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Question 521Question

A municipal solar power facility distributes its total generating capacity among three sectors: residential, commercial, and municipal. The residential sector is allocated 715\frac{7}{15} of the total capacity, and the commercial sector is allocated 36%36\% of the total capacity. The remaining 2626 megawatts (MW) of capacity is allocated to municipal buildings. What is the total generating capacity, in megawatts, of the facility?

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Answer: 150

Answer

The total generating capacity of the facility is 150 megawatts.
The residential portion (715\frac{7}{15}) and commercial portion (36%=92536\% = \frac{9}{25}) combine to equal 6275\frac{62}{75} of the total capacity. The municipal portion makes up the remaining 1375\frac{13}{75} of the total, which is given as 2626 MW. Setting 1375T=26\frac{13}{75} T = 26 and solving yields T=150T = 150 MW.

Step-by-Step Solution

1
Convert the commercial percentage into a simplified fraction.
36%=36100=92536\% = \frac{36}{100} = \frac{9}{25}
Converting all proportions to fractions allows for direct operations.
2
Find the combined fraction of capacity allocated to residential and commercial sectors.
715+925=3575+2775=6275\frac{7}{15} + \frac{9}{25} = \frac{35}{75} + \frac{27}{75} = \frac{62}{75}
Finding a common denominator (7575) allows adding the two fractional parts.
3
Find the fraction corresponding to the remaining municipal portion.
16275=13751 - \frac{62}{75} = \frac{13}{75}
Subtracting the allocated fraction from 11 yields the unallocated fractional portion.
4
Calculate the total capacity by setting up a linear equation.
1375×Total=26    Total=26×7513=150\frac{13}{75} \times \text{Total} = 26 \implies \text{Total} = 26 \times \frac{75}{13} = 150
Multiplying the known remaining value by the reciprocal of its fraction gives the whole total.

Key Concept

Combining fractions and percentages to find an unknown total amount.
Estimated Time:1m 30s
Question 522Question

An engineering formula used to calculate a structural load index is given by L=a3b2c3/4a2+12bL = \frac{a^3 b^{-2} - c^{3/4}}{a^2 + 12b}. What is the value of LL when a=2a = -2, b=13b = \frac{1}{3}, and c=16c = 16?

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Answer: -10

Answer

The value of the expression is -10.
Substituting the values into the formula gives L=(2)3(1/3)2163/4(2)2+12(1/3)=8984+4=7288=808=10L = \frac{(-2)^3 \cdot (1/3)^{-2} - 16^{3/4}}{(-2)^2 + 12(1/3)} = \frac{-8 \cdot 9 - 8}{4 + 4} = \frac{-72 - 8}{8} = \frac{-80}{8} = -10.

Step-by-Step Solution

1
Evaluate the terms in the numerator containing powers and negative exponents
a3=8a^3 = -8, b2=9b^{-2} = 9, and c3/4=8c^{3/4} = 8
Negative bases raised to odd powers remain negative: (2)3=8(-2)^3 = -8. A negative exponent represents the reciprocal raised to a positive exponent: (1/3)2=32=9(1/3)^{-2} = 3^2 = 9. Fractional exponent c3/4=(164)3=23=8c^{3/4} = (\sqrt[4]{16})^3 = 2^3 = 8.
2
Compute the full numerator
728=80-72 - 8 = -80
Multiply a3a^3 and b2b^{-2} to get (8)(9)=72(-8)(9) = -72, then subtract c3/4=8c^{3/4} = 8.
3
Evaluate the denominator
(2)2+12(13)=4+4=8(-2)^2 + 12\left(\frac{1}{3}\right) = 4 + 4 = 8
Squaring a negative number yields a positive value: (2)2=4(-2)^2 = 4. Multiplying 1213=412 \cdot \frac{1}{3} = 4.
4
Divide the numerator by the denominator
808=10\frac{-80}{8} = -10
Dividing a negative integer by a positive integer yields a negative result.

Key Concept

Evaluating algebraic expressions involving negative numbers, negative exponents, and rational exponents
Estimated Time:1m 15s
Question 523Question

A box contains 1010 tiles labeled with the integers from 11 through 1010. If 22 tiles are drawn at random without replacement, how many distinct pairs of tiles (where the order of selection does not matter) have a sum that is an odd number?

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Answer: 25

Answer

The total number of distinct pairs with an odd sum is 25.
To obtain an odd sum when adding two integers, one integer must be odd and the other must be even. In the range 11 through 1010, there are 55 odd integers (1,3,5,7,91, 3, 5, 7, 9) and 55 even integers (2,4,6,8,102, 4, 6, 8, 10). To form a pair with an odd sum, one tile must be selected from the 55 odd tiles and one tile must be selected from the 55 even tiles. By the Fundamental Counting Principle, the number of such distinct pairs is 5×5=255 \times 5 = 25.

