Algebra

282 soru

Soru 241Soru →

Simplify the following algebraic expression:

(12p4q−33p−2q2)−1 \left( \frac{12p^4 q^{-3}}{3p^{-2} q^2} \right)^{-1}

What is the fully simplified form of this expression?

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Cevap: q54p6\frac{q^5}{4p^6}

Cevap

The expression simplifies to q54p6\frac{q^5}{4p^6}.
The correct answer is derived by first simplifying the inner fraction using the quotient rule for exponents, resulting in 4p6q−54p^6q^{-5}. Applying the outer negative exponent of −1-1 takes the reciprocal of each factor, leading to 4−1p−6q54^{-1}p^{-6}q^5, which is written with positive exponents as q54p6\frac{q^5}{4p^6}.

Adım Adım Çözüm

1
Divide the numerical coefficients.
12÷3=412 \div 3 = 4
Coefficients follow standard division rules.
2
Simplify the variable pp using the quotient rule for exponents.
p4÷p−2=p4−(−2)=p6p^4 \div p^{-2} = p^{4 - (-2)} = p^6
When dividing like bases, subtract the exponent in the denominator from the exponent in the numerator.
3
Simplify the variable qq using the quotient rule for exponents.
q−3÷q2=q−3−2=q−5q^{-3} \div q^2 = q^{-3 - 2} = q^{-5}
Subtracting a positive exponent is mathematically equivalent to adding its negative value.
4
Combine the simplified parts into a single expression inside the parentheses.
4p6q−54p^6q^{-5}
This represents the fully simplified value of the fraction before applying the outer exponent.
5
Apply the outer exponent of −1-1 to every factor in the expression.
(4p6q−5)−1=4−1⋅(p6)−1⋅(q−5)−1(4p^6q^{-5})^{-1} = 4^{-1} \cdot (p^6)^{-1} \cdot (q^{-5})^{-1}
The power of a product rule states that (abc)x=axbxcx(abc)^x = a^x b^x c^x.
6
Simplify the resulting exponents and write with positive exponents.
4−1p−6q5=q54p64^{-1}p^{-6}q^5 = \frac{q^5}{4p^6}
A negative exponent indicates the reciprocal of the base (x−n=1/xnx^{-n} = 1/x^n).

Anahtar Kavram

Simplifying algebraic fractions using the quotient, product, and negative power rules for exponents.
Soru 242Soru →

Determine the value of the polynomial −2a2+5ab−b3-2a^2 + 5ab - b^3 under the condition that a=−2a = -2 and b=−3b = -3. Which of the following represents the correct evaluation?

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Cevap: 49

Cevap

49
The correct answer is found by substituting the variable values, properly applying the exponents to the negative numbers (where (−2)2=4(-2)^2 = 4 and (−3)3=−27(-3)^3 = -27), and adhering to the order of operations to multiply before adding and subtracting.

Adım Adım Çözüm

1
Substitute −2-2 for aa and −3-3 for bb into the given polynomial.
−2(−2)2+5(−2)(−3)−(−3)3-2(-2)^2 + 5(-2)(-3) - (-3)^3
To prepare the expression for numerical evaluation.
2
Evaluate the exponential terms, noting that a negative number raised to an even power is positive, and to an odd power is negative.
−2(4)+5(−2)(−3)−(−27)-2(4) + 5(-2)(-3) - (-27)
The order of operations (PEMDAS) requires resolving exponents before multiplication.
3
Perform the multiplication operations from left to right.
−8+30−(−27)-8 + 30 - (-27)
The order of operations dictates that multiplication must be completed before addition and subtraction.
4
Convert the subtraction of a negative into addition and calculate the final sum.
−8+30+27=22+27=49-8 + 30 + 27 = 22 + 27 = 49
This is the final step to find the total value of the polynomial.

Anahtar Kavram

Evaluating Algebraic Expressions
Tahmini Süre:45s
Soru 243Soru →

When the algebraic expression (4x−3)(2x2+5x−1)(4x - 3)(2x^2 + 5x - 1) is fully expanded and simplified into standard polynomial form, what is the value of the coefficient of the xx term?

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Cevap: -19

Cevap

-19
The correct answer is −19-19 because the xx term is exclusively formed by the sum of the products (4x)(−1)(4x)(-1) and (−3)(5x)(-3)(5x), which equals −4x−15x=−19x-4x - 15x = -19x.

