All practice questions

Question 6061Question →

Which of the following processes describes the breakdown and decay of rocks in situ without involving the active removal or transport of the weathered material?

Weathering

Mass wasting

Metamorphism

Deposition

Show answer & explanation

Answer: Weathering

Answer

Weathering is the correct process, as it refers specifically to the in-situ breakdown of rocks without transportation.

Weathering specifically denotes the mechanical disintegration or chemical decomposition of rocks in place (in situ) at or near the Earth's surface, without any major transportation of the fragments.

Step-by-Step Solution

1

Identify the key defining characteristic in the question stem

The core phrase is 'in situ', meaning the process occurs in place without movement of the material.

Geomorphological processes are primarily distinguished by whether material is moved during the process.

2

Compare geomorphic process definitions

Weathering strictly operates in situ, whereas mass wasting involves gravity-driven downslope displacement, and deposition involves accumulation after transport.

Matching the process definition to in-situ rock breakdown leads directly to weathering.

Key Concept

In-situ rock breakdown (Weathering vs. Mass Wasting)

Question 6062Question →

Metro Social Club received $\text{N}80,000$ cash for subscriptions during the year ended 31 December 2025. Included in this amount was $\text{N}5,000$ paid by members in advance for the year 2026. What amount should be credited to the Income and Expenditure Account as subscription income for 2025?

\text{N}75,000

\text{N}85,000

\text{N}80,000

\text{N}5,000

Show answer & explanation

Answer: $\text{N}75,000$

Answer

\text{N}75,000

Subscription income for the current financial year is calculated by taking total cash received for subscriptions and deducting subscriptions received in advance for future periods (

\text{N}80,000 - \text{N}5,000 = \text{N}75,000

). Under the accrual concept, only income earned in the current period is credited to the Income and Expenditure Account.

Step-by-Step Solution

1

Identify total cash received for subscriptions during the year.

Total subscriptions cash received =

\text{N}80,000

This is the gross amount collected in the Receipts and Payments Account.

2

Deduct subscriptions received in advance for the year 2026.

\text{N}80,000 - \text{N}5,000 = \text{N}75,000

In accordance with the accrual concept, income received in advance for a future period must be excluded from current year revenue.

Key Concept

Accounting treatment of subscriptions received in advance

Estimated Time:45s

Question 6063Question →

On a topographical map drawn to a scale of $1:100,000$ , a hill summit is marked with a spot height of $520\text{ m}$ . The terrain features uniform contour intervals of $20\text{ m}$ . Point $X$ is located on the fifth contour line directly below the summit. Point $Y$ is situated at a lower elevation such that the vertical difference in height between Point $X$ and Point $Y$ is $240\text{ m}$ . If the straight-line distance measured between Point $X$ and Point $Y$ on the map is $6\text{ cm}$ , calculate the average gradient between Point $X$ and Point $Y$ expressed in the ratio $1 : n$ . What is the value of $n$ ?

Show answer & explanation

Answer: 25

Answer

The value of

n

is 25, corresponding to an average gradient of

1 : 25

(or 1 in 25).

To find the denominator

n

of the gradient ratio

1:n

, the vertical interval (VI =

240\text{ m}

) is compared to the horizontal equivalent (HE =

6,000\text{ m}

). Dividing

6,000\text{ m}

by

240\text{ m}

yields

25

, meaning the slope rises 1 meter vertically for every 25 meters horizontally.

Step-by-Step Solution

1

Determine the elevation of Point X from the contour interval and spot height.

Elevation of Point X =

520\text{ m} - (5 \times 20\text{ m}) = 420\text{ m}

.

Point X lies on the fifth contour line below the

520\text{ m}

summit with a

20\text{ m}

interval.

2

Identify the Vertical Interval (VI) between Point X and Point Y.

\text{VI} = 240\text{ m}

.

The vertical elevation difference is directly specified in the problem statement.

3

Convert map distance to actual ground horizontal distance (Horizontal Equivalent, HE) using the map scale.

\text{HE} = 6\text{ cm} \times 100,000 = 600,000\text{ cm} = 6,000\text{ m}

.

Unit conversions must align VI and HE in meters before computing the ratio.

4

Express the gradient as a ratio

1 : n

by dividing HE by VI.

n = \frac{\text{HE}}{\text{VI}} = \frac{6,000\text{ m}}{240\text{ m}} = 25

.

Gradient ratio is defined as

\frac{\text{Vertical Interval}}{\text{Horizontal Equivalent}} = \frac{1}{n}

.

