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Question 1341Question

For all positive real numbers xx and yy, the expression (x3y2)2/3(x1y4)1/6(x2y)1/2\frac{(x^{3} y^{2})^{2/3} \cdot (x^{-1} y^{4})^{1/6}}{(x^2 y)^{1/2}} can be written in the equivalent form xaybx^a y^b, where aa and bb are constants. What is the value of 6a+2b6a + 2b?

Show answer & explanation

Answer: 8

Answer

The correct answer is 8.
Applying the rules of exponents systematically yields the simplified expression x5/6y3/2x^{5/6} y^{3/2}. By setting a=56a = \frac{5}{6} and b=32b = \frac{3}{2}, the linear combination 6a+2b6a + 2b evaluates to 6(56)+2(32)=5+3=86\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8.

Step-by-Step Solution

1
Apply the power of a power rule to the first term in the numerator.
(x3y2)2/3=x323y223=x2y4/3(x^3 y^2)^{2/3} = x^{3 \cdot \frac{2}{3}} y^{2 \cdot \frac{2}{3}} = x^2 y^{4/3}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
2
Apply the power of a power rule to the second term in the numerator.
(x1y4)1/6=x116y416=x1/6y2/3(x^{-1} y^4)^{1/6} = x^{-1 \cdot \frac{1}{6}} y^{4 \cdot \frac{1}{6}} = x^{-1/6} y^{2/3}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
3
Multiply the two simplified terms in the numerator.
(x2y4/3)(x1/6y2/3)=x216y43+23=x11/6y2(x^2 y^{4/3})(x^{-1/6} y^{2/3}) = x^{2 - \frac{1}{6}} y^{\frac{4}{3} + \frac{2}{3}} = x^{11/6} y^2
When multiplying expressions with the same base, add their exponents.
4
Simplify the denominator.
(x2y)1/2=x212y112=xy1/2(x^2 y)^{1/2} = x^{2 \cdot \frac{1}{2}} y^{1 \cdot \frac{1}{2}} = x y^{1/2}
To raise a product to a power, raise each factor to that power by multiplying their exponents.
5
Divide the numerator by the denominator.
x11/6y2xy1/2=x1161y212=x5/6y3/2\frac{x^{11/6} y^2}{x y^{1/2}} = x^{\frac{11}{6} - 1} y^{2 - \frac{1}{2}} = x^{5/6} y^{3/2}
When dividing expressions with the same base, subtract the exponent of the denominator from the exponent of the numerator.
6
Identify the values of aa and bb and calculate 6a+2b6a + 2b.
a=56a = \frac{5}{6}, b=32b = \frac{3}{2}, so 6a+2b=6(56)+2(32)=5+3=86a + 2b = 6\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8
Matching the simplified expression x5/6y3/2x^{5/6} y^{3/2} to xaybx^a y^b yields the values of the constants aa and bb, which are then used to calculate the required expression.

Key Concept

Simplifying rational expressions with fractional exponents using exponent rules.
Question 1342Question

In 2024, a local coalition of historical preservationists in Philadelphia began a comprehensive project to restore several neglected structures from the colonial era. Although the diverse coalition of architects, historians, and community organizers has encountered numerous logistical obstacles, _______ remains determined to complete the restoration before the city's upcoming semiquincentennial celebration.

Which choice completes the text so that it conforms to the conventions of Standard English?

Show answer & explanation

Answer: it

Answer

it
The singular pronoun 'it' correctly agrees in number with the singular collective noun 'coalition', which serves as the antecedent. Additionally, 'it' is in the subjective case, fitting as the subject of the verb 'remains'.

Step-by-Step Solution

1
Identify the antecedent of the pronoun needed in the blank.
The antecedent is 'the diverse coalition', which is a singular collective noun.
The pronoun must agree in number and gender with its antecedent.
2
Determine the grammatical function of the pronoun in the subordinate clause.
The pronoun serves as the subject of the singular verb 'remains'.
The pronoun must be in the subjective case rather than the objective case.
3
Select the option that is both singular and in the subjective case.
The singular subjective pronoun 'it' is the correct choice.
This establishes proper pronoun-antecedent agreement and correct pronoun case.

Key Concept

Pronoun-Antecedent Agreement and Case
Question 1343Question

Desert ants of the genus *Cataglyphis* navigate harsh, featureless environments using a method called path integration, which relies on an internal odometer. While foraging, the ants continuously track their direction and distance relative to the nest ______ this mental log allows them to return home in a direct line rather than retracing their outward path.

Which choice completes the text so that it conforms to the conventions of Standard English?

Show answer & explanation

Answer: ; this

Answer

The choice containing a semicolon followed by the pronoun 'this' is correct because it properly separates two independent clauses without creating a comma splice or a run-on sentence.
The correct option properly uses a semicolon to connect two independent clauses, which is grammatically correct and maintains the logical connection between the ants tracking their location and the resulting benefit of that tracking.

