Tables and Data Grids Practice Questions — State PSC Exam

Question 1Question →

The table below presents the quarterly administrative software licensing costs (in ₹ Lakhs) for four governmental departments during the fiscal year 2025-26:

Department	Q1	Q2	Q3	Q4
Dept A	45	50	60	55
Dept B	30	35	40	45
Dept C	80	75	90	120
Dept D	25	30	35	40

What is the absolute difference in Rupees between the average quarterly cost of Dept C and the combined cost of Dept B in the first half of the fiscal year (Q1 and Q2)?

₹ 26.25

₹ 58,75,000

₹ 26,25,000

₹ 2,10,00,000

Show answer & explanation

Answer: ₹ 26,25,000

Answer

₹ 26,25,000

The average quarterly cost for Dept C is calculated by adding its four quarters and dividing by 4: (80 + 75 + 90 + 120) / 4 = 365 / 4 = 91.25 Lakhs. The combined cost for Dept B in Q1 and Q2 is 30 + 35 = 65 Lakhs. The absolute difference is 91.25 - 65 = 26.25 Lakhs. Since the table scale is in Lakhs (where 1 Lakh = 1,00,000), the absolute difference in Rupees is 26.25 * 1,00,000 = ₹ 26,25,000.

Step-by-Step Solution

1

Calculate the average quarterly cost for Dept C.

91.25 Lakhs

The average is the total of all four quarters divided by 4: (80 + 75 + 90 + 120) / 4 = 365 / 4 = 91.25.

2

Calculate the combined cost for Dept B in the first half of the year (Q1 and Q2).

65 Lakhs

The combined cost is the direct sum of Q1 and Q2 values: 30 + 35 = 65.

3

Find the absolute numeric difference between the two calculated values.

26.25

91.25 - 65 = 26.25.

4

Convert the numeric difference into actual Rupees using the scale multiplier.

₹ 26,25,000

The table header specifies the values are in '₹ Lakhs'. 1 Lakh is equal to 1,00,000. Multiplying 26.25 by 1,00,000 gives 26,25,000.

Key Concept

Extracting targeted data points from a grid, calculating averages and sums, and applying chart scale multipliers accurately.

Question 2Question →

The table below presents the quarterly renewable energy generation (in Megawatts, MW) of four geographical zones of a state in 2025:

Zone	Q1 (MW)	Q2 (MW)	Q3 (MW)	Q4 (MW)
North Zone	120	150	180	150
South Zone	200	220	250	210
East Zone	90	110	130	110
West Zone	160	180	200	160

Based on the table, what is the average quarterly renewable energy generation (in MW) for the South Zone in 2025?

Show answer & explanation

Answer: 220

Answer

The average quarterly renewable energy generation for the South Zone in 2025 is

220\text{ MW}

.

The correct average is obtained by summing the four quarterly generation figures of the South Zone (

200 + 220 + 250 + 210 = 880\text{ MW}

) and dividing by

4

, giving

220\text{ MW}

.

Step-by-Step Solution

1

Locate the row for the South Zone and extract data for all four quarters.

Q1 =

200\text{ MW}

, Q2 =

220\text{ MW}

, Q3 =

250\text{ MW}

, Q4 =

210\text{ MW}

.

Data needs to be aggregated across the full year.

2

Calculate total annual generation for the South Zone.

Total =

200 + 220 + 250 + 210 = 880\text{ MW}

.

Summing values is required before finding the average.

3

Divide total generation by the number of quarters.

Average =

\frac{880}{4} = 220\text{ MW}

.

An average across four periods requires dividing the total sum by 4.

Key Concept

Average calculation from a tabular dataset

Question 3Question →

The table below shows the annual wheat production (in metric tonnes) across four agricultural zones from 2021 to 2023:

Agricultural Zone	2021	2022	2023
Zone A	150	180	210
Zone B	200	250	300
Zone C	100	120	150
Zone D	300	330	360

Which of the following statements regarding the data given in the table are correct?

Select all that apply

Zone A registered a

20\%

growth in wheat production from 2021 to 2022.

In 2023, the wheat production of Zone B was exactly double that of Zone C.

The percentage increase in wheat production for Zone D from 2021 to 2022 was

15\%

.

Zone C produced a total of

400

metric tonnes of wheat over the three-year period from 2021 to 2023.

Show answer & explanation

Answer: Zone A registered a $20\%$ growth in wheat production from 2021 to 2022.; In 2023, the wheat production of Zone B was exactly double that of Zone C.

Answer

The correct statements are that Zone A registered a

20\%

growth in wheat production from 2021 to 2022, and in 2023, the wheat production of Zone B was exactly double that of Zone C.

Zone A's production grew from

150

to

180

tonnes, which is a growth of

\frac{30}{150} \times 100\% = 20\%

. In 2023, Zone B produced

300

tonnes while Zone C produced

150

tonnes, making Zone B's production exactly double that of Zone C.