Key Concept

Gradient Calculation and Unit Alignment from Topographical Maps

Estimated Time:2m 30s

Question 6064Question →

A topographic cross-section is constructed from a map with a horizontal scale of $1 : 50{}000$ . If the vertical scale of the cross-section is set at $1\text{ cm}$ to represent $100\text{ m}$ , what is the vertical exaggeration of the cross-section?

Show answer & explanation

Answer: 5

Answer

The vertical exaggeration of the cross-section is 5.

To find vertical exaggeration, both scales must be in representative fraction (R.F.) form. A vertical scale of

1\text{ cm}

to

100\text{ m}

equals

1 : 10{}000

. Dividing the horizontal scale denominator (

50{}000

) by the vertical scale denominator (

10{}000

) gives a vertical exaggeration of

5

.

Step-by-Step Solution

1

Convert the vertical scale to a representative fraction

Vertical Scale = 1 : 10,000

Units must be consistent (centimetres to centimetres) to obtain a non-dimensional ratio.

2

Divide the horizontal scale denominator by the vertical scale denominator

50,000 / 10,000 = 5

Vertical exaggeration measures how many times greater the vertical scale is than the horizontal scale.

Key Concept

Vertical Exaggeration of Cross-Sections

Question 6065Question →

During October 2026, Emeka Enterprises completed the following transactions:
- Oct 4: Purchased goods for resale on credit from Chidi Ltd valued at $\text{₦}180,000$ , subject to a $10\%$ trade discount.
- Oct 12: Purchased office equipment on credit from Prime Tech Ltd for $\text{₦}120,000$ .
- Oct 20: Purchased goods for resale on credit from Bola & Sons valued at $\text{₦}240,000$ , subject to a $15\%$ trade discount.
- Oct 22: Purchased goods for resale for cash amounting to $\text{₦}45,000$ .

What is the total amount (in $\text{₦}$ ) to be recorded in the Purchases Journal for October 2026?

Show answer & explanation

Answer: 366000

Answer

The total amount to be recorded in the Purchases Journal for October 2026 is ₦366,000.

The Purchases Journal only records credit purchases of goods intended for resale. The net amounts after trade discounts are ₦162,000 for the Oct 4 transaction and ₦204,000 for the Oct 20 transaction. Office equipment is a non-current asset (General Journal) and cash purchases belong in the Cash Book. Thus, the total balance of the Purchases Journal is ₦162,000 + ₦204,000 = ₦366,000.

Step-by-Step Solution

1

Calculate the net price of goods purchased on credit from Chidi Ltd on Oct 4

₦162,000

Trade discounts are deducted immediately from the gross price when entering invoices into books of original entry:

\text{₦}180,000 - (10\% \times \text{₦}180,000) = \text{₦}162,000

.

2

Evaluate the transaction on Oct 12 for office equipment

Excluded (₦0)

The Purchases Journal strictly records credit purchases of goods intended for resale (trading inventory). Non-current asset purchases on credit are entered in the General Journal (Journal Proper).

3

Calculate the net price of goods purchased on credit from Bola & Sons on Oct 20

₦204,000

Apply the

15\%

trade discount:

\text{₦}240,000 - (15\% \times \text{₦}240,000) = \text{₦}204,000

.

4

Evaluate the cash purchase on Oct 22

Excluded (₦0)

Cash transactions are recorded in the Cash Book, not in the Purchases Journal.

5

Calculate the monthly total for the Purchases Journal

₦366,000

Sum the net amounts of eligible credit purchases of inventory:

\text{₦}162,000 + \text{₦}204,000 = \text{₦}366,000

.

Key Concept

Purchases Journal Scope and Trade Discount Calculations

Question 6066Question →

During field investigations in a humid tropical highland underlain by dense, jointed limestone, geologists observed both deep subterranean cave expansion and sudden downhill displacement of mud-rich regolith following torrential rains. Which statement accurately identifies the specific weathering mechanism operating on the bedrock and the distinct movement process displacing the surface material?

Carbonation dissolves the limestone bedrock in situ through carbonic acid reactions, while mass wasting in the form of a mudflow displaces saturated surface regolith downslope under gravity.

Exfoliation peels outer rock layers off the limestone bedrock through diurnal thermal expansion, while fluvial erosion transports the loosened sediment downstream.

Hydrolysis chemically transforms the limestone into metamorphic slate bedrock, which then undergoes frost shattering to push debris downslope.