Step-by-Step Solution

1
Analyze the clause structure before and after the blank.
The clause before the blank ('While foraging, the ants continuously track their direction and distance relative to the nest') is an independent clause. The clause after the blank ('this mental log allows them to return home...') is also an independent clause.
Identifying clause types is necessary to determine the required punctuation for linking them.
2
Determine valid grammatical linkers for independent clauses.
Two independent clauses must be joined using a period, a semicolon, a colon, or a comma paired with a coordinating conjunction.
This prevents grammatical errors such as comma splices and run-on sentences.
3
Evaluate the choices based on grammatical correctness and logical relationship.
A semicolon alone is a valid linker. A comma alone creates a comma splice, and no punctuation creates a run-on. Using 'but' is logically incorrect because there is no contrast.
The correct option must satisfy both punctuation rules and transition logic.

Key Concept

Clause Boundaries and Linking
Question 1344Question

Based on the rules of Standard English conventions, which punctuation mark should be inserted in the blank to grammatically connect the two independent clauses in the passage?

Fill in the blanks below

In 19081908, excavations at the ancient palace of Phaistos on Crete yielded a mysterious clay disc covered in enigmatic stamped symbols. Despite over a century of intense scrutiny by linguists and cryptographers, the Phaistos Disc remains undeciphered its true purpose and the language it records continue to elude scholarly consensus.
Show answer & explanation

Answer

A semicolon should be used to connect the two independent clauses.
A semicolon is the correct punctuation mark to join two independent clauses that are closely related and not joined by a coordinating conjunction. Here, the clauses on both sides of the blank are independent, and a semicolon properly links them without causing a run-on or comma splice.

Step-by-Step Solution

1
Identify the grammatical structure of the clauses surrounding the blank.
The clause before the blank ('Despite over a century of intense scrutiny by linguists and cryptographers, the Phaistos Disc remains undeciphered') and the clause after the blank ('its true purpose and the language it records continue to elude scholarly consensus') are both independent clauses.
Determining clause type dictates which punctuation marks are grammatically permissible.
2
Determine the appropriate punctuation mark to link two independent clauses without a coordinating conjunction.
A semicolon is the standard punctuation mark used to link two closely related independent clauses when no coordinating conjunction (like 'and' or 'but') is present.
Using a comma alone would create a comma splice, whereas a colon is incorrect because the second clause does not explain, illustrate, or define the first clause.

Key Concept

Semicolons are used to link two independent clauses that are closely related in thought.
Question 1345Question

If the expression (x+5)2(x3)2(x + 5)^2 - (x - 3)^2 is equivalent to ax+bax + b for all values of xx, where aa and bb are constants, what is the value of aa?

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Answer: 16

Answer

16
Expanding (x+5)2(x + 5)^2 gives x2+10x+25x^2 + 10x + 25, and expanding (x3)2(x - 3)^2 gives x26x+9x^2 - 6x + 9. Subtracting the second expression from the first requires distributing the negative sign across all terms: x2+10x+25(x26x+9)=x2+10x+25x2+6x9x^2 + 10x + 25 - (x^2 - 6x + 9) = x^2 + 10x + 25 - x^2 + 6x - 9. Combining like terms yields 16x+1616x + 16. Comparing this to ax+bax + b shows that the coefficient of xx, aa, is 16.

Step-by-Step Solution

1
Expand the first squared binomial term
(x+5)2=x2+10x+25(x + 5)^2 = x^2 + 10x + 25
To express the binomial square as a trinomial using the perfect square identity (u+v)2=u2+2uv+v2(u + v)^2 = u^2 + 2uv + v^2.
2
Expand the second squared binomial term
(x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9
To express the binomial square as a trinomial using the perfect square identity (uv)2=u22uv+v2(u - v)^2 = u^2 - 2uv + v^2.
3
Subtract the expanded expressions and distribute the negative sign
x2+10x+25x2+6x9x^2 + 10x + 25 - x^2 + 6x - 9
To combine the terms while correctly applying the distributive property to the subtracted expression.
4
Combine like terms to simplify the polynomial
16x+1616x + 16
To find the final simplified polynomial of the form ax+bax + b.
5
Compare the simplified expression to the standard form to find the value of aa
a=16a = 16
The constant aa represents the coefficient of the linear term xx, which is 16.

Key Concept

Simplifying algebraic expressions by expanding binomial products and combining like terms.
Question 1346Question

Let cc be a constant such that c<0c < 0. If c(x3)4(x+c)c(x - 3) \leq 4(x + c), which of the following inequalities must be true?

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Answer: x7cc4x \geq \frac{7c}{c - 4}

Answer

x7cc4x \geq \frac{7c}{c - 4}
The correct answer is obtained by first distributing terms on both sides to get cx3c4x+4ccx - 3c \leq 4x + 4c. Rearranging the terms to isolate the variable xx on one side yields (c4)x7c(c - 4)x \leq 7c. Since cc is a negative constant (c<0c < 0), the coefficient (c4)(c - 4) must also be negative. Dividing both sides of the inequality by this negative coefficient requires reversing the direction of the inequality sign, which yields the final result.

Step-by-Step Solution

1
Distribute the constants on both sides of the inequality.
cx3c4x+4ccx - 3c \leq 4x + 4c
This simplifies the parentheses so that variable terms can be grouped.
2
Group all terms with xx on the left side and terms with cc on the right side.
cx4x7ccx - 4x \leq 7c
Isolating the variable terms on one side makes it possible to factor and solve for xx.
3
Factor out xx on the left side of the inequality.
(c4)x7c(c - 4)x \leq 7c
This expresses the left side as a product of xx and a single coefficient.
4
Analyze the sign of the coefficient (c4)(c - 4) given that c<0c < 0.
c4<0c - 4 < 0
Since cc is less than 00, subtracting 44 from cc must result in a value less than 4-4, which is strictly negative.
5
Divide both sides of the inequality by (c4)(c - 4) and flip the inequality symbol.
x7cc4x \geq \frac{7c}{c - 4}
Dividing an inequality by a negative number requires reversing the direction of the inequality sign.