Step-by-Step Solution

1

Calculate the percentage growth for Zone A from 2021 to 2022.

Percentage increase =

\frac{180 - 150}{150} \times 100\% = 20\%

. Statement is correct.

To verify the growth statement for Zone A using the base year 2021 value (

150

).

2

Compare Zone B and Zone C production figures for the year 2023.

Zone B produced

300

tonnes and Zone C produced

150

tonnes. Ratio =

\frac{300}{150} = 2

. Statement is correct.

To check if Zone B production was double that of Zone C in 2023.

3

Calculate the percentage increase for Zone D from 2021 to 2022.

Percentage increase =

\frac{330 - 300}{300} \times 100\% = 10\% \neq 15\%

. Statement is incorrect.

To evaluate the claim regarding Zone D's percentage growth.

4

Calculate the total wheat production of Zone C across 2021, 2022, and 2023.

Total =

100 + 120 + 150 = 370

tonnes

\neq 400

tonnes. Statement is incorrect.

To verify the three-year total production claim for Zone C.

Key Concept

Tabular Data Interpretation and Percentage Growth Analysis

Question 4Question →

The table below details the renewable energy generation (in Gigawatt-hours, GWh) across four zones in 2025:

Zone	Solar	Wind	Hydro	Biomass
North	120	150	200	50
South	180	220	160	40
East	90	60	250	80
West	210	190	100	70

What is the total solar energy generation (in GWh) across all four zones combined in 2025?

Show answer & explanation

Answer: 600

Answer

The total solar energy generation across all four zones in 2025 is 600 GWh.

Summing the values in the Solar column (

120 + 180 + 90 + 210

) yields a total of

600

GWh.

Step-by-Step Solution

1

Locate and extract the values under the 'Solar' column for all four zones.

North = 120, South = 180, East = 90, West = 210.

The question asks specifically for total solar energy generation.

2

Sum the extracted values across all rows.

120 + 180 + 90 + 210 = 600

GWh.

Combining values across all four zones yields the overall total for the solar category.

Key Concept

Data Extraction and Summation from Tables

Question 5Question →

The table below presents the operational metrics for Agricultural Processing Units across four districts of a state for FY 2025–26:

District	Total Processing Capacity (in '000 MT)	Operational Units Count	Total Raw Produce Received (in '000 MT)	Processing Efficiency Rate (%)
District A	450	18	360	$85\%$
District B	600	24	480	$90\%$
District C	500	20	420	$80\%$
District D	350	14	320	$75\%$

*Note: Processing Efficiency Rate is defined as the percentage of Total Raw Produce Received that is converted into finished products. The remaining portion of received raw produce is lost as processing waste.*

What is the overall average processing waste (in '000 Metric Tonnes) per operational unit across all four districts combined?

Show answer & explanation

Answer: 3.5

Answer

The overall average processing waste per operational unit across all four districts combined is

3.5

thousand Metric Tonnes.

The correct answer is derived by first finding the waste volume for each district based on raw produce received: District A (

360 \times 0.15 = 54

), District B (

480 \times 0.10 = 48

), District C (

420 \times 0.20 = 84

), and District D (

320 \times 0.25 = 80

). Summing these gives a combined total waste of

266

thousand MT. Dividing this total waste by the total count of operational units (

18 + 24 + 20 + 14 = 76

) yields

\frac{266}{76} = 3.5

thousand MT per unit.

Step-by-Step Solution

1

Calculate the processing waste percentage for each district

District A waste rate =

100\% - 85\% = 15\%

; District B waste rate =

100\% - 90\% = 10\%

; District C waste rate =

100\% - 80\% = 20\%

; District D waste rate =

100\% - 75\% = 25\%

.

Processing waste is the complement of processing efficiency rate.

2

Calculate total processing waste generated in each district in '000 MT

District A waste =

360 \times 0.15 = 54

'000 MT; District B waste =

480 \times 0.10 = 48

'000 MT; District C waste =

420 \times 0.20 = 84

'000 MT; District D waste =

320 \times 0.25 = 80

'000 MT.

Absolute waste is obtained by multiplying Total Raw Produce Received by the waste rate.

3

Calculate total waste and total operational units across all four districts combined

Total Waste =

54 + 48 + 84 + 80 = 266

'000 MT. Total Operational Units =

18 + 24 + 20 + 14 = 76

units.

Aggregating metrics across districts is required to find the combined weighted average.

4

Divide total combined waste by total combined operational units

Average Waste per Unit =

\frac{266}{76} = 3.5

'000 MT per unit.

Overall average metric equals total aggregate waste divided by total aggregate count of units.

Key Concept

Weighted Average and Percentage Calculation from Data Grids

Estimated Time:2m 30s

Question 6Question →

The table below presents the operational performance and energy distribution metrics of four regional power grids during FY 2025–26. Net available energy for distribution is determined by first deducting transmission and storage losses from total generation, and then subtracting auxiliary station consumption.