Adım Adım Çözüm

1
Identify the goal.
We need to find the coefficient of the xx term in the product of (4x−3)(4x - 3) and (2x2+5x−1)(2x^2 + 5x - 1).
Focusing only on the terms that produce an xx term saves time compared to expanding the entire polynomial expression.
2
Find the first partial product that results in an xx term.
Multiply the xx term from the binomial (4x4x) by the constant term from the trinomial (−1-1) to get −4x-4x.
An xx term multiplied by a constant results in an xx term.
3
Find the second partial product that results in an xx term.
Multiply the constant term from the binomial (−3-3) by the xx term from the trinomial (5x5x) to get −15x-15x.
A constant multiplied by an xx term results in an xx term.
4
Combine the partial products.
−4x+(−15x)=−19x-4x + (-15x) = -19x
To find the total xx term in the expanded polynomial, all like terms must be combined.
5
Identify the final coefficient.
The coefficient of −19x-19x is −19-19.
The coefficient is the numerical multiplier of the variable.

Anahtar Kavram

Multiplying Polynomials and Combining Like Terms
Soru 244Soru →

Evaluate the algebraic expression P=4v3−3uv+2u2P = 4v^3 - 3uv + 2u^2 using the assigned values u=−4u = -4 and v=−2v = -2. Fill in the missing numerical values for the intermediate calculation step and the final evaluated result.

Aşağıdaki boşlukları doldurun

The calculated value for the isolated term 4v34v^3 is , which makes the final evaluated total for the entire expression PP equal to .
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Cevap

The first term evaluates to -32, and the entire expression evaluates to -24.
The expression requires careful substitution of u=−4u = -4 and v=−2v = -2. Following the order of operations (PEMDAS), we first calculate the exponents: (−2)3=−8(-2)^3 = -8 and (−4)2=16(-4)^2 = 16. Next, we perform the multiplication for each term: 4(−8)=−324(-8) = -32, −3(−4)(−2)=−24-3(-4)(-2) = -24, and 2(16)=322(16) = 32. Finally, combining these intermediate values gives −32−24+32=−24-32 - 24 + 32 = -24.

Adım Adım Çözüm

1
Substitute the value of v into the first term 4v34v^3 and evaluate according to the order of operations.
4(−2)3=4(−8)=−324(-2)^3 = 4(-8) = -32
Exponents must be evaluated before multiplication. The cube of a negative number remains negative.
2
Substitute the values of u and v into the second term −3uv-3uv and evaluate.
−3(−4)(−2)=−3(8)=−24-3(-4)(-2) = -3(8) = -24
Multiplying two negative numbers yields a positive product, which is then multiplied by the negative coefficient.
3
Substitute the value of u into the third term 2u22u^2 and evaluate.
2(−4)2=2(16)=322(-4)^2 = 2(16) = 32
The square of a negative number is positive. This must be calculated before multiplying by the coefficient.
4
Combine the evaluated terms to find the final total for P.
−32−24+32=−24-32 - 24 + 32 = -24
Adding and subtracting the values from left to right yields the final result.

Anahtar Kavram

Evaluating multi-variable algebraic expressions by correctly substituting negative integers and rigorously applying the order of operations.
Soru 245Soru →

An algebraic equation requires simplification to isolate the unknown variable. Which of the following represents the correct value of yy in the equation below?

3(2y+5)−y=2(2y−1)+13 3(2y + 5) - y = 2(2y - 1) + 13
Cevabı ve açıklamayı göster

Cevap: -4

Cevap

The correct value for yy is −4-4.
The correct answer is found by properly applying the distributive property to both sides, combining the resulting like terms, and systematically isolating the variable. Maintaining the balance of the equation by performing inverse operations yields a final value of -4.

Adım Adım Çözüm

1
Distribute the constants into the parentheses on both sides of the equation.
6y+15−y=4y−2+136y + 15 - y = 4y - 2 + 13
To eliminate the parentheses and prepare the equation for combining terms.
2
Combine like terms on each individual side.
5y+15=4y+115y + 15 = 4y + 11
To simplify the expressions on both sides before isolating the variable.
3
Subtract 4y4y from both sides.
y+15=11y + 15 = 11
To group all variable terms onto the left side of the equation.
4
Subtract 1515 from both sides.
y=−4y = -4
To completely isolate yy and find the final root of the equation.