Step-by-Step Solution

1
Determine the parity condition for an odd sum
One tile must be odd and the other must be even
The sum of two integers is odd if and only if one addend is odd and the other addend is even.
2
Count the number of odd and even options
5 odd tiles and 5 even tiles
Among the integers 11 through 1010, the odd numbers are 1,3,5,7,91, 3, 5, 7, 9 (55 total) and the even numbers are 2,4,6,8,102, 4, 6, 8, 10 (55 total).
3
Apply the Fundamental Counting Principle
5 × 5 = 25 distinct pairs
Selecting one odd tile out of 5 possibilities and one even tile out of 5 possibilities gives 5×5=255 \times 5 = 25 distinct unordered pairs.

Key Concept

Fundamental Counting Principle and Parity of Integers
Estimated Time:1m 0s
Question 524Question

A regional sports club assigns identification codes to all of its members. Each code consists of 11 letter chosen from the set {K,L,M,N}\{K, L, M, N\}, followed by 22 digits chosen from {1,2,3,4,5}\{1, 2, 3, 4, 5\} such that no digit is repeated within a code, followed by 11 symbol chosen from {,#}\{*, \#\}. How many unique identification codes can be created using this system?

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Answer: 160

Answer

The total number of unique identification codes that can be created is 160160.
According to the Fundamental Counting Principle, to find the total number of multi-stage outcomes, multiply the number of choices at each stage. For the letter slot, there are 44 choices. For the two digit slots without repetition, there are 5×4=205 \times 4 = 20 choices. For the symbol slot, there are 22 choices. Multiplying these gives 4×20×2=1604 \times 20 \times 2 = 160 unique identification codes.

Step-by-Step Solution

1
Determine the number of available letter choices for the first slot.
4 options
The set of allowed letters {K,L,M,N}\{K, L, M, N\} contains 4 distinct elements.
2
Calculate the number of permutations for the two-digit section without repetition.
20 options
Choosing 2 distinct digits from 5 options gives 5×4=205 \times 4 = 20 possible outcomes.
3
Determine the number of available symbol choices for the last slot.
2 options
The set of allowed symbols {,#}\{*, \#\} contains 2 elements.
4
Multiply the number of choices for each slot using the Fundamental Counting Principle.
160 unique codes
Total codes = 4×20×2=1604 \times 20 \times 2 = 160.

Key Concept

Fundamental Counting Principle and Permutations without Repetition
Estimated Time:1m 0s
Question 525Question

In July, a company's IT department logged a set of service tickets. Of these tickets, 310\frac{3}{10} were categorized as hardware issues, 45%45\% were categorized as software issues, and the remaining 60 tickets were categorized as network issues. What was the total number of service tickets logged by the IT department in July?

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Answer: 240

Answer

The total number of service tickets logged in July was 240.
Converting 310\frac{3}{10} gives 30%30\%. Combining hardware (30%30\%) and software (45%45\%) issues yields 75%75\% of the total tickets. The network tickets make up the remaining 25%25\% (100%75%100\% - 75\%). Setting 25%25\% of the total equal to 60 tickets gives a total of 600.25=240\frac{60}{0.25} = 240 service tickets.

Step-by-Step Solution

1
Convert the fraction of hardware tickets to a percentage
310=0.30=30%\frac{3}{10} = 0.30 = 30\%
Expressing all portions as percentages enables direct combination.
2
Sum the percentages for hardware and software tickets
30\% + 45\% = 75\%
This determines the combined percentage of the non-network tickets.
3
Determine the remaining percentage corresponding to network tickets
100\% - 75\% = 25\%
The total of all categories must sum to 100%.
4
Calculate the total number of service tickets
600.25=240\frac{60}{0.25} = 240
Dividing the quantity of network tickets by their decimal equivalent of 0.25 gives the total count.

Key Concept

Combining fractions and percentages to solve for an unknown whole amount
Estimated Time:1m 30s
Question 526Question

A fair spinner is divided into 88 congruent sectors numbered 11 through 88. A player spins the spinner twice in succession. How many of the 6464 possible outcomes result in a sum of the two spins that is strictly greater than 1212?

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Answer: 10

Answer

There are 10 outcomes that yield a sum strictly greater than 12.
Systematically listing all ordered pairs (x,y)(x, y) from {1,2,,8}×{1,2,,8}\{1, 2, \dots, 8\} \times \{1, 2, \dots, 8\} such that x+y>12x + y > 12 yields 4 outcomes for sum 13, 3 outcomes for sum 14, 2 outcomes for sum 15, and 1 outcome for sum 16, totaling 10 valid outcomes.