Key Concept

Solving linear inequalities by isolating the variable, and correctly reversing the inequality direction when multiplying or dividing by a negative variable parameter.
Question 1347Question

A software company offers a Basic subscription for $15\$15 per month and a Premium subscription for $30\$30 per month. In April, the company had a total of 1,2001,200 active subscriptions. In May, the number of Basic subscriptions increased by 20%20\%, and the number of Premium subscriptions increased by 5%5\% compared to April. If the company's total monthly revenue increased by $2,700\$2,700 from April to May, how many Premium subscriptions did the company have in April?

Show answer & explanation

Answer: 600

Answer

600
To find the number of Premium subscriptions in April, we can set up a system of linear equations. Let BB represent the number of Basic subscriptions in April and PP represent the number of Premium subscriptions in April. Since the total number of subscriptions is 1,2001,200, we have B+P=1,200B + P = 1,200. The revenue increase from April to May is $2,700\$2,700. The increase in Basic subscriptions is 20%20\%, which contributes 15×0.20B=3B15 \times 0.20B = 3B dollars to the revenue increase. The increase in Premium subscriptions is 5%5\%, which contributes 30×0.05P=1.5P30 \times 0.05P = 1.5P dollars to the revenue increase. Thus, 3B+1.5P=2,7003B + 1.5P = 2,700. Substituting B=1,200PB = 1,200 - P into this equation yields 3(1,200P)+1.5P=2,7003(1,200 - P) + 1.5P = 2,700. Solving for PP gives 3,6001.5P=2,7003,600 - 1.5P = 2,700, which simplifies to 1.5P=9001.5P = 900, or P=600P = 600.

Step-by-Step Solution

1
Define variables and write the first equation based on the total number of subscriptions in April.
B+P=1,200B + P = 1,200, where BB is the number of Basic subscriptions and PP is the number of Premium subscriptions.
To represent the relationship between the two types of subscriptions in April.
2
Write the second equation representing the change in monthly revenue from April to May.
3B+1.5P=2,7003B + 1.5P = 2,700
The change in revenue is the sum of the increase in revenue from each subscription type: 15(0.20B)+30(0.05P)=2,70015(0.20B) + 30(0.05P) = 2,700.
3
Solve the system of equations by substituting B=1,200PB = 1,200 - P into the revenue equation.
3(1,200P)+1.5P=2,700    3,6001.5P=2,7003(1,200 - P) + 1.5P = 2,700 \implies 3,600 - 1.5P = 2,700
Substitution eliminates the variable BB, allowing us to solve for PP directly.
4
Isolate the variable PP to find the number of Premium subscriptions in April.
1.5P=900    P=600-1.5P = -900 \implies P = 600
Dividing the revenue difference by the coefficient solves for the value of PP.

Key Concept

Solving systems of linear equations in real-life contexts involving percentage changes.
Question 1348Question

An environmental scientist is monitoring the water level of a reservoir during a dry season. The water level, L(d)L(d), in meters, can be modeled by a linear function of the number of days, dd, since the start of the dry season. On day 12, the water level was 30 meters, and on day 20, the water level was 26 meters. If the water level continues to decrease at this constant rate, on which day will the water level be exactly 18 meters?

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Answer: Day 36

Answer

Day 36
To find the day when the water level is exactly 18 meters, we first find the constant rate of change (slope) using the given points (12,30)(12, 30) and (20,26)(20, 26). The slope is m=26302012=0.5m = \frac{26 - 30}{20 - 12} = -0.5 meters per day. Using the point-slope form with (12,30)(12, 30), we get L(d)30=0.5(d12)L(d) - 30 = -0.5(d - 12), which simplifies to L(d)=0.5d+36L(d) = -0.5d + 36. Substituting 18 for L(d)L(d) gives 18=0.5d+3618 = -0.5d + 36. Subtracting 36 from both sides results in 18=0.5d-18 = -0.5d, and dividing by 0.5-0.5 yields d=36d = 36. Thus, the correct answer is Day 36.

Step-by-Step Solution

1
Calculate the constant rate of change (slope, mm) using the points (12,30)(12, 30) and (20,26)(20, 26).
m=26302012=48=0.5m = \frac{26 - 30}{20 - 12} = \frac{-4}{8} = -0.5 meters per day.
A linear function has a constant rate of change, which is determined by the slope formula: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Write the equation of the linear model in point-slope form and solve for the standard form.
L(d)30=0.5(d12)L(d)=0.5d+36L(d) - 30 = -0.5(d - 12) \Rightarrow L(d) = -0.5d + 36.
Using the point-slope formula yy1=m(xx1)y - y_1 = m(x - x_1) with the point (12,30)(12, 30) and slope 0.5-0.5 defines the function for any day dd.
3
Substitute L(d)=18L(d) = 18 into the equation and solve for dd.
18=0.5d+3618=0.5dd=3618 = -0.5d + 36 \Rightarrow -18 = -0.5d \Rightarrow d = 36.
Setting the dependent variable to the target water level of 18 meters yields the corresponding day.