Anahtar Kavram

Solving one-variable linear equations by applying the distributive property and combining like terms.
Soru 246Soru →

What value of xx satisfies the equation 12(4x−6)+3x=23(9x−12)\frac{1}{2}(4x - 6) + 3x = \frac{2}{3}(9x - 12)?

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Cevap: 5

Cevap

5
The correct answer is 55. By distributing the fractions, combining the like terms, and properly using inverse operations to isolate xx, the equation simplifies step-by-step to x=5x = 5.

Adım Adım Çözüm

1
Distribute the fractions into the parentheses on both sides of the equation.
2x−3+3x=6x−82x - 3 + 3x = 6x - 8
Applying the distributive property removes the parentheses and prepares the equation for combining terms.
2
Combine the like terms on the left side.
5x−3=6x−85x - 3 = 6x - 8
Simplifying each side individually makes it easier to isolate the variable.
3
Subtract 5x5x from both sides to group the variable terms on the right side.
−3=x−8-3 = x - 8
Keeping the variable coefficient positive reduces the chance of a sign error.
4
Add 88 to both sides to isolate xx.
5=x5 = x
Applying the inverse operation isolates the variable and provides the final solution.

Anahtar Kavram

Solving One-Variable Linear Equations
Soru 247Soru →

Determine the simplified form of the following product, assuming cc and dd are non-zero real numbers:

(2c−3d5)−2(4c2d−1)(2c^{-3}d^5)^{-2}(4c^2d^{-1})

What is the resulting fully simplified expression?

Cevabı ve açıklamayı göster

Cevap: c8d11\frac{c^8}{d^{11}}

Cevap

The fully simplified expression is c8d11\frac{c^8}{d^{11}}.
The correct answer is obtained by first applying the power of a power rule to (2c−3d5)−2(2c^{-3}d^5)^{-2}, yielding 14c6d−10\frac{1}{4}c^6d^{-10}. Multiplying this by 4c2d−14c^2d^{-1} involves adding the exponents of like bases, which results in c8d−11c^8d^{-11}. Moving the negative exponent to the denominator yields the fully simplified form.

Adım Adım Çözüm

1
Apply the power of a product rule to the first term, distributing the −2-2 exponent to the coefficient and both variables.
2−2(c−3)−2(d5)−2=14c6d−102^{-2}(c^{-3})^{-2}(d^5)^{-2} = \frac{1}{4}c^6d^{-10}
The rules (xy)a=xaya(xy)^a = x^ay^a and (xa)b=xab(x^a)^b = x^{ab} require every part of the base to be raised to the outer power.
2
Multiply the expanded first term by the second term by grouping the coefficients and the like variables together.
(14⋅4)(c6⋅c2)(d−10⋅d−1)(\frac{1}{4} \cdot 4)(c^6 \cdot c^2)(d^{-10} \cdot d^{-1})
Multiplication is commutative, which allows rearranging the terms to combine matching bases.
3
Multiply the numerical coefficients and add the exponents for the variables with the same base.
1⋅c6+2⋅d−10+(−1)=c8d−111 \cdot c^{6+2} \cdot d^{-10+(-1)} = c^8d^{-11}
The product of powers rule states that when multiplying terms with the same base, their exponents should be added (xa⋅xb=xa+bx^a \cdot x^b = x^{a+b}).
4
Rewrite the expression so that all exponents are positive.
c8d11\frac{c^8}{d^{11}}
A fully simplified algebraic expression is typically written with positive exponents, using the rule x−a=1xax^{-a} = \frac{1}{x^a}.

Anahtar Kavram

Operations with Variable Exponents
Soru 248Soru →

When the expression (3x−4)(2x+5)−x(x−2)(3x - 4)(2x + 5) - x(x - 2) is fully expanded and simplified into standard polynomial form, what is the value of the coefficient of xx?

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Cevap: 9

Cevap

9
Expanding the binomials gives 6x2+7x−206x^2 + 7x - 20. Distributing −x-x gives −x2+2x-x^2 + 2x. Combining like terms results in 5x2+9x−205x^2 + 9x - 20. The question asks for the coefficient of xx, which is the number multiplying the xx term: 9.