Oxidation breaks down calcium ions in situ, while running water acts as the primary mass wasting agent carrying the material as bedload.

Show answer & explanation

Answer: Carbonation dissolves the limestone bedrock in situ through carbonic acid reactions, while mass wasting in the form of a mudflow displaces saturated surface regolith downslope under gravity.

Answer

Carbonation dissolves the limestone bedrock in situ through carbonic acid reactions, while mass wasting in the form of a mudflow displaces saturated surface regolith downslope under gravity.

The correct answer identifies that carbonation is the in-situ chemical weathering mechanism where weak carbonic acid dissolves jointed limestone to form subterranean caverns, and that mudflow is the rapid downslope mass wasting movement triggered by water saturation reducing friction along a slope.

Step-by-Step Solution

1

Analyze the bedrock weathering process

Limestone (

CaCO_3

) reacts with rainwater containing dissolved carbon dioxide (

H_2CO_3

) to form soluble calcium bicarbonate (

Ca(HCO_3)_2

). This in-situ chemical process is carbonation, which forms subterranean caves in karst landscapes.

Chemical weathering breaks down rock material in place without moving it.

2

Analyze the surface displacement process

Heavy seasonal rainfall saturates the surface regolith, reducing internal shear strength and causing the material to slide or flow downslope under the direct force of gravity as a mudflow or earthflow.

Mass wasting is strictly defined as the downslope movement of rock and soil debris under the direct influence of gravity, distinct from running water channel transport.

Key Concept

Distinction between in-situ weathering (carbonation) and gravity-driven mass wasting (mudflow)

Estimated Time:2m 0s

Question 6067Question →

Match each inventory concept or presentation in final accounts with its correct accounting rule or description.

Click a left item, then click its matching right item

Show answer & explanation

Answer

The Prudence Concept matches with 'Inventory is valued at the lower of cost and net realizable value'. Trading Account Treatment matches with 'Closing inventory is deducted from cost of goods available for sale'. Balance Sheet Treatment matches with 'Closing inventory is shown as a current asset'.

Each inventory valuation rule directly reflects fundamental sole trader accounting principles: the prudence concept governs valuation at lower of cost or net realizable value, the trading account deducts closing inventory to calculate cost of goods sold, and the balance sheet classifies closing inventory as a current asset.

Step-by-Step Solution

1

Identify the valuation basis for inventory.

According to the prudence convention, inventory must be valued at the lower of cost and net realizable value.

This prevents anticipating profit and ensures assets are not overstated.

2

Identify how closing inventory affects the Trading Account.

Closing inventory is deducted from total goods available for sale.

This calculation determines the Cost of Goods Sold for the financial period.

3

Identify the classification of closing inventory on the Balance Sheet.

Closing inventory is listed as a current asset.

It is an unconsumed resource held for resale or production within the upcoming operating cycle.

Key Concept

Valuation and Treatment of Inventory in Final Accounts

Question 6068Question →

Bello & Sons Enterprises operates two departments: Hardware and Stationery. For the accounting year ended 31 December 2025, the following information relates to the Hardware Department:

- Sales: $₦180,000$
- Opening Stock: $₦30,000$
- Purchases: $₦110,000$
- Closing Stock: $₦20,000$

The total administrative expenses for both departments combined amounted to $₦40,000$ , which are apportioned between Hardware and Stationery in proportion to their sales turnover. The total sales turnover for the business was $₦300,000$ .

What is the net profit of the Hardware Department?

₦60,000

₦40,000

₦36,000

₦16,000

Show answer & explanation

Answer: ₦36,000

Answer

The net profit of the Hardware Department is ₦36,000.

The gross profit of Hardware Department is calculated as Sales (

₦180,000

) minus Cost of Goods Sold (

₦30,000 + ₦110,000 - ₦20,000 = ₦120,000

), yielding

₦60,000

. Apportioning the administrative expenses of

₦40,000

based on Hardware's share of turnover (

₦180,000 / ₦300,000 = 60\%

) gives

₦24,000

. Deducting

₦24,000

from

₦60,000

gross profit gives the net profit of

₦36,000

.

Step-by-Step Solution

1

Calculate Cost of Goods Sold (COGS) for Hardware Department

COGS = Opening Stock + Purchases - Closing Stock =

₦30,000 + ₦110,000 - ₦20,000 = ₦120,000

Cost of goods sold measures the direct cost of merchandise sold during the period.

