+b24 = 12 + b. Solving for bb gives b=12b = 12.

Adım Adım Çözüm

1
Identify the data points representing the relationship between time and temperature.
The two data points are (t1,T1)=(5,24)(t_1, T_1) = (5, 24) and (t2,T2)=(15,48)(t_2, T_2) = (15, 48).
These points represent coordinates (t,T)(t, T) on the line representing the temperature over time.
2
Calculate the slope mm of the linear equation.
m=4824155=2410=2.4m = \frac{48 - 24}{15 - 5} = \frac{24}{10} = 2.4
The slope represents the constant rate of temperature increase per minute.
3
Substitute the slope mm and the coordinates of one point into the equation T=mt+bT = mt + b to solve for the y-intercept bb.
24=2.4(5)+b    24=12+b    b=1224 = 2.4(5) + b \implies 24 = 12 + b \implies b = 12
This determines the value of the constant bb, which corresponds to the initial temperature of the liquid.

Anahtar Kavram

Determining the y-intercept of a linear model in two variables given two points.
Soru 37Soru

The graph of the equation ax+by=24ax + by = 24, where aa and bb are constants, is a line in the xyxy-plane. If this line passes through the points (2,9)(2, 9) and (6,3)(6, 3), what is the value of a+ba + b?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

The value of a+ba + b is 55.
Substituting the coordinates of the two points (2,9)(2, 9) and (6,3)(6, 3) into the given linear equation ax+by=24ax + by = 24 yields a system of two equations: 2a+9b=242a + 9b = 24 and 6a+3b=246a + 3b = 24. Simplifying the second equation gives 2a+b=82a + b = 8, which means b=82ab = 8 - 2a. Substituting this expression for bb into the first equation yields 2a+9(82a)=242a + 9(8 - 2a) = 24, which simplifies to 16a=48-16a = -48, or a=3a = 3. Plugging a=3a = 3 back into b=82ab = 8 - 2a gives b=2b = 2. Thus, the value of a+ba + b is 3+2=53 + 2 = 5.

Adım Adım Çözüm

1
Substitute the point (2,9)(2, 9) into the equation ax+by=24ax + by = 24.
2a+9b=242a + 9b = 24
Since the line passes through the point (2,9)(2, 9), the coordinates must satisfy the equation of the line.
2
Substitute the point (6,3)(6, 3) into the equation ax+by=24ax + by = 24.
6a+3b=246a + 3b = 24
Since the line passes through the point (6,3)(6, 3), the coordinates must satisfy the equation of the line.
3
Solve the system of equations for aa and bb.
a=3a = 3 and b=2b = 2
To find the values of the constants aa and bb, we solve the linear system: (1) 2a+9b=242a + 9b = 24 and (2) 6a+3b=246a + 3b = 24. Dividing the second equation by 3 gives 2a+b=82a + b = 8, or b=82ab = 8 - 2a. Substituting this into the first equation gives 2a+9(82a)=24    2a+7218a=24    16a=48    a=32a + 9(8 - 2a) = 24 \implies 2a + 72 - 18a = 24 \implies -16a = -48 \implies a = 3. Then, b=82(3)=2b = 8 - 2(3) = 2.
4
Add the values of aa and bb.
a+b=5a + b = 5
The question asks for the value of a+ba + b.

Anahtar Kavram

Solving systems of linear equations derived from coordinate substitution in a two-variable linear equation.
Tahmini Süre:1m 30s
Soru 38Soru

A solar power system stores electricity in a battery at a constant rate during the day. The total amount of energy in the battery, in kilowatt-hours (kWh), is a linear function of the number of hours after sunrise. Exactly 33 hours after sunrise, the battery contains 1414 kWh of energy, and exactly 77 hours after sunrise, it contains 2626 kWh of energy. If the battery's maximum capacity is 3535 kWh, how many hours after sunrise will it take for the battery to be fully charged?

Cevabı ve açıklamayı göster

Cevap: 10

Cevap

10
To find the number of hours after sunrise it takes to fully charge the battery to 35 kWh, we first determine the constant rate of energy storage. The rate of change is given by the difference in energy divided by the difference in hours: 261473=124=3\frac{26 - 14}{7 - 3} = \frac{12}{4} = 3 kWh per hour. The relationship between energy EE and hours hh can be written as E=3h+bE = 3h + b. Substituting the known point (3,14)(3, 14) gives 14=3(3)+b14 = 3(3) + b, which simplifies to b=5b = 5. Thus, the linear equation representing this relationship is E=3h+5E = 3h + 5. To find the time when the battery is fully charged to 3535 kWh, set E=35E = 35 in the equation: 35=3h+535 = 3h + 5. Subtracting 5 from both sides yields 30=3h30 = 3h, and dividing by 3 gives h=10h = 10 hours.