Adım Adım Çözüm

1
Multiply the binomials (3x−4)(3x - 4) and (2x+5)(2x + 5).
6x2+15x−8x−206x^2 + 15x - 8x - 20, which simplifies to 6x2+7x−206x^2 + 7x - 20.
To expand the first part of the expression using the distributive property (FOIL).
2
Distribute −x-x across the binomial (x−2)(x - 2).
−x2+2x-x^2 + 2x.
To expand the second part of the expression, ensuring the negative sign is applied to both terms inside the parentheses.
3
Combine the expanded parts.
(6x2+7x−20)+(−x2+2x)=5x2+9x−20(6x^2 + 7x - 20) + (-x^2 + 2x) = 5x^2 + 9x - 20.
To simplify the full expression into standard polynomial form by grouping like terms.
4
Identify the coefficient of xx.
The coefficient of xx in 5x2+9x−205x^2 + 9x - 20 is 99.
This answers the specific question asked.

Anahtar Kavram

Multiplying polynomials and combining like terms
Soru 249Soru →

Consider the algebraic expression 2x2−yzx+y\frac{2x^2 - yz}{x + y}. If the variables are assigned the values x=−3x = -3, y=5y = 5, and z=−2z = -2, what are the intermediate evaluated values for the numerator and denominator, and what is the final result?

Aşağıdaki boşlukları doldurun

After substituting the values, the evaluated result of the numerator is and the denominator is . Dividing these intermediate values yields a final result of .
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Cevap

The intermediate numerator evaluates to 28, the denominator to 2, and the final evaluated result is 14.
The correct final value is 14. This is determined by carefully substituting the negative and positive variable values into the numerator and denominator, strictly applying the order of operations to handle exponents and negative signs, and finally dividing the intermediate numerator 28 by the denominator 2.

Adım Adım Çözüm

1
Substitute the value of xx into the first term of the numerator, 2x22x^2.
2(−3)2=2(9)=182(-3)^2 = 2(9) = 18
Applying the order of operations, exponentiation must be evaluated before multiplication.
2
Substitute the values of yy and zz into the second term of the numerator, yzyz.
(5)(−2)=−10(5)(-2) = -10
Multiplying a positive integer by a negative integer results in a negative integer.
3
Calculate the complete numerator by subtracting the second term from the first.
18−(−10)=18+10=2818 - (-10) = 18 + 10 = 28
Subtracting a negative number is mathematically equivalent to adding its positive counterpart.
4
Substitute the values of xx and yy to evaluate the denominator, x+yx + y.
−3+5=2-3 + 5 = 2
Combining the negative and positive integers.
5
Divide the fully evaluated numerator by the evaluated denominator.
282=14\frac{28}{2} = 14
The final step in evaluating the rational expression.

Anahtar Kavram

Evaluating Algebraic Expressions
Soru 250Soru →

In a mathematical model, the output variable MM is defined by the equation M=2a2−3ab+b3M = 2a^2 - 3ab + b^3. What is the computed value of MM if the input parameters are set to a=−3a = -3 and b=−2b = -2?

Cevabı ve açıklamayı göster

Cevap: -8

Cevap

-8
The correct answer is found by substituting the values and strictly following the order of operations. First, the exponents are evaluated: (−3)2=9(-3)^2 = 9 and (−2)3=−8(-2)^3 = -8. Next, the multiplication is performed: 2(9)=182(9) = 18 and −3(−3)(−2)=−18-3(-3)(-2) = -18. Finally, combining these values gives 18−18−8=−818 - 18 - 8 = -8.

Adım Adım Çözüm

1
Substitute the values a=−3a = -3 and b=−2b = -2 into the original equation M=2a2−3ab+b3M = 2a^2 - 3ab + b^3.
M=2(−3)2−3(−3)(−2)+(−2)3M = 2(-3)^2 - 3(-3)(-2) + (-2)^3
Direct substitution is the first step in evaluating any algebraic expression.
2
Evaluate the terms with exponents according to the order of operations (PEMDAS/BODMAS).
(−3)2=9(-3)^2 = 9 and (−2)3=−8(-2)^3 = -8
Exponents must be calculated before multiplication. A negative number squared is positive, while a negative number cubed remains negative.
3
Perform the multiplication for each term in the expression.
2(9)=182(9) = 18 and −3(−3)(−2)=−18-3(-3)(-2) = -18
Multiplication is performed next. For the middle term, multiplying three negative numbers results in a negative product.
4
Combine the resulting values using addition and subtraction.
18−18+(−8)=0−8=−818 - 18 + (-8) = 0 - 8 = -8
This final arithmetic operation yields the evaluated result of the expression.