Step-by-Step Solution

1
Determine the acceptable sums for the two spins
The possible sums strictly greater than 12 are 13, 14, 15, and 16.
Since each spin has a maximum value of 8, the maximum possible sum is 8 + 8 = 16.
2
Count the ordered pairs (spin 1, spin 2) for each valid sum
4 outcomes for sum 13, 3 outcomes for sum 14, 2 outcomes for sum 15, and 1 outcome for sum 16.
First and second spins are ordered, so (5,8) and (8,5) represent distinct outcomes.
3
Sum the outcome counts across all valid cases
4 + 3 + 2 + 1 = 10 outcomes.
The sets of outcomes for distinct sums are mutually exclusive.

Key Concept

Basic Probability and Counting Sample Space Outcomes
Estimated Time:1m 15s
Question 527Question

Biophysicists conducted an experiment measuring the action potential conduction velocity (vv, in m/s\text{m/s}) in unmyelinated giant nerve fibers as a function of fiber diameter (dd, in μm\mu\text{m}) at a constant temperature of 20C20^\circ\text{C}. The recorded data is presented in Table 1.

Fiber Diameter (dd, μm\mu\text{m})Conduction Velocity (vv, m/s\text{m/s})
1005.0
2008.0
40014.0
60018.0
90021.0

Based on Table 1, what is the average rate of change in conduction velocity, in m/s\text{m/s} per 100μm100\,\mu\text{m} increase in fiber diameter, over the interval from d=200μmd = 200\,\mu\text{m} to d=600μmd = 600\,\mu\text{m}?

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Answer: 2.5

Answer

The average rate of change in conduction velocity over the specified interval is 2.5m/s per 100μm2.5\,\text{m/s per }100\,\mu\text{m} increase in fiber diameter.
To find the average rate of change in conduction velocity per 100μm100\,\mu\text{m} increase in fiber diameter between d=200μmd = 200\,\mu\text{m} and d=600μmd = 600\,\mu\text{m}, subtract the initial velocity (8.0m/s8.0\,\text{m/s}) from the final velocity (18.0m/s18.0\,\text{m/s}) to get Δv=10.0m/s\Delta v = 10.0\,\text{m/s}. Divide by the change in diameter Δd=600200=400μm\Delta d = 600 - 200 = 400\,\mu\text{m} to obtain 0.025m/s per μm0.025\,\text{m/s per }\mu\text{m}. Multiplying by 100100 yields 2.5m/s per 100μm2.5\,\text{m/s per }100\,\mu\text{m}.

Step-by-Step Solution

1
Locate data points for d=200μmd = 200\,\mu\text{m} and d=600μmd = 600\,\mu\text{m} in Table 1.
At d=200μmd = 200\,\mu\text{m}, v=8.0m/sv = 8.0\,\text{m/s}. At d=600μmd = 600\,\mu\text{m}, v=18.0m/sv = 18.0\,\text{m/s}.
These data points define the boundaries of the interval specified in the question.
2
Calculate the overall changes in velocity (Δv\Delta v) and diameter (Δd\Delta d).
Δv=18.08.0=10.0m/s\Delta v = 18.0 - 8.0 = 10.0\,\text{m/s} and Δd=600200=400μm\Delta d = 600 - 200 = 400\,\mu\text{m}.
Calculating the rate of change requires dividing the change in the dependent variable by the change in the independent variable.
3
Scale the rate of change to a 100μm100\,\mu\text{m} diameter interval.
10.0m/s400μm×100μm=2.5m/s per 100μm\frac{10.0\,\text{m/s}}{400\,\mu\text{m}} \times 100\,\mu\text{m} = 2.5\,\text{m/s per }100\,\mu\text{m}.
The question asks specifically for the rate per 100μm100\,\mu\text{m} increase in diameter.

Key Concept

Calculating average rate of change and trend slopes from quantitative scientific data tables.
Question 528Question

A school library receives a shipment of 1212 new books, consisting of 55 science fiction novels, 44 historical fiction novels, and 33 biography books. A librarian wants to choose 33 books to feature on a display shelf. How many different combinations of 33 books can be formed that contain exactly 22 science fiction novels and 11 biography book?

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Answer: 30

Answer

The total number of combinations containing exactly 2 science fiction novels and 1 biography book is 30.
To find the total number of combinations, first determine the number of ways to choose 22 science fiction novels from 55 available: (52)=5×42×1=10\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10. Next, determine the number of ways to choose 11 biography book from 33 available: (31)=3\binom{3}{1} = 3. Finally, apply the Fundamental Counting Principle by multiplying the counts together: 10×3=3010 \times 3 = 30.