2

Calculate Gross Profit for Hardware Department

Gross Profit = Sales - COGS =

₦180,000 - ₦120,000 = ₦60,000

Gross profit represents revenue remaining after subtracting direct cost of sales.

3

Determine Hardware Department's share of administrative expenses

Turnover Ratio =

\frac{₦180,000}{₦300,000} = 0.60

(or

60\%

). Apportioned Expense =

0.60 \times ₦40,000 = ₦24,000

Shared overheads must be allocated using the specified turnover ratio basis.

4

Calculate Net Profit for Hardware Department

Net Profit = Gross Profit - Apportioned Expenses =

₦60,000 - ₦24,000 = ₦36,000

Net profit is the final departmental operating profit after overhead allocation.

Key Concept

Preparation of Departmental Trading, Profit and Loss Accounts and Expense Apportionment

Question 6069Question →

Unity Social Club received a donation of ₦500,000 specifically intended for the construction of a new library building. What is the correct accounting treatment for this donation in the club's financial statements?

Credit it to a Special Building Fund account as a capital receipt

Credit it to the Income and Expenditure Account as revenue income

Debit it to the Receipts and Payments Account as a revenue expense

Credit it to the Trading Account as operating profit

Show answer & explanation

Answer: Credit it to a Special Building Fund account as a capital receipt

Answer

The donation should be credited to a Special Building Fund account in the Statement of Financial Position as a capital receipt.

Donations designated for a specific capital purpose, such as constructing a building, are capitalized and credited directly to a dedicated capital fund account in the Statement of Financial Position (Balance Sheet).

Step-by-Step Solution

1

Identify the nature of the receipt

The donation is tied to a specific project (construction of a library building).

Specific donations carry a legal or constitutional restriction on how the funds must be spent.

2

Determine accounting classification (Capital vs Revenue)

Specific donations are classified as capital receipts rather than general revenue income.

Capital receipts create or add to long-term funds or non-current asset financing rather than supporting day-to-day operational activities.

3

Select the correct accounting record and statement placement

Credit the Special Library/Building Fund account shown on the liabilities side of the Balance Sheet (Statement of Financial Position).

This keeps the funds earmarked until utilized for the intended capital asset construction.

Key Concept

Accounting Treatment of Specific Donations in Non-Profit Organizations

Estimated Time:45s

Question 6070Question →

On a topographical map drawn to a scale of $1:25,000$ , a road ascends continuously from Point P at a contour elevation of $180\text{ m}$ to Point Q at a contour elevation of $430\text{ m}$ . If the average gradient along this section of the road is $1\text{ in } 20$ , what is the distance between Point P and Point Q on the map in centimeters?

2.0\text{ cm}

20.0\text{ cm}

34.4\text{ cm}

50.0\text{ cm}

Show answer & explanation

Answer: $20.0\text{ cm}$

Answer

The distance between Point P and Point Q on the map is

20.0\text{ cm}

.

The height difference (Vertical Interval) between the two points is

430\text{ m} - 180\text{ m} = 250\text{ m}

. With a gradient ratio of

1\text{ in } 20

, the horizontal ground distance (Horizontal Equivalent) is

250\text{ m} \times 20 = 5,000\text{ m}

, which equals

500,000\text{ cm}

. Applying the map scale of

1:25,000

gives a map measurement of

500,000\text{ cm} / 25,000 = 20.0\text{ cm}

.

Step-by-Step Solution

1

Calculate the Vertical Interval (VI) between Point P and Point Q

\text{VI} = 430\text{ m} - 180\text{ m} = 250\text{ m}

Vertical Interval represents the height difference between the two contour elevations.

2

Calculate the Horizontal Equivalent (HE) on the ground using the given gradient

\text{HE} = \text{VI} \times 20 = 250\text{ m} \times 20 = 5,000\text{ m}

Gradient is defined as

\frac{\text{VI}}{\text{HE}}

. Therefore,

\text{HE} = \text{VI} / \text{Gradient} = 250\text{ m} \times 20

.

3

Convert the ground distance (HE) to centimeters

\text{HE in cm} = 5,000\text{ m} \times 100\text{ cm/m} = 500,000\text{ cm}

Map distance calculations require identical linear units for numerator and denominator.

4

Determine the map distance using the Representative Fraction scale (

1:25,000

)

\text{Map Distance} = \frac{500,000\text{ cm}}{25,000} = 20.0\text{ cm}

Dividing the actual ground distance by the scale factor gives the equivalent measurement on the map.