Anahtar Kavram

Evaluating algebraic expressions involving exponents, negative bases, and strict adherence to the order of operations.
Tahmini Süre:1m 0s
Soru 251Soru →

Solve the following linear equation for ww:

13(12w−9)+5=2(w−1)+8 \frac{1}{3}(12w - 9) + 5 = 2(w - 1) + 8

Enter the exact integer value that satisfies the equation.

Aşağıdaki boşlukları doldurun

The value of ww is .
Cevabı ve açıklamayı göster

Cevap

2
By successfully distributing the factors, combining like terms on each side, and balancing the equation by moving variables and constants to opposite sides, the isolated variable equates to exactly 2.

Adım Adım Çözüm

1
Distribute the coefficients to remove parentheses on both sides of the equation.
4w−3+5=2w−2+84w - 3 + 5 = 2w - 2 + 8
Applying the distributive property simplifies the expression and exposes the variable terms.
2
Combine the constant terms on each side.
4w+2=2w+64w + 2 = 2w + 6
Simplifying each side makes it easier to balance the equation in the next steps.
3
Subtract 2w2w from both sides of the equation.
2w+2=62w + 2 = 6
This groups all the variable terms onto the left side.
4
Subtract 22 from both sides, then divide the result by 22.
2w=4⇒w=22w = 4 \Rightarrow w = 2
This completely isolates the variable ww to reveal its final value.

Anahtar Kavram

Solving One-Variable Linear Equations
Soru 252Soru →

What is the numerical value of the algebraic expression −5x2+12yx−y2-5x^2 + \frac{12y}{x} - y^2 when evaluated for x=−2x = -2 and y=−3y = -3?

Cevabı ve açıklamayı göster

Cevap: -11

Cevap

The correct numerical value of the expression is -11.
Substituting x=−2x = -2 and y=−3y = -3 gives −5(−2)2+12(−3)−2−(−3)2-5(-2)^2 + \frac{12(-3)}{-2} - (-3)^2. Evaluating the exponents first results in −5(4)+−36−2−9-5(4) + \frac{-36}{-2} - 9. Multiplying and dividing yields −20+18−9-20 + 18 - 9. Finally, adding and subtracting gives the correct value of −11-11.

Adım Adım Çözüm

1
Substitute the given numeric values into the algebraic expression using parentheses.
−5(−2)2+12(−3)−2−(−3)2-5(-2)^2 + \frac{12(-3)}{-2} - (-3)^2
Using parentheses during substitution prevents sign errors, especially when variables have negative values.
2
Evaluate the terms with exponents.
−5(4)+12(−3)−2−(9)-5(4) + \frac{12(-3)}{-2} - (9)
According to the order of operations (PEMDAS), exponents must be evaluated before multiplication and division.
3
Perform the multiplication and division operations.
−20+−36−2−9⇒−20+18−9-20 + \frac{-36}{-2} - 9 \Rightarrow -20 + 18 - 9
Multiplication and division are processed from left to right before addition and subtraction.
4
Complete the evaluation by performing addition and subtraction from left to right.
−20+18−9=−2−9=−11-20 + 18 - 9 = -2 - 9 = -11
Addition and subtraction are the final steps in the order of operations.

Anahtar Kavram

Evaluating algebraic expressions requires careful substitution of values using parentheses and strict adherence to the order of operations (PEMDAS).
Soru 253Soru →

The dimensions of a rectangular box are given by the expressions 5x5x, (2x−3)(2x - 3), and (x+4)(x + 4). The volume of the box is the product of its three dimensions. When the volume is expressed as a fully simplified polynomial in the form ax3+bx2+cxax^3 + bx^2 + cx, determine the value of the coefficient bb.

Aşağıdaki boşlukları doldurun

The value of bb is .
Cevabı ve açıklamayı göster

Cevap

25
To find the coefficient bb, you must expand the product of the three dimensions. First, multiply the binomials using FOIL: (2x−3)(x+4)=2x2+8x−3x−12=2x2+5x−12(2x - 3)(x + 4) = 2x^2 + 8x - 3x - 12 = 2x^2 + 5x - 12. Then, distribute 5x5x across the resulting trinomial: 5x(2x2+5x−12)=10x3+25x2−60x5x(2x^2 + 5x - 12) = 10x^3 + 25x^2 - 60x. Comparing this to the specified polynomial form ax3+bx2+cxax^3 + bx^2 + cx, the term with x2x^2 is 25x225x^2, making the coefficient b=25b = 25.