Regional Grid	Total Energy Generated (GWh)	Transmission & Storage Loss (%)	Auxiliary Station Consumption (GWh)	Commercial Sector Share of Net Available Energy (%)
Northern Grid	12,000	15%	200	40%
Southern Grid	15,000	12%	400	35%
Eastern Grid	10,000	20%	300	50%
Western Grid	18,000	10%	200	25%

Based on the data provided, what is the ratio of the total energy distributed to the commercial sector by the Southern Grid to the combined energy distributed to the commercial sector by the Northern and Western Grids?

14 : 25

97 : 178

154 : 271

21 : 40

Show answer & explanation

Answer: 14 : 25

Answer

The ratio of energy distributed to the commercial sector by the Southern Grid to the combined commercial distribution of the Northern and Western Grids is 14 : 25.

The correct option stating '14 : 25' accurately follows the prescribed two-stage deduction process. For the Southern Grid, subtracting 12% loss (

1,800\text{ GWh}

) from

15,000\text{ GWh}

gives

13,200\text{ GWh}

, and subtracting

400\text{ GWh}

auxiliary consumption leaves

12,800\text{ GWh}

. Applying

35\%

yields

4,480\text{ GWh}

. For the Northern Grid, net energy is

(12,000 - 1,800) - 200 = 10,000\text{ GWh}

, giving

40\% \times 10,000 = 4,000\text{ GWh}

. For the Western Grid, net energy is

(18,000 - 1,800) - 200 = 16,000\text{ GWh}

, giving

25\% \times 16,000 = 4,000\text{ GWh}

. Combining Northern and Western gives

8,000\text{ GWh}

. The ratio

\frac{4,480}{8,000}

simplifies precisely to

14 : 25

.

Step-by-Step Solution

1

Calculate the net available energy and commercial distribution for the Southern Grid.

Net Available =

(15,000 - 0.12 \times 15,000) - 400 = (15,000 - 1,800) - 400 = 12,800\text{ GWh}

. Commercial Distribution =

35\% \text{ of } 12,800 = 4,480\text{ GWh}

.

Transmission loss must be deducted from total generation first, followed by auxiliary consumption.

2

Calculate the net available energy and commercial distribution for the Northern Grid.

Net Available =

(12,000 - 0.15 \times 12,000) - 200 = (12,000 - 1,800) - 200 = 10,000\text{ GWh}

. Commercial Distribution =

40\% \text{ of } 10,000 = 4,000\text{ GWh}

.

Required to compute the combined baseline for Northern and Western grids.

3

Calculate the net available energy and commercial distribution for the Western Grid.

Net Available =

(18,000 - 0.10 \times 18,000) - 200 = (18,000 - 1,800) - 200 = 16,000\text{ GWh}

. Commercial Distribution =

25\% \text{ of } 16,000 = 4,000\text{ GWh}

.

Required to complete the denominator sum of the target ratio.

4

Compute the target ratio of Southern Grid commercial distribution to Northern + Western Grid commercial distribution.

Combined Northern + Western =

4,000 + 4,000 = 8,000\text{ GWh}

. Ratio =

4,480 : 8,000 = 14 : 25

.

Simplifying

\frac{4,480}{8,000}

by dividing both terms by their greatest common divisor

160

yields

14 : 25

.

Key Concept

Multi-step tabular data interpretation involving sequential percentage reduction, absolute deductions, and ratio simplification.

Question 7Question →

The table below details raw material procurement, fabric output, and sales revenues across four regional textile development clusters for FY 2024–25:

Textile Cluster	Raw Cotton Procured ('000 MT)	Fabric Produced ('000 metres)	Export Value (₹ Crores)	Domestic Sales (₹ Crores)
Cluster A	40	320	160	240
Cluster B	50	500	300	200
Cluster C	60	480	240	360
Cluster D	30	240	180	120

What is the absolute difference (in ₹ Crores) between the average domestic sales across all four clusters and the domestic sales of the cluster that achieved the highest fabric production efficiency per unit of raw cotton procured?

₹30 Crores

₹50 Crores

₹130 Crores

₹30,000

Show answer & explanation

Answer: ₹30 Crores

Answer

The absolute difference is ₹30 Crores.

The correct answer is ₹30 Crores. Fabric production efficiency per unit of raw cotton is calculated as Fabric Produced ('000 metres) divided by Raw Cotton Procured ('000 MT). Cluster B yields 500 / 50 = 10 metres/MT, which is the highest among all clusters (others yield 8 metres/MT). Cluster B's domestic sales are ₹200 Crores. The average domestic sales across all clusters is (240 + 200 + 360 + 120) / 4 = ₹230 Crores. The absolute difference between ₹230 Crores and ₹200 Crores is ₹30 Crores.