Key Concept

Topographic Gradient and Map Scale Conversion

Estimated Time:2m 0s

Question 6071Question →

Match each layer or region of the Earth's structure listed in Column A with its correct physical property and composition in Column B.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Sial matches the lighter granitic continental crust (silica and alumina); Sima matches the dense basaltic oceanic crust (silica and magnesium); Asthenosphere matches the semi-fluid upper mantle zone enabling tectonic movement; Barysphere matches the innermost high-density metallic core (iron and nickel).

Sial is the lighter granitic layer rich in silica and aluminum forming continents. Sima is the denser basaltic layer rich in silica and magnesium forming ocean floors. The asthenosphere is the weak, semi-fluid region of the upper mantle supporting plate convection. The barysphere is the innermost heavy core composed of iron and nickel.

Step-by-Step Solution

1

Identify chemical compositions of the crustal layers

Sial stands for Silica + Alumina (continental), while Sima stands for Silica + Magnesium (oceanic).

Acronyms in physical geography directly correspond to dominant chemical elements in Earth's crust.

2

Analyze upper mantle mechanical properties

The asthenosphere is ductile and semi-fluid, located beneath the rigid lithosphere.

High temperatures allow asthenospheric rocks to slowly deform plastically, permitting lithospheric movement.

3

Classify the deep metallic interior

The barysphere refers specifically to the core region (Nife) composed of heavy metals like iron and nickel.

Barysphere originates from Greek root words implying 'heavy sphere'.

Key Concept

Internal Structure and Composition of the Earth

Question 6072Question →

A manufacturing business reported a Prime Cost of $\text{₦}248,500$ for its operational year. The financial records contain the following summary of costs:

Cost Component	Amount (\text{₦})
Opening inventory of raw materials	28,000
Closing inventory of raw materials	32,000
Direct factory wages	95,000
Carriage inwards on raw materials	6,500
Factory supervisor salary	24,000
Production royalty	14,000
Depreciation of factory plant	18,000

What was the total cost of raw materials purchased during the year?

\text{₦}137,000

\text{₦}113,000

\text{₦}95,000

\text{₦}150,000

Show answer & explanation

Answer: \text{₦}137,000

Answer

\text{₦}137,000

The value of \text{₦}137,000 is obtained by first subtracting direct labor (\text{₦}95,000) and production royalties (\text{₦}14,000) from Prime Cost (\text{₦}248,500), yielding raw materials consumed of \text{₦}139,500. Working backward through raw materials consumed (Opening Inventory + Purchases + Carriage Inwards - Closing Inventory) gives Purchases = \text{₦}139,500 - \text{₦}28,000 - \text{₦}6,500 + \text{₦}32,000 = \text{₦}137,000.

Step-by-Step Solution

1

Identify direct costs and exclude factory overheads

Direct costs comprise Direct Raw Materials Consumed, Direct Wages (\text{₦}95,000), and Production Royalty (\text{₦}14,000). Factory supervisor salary (\text{₦}24,000) and plant depreciation (\text{₦}18,000) are indirect factory overheads and must be excluded.

Prime Cost includes only direct costs directly traceable to unit production.

2

Calculate Raw Materials Consumed from Prime Cost formula

\text{Prime Cost} = \text{Raw Materials Consumed} + \text{Direct Wages} + \text{Direct Expenses}

\text{₦}248,500 = \text{Raw Materials Consumed} + \text{₦}95,000 + \text{₦}14,000

\text{Raw Materials Consumed} = \text{₦}248,500 - \text{₦}109,000 = \text{₦}139,500

Rearranging the Prime Cost equation isolates the total cost of raw materials consumed.

3

Calculate Raw Material Purchases using the inventory equation

\text{Raw Materials Consumed} = \text{Opening Inventory} + \text{Purchases} + \text{Carriage Inwards} - \text{Closing Inventory}

\text{₦}139,500 = \text{₦}28,000 + \text{Purchases} + \text{₦}6,500 - \text{₦}32,000

\text{₦}139,500 = \text{Purchases} + \text{₦}2,500

\text{Purchases} = \text{₦}139,500 - \text{₦}2,500 = \text{₦}137,000

Carriage inwards increases raw material acquisition cost while inventory changes adjust for stock held across periods.

Key Concept

Prime cost is the sum of direct materials consumed, direct labor, and direct expenses. Factory overheads must be omitted from Prime Cost calculations.