Step-by-Step Solution

1
Calculate the combinations for selecting the science fiction novels.
(52)=5×42×1=10\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10
Select 22 novels out of the 55 available science fiction novels without regard to order.
2
Calculate the combinations for selecting the biography book.
(31)=3\binom{3}{1} = 3
Select 11 book out of the 33 available biography books.
3
Apply the Fundamental Counting Principle to find total combinations.
10×3=3010 \times 3 = 30
Multiply the combinations calculated for each independent selection.

Key Concept

Combinations and the Fundamental Counting Principle
Question 529Question

An art gallery manager is arranging 6 unique paintings side by side in a single line on a display wall. Two specific paintings created by the same artist must be placed directly next to each other. How many different line arrangements of the 6 paintings are possible?

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Answer: 240

Answer

The total number of different line arrangements is 240.
To satisfy the constraint that two specific paintings must be adjacent, treat them as a single combined block. This reduces the problem to arranging 5 items (the single block plus the other 4 paintings), which can be ordered in 5! = 120 ways. Within the block, the two paintings can be ordered in 2! = 2 ways. Applying the Fundamental Counting Principle gives 120 * 2 = 240 distinct arrangements.

Step-by-Step Solution

1
Group the two specific paintings together as a single block.
There are 5 units to arrange (1 block of 2 paintings plus 4 individual paintings).
Since the two paintings must remain adjacent, treating them as a single item guarantees they will stay together.
2
Calculate the permutations of the 5 units.
5! = 5 * 4 * 3 * 2 * 1 = 120 ways.
There are 5 distinct units being arranged in a straight line.
3
Determine the internal arrangements of the grouped pair.
2! = 2 * 1 = 2 ways.
The two specific paintings within the block can switch positions (Painting A then B, or Painting B then A).
4
Multiply the arrangements together.
120 * 2 = 240 total arrangements.
By the Fundamental Counting Principle, total arrangements equal the number of ways to place the units multiplied by the internal arrangements of the restricted pair.

Key Concept

Permutations with Restrictions (Grouped Elements)
Estimated Time:1m 15s
Question 530Question

A student is creating a flag design consisting of 3 vertical stripes in a row. The student can choose from 5 different colors: Red, Blue, Green, Yellow, and White. To ensure visual contrast, any 2 adjacent stripes must be different colors. How many different flag designs can be created under these rules?

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Answer: 80

Answer

80
To find the total number of flag designs, apply the Fundamental Counting Principle across the three sequential stripe choices. The first stripe can be any of the 5 colors. The second stripe cannot match the first stripe's color, leaving 4 options. The third stripe cannot match the second stripe's color, which also leaves 4 options (since it can re-use the first stripe's color). Multiplying these choices together gives 5×4×4=805 \times 4 \times 4 = 80 unique flag designs.

Step-by-Step Solution

1
Determine choices for the first stripe
5 choices
Any of the 5 available colors can be selected for the first stripe.
2
Determine choices for the second stripe
4 choices
The second stripe must differ in color from the first stripe.
3
Determine choices for the third stripe
4 choices
The third stripe must differ in color from the second stripe (it may be the same color as the first stripe).
4
Apply the Fundamental Counting Principle
5×4×4=805 \times 4 \times 4 = 80
Multiply the options available at each stage to calculate the total number of distinct flag designs.

Key Concept

Fundamental Counting Principle with adjacent restrictions
Estimated Time:1m 15s
Question 531Question

If x=3x = -3, y=12y = -\frac{1}{2}, and z=8z = 8, what is the value of the algebraic expression x2y1+z2/32xy1\frac{x^2 y^{-1} + z^{2/3}}{2xy - 1}?

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Answer: -7

Answer

The value of the expression is -7.
Substituting the given values into the expression requires careful application of exponent rules and order of operations. First, (3)2=9(-3)^2 = 9 and (12)1=2(-\frac{1}{2})^{-1} = -2, so x2y1=9×(2)=18x^2 y^{-1} = 9 \times (-2) = -18. Second, 82/3=(83)2=22=48^{2/3} = (\sqrt[3]{8})^2 = 2^2 = 4. This makes the numerator 18+4=14-18 + 4 = -14. The denominator evaluates to 2(3)(12)1=31=22(-3)(-\frac{1}{2}) - 1 = 3 - 1 = 2. Dividing 14-14 by 22 gives the correct answer of 7-7.

Step-by-Step Solution

1
Substitute x=3x = -3 and y=12y = -\frac{1}{2} into x2y1x^2 y^{-1}
(3)2(2)=18(-3)^2 \cdot (-2) = -18
Squaring 3-3 yields 99, and taking the reciprocal of 12-\frac{1}{2} yields 2-2.
2
Substitute z=8z = 8 into z2/3z^{2/3}
82/3=48^{2/3} = 4
Taking the cube root of 88 gives 22, and squaring 22 gives 44.
3
Evaluate the numerator
18+4=14-18 + 4 = -14
Adding the evaluated terms together.
4
Substitute values into the denominator 2xy12xy - 1
2(3)(12)1=31=22(-3)\left(-\frac{1}{2}\right) - 1 = 3 - 1 = 2
Multiplying 22, 3-3, and 12-\frac{1}{2} produces 33, then subtracting 11 yields 22.
5
Divide the numerator by the denominator
142=7\frac{-14}{2} = -7
Simplifying the rational expression yields the final numeric answer.