Step-by-Step Solution

1

Calculate fabric production efficiency per unit of raw cotton procured for each cluster

Cluster A: 320 / 40 = 8 metres/MT; Cluster B: 500 / 50 = 10 metres/MT; Cluster C: 480 / 60 = 8 metres/MT; Cluster D: 240 / 30 = 8 metres/MT.

To identify which cluster achieved the highest fabric production per unit of raw cotton procured.

2

Identify the domestic sales of the most efficient cluster

Cluster B achieved the highest efficiency (10 metres/MT). Its domestic sales volume is ₹200 Crores.

This provides the targeted cluster's metric for comparison.

3

Calculate the average domestic sales across all four clusters

Total Domestic Sales = 240 + 200 + 360 + 120 = ₹920 Crores. Average Domestic Sales = 920 / 4 = ₹230 Crores.

To determine the benchmark average domestic sales across the dataset.

4

Compute the absolute difference

| ₹230 Crores - ₹200 Crores | = ₹30 Crores.

To answer the final question requirement.

Key Concept

Data grid ratio comparison and benchmark deviation analysis

Question 8Question →

The table below presents the organic horticulture harvest (in metric tonnes) across four agricultural zones in a state for the years 2022 to 2025:

Agricultural Zone	2022	2023	2024	2025
Zone A	320	360	400	480
Zone B	450	500	550	620
Zone C	280	310	350	420
Zone D	550	630	700	780

Based on the table, what is the percentage share of Zone B in the total horticulture harvest across all four agricultural zones combined in the year 2024?

Show answer & explanation

Answer: 27.5

Answer

The percentage share of Zone B in the total horticulture harvest across all four zones combined in 2024 is

27.5\%

.

The total harvest across all four zones in 2024 is

400 + 550 + 350 + 700 = 2000

metric tonnes. Zone B contributed

550

metric tonnes in 2024. Dividing

550

by

2000

and multiplying by

100

yields exactly

27.5\%

.

Step-by-Step Solution

1

Calculate total harvest for all zones in 2024

Total harvest in 2024 =

400 + 550 + 350 + 700 = 2000

metric tonnes

To find the baseline total harvest across all zones for the target year.

2

Locate the specific harvest for Zone B in 2024

Zone B harvest in 2024 =

550

metric tonnes

To isolate the target numerator specified in the question.

3

Compute the percentage share

Percentage share =

\left( \frac{550}{2000} \right) \times 100 = 27.5\%

Dividing the specific zone harvest by the total harvest yields the fractional share, which is converted to percentage by multiplying by 100.

Key Concept

Tabular Percentage Share Calculation

Estimated Time:1m 30s

Question 9Question →

The table below presents the operational metrics for four Inland Freight Terminals in a state for FY 2025–26:

Freight Terminal	Total Cargo Handled (in thousand metric tonnes)	Rail Transshipment Share (%)	Average Dwell Time per Container (days)	Revenue Generated per Tonne (₹)
North	450	40%	4.5	800
South	600	65%	3.0	750
East	350	50%	5.0	900
West	500	30%	6.0	850

What is the total revenue generated from cargo moved specifically via rail transshipment across all four freight terminals combined during FY 2025–26?

₹7.215 crore

₹72.15 crore

₹82.85 crore

₹71.69 crore

Show answer & explanation

Answer: ₹72.15 crore

Answer

₹72.15 crore

To find the total rail transshipment revenue, compute the rail-moved tonnage for each terminal: North (1.80 lakh tonnes), South (3.90 lakh tonnes), East (1.75 lakh tonnes), and West (1.50 lakh tonnes). Multiplying each by its respective revenue per tonne yields ₹14.40 crore, ₹29.25 crore, ₹15.75 crore, and ₹12.75 crore. Summing these four values gives exactly ₹72.15 crore.

Step-by-Step Solution

1

Convert cargo volumes from thousand metric tonnes to tonnes for each terminal

North: 4,50,000 tonnes; South: 6,00,000 tonnes; East: 3,50,000 tonnes; West: 5,00,000 tonnes.

The table header specifies cargo handled in 'thousand metric tonnes'.

2

Calculate the rail transshipment volume for each terminal

North: 4,50,000 × 40% = 1,80,000 tonnes
South: 6,00,000 × 65% = 3,90,000 tonnes
East: 3,50,000 × 50% = 1,75,000 tonnes
West: 5,00,000 × 30% = 1,50,000 tonnes

Rail transshipment share percentage is applied to total cargo volume of each terminal.

3

Compute revenue from rail transshipment for each terminal

North: 1,80,000 × ₹800 = ₹14,40,00,000 (₹14.40 crore)
South: 3,90,000 × ₹750 = ₹29,25,00,000 (₹29.25 crore)
East: 1,75,000 × ₹900 = ₹15,75,00,000 (₹15.75 crore)
West: 1,50,000 × ₹850 = ₹12,75,00,000 (₹12.75 crore)

Multiply rail transshipment tonnes by revenue per tonne.