Estimated Time:2m 0s

Question 6073Question →

Match each rock type or mineral deposit in Column I with its correct geological formation process and primary economic usage in Column II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Kimberlite matches ultramafic volcanic pipe igneous rock (diamond source); Bauxite matches residual sedimentary rock formed via tropical leaching (aluminum ore); Marble matches thermal metamorphic recrystallized limestone (decorative building stone); Dolomite matches magnesium-bearing sedimentary carbonate rock (cement and refractory production).

Each rock is matched precisely to its mode of formation and primary economic application: Kimberlite is an intrusive igneous rock containing diamonds; Bauxite is a residual sedimentary rock that serves as aluminum ore; Marble is a metamorphic rock recrystallized from limestone used in ornamentation; Dolomite is a magnesium-rich sedimentary rock used in industrial construction.

Step-by-Step Solution

1

Analyze Kimberlite origin and economic value.

Kimberlite is an intrusive, ultramafic igneous rock forming narrow volcanic pipes. It is famous worldwide as the primary economic source of natural diamonds.

Igneous rock classifications link deep mantle plutonic/volcanic features with specific heavy mineral deposits.

2

Analyze Bauxite formation mechanism.

Bauxite is a residual sedimentary deposit created when prolonged chemical leaching in hot, wet climates washes away soluble minerals, leaving concentrated aluminum oxide.

Residual rocks are classified under surface sedimentary processes driven by weathering rather than deep thermal metamorphic forces.

3

Evaluate Marble metamorphic parentage.

Marble is formed when existing limestone undergoes heat and pressure, causing calcite minerals to recrystallize into a denser, polished decorative stone.

Identifying the parent rock (protolith) clarifies the transition from sedimentary carbonate to metamorphic rock.

4

Evaluate Dolomite sedimentary characteristics.

Dolomite is a sedimentary rock formed when magnesium replaces part of the calcium in limestone or precipitates directly in saline marine environments.

Chemical and biochemical sedimentary processes yield distinct magnesium-rich mineral compositions valuable in metallurgy and construction.

Key Concept

Classification of Rock Origins (Igneous, Sedimentary, Metamorphic, Residual) and Economic Minerals

Question 6074Question →

Under the Sale of Goods Act, unless otherwise agreed by the contracting parties, the risk of loss or damage to the goods passes to the buyer only upon physical delivery, regardless of when property in the goods is transferred.

True

False

Show answer & explanation

Answer: False

Answer

False. Under the Sale of Goods Act, risk prima facie passes with ownership (property), not upon physical delivery, unless the parties explicitly agree otherwise.

The statement is false because under the Sale of Goods Act, the transfer of risk is linked to the passing of property (ownership) rather than physical delivery. If property has passed to the buyer, the goods are at the buyer's risk whether delivery has been made or not.

Step-by-Step Solution

1

Identify the statutory default rule regarding the passing of risk in a contract for the sale of goods.

Section 20 of the Sale of Goods Act establishes that unless otherwise agreed, goods remain at the seller's risk until property in them is transferred to the buyer.

The act applies the legal doctrine of 'res perit domino' (the loss falls on the owner).

2

Distinguish between the transfer of property (ownership) and physical delivery of goods.

Property can pass to the buyer before physical delivery occurs (for example, in an unconditional contract for specific goods in a deliverable state).

Physical delivery is not the legal prerequisite for the transfer of risk unless stipulated in the contract.

Key Concept

Passing of Risk vs. Passing of Property under the Sale of Goods Act

Question 6075Question →

Arrange the following stages in the formation of an oxbow lake in the correct sequential order from first to last.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence of oxbow lake formation begins with the river forming a pronounced meander loop, followed by continuous erosion and deposition narrowing the neck. The river then cuts straight through the neck during a flood, and finally deposition seals off the abandoned loop to form an oxbow lake.

The correct order follows the progressive geomorphic stages of oxbow lake development: initial meander development with a narrow neck, neck narrowing through lateral erosion and deposition, sudden neck cut-off during a flood event, and final isolation of the crescent lake by alluvial deposition at the entrance and exit of the abandoned loop.

Step-by-Step Solution

1

Identify the initial channel shape

Establish that a meander loop with a narrow neck must exist prior to cut-off.

An oxbow lake can only form from a pre-existing river meander loop in its middle or lower course.

2

Trace the process of meander neck narrowing

Recognize that lateral erosion on hydraulic cut-banks and deposition on slip-off slopes narrow the neck.

Helicoidal flow concentrates energy on the outer banks, bringing the neck ends closer together over time.