Key Concept

Evaluating algebraic expressions with negative bases, rational exponents, and negative exponents
Question 532Question

If x=3x = -3, y=12y = -\frac{1}{2}, and z=4z = 4, what is the numerical value of the algebraic expression x24y2x+yz\frac{x^2 - 4y^2}{x + yz}?

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Answer: -1.6

Answer

The numerical value of the expression is 1.6-1.6.
Substituting x=3x = -3, y=12y = -\frac{1}{2}, and z=4z = 4 into x24y2x+yz\frac{x^2 - 4y^2}{x + yz} gives a numerator of (3)24(12)2=94(14)=8(-3)^2 - 4\left(-\frac{1}{2}\right)^2 = 9 - 4\left(\frac{1}{4}\right) = 8 and a denominator of 3+(12)(4)=32=5-3 + \left(-\frac{1}{2}\right)(4) = -3 - 2 = -5. Evaluating 85\frac{8}{-5} yields 1.6-1.6.

Step-by-Step Solution

1
Evaluate the numerator x24y2x^2 - 4y^2
8
Squaring 3-3 gives 99, and squaring 12-\frac{1}{2} gives 14\frac{1}{4}. Thus, 94(14)=91=89 - 4\left(\frac{1}{4}\right) = 9 - 1 = 8.
2
Evaluate the denominator x+yzx + yz
-5
Multiplying 12-\frac{1}{2} by 44 gives 2-2. Adding 3+(2)-3 + (-2) yields 5-5.
3
Compute the final fraction quotient
-1.6
Dividing the numerator 88 by the denominator 5-5 yields 1.6-1.6.

Key Concept

Evaluating algebraic expressions using order of operations with negative bases and fractional values.
Estimated Time:1m 30s
Question 533Question

The polynomial 4x28x54x^2 - 8x - 5 is subtracted from the polynomial 7x23x+47x^2 - 3x + 4. The simplified difference can be expressed as ax2+bx+cax^2 + bx + c, where aa, bb, and cc are constant integers. What is the value of the coefficient bb?

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Answer: 5

Answer

The coefficient of the xx term, bb, is 5.
Subtracting 4x28x54x^2 - 8x - 5 from 7x23x+47x^2 - 3x + 4 yields (7x24x2)+(3x(8x))+(4(5))=3x2+5x+9(7x^2 - 4x^2) + (-3x - (-8x)) + (4 - (-5)) = 3x^2 + 5x + 9. The coefficient of the linear term xx is 55.

Step-by-Step Solution

1
Set up the subtraction expression.
(7x23x+4)(4x28x5)(7x^2 - 3x + 4) - (4x^2 - 8x - 5)
Subtracting the second polynomial from the first requires enclosing the second polynomial in parentheses to apply the subtraction to all terms.
2
Distribute the negative sign to all terms inside the parentheses.
7x23x+44x2+8x+57x^2 - 3x + 4 - 4x^2 + 8x + 5
Distributing the subtraction sign flips the sign of each term: positive terms become negative, and negative terms become positive.
3
Group and combine like terms.
3x2+5x+93x^2 + 5x + 9
Combine the coefficients of matching variable parts: (74)x2=3x2(7 - 4)x^2 = 3x^2, (3+8)x=5x(-3 + 8)x = 5x, and 4(5)=94 - (-5) = 9.
4
Identify the coefficient bb corresponding to the xx term.
b=5b = 5
Comparing the simplified expression 3x2+5x+93x^2 + 5x + 9 to ax2+bx+cax^2 + bx + c shows that the coefficient of xx is 5.

Key Concept

Polynomial Subtraction and Combining Like Terms
Question 534Question

If xx is a real number such that log5(x)+log5(x20)=3\log_5(x) + \log_5(x - 20) = 3, what is the value of xx?

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Answer: 25

Answer

The value of xx is 25.
Applying the logarithmic product rule simplifies the equation to log5(x220x)=3\log_5(x^2 - 20x) = 3. Writing this in exponential form yields x220x=125x^2 - 20x = 125. Rearranging into standard form gives x220x125=0x^2 - 20x - 125 = 0, which factors into (x25)(x+5)=0(x - 25)(x + 5) = 0. This gives potential solutions of 2525 and 5-5. Because the logarithmic arguments must be strictly positive, x=5x = -5 is extraneous. Therefore, the only correct value is 25.