Key Concept

Determining and evaluating linear equations from two given coordinate points

Alternative Method

Instead of constructing the entire equation, you can analyze the constant rate of change directly. The water level decreases by 44 meters (from 30 to 26) over 88 days (from day 12 to day 20), which means the rate of decrease is 0.50.5 meters per day. To drop from 26 meters (on day 20) to 18 meters requires a further decrease of 2618=826 - 18 = 8 meters. At a rate of 0.50.5 meters per day, dropping 8 meters will take 80.5=16\frac{8}{0.5} = 16 days. Adding these 16 days to day 20 yields day 36.
Estimated Time:1m 30s
Question 1349Question

A shipping company offers two types of delivery services: standard and express. The total shipping cost, in dollars, for a package sent via standard service is modeled by the function C(w)=1.25w+bsC(w) = 1.25w + b_s, where ww is the weight of the package, in pounds, and bsb_s is a constant representing the flat handling fee. The total shipping cost, in dollars, for a package sent via express service is modeled by the function E(k)=mek+beE(k) = m_e k + b_e, where kk is the weight of the package, in kilograms, and beb_e is a constant representing the flat handling fee.

The rate of change of the express shipping cost with respect to the package's weight, in dollars per kilogram, is 2.42.4 times the rate of change of the standard shipping cost with respect to the package's weight, in dollars per pound. The flat handling fee for the express service is 4.504.50 dollars more than the flat handling fee for the standard service. If it costs 58.5058.50 dollars to ship a package weighing 26.426.4 pounds using the express service, what is the cost, in dollars, to ship a package weighing 2020 pounds using the standard service? (Assume 1 kilogram=2.2 pounds1\text{ kilogram} = 2.2\text{ pounds}.)

Show answer & explanation

Answer: 43

Answer

The cost to ship a package weighing 20 pounds using the standard service is 43 dollars.
The correct answer is obtained by first calculating the rate of change of the express shipping cost (2.4×1.25=3.002.4 \times 1.25 = 3.00 dollars per kilogram). Next, the weight of the package is converted to kilograms (26.4/2.2=1226.4 / 2.2 = 12 kilograms) to match the express cost function's variable. Using the given cost of 58.5058.50 dollars for the express shipment, the express handling fee is determined to be 58.503(12)=22.5058.50 - 3(12) = 22.50 dollars. The standard handling fee is then found by subtracting 4.504.50 dollars from the express fee (22.504.50=18.0022.50 - 4.50 = 18.00 dollars). Finally, the cost of a 2020-pound standard package is computed as 1.25(20)+18.00=43.001.25(20) + 18.00 = 43.00 dollars.

Step-by-Step Solution

1
Determine the rate of change for the express service (mem_e).
me=3.00m_e = 3.00 dollars per kilogram
The rate of change of the standard shipping cost is 1.251.25 dollars per pound. Since the rate of change for the express shipping cost is 2.42.4 times this rate, me=2.4×1.25=3.00m_e = 2.4 \times 1.25 = 3.00 dollars per kilogram.
2
Convert the weight of the express package from pounds to kilograms.
k=12k = 12 kilograms
The weight of the package is given as 26.426.4 pounds. Using the conversion 1 kilogram=2.2 pounds1\text{ kilogram} = 2.2\text{ pounds}, the weight in kilograms is 26.42.2=12\frac{26.4}{2.2} = 12 kilograms.
3
Find the express flat handling fee (beb_e) using the given cost of the express shipment.
be=22.50b_e = 22.50 dollars
We are given that the cost of shipping a 1212-kilogram package using the express service is 58.5058.50 dollars. Substituting these values into the express cost function: 3(12)+be=58.5036+be=58.50be=22.503(12) + b_e = 58.50 \Rightarrow 36 + b_e = 58.50 \Rightarrow b_e = 22.50 dollars.
4
Find the standard flat handling fee (bsb_s).
bs=18.00b_s = 18.00 dollars
The express handling fee is 4.504.50 dollars more than the standard handling fee: be=bs+4.5022.50=bs+4.50bs=18.00b_e = b_s + 4.50 \Rightarrow 22.50 = b_s + 4.50 \Rightarrow b_s = 18.00 dollars.
5
Calculate the cost to ship a 2020-pound package using the standard service.
43.0043.00 dollars
Using the standard cost function C(w)=1.25w+bsC(w) = 1.25w + b_s with w=20w = 20 and bs=18.00b_s = 18.00: C(20)=1.25(20)+18.00=25.00+18.00=43.00C(20) = 1.25(20) + 18.00 = 25.00 + 18.00 = 43.00 dollars.

Key Concept

Interpreting slope, y-intercept, and rates of change of linear functions in a real-world context with unit conversions.
Question 1350Question

In a study of cognitive processing and memory consolidation, psychologist Dr. Elena Rostova analyzed how sleep deprivation affects learning outcomes. Her research concluded that a full night of sleep not only strengthens the neural connections formed during the day but also ______

Which choice completes the passage so that it conforms to the conventions of Standard English?