3

Identify the breach event

Determine that flood conditions cause the river to cut directly through the neck.

High discharge provides sufficient hydraulic force to carve a new, straight channel along the path of maximum gradient.

4

Conclude with channel abandonment and isolation

Note that alluvium deposition blocks the old meander entrances.

Slower water current at the cut-off entry and exit points encourages deposition, leaving behind a cutoff lake.

Key Concept

Fluvial meander evolution and cut-off mechanisms leading to oxbow lake formation

Question 6076Question →

Which of the following conditions in rural areas acts as a major push factor driving rural-to-urban migration in developing countries?

Inadequate social amenities and shortage of employment opportunities

Availability of modern healthcare and higher educational institutions

Concentration of manufacturing industries and commercial hubs

Linear alignment of village homesteads along major transport routes

Show answer & explanation

Answer: Inadequate social amenities and shortage of employment opportunities

Answer

Inadequate social amenities and shortage of employment opportunities

The correct option identifies inadequate social amenities and a shortage of employment opportunities as rural push factors. In human geography, push factors are disadvantageous or adverse conditions at the place of origin—such as lack of pipe-borne water, poor electricity, and limited jobs—that compel people to move away toward urban centers.

Step-by-Step Solution

1

Define migration push factors in human geography context.

Push factors are negative conditions at a place of origin that compel individuals to leave.

Distinguishing between origin (push) and destination (pull) forces is fundamental to understanding urbanization.

2

Evaluate rural attributes to identify which condition acts as a negative force.

Lack of basic infrastructure and job opportunities in rural regions serve as unfavorable push drivers.

Poverty and inadequate services directly pressure rural inhabitants to seek better opportunities in urban centers.

Key Concept

Migration Push Factors in Urbanization

Estimated Time:45s

Question 6077Question →

When swash carries beach material up a shoreline at an oblique angle and backwash drags it perpendicular to the coast, sediment migrates laterally via longshore drift. If this ongoing deposition extends an embankment entirely across the entrance of an indentation, connecting two headlands and impounding a coastal lagoon behind it, which geomorphic feature is formed?

A baymouth bar

An oxbow lake

A scree slope

A metamorphic slate bench

Show answer & explanation

Answer: A baymouth bar

Answer

A baymouth bar

Longshore drift moves sediment along the shoreline when waves break obliquely. When sand and shingle build out across an indentation or bay until reaching the opposite headland, the feature completely encloses the bay to form a baymouth bar, isolating a lagoon behind it.

Step-by-Step Solution

1

Analyze the marine sediment transport mechanism described in the stem

Identify that oblique swash and direct backwash produce longshore drift along the coast

Prevailing wind direction governs swash angle while gravity dictates backwash return

2

Determine the morphological outcome of longshore drift across a bay

Sediment builds a spit that progressively extends across the bay mouth to the opposing headland

Uninterrupted deposition joins both sides and traps water behind the sand ridge

3

Match the complete closure feature to coastal landform terminology

A continuous ridge sealing off a bay and forming a lagoon is classified as a baymouth bar

Distinguishes a fully closed bar from an open-ended spit or offshore bar

Key Concept

Longshore drift and coastal depositional landforms (Baymouth bar formation)

Estimated Time:1m 30s

Question 6078Question →

A civil engineering firm in Nigeria requires a coarse-grained, highly durable rock with high compressive strength for constructing heavy building foundations and road monuments. Which rock type best fulfills this requirement, and what is its primary mode of origin?

Granite, formed through the slow cooling and crystallization of magma deep beneath the Earth's surface

Marble, formed through the accumulation and compaction of organic marine sediments

Basalt, formed through the in-situ chemical weathering and mechanical breakdown of surface rocks

Slate, formed through the deposition and consolidation of fine clay particles in river basins

Show answer & explanation

Answer: Granite, formed through the slow cooling and crystallization of magma deep beneath the Earth's surface

Answer

Granite, formed through the slow cooling and crystallization of magma deep beneath the Earth's surface

Granite is an intrusive (plutonic) igneous rock. Because magma cools slowly beneath the Earth's crust, large mineral crystals form, giving it a coarse-grained texture and immense structural strength. This makes it an ideal material for foundation construction, aggregate production, and monuments.

Step-by-Step Solution

1

Identify the required rock characteristics described in the engineering scenario

The target rock must be coarse-grained (phaneritic), exceptionally durable, and resistant to high pressure.