4

Sum the rail transshipment revenues across all terminals

₹14.40 crore + ₹29.25 crore + ₹15.75 crore + ₹12.75 crore = ₹72.15 crore (₹72,15,00,000).

Total combined rail revenue is the sum of terminal-level rail revenues.

Key Concept

Multi-step weighted calculation from data grids involving unit scale factors and percentages.

Question 10Question →

The table below presents the operational and processing metrics for four municipal water treatment plants in a coastal state for FY 2025–26:

Plant Location	Total Raw Water Processed (Million Liters)	Purified Water Output (%)	Operational Cost per Million Liters (₹ Thousand)
Northern Zone	450	80%	12
Southern Zone	600	85%	10
Eastern Zone	500	78%	15
Western Zone	750	92%	14

Based on the table above, calculate the average volume of purified water output (in Million Liters) produced per plant across the four zones.

Show answer & explanation

Answer: 487.5

Answer

The average volume of purified water output per plant is

487.5

Million Liters.

The purified water volume outputs for Northern, Southern, Eastern, and Western zones are

360

,

510

,

390

, and

690

Million Liters respectively. Summing these values gives a total output of

1950

Million Liters. Dividing this total by the

4

plants gives an average purified water output of

487.5

Million Liters per plant.

Step-by-Step Solution

1

Calculate the purified water volume for each of the four treatment plants

Northern Zone =

360

Million Liters, Southern Zone =

510

Million Liters, Eastern Zone =

390

Million Liters, Western Zone =

690

Million Liters

Purified water output volume is calculated by multiplying Total Raw Water Processed by the Purified Water Output percentage.

2

Sum the purified water volumes across all four zones

Total purified output =

1950

Million Liters

The aggregate sum is required to compute the mean value across all plants.

3

Divide the total purified output by the number of plants (4)

Average purified output =

487.5

Million Liters

Dividing the total sum by the count of entities yields the arithmetic average.

Key Concept

Tabular Data Extraction and Weighted Average Calculation

Question 11Question →

The table below presents the operational and storage metrics for the State Warehousing Corporation across four district hubs for FY 2024–25:

District Hub	Total Storage Capacity ('000 MT)	Actual Grain Stored ('000 MT)	Spoilage Rate (%)	Milling Processing Fee (₹/MT)
Hub Alpha	$250$	$200$	$4\%$	$150$
Hub Beta	$400$	$350$	$2\%$	$120$
Hub Gamma	$300$	$240$	$5\%$	$200$
Hub Delta	$500$	$450$	$3\%$	$100$

Note: $1\text{ MT} = 1\text{ Metric Tonne}$ ; figures in capacity and stored columns are in thousands of MT.

If the government procurement cost of grain is $₹20,000$ per Metric Tonne, what is the total financial loss (in $₹\text{ Lakhs}$ ) incurred due to grain spoilage across Hub Alpha and Hub Gamma combined?

₹4,000\text{ Lakhs}

₹5,000\text{ Lakhs}

₹1,600\text{ Lakhs}

₹4\text{ Lakhs}

Show answer & explanation

Answer: $₹4,000\text{ Lakhs}$

Answer

The total financial loss incurred due to grain spoilage across Hub Alpha and Hub Gamma combined is

₹4,000\text{ Lakhs}

.

To find the total financial loss due to spoilage across Hub Alpha and Hub Gamma, we calculate the spoiled quantity for each hub based on the actual grain stored (in MT):
- Hub Alpha:

200,000\text{ MT} \times 4\% = 8,000\text{ MT}

- Hub Gamma:

240,000\text{ MT} \times 5\% = 12,000\text{ MT}

Total spoiled quantity

= 8,000 + 12,000 = 20,000\text{ MT}

.
At

₹20,000

per MT, total loss

= 20,000 \times 20,000 = ₹400,000,000

. Expressed in Lakhs (

1\text{ Lakh} = 100,000

), this equals

₹4,000\text{ Lakhs}

.

Step-by-Step Solution

1

Calculate the actual quantity of spoiled grain in Hub Alpha

Spoiled grain in Alpha =

4\% \times 200,000\text{ MT} = 8,000\text{ MT}

Actual grain stored in Alpha is

200 \times 1,000 = 200,000\text{ MT}

and spoilage rate is

4\%

.

2

Calculate the actual quantity of spoiled grain in Hub Gamma

Spoiled grain in Gamma =

5\% \times 240,000\text{ MT} = 12,000\text{ MT}

Actual grain stored in Gamma is

240 \times 1,000 = 240,000\text{ MT}

and spoilage rate is

5\%

.

3

Find the combined total quantity of spoiled grain

Total spoiled grain =

8,000\text{ MT} + 12,000\text{ MT} = 20,000\text{ MT}

Combine the spoiled quantities from both hubs.