Show answer & explanation

Answer: integrates new information with existing knowledge

Answer

integrates new information with existing knowledge
The correct answer completes the passage with the present-tense verb 'integrates', which is parallel to the present-tense verb 'strengthens' that follows 'not only'.

Step-by-Step Solution

1
Identify the grammatical structure of the sentence.
The sentence uses the correlative conjunction 'not only... but also...', with the first part followed by the singular, present-tense verb 'strengthens'.
This establishes that the second part of the conjunction must also be followed by a singular, present-tense verb to maintain parallel structure.
2
Evaluate the grammatical form of each answer choice.
Only one choice uses a singular, present-tense verb ('integrates') to complete the parallel structure.
This maintains grammatical consistency across both parts of the correlative conjunction.

Key Concept

Parallel Structure
Question 1351Question

In molecular biology, histone acetylation plays a crucial role in regulating gene expression by modifying chromatin structure. When acetyl groups attach to histones, the DNA wraps more loosely around these ______ transcription factors can then access the genetic sequence and initiate the process of transcription. Consequently, this modification is vital for cell differentiation.

Which choice completes the text so that it conforms to the conventions of Standard English?

Show answer & explanation

Answer: proteins;

Answer

The choice ending with a semicolon ('proteins;') is the correct answer because it successfully links two independent clauses without a coordinating conjunction.
The correct answer is the option ending with a semicolon. The sentence contains two independent clauses: the first begins with the subordinate clause 'When acetyl groups attach to histones' followed by the main clause 'the DNA wraps more loosely around these proteins,' and the second clause is 'transcription factors can then access the genetic sequence...' A semicolon is a standard and correct way to link two closely related independent clauses.

Step-by-Step Solution

1
Identify the clause boundaries in the sentence containing the blank.
The sentence contains two distinct clauses: the first begins with 'When acetyl groups attach...' and ends at the blank, and the second begins with 'transcription factors can then...'
Understanding where one clause ends and the next begins is necessary to determine the correct punctuation or conjunction.
2
Analyze the grammatical structure of both clauses.
The first clause ('When acetyl groups attach to histones, the DNA wraps more loosely around these proteins') is an independent clause because it contains a subject ('the DNA') and a verb ('wraps') and can stand alone as a sentence. The second clause ('transcription factors can then access the genetic sequence and initiate the process of transcription') is also an independent clause with its own subject ('transcription factors') and verbs ('can access' and 'initiate').
Two independent clauses must be separated by a period, a semicolon, or a comma combined with a coordinating conjunction.
3
Evaluate the options to find the correct punctuation or conjunction that follows standard grammar rules.
The option with a semicolon ('proteins;') is the only grammatically correct way to join these two independent clauses. A comma alone ('proteins,') creates a comma splice; omitting punctuation entirely ('proteins') creates a run-on sentence; and using 'although' ('proteins, although') is logically incorrect because it incorrectly signals a contrast instead of a direct consequence.
Applying these rules identifies the grammatically correct option.

Key Concept

Linking Independent Clauses
Question 1352Question
Consider the system of equations below.
3(x+y)2(xy)=202(x+y)+3(xy)=22\begin{aligned} 3(x + y) - 2(x - y) &= 20 \\ 2(x + y) + 3(x - y) &= 22 \end{aligned}
If (x,y)(x, y) is the solution to the system of equations, what is the value of xx?
Show answer & explanation

Answer: 5

Answer

The value of xx is 55.
Expanding and simplifying the given system yields x+5y=20x + 5y = 20 and 5xy=225x - y = 22. Multiplying the second equation by 5 results in 25x5y=11025x - 5y = 110. Adding this to the first equation eliminates yy, leaving 26x=13026x = 130. Dividing both sides by 26 gives x=5x = 5.

Step-by-Step Solution

1
Expand the algebraic expressions in both equations to rewrite the system in standard form.
x+5y=20x + 5y = 20 and 5xy=225x - y = 22
Expanding the first equation gives 3x+3y2x+2y=203x + 3y - 2x + 2y = 20, which simplifies to x+5y=20x + 5y = 20. Expanding the second equation gives 2x+2y+3x3y=222x + 2y + 3x - 3y = 22, which simplifies to 5xy=225x - y = 22.
2
Multiply the second equation by 5 to align the coefficients of the y-terms.
25x5y=11025x - 5y = 110
Multiplying 5xy=225x - y = 22 by 5 allows the subtraction of yy to cancel with the addition of 5y5y in the first equation.
3
Add the first equation to the modified second equation to eliminate the y-variable and solve for x.
26x=13026x = 130, which simplifies to x=5x = 5.
Adding (x+5y)+(25x5y)=20+110(x + 5y) + (25x - 5y) = 20 + 110 yields 26x=13026x = 130. Dividing by 26 gives the final value of xx.

Key Concept

Solving systems of linear equations using expansion and elimination.