Engineering applications such as heavy foundations demand plutonic igneous rocks with interlocking mineral crystals.

2

Evaluate the geological origin of candidate rock types

Granite forms as intrusive magma cools slowly deep underground, allowing large crystals of quartz and feldspar to grow, imparting high strength and coarse texture.

Slow cooling underground produces plutonic igneous rocks, whereas rapid surface cooling produces fine-grained volcanic rocks like basalt.

Key Concept

Classification and Economic Importance of Igneous Rocks

Question 6079Question →

A morphometric quantitative analysis of a river basin using Strahler's stream ordering method yields the following stream segment counts:
- $N_1$ (1st-order streams) = $40$
- $N_2$ (2nd-order streams) = $10$
- $N_3$ (3rd-order streams) = $4$
- $N_4$ (4th-order streams) = $1$

Based on these morphometric data, what is the mean bifurcation ratio ( $R_b$ ) of this drainage basin?

Show answer & explanation

Answer: 3.5

Answer

The mean bifurcation ratio (

R_b

) of the drainage basin is 3.5.

The mean bifurcation ratio (

R_b

) is obtained by computing the ratio of stream segments between successive orders:

N_1/N_2 = 4.0

,

N_2/N_3 = 2.5

, and

N_3/N_4 = 4.0

. Averaging these three values gives

(4.0 + 2.5 + 4.0) / 3 = 3.5

.

Step-by-Step Solution

1

Calculate the individual bifurcation ratios (

R_b

) between consecutive stream orders using the formula

R_b = \frac{N_u}{N_{u+1}}

.

R_{b(1-2)} = \frac{40}{10} = 4.0

,

R_{b(2-3)} = \frac{10}{4} = 2.5

, and

R_{b(3-4)} = \frac{4}{1} = 4.0

.

Bifurcation ratio measures the ratio of the number of stream segments of a given order to the number of segments of the next higher order.

2

Sum the calculated individual bifurcation ratios.

Sum

= 4.0 + 2.5 + 4.0 = 10.5

.

To find the average across all order transitions, the sum of all calculated ratios must first be determined.

3

Divide the total sum by the number of order transitions (

k = 3

).

Mean

R_b = \frac{10.5}{3} = 3.5

.

There are 3 transitions between the 4 stream orders, so dividing the sum by 3 gives the arithmetic mean bifurcation ratio.

Key Concept

Bifurcation Ratio and Stream Order Analysis in River Basins

Question 6080Question →

Match each head office and independent branch reconciliation scenario on the left with its corresponding adjusting journal entry on the right.

Click a left item, then click its matching right item

Show answer & explanation

Answer

1. Goods in transit dispatched by Head Office matches Debit Goods in Transit Account and Credit Head Office Current Account (in Branch books).
2. Cash remitted by Branch in transit matches Debit Cash in Transit Account and Credit Branch Current Account (in Head Office books).
3. Branch operating expenses paid by Head Office matches Debit Operating Expenses Account and Credit Head Office Current Account (in Branch books).
4. Branch trade creditor settled by Head Office matches Debit Trade Creditors Account and Credit Head Office Current Account (in Branch books).

Each reconciliation scenario requires specific journal entries to align the reciprocal Branch Current Account in the Head Office books with the Head Office Current Account in the Branch books. Items in transit are always recorded in the receiving entity's books at year-end, while direct payments by Head Office increase the Head Office Current Account balance in the Branch books.

Step-by-Step Solution

1

Identify the entity responsible for recording transit items at year-end balance sheet date

Goods in transit are recorded in the Branch books, while cash in transit is recorded in the Head Office books.

In-transit reconciliation adjustments are posted in the books of the receiving entity where the transaction remains unrecorded.

2

Determine double-entry adjustments for unreceived goods

Debit Goods in Transit Account and Credit Head Office Current Account in Branch books.

The branch recognizes the asset in transit and adjusts its reciprocal obligation to the head office.

3

Determine double-entry adjustments for unreceived cash remittances

Debit Cash in Transit Account and Credit Branch Current Account in Head Office books.

Head office recognizes cash asset in transit while reducing the reciprocal branch current account balance.

4

Determine double-entry postings for direct Head Office disbursements on behalf of the branch

Debit Expenses or Trade Creditors Account and Credit Head Office Current Account in Branch books.

The branch records the expense or liability reduction while crediting Head Office Current Account to record capital/funding from head office.

Key Concept

Independent Branch Accounts and Head Office Reconciliation Adjustments

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