Step-by-Step Solution

1
Use the product property of logarithms to combine the terms on the left side.
log5(x(x20))=3\log_5(x(x - 20)) = 3
The sum of logarithms with the same base is equal to the logarithm of the product of their arguments: logb(M)+logb(N)=logb(MN)\log_b(M) + \log_b(N) = \log_b(MN).
2
Rewrite the logarithmic equation in exponential form.
x(x20)=53    x220x=125x(x - 20) = 5^3 \implies x^2 - 20x = 125
The logarithmic equation logb(y)=c\log_b(y) = c is equivalent to the exponential equation bc=yb^c = y.
3
Rearrange the quadratic equation into standard form and solve by factoring.
x220x125=0    (x25)(x+5)=0    x=25 or x=5x^2 - 20x - 125 = 0 \implies (x - 25)(x + 5) = 0 \implies x = 25 \text{ or } x = -5
Subtracting 125 from both sides sets the quadratic equation to 0, which can then be factored into binomials whose product is 0.
4
Verify the potential solutions in the original equation to identify any extraneous roots.
For x=5x = -5, the arguments of the original logarithms are negative, which is undefined. For x=25x = 25, the arguments are positive. Thus, the only valid solution is x=25x = 25.
Logarithmic functions are only defined for positive real numbers. Therefore, we must have x>0x > 0 and x20>0x - 20 > 0, which requires x>20x > 20.

Key Concept

Solving logarithmic equations by combining logarithmic terms and checking for extraneous solutions.
Estimated Time:1m 30s
Question 535Question

In ABC\triangle ABC, the measure of angle AA is 4040^\circ. Point DD lies on side ACAC such that segment BDBD bisects angle ABCABC. If the measure of angle BDCBDC is 7575^\circ, what is the measure, in degrees, of angle CC?

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Answer: 70

Answer

The measure of angle C is 70 degrees.
The correct measure of angle CC is found by first identifying that angle ADBADB is supplementary to angle BDCBDC, giving a measure of 105105^\circ. Using the triangle angle sum theorem on triangle ABDABD, we find that angle ABDABD is 3535^\circ. Since BDBD bisects angle ABCABC, angle DBCDBC is also 3535^\circ. Finally, applying the triangle angle sum theorem to triangle BCDBCD, we subtract the measures of angles DBCDBC (3535^\circ) and BDCBDC (7575^\circ) from 180180^\circ to get 7070^\circ.

Step-by-Step Solution

1
Find the measure of angle ADBADB using the supplementary angle relationship with angle BDCBDC.
105105^\circ
Angles ADBADB and BDCBDC form a linear pair along the line segment ACAC, so their sum is 180180^\circ.
2
Find the measure of angle ABDABD using the sum of interior angles in ABD\triangle ABD.
3535^\circ
The sum of interior angles in any triangle is 180180^\circ. Therefore, the measure of angle ABDABD is 180(40+105)=35180^\circ - (40^\circ + 105^\circ) = 35^\circ.
3
Find the measure of angle DBCDBC using the definition of an angle bisector.
3535^\circ
Since segment BDBD bisects angle ABCABC, the measures of angles ABDABD and DBCDBC must be equal.
4
Find the measure of angle CC using the sum of interior angles in BCD\triangle BCD.
7070^\circ
The sum of interior angles in BCD\triangle BCD is 180180^\circ. Therefore, the measure of angle CC is 180(35+75)=70180^\circ - (35^\circ + 75^\circ) = 70^\circ.

Key Concept

Using the triangle angle sum theorem and angle bisector properties to determine unknown angle measures in a geometric figure.
Question 536Question

In right triangle ABCABC, the hypotenuse ACAC has a length of 13 centimeters, and leg ABAB has a length of 5 centimeters. What is the length, in centimeters, of leg BCBC?

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Answer: 12

Answer

The length of leg BCBC is 12 centimeters.
Applying the Pythagorean theorem, we have 52+BC2=1325^2 + BC^2 = 13^2, which simplifies to 25+BC2=16925 + BC^2 = 169. Subtracting 25 from both sides gives BC2=144BC^2 = 144, and taking the square root of both sides gives BC=12BC = 12 centimeters.

Step-by-Step Solution

1
Set up the Pythagorean Theorem equation for right triangle ABCABC.
AB2+BC2=AC2AB^2 + BC^2 = AC^2
The Pythagorean Theorem states that in a right triangle, the sum of the squares of the legs is equal to the square of the hypotenuse.
2
Substitute the given values for ABAB and ACAC into the formula.
52+BC2=1325^2 + BC^2 = 13^2
The length of leg ABAB is given as 5 centimeters, and the length of the hypotenuse ACAC is given as 13 centimeters.
3
Solve for the unknown leg length BCBC.
BC=12BC = 12
Squaring the values gives 25+BC2=16925 + BC^2 = 169. Subtracting 25 from both sides yields BC2=144BC^2 = 144. Taking the square root of both sides gives BC=12BC = 12.