Alternative Method

Define substitution variables u=x+yu = x + y and v=xyv = x - y. The system simplifies to 3u2v=203u - 2v = 20 and 2u+3v=222u + 3v = 22. Multiplying the first equation by 3 and the second by 2 gives 9u6v=609u - 6v = 60 and 4u+6v=444u + 6v = 44. Adding these equations yields 13u=104    u=813u = 104 \implies u = 8. Substituting u=8u = 8 back in gives 16+3v=22    3v=6    v=216 + 3v = 22 \implies 3v = 6 \implies v = 2. Now, solve the system x+y=8x + y = 8 and xy=2x - y = 2. Adding these two equations gives 2x=10    x=52x = 10 \implies x = 5.
Estimated Time:1m 30s
Question 1353Question

A manufacturer produces standard chairs and deluxe chairs. Each standard chair requires 22 hours of assembly and 11 hour of finishing. Each deluxe chair requires 33 hours of assembly and 22 hours of finishing. The manufacturer has a maximum of 240240 hours available for assembly and a maximum of 150150 hours available for finishing each day. Additionally, the manufacturer must produce at least 1010 deluxe chairs daily. If xx represents the number of standard chairs produced daily and yy represents the number of deluxe chairs produced daily, which of the following systems of inequalities best represents this situation?

Show answer & explanation

Answer: 2x+3y240x+2y150y10\begin{aligned} 2x + 3y &\leq 240 \\ x + 2y &\leq 150 \\ y &\geq 10 \end{aligned}

Answer

The system containing 2x+3y2402x + 3y \leq 240, x+2y150x + 2y \leq 150, and y10y \geq 10.
The correct system represents each constraint accurately. The assembly time requirement is 2x+3y2402x + 3y \leq 240 because standard chairs consume 22 hours each, deluxe chairs consume 33 hours each, and the total cannot exceed 240240. The finishing time requirement is x+2y150x + 2y \leq 150 since standard chairs consume 11 hour each, deluxe chairs consume 22 hours each, and the total cannot exceed 150150. Finally, the requirement to produce at least 1010 deluxe chairs means y10y \geq 10.

Step-by-Step Solution

1
Set up the inequality for assembly time.
2x+3y2402x + 3y \leq 240
Each standard chair (xx) needs 22 hours and each deluxe chair (yy) needs 33 hours, with a maximum limit of 240240 hours.
2
Set up the inequality for finishing time.
x+2y150x + 2y \leq 150
Each standard chair (xx) needs 11 hour and each deluxe chair (yy) needs 22 hours, with a maximum limit of 150150 hours.
3
Set up the inequality for the minimum production limit of deluxe chairs.
y10y \geq 10
The manufacturer must produce at least 1010 deluxe chairs, meaning the quantity must be greater than or equal to 1010.
4
Combine the individual inequalities into a single system.
The final system is 2x+3y2402x + 3y \leq 240, x+2y150x + 2y \leq 150, and y10y \geq 10.
All three conditions must be satisfied simultaneously.

Key Concept

Systems of Linear Inequalities in Two Variables
Question 1354Question

The passage below is from an essay about ancient Roman engineering. Which form of the verb 'remove' completes the passage so that it conforms to the conventions of Standard English?

Fill in the blanks below

In his analysis of ancient Roman infrastructure, historian Marcus Vance argues that aqueducts were designed not only to transport freshwater to growing cities but also to waste from public baths. These stone channels represented a major leap in civil engineering, vastly transforming urban sanitation and improving public health across the empire.
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Answer

remove
The sentence employs the correlative conjunction 'not only... but also...' to connect two actions. The first action is expressed using the infinitive construction 'to transport'. To maintain parallel structure, the second action must also use an infinitive construction. Because the word 'to' precedes the blank in the sentence ('but also to {{blank_1}}'), the blank must be filled with the base verb 'remove' to form the parallel infinitive 'to remove'.

Step-by-Step Solution

1
Identify the grammatical construction linking the elements in the sentence.
The sentence uses the correlative conjunction 'not only... but also...' to link two parallel actions.
Correlative conjunctions require the phrases they connect to be grammatically parallel.
2
Determine the grammatical form of the first element in the parallel construction.
The first element is the infinitive phrase 'to transport freshwater'.
This establishes that the second element must also use an infinitive verb form.
3
Select the form of the verb 'remove' that completes the second infinitive phrase parallel to 'to transport'.
Since the preposition 'to' is already present before the blank ('but also to {{blank_1}}'), the blank must be completed with the base form of the verb: 'remove'.
This creates the parallel construction 'not only to transport... but also to remove...'.

Key Concept

Parallel Structure with Correlative Conjunctions
Estimated Time:1m 0s
Question 1355Question

A worker at a distribution center packages boxes at a constant rate. The total number of boxes, BB, the worker has packaged hh hours after starting their shift can be modeled by the equation B=12h+15B = 12h + 15. According to the model, how many boxes were already packaged at the start of the worker's shift?

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Answer: 15

Answer

At the start of the worker's shift, 1515 boxes were already packaged.
In the linear model B=12h+15B = 12h + 15, the term 1515 is the constant term (y-intercept), which represents the value of BB when h=0h = 0. In this context, h=0h = 0 represents the start of the worker's shift. Therefore, 1515 boxes were already packaged at the start of the shift.

Step-by-Step Solution

1
Identify the value of hh that represents the start of the shift.
h=0h = 0
The variable hh represents the number of hours since the shift started, so the start of the shift corresponds to 00 hours.
2
Substitute h=0h = 0 into the given equation to find the value of BB.
B=15B = 15
Evaluating the equation at h=0h = 0 gives the initial number of packaged boxes, which is represented by the constant term of the linear equation.