Adım Adım Çözüm

1
Set up the volume expression by multiplying the three given dimensions.
V=5x(2x−3)(x+4)V = 5x(2x - 3)(x + 4)
The volume of a rectangular box is calculated as length ×\times width ×\times height.
2
Multiply the two binomials using the FOIL method.
(2x−3)(x+4)=2x2+8x−3x−12=2x2+5x−12(2x - 3)(x + 4) = 2x^2 + 8x - 3x - 12 = 2x^2 + 5x - 12
It is mathematically sound and often easier to multiply the binomials first before distributing the monomial.
3
Distribute the monomial 5x5x to each term in the resulting trinomial.
5x(2x2+5x−12)=10x3+25x2−60x5x(2x^2 + 5x - 12) = 10x^3 + 25x^2 - 60x
To fully expand the polynomial, every term inside the parentheses must be multiplied by 5x5x.
4
Identify the value of bb by matching the result to the given standard form ax3+bx2+cxax^3 + bx^2 + cx.
b=25b = 25
The variable bb represents the coefficient of the x2x^2 term in the fully expanded polynomial.

Anahtar Kavram

Multiplying Polynomials and the Distributive Property
Soru 254Soru →

Given the values x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2, determine the value of the expression 4x2y−yz34x^2y - yz^3.

Cevabı ve açıklamayı göster

Cevap: -36

Cevap

-36
The correct answer is derived by substituting the variables accurately, applying the exponents (especially noting that a negative base to an odd power remains negative), and strictly following the order of operations to multiply and then subtract.

Adım Adım Çözüm

1
Substitute x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2 into the expression.
4(12)2(−4)−(−4)(−2)34(\frac{1}{2})^2(-4) - (-4)(-2)^3
Variable substitution must be done exactly as given to prepare for evaluation.
2
Evaluate the terms with exponents.
(12)2=14(\frac{1}{2})^2 = \frac{1}{4} and (−2)3=−8(-2)^3 = -8. The expression becomes 4(14)(−4)−(−4)(−8)4(\frac{1}{4})(-4) - (-4)(-8).
According to the order of operations (PEMDAS), exponents must be resolved before multiplication.
3
Perform the multiplication operations from left to right.
4(14)(−4)=1(−4)=−44(\frac{1}{4})(-4) = 1(-4) = -4 and (−4)(−8)=32(-4)(-8) = 32. The expression is now −4−32-4 - 32.
Multiplication is the next step in the order of operations. Note that multiplying two negative numbers results in a positive product.
4
Perform the final subtraction.
−4−32=−36-4 - 32 = -36
Subtracting a positive number from a negative number moves further left on the number line.

Anahtar Kavram

Evaluating algebraic expressions using rational numbers, negative bases, and the correct order of operations.
Tahmini Süre:1m 0s
Soru 255Soru →

If the polynomial expression (3x−5)(3x - 5) is multiplied by the expression (Ax2+2x−7)(Ax^2 + 2x - 7), the resulting simplified polynomial has an x2x^2 coefficient of −19-19. What is the value of the constant AA?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

5
The x2x^2 terms in the product of (3x−5)(3x - 5) and (Ax2+2x−7)(Ax^2 + 2x - 7) are generated by multiplying the xx terms together (3x⋅2x=6x2)(3x \cdot 2x = 6x^2) and by multiplying the constant by the x2x^2 term (−5⋅Ax2=−5Ax2)(-5 \cdot Ax^2 = -5Ax^2). Setting their sum equal to −19x2-19x^2 gives the equation 6−5A=−196 - 5A = -19. Solving for AA yields A=5A = 5.

Adım Adım Çözüm

1
Identify combinations that yield an x2x^2 term
The x2x^2 terms come from multiplying (3x)(3x) by (2x)(2x) and (−5)(-5) by (Ax2)(Ax^2).
To find the coefficient of a specific term without expanding the entire polynomial, only multiply the terms whose exponents sum to the target power.
2
Calculate the partial products
(3x)(2x)=6x2(3x)(2x) = 6x^2 and (−5)(Ax2)=−5Ax2(-5)(Ax^2) = -5Ax^2
These represent the only contributions to the x2x^2 term in the final expanded polynomial.
3
Formulate an equation for the coefficient
6−5A=−196 - 5A = -19
The sum of the partial x2x^2 coefficients must equal the total x2x^2 coefficient given in the problem.
4
Solve the linear equation for AA
−5A=−25→A=5-5A = -25 \rightarrow A = 5
Isolating the variable AA provides the final answer.