Key Concept

Pythagorean Theorem

Alternative Method

Recognize the triangle as a standard 5-12-13 Pythagorean triple, which immediately gives the missing leg length of 12 without needing calculations.
Estimated Time:30s
Question 537Question

The circle x2+y2=25x^2 + y^2 = 25 and the line y=2x5y = 2x - 5 intersect at two points. What is the sum of the yy-coordinates of these two intersection points?

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Answer: -2

Answer

The sum of the yy-coordinates of the intersection points is 2-2.
Substituting y=2x5y = 2x - 5 into the circular equation x2+y2=25x^2 + y^2 = 25 yields the quadratic equation 5x220x=05x^2 - 20x = 0. Factoring this equation gives x=0x = 0 and x=4x = 4. Evaluating the linear equation at these values gives the yy-coordinates 5-5 and 33. The sum of these coordinates is 5+3=2-5 + 3 = -2.

Step-by-Step Solution

1
Substitute y=2x5y = 2x - 5 into the circle equation x2+y2=25x^2 + y^2 = 25.
x2+(2x5)2=25x^2 + (2x - 5)^2 = 25
To find the points of intersection, we solve the system of equations by substitution.
2
Expand and simplify the resulting equation.
5x220x=05x^2 - 20x = 0
Expanding (2x5)2(2x - 5)^2 gives 4x220x+254x^2 - 20x + 25. Combining like terms and subtracting 25 from both sides simplifies the equation.
3
Factor the quadratic equation to solve for xx.
x=0x = 0 or x=4x = 4
Factoring out 5x5x gives 5x(x4)=05x(x - 4) = 0, which yields the roots x=0x = 0 and x=4x = 4.
4
Find the corresponding yy-coordinates by substituting the xx-values back into y=2x5y = 2x - 5.
The intersection points are (0,5)(0, -5) and (4,3)(4, 3).
For x=0x = 0, y=2(0)5=5y = 2(0) - 5 = -5. For x=4x = 4, y=2(4)5=3y = 2(4) - 5 = 3.
5
Calculate the sum of the yy-coordinates.
2-2
Adding the yy-coordinates 5-5 and 33 gives 5+3=2-5 + 3 = -2.

Key Concept

Systems of Linear and Non-Linear Equations
Question 538Question

In the standard (x,y)(x, y) coordinate plane, a triangle has vertices at A(0,1)A(0, 1), B(2,3)B(2, 3), and C(8,11)C(8, 11). If point MM is the midpoint of side ABAB and point NN is the midpoint of side ACAC, what is the length of the line segment MNMN?

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Answer: 5

Answer

The length of the line segment MNMN is 55.
The length of the line segment MNMN is 55. Calculating the coordinates of the midpoint of ABAB, we get M(1,2)M(1, 2). For ACAC, the midpoint is N(4,6)N(4, 6). Applying the distance formula between MM and NN yields (41)2+(62)2=9+16=5\sqrt{(4-1)^2 + (6-2)^2} = \sqrt{9+16} = 5. Alternatively, by the Midsegment Theorem, the segment connecting the midpoints of two sides of a triangle is half the length of the third side. The length of the third side BCBC is (82)2+(113)2=36+64=10\sqrt{(8-2)^2 + (11-3)^2} = \sqrt{36 + 64} = 10, so the length of MNMN is 102=5\frac{10}{2} = 5.

Step-by-Step Solution

1
Find the coordinates of MM, the midpoint of side ABAB with endpoints A(0,1)A(0, 1) and B(2,3)B(2, 3).
M(1,2)M(1, 2)
The midpoint formula is M=(x1+x22,y1+y22)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right).
2
Find the coordinates of NN, the midpoint of side ACAC with endpoints A(0,1)A(0, 1) and C(8,11)C(8, 11).
N(4,6)N(4, 6)
Applying the midpoint formula gives (0+82,1+112)=(4,6)\left(\frac{0 + 8}{2}, \frac{1 + 11}{2}\right) = (4, 6).
3
Calculate the distance between M(1,2)M(1, 2) and N(4,6)N(4, 6) using the distance formula.
55
The distance formula is d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}. Here, d=(41)2+(62)2=32+42=25=5d = \sqrt{(4-1)^2 + (6-2)^2} = \sqrt{3^2 + 4^2} = \sqrt{25} = 5.