Adım Adım Çözüm

1
Calculate the rate of energy storage per hour.
3 kWh per hour
Since the energy increases at a constant rate, the rate is the change in energy divided by the change in time: 261473=3\frac{26 - 14}{7 - 3} = 3.
2
Determine the initial energy stored at sunrise.
5 kWh
Using the rate of 3 kWh per hour and the fact that the battery had 14 kWh at 3 hours, we subtract the energy gained in those 3 hours: 143(3)=514 - 3(3) = 5.
3
Set up the linear equation and solve for the time when the battery reaches 35 kWh.
10 hours
The linear relationship is E=3h+5E = 3h + 5. Setting E=35E = 35 gives 35=3h+535 = 3h + 5. Subtracting 5 from both sides gives 30=3h30 = 3h, which simplifies to h=10h = 10.

Anahtar Kavram

Linear Equations in Two Variables
Soru 39Soru

In the xyxy-plane, the graph of the linear equation 3x+by=363x + by = 36, where bb is a constant, is a line with a slope of 0.75-0.75. What is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The value of bb is 44.
The linear equation 3x+by=363x + by = 36 can be rewritten in slope-intercept form by subtracting 3x3x from both sides to get by=3x+36by = -3x + 36, and then dividing all terms by bb to get y=3bx+36by = -\frac{3}{b}x + \frac{36}{b}. The slope of this line is the coefficient of xx, which is 3b-\frac{3}{b}. Setting this equal to the given slope of 0.75-0.75 (or 34-\frac{3}{4}) gives 3b=34-\frac{3}{b} = -\frac{3}{4}. Solving for bb yields b=4b = 4.

Adım Adım Çözüm

1
Express the given linear equation in slope-intercept form.
y=3bx+36by = -\frac{3}{b}x + \frac{36}{b}
To identify the slope of the line in terms of the constant bb, we rewrite the equation 3x+by=363x + by = 36 in the form y=mx+dy = mx + d.
2
Equate the expression for the slope to the given slope value.
3b=0.75-\frac{3}{b} = -0.75
The coefficient of xx in the slope-intercept form represents the slope of the line, which is given as 0.75-0.75.
3
Solve the equation for bb.
b=4b = 4
Multiply both sides of the equation by 1-1 to get 3b=0.75\frac{3}{b} = 0.75. Since 0.75=340.75 = \frac{3}{4}, we have 3b=34\frac{3}{b} = \frac{3}{4}, which gives b=4b = 4.

Anahtar Kavram

Converting a linear equation from standard form to slope-intercept form to determine its slope.
Tahmini Süre:1m 30s
Soru 40Soru

In the xyxy-plane, the graph of the linear equation y4=m(x+2)y - 4 = m(x + 2) contains the point (6,8)(6, 8), where mm is a constant. What is the value of the xx-intercept of the line?

Cevabı ve açıklamayı göster

Cevap: -10

Cevap

-10
The correct answer is 10-10. By substituting the point (6,8)(6, 8) into the equation y4=m(x+2)y - 4 = m(x + 2), we obtain 84=m(6+2)8 - 4 = m(6 + 2), which simplifies to 4=8m4 = 8m, giving m=0.5m = 0.5. Using this value of mm, the equation of the line is y4=0.5(x+2)y - 4 = 0.5(x + 2). The xx-intercept is the value of xx when y=0y = 0. Substituting 00 for yy gives 4=0.5(x+2)-4 = 0.5(x + 2), which simplifies to 8=x+2-8 = x + 2. Solving for xx gives x=10x = -10.

Adım Adım Çözüm

1
Substitute the given point (6,8)(6, 8) into the equation to find the value of the constant mm.
84=m(6+2)4=8mm=0.58 - 4 = m(6 + 2) \Rightarrow 4 = 8m \Rightarrow m = 0.5
Since the line passes through the point (6,8)(6, 8), these coordinates must satisfy the equation.
2
Write the completed equation of the line using the value of mm.
y4=0.5(x+2)y - 4 = 0.5(x + 2)
Substituting m=0.5m = 0.5 back into the original point-slope equation gives the specific line.
3
Find the xx-intercept by setting y=0y = 0 and solving for xx.
04=0.5(x+2)4=0.5x+15=0.5xx=100 - 4 = 0.5(x + 2) \Rightarrow -4 = 0.5x + 1 \Rightarrow -5 = 0.5x \Rightarrow x = -10
The xx-intercept of a graph is the point where the graph crosses the xx-axis, which occurs where y=0y = 0.

Anahtar Kavram

Finding the intercepts and slope of a linear equation in two variables
ÖncekiSayfa 2 / 3Sonraki