Anahtar Kavram

Multiplying Polynomials
Soru 256Soru →

Calculate the result of the following algebraic fraction when x=−2x = -2 and y=2y = 2.

Aşağıdaki boşlukları doldurun

The evaluated value of the expression 4x3+2y2x−y\frac{4x^3 + 2y^2}{x - y} is .
Cevabı ve açıklamayı göster

Cevap

6
The correct answer is 6 because substituting the values x=−2x = -2 and y=2y = 2 into the expression yields a numerator of −24-24 and a denominator of −4-4. Dividing a negative by a negative results in a positive 6.

Adım Adım Çözüm

1
Substitute the given values for xx and yy into the expression.
4(−2)3+2(2)2−2−2\frac{4(-2)^3 + 2(2)^2}{-2 - 2}
Variable substitution is the first required step in evaluating any algebraic expression.
2
Evaluate the terms with exponents in the numerator.
(−2)3=−8(-2)^3 = -8 and 22=42^2 = 4
According to the order of operations (PEMDAS), exponents must be resolved before multiplication.
3
Perform the multiplication operations in the numerator.
4(−8)=−324(-8) = -32 and 2(4)=82(4) = 8
Multiplication is performed after exponents.
4
Add the resulting terms in the numerator and subtract the terms in the denominator.
Numerator: −32+8=−24-32 + 8 = -24. Denominator: −2−2=−4-2 - 2 = -4.
Simplify the numerator and denominator completely before dividing.
5
Divide the simplified numerator by the simplified denominator.
−24−4=6\frac{-24}{-4} = 6
Dividing a negative number by a negative number results in a positive quotient.

Anahtar Kavram

Evaluating algebraic expressions with negative integers and exponents
Tahmini Süre:1m 0s
Soru 257Soru →

A polynomial P(x)P(x) is defined as the product of the binomial (4x−3)(4x - 3) and the trinomial (−2x2+5x−1)(-2x^2 + 5x - 1). What is the fully expanded and simplified form of P(x)P(x)?

Cevabı ve açıklamayı göster

Cevap: −8x3+26x2−19x+3-8x^3 + 26x^2 - 19x + 3

Cevap

−8x3+26x2−19x+3-8x^3 + 26x^2 - 19x + 3
The correct expression is found by successfully distributing both 4x4x and −3-3 across the trinomial (−2x2+5x−1)(-2x^2 + 5x - 1), maintaining correct exponents and signs, and finally combining the like terms: 20x220x^2 with 6x26x^2, and −4x-4x with −15x-15x.

Adım Adım Çözüm

1
Set up the multiplication using the distributive property.
4x(−2x2+5x−1)−3(−2x2+5x−1)4x(-2x^2 + 5x - 1) - 3(-2x^2 + 5x - 1)
Every term in the first polynomial must be multiplied by every term in the second polynomial.
2
Distribute 4x4x through the trinomial.
4x(−2x2)+4x(5x)+4x(−1)=−8x3+20x2−4x4x(-2x^2) + 4x(5x) + 4x(-1) = -8x^3 + 20x^2 - 4x
Multiply coefficients and add exponents for the variable base.
3
Distribute −3-3 through the trinomial.
−3(−2x2)−3(5x)−3(−1)=6x2−15x+3-3(-2x^2) - 3(5x) - 3(-1) = 6x^2 - 15x + 3
Multiply the constant by each term, carefully applying integer sign rules.
4
Combine the results and group like terms.
−8x3+(20x2+6x2)+(−4x−15x)+3-8x^3 + (20x^2 + 6x^2) + (-4x - 15x) + 3
Grouping terms with the same variable exponent prepares the expression for final simplification.
5
Add the coefficients of the like terms.
−8x3+26x2−19x+3-8x^3 + 26x^2 - 19x + 3
This yields the polynomial in standard form.

Anahtar Kavram

Multiplying polynomials by distributing every term in the first factor to every term in the second, then combining like terms.
Soru 258Soru →

Evaluate the given algebraic equation to solve for pp:

7−3(p+2)=p−77 - 3(p + 2) = p - 7

Which of the following represents the correct solution for pp?

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

The correct value is 2.
The correct approach involves distributing the −3-3 into the parentheses to get 7−3p−67 - 3p - 6, combining like terms to get 1−3p1 - 3p, and then balancing the equation to solve for pp. Adding 3p3p to both sides yields 1=4p−71 = 4p - 7, and adding 77 gives 8=4p8 = 4p, which simplifies to p=2p = 2.