Key Concept

Interpreting the y-intercept of a linear relationship in context
Question 1356Question

In the xyxy-plane, the graph of the linear equation ax+by=cax + by = c, where aa, bb, and cc are constants, has a slope of 23\frac{2}{3} and passes through the point (6,5)(6, 5). If a+b=5a + b = 5, what is the value of cc?

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Answer: 15

Answer

15
Rearranging the linear equation ax+by=cax + by = c into slope-intercept form y=abx+cby = -\frac{a}{b}x + \frac{c}{b} shows the slope is ab-\frac{a}{b}. Setting ab=23-\frac{a}{b} = \frac{2}{3} gives 2b=3a2b = -3a, or b=1.5ab = -1.5a. Substituting this into a+b=5a + b = 5 yields a1.5a=5a - 1.5a = 5, which simplifies to 0.5a=5-0.5a = 5, so a=10a = -10. This means b=1.5(10)=15b = -1.5(-10) = 15. Substituting the values of a=10a = -10 and b=15b = 15 along with the point (6,5)(6, 5) into the equation ax+by=cax + by = c yields (10)(6)+(15)(5)=15(-10)(6) + (15)(5) = 15, so the value of cc is 1515.

Step-by-Step Solution

1
Rewrite the standard form equation ax+by=cax + by = c in slope-intercept form.
y=abx+cby = -\frac{a}{b}x + \frac{c}{b}
This allows the identification of the slope of the line in terms of the coefficients aa and bb.
2
Set the slope expression equal to the given slope of 23\frac{2}{3} and solve for bb in terms of aa.
b=1.5ab = -1.5a
The slope of the line is ab-\frac{a}{b}, so ab=23    2b=3a    b=1.5a-\frac{a}{b} = \frac{2}{3} \implies 2b = -3a \implies b = -1.5a.
3
Substitute b=1.5ab = -1.5a into the given equation a+b=5a + b = 5 and solve for aa, then find bb.
a=10a = -10 and b=15b = 15
Substituting gives a1.5a=5    0.5a=5    a=10a - 1.5a = 5 \implies -0.5a = 5 \implies a = -10. Substituting a=10a = -10 back into the relationship gives b=1.5(10)=15b = -1.5(-10) = 15.
4
Substitute a=10a = -10, b=15b = 15, and the point (6,5)(6, 5) into the equation ax+by=cax + by = c and solve for cc.
c=15c = 15
(10)(6)+(15)(5)=c    60+75=15    c=15(-10)(6) + (15)(5) = c \implies -60 + 75 = 15 \implies c = 15.

Key Concept

Linear Equations in Two Variables
Question 1357Question

A hiker begins a climb at an elevation of 1,2001,200 feet above sea level and climbs at a constant rate of 350350 feet per hour. The hiker's elevation, EE, in feet, tt hours after beginning the climb is given by the equation E=350t+1,200E = 350t + 1,200. Which of the following is the best interpretation of 350350 in this context?

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Answer: The increase in the hiker's elevation, in feet, for each hour of climbing

Answer

The increase in the hiker's elevation, in feet, for each hour of climbing
The coefficient of tt, which is 350350, represents the rate of change of the hiker's elevation with respect to time. Since elevation is measured in feet and time is measured in hours, this rate is 350350 feet per hour. Therefore, the value 350350 represents the increase in the hiker's elevation, in feet, for each hour of climbing.

Step-by-Step Solution

1
Identify the structure of the linear equation.
The equation E=350t+1,200E = 350t + 1,200 is in the slope-intercept form y=mx+by = mx + b, where m=350m = 350 is the slope and b=1,200b = 1,200 is the yy-intercept.
Linear equations in context have constant rates of change (slope) and starting values (yy-intercept).
2
Determine the meaning of the slope in context.
The slope 350350 represents the change in the dependent variable EE (elevation in feet) per unit change in the independent variable tt (time in hours).
The unit of the slope is the unit of the dependent variable divided by the unit of the independent variable, which is feet per hour.
3
Interpret the positive sign of the slope.
Since 350350 is positive, the elevation increases by 350350 feet for each hour of climbing.
A positive slope indicates a constant increase over time.

Key Concept

Interpreting slope in a linear context
Question 1358Question

For all positive real numbers aa and bb such that aba \neq b, which of the following is equivalent to the expression a3/2b3/2ab\frac{a^{3/2} - b^{3/2}}{\sqrt{a} - \sqrt{b}}?

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Answer: a+ab+ba + \sqrt{ab} + b

Answer

a+ab+ba + \sqrt{ab} + b
The correct answer is obtained by expressing the numerator as a difference of cubes: (a)3(b)3(\sqrt{a})^3 - (\sqrt{b})^3. Factoring this expression gives (ab)(a+ab+b)(\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b). Since aba \neq b, dividing by the denominator ab\sqrt{a} - \sqrt{b} simplifies the expression to a+ab+ba + \sqrt{ab} + b.