4

Compute the total financial loss in Rupees and convert to Lakhs

Total Loss =

20,000\text{ MT} \times ₹20,000/\text{MT} = ₹400,000,000 = ₹4,000\text{ Lakhs}

Multiply total spoiled MT by the cost per MT (

₹20,000

) and divide by

100,000

to express in Lakhs.

Key Concept

Data Interpretation from Tables: Multi-step calculation involving unit scale conversion, percentage bases, and aggregation

Question 12Question →

The table below presents the freshwater fish production and pricing metrics across four regional inland lake zones managed by the State Fisheries Development Board for the year 2025:

Lake Zone	Total Catch (in Tonnes)	Export Grade Share (%)	Local Market Price (in ₹ per kg)	Export Market Price (in ₹ per kg)
Lake Alpha	400	30%	150	350
Lake Beta	500	40%	160	400
Lake Gamma	350	20%	140	300
Lake Delta	600	25%	180	420

Note: $1\text{ Tonne} = 1,000\text{ kg}$ and $1\text{ Lakh} = 100,000$ .

Based on the table, calculate the total revenue (in ₹ Lakhs) generated by Lake Beta from both local and export market sales combined.

Show answer & explanation

Answer: 1280

Answer

The total revenue generated by Lake Beta from local and export market sales combined is ₹1,280 Lakhs.

Lake Beta produces

500\text{ tonnes} = 500,000\text{ kg}

of fish.

40\%

of this (

200,000\text{ kg}

) is exported at ₹

400/\text{kg}

, yielding ₹

800\text{ Lakhs}

. The remaining

60\%

(

300,000\text{ kg}

) is sold locally at ₹

160/\text{kg}

, yielding ₹

480\text{ Lakhs}

. Combining both gives ₹

1,280\text{ Lakhs}

.

Step-by-Step Solution

1

Convert the total catch of Lake Beta to kilograms.

500\text{ tonnes} = 500,000\text{ kg}

.

Prices are given per kilogram, so total mass must be in kilograms.

2

Partition the total catch into export grade and local market quantities.

Export quantity =

40\% \times 500,000 = 200,000\text{ kg}

; Local quantity =

60\% \times 500,000 = 300,000\text{ kg}

.

Different market prices apply to export grade vs local grade catch.

3

Calculate monetary revenue for each grade and find their sum in ₹ Lakhs.

Export revenue =

200,000 \times 400 = ₹80,000,000 = ₹800\text{ Lakhs}

; Local revenue =

300,000 \times 160 = ₹48,000,000 = ₹480\text{ Lakhs}

; Total =

800 + 480 = ₹1,280\text{ Lakhs}

.

Summing both revenue streams gives the total earnings for Lake Beta.

Key Concept

Weighted revenue calculation from multi-column tabular data

Estimated Time:1m 30s

Question 13Question →

The following data grid presents the cargo volume handled (in thousands of Metric Tonnes, '000 MT) across five maritime ports from FY 2021–22 to FY 2024–25:

Port	FY 2021–22	FY 2022–23	FY 2023–24	FY 2024–25
Port Alpha	450	540	648	777.6
Port Beta	800	720	648	583.2
Port Gamma	300	375	450	562.5
Port Delta	600	660	792	871.2
Port Epsilon	500	550	605	726

Which of the following statements regarding the performance of these ports are correct? Select all that apply.

Select all that apply

Port Alpha registered a constant year-on-year cargo growth rate of 20% across all three consecutive periods.

The combined total cargo volume handled by all five ports increased by more than 30% in FY 2024–25 compared to FY 2021–22.

Port Beta accounted for more than 20% of the total cargo volume handled across all five ports in FY 2024–25.

Port Gamma achieved the largest absolute increase in cargo volume between FY 2021–22 and FY 2024–25.

Show answer & explanation

Answer: Port Alpha registered a constant year-on-year cargo growth rate of 20% across all three consecutive periods.; The combined total cargo volume handled by all five ports increased by more than 30% in FY 2024–25 compared to FY 2021–22.

Answer

The statements confirming that Port Alpha registered a constant year-on-year growth rate of 20% and that the combined total cargo volume grew by more than 30% are correct.

The statement regarding Port Alpha is correct because the year-on-year growth rate is uniformly

20\%

for every year (

90/450 = 20\%

,

108/540 = 20\%

, and

129.6/648 = 20\%

). The statement regarding combined total growth is also correct because the total cargo grew from

2650

thousand MT to

3520.5

thousand MT, which equals a

32.85\%

increase—clearly exceeding

30\%

.

Step-by-Step Solution

1

Calculate year-on-year percentage growth for Port Alpha.

FY 21–22 to 22–23:

(540 - 450) / 450 = 0.20

(

20\%

). FY 22–23 to 23–24:

(648 - 540) / 540 = 0.20

(

20\%

). FY 23–24 to 24–25:

(777.6 - 648) / 648 = 0.20

(

20\%

).