Key Concept

Midpoint and Distance Formulas
Question 539Question

In a convex polygon, the measures of the interior angles form an arithmetic progression. The smallest interior angle measures 120120^\circ, and the common difference between consecutive interior angles is 55^\circ. What is the number of sides of this polygon?

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Answer: 9

Answer

The number of sides of the polygon is 9.
The sum of the interior angles of a convex polygon with nn sides is (n2)×180(n-2) \times 180^\circ. Since the angles form an arithmetic progression with the first term a=120a = 120^\circ and common difference d=5d = 5^\circ, their sum is also given by the arithmetic series formula: Sn=n2[2(120)+(n1)5]=n2(5n+235)S_n = \frac{n}{2}[2(120) + (n-1)5] = \frac{n}{2}(5n + 235). Setting the two sums equal yields n2(5n+235)=180(n2)\frac{n}{2}(5n + 235) = 180(n - 2), which simplifies to the quadratic equation n225n+144=0n^2 - 25n + 144 = 0. Solving this gives n=9n = 9 or n=16n = 16. Because the polygon is convex, every interior angle must be less than 180180^\circ. If n=16n = 16, the largest angle would be 120+15(5)=195120^\circ + 15(5^\circ) = 195^\circ, which is impossible for a convex polygon. If n=9n = 9, the largest angle is 120+8(5)=160120^\circ + 8(5^\circ) = 160^\circ, which is valid. Therefore, the number of sides must be 9.

Step-by-Step Solution

1
Set up the equation equating the geometric sum of interior angles to the arithmetic series sum.
The sum of the interior angles of a convex nn-gon is (n2)×180(n - 2) \times 180^\circ. The sum of the arithmetic sequence of angles is Sn=n2[2(120)+(n1)5]S_n = \frac{n}{2}[2(120^\circ) + (n - 1)5^\circ]. Setting them equal gives: n2(5n+235)=180(n2)\frac{n}{2}(5n + 235) = 180(n - 2).
This establishes the algebraic relationship between the polygon's geometric properties and the given sequence of angle measures.
2
Simplify the equation and solve the resulting quadratic equation for nn.
5n2+235n=360n7205n2125n+720=0n225n+144=05n^2 + 235n = 360n - 720 \Rightarrow 5n^2 - 125n + 720 = 0 \Rightarrow n^2 - 25n + 144 = 0. Factoring the quadratic yields (n9)(n16)=0(n - 9)(n - 16) = 0, so n=9n = 9 or n=16n = 16.
Solving the quadratic equation yields all mathematically possible values for the number of sides.
3
Apply the convexity constraint to determine the valid number of sides.
For a polygon to be convex, every interior angle must be less than 180180^\circ. For n=16n = 16, the largest angle is 120+15(5)=195120^\circ + 15(5^\circ) = 195^\circ, which is impossible. For n=9n = 9, the largest angle is 120+8(5)=160120^\circ + 8(5^\circ) = 160^\circ, which is valid.
The definition of a convex polygon requires all interior angles to be strictly less than 180180^\circ, which eliminates the extraneous solution of 16.

Key Concept

Sum of interior angles of a convex polygon and arithmetic progressions
Question 540Question

The equation x2+y212x+8y+3=0x^2 + y^2 - 12x + 8y + 3 = 0 defines a circle in the standard (x,y)(x, y) coordinate plane. What is the radius of this circle?

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Answer: 7

Answer

The radius of the circle is 7.
Completing the square on the given equation yields (x6)2+(y+4)2=49(x - 6)^2 + (y + 4)^2 = 49. By comparing this to the standard circle equation (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, we find r2=49r^2 = 49. Taking the square root of 4949 gives a radius of 77.

Step-by-Step Solution

1
Group the xx and yy terms and move the constant to the right-hand side of the equation.
x212x+y2+8y=3x^2 - 12x + y^2 + 8y = -3
This groups terms containing the same variables together to prepare for completing the square.
2
Add the square of half of the linear coefficients to both sides to complete the square for both xx and yy.
(x212x+36)+(y2+8y+16)=3+36+16(x^2 - 12x + 36) + (y^2 + 8y + 16) = -3 + 36 + 16
Adding (122)2=36(\frac{-12}{2})^2 = 36 and (82)2=16(\frac{8}{2})^2 = 16 to both sides forms perfect square trinomials on the left side while maintaining equality.
3
Factor the trinomials into squared binomials and combine the constants on the right side.
(x6)2+(y+4)2=49(x - 6)^2 + (y + 4)^2 = 49
This rewrites the equation in the standard circle equation form.
4
Extract the radius from the standard form equation (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2.
r=7r = 7
Since the constant on the right side corresponds to r2r^2, taking the square root of 4949 gives the radius of the circle.

Key Concept

Converting a circle's equation from general form to standard form by completing the square to determine its properties.
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