Step-by-Step Solution

1
Rewrite the terms in the numerator using square roots to reveal a difference of cubes pattern.
a3/2=(a)3a^{3/2} = (\sqrt{a})^3 and b3/2=(b)3b^{3/2} = (\sqrt{b})^3, so the numerator is (a)3(b)3(\sqrt{a})^3 - (\sqrt{b})^3.
This allows us to factor the numerator using the algebraic identity for the difference of two cubes.
2
Factor the numerator using the difference of cubes formula: u3v3=(uv)(u2+uv+v2)u^3 - v^3 = (u - v)(u^2 + uv + v^2).
(a)3(b)3=(ab)(a+ab+b)(\sqrt{a})^3 - (\sqrt{b})^3 = (\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b) where u=au = \sqrt{a} and v=bv = \sqrt{b}.
Factoring allows us to identify common factors shared with the denominator.
3
Substitute the factored expression back into the fraction and cancel the common factor of ab\sqrt{a} - \sqrt{b}.
(ab)(a+ab+b)ab=a+ab+b\frac{(\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b)}{\sqrt{a} - \sqrt{b}} = a + \sqrt{ab} + b.
Since aba \neq b, ab0\sqrt{a} - \sqrt{b} \neq 0, which makes it mathematically valid to divide by this term.

Key Concept

Equivalent algebraic expressions involving fractional exponents and difference of cubes factoring

Alternative Method

Let a=4a = 4 and b=1b = 1. Substitute these values into the original expression: 43/213/241=8121=7\frac{4^{3/2} - 1^{3/2}}{\sqrt{4} - \sqrt{1}} = \frac{8 - 1}{2 - 1} = 7. Now substitute these same values into each option to see which one evaluates to 7. The correct option evaluates to 4+4(1)+1=74 + \sqrt{4(1)} + 1 = 7.
Estimated Time:2m 0s
Question 1359Question

If the solution to the inequality a(23x)4(x+3)12a(2 - 3x) - 4(x + 3) \ge 12, where aa is a constant, is x1x \le -1, what is the value of aa?

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Answer: 4

Answer

The value of aa is 44.
To solve the inequality a(23x)4(x+3)12a(2 - 3x) - 4(x + 3) \ge 12, we first expand it to get 2a3ax4x12122a - 3ax - 4x - 12 \ge 12. Grouping the xx terms gives (3a4)x242a(-3a - 4)x \ge 24 - 2a. Since the inequality's solution is x1x \le -1, the direction of the inequality must flip, which means the coefficient of xx, namely 3a4-3a - 4, must be negative. Dividing both sides by this coefficient gives the boundary value of the inequality as 242a3a4\frac{24 - 2a}{-3a - 4}. Setting this boundary equal to 1-1 yields 242a=3a+424 - 2a = 3a + 4, which simplifies to 5a=205a = 20, or a=4a = 4. Since a=4a = 4 makes the coefficient 3(4)4=16-3(4) - 4 = -16 negative, the solution holds.

Step-by-Step Solution

1
Expand the inequality using the distributive property.
2a3ax4x12122a - 3ax - 4x - 12 \ge 12
This allows us to separate and group the terms containing the variable xx and the constant terms.
2
Group like terms and isolate the variable terms on the left-hand side.
(3a4)x242a(-3a - 4)x \ge 24 - 2a
By combining the coefficients of xx and adding 122a12 - 2a to both sides, we prepare the inequality to solve for xx.
3
Determine the effect of dividing by the variable's coefficient.
Since the given solution is x1x \le -1, the inequality sign flipped from \ge to \le. Therefore, the coefficient 3a4-3a - 4 must be negative.
Multiplying or dividing both sides of an inequality by a negative number reverses the direction of the inequality sign.
4
Set the boundary value of the solution equal to 1-1 and solve for aa.
a=4a = 4
Setting the boundary of the inequality 242a3a4\frac{24 - 2a}{-3a - 4} equal to 1-1 allows us to find the specific constant aa that produces this solution set.

Key Concept

Solving linear inequalities in one variable involving parameters and sign flips.
Question 1360Question

For all x>1x > 1, which of the following is equivalent to the expression 2x25x32x+1(x4)\frac{2x^2 - 5x - 3}{2x + 1} - (x - 4)?

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Answer: 1

Answer

1
The correct answer is 11. Factoring the numerator of the rational expression gives 2x25x3=(2x+1)(x3)2x^2 - 5x - 3 = (2x + 1)(x - 3). Since x>1x > 1, the denominator 2x+12x + 1 is non-zero, allowing the expression to be simplified to x3x - 3. Subtracting (x4)(x - 4) and distributing the negative sign to both terms inside the parentheses yields (x3)(x4)=x3x+4=1(x - 3) - (x - 4) = x - 3 - x + 4 = 1.

Step-by-Step Solution

1
Factor the quadratic expression in the numerator of the rational term.
2x25x3=(2x+1)(x3)2x^2 - 5x - 3 = (2x + 1)(x - 3)
This allows for the identification of common factors that can be simplified with the denominator.
2
Simplify the rational expression by canceling the common factor in the numerator and denominator.
(2x+1)(x3)2x+1=x3\frac{(2x + 1)(x - 3)}{2x + 1} = x - 3
Since x>1x > 1, the term 2x+12x + 1 is positive and non-zero, making the division valid.
3
Subtract the linear expression from the simplified rational expression, distributing the negative sign to both terms inside the parentheses.
(x3)(x4)=x3x+4=1(x - 3) - (x - 4) = x - 3 - x + 4 = 1
This performs the final subtraction and simplifies the expression to its equivalent constant form.

Key Concept

Simplifying rational expressions by factoring and performing operations on equivalent expressions
Estimated Time:1m 15s
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