Verify if the annual growth rate remains constant across all three consecutive periods.

2

Calculate total cargo volume for FY 2021–22 and FY 2024–25 across all ports.

Total FY 2021–22

= 450 + 800 + 300 + 600 + 500 = 2650

thousand MT. Total FY 2024–25

= 777.6 + 583.2 + 562.5 + 871.2 + 726 = 3520.5

thousand MT.

Determine the combined aggregate performance for percentage growth evaluation.

3

Compute total overall growth percentage from FY 2021–22 to FY 2024–25.

Percentage Growth

= \frac{3520.5 - 2650}{2650} \times 100\% = \frac{870.5}{2650} \times 100\% \approx 32.85\%

.

Compare calculated growth (

32.85\%

) against the target threshold of

30\%

.

4

Calculate Port Beta's share of total cargo in FY 2024–25.

Share

= \frac{583.2}{3520.5} \times 100\% \approx 16.57\%

.

Test whether Port Beta's share exceeded

20\%

in FY 2024–25.

5

Compare absolute growth values across all ports between FY 2021–22 and FY 2024–25.

Alpha:

327.6

, Beta:

-216.8

, Gamma:

262.5

, Delta:

271.2

, Epsilon:

226.0

.

Identify the port with the maximum absolute increase.

Key Concept

Tabular Data Interpretation: Multi-Period Rate Analysis and Baseline Distinctions

Question 14Question →

The table below provides operational details regarding procurement, storage loss, public distribution system (PDS) allocation, and unit storage costs for rice across four agricultural zones of a state during FY 2025–26:

Zone	Rice Procured (in '000 MT)	Storage & Transit Loss (% of Procured Rice)	Distribution to PDS (% of Net Retained Rice)	Unit Storage Cost per MT of Net Retained Rice (₹)
Zone Alpha	250	4.0%	80%	₹ 450
Zone Beta	180	5.0%	75%	₹ 500
Zone Gamma	200	2.5%	85%	₹ 400
Zone Delta	300	6.0%	70%	₹ 350

*Note: Net Retained Rice = Total Rice Procured $-$ Storage & Transit Loss.*

What is the total quantity of rice (in MT) retained as undistributed buffer stock across all four zones combined after completing the PDS distribution?

204,600\text{ MT}

215,000\text{ MT}

20,460\text{ MT}

162,600\text{ MT}

Show answer & explanation

Answer: $204,600\text{ MT}$

Answer

204,600\text{ MT}

The correct answer is derived by first subtracting the percentage storage loss from the gross procurement of each zone to establish the net retained rice base (

240,000\text{ MT}

for Alpha,

171,000\text{ MT}

for Beta,

195,000\text{ MT}

for Gamma, and

282,000\text{ MT}

for Delta). Multiplying these net figures by their respective remaining undistributed percentages (

20\%

,

25\%

,

15\%

, and

30\%

) gives buffer quantities of

48,000\text{ MT}

,

42,750\text{ MT}

,

29,250\text{ MT}

, and

84,600\text{ MT}

. The sum of these four quantities equals

204,600\text{ MT}

.

Step-by-Step Solution

1

Convert procured quantities into metric tonnes (MT) and compute net retained rice for each zone.

Zone Alpha:

250,000 \times (1 - 0.04) = 240,000\text{ MT}

.
Zone Beta:

180,000 \times (1 - 0.05) = 171,000\text{ MT}

.
Zone Gamma:

200,000 \times (1 - 0.025) = 195,000\text{ MT}

.
Zone Delta:

300,000 \times (1 - 0.06) = 282,000\text{ MT}

.

Storage loss must be deducted from gross procurement to get net retained rice.

2

Calculate the undistributed buffer stock percentage for each zone.

Zone Alpha:

100\% - 80\% = 20\%

.
Zone Beta:

100\% - 75\% = 25\%

.
Zone Gamma:

100\% - 85\% = 15\%

.
Zone Delta:

100\% - 70\% = 30\%

.

Buffer stock represents the remaining fraction of net retained rice after PDS distribution.

3

Calculate the volume of undistributed buffer stock for each zone.

Zone Alpha:

240,000 \times 0.20 = 48,000\text{ MT}

.
Zone Beta:

171,000 \times 0.25 = 42,750\text{ MT}

.
Zone Gamma:

195,000 \times 0.15 = 29,250\text{ MT}

.
Zone Delta:

282,000 \times 0.30 = 84,600\text{ MT}

.

Multiply net retained rice by the respective buffer stock percentage.

4

Sum the buffer stock volumes across all four zones.

48,000 + 42,750 + 29,250 + 84,600 = 204,600\text{ MT}

.

To find the combined total buffer stock for the state.

Key Concept

Multi-stage sequential percentage calculations on tabular net base values.