Adım Adım Çözüm

1
Apply the distributive property to the left side of the equation.
7−3p−6=p−77 - 3p - 6 = p - 7
The -3 must be multiplied by both pp and 22 to eliminate the parentheses.
2
Combine the constant terms on the left side.
1−3p=p−71 - 3p = p - 7
Combining 77 and −6-6 simplifies the equation before moving terms across the equals sign.
3
Add 3p3p to both sides of the equation.
1=4p−71 = 4p - 7
This groups all terms containing the variable pp on the right side.
4
Add 77 to both sides and divide by 44.
8=4p⇒p=28 = 4p \Rightarrow p = 2
This isolates the variable pp to find the final numerical solution.

Anahtar Kavram

Solving Linear Equations with Distribution
Soru 259Soru →

A manufacturer is cutting a square opening out of a rectangular metal panel. The rectangular panel has a length of (4x−1)(4x - 1) inches and a width of (2x+3)(2x + 3) inches. The square opening to be removed has a side length of (x+2)(x + 2) inches. Which of the following expressions represents the total remaining area of the metal panel after the square is removed?

Cevabı ve açıklamayı göster

Cevap: 7x2+6x−77x^2 + 6x - 7

Cevap

The correct expression is 7x2+6x−77x^2 + 6x - 7.
The remaining area is found by subtracting the square's area from the rectangle's area. Multiplying the dimensions (4x−1)(2x+3)(4x - 1)(2x + 3) yields 8x2+10x−38x^2 + 10x - 3. Squaring the dimension (x+2)(x + 2) yields x2+4x+4x^2 + 4x + 4. Subtracting the entire second polynomial requires distributing the negative sign, resulting in 8x2+10x−3−x2−4x−48x^2 + 10x - 3 - x^2 - 4x - 4, which correctly simplifies to 7x2+6x−77x^2 + 6x - 7.

Adım Adım Çözüm

1
Calculate the area of the rectangular panel.
(4x−1)(2x+3)=8x2+12x−2x−3=8x2+10x−3(4x - 1)(2x + 3) = 8x^2 + 12x - 2x - 3 = 8x^2 + 10x - 3
The area of a rectangle is length multiplied by width, which requires multiplying two binomials using the FOIL method.
2
Calculate the area of the square opening.
(x+2)2=(x+2)(x+2)=x2+2x+2x+4=x2+4x+4(x + 2)^2 = (x + 2)(x + 2) = x^2 + 2x + 2x + 4 = x^2 + 4x + 4
The area of a square is its side length multiplied by itself.
3
Subtract the square's area from the rectangle's area.
(8x2+10x−3)−(x2+4x+4)=8x2+10x−3−x2−4x−4=7x2+6x−7(8x^2 + 10x - 3) - (x^2 + 4x + 4) = 8x^2 + 10x - 3 - x^2 - 4x - 4 = 7x^2 + 6x - 7
To find the remaining area, the removed portion must be subtracted. It is critical to distribute the negative sign to every term inside the parentheses being subtracted.

Anahtar Kavram

Multiplying binomials and subtracting polynomials while properly distributing negative signs.
Soru 260Soru →

Which of the following represents the value of yy that makes the given equation true?

2y−53+8=3\frac{2y - 5}{3} + 8 = 3
Cevabı ve açıklamayı göster

Cevap: -5

Cevap

The correct value for the variable is -5.
The solution requires a sequence of inverse operations to isolate the variable. First, subtracting 8 from both sides gives a value of -5 on the right. Then, multiplying by 3 clears the fraction, resulting in 2y - 5 = -15. Adding 5 yields 2y = -10, and dividing by 2 confirms the final value is -5.

Adım Adım Çözüm

1
Isolate the fractional term by subtracting 8 from both sides of the equation.
2y−53=−5\frac{2y - 5}{3} = -5
Applying the inverse operation of addition moves the constant term to the right side, simplifying the equation.
2
Multiply both sides of the equation by 3.
2y−5=−152y - 5 = -15
Multiplying by the denominator eliminates the fraction, making it possible to solve for the variable.
3
Add 5 to both sides of the equation.
2y=−102y = -10
This step isolates the term with the variable on the left side.
4
Divide both sides by 2.
y=−5y = -5
Dividing by the coefficient of the variable gives the final exact value.

Anahtar Kavram

Solving one-variable linear equations involving fractions
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Algebra Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) — Sayfa 13 | Examkin