Question 15Question →

The table below presents the annual handicraft exports (in ₹ Crore) across four regional development boards from 2021–22 to 2024–25:

Regional Board	2021–22	2022–23	2023–24	2024–25
Northern Region	150	180	200	240
Southern Region	240	260	300	360
Eastern Region	120	150	180	210
Western Region	160	200	250	300

Based on the table, what is the ratio of the total handicraft exports from the Northern and Eastern Regions combined in 2024–25 to the total handicraft exports from the Southern and Western Regions combined in 2021–22?

9 : 8

8 : 9

9 : 22

15 : 7

Show answer & explanation

Answer: 9 : 8

Answer

The correct ratio of exports is 9 : 8.

The total exports from the Northern and Eastern Regions combined in 2024–25 amount to ₹240 Crore + ₹210 Crore = ₹450 Crore. The total exports from the Southern and Western Regions combined in 2021–22 amount to ₹240 Crore + ₹160 Crore = ₹400 Crore. Taking the ratio of 450 to 400 gives 450 : 400, which simplifies directly to 9 : 8.

Step-by-Step Solution

1

Identify and sum the export values for Northern and Eastern Regions for the year 2024–25 from the table grid.

Northern Region (2024–25) = ₹240 Crore; Eastern Region (2024–25) = ₹210 Crore. Total = 240 + 210 = ₹450 Crore.

This establishes the numerator component requested in the question stem.

2

Identify and sum the export values for Southern and Western Regions for the base year 2021–22.

Southern Region (2021–22) = ₹240 Crore; Western Region (2021–22) = ₹160 Crore. Total = 240 + 160 = ₹400 Crore.

This establishes the denominator component requested in the question stem.

3

Form the ratio and simplify to its lowest integer terms.

Ratio = 450 / 400 = 9 / 8, or 9 : 8.

Simplifying by dividing both numbers by their highest common factor (50) yields the final required ratio.

Key Concept

Tabular Data Interpretation and Multi-Cell Ratio Calculation

Estimated Time:1m 30s

Question 16Question →

The table below shows the annual solar power generation (in Megawatts, MW) across four districts (P, Q, R, and S) in a state from 2021 to 2024:

District	2021 (MW)	2022 (MW)	2023 (MW)	2024 (MW)
District P	100	120	150	200
District Q	200	240	300	360
District R	150	180	200	240
District S	50	60	150	200

Based on the table above, which of the following statements are correct?

Select all that apply

District P experienced a 100% increase in solar power generation in 2024 compared to its generation in 2021.

District S contributed the highest percentage share to the total solar power generation in 2023.

The ratio of total solar power generation in 2021 to total solar power generation in 2024 across all four districts is

1 : 2

.

The average annual solar power generation for District R over the four-year period (2021–2024) is

210\text{ MW}

.

Show answer & explanation

Answer: District P experienced a 100% increase in solar power generation in 2024 compared to its generation in 2021.; The ratio of total solar power generation in 2021 to total solar power generation in 2024 across all four districts is $1 : 2$ .

Answer

The correct statements are that District P experienced a 100% increase in solar power generation in 2024 compared to 2021, and the ratio of total solar power generation in 2021 to 2024 across all four districts is 1 : 2.

The statement regarding District P's growth is valid because generation doubled from 100 MW in 2021 to 200 MW in 2024, representing a 100% increase. The statement comparing overall totals is also valid because total generation in 2021 (500 MW) and 2024 (1000 MW) forms a simplified ratio of 1 : 2.

Step-by-Step Solution

1

Evaluate the statement regarding District P's percentage growth from 2021 to 2024.

Percentage Increase =

\frac{200 - 100}{100} \times 100 = 100\%

. This statement is correct.

Calculate relative growth using 2021 as the base year.

2

Evaluate the statement regarding District S's share in 2023.

Total 2023 generation =

150 + 300 + 200 + 150 = 800\text{ MW}

. District Q generated

300\text{ MW}

(

37.5\%

), which is the highest. District S generated

150\text{ MW}

(

18.75\%

). This statement is incorrect.

Determine total generation for 2023 and compare individual district contributions.

3

Evaluate the statement regarding the ratio of total generation in 2021 vs 2024.

Total 2021 generation =

100 + 200 + 150 + 50 = 500\text{ MW}

. Total 2024 generation =

200 + 360 + 240 + 200 = 1000\text{ MW}

. Ratio =

500 : 1000 = 1 : 2

. This statement is correct.

Sum values across all districts for 2021 and 2024, then simplify the resulting ratio.

4

Evaluate the statement regarding District R's annual average generation.

Sum for District R =

150 + 180 + 200 + 240 = 770\text{ MW}

. Average =

\frac{770}{4} = 192.5\text{ MW}

. This statement is incorrect.

Divide total four-year generation for District R by the number of years (4).

Key Concept

Tabular Data Interpretation: Multi-Step Percentage Growth, Aggregation, Ratio Analysis, and Averages

Estimated Time:1m